Please someone help me with steps!

[tex] {8x}^{0} \\( {8 \times 0})^{0} \\ {0}^{0} \\ it \: is \: undefined[/tex]

PLEASE GIVE BRAINLIEST

Answer:

[tex]2x^{2}[/tex] - 16x + 14

Step-by-step explanation:

(2x - 4)(x - 6)

= (2x + −4)(x + −6)

= (2x)(x) + (2x)(−6) + (−4)(x) + (−4)(−6)

= [tex]2x^{2}[/tex] − 12x − 4x + 24

= [tex]2x^{2}[/tex] - 16x + 14

the answer should be 5 inches I guess

Answer:

                                  [tex]f^{\prime}\left(x\right)\ =\ -\frac{65}{2}x^{\frac{11}{2}}\ +\frac{49}{2}x^{-\frac{9}{2}}[/tex]

or

                                  [tex]f^{\prime}\left(x\right)\ =\ -32.5x^{5.5}\ +\ 24.5x^{-4.5}[/tex]

Step-by-step explanation:

Rather than solving this question in a more complex method by directly using the product rule and quotient rule, it can first be considered to perform some algebraic manipulation (index laws) to simplify the expression before taking the derivative.

                                       [tex]\begin{large}\begin{array}{l}f\left(x\right)\ =\ -5x^6\ \sqrt{x}\ +\ \frac{-7}{x^3\ \sqrt{x}}\\\\f\left(x\right)\ =\ -5x^6\cdot x^{\frac{1}{2}}\ +\ \frac{-7}{x^3\cdot x^{\frac{1}{2}}}\\\\f\left(x\right)\ =\ -5x^{6\ +\ \frac{1}{2}}\ +\ \frac{-7}{x^{3\ +\ \frac{1}{2}}}\\\\f\left(x\right)\ =\ -5x^{\frac{13}{2}}\ +\ \frac{-7}{x^{\frac{7}{2}}}\\\\f\left(x\right)\ =\ -5x^{\frac{13}{2}}\ -7x^{-\frac{7}{2}}\end{array}[/tex]

Now, the derivative of the function can be calculated simply by only using the power rule, which yields

                   [tex]\begin{large}\begin{array}{l}f\left(x\right)\ =\ -5x^{\frac{13}{2}}\ -7x^{-\frac{7}{2}}\\\\f^{\prime}\left(x\right)\ =\ \left(-5\right)\left(\frac{13}{2}\right)\left(x^{\frac{13}{2}\ -\ 1}\right)\ -\ \left(7\right)\left(-\frac{7}{2}\right)\left(x^{-\frac{7}{2}\ -\ 1}\right)\\\\f^{\prime}\left(x\right)\ =\ -\frac{65}{2}x^{\frac{11}{2}}\ +\frac{49}{2}x^{-\frac{9}{2}}\\\\f^{\prime}\left(x\right)\ =\ -32.5x^{5.5}\ +\ 24.5x^{-4.5}\end{array}\\\end{large}[/tex]

Answer:

Using the formula multiplicity, we find that the equation of the function will be [tex]f(x)=-(x+6)^{3} (x-2)^{4}[/tex]. The graph is in the attachment.

Step-by-step explanation:

Concept: Given that for -6, multiplicity is 3 and for 2 multiplicity is 4.

So, the equation of multiplicity is represented as:

[tex]f(x)=a(x-root)^{mutliplicity}[/tex]

This gives the following function

[tex]f(x)=a(x+6)^{3} (x-2)^{4}[/tex]

The equation has a negative leading coefficient.

This means that, the value of a is less than 0 i.e. a < 0

Assume any value of a (say a = -1), the equation becomes

[tex]f(x)=-(x+6)^{3} (x-2)^{4}[/tex]

The graph is in the attachment.

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Answer:

C

Step-by-step explanation:

trust bro

Answer:

When x = 10, they will both be y = 60

(10, 60)

Step-by-step explanation:

2(10) + 40 = 60

4(10) + 20 = 60

Answer:

x = 10

Step-by-step explanation:

2 (10) +40 = 60

4(10) +20 = 60

Using it's concept, it is found that the domain of the function is given as follows:

d. 0 < c ≤ 15

The domain is the set that contains all possible input values for the function.

