Answers
Answer:
(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz
(b) 250 m/s
(c) 1250 N
(d) Positive x-direction
(e) 6.00 m/s
(f) 0.0365 m
Explanation:
(a) The standard form of the wave is:
y = A cos ((2πf) t ± (2π/λ) x)
where A is the amplitude, f is the frequency, and λ is the wavelength.
If the x term has a positive coefficient, the wave moves to the left.
If the x term has a negative coefficient, the wave moves to the right.
Therefore:
A = 0.0800 m
2π/λ = 0.300 m⁻¹
λ = 20.9 m
2πf = 75.0 rad/s
f = 11.9 Hz
(b) Velocity is wavelength times frequency.
v = λf
v = (20.9 m) (11.9 Hz)
v = 250 m/s
(c) The tension is:
T = v²ρ
where ρ is the mass per unit length.
T = (250 m/s)² (0.0200 kg/m)
T = 1250 N
(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).
(e) The maximum transverse speed is Aω.
(0.0800 m) (75.0 rad/s)
6.00 m/s
(f) Plug in the values and find y.
y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))
y = 0.0365 m
Related Questions
During a race, a runner runs with an average velocity of 4.26 m/s toward city hall. What is the runner’s displacement after 167s?
Answers
Answer:
d = 711.42 m
Explanation:
Given that,
The average velocity of a runner, v = 4.26 m/s
Time, t = 167 s
We need to find the runner's displacement.
The average velocity of an object is equal to the displacement per unit time. It can be given by :
[tex]v=\dfrac{d}{t}\\\\d=vt\\\\d=4.26\ m/s\times 167\ s\\\\d=711.42\ m[/tex]
So, the runner's displacement is 711.42 m.
The rotational inertia of a thin rod about one end is 1/3 ML2. What is the rotational inertia of the same rod about a point located 0.40 L from the end
Answers
Answer:
The value is [tex]I = 0.0932 ML ^2[/tex]
Explanation:
From the question we are told that
The rotational inertia about one end is [tex]I_R = \frac{1}{3} ML^2[/tex]
The location of the axis of rotation considered is [tex]d = 0.4 L[/tex]
Generally the mass of the portion of the rod from the axis of rotation considered to the end of the rod is [tex]0.4 M[/tex]
Generally the length of the rod from the its beginning to the axis of rotation consider is
[tex]k = 1 - 0.4 L = 0.6L[/tex]
Generally the mass of the portion of the rod from the its beginning to the axis of rotation consider is
[tex]m = 1- 0.4 M = 0.6 M[/tex]
Generally the rotational inertia about the axis of rotation consider for the first portion of the rod is
[tex]I_{R1} = \frac{1}{3} (0.6 M )(0.6L)^2[/tex]
[tex]I_{R1} = \frac{1}{3} (0.6 M )L^2 0.6^2[/tex]
Generally the rotational inertia about the axis of rotation consider for the second portion of the rod is
[tex]I_{R2} = \frac{1}{3} (0.6 M )(0.6L)^2[/tex]
=> [tex]I_{R2} = \frac{1}{3} (0.4 M )(0.4L)^2[/tex]
=> [tex]I_{R2} = \frac{1}{3} (0.4 M )L^2 0.4^2[/tex]
Generally by the principle of superposition that rotational inertia of the rod at the considered axis of rotation is
[tex]I = \frac{1}{3} (0.6 M )L^2 0.6^2 + \frac{1}{3} (0.4 M )L^2 0.4^2[/tex]
=> [tex]I = \frac{1}{3} ML ^2 [0.6 * (0.6)^2 + 0.4 * (0.4)^2 ][/tex]
=> [tex]I = 0.0932 ML ^2[/tex]
Describe the difference between simply taking measurements and doing a scientific experiment.
In 2-3 sentences
Answers
A rocket is fired in deep space, where gravity is negligible. In the first second it ejects 1/160 of its mass as exhaust gas and has an acceleration of 14.0 m/s^2.
Required:
What is the speed vgas of the exhaust gas relative to the rocket?
Answers
Answer:
840 m/s
Explanation:
Given that,
In the first second the rocket ejects 1/160 of its mass as exhaust gas and has an acceleration of 14.0 m/s².
We need to find the speed of the exhaust gas relative to the rocket.
