Please help i ahev a screen shot

y = (At + B) e^(rt)

where A = -r/2 and B = 3r/2, as expected.

When the two roots of the characteristic equation are both equal to r, we say that the roots are equal or repeated. In this case, the general solution to the corresponding second order linear homogeneous ODE with constant coefficients is of the form:

y = (At + B) e^(rt)

where A and B are constants to be determined by the initial or boundary conditions.

However, the form given in the question, (at+b)âe^rt, is not correct. The â symbol is not standard notation for mathematical expressions and its meaning is unclear. It is possible that it was intended to represent a coefficient or parameter, but without more information, we cannot determine its value or significance.

To see why the correct form of the solution is y = (At + B) e^(rt), we can use the method of undetermined coefficients. Suppose that y = e^(rt) is a solution to the homogeneous ODE with repeated roots. Then, we can try the solution y = (At + B) e^(rt) and see if it satisfies the ODE.

Taking the first and second derivatives of y, we get:

y' = A e^(rt) + r(At + B) e^(rt) = (Ar + r(At + B)) e^(rt)

y'' = A r e^(rt) + r^2(At + B) e^(rt) = (Ar^2 + 2rAt + r^2B) e^(rt)

Substituting y, y', and y'' into the homogeneous ODE with repeated roots, we get:

(Ar^2 + 2rAt + r^2B) e^(rt) = 0

Since e^(rt) is never zero, we can divide both sides by e^(rt) to get:

Ar^2 + 2rAt + r^2B = 0

This is a linear equation in A and B, and we can solve for them by using the initial or boundary conditions. For example, if we are given that y(0) = 1 and y'(0) = 0, we have:

y(0) = A e^(0) + B e^(0) = A + B = 1

y'(0) = (Ar + rB) e^(0) + A e^(0) = Ar + A = 0

Solving this system of equations, we get:

A = -r/2, B = 3r/2

Therefore, the general solution to the homogeneous ODE with repeated roots is:

y = (-rt/2 + 3r/2) e^(rt)

which can be rewritten as:

y = (At + B) e^(rt)

where A = -r/2 and B = 3r/2, as expected.

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The values of the trigonometric functions are given by,

sin (2u) = - 240/289

cos (2u) = 161/289

tan (2u) = - 240/161

The given trigonometric function value is,

cos u = -15/17

Since π/2 < u < π then value of Sine will be positive.

sin u = √(1 - cos² u) = √(1 - (15/17)²) = √(1 - 225/289) = √((289-225)/289) = √(64/289) = 8/17

tan u = sin u/cos u = (8/17)/(-15/17) = - 8/15

So now using double angle formulae we get,

sin (2u) = 2*sin u*cos u = 2*(8/17)*(-15/17) = - 240/289

cos (2u) = 1 - 2sin² u = 1 - 2*(8/17)² = 1 - 128/289 = (289-128)/289 = 161/289

tan (2u) = 2tan u/(1 - tan²u) = (2*(-8/15))/(1 - (-8/15)²) = (-16/15)/(1 - 64/225)

            = (-16/15)/((225-64)/225) = (-16/15)/(161/225) = -(16*15)/161 = -240/161

Hence the values are: sin 2u = - 240/289; cos 2u = 161/289; tan 2u = -240/161.

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The question is incomplete. The complete question will be -

"Use the given conditions to find the exact values of sin(2u), cos(2u), and tan(2u) using the double-angle formulas COS(u) = - 15/17, π/2 < u < π"

a) The Area of disk

dA= 26.376 cm²

b) Relative error  = 0.01904

c) Percent Error = 1.904%

We have,

Radius= 21 cm

Maximum error= 0.2 cm

a) Area of Disk

A = πr²

A = π(21)²

A = 1,384.74 cm²

Now, take the derivative on both side we get

dA = 2πr dr

dA = 2(3.14) (21)(0.2)

dA= 26.376 cm²

b) Relative error

= dA/ A

= 0.01904

c) Percent Error

= 100 x Relative Error

= 100 x 0.01904

= 1.904%

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The number 8-9.99 indicates that 68.26 percent of scores fall within 9.99 raw score units around the mean. This means that most scores deviate from the mean by an average amount of 9.99 units. Therefore, the correct answer is d) all of the above.