He is losing weight consistently, hence c > 0, and the maximum amount is of 15 calories, hence c ≤ 15 and the domain is given by:

d. 0 < c ≤ 15

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The total price of the truck =$x + $ 0.13x

We have given that,

Camacho is buying a monster truck. The price of the truck is x dollars, and he also has to pay a 13%, percent monster truck tax.

We have to determine the expressions that could represent how much Camacho pays in total for the truck.

We will consider the price of the truck to be $x

And the amount of tax in the percentage would be 13%

13/100 = $ 0.13x (this is the actual amount of the tax)

Now we will calculate the total price of the truck =$x + $ 0.13x

= $ x(1 + 0.13)

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Answer:

11/200

Step-by-step explanation:

Convert the percentage to a fraction by placing the expression over

100

Percentage means 'out of 100

5.5

100

Convert the decimal number to a fraction by shifting the decimal point in both the numerator and denominator. Since there is

1

number to the right of the decimal point, move the decimal point

1

place to the right.

55

1000

Cancel the common factor of

55

and

1000

11/200

Answer:

48 cm²

Explanation:

The figure can be cut into 1 rectangle and 1 triangle.

Area of the figure:

⇒ area of rectangle + area of triangle

⇒ Length × Width  +  1/2 × Base × Height

⇒ 6 × 4  +  1/2 × 6 × 8

⇒ 24  +  24

⇒ 48

Therefore, area of figure is 48 cm².

Answer:

48 cm squared

Step-by-step explanation:

The given figure is composed of a rectangle (L=6 cm and W = 4 cm) and a right angled triangle { Base = (12- 4) = 8 cm, height = 6 cm. }

Area of the two figures is to be calculated separately and then added to get the required result.

Area of the rectangle = l × w

= 6 × 4

= 24 cm²

Area of the right triangle = ½ × base × height

= ½ × 8 × 6

= 24 cm²

Hence, area of the given figure = 24 + 24

= 48 cm squared.

If the geometric series has first term [tex]a[/tex] and common ratio [tex]r[/tex], then its [tex]N[/tex]-th partial sum is

[tex]\displaystyle S_N = \sum_{n=1}^N ar^{n-1} = a + ar + ar^2 + \cdots + ar^{N-1}[/tex]

Multiply both sides by [tex]r[/tex], then subtract [tex]rS_N[/tex] from [tex]S_N[/tex] to eliminate all the middle terms and solve for [tex]S_N[/tex] :

[tex]rS_N = ar + ar^2 + ar^3 + \cdots + ar^N[/tex]

[tex]\implies (1 - r) S_N = a - ar^N[/tex]

[tex]\implies S_N = \dfrac{a(1-r^N)}{1-r}[/tex]

The [tex]N[/tex]-th partial sum for the series of reciprocal terms (denoted by [tex]S'_N[/tex]) can be computed similarly:

[tex]\displaystyle S'_N = \sum_{n=1}^N \frac1{ar^{N-1}} = \frac1a + \frac1{ar} + \frac1{ar^2} + \cdots + \frac1{ar^{N-1}}[/tex]

[tex]\dfrac{S'_N}r = \dfrac1{ar} + \dfrac1{ar^2} + \dfrac1{ar^3} + \cdots + \dfrac1{ar^N}[/tex]

[tex]\implies \left(1 - \dfrac1r\right) S'_N = \dfrac1a - \dfrac1{ar^N}[/tex]

[tex]\implies S'_N = \dfrac{1 - \frac1{r^N}}{a\left(1 - \frac1r\right)} = \dfrac{r^N - 1}{a(r^N - r^{N-1})} = \dfrac{1 - r^N}{a r^{N-1} (1 - r)}[/tex]

We're given that [tex]a=1[/tex], and the sum of the first [tex]n[/tex] terms of the series is

[tex]S_n = \dfrac{1-r^n}{1-r} = 364[/tex]

and the sum of their reciprocals is

[tex]S'_n = \dfrac{1 - r^n}{r^{n-1}(1 - r)} = \dfrac{364}{243}[/tex]

By substitution,

[tex]\dfrac{1 - r^n}{r^{n-1}(1-r)} = \dfrac{364}{r^{n-1}} = \dfrac{364}{243} \implies r^{n-1} = 243[/tex]