The thrust of rocket is given by :
[tex]T=v_{gas}\dfrac{dm}{dt}\\\\ma=v_{gas}\dfrac{dm}{dt}\\\\v_{gas}=\dfrac{ma}{\dfrac{dm}{dt}}\\\\v_{gas}=\dfrac{14m}{\dfrac{1}{60}m}\\\\v_{gas}=840\ m/s[/tex]
So, the speed of the exhaust gas relative to the rocket is 840 m/s.
The speed ( Vgas) of the exhaust gas relative to rocket is : 840 m/s
Given data :
In first round Rocket ejects 1/60 of mass as exhaust gas
Acceleration of rocket ( a ) = 14.0 m/s²
Determine the speed of the exhaust gas relative to rocket
We will apply the equation for Rocket thrust
T = Vgas * [tex]\frac{dm}{dt}[/tex]
where : T = ma
∴ Vgas = ma / [tex]\frac{dm}{dt}[/tex]
= 14 m / [tex]\frac{1}{60}[/tex] m
therefore V gas = 840 m/s
Hence we can conclude that the speed ( Vgas) of the exhaust gas relative to rocket is : 840 m/s
Learn more about Rocket thrust : https://brainly.com/question/24726786
How do you determine: how many significant figures should you to round to when doing addition and subtraction?
Answers
How many seconds did it take (after starting his descent) for the worker to hit the ground? Answer in units of s.
Answers
Answer:
This question is incomplete
Explanation:
The question is incomplete. However, to determine the time (in seconds) it took a worker to hit the ground from an elevated point. The speed the worker was coming with to the ground and the distance between the elevated point and the ground will have to be considered. Thus the formula to be used here will be
Speed (in meter per second) = distance (in meters) ÷ time (in seconds)
time (in seconds) = distance (in meters) ÷ speed (in meter per seconds)
If you can answer my last post ill give you 75 points pls its very important and please make sure it correct!!!!!!!
Answers
Answer:
I can't see the post :/
Explanation:
Answer:
ok
Explanation:
ok how many points is this?????
If a 25 kg lawnmower produces 347 w and does 9514 J of work, for
how much time did the lawnmower run?
Answers
Steps 1 and 2)
The variables are W = work, P = power, and t = time. In this case, W = 9514 joules and P = 347 watts.
The goal is to solve for the unknown time t.
-----------------------
Step 3)
Since we want to solve for the time, and we have known W and P values, we use the equation t = W/P
-----------------------
Step 4)
t = W/P
t = 9514/347
t = 27.4178674351586
t = 27.4 seconds
-----------------------
Step 5)
The lawn mower ran for about 27.4 seconds. I rounded to three sig figs because this was the lower amount of sig figs when comparing 9514 and 347.
-----------------------
Note: we don't use the mass at all
Is Nuclear Energy renewable or nonrenewable? Use in your own words.
Answers
How do you calculate the net force when there are multiple forces in different directions?
Answers
To find [tex]F_{net}[/tex] we need to use vector addition and use the x and y components. First we subtract vector 2 from vector 5 which results in a vector with a length of 3 pointing directly east, then we use the distance formula to find the length of the net force [tex]F_{net} = \sqrt{(3)^2+(4)^2} \\[/tex] which gives [tex]F_{net} = 5[/tex]. We now have a magnitude but we also need a direction, since vector 4 and vector 5 are perpendicular. Using [tex]\theta = \tan^{-1} (\frac{4}{3})[/tex] where tan^-1(y/x) we get an angle of 53 degrees. The resultant force vector is 5 distance with an angle of 53 degrees north east.
A train slows down as it rounds a sharp horizontal turn, going from 88.0 km/h to 52.0 km/h in the 18.0 s that it takes to round the bend. The radius of the curve is 120 m. Compute the acceleration at the moment the train speed reaches 52.0 km/h. Assume the train continues to slow down at this time at the same rate.
Answers
Answer:
The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.
Explanation:
According to Rotational Physics, the total acceleration of the train rounding the horizontal turn is a combination of tangential ([tex]a_{t}[/tex]) and radial accelerations ([tex]a_{r}[/tex]), measured in meters per square second. The former one represents the change in the magnitude of the velocity, whereas the latter one represents the change in its direction. By definition of magnitude and Pythagorean Theorem we get that magnitude of total acceleration ([tex]a[/tex]), measured in meters per square second, is:
[tex]a = \sqrt{a_{r}^{2}+a_{t}^{2}}[/tex] (Eq. 1)
Magnitudes of tangential and radial accelerations are determined by using the following formulas:
[tex]a_{t} = \frac{v_{f}-v_{o}}{t}[/tex] (Eq. 1)
[tex]a_{r} = \frac{v_{f}^{2}}{R}[/tex] (Eq. 2)
Where:
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds, measured in meters per second.
