Answer:
If you are reffering true or false, its true! <3
Answer:
yes, sliding a box is work against friction .
An 80 kg object has a µk = 0.35 and a µs = 0.60. Assuming it is on a flat surface
Answer:
What is the normal force on the object (draw a diagram if needed)
784 N
How much force is required to get the object to start to move from rest (max static friction)?
470.4 N
When the object starts moving, what is the force of kinetic friction?
274.4 N
If the moving object has a tension force of 300N to the right pulling it, what is the net force on the object in the horizontal direction? 784 N
What is the acceleration (with direction) of the object based on your answer for part d? Remember that a = net force/m.
Explanation:
We have that for the Question "" it can be said that the normal force and How much force is required to get the object to start to move from rest is
F_N=784NF_{max}480N
From the question we are told
An 80 kg object has a µk = 0.35 and a µs = 0.60. Assuming it is on a flat surface
What is the normal force on the object (draw a diagram if needed) How much force is required to get the object to start to move from rest?
a)
Generally the equation for the Normal Force is mathematically given as
[tex]F_N=mg\\\\F_N=80*9.8\\\\F_N=784N\\\\[/tex]
b)
[tex]F_{max}=0.60*800\\\\\F_{max}480N\\\\[/tex]
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https://brainly.com/question/23379286
Complete Question
An 80 kg object has a µk = 0.35 and a µs = 0.60. Assuming it is on a flat surface
What is the normal force on the object (draw a diagram if needed) How much force is required to get the object to start to move from rest?
A car having a total mass of 2250 kg and traveling at 72.0 km/h smashes into a tree. The car is stopped in 0.250 s. The average force acting on the car during the collision is
A. 1.80, 105 N.
B. 80.0 N.
C. 1.80 102 N
D. zero. E. 2.20 104
Answer:
A. 1.8x10⁵
Explanation:
For this question we have
72km/h = speed
Total mass = 2250kg
Stopped at t = 0.2250s
To get average force acting on this car on collision:
72km/3.6 = 20m|s
Impulse = ∆p
This implies:
F∆t = m∆v
F = m∆v/∆t
= 2250x20/0.250
= 180000
= 1.8x10⁵
Therefore option A is correct.
what is Force and Preasure ??
Answer:
Definition: Pressure:- Force per unit area surface is called pressure. P = F/ A Pressure = Force /Area Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed. Gauge pressure is the pressure relative to the ambient pressure.
Answer:
A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. When the interaction ceases, the two objects no longer experience the force.
Pressure is defined to be the amount of force exerted per area.
Formula of pressure = P = F÷A
Where, P = Pressure,
F = Force applied and,
A = Unit area.
Examples of Pressure is Air pressure.
A 4.5 kg block is pulled across a table by a horizontal force of 42 N. The frictional force
opposing the motion is 7.5 N. Calculate the acceleration of the object.
Answer:
7.67m/s²
Explanation:
The net force on the block is;
Net force = Force of pull - Frictional force
mass of block = 4.5kg
force of pull = 42N
Frictional force = 7.5N
Net force = 42 - 7.5
Force = mass x acceleration
ma = 34.5
4.5 x a = 34.5
a = [tex]\frac{34.5}{4.5}[/tex] = 7.67m/s²
Unscramble heenagwirt
Answer:
weathering
Explanation:
PLEASE PROVIDE AN EXPLANATION.
THANKS!!!
Answer:
(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz
(b) 250 m/s
(c) 1250 N
(d) Positive x-direction
(e) 6.00 m/s
(f) 0.0365 m
Explanation:
(a) The standard form of the wave is:
y = A cos ((2πf) t ± (2π/λ) x)
where A is the amplitude, f is the frequency, and λ is the wavelength.
If the x term has a positive coefficient, the wave moves to the left.
If the x term has a negative coefficient, the wave moves to the right.
Therefore:
A = 0.0800 m
2π/λ = 0.300 m⁻¹
λ = 20.9 m
2πf = 75.0 rad/s
f = 11.9 Hz
(b) Velocity is wavelength times frequency.
v = λf
v = (20.9 m) (11.9 Hz)
v = 250 m/s
(c) The tension is:
T = v²ρ
where ρ is the mass per unit length.