Manipulating the [tex]S_n[/tex] equation gives

[tex]\dfrac{1 - r^n}{1-r} = 364 \implies r (364 - r^{n-1}) = 363[/tex]

so that substituting again yields

[tex]r (364 - 243) = 363 \implies 121r = 363 \implies \boxed{r=3}[/tex]

and it follows that

[tex]r^{n-1} = 243 \implies 3^{n-1} = 3^5 \implies n-1 = 5 \implies \boxed{n=6}[/tex]

D. 12.5

The equation to find the average rate of change is

[tex] \frac{y2 - y1 }{x2 - x1} [/tex]

To find the average rate of change between points (0,20) and (8,120) you need to plug it into the equation so it'll be

[tex] \frac{120 - 20}{8 - 0} [/tex]

this simplifies to

[tex] \frac{100}{8} [/tex]

which is 12.5

Answer:

[tex]sec(\theta)=\frac{2}{\sqrt3}[/tex]

Step-by-step explanation:

Given [tex]sin(\theta)=\frac{1}{2}[/tex] , to find [tex]sec(\theta)[/tex], it will be helpful to visualize a right triangle (triangle with a 90 degree angle) associated with that particular θ.  There are a few ways to go about this:

All of the basic trigonometric functions, applied to an angle) are a ratio of two specific sides of any right triangle that holds that angle.

Remember that the Sine of an angle is defined specifically, the ratio of the opposite side (the side across from the angle in the Sine function), and the hypotenuse (the side across from the right angle).  You might remember this through SohCahToa

[tex]sin(\theta)=\frac{opp}{hyp}[/tex]

In our case, since [tex]sin(\theta)=\frac{1}{2}[/tex] , so  [tex]\frac{opp}{hyp}=\frac{1}{2}[/tex] .  While there are an infinite number of triangles that have that ratio of those sides, they are all "similar" triangles (corresponding angles congruent, and corresponding sides are proportional, yielding common ratios of sides), and for ease, we can consider simply the triangle where the value of the numerator is the length of the opposite side, and the value of the denominator is equal to the hypotenuse.  So, [tex]opp=1[/tex], and [tex]hyp=2[/tex].

While we haven't actually talked about θ yet, we can still set up the triangle that has these sides so that we can visualize what the triangle looks like. (see image)

This triangle represents the triangle for the unknown θ in the original sine function.  We're tasked with finding the secant of that particular unknown θ.

Working toward Secant

Here, it will be helpful to remember either the reciprocal identities for[tex]sec(\theta)=\frac{1}{cos(\theta)}[/tex], or the definition of the secant function [tex]sec(\theta)=\frac{hyp}{adj}[/tex].

I find that most people remember the reciprocal identities more easily than keeping track of the definitions, so, since secant is related to cosine, it will be important to remember that [tex]cos(\theta)=\frac{adj}{hyp}[/tex].  From there, take the reciprocal of the cosine-value to get the secant-value (which matches the definition of the secant function).

Either way, it comes down to knowing the lengths of the side adjacent to theta, and the hypotenuse.  We already know the length of the hypotenuse, so we just need the length of the adjacent side.

Applying the Pythagorean Theorem

Fortunately, because it is a right triangle, the Pythagorean Theorem applies: [tex]a^{2} +b^{2} =c^{2}[/tex]  (where c is the length of the hypotenuse, and a & b are the lengths of the legs)

Substituting the known values for the sides we do know...[tex](adj)^{2} +(1)^{2} =(2)^{2}\\(adj)^{2} +1 =4[/tex]

...isolating "adj" by subtraction...

[tex](adj)^2=4-1\\(adj)^2=3[/tex]

...applying the square root property...

[tex]adj=\sqrt{3}[/tex]  or  [tex]adj=-\sqrt{3}[/tex]

Identifying which Quadrant the triangle is in

Since we were given that [tex]0^o < \theta < 90^o[/tex], our triangle is an acute triangle (as drawn in the diagram), and is in quadrant I (indicating that both legs will be measured with a positive value.

Thus, we discard the negative solution and conclude that [tex]adj=\sqrt{3}[/tex].

Finding the final solution

From there, [tex]cos(\theta)=\frac{adj}{hyp}[/tex] implies [tex]cos(\theta)=\frac{\sqrt3}{2}[/tex], and through the reciprocal relationship (or simply the definition of secant, whichever is easier for you to remember), [tex]sec(\theta)=\frac{2}{\sqrt3}[/tex]

Note:  This method did not require knowing what the angle θ was.

