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Answer:

x=50

Explanation:

Answer:

vertically opposite angles are equal

Explanation:

so

2x+30=3x-20

2x-3x= -20-30

-1x= -50

so x is 50

as minus gets cancelled both sides.

HOPE IT HELPS YOU

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Answer:

B.

I think.

Explanation:

Mars doesn't have that much of an atmosphere!

Have a great day!

Answer:

I think it's 5000N

Explanation:

You use the formula F=a.m, so m=10 meters, a=500 joules. F=10x500=5000N

Answer:

A

Explanation:

Given that two balls are in motion. A 2-kg ball moving at 4m/s and a 4-kg ball moving at 2m/s, which one has greater kinetic energy? a. 2 kg ball moving at 4 m/s c. Both balls have the same KE b. 4 kg ball moving at 2 m/s d. Cannot be determined

The formula for kinetic energy is :

K.E = 1/2mv^2

A 2-kg ball moving at 4m/s will have kinetic energy of 1/2 × 2 × 4^2

K.E = 16J

and a 4-kg ball moving at 2m/s will have kinetic energy of 1/2 × 4 × 2^2

K.E = 2 × 4

K.E = 8J

which one has greater kinetic energy? Definitely it is a 2 kg ball moving at 4 m/s. Since 16J is greater than 8J. The correct answer is A.

The energy which we obtained from the moving particle is called kinetic energy.  According to the conservation of energy, the energy can neither be created nor be destroyed.

Hence, the formula used in the question is:- [tex]K.E =\frac{1}{2} mv^{2}[/tex] .

Therefore, the kinetic energy of the ball moving the 2kg is 16J.

Hence the Kinetic energy of the ball moving the 4 kg is 8J.

For more information, refer to the link:-

https://brainly.com/question/12669551

Answer:

6000pa

Explanation:

force= 2400N

area= 0.4m

pressure=?

now,

p= f/a

p= 2400/ 0.4

therefore,P=6000 pa.

I think that you need the gravitational acceleration of mercury

so we will use Newton's gravitational law :

gravitational acceleration = [tex]\frac{G * m}{r^{2} }[/tex]

G is the gravitational constant = G = 6.673×10^-11 N m^2 kg^-2

after substitution :

6.673×10^-11 * 3.2x10^23 / (2.43x10^6)^2

using calculator :

gravitational acceleration of mercury = 3.61625 m/s^2

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Answer:

I believe the answer is B.)

Answer:

6km

Explanation:

3hours X 2km = 6 kilometres

Answer:

The answer is B. 8000.

Explanation:

She gained 10,000J , but when she reached the bottom she was at 2,000J. All you need to do is 10,000-2,000 and you get 8,000. So the answer is 8,000J.

Answer:

A

Explanation

The diagram in A. contain a variable resistor which can be use to vary the pd from the 6v battery

Answer: 1-5 so A

Explanation:

if u just look at a diagram of like the moons it says that

The moon changes shape every day the changes in their shape are defined as the moon phase. In positions 1 and 5 first-quarter moon and last quarter moon appear to an observer on Earth.

The moon changes shape every day. This is due to the fact that the celestial body has no light of its own and can only reflect sunlight.

Only the side of the moon facing the sun can reflect this light and seem bright. On the opposite side appears black is a full moon.

We can only see the black section when it lies between the sun and the earth when a new moon occurs. We witness intermediate phases like a half-moon and crescent in between these two extremes.

The moon changes shape every day the changes in their shape are defined as the moon phase.

In general, we may estimate the third by knowing any two of the following three things

(1) the moon's position in the sky

(2) the moon phase

(3) the time

Hence in positions 1 and 5 first-quarter moon and last quarter moon appear to an observer on Earth.

To learn more about the moon's phase refer to the link;

https://brainly.com/question/2285324

[tex]ek = \frac{1}{2}m {v}^{2} [/tex]

[tex]ek = \frac{1}{2}(50) {(1)}^{2} [/tex]

[tex]ek = \frac{1}{2}(50)[/tex]

[tex]ek = 25j[/tex]

//

I'm not really sure but I do know that it's not 0 because the object is still moving, even if it's only moving at 1 m/s.

The gravitational potential energy associated with the plane is 2.36 x [tex]10^{5}[/tex] J

Gravitational potential energy is energy an object possesses because of its position in a gravitational field.

It is given by P.E = mgh

where m = mass

g= acceleration due to gravity

h = height of the object

Here,

h = 1.45km  = 1450 m

P.E = 3.36 x [tex]10^{9}[/tex] J

g = 9.8m/[tex]s^{2}[/tex]

therefore, m = P.E/ gh = (3.36 x [tex]10^{9}[/tex]s J)/ 9.8 x 1450

m = 2.36 x [tex]10^{5}[/tex]

Hence mass of the airplane is 2.36 x [tex]10^{5}[/tex]

To know more about gravitational potential energy here

https://brainly.com/question/19768887

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Explanation:

[tex]b = m \div v \\ 80 \div 30 \times 10 { -}^{2} [/tex]

Answer:

I think it electrical energy to kinetic energy

The isotopes of any element have same number of protons inside them.