This information is useful in understanding the distribution of scores and the degree to which they vary from the average. It can be helpful in identifying outliers or patterns within the data.
The number 9.99 indicates that, on average, each score deviates from the mean by 9.99 units (option C). It reflects the average amount by which the scores differ from the mean value, giving insight into the dispersion or spread of the data. The other options (A, B, and D) do not accurately describe the meaning of this number in the context provided.

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The party of Mary was approximately 5 hours long. So, the correct option is B).

Let the number of hours of the party be "h".

Mary spent $30.36 for each hour of the party.

So, the total amount spent on the party other than food = 30.36h.

Given, the total amount spent on the party = $352.63

Therefore, we can form the equation:

200.83 + 30.36h = 352.63

Subtracting 200.83 from both sides, we get:

30.36h = 151.80

Dividing both sides by 30.36, we get:

h ≈ 4.999

Therefore, the party was approximately 5 hours long.

So, the correct answer is B. 5 hours.

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The time taken for the kitten to catch the puppy is -36 seconds.

The time taken for the kitten to catch the puppy is calculated as follows;

Apply the rules of relative velocity;

(V₂ - V₁)t = d

where;

(20 m/s - 25 m/s )t = 180 m

-5t = 180

-t = 180/5

t = -36 seconds

The negative sign indicates the question is constructed wrongly.

Thus, the time taken for the kitten to catch up with the puppy is determined by applying the principle of relative velocity.

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Answer:

8.21

Step-by-step explanation:

To solve for x in the equation:

x - 6.41 = 1.8 (or 1.80)

We want to isolate x on one side of the equation.

First, we can add 6.41 to both sides of the equation:

x - 6.41 + 6.41 = 1.8 + 6.41

Simplifying the left-hand side by canceling out the -6.41 and +6.41, we get:

x = 1.8 (cough cough --> 1.80) + 6.41

x = 8.21

Therefore, the solution is x = 8.21.

Note that adding 6.41 to both sides of the equation is equivalent to moving -6.41 to the right-hand side of the equation, which changes its sign to +6.41. Also, in this case, since 1.8 and 1.80 are the same number, we can treat them interchangeably in the calculations.

Blocking can allude to an assortment of activities, but for the most part, talking includes anticipating somebody or something from getting to or collaborating with a specific individual, framework, or asset. Here are a few of the common objectives and benefits of blocking:

Security: Blocking can be utilized as a security degree to anticipate unauthorized get too touchy data or assets. For illustration, arrange chairmen can piece certain IP addresses or spaces from getting to their company's servers to avoid hacking endeavors.

Protection: Blocking can too be utilized to secure individual protection. For occurrence, social media clients can piece other clients who are annoying them or posting improper substances.

Efficiency: Blocking can be utilized to extend efficiency by blocking diverting websites or apps during work hours.

Parental control: Guardians can utilize blocking to confine their children get to improper substances on the web or to constrain their time going through certain apps or websites.

Asset administration: Blocking can be utilized to oversee assets productively. For case, organize chairmen can piece certain applications or websites to avoid them from utilizing up as well as much transmission capacity.

Generally, the objective of blocking is to avoid undesirable or destructive intelligence or exercises, and the benefits incorporate expanded security, security, efficiency, and asset administration. 

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A. In the survey of 800 adults, 560 had credit card debt. To construct a 99% confidence interval for the population proportion, the interval is (.66, .74). B. In the survey of 20 adults, 14 had credit card debt. To construct a 90% confidence interval for the population proportion, the interval is (.43, .97).

