Predict the magnitude of force applied on you if you push against a tree with a force of 50 and directed to the

Answers

Answer 1

Answer: -50N

Explanation:

Newton's 3rd law says that for every force applied, there is an opposite force with equal magnitude. The person pushing on the tree will experience a force of -50N


Related Questions

NEED HELP DUE AT 11:59!! A ball is thrown horizontally from the top of
a building 130 m high. The ball strikes the
ground 53 m horizontally from the point of
release.
What is the speed of the ball just before it
strikes the ground?
Answer in units of m/s.

Answers

Answer:

Since the ball was thrown horizontally, there was no vertical component in that force. and hence, the initial vertical velocity of the ball is 0 m/s and the initial horizontal velocity is r.

We are given:

initial velocity  (u) = 0 m/s     [vertical]

final velocity (v) = v m/s  [vertical]

time taken to reach the ground (t) = t seconds

acceleration (a) = 10 m/s/s   [vertical , due to gravity]

height from the ground (h) = 130 m

displacement (s) = 53 m [horizontal]

Solving for time taken:

From the third equation of motion:

s = ut + 1/2 at²

130 = (0)(t) + 1/2 * (10) * t²

130 = 5t²

t² = 26

t = √26 seconds  or   5.1 seconds

Final Horizontal velocity of the ball

Since the horizontal velocity of the ball will remain constant:

the ball covered 53 m in 5.1 seconds [horizontally]

horizontal velocity of the ball = horizontal distance covered / time taken

Velocity of the ball = 53 / 5.1

Velocity of the ball = 10.4 m/s

Answer:

51.51519 m/s

Explanation:

Given: [tex]a_{x} =0[/tex] [tex]a_{y} -g[/tex] [tex]v_{yo} =0[/tex] [tex]x_{o} =0[/tex] [tex]x=53[/tex][tex]y_{o} =130[/tex]

X-direction                           | Y-direction

[tex]x=x_{o} +v_{xo}t[/tex]                         | [tex]y=y_{o} +v_{yo}t+\frac{1}{2}a_{y}t^2[/tex]

[tex]53=0v_{xo}(5.15078)[/tex]                 | [tex]0=130+\frac{1}{2}(-9.8)t^2[/tex]

[tex]53=v_{xo} (5.15078)[/tex]                    | [tex]-130=-4.9t^2[/tex]

[tex]\frac{53}{5.15078} =v_{xo}[/tex]                             |  [tex]\sqrt{\frac{-130}{-4.9} }=\sqrt{t^2}[/tex]

[tex]10.2897=v_{xo}[/tex]                            | [tex]5.15078=t[/tex]

[tex]v=\sqrt{v_{y}^2+ v_{x}^2}[/tex]                            | [tex]v_{y}^2 =v_{yo}+2a_{y} d[/tex]

[tex]v=\sqrt{(50.27771)^2+(10.2897)^2}[/tex] | [tex]\sqrt{v_{y}^2} =\sqrt{2(-9.8)(0-130)}[/tex]

[tex]v=51.51519 m/s[/tex]                        | [tex]v_{y}=50.47771[/tex]

A cell contains 20% solute. If it is placed in a solution with 35% solute, what will happen to the cell?

Answers

i think it will shrink because it will loose or is loosing the water. I am not very sure but i have done my research

A 55-kg packing crate is pulled with constant speed across a rough floor with a rope that is at an angle of 40.0o above the horizontal. If the tension in the rope is 125 N, how much work is done on the crate to move it 5.0 m?

Answers

Answer:

478.75 J

Explanation:

W=force* displacement

constant speed= (a=0) net F=0

Horizontal component of tension

Tcosx

125Ncos40= 95.76 N

W= (95.76 N)(5 m)

=478.75 J

The work done in moving the crate across the given distance is 478.75 J.

The given parameters;

Mass of the packing create, m = 55 kgAngle of inclination of the rope, Ф = 40°Tension on the rope, T = 125 NDistance through which the crate is the moved, d = 5 m

The work done in moving the crate is the product of the horizontal component of the tension and the distance through which the crate is moved.

The work-done in moving the crate is calculated as;

W = Tcos(Ф) x d

W = 125cos(40) x 5

W = 478.75 J.

Thus, the work done in moving the crate across the given distance is 478.75 J.

Learn more here: https://brainly.com/question/19498865

answer fast plz
....................

Answers

Answer:

114 m/s

Explanation:

see the image below

how quickly a 0.4 ball.be accelerated if its struck by 12 N force?