[tex]t[/tex] - Time, measured in seconds.
[tex]R[/tex] - Radius, measured in meters.
If we know that [tex]v_{o} = 24.444\,\frac{m}{s}[/tex], [tex]v_{f} = 14.444\,\frac{m}{s}[/tex], [tex]t = 18\,s[/tex] and [tex]R = 120\,m[/tex], then the magnitude of the total acceleration when the train speed reaches 52 kilometers per hour is:
[tex]a_{t} = \frac{14.444\,\frac{m}{s}-24.444\,\frac{m}{s} }{18\,s}[/tex]
[tex]a_{t} = -0.556\,\frac{m}{s^{2}}[/tex]
[tex]a_{r} = \frac{\left(14.444\,\frac{m}{s} \right)^{2}}{120\,m}[/tex]
[tex]a_{r} = 1.739\,\frac{m}{s^{2}}[/tex]
[tex]a = \sqrt{\left(-0.556\,\frac{m}{s^{2}} \right)^{2}+\left(1.739\,\frac{m}{s^{2}} \right)^{2}}[/tex]
[tex]a \approx 1.826\,\frac{m}{s^{2}}[/tex]
The acceleration at the moment the train speed reaches 52 kilometers per hour is approximately 1.826 meters per square second.
A 5 kg ball and a 2 kg ball are placed at opposite ends of a massless beam so that the system is in equilibrium. What is the ratio of the length of the beam to the distance from the heavier ball to the pivot
Answers
Answer:
L/x = 3.5 (The ratio of length of beam to the distance from heavier ball to pivot).
Explanation:
In order for the system to be in equilibrium, the moment created by both masses about the pivot point must be equal:
m₁x = m₂y
where,
m₁ = 5 kg
m₂ = 2 kg
x = distance of 5 kg ball from pivot
y = distance of 2 kg ball from pivot
Therefore,
(5 kg)x = (2 kg)y
y = (5kg/2kg)x
y = 2.5 x
but,
x + y = L
where,
L = length of beam
using the value of y from the previous equation:
x + 2.5 x = L
3.5 x = L
L/x = 3.5 (The ratio of length of beam to the distance from heavier ball to pivot).
A 600 kg rocket sled can be accelerated at a constant rate from rest to 1400 km/h in 2.1 s. What is the magnitude of the required net force
Answers
Answer:
7.2 × 10^5 N
Explanation:
The first step is to convert 1400 km/hr to m/s
= 1,400×1000/3600
= 1,400,000/3600
= 388.88 m/s
The acceleration can be calculated as follows
a= v-u/t
= 388.88/2.1
= 185.18
Therefore the required net force can be calculated as follow
= 388.88 × 185.18
= 7.2 × 10^5 N
A car travels at a speed of 55 km/hr and slows down to 10 km/hr in 20 seconds. What is the acceleration?
Answers
Answer:
a = 0.62 [m/s²]
Explanation:
To solve this problem we must use the following equation of kinematics. But first, we must convert speeds from kilometers per hour to meters per second.
[tex]v_{f} =v_{o} -a*t[/tex]
[tex]55[\frac{km}{hr}]*\frac{1hr}{3600s}*\frac{1000m}{1km} =15.27[\frac{m}{s} ]\\10[\frac{km}{hr} ]*\frac{1hr}{3600s}*\frac{1000m}{1km} = 2.77[\frac{m}{s} ][/tex]
where:
Vf = final velocity = 2,77 [m/s]
Vo = initial velocity = 15.27 [m/s]
t = time = 20 [s]
a = acceleration [m/s²]
Now replacing:
[tex]2.77=15.27-a*(20)\\20*a=12.49\\a = 0.62[m/s^{2}][/tex]
Answer:
It would be 10.00
Explanation:
Hope this helps its different for everyone what was it for u it was D for me
what is the voltage of A simple circuit with one battery
Answers
Answer:
depends on the battery
What property of a wave remains unchanged when a wave enters a different medium? 5 points amplitude frequency wavelength velocity
Answers
Answer:
frequency
Explanation:
When a wave enters a different medium, the property that remains unchanged is the frequency of the wave.
The frequency of a wave is defined as the number of wave cycles passing a given point per unit time. It represents the rate at which the wave oscillates or repeats its pattern.
The frequency of a wave remains constant when it enters a different medium, regardless of any changes in other properties such as amplitude, wavelength, or velocity.
