Answer:
a. 1.8 kV b. 30 A c. power input = 3.6 kW, power output = 3.6 kW
Explanation:
a. Since turns ratio N₁/N₂ = V₁/V₂ where N₁ = number of turns of primary coil = 80 turns, N₂ = number of turns of secondary coil = 1200 turns, V₁ = voltage in primary circuit = 120 V and V₂ = voltage in secondary circuit = unknown
So, V₂ = N₂V₁/N₁
= 1200 × 120 V/80
= 1800 V
= 1.8 kV
b. Also, N₁/N₂ = I₂/I₁ where I₁ = current in primary circuit = unknown and I₂ = current in secondary circuit = 2.0 A
So, I₁ = N₂I₂/N₁
= 1200 × 2.0 A/80
= 30 A
c. The power input of the transformer P₁ = I₁V₁
= 30 A × 120 V
= 3600 W
= 3.6 kW
The power output of the transformer P₂ = I₂V₂
= 2 A × 1800 V
= 3600 W
= 3.6 kW
a) The voltage applied across the secondary circuit is 1.8 kV
b) The current in the primary circuit is 30 A
c) The power input and output of the transformer are 3.6 kW and 3.6 kW.
What is transformer?A transformer transfers electric energy from one AC circuit to one or more other circuits, either stepping up or stepping down the voltage.
a) Turns ratio N₁/N₂ = V₁/V₂ where N₁ = number of turns of primary coil = 80 turns, N₂ = number of turns of secondary coil = 1200 turns, V₁ = voltage in primary circuit = 120 V
Substitute the values and we get the voltage in secondary circuit is
V₂ = N₂V₁/N₁
V₂ = 1200 × 120 V/80
V₂ = 1800 V
V₂ = 1.8 kV
Thus, the voltage applied across the secondary circuit is 1.8 kV
b) Turn ratio also represented as N₁/N₂ = I₂/I₁ where I₂ is the current in secondary circuit = 2.0 A
Put the values, we have current in primary circuit is
I₁ = N₂I₂/N₁
I₁ = 1200 × 2.0 A/80
I₁ = 30 A
Thus, the current in the primary circuit is 30 A
c) The power input of the transformer P₁ = I₁V₁
P₁ = 30 A × 120 V
P₁ = 3600 W
P₁ = 3.6 kW
The power output of the transformer P₂ = I₂V₂
P₂= 2 A × 1800 V
P₂= 3600 W
P₂= 3.6 kW
The power input and output of the transformer are 3.6 kW and 3.6 kW.
Learn more about transformer.
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how many chromosomes will an elephant's sperm have ?
Mass is the amount of what
Answer:
Mass is the amount of matter in a substance.
Explanation:
The basic SI unit for mass is the kilogram (kg).
Calculate the weight of an object on earth surface having 600km from surface of earth?
Your question seems to contradict itself. You said "on Earth surface" and then you said "600 km from surface of the Earth" ... both in the same sentence.
I'll assume that the object is actually 600 km from surface of the Earth, because that makes the question (and the answer) more interesting.
We know that the weight of any object is (mass) x (gravity). Those are the two numbers we need in order to calculate the object's weight. Mysteriously, you haven't told us either one. We'll call the object's mass ' M ' (clever, eh ?), and we'll calculate the value of gravity up there where the object is located.
We now that the acceleration of gravity is inversely proportional to the square of the distance between the centers of two objects. When an object is on the Earth's surface, it's 6,371 km from Earth's center, and the acceleration of gravity there is 9.8 m/s².
The object in the question is 600 km farther from Earth's center, so the acceleration of gravity there is
(9.8 m/s²) · (6371 / 6971)² = 8.2 m/s².
So the object's weight is (8.2 M) Newtons.
This is about 84% of its weight on Earth's surface.
(Notice that the astronauts aboard the International Space Station are NOT "weightless". The strength of gravity up there where they are is around 84% of what it is down on the ground. The question of why they float, and why their muscles waste away, is a topic for another Brainly question.)
Can someone explain what ice jacking is and how it can cause structures to fail?