For part A, the interval given is not relevant to the question, but here is the solution to construct a 99% confidence interval around the population proportion:

First, calculate the sample proportion: 560/800 = 0.7

Next, calculate the standard error: sqrt((0.7*(1-0.7))/800) = 0.018

Then, calculate the margin of error using the z-score for a 99% confidence level: 2.576 * 0.018 = 0.046

Finally, construct the confidence interval: 0.7 +/- 0.046, which gives us (0.654, 0.746).

For part B, the interval given is (0.43, 0.97), and we need to construct a 90% confidence interval around the population proportion based on a sample of 20 adults with 14 having credit card debt:

First, calculate the sample proportion: 14/20 = 0.7

Next, calculate the standard error: sqrt((0.7*(1-0.7))/20) = 0.187

Then, calculate the margin of error using the z-score for a 90% confidence level: 1.645 * 0.187 = 0.308

Finally, construct the confidence interval: 0.7 +/- 0.308, which gives us (0.392, 1.008).

However, since the upper limit of the interval is greater than 1, we need to adjust it to 1, giving us the final interval of (0.392, 1). Note that the upper limit being greater than 1 indicates that we may not have enough data to make a reliable estimate of the population proportion.

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The exact value of the expression,

(a) tan(arctan(8)) = 8

(b) arcsin(sin(5Ï/4)) = 51/4

Let's now look at the first expression: tan(arctan(8)). Here, we have an expression that involves both tan and arctan.

In this case, we have arctan(8) as the argument of the tan function. Therefore, the value of the expression is tan(arctan(8)) = 8.

Moving on to the second expression: arcsin(sin(51/4)). Here, we have an expression that involves both sin and arcsin.

To find the value of this expression, we need to use the property that states: arcsin(sin(x)) = x, where x is an angle measured in radians.

Therefore, the value of the expression is arcsin(sin(51/4)) = 51/4 (measured in radians).

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After the evaluation of integral I = Sπ/6 0 2sin2x/cosx the result is -2 [Si(1) - Si(√3/2)], under the condition that the given integral is a form of infinite integral.

The  given integral I = ∫(π/6)0 2sin2x/cosx

can be evaluated by performing the principles of substitution method.

Then Let us consider u = cos(x),

then du/dx = -sin(x)

dx = -du/sin(x).

Staging these values in the integral

I = ∫(π/6)0 2sin2x/cosx dx

 = ∫(π/6)0 2sin2x/u (-du/sin(x))

 = -2 ∫u=cos(π/6)u=cos(0) sin(u)²/u du

 = -2 ∫u=√3/2u=1 sin(u)²/u du

 = -2 [Si(1) - Si(√3/2)]

here Si is the sine integral function.

After the evaluation of integral I = Sπ/6 0 2sin2x/cosx the result is -2 [Si(1) - Si(√3/2)], under the condition that the given integral is a form of infinite integral.

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To find the distance traveled by the car in the 3 seconds from t=0 to t=3, we need to integrate the velocity function from t=0 to t=3.

∫(0 to 3) [2t√10 - t^2] dt

= [√10 (t^2) - (1/3)(t^3)] from 0 to 3

= [√10 (3^2) - (1/3)(3^3)] - [√10 (0^2) - (1/3)(0^3)]

= [9√10 - 9/3] - [0 - 0]

= 9√10 - 3

Therefore, the distance traveled by the car in the 3 seconds from t=0 to t=3 is 9√10 - 3 feet.
To find the distance traveled by the car from t=0 to t=3, we'll need to integrate the velocity function, V(t), over the given time interval.

1. First, write down the given velocity function:
V(t) = 2t√(10 - t^2)

2. Next, integrate the velocity function with respect to t from 0 to 3:
Distance = ∫(2t√(10 - t^2)) dt, where the integration limits are 0 to 3.

3. Perform the integration:
To do this, use substitution. Let u = 10 - t^2, so du = -2t dt. Therefore, t dt = -1/2 du.

The integral now becomes:
Distance = -1/2 ∫(√u) du, where the integration limits are now in terms of u (u = 10 when t = 0 and u = 1 when t = 3).