Therefore, When a wave enters a different medium, the property that remains unchanged is the frequency of the wave.
To know more about the frequency:
https://brainly.com/question/29739263
#SPJ6
1.) There was an earthquake in Salt Lake City, Utah, on March 18, 2020, in the morning at 9 hours, 9 minutes, and 45 seconds Mountain Standard Time (9:9:45 MST). If the velocity of the p-wave is 7.3 km/sec and the velocity of the s-wave is 5.1 km/sec and the s-p time lag is 16 seconds, what is the distance in kilometers from Salt Lake City to the focus of the earthquake? Explain how you calculated the answer.
Answers
Answer:
7 because salt lake and Southis weat
A gas was compressed to 30.0 mL at 1.5 atm from 65
mL. What was the original pressure?
Answers
Two identical bowling balls are moving down a bowling alley so that their centers of mass have the same velocity, but one just slides down the alley, while the other rolls down the alley. Which ball has more energy?
a. Sliding ball
b. Rolling ball
c. They both have the same energy
Answers
Answer:
Rolling Ball
Explanation
Two identical bowling balls are moving down a bowling alley so that their centers of mass have the same velocity, but one just slides down the alley, while the other rolls down the alley, rolling ball has more energy.
what is velocity ?Velocity can be referred to the rate of change of the position of the object with respect to time which is basically speeding the object in a specific direction.
Velocity is vector quantity, as it is present both magnitude and direction and The SI unit is meter per second (ms-1). The change in magnitude or the direction of velocity of a body, the object will accelerate.
the final velocity of the object is simple but few calculations and basic conceptual knowledge are needed.
For more details regarding velocity, visit
brainly.com/question/12109673
#SPJ2
A 306-kg car moving at 16.5 m/s hits from behind a 810-kg car moving at 13.2 m/s in the same direction. If the new speed of the heavier car is 17.5 m/s, what is the velocity of the lighter car after the collision, assuming that any unbalanced forces on the system are negligibly small?
Answers
Answer:
v₂f = 5.1 m/s
Explanation:
Assuming no external forces acting during the collision, total momentum must be conserved.⇒ p₀ = pfThe initial momentum p₀, can be written as follows:[tex]p_{o} = m_{1} *v_{1o} + m_{2} *v_{2o} (1)[/tex]
where m₁ = 306 kg, m₂ = 810 kg, v₁₀ = 16.5 m/s, v₂₀ = 13.2 m/s
The final momentum, pf, can be written as follows:[tex]p_{f} = m_{1} *v_{1f} + m_{2} *v_{2f} (2)[/tex]
where v₂f = 17.5 m/s
Since p₀ = pf, which means that (1) is equal to (2),Replacing by the givens, and rearranging, we can solve for the only unknown that still remains, v₁f, as follows:[tex]v_{1f} = v_{1o} +\frac{m_{2} }{m_{1}} * (v_{2o} - v_{2f} ) \\= 16.5 m/s + \frac{810}{306} * (13.2 m/s - 17.5 m/s) \\= 16.5 m/s + \frac{810}{306} * (-4.3 m/s) \\= 16.5 m/s -11.4 m/s = 5.1 m/s[/tex]
The velocity of the lighter car after the collision is 5.1 m/s.answer pls urgent pls
Answers
Answer:
I think its A: Magnesium
Explanation:
Basic oxide is formed by metal, and magnesium is the only metal in these options :)
Please inform me if this is incorrect
we feel cold in winter when we come out from the quilt but the same room becomes warmer after coming back from outside the room
Answers
Answer:
Yes
Explanation:
I think this is because when you go out of the room and going to a hotter room you then get the heat from that room. It then becomes warmer in the room you are coming from because your body got the heat from the outside the room. I think it is because of body temperature.
HOPE THIS HELPED
The above photo shows Plates A and B at an mid ocean ridge. If you were to draw arrows on the plates showing plate movement, which way would you draw arrows?
A . The arrows on plates A and B would show the plates moving in the same direction
B . The arrows on plates A and B would show the plates moving towards eachother
C . The arrows on plates A and B would show the plates moving in random directions
D . The arrows on plates A and B would show the plated moving away from each other
Answers
Answer:
D . The arrows on plates A and B would show the plated moving away from each other
Explanation:
The correct arrow in this instance will show that the plates A and B would be moving away from each other.
At the mid-ocean ridge, two plates are moving apart and pulling away from one another.