Answer: Rock slope failures can occur due to the presence of water; ice jacking occurs when water between joint or fissure surfaces freezes and expands. This type of failure is progressive, resulting in incremental weakening over time, often requiring several cycles before failure. Ice jacking is one form of rock erosion.
When a rocket accelerates through space is there work done?
Ed biked home from school in 400 seconds. His home is located 2000 m south of the school. What was his velocity?
[tex]answer = 5 \: \: metre \: per \: second\\ distance = 2000 \: m \\ time = 400 \: seconds \\ velocity = \: \frac{distance \:t ravelled}{time \: taken} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{2000}{400} \\ \: \: \: \: \: \: \: \: \: = 5 \: metre \: per \: second \\ hope \: it \: helps[/tex]
A) Is it possible for an object that, object with zero acceleration have velocity? If yes give an example if not give its proof.
Answer:
Yes, in case of uniform velocity
Explanation:
This is the case of uniform velocity. If a body covers equal displacement in equal intervals of time, then the velocity of a body is said to be ‘Uniform Velocity’. It meas that the velocity of a body remains constant during the motion and it does not change.
Since, acceleration is defined as the rate of change of velocity.
Therefore, if there is no change in velocity or in other words the change in velocity is zero, then the acceleration is also zero.
a = ΔV/t = 0/t
a = 0 m/s²
So, the acceleration of the body is 0 m/s², but it has a uniform velocity
Hence, it is possible for an object that, object with zero acceleration have velocity, which is the case case of uniform velocity.
What observation about light supported Einstein’s theory?
Answer:
Explanation:
Do you mean the theory that space-time is defined by what's in it? And that mass warps space-time?
There are many instances where his observation turned out to be correct. The most popular one is the phenomena of gravitational lensing. We can see the light from stars that are actually behind the sun. The huge gravity of the sun bends space-time and this also bends light. We use gravitational lensing alllll the time when trying to see very distant stars or galaxies.
Answer:
The Sun bent the light from a star. This bending made the star appear in a slightly different position from its actual position. This observation supported Einstein’s theory.
Explanation:
This is the answer on Edmentum! :)
If there are a boys pulling a rubber
with the same amount of force what will happen?
Answer:
The rubber will expand to its maximum and then tear in the middle.
Explanation:
Answer:
Hey!
Well if they continue to pull the rubber band, it would eventually rip apart right in the middle as the force could not be contained by the elastic fibres and had reached its maximum extension!
Explanation:
HOPE THIS HELPS!!
An escalator is used to move 25 passengers every minute from the first floor of a department store to the second. The second floor is located 5.30 meters above the first floor. The average passenger's mass is 60 kg. Determine the power requirement of the escalator in order to move this number of passengers in this amount of time.
Please help me quickly!
Answer:
1298.5watt
Explanation:
Power is defined as the rate at which work is done
Expressed mathematically as;
P = F × d/ t; F = force or weight of object ;d is height or distance sustain and t is time covered
Hence for 1 person the power consumption is ;
Note weight =mass× acceleration of free fall due to gravity,g
g is known as 9.8m/S2
Time taken is 1min which is 60 sec
60 ×9.8 × 5.3/60 = 51.94 watt
Hence for 25 persons we have
25 × 51.94 =1298.5watt
1.3kilo watt( kilo is 1000)
The work done by the escalator is 3,080.4 joules and the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.
The Work Done is calculated as:
Force (F) = 60 × 9.8
Distance (d) = 5.30 meters
Work (W) = F × d
Work (W) = (60 × 9.8) × 5.30
Work (W) = 3,080.4 joules
The Power is calculated as:
Time (t) = 1 minute
Power (P) = Work / Tim (t)
Power (P) = 3,080.4 / 60
Power (P) = 51.34 watts
Therefore, the power requirement of the escalator to move 25 passengers every minute is approximately 51.34 watts.
To know more about the work done and power:
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!! i will mark as brainliest so pls answer quick !!
The student becomes negatively charged because of the friction between her socks and the carpet.