Answers

Answer:

(assume moving in the positive direction, vi = + 20 m/s)

Explanation:

What are the Function of stand unit ​

Answers

Answer:

It is called the unit function because it is the identity element for Dirichlet convolution. It may be described as the "indicator function of 1" within the set of positive integers. It is also written as u(n) (not to be confused with μ(n), which generally denotes the Möbius function).

Electrically neutral objects become___when they or lose electrons.

Answers

If they lose an electron, that means they become more positive since an electron is negatively charged. So the answer is ‘positive’

Answer: positively charged

Explanation: basically when a neutral atom gets some electrons it becomes negatively charged and when a neutral atom loses elections it's positively charged Ik science is weird lol.

I hope this was the answer you were looking for.

A ball is thrown straight upward with an initial velocity of 16m/s. What is its velocity at its highest point?

Answers

Answer:

its going very fast

Explanation:

A black widow spider hangs motionless from a web that extends vertically from the ceiling above. If the spider has a mass of 1.81 g, what is the tension in the web?
N=

Answers

Answer:

The tension in the web is 0.017738 N

Explanation:

Net Force

The net force exerted on an object is the sum of the vectors of each individual force applied to an object.

If the net force equals 0, then the object is at rest or moving at a constant speed.

The spider described in the question is hanging at rest. It means the sum of the forces it's receiving is 0.

A hanging object has only two forces: The tension of the supporting string (in our case, the web) and its weight. If the object is in equilibrium, the tension is numerically equal to the weight:

T=W=m.g

The mass of the spider is m=1.81 gr = 0.00181 Kg, thus the tension is:

[tex]T = 0.00181\ Kg\cdot 9.8\ m/s^2[/tex]

[tex]T=0.017738\ N[/tex]

The tension in the web is 0.017738 N

The day time temperature of Mercury is 800 F . What is Mercury’s temperature in Celsius and kelvin?

Answers

Answer:

In Celsius it is 426.667

In Kevin it is 699.817

Explanation:

A car of mass 500kg travelling at 60m/s has it speed reduced to 40m/s by a constant breaking force over a distance of 200m. find car initial kinetic energy. the final kinetic energy​

Answers

Answer:

Ek1 = 900000 [J]

Ek1 = 400000 [J]

Explanation:

In order to solve this problem we must remember that kinetic energy is defined as the product of mass by velocity squared by a medium. Therefore using the following equation we have:

[tex]E_{k1}=\frac{1}{2}*m*v1^{2}[/tex]

where:

m = mass = 500 [kg]

v1 = 60 [m/s]

So we have:

Ek1 = 0.5*500*(60^2)

Ek1 = 900000 [J]

and:

Ek2 = 0.5*500*(40^2)

Ek2 = 400000 [J]

blank refers to the method of spreading fertilizer evenly over the entire field by hand it is done at the blank stage

Answers

Answer:

Broadcasting is the method, not sure about the stage it is done in

Explanation:

Answer:

Broadcasting is the first (blank) second (blank) is Cultivation.

Explanation:

I took the test & got this answer correct.

The suffix used to name a monatomic anion is
O A. ite
O B. ide
O C. anion
O D. ate

Answers

The answer is B.ide I looked it up on google hope this help and sorry if it was late
The answer is B . Just took the quiz. IDE

You are piloting a General Aviation aircraft (e.g. Cessna 172) over the Georgia Tech campus in level flight at 3000 ft altitude. Your airspeed indicator shows that the true airspeed is 100 knots. You have trimmed the aircraft to have no sideslip and pitch angle at a 3 degree angle of attack. Your magnetic compass (which is uncorrected for magnetic variation) indicates that you are flying in the direction of local magnetic East. A local weather forecast predicted the winds to be steady at 10 knots coming exactly from the northeast direction at the time you took off.
a. Using the information provided above and any additional information you may require (state what it is), determine your aircraft's north and east velocity components, Vn and ve, in knots. Starting from Tech Tower at t = 0, you continue in this direction and you are planning to fly directly over a local VOR beacon exactly 10 minutes later. However, you note that you don't pass directly over the beacon and after 10 minutes and 15 seconds have elapsed you are exactly 300 meters away from the VOR beacon in the Easterly direction.
b. Assuming the discrepancy is attributable only to wind speed, estimate the actual average wind speed components, Vwind-n and Vwind-e in knots. Use a flat Earth approximation.
c. Based on the instruments you are using, describe 3 common causes of measurement error that could affect the output of either sensor.