T = (250 m/s)² (0.0200 kg/m)
T = 1250 N
(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).
(e) The maximum transverse speed is Aω.
(0.0800 m) (75.0 rad/s)
6.00 m/s
(f) Plug in the values and find y.
y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))
y = 0.0365 m
A baseball player hits a ball with a bat. At one moment the force exerted by the bat on the ball is 18,000 N. At that same moment, how much force is exerted on the bat by the ball?
a) 18,000 N
b) less than 18,000 N
c) more than 18,000 N
Answer:
Less than 18000N
Explanation:
Given
[tex]Force\ Exerted = 18000N[/tex]
This question will be answered using Newton's third law.
Understanding this law, it implies that reaction force is equal and opposite to the force exerted.
This implies that;
If the force exerted on the ball is 18000N
the force exerted is -18000N
So, the option that answers the question is less than 18000N because -18000N < 18000N
Two identical conducting spheres each have a charge of 2 C. They have a radius of 0.1 m and are separated by 0.5 meters. If you were to increase the radius of these spheres to 0.2 meters, the electrostatic force between them would
Answer:
The electrostatic force will remain the same
Explanation:
From the question we are told that
The charge on the each conducting sphere is [tex]q = 2 \ C[/tex]
The radius each sphere is [tex]r_1 = r_2 = r = 0. 1\ m[/tex]
Generally electrostatic force between the sphere is mathematically represented as
[tex]F = \frac{k * q_1 q_2 }{d^2}[/tex]
Here k is the coulomb constant ,
d is the distance between the two sphere which is measured from one center of the sphere to the other center of the sphere
Now from the question we are told that the radius of the spheres is doubled (i.e from 0.10 m to 0.2 m ) , this will not affect the distance between the sphere because their center are still in the same position
and given there is no change in the distance between the spheres , the electrostatic force will remain the same
A soccor ball lies still on the grass until it is kicked by a player. This desribes which of Newton's Laws?
A 55-kg woman is wearing high heels. If each heel has a circular cross-section 6.0 mm in diameter and she puts all her weight on one heel, how much pressure does that exert on the floor
Answer:
The pressure exerted by the woman on the floor is 1.9061 x 10⁷ N/m²
Explanation:
Given;
mass of the woman, m = 55 kg
diameter of the circular heel, d = 6.0 mm
radius of the heel, r = 3.0 mm = 0.003 m
Cross-sectional area of the heel is given by;
A = πr²
A = π(0.003)²
A = 2.8278 x 10⁻⁵ m²
The weight of the woman is given by;
W = mg
W = 55 x 9.8
W = 539 N
The pressure exerted by the woman on the floor is given by;
P = F / A
P = W / A
P = 539 / (2.8278 x 10⁻⁵ )
P = 1.9061 x 10⁷ N/m²
Therefore, the pressure exerted by the woman on the floor is 1.9061 x 10⁷ N/m²
Cecelia dropped a ball from a height of 2 m. The ball fell in a straight path down to the ground.
According to Newton’s universal law of gravitation, which would change the path of the ball so it traces out the widest curved path possible?
tossing it horizontally at a slower speed
tossing it horizontally at a faster speed
dropping it from a shorter distance
dropping it from a greater distance
How long had the Romans ruled those regions?
precisely which regions?
Answer:
Romans have ruled for 450 years
Explanation:
A rocket of mass m is to be launched fromplanet X, which has a mass M and a radius R. What is the minimum speed that the rocket must have for it to escape into space?
Answer:
The minimum speed = [tex]\sqrt{\frac{2GM}{R} }[/tex]
Explanation:
The minimum speed that the rocket must have for it to escape into space is called its escape velocity. If the speed is not attained, the gravitational pull of the planet would pull down the rocket back to its surface. Thus the launch would not be successful.
The minimum speed can be determined by;
Escape velocity = [tex]\sqrt{\frac{2GM}{R} }[/tex]
where: G is the universal gravitational constant, M is the mass of the planet X, and R is its radius.