Explain why the friction causes the student to become charged
Answer:
A student becomes negatively charged because of the friction between his socks and the carpet. ... The electrons get rubbed and move towards the carpet so the carpets electrons move away and the student becomes negatively charged.
What do nuclear fission and nuclear fusion have in common?
A. They start with the same reactants.
B. They're both used in power plants.
C. Their products have more mass than their reactants.
D. Their products have less mass than their reactants.
Answer:
B
Explanation:
Fission and Fission are nuclear reaction processes that releases energy.
Fission is the process where the nuclei of an atom splits into smaller nuclei of same element or elements of smaller nuclei when Fussion is when two smaller nuclei combined to form one of a different element of a higher nuclei. These processes release energy.
Answer:
D. Their products have less mass than their reactants.
Explanation:
Suppose that you walk 15 meters at 30 degrees as measured from the East. Then you walk another 25 meters at 60 degrees from the East what is your net displacement
Answer:
The net displacement is
[tex]R= \sqrt{A^2+B^2+2AB \cos \theta}[/tex]
[tex]=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m[/tex]
Explanation:
Suppose that you walk 15 meters at 30 degrees as measured from the East. Then you walk another 25 meters at 60 degrees from the East what is your net displacement
Given data
A = 15 m
B = 25 m
Angle between the vectors A and B is θ = 30°
The net displacement is
[tex]R= \sqrt{A^2+B^2+2AB \cos \theta}[/tex]
[tex]=\sqrt{15^2+25^2+2AB \cos 30^\circ} \\\\=\sqrt{225+625+ \cos30^0} \\\\=38.7m[/tex]
When salt is added to the water what happens to the surface?
Answer:
it increases the surface tension of the water
Which musical instruments produce lower pitches
Answer:
bigger instruments make lower pitches
Explanation:
bass drums and other large instruments have low sounds because they're so big. the smaller the instrument is, the higher pitch it's going to have
Answer:
It is mostly the Bass instruments because they use mouthpieces while the wind instrument use reeds and make a higher pitched sounds
Explanation:
Band
QUICK WILL MARK BRAINLIEST
As light shines from air to water, the index of refraction is 1.02 and the angle of
incidence is 38.0 °. What is the light's angle of refraction?
29.8°
32.5°
37.1°
39.8°
Answer:
37.1°
Explanation:
A 2kg object is dropped from a height 10m.Calculate the speed of the object after it has fallen 5m, assuming there is no resistance. g= 10 N/kg
Answer:
10m/s
Explanation:
[tex]d=v_ot+\dfrac{1}{2}at^2[/tex]
Since there is no initial velocity as the object is dropped, you can write the following equation:
[tex]5=\dfrac{1}{2}(10)t^2 \\\\1=t^2 \\\\t=1[/tex]
Now that you know how long the fall took, you can use another physics equation to find the velocity at that point.
[tex]v_f=v_o+at[/tex]
Since there once again is no initial velocity, you can rewrite this as:
[tex]v_f=at=(10)(1)=10m/s[/tex]
Hope this helps!
The kinetic energy the object has at any point during the fall is exactly the potential energy it lost by falling to that height.
Potential energy = (mass) · (gravity) · (height)
Change of potential energy = (mass) · (gravity) · (change of height)
Change of potential energy = (2 kg) · (10 m/s ) · (-5 m)
Change of potential energy = 100 Joules
Kinetic energy = (1/2) · (mass) · (speed²)
Kinetic energy = (1 kg) · (speed² )
100 J = (1 kg) · (speed²)
Speed² = (100 J) / (1 kg)
Speed² = (100 kg-m²/s²) / (1 kg)
Speed² = (100 m²/s²)
Speed = 10 m/s
1. Calculate the total binding energy of 12
6 C.
Answer in units of MeV.
2. Calculate the average binding energy per nucleon of 24
12Mg.
Answer in units of MeV/nucleon.
3. Calculate the average binding energy per nucleon of 85
37Rb.
Answer in units of MeV/nucleon.
4. Find the binding energy per nucleon of 238
92U.
Answer in units of MeV/nucleon.
5. Calculate the total binding energy of 20
10Ne.