In short, at the mid-oceanic ridge, we have a divergent margin. At a divergent margin, the plates are spreading or moving apart.During a soccer game, the goalie kicks the ball out toward the other end of the field. It travels 60 yards in 8 seconds before landing on the ground. What is the velocity of the ball?
Answers
Answer:
velocity = 7.5 yards / second
Explanation:
velocity = distance / time
where distance = 60 yards
time = 8 seconds
plug in values into the formula:
velocity = 60 yards
8 seconds
velocity = 7.5 yards / second
Answer:
the velocity of the ball is 7.5 yards/second
Explanation:
This is my question
Answers
Answer:
N = 470 [N]
Explanation:
The normal force is defined as the reaction exerted by the surface where the body is located in the opposite direction to the weight component.
It can be easily calculated by means of the product of mass by gravitational acceleration.
N = m*g
where:
N = normal force [N] (units of Joules)
m = mass = 47 [kg]
g = gravity acceleration = 10 [N]
N = 47*10
N = 470 [N]
an airplane flies at a speed of 100 m/s and starts to accelerate constantly at a rate of 50 m/s2. how fast is the plane flying after traveling a distance of 1 kilometer?
Answers
Answer:
331.7m/s
Explanation:
Given parameters:
Initial velocity = 100m/s
Acceleration = 50m/s²
Distance = 1km = 1000m
Unknown:
Final velocity = ?
Solution:
To solve this problem, we have to apply the right motion equation shown below;
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance
Now insert the parameters and solve;
v² = 100² + (2 x 50 x 1000)
v² = 110000
v = √110000 = 331.7m/s
A photon has 8.0 x 10-15 J of energy. Planck's constant
is 6.63 x 10-34 Jos.
What is the frequency of the photon?
O 1.21 x 1019 Hz
O 8.3 x 10-20 HZ
O 1.21 10-19 Hz
O 8.3 x 1020 HZ
Answers
Answer:
^I dont know how he got 12 but the answer is A i believe
Explanation:Smart like dat
The frequency of a photon is related to its energy and Planck's constant by the equation:
frequency = energy / Planck's constant.
frequency =[tex](8.0 x 10-15 J) / (6.63 x 10-34 J) = 1.21 x 10^19 Hz[/tex]
Therefore, the correct answer is [tex]1.21 x 10^19 Hz[/tex]
What is Planck's constant?Planck's constant is a fundamental constant in physics that is related to the behavior of particles at the atomic and subatomic level. It is denoted by the letter "h" and is approximately equal to 6.63 x 10^-34 Joule-seconds. Planck's constant is named after Max Planck, a German physicist who proposed its existence in 1900 to explain the behavior of radiation emitted by black bodies.
Planck's constant plays a central role in quantum mechanics, which is the branch of physics that describes the behavior of particles at the atomic and subatomic level. It appears in a number of important equations, including the equation for the energy of a photon (E = hf) and the equation for the uncertainty principle (ΔxΔp ≥ h/4π).
Learn more about planck's constant here:
https://brainly.com/question/27389304
#SPJ2
Why is creativity important in constructing scientific explanations?
A. There are very few scientists who are creative people.
B. Science works when scientists make up their data.
C. The results of some experiments might not be explained by any
known theories.
D. Scientists all think in exactly the same way.
Answers
A piece of wood from a nearby construction site floats near the shore of a lake. It floats in very calm water with half of its volume just above the surface. What is the density of this piece of wood
Answers
Answer:
Explanation:
The density of a substance can be described as the mass per volume of the substance. The density of the piece of wood described in the question can be calculated as the mass of the wood divided by the volume of the water the wood displaced (which was referred to in the question as making half of the wood's volume i.e half of the thickness of the wood was in the water).
C4. A 50.0 kg boy runs at 10.0 m/s, jumps on a cart and rolls off at 2.50 m/s. What is the mass of the cart
Answers
Answer:
The mass of the cart is 150 kg.
Explanation:
Given that,
Mass of a boy, m₁ = 50 kg
Initial speed of boy, u₁ = 10 m/s
Initial speed of car, u₂ = 0 (at rest)
The speed of the cart with the boy on it is 2.50 m/s, V = 2.5 m/s
Let m₂ is the mass of the cart. Using the conservation of momentum as follows :
[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\50(10)+m_2(0)=(50+m_2)(2.5)\\\\500=125+2.5m_2\\\\375=2.5m_2\\\\m_2=150\ kg[/tex]
So, the mass of the cart is 150 kg.