If the appropriate values of the variables are substituted into the expression, the value of the minimum speed required can be determined.
The minimum speed that the rocket must have for it to escape into space is [tex]\sqrt{\frac{2GM}{R} }[/tex].
What is escape velocity?Escape velocity is the minimum speed that the rocket must have for it to escape into space.
The minimum speed (escape velocity) that the rocket must have for it to escape into space is given as;
[tex]V = \sqrt{\frac{2GM}{R} }[/tex]
where;
M is mass of the planetG is gravitational constantR is the radiusThus, the minimum speed that the rocket must have for it to escape into space is [tex]\sqrt{\frac{2GM}{R} }[/tex].
Learn more about escape velocity here: https://brainly.com/question/13726115
Use Newton’s first law to explain why a book on a desk does not move
Answer:
nothing moves if anything other doesn't move it.
natural position of things is the resting
Explanation:
yeah that's it
Answer:
The book does not move because all the forces acting on the book are in equilibrium, creating a net force of zero magnitude on the book. Since the net force on the book is zero, this means that the book will remain in its present state of motion (which is that the book is motionless).
Explanation:
Newton's first law states that all body will remain in their present state of motion unless acted upon by an external force. In order word, a moving body should continue moving forever, and a body at rest should remain like that forever, unless they are acted upon by a force to either cause them to stop stop or to start moving respectively.
Intense physical activity that requires little oxygen but uses short bursts of energy is called Anaerobic exercise? True or false 
Which of these types of land is included under special land use?
Answer:
Special land use basically include all land parcels that cannot be defined in terms of residential and commercial land uses.
Answer:
Applying pesticides
Explanation:
there is a limit on the use of pesticides and it is the only one that is truly applied water is naturally occuring same with rocks and trees and you are applying things to the soil not the other way around
A force of 1.50 N acts on a 0.20 kg trolley so as to accelerate it along an air track.
The track and force are horizontal and in line. How fast is the trolley going after acceleration from rest through 30 cm, if friction is negligible?
Answer: The trolley is moving at 2.12m/s
Explanation:
Given from the question that the track and force are horizontal and inline, we have that
F= ma
where F= force= 1.50 N
m= mass = 0.2kg
therefore Acceleration , a = F/ m= 1.50/0.2 =7.5 m/s^2
To find how fast the trolley is going ie the Velocity, v
Having that
initial velocity at rest , u = 0,
acceleration a = 7.5 and
and distance, s = 30 cm = 30/100 = 0.30 m
we use motion equation that
v² = u² + 2 a s
v² = 0² + 2 x 7.5 x 0.30
v² = 4.5
v = [tex]\sqrt{4.5}[/tex]
v = 2.12 m/s
* WILL GIVE BRAINLIEST TO CORRECT ANSWER *
Name a product that people commonly purchase by mass and not by weight.
I would say food but like they take weight too
i need this ASAP please!!!
What is the significance of the discovery of exoplanets?
a. they may possibly be inhabited or harbor life.
b. they can provide natural resources for the future.
c. they help our understanding of the formation of planetary bodies.
d. they help calibrate gps satellites.
e. they help understand the nature of the expansion of the universe.
Answer:
C. the help our understanding of the formation of planetary bodies.
Explanation:
this is the answer of PLATO
Which best describes what occurs when technology advances
Answer: Technology advancement includes the creation of printhead arrays and multiple carriage systems that cover a larger area of cloth in a single pass of the substrate.
Explanation:
Can someone please help me I don’t understand this please show work plus I got it wrong it’s not C
A cat is trying to cross the street. Its velocity v as a function of time t is given in the graph below where
rightwards is the positive velocity direction.
v (m/s)
5
4
3
2+
2
1
5
-2
-3-
-4
-5
What is the cat's displacement Ax from t = 0.5 s to 1.5 s?