Answer in units of MeV.
6. Calculate the total binding energy of 40
20Ca.
Answer in units of MeV.
Answer:
1. B = 79.12 MeV
2. B = -4.39 MeV/nucleon
3. B = 2.40 MeV/nucleon
4. B = 7.48 MeV/nucleon
5. B = -18.72 MeV
6. B = 225.23 MeV
Explanation:
The binding energy can be calculated using the followng equation:
[tex] B = (Zm_{p} + Nm_{n} - M)*931 MeV/C^{2} [/tex]
Where:
Z: is the number of protons
[tex]m_{p}[/tex]: is the proton's mass = 1.00730 u
N: is the number of neutrons
[tex]m_{n}[/tex]: is the neutron's mass = 1.00869 u
M: is the mass of the nucleus
1. The total binding energy of [tex]^{12}_{6}C[/tex] is:
[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]
[tex] B = (6*1.00730 + 6*1.00869 - 12.011)*931.49 MeV/u = 79.12 MeV [/tex]
2. The average binding energy per nucleon of [tex]^{24}_{12}Mg[/tex] is:
[tex] B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u [/tex]
Where: A = Z + N
[tex] B = \frac{(12*1.00730 + 12*1.00869 - 24.305)}{(12 + 12)}*931.49 MeV/u = -4.39 MeV/nucleon [/tex]
3. The average binding energy per nucleon of [tex]^{85}_{37}Rb[/tex] is:
[tex] B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u [/tex]
[tex] B = \frac{(37*1.00730 + 48*1.00869 - 85.468)}{85}*931.49 MeV/u = 2.40 MeV/nucleon [/tex]
4. The binding energy per nucleon of [tex]^{238}_{92}U[/tex] is:
[tex] B = \frac{(92*1.00730 + 146*1.00869 - 238.03)}{238}*931.49 MeV/u = 7.48 MeV/nucleon [/tex]
5. The total binding energy of [tex]^{20}_{10}Ne[/tex] is:
[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]
[tex] B = (10*1.00730 + 10*1.00869 - 20.180)*931.49 MeV/u = -18.72 MeV [/tex]
6. The total binding energy of [tex]^{40}_{20}Ca[/tex] is:
[tex] B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u [/tex]
[tex] B = (20*1.00730 + 20*1.00869 - 40.078)*931.49 MeV/u = 225.23 MeV [/tex]
I hope it helps you!
write the different between the fall of a parachute on earth and its fall on the moon?on what condition does a body have free fall?
Answer:
Shown from explanation
Explanation:
You have heard that expression what ever goes up must come down that's usually used to mean when you throw an object up, it comes down on its accord. This is due to a force on the earth that occurs in nature known as gravity.
So when an object falls under this influence it's said to fall freely.
Note not all heavenly bodies have gravitational pull, from experience by scientists who went to the moon they found out whatever goes up keeps flying endlessly so in that case an external force is needed to keep objects in the moon on ground level.
Hence the parachute falls on earth freely without an external force but on the moon it must fall with an external force inputed on the parachute system.
This means in the earth we have free fall but in the moon no such thing exist. So a body falls freely when there is gravity.