If you know well the values of special triangles in the unit circle, you may have identified that [tex]sin(\theta)=\frac{1}{2}[/tex]  is associated with [tex]\theta=30^o[/tex].  If so, if you also recall that the ordered pair associated with that point on the unit circle is [tex](\frac{\sqrt3}{2} ,\frac{1}{2} )[/tex], and that the [tex]cos(\theta)=x\text{-coordinate on the unit circle}[/tex], then you can quickly identify that  [tex]cos(\theta)=\frac{\sqrt3}{2}[/tex].

This method still ends the same: recalling the reciprocal relationship between cosine and secant, giving [tex]sec(\theta)=\frac{2}{\sqrt3}[/tex].

The values that are part of the solution are x = -5 and x = -4.5

Number lines are lines that are used to represent the solution to inequalities.

From the given number line with he solution x > -4, this shows that all the solutions must be values that are greater than -4.

The values that are part of the solution are x = -5 and x = -4.5

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Answer:

78.7

Step-by-step explanation:

To find the mean, we can do the sum of all scores divided by the total amount of scores.

We see that there are 7 scores of 70, and 70*7=490.

We see that there are 5 scores of 75, and 75*5=375.

We see that there are 4 scores of 80, and 80*4=320.

We see that there is 1 score of 85, and 85*1=85.

We see that there are 6 scores of 90, and 90*6=540.

Now we can do [tex]\frac{490+375+320+85+540}{7+5+4+1+6} =\frac{1810}{23} =78.7[/tex]

Answer:

if angle 2 is congruent to 6 them the slope of line o and q is equal

that is line o is parallel to q

Let's prove that (sec x)(csc x) is equal to cot x + tan x

[tex]\Longrightarrow \sf (sec(x) )(csc(x))[/tex]

[tex]\Longrightarrow \sf \dfrac{1}{\cos \left(x\right)\sin \left(x\right)}[/tex]

[tex]\Longrightarrow \sf \dfrac{\cos ^2\left(x\right)+\sin ^2\left(x\right)}{\cos \left(x\right)\sin \left(x\right)}[/tex]

[tex]\Longrightarrow \sf \dfrac{\cos ^2\left(x\right)}{\cos \left(x\right)\sin \left(x\right)} + \dfrac{\sin ^2\left(x\right)}{\cos \left(x\right)\sin \left(x\right)}[/tex]

[tex]\Longrightarrow \sf \dfrac{\cos\left(x\right)}{\sin \left(x\right)} + \dfrac{\sin \left(x\right)}{\cos \left(x\right)}[/tex]

[tex]\Longrightarrow \sf cot(x) + tan(x)[/tex]

Hence student A did correctly prove the identity properly.

Also Looking at student B's work, he verified the identity properly.

So, Both are correct in their own way.

Identities used:

[tex]\rightarrow \sf sin^2 (x) + cos^2 (x) = 1[/tex]       (appeared in step 3)

[tex]\sf \rightarrow \dfrac{cos(x) }{sin(x) } = cot(x)[/tex]               (appeared in step 6)

[tex]\rightarrow \sf \dfrac{sin(x )}{cos(x) } = tan(x)[/tex]               (appeared in step 6)

Answer:

The solution is 4 - 9/(2x + 1)

No, the divisor does not evenly divide into the dividend

Step-by-step explanation:

Please see the attached image

Step-by-step explanation:

1) the required equation in common form is:

(x-x₀)²+(y-y₀)²=r², where (x₀;y₀) - coordinates, where Michael is standing; r - the social distance;

According to the common form and given coordinates (x₀=-5; y₀=2; r=6) it is possible to make up the required equation:

(x+5)²+(y-2)²=6².

2) if the distance between two friends is:

[tex]d=\sqrt{(-5-1)^2+(2-1)^2}=\sqrt{37}, \ then[/tex]

this distance is longer than social (6 ft). For more info see the attachment.

An arithmetic sequence is a sequence in which the difference between any two consecutive terms of the sequence is equal. The number of term 107 is 17th.

What is Arithmetic Sequence?

An arithmetic sequence is a sequence in which the difference between any two consecutive terms of the sequence is equal.

a_n = a₁ + (n-1)r

where,

a_n is the nth term of the sequence,

a₁ is the first term of the sequence,

r is a common difference between every two terms.