Answers

Answer:

a)  vₓ = 100 + 7.07 = 107.07 knot     (East) ,   v_{y} = 7.07 knot            (North)

b) v_wind_ North = 0 ,   v_wind_West = 61.12 knot      (West)

Explanation:

a) This is a vector velocity addition problem, they tell us that the plane goes East at 100 Knots and the wind goes North East at 10 Knots

the components ask the total speed of the plane.

For this we decompose the wind speed

            cos 45 = v₂ₓ / V₂

            sin 45 = [tex]v_{2y}[/tex] / v₂

            v₂ₓ = v₂ cos 45

           v_{2y} = v₂ sin 45

            v₂ₓ = 10 cos 45 = 7.07 m / s

            v_{2y} = 10 sin45 = 7.07 m / s

the speed of the plane is

            vₓ = v_plane + v₂ₓ

            v_{y} = v_{2y}

            vₓ = 100 + 7.07 = 107.07 knot     (East)

            v_{y} = 7.07 knot            (North)

speed is

            v = (107.07 i ^ + 7.07 j ^) knot

b) Estimated time for Target VOR t = 10 min

for a time of t = 10 min and 15 s, it is at a distance of d = 300 m from the VOR in an easterly direction

find the average speed of time on the ride

in the North direction there is no deviation so the average wind speed is zero

            v_wind_ North = 0

In the east direction

as the estimated time was 10 min and the real time for the distance is 10 min 15 s

the time difference is t = 15 s to travel d = 300 m

with these data we can calculate the speed of the plane

              v = x / t

              v = 300/15

              v = 20 m / s

let's reduce this speed to knot

             v_real = 20 m / s (1knot / 0.5144 m / s) = 38.88 knots

therefore the wind speed is

              v_tral = v_plane + v_wind_Este

              v_wind_Este = v_real - v_avión

               v_wind_Este = 38.88 - 100

                v_wind_Este = -61.12 knot

the negative sign indicates that the wind is going west

                v_wind_West = 61.12 knot (West)

3)

* The compass is not calibrated, to correct the magnetic deviation, therefore it gives an appreciable error in the direction

* The wind speed is taken when leaving, but there is no constant monitoring, so a change in direction or wind speed in the trajectory can significantly affect the results.

* The aircraft may noir throughout the trajectory at level, due to pitch errors

The mass of proton is 1.67x10 kg. How many protons will make a mass of
1,00kg?
1011

Answers

Answer: 938

Explanation:

1.67x10^-27kg (938V/c2)

43. The particle consists of fast moving electrons is.​

Answers

Answer:

Explanation: someone help me please you want free points right

when an objects motion is not changing , the object is moving at a ___

Answers

I’m gonna say it’s No Speed. Hope this helps!

Where do laws apply?​

Answers

Anywhere inside the boundaries of the country you are in

Answer: Statutes are laws created by the legislative branch through the lawmaking process. Statutes are written, discussed, argued and voted on in Congress or in the legislature of a state. The courts then apply and interpret these statutes on a case by case basis.

happy to help ☀️keep on shining☀️

Explanation:

I will give you branilest


How do two interacting objects exert equal and opposite forces on each other when they collide, even though they have different masses?

Claim:


Evidence:


Reasoning:

Answers

Answer:

ok can u m a e the question make more sense like break ot down cs i wanna give u a answer but i dont really understand the question

What feature does not require a planet to have any particular characteristics?
Stream Beds
Dunes
Impact Craters
Volcanic Lava Flows
What is the correct answer?

Answers

Answer:

Impact Craters.

Explanation:

An impact crater can be defined as a circular depression that is caused by impact on any planet or asteroids or any other celestial body's surface. When smaller body in galaxy impacts these larger bodies, they form a circular depression on it's surface.

This is a major feature found in solid object such as the Moon, Mercury, etc.

Therefore, the feature that a planet does not require is an impact crater. As other features are important to define a planet. Thus correct option is C.

A cannon is fired straight up into the air. If the cannon ball comes back down to the launch point in 5 seconds, what was the maximum height reached by the ball? ​

Answers

Answer:

30.63 m

Explanation:

From the question given above, the following data were obtained:

Total time (T) spent by the ball in air = 5 s

Maximum height (h) =.?

Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:

Total time (T) spent by the ball in air = 5 s

Time (t) taken to reach the maximum height =.?