Answer:
rightwards is the positive velocity
Rightwards is the positive elicitation:
Answer:
3.8
Explanation:
mtngmrgncseeieeeie what is the unscramble word of this
Answer:
emergencies
Explanation:
This is what I got when I unscrambeled it
i think that would be magnetesium
Everyday activities do NOT produce significant muscle growth because:
A. Cytokines are released during everyday activities that inhibit (prevent) muscle regeneration.
B. Muscle growth requires going to the gym and lifting weights.
C. The nervous system cannot respond by recruiting more muscle fibers to generate hypertrophy.
D. The body adapts to the repeated demands so that those movements do not produce enough stress to cause hypertrophy (enlarging of the muscle).
Answer:
When elements bond together or when bonds of compounds are broken and form a new substance
Explanation:
Answer:
D
Explanation:
If you are riding your bike west to your friend’s house, and you ride the 1.25 miles in 5 minutes, what is your velocity, in miles per hour?
Answer:
velocity = 15 miles / hourExplanation:
distance = 1.25 mile
time traveled = 5 min.
find velocity in miles / hour
solution:
use the formula: velocity = distance / time
velocity = 1.25 mile x 60 min
5 min 1 hour
velocity = 15 miles / hour
The difference in a brass rod and steel rod is same as 12cm at all temperature .Find the length of the rod at 0°C.(Alpha b =18×10^-6k^-1 and alpha s =12×10^-6k^-1)
Answer:
length of brass=24cm and length of steel rod=36cm
The power rating of a 400-ΩΩ resistor is 0.800 W.
Required:
a. What is the maximum voltage that can be applied across this resistor without damaging it?
b. What is the maximum current it can draw?
Answer:
voltage= 17.88volts
current= 0.04 amps
Explanation:
Step one:
given data
resistance R=400 ohms
Power P= 0.8W
a. What is the maximum voltage that can be applied across this resistor without damaging it?
the expression relating power and voltage is
P=V^2/R
substituting we have
0.8=V^2/400
V^2=0.8*400
V^2=320
V=√320
V=17.88 volts
the maximum voltage is 17.88volts
b.What is the maximum current it can draw?
we know that from Ohm' law
V=IR
17.88=I*400
I=17.88/400
I=0.04amps
A stationary object is pushed with a force of 400N for 8s, resulting in its having a final velocity of 24m/s. What is its mass?
Answer:
The mass of the object is 133.33 kg
Explanation:
From Newton's second law of motion
F = ma
Where F is the force
m is the mass
and a is the acceleration
From the question,
A stationary object is pushed with a force of 400N, that is F = 400N. To determine the mass of the object,
First, we will determine the acceleration.
From one of the equations of kinematics for linear motion,
v = u + at
Where v is the final velocity
u is the initial velocity
a is the acceleration
and t is time
We can write that
v - u = at
Then, a = (v - u) / t
From the question,
t = 8s
v = 24m/s
u = 0 m/s (Since the object was stationary, that is, it was pushed from rest)
∴ a = (24m/s - 0m/s) / 8s
a = 24 / 8 = 3 m/s²
Therefore, acceleration is 3 m/s²
Now,
From F = ma
m = F / a
From the question
F = 400N
∴ m = 400N / 3m/s²
m = 133.33 kg
Hence, the mass of the object is 133.33 kg.
A ball was thrown vertically upward on a planet with a velocity of 2.5 m/sec. If it can rise up to 4m,then calculate gravitational strength of the planet.
pleaseeeeeeeeeeee helppppppppppp
Answer:
0.78m/s^2
Explanation:
using the third equation of motion, the answer is found
v^2=u^2 -2gs
where V= 0 at the maximum point
2gs=u^2
g=u^2
2s
g=2.5^2
2(4)
g=0.78125m/s^2
or g=0.78m/s^2
A boat can travel in still water at 56 m/s. If the boats sails directly across a river that flows at 126 m/s. What is the boats speed relative to the ground
Answer:
The answer is below
Explanation:
The speed of the boat in still water is perpendicular to the speed of the water flow. Therefore the speed relative to the ground (V), the speed of flow and the speed of the boat in still water form a right angled triangle. Hence the speed relative to the ground is given as:
V² = 56² + 126²
V² = 19012
V = 137.9 m/s