Given the formula for the nth term of the arithmetic sequence is,

[tex]a_n = 11+6(n-1)[/tex]

Now, the number of term that 107 will be,

107 = 11 + 6(n-1)

96 = 6(n-1)

16 = n- 1

n =17

Hence, the number of term that 107 is 17.

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first one b 315, second d

Step-by-step explanation:

18*=3*+315

7*+4*=a*

Answer:

[tex]\displaystyle\frac{dy}{dx} \ = \ 3x^{2} \ + \ \displaystyle\frac{1}{2\sqrt{x^{3}}} \ - \ \displaystyle\frac{12}{x^{5}}[/tex]

Step-by-step explanation:

                      [tex]y \ = \ x^{3} \ - \ \displaystyle\frac{1}{\sqrt{x}} \ + \ \displaystyle\frac{3}{x^{4}} \\ \\ y \ = \ x^{3} \ - \ x^{-\frac{1}{2}} \ + \ 3x^{-4} \\ \\ \displaystyle\frac{dy}{dx} \ = \ 3x^{3 \ - \ 1} \ - \ \left(-\displaystyle\frac{1}{2}\right)x^{-\frac{1}{2} \ - \ 1} \ + \ \left(-4 \ \times \ 3\right)x^{-4-1}[/tex]

                       [tex]\displaystyle\frac{dy}{dx} \ = \ 3x^{2} \ + \ \displaystyle\frac{1}{2}x^{-\frac{3}{2}} \ - \ 12x^{-5} \\ \\ \displaystyle\frac{dy}{dx} \ = \ 3x^{2} \ + \ \displaystyle\frac{1}{2\sqrt{x^{3}}} \ - \ \displaystyle\frac{12}{x^{5}}[/tex]

We have y+2 = 0 and x - 2 = 0. The provided function has an x and y-intercept of -2 and +2, respectively. There is no vertical asymptote. Two is the horizontal asymptote.

A diagram depicting the relationship between two or more variables, each measured along with one of a pair of axes at right angles.

The y-intercept of a function is determined by the intersection of its graph with the y-axis. The value of y on the y-axis at which the considered function crosses it is called the y-intercept.

Assume the following equation: y = f (x)

We have x   =0- 2 and y+2 = 0,The x and y intercept of the given function is -2 and +2.

The vertical asymptote is none. The horizontal asymptote is 2.

Hence,we have y+2 = 0 and x - 2 = 0. The provided function has an x and y-intercept of -2 and +2, respectively. There is no vertical asymptote. Two is the horizontal asymptote.

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Answer:

1 cup

Step-by-step explanation:

1/3 cup of chocolate chips : 2 cup of flours

So 1/3:2 = x:3

Because we want to find x, the number of how many cups of chocolate chips he needs.
you can cross multiply where you get 1/3·3=2x
which is 1=2x and x=1

Answer:

28 feet

Step-by-step explanation:

Area of a rectangle is :

A = L × W

We are given A and a expression for L, so let's substitute :

448 = (2W-4) × W

Now we expand the left side :

2W²-4w = 448

Subtract 448 from both sides :

2W²-4W-448 = 0

Divide everything by 2 :

W²-2W-224 = 0

Now we factorise :

Find 2 numbers that multiply to give -224 and add to give -2 :

-16 and 14

Rewrite -2W with -16W and +14W :

W² - 16W + 14W -224 = 0

W(W-16)  +14(W-16) = 0

(W+14)(W-16) = 0

W = -14 ,  W = 16

Only take positive value since this is lengths :

W = 16

Now we substitute W into the expression to find L :

L = (2W -4)

L = 2(16) - 4

L = 32 - 4

L = 28

Units will be feet since it is a length

Hope this helped and have a good day

The formula for the surface area N(t) of the balloon after t seconds is [tex]N(t) = \frac {64}9\pi t^2[/tex]

We have:

[tex]S(r) = 4\pi r^2[/tex]

Also, we have:

[tex]P(t) = \frac 43t[/tex]

The above can be rewritten as:

[tex]r = \frac 43t[/tex]

Substitute [tex]r = \frac 43t[/tex] in S(r) to determine the function N(t)

[tex]S(r) = 4\pi (\frac 43t)^2[/tex]

Express as N(t)

[tex]N(t) = 4\pi (\frac 43t)^2[/tex]

Expand the exponent

[tex]N(t) = 4\pi *\frac {16}9t^2[/tex]

Evaluate the product

[tex]N(t) = \frac {64}9\pi t^2[/tex]

Hence, the formula for the surface area N(t) of the balloon after t seconds is [tex]N(t) = \frac {64}9\pi t^2[/tex]

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Answer:

B

Step-by-step explanation:

4, 16, 64 should be the correct order

The multiplication of the expression will be 1215 cubic yd 2295 cubic inches.