T = 2t

5 = 2t

Divide both side by 2

t = 5/2

t = 2.5 s

Thus, the time (t) taken to reach the maximum height is 2.5 s

Finally, we shall determine the maximum height reached by the ball as follow:

Time (t) taken to reach the maximum height = 2.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =.?

h = ½gt²

h = ½ × 9.8 × 2.5²

h = 4.9 × 6.25

h = 30.625 ≈ 30.63 m

Therefore, the maximum height reached by the cannon ball is 30.63 m

why did Iran experience almost 80 times more deaths in the 20th Century than California, despite having the same seismicity?

Answers

Answer: poor construction of houses

Explanation:

Majority of the people that died in Iran were as a result of poor building methods coupled with the fact that there was lack of proper regulation.

California experienced a similar earthquake but due to safer construction methods, about three people died.

Due to population boom in Iran and house shortage, this resulted in builders building cheap houses which were not strong enough.

A system of 18 electrons and 11 neutrons has a net charge of

Answers

Answer:

-28.8 × 10-19 C

The displacement of an object moving 330 km North for 2 hours and an additional 220 km North for 5 hours is?

Answers

Answer:

Usbe

Explanation:

Before the development of quantum theory, Ernest Rutherford's experiments with gold atoms led him to propose the so-called Rutherford Model of atomic structure. The basic idea is that the nucleus of the atom is a very dense concentration of positive charge, and that negatively charged electrons orbit the nucleus in much the same manner as planets orbit a star. His experiments appeared to show that the average radius of an electron orbit around the gold nucleus must be about 10−1010−10 m. Stable gold has 79 protons and 118 neutrons in its nucleus.
What is the strength of the nucleus' electric field at the orbital radius of the electrons?
What is the kinetic energy of an electron in a circular orbit around the gold nucleus?

Answers

Answer:

a)    F = -1.82 10⁻¹⁵ N,  b) K = 9.1 10⁻¹⁶ J

Explanation:

a) To calculate the force between the nucleus and the electrons, let's use the Coulomb equation

           F = k q Q / r²

as the nucleus occupies a very small volume compared to electrons, we can suppose it as punctual

let's calculate

          F = 9 10⁹ (-1.6 10⁻¹⁹) (79 1.6 10⁻¹⁹) / (10⁻¹⁰)²

          F = -1.82 10⁻¹⁵ N

b) they ask us for kinetic energy

let's use Newton's second law

         F = m a

acceleration is centripetal

         a = v² / r

we substitute

         F = m v² / r

         v = √ (F r / m)

         v = √ (1.82 10⁻¹⁵ 10⁻¹⁰ / 9.1 10⁻³¹)

         v = √ (0.2 10⁻¹⁶)

         v = 0.447 10⁸ m / s

kinetic energy is

          K = ½ m v²

          K = ½ 9.1 10⁻³¹ (0.447 10⁸)²

          K = 0.91 10⁻¹⁵ J

          K = 9.1 10⁻¹⁶ J

Based on what you learn about gravity describe why objects float in outer space

Answers

Answer:

Objects float in outer space because there is no gravitational force. The farther you get from earth, the less gravity.

Explanation:

Answer:

they float do to gravity

Explanation:

here if you tossed a ball in the air it would come back down fast in space however it would only float up and stay do to gravity

Place a small object on the number line below at the position marked zero. Draw a circle around the object. Mark the center of this circle with the symbol for “initial position”. Move the object 5.0cm to the right and stop. Label this circle with the correct symbol for “final position.”







(A) What was the initial position of the object?    

(B) What is the final position of the object?    

(C) What is the distance traveled by the object?    

(D) What is the displacement of the object?    

(E) Of the three underlined quantities, which are numerically equal?


Answers

Can you post a picture of the whole thing please

a force of magnitude 30 n stretches a spring 0.83 m from equilibrium. what is the value of the spring constant?

Answers

Answer:

36 N/m

Explanation: I got the answer right on the test ight noo cap

What is the momentum of a 20.0 kg scooter traveling at 5.00 m/s?

Answers

Answer:

The answer is 100 kgm/s

Explanation:

To find the momentum of an object given it's mass and velocity we use the formula

momentum = mass × velocity

From the question

mass = 20 kg

velocity = 5 m/s

We have

momentum = 20 × 5

We have the final answer as

100 kgm/s

Hope this helps you

Which of the following is true as a ball that was thrown straight up into the air is traveling up?
A. The acceleration is upward until it stops and the acceleration becomes downward. The object is also slowing down as it rises.
B. The acceleration is downward as the object moves up. This causes the object to slow down until it stops and then speed up as it falls down.

Answers

Answer:

b

Explanation:

when a ball falls from the sky, it falls down fast due to no friction.

The answer should be B.
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