Cadmium is a chemical element with the symbol Cd and atomic number 48. It is soft, silvery and white metal.

Given is about Cadmium that it has eight naturally occurring isotopes.

Isotopes are the atoms of the same element which have same number of protons in them but the number of neutrons are different. Isotopes usually have same chemical properties, but they have different physical properties. Their can be stable and unstable isotopes. These unstable isotopes are also called radioisotopes, since they emit radiation. Thus, the isotopes have same number of protons.

Therefore, the isotopes of any element have same number of protons inside them.

To solve more questions on isotopes, visit the link below-

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Answer:

An earthquake is a sudden shaking movement of the surface of the earth. It is known as a quake, tremblor or tremor. Earthquakes can range in size from those that are so weak that they cannot be felt to those violent enough to toss people around and destroy whole cities. ... An earthquake is measured on Richter's scale.

Answer:

c

Explanation:

bnbbbn nbnbnb bbbb bnbb

Answer:

- 0.0481666 °C^-1

Explanation:

Linear expansivity of brass, α

α = (2T - 2T0) / T0.dt

T0 = 30°

dt = change in temperature = 30 - 10 = 20°C

T = 15.55 sec

α = (2*15.55 - 2*30) / 30*20

α = (31.1 - 60) / 600

α = - 28.9 / 600

α = - 0.0481666 °C^-1

Answer:

D

Explanation:

The bowling ball has a greater mass, so there's more stuff for gravity to act on. In that sense, gravity is pulling on it more. But it still doesn't fall any faster

Answer:

D: The acceleration of the gold ball will be greater than that of the bowling ball.

Hopefully this is right

Explanation:

The ball is lighter and bowling ball is heavy

Answer:

U-235

Explanation:

a rare needed compound

The answer is C, 5.2

Answer:

just awnsered this one your awnser is the the second option

Answer:

answer one

Explanation:

Answer:The answer is C

Explanation:

Answer:

you know the answer i answered it before on a question 0-0

Explanation:

Answer:

The answer is B.

Barnard’s star, Sun, Altair, Achernar

Explanation:

Remember the brighter the star the higher the temperature, Red being the oldest of the stars orange middle age, white stars ( getting to its ends can be also a dwarf star), and blue star being the youngest of the stars Also blue is the hottest star

Answer:

B

Explanation:

Answer:

The ball would hit the floor approximately [tex]0.55\; \rm s[/tex] after leaving the table.

The ball would travel approximately [tex]5.5\; \rm m[/tex] horizontally after leaving the table.

(Assumption: [tex]g = 9.81\; \rm m \cdot s^{-2}[/tex].)

Explanation:

Let [tex]\Delta h[/tex] denote the change to the height of the ball. Let [tex]t[/tex] denote the time (in seconds) it took for the ball to hit the floor after leaving the table. Let [tex]v_0(\text{vertical})[/tex] denote the initial vertical velocity of this ball.

If the air resistance on this ball is indeed negligible:[tex]\displaystyle \Delta h = -\frac{1}{2}\, g\, t^{2} + v_0(\text{vertical}) \cdot t[/tex].

The ball was initially travelling horizontally. In other words, before leaving the table, the vertical velocity of the ball was [tex]v_0(\text{vertical}) = 0 \; \rm m \cdot s^{-1}[/tex].

The height of the table was [tex]1.5\; \rm m[/tex]. Therefore, after hitting the floor, the ball would be [tex]1.5\; \rm m \![/tex] below where it was before leaving the table. Hence, [tex]\Delta h = -1.5\;\rm m[/tex].

The equation becomes:

[tex]\displaystyle -1.5 = -\frac{9.81}{2} \, t^{2}[/tex].

Solve for [tex]t[/tex]:

[tex]\displaystyle t = \sqrt{1.5 \times \frac{2}{9.81}} \approx 0.55[/tex].

In other words, it would take approximately [tex]0.55\; \rm s[/tex] for the ball to hit the floor after leaving the table.

Since the air resistance on the ball is negligible, the horizontal velocity of this ball would be constant (at [tex]v(\text{horizontal}) =10\; \rm m \cdot s^{-1}[/tex]) until the ball hits the floor.

The ball was in the air for approximately [tex]t = 0.55\; \rm s[/tex] and would have travelled approximately [tex]v(\text{horizontal})\cdot t \approx 5.5\;\rm m[/tex] horizontally during the flight.