It is also known as the product. If the object n is given to m times, then we just simply multiply them.

The expression is given below.

(9 cubic yd and 17 cubic in) × 135

On multiplication, we have

135 × 9 cubic yd and 135 ×  17 cubic in

1215 cubic yd and 2295 cubic inches

1215 cubic yd 2295 cubic inches

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The multiplication is 56,689,335 cu in

A number system is defined as a system of writing to express numbers. It is the mathematical notation for representing numbers of a given set by using digits or other symbols in a consistent manner.

9 cu yd 17cu in

1 cu yard = 46656 cu inches

9 cu yard = 9*46656 = 419904 cu inches

Now, total inches

= 419904 cu inches + 17 cu in

= 419,921 cu inches.

and, the multiplication is

=56689335

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Answer: (6, -5)

Step-by-step explanation: I used the midpoint formula and this is what I got. I hope this helps!

The formula:

(xm, xy) = (x1 + x2/2, y1 + y2/2)

The probabilities for various binomial distribution have been determined.

The complete question is

About 5% of hourly paid workers in a region earn the prevailing minimum wage or less. A grocery chain offers discount rates to companies that have at least 30 employees who earn the prevailing minimum wage or less. Complete parts (a) through (c) below.

(a) Company A has 285 employees. What is the probability that Company A will get the discount? (Round to four decimal places as needed.)

(b) Company B has 502 employees. What is the probability that Company B will get the discount? (Round to four decimal places as needed.)

(c) Company C has 1033 employees. What is the probability that Company C will get the discount? (Round to four decimal places as needed.)

Probability is a stream in mathematics that study the likeliness of an event to happen .

On the basis of the given data

(a) Let X is a random variable that denotes the number of employees that earn less than prevailing average.

Here X has binomial distribution with

n=285 and p=0.05.

As np and n(1-p) are greater than 5 so using normal approximation X has normal distribution with parameters

μ=  np-285 * 0.05

= 14.25

standard deviation is given by

[tex]\sigma=\sqrt{np(1-p)}=\sqrt{285* 0.05* 0.95}\\\\=3.6793[/tex]

Applying continuity correction.

The z-score for X = 30-0.5 = 29.5 is

[tex]z=\dfrac{29.5-14.25}{3.6793}\\\\=4.14[/tex]

The probability that Company A will get the discount is given by

[tex]P(X\geq 30)=P(z > 4.14)=0.0000[/tex]

(b) Let X is a random variable that denotes the number of employees that earn less than prevailing average.Here X has binomial distribution with

n=502 and p=0.05.

[tex]\rm \mu=np=502* 0.05=25.1[/tex]

standard deviation

[tex]\rm \sigma=\sqrt{np(1-p)}=\sqrt{502\cdot 0.05\cdot 0.95}=4.8831[/tex]

Applying continuity correction.

The z-score for X = 30-0.5 = 29.5 is

[tex]\rm z=\dfrac{29.5-25.1}{4.8831}=0.90[/tex]

The probability that Company B will get the discount is

[tex]P(X\geq 30)=P(z > 0.90)=0.1841[/tex]

(c)Let X is a random variable that denotes the number of employees that earn less than prevailing average.Here X has binomial distribution with

n=1033 and p=0.05.

[tex]\mu=np=1033\cdot 0.05=51.65[/tex]

standard deviation

[tex]\rm \sigma=\sqrt{np(1-p)}=\sqrt{1033*0.05* 0.95}=7.0048[/tex]

Applying continuity correction.

The z-score for X = 30-0.5 = 29.5 is

[tex]\rm z=\dfrac{29.5-51.65}{7.0048}=-3.16[/tex]

The probability that Company C will get the discount is

[tex]\rm P(X\geq 30)=P(z > -3.16)=0.9992[/tex]

Therefore the probabilities for various binomial distribution have been determined.

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