Standing on top of a building, Bob tosses a baseball straight up with an initial speed of 15 m/s. It takes 4.0 s for the ball to hit the ground. What is the vertical distance of the building? (g = -9.8 m/s²)
Answer:
48.26 m
Explanation:
time to goes up (till stop for a while in the air - maximum height)
vt = vo + a t
0 = 15 + g . t
0 = 15 + (-9.8) . t
9.8t = 15
t = 1.531 s
so the time left to goes down is
4.0 - 1.531 = 2.469 s
height from the top of building can find it by using
vo =√(2gh)
15 = √(2)(9.8).h
15² = 19.6h
h = 225/19.6 = 11.48 m
so the distance of maximum height to the ground is
t = √(2H/g)
2.469 = √(2H/9.8)
2.469² = 2H/9.8
6.096 = 2H/9.8
2H = 6.096 x 9.8 = 59.74 m
so the vertical distance of the building (or the building height's is)
H - h = 59.74 - 11.48 = 48.26 m
What is the magnitude of impulse of a 2.7 gram ping pong ball initially moving at 15 m/s, if hit by a ping pong paddle and then moves the opposite direction at 14/ms
Answer:
impulse = 0.0783 kg.m/s
Explanation:
The impulse is the product of the force and an interval of time. This can be represented in terms of the mass of the body and the change in the velocity of the body in such a time:
[tex]F\Delta t=m\Delta v[/tex] [tex]=|m(v_f-v_i)|[/tex]
m: mass of the body = 2.7gm = 0.0027 kg
vf: final velocity = -14m/s
vi: initial velocity = 15m/s
vf is negative because the direction of the ball is opposite to the initial direction:
[tex]|m(v_f-v_i)|=|(0.0027kg)(-14m/s-15m/s)|=0.0783\frac{kg.m}{s}[/tex]
hence, the impulse of the ping pong ball is 0.0783 kg.m/s
What are some advantages
and disadvantages to using
superconductors as electric
transmission lines
Answer:
Insulators show very high resistance to electricity. Conductors like copper show some resistance. Another class of materials show no resistance at all when cooled to very low temperatures, cooler than the coolest deep freezer. Called superconductors, they were discovered in 1911.
Explanation: i looked it up
The mass of an object is 50 kg. If its weight is 600N on a certain planet. Calculate the
gravitational field strength of the planet.,
Answer: The answer is 700kg
Explanation:
energy is the ability to___or___ matter
Energy is defined in science as the ability to move matter or change matter in some other way.
If a 5kg ball is rolling to the left and has a momentum of -25kg*m/s what is the velocity (not just speed) of the ball
Answer:
The velocity of the ball is 5 m/s to the left.
Explanation:
-25kg*m/s divided by 5 kg gives
speed of -5 m/s
The velocity of the ball is 5 m/s to the left.
When did Pangaea begin to break apart?
Answer:
Hey!
Well according to scientific data and analysis, it started to break up about 175 - 200 million years ago!!
Explanation:
HOPE THIS HELPS!!
Answer:
250 million (:
Explanation:
Which of these would not improve accuracy?
A)Taking a bigger sample size
B)Using a bigger range of the independent variable
C)Using measuring instruments that can read to a greater number of decimal places
D)Remove anomalies
Who is prime minister of india
His name is
Narendra Modi
Answer:
Hey!
*its kinda the wrong topic but ill answer anyway!!!*
The Prime Minister of India is...
Narendra ModiExplanation:
HOPE THIS HELPS!!
A remote controlled plane accelerates to a velocity of 21.0 m/s while covering a distance of 87.4 m in 6.11 s. What was the plane's initial velocity?
Answer:
7.61 m/s
Explanation:
Given:
Δx = 87.4 m
v = 21.0 m/s
t = 6.11 s
Find: v₀
Δx = ½ (v + v₀) t
87.4 m = ½ (21.0 m/s + v₀) (6.11 s)
v₀ = 7.61 m/s
71.6
Δx = 87.4 m
v = 21.0 m/s
t = 6.11 s
Find: v₀
Δx = ½ (v + v₀) t
87.4 m = ½ (21.0 m/s + v₀) (6.11 s)
v₀ = 7.61 m/s
A student with a mass of 66.0 kg climbs a staircase in 44.0 s. If the distance between the base and the top of the staircase is 14.0 m, how much power will the student deliver by climbing the stairs
[tex]power = 205.8 \: watt \\ solution \\ mass = 66 \: kg \\ time = 44 \: sec \\ distance = 14 \\ now \\ power = \frac{w}{t} \\ \: \: \: \: \: \: \: \: = \frac{f \times d}{t} \\ \: \: \: \: \: = \frac{m \times g \times d}{t} \\ \: \: \: \: \: \: = \frac{66 \times 9.8 \times 14}{44} \\ \: \: \: \: = \frac{9055.2}{44} \\ \: \: \: \: \: = 205.8 \: watt \\ hope \: it \: helps[/tex]
