Pls help me, I don't know how to do it?:(​

Answer and Step-by-step explanation:

Alot of these can be solved with the table up above the problems.

According to the table, every time a value has an exponent of 0, it would equal to 1. Since all A B and C values follow the 0 exponent, their value is 1.

According to the table, when we have a negative exponent, the number gets turned into a fraction of [tex]\frac{1}{x^x}[/tex]

Since our value is 9^-2, do as followed :

[tex]\frac{1}{9^2}[/tex]

Solve what is 9^2 :

[tex][\frac{1}{81} ][/tex]

[tex]\frac{1}{x^{-5} }[/tex]

This question is different, since we have to go backwards, we have to switch the negative exponent to a positive exponent and rid the fraction.

[tex]x^5[/tex]

[tex]5a^3b^{-2}[/tex]

Since we have one negative exponent, follow the fraction rule but instead of having one as the numerator, have 5a^3.

[tex]\frac{5a^3}{b^{2}}[/tex]

[tex]-3^4 = -3*-3*-3*-3=-81[/tex]

Since -3 is in parenthesis, we can rid the negative along with the parenthesis :

[tex](-3)^4=3^4=3*3*3=81[/tex]

Follow the negative exponent rule :

[tex](-3)^{-4}=\frac{1}{(-3)^4} =\frac{1}{3^4} =\frac{1}{3*3*3*3}= \frac{1}{81}[/tex]

Follow the negative exponent rule yet again :

[tex]-3^{-4}=-\frac{1}{3^4} =-\frac{1}{3*3*3*3} =-\frac{1}{81}[/tex]

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PLEASEEEEEEEE HELPPPPPPPPP I WILL GIVE BRAINLIEST

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(ONLY TWO CAPITAL LETTERS) Please answer correctly !!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!! URGENT

Please help me with this first answer gets brainliest

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SOLUTION

my

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Ill give u brainliest if you help me tyy

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I’ll mark as brainliest.