4. Integrate with respect to u:
Distance = -1/2 * (2/3)(u^(3/2)) | evaluated from 10 to 1
Distance = -1/3(u^(3/2)) | evaluated from 10 to 1

5. Evaluate the definite integral at the limits:
Distance = (-1/3(1^(3/2))) - (-1/3(10^(3/2)))
Distance = (-1/3) - (-1/3(10√10))

6. Simplify the expression:
Distance = (1/3)(10√10 - 1)

The distance traveled by the car in the 3 seconds from t = 0 to t = 3 is (1/3)(10√10 - 1) feet.

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After answering the query, we may state that Consequently, y = 2/5x + 24/5 is the equation of the line with the same slope that crosses through the points (3, 6).

The slope of a line defines its steepness. Gradient overflow (the change in y divided by the change in x) is a mathematical term for the gradient. The slope is the ratio of the vertical (rise) to the horizontal (run) change in elevation between any two places. The slope-intercept form of an equation is used to represent a straight line when its equation is expressed as y = mx + b. The line's slope, b, and (0, b) are all at the place where the y-intercept is found. Consider the y-intercept (0, 7) and slope of the equation y = 3x - 7.The y-intercept is located at (0, b), and the slope of the line is m.

provided that it is in the slope-intercept form y = mx + b, where m is the slope, the provided line has a slope of 2.5.

We may use point-slope form, which is: to locate a line that has the same slope as the one that goes through (3, 6).

[tex]y - y1 = m(x - x1)\\y - 6 = 2/5(x - 3)[/tex]

We may simplify this equation by writing it in slope-intercept form:

[tex]y - 6 = 2/5x - 6/5\\y = 2/5x - 6/5 + 6\\y = 2/5x + 24/5\\[/tex]

Consequently, y = 2/5x + 24/5 is the equation of the line with the same slope that crosses through the points (3, 6).

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The marketing firm should sample at least 753 people for their next advertising campaign to achieve a margin of error of 3% with 90% confidence.

To determine the sample size needed for the marketing firm's next advertising campaign, we can use the formula:

n = (z² * p * (1-p)) / (E²)

Where:
n = sample size
z = z-score for the desired confidence level (90% in this case, which corresponds to a z-score of 1.645)
p = estimated proportion of the population that will approve of the advertising campaign (unknown)
E = margin of error (3% in this case)

Since we don't know the estimated proportion of the population that will approve of the advertising campaign, we can assume a conservative estimate of 50%. This is because 50% gives us the largest sample size, which will ensure that our margin of error is as small as possible.

Plugging in the values, we get:

n = (1.645² * 0.5 * (1-0.5)) / (0.03²)
n = 752.68

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a) The estimate of b3 is 1.

b) The estimate of b7 represents the interaction between the dummy variable for Vilnius and the interaction between the dummy variables for After and Women.

c) The estimate from the model in part (b) would be preferred.

(a) The estimate of b3 can be obtained by comparing the difference in the mean wage for women before and after the law in Vilnius. The difference is 12 - 9 = 3 for women and 14 - 12 = 2 for men. Therefore, the estimate of b3 is 3 - 2 = 1.

(b) The estimate of b7 can be used to measure the effect of the law on women's wages while controlling for the difference in wages between Vilnius and Kaunas, and the difference between men and women. The estimate of b7 represents the interaction between the dummy variable for Vilnius and the interaction between the dummy variables for After and Women. The estimate of b7 will give the effect of the law on women's wages in Vilnius relative to Kaunas. The estimate of b5 will give the effect of the law on women's wages relative to men in Vilnius. The estimate of b6 will give the difference in the effect of the law between women in Vilnius and Kaunas.

(c) It is difficult to determine which estimate is preferable without the necessary standard errors. However, the estimate from the model in part (b) would be preferred because it controls for differences in wages between Vilnius and Kaunas and differences in wages between men and women. The estimate in part (a) does not account for these differences and may be biased as a result. Additionally, the estimate in part (b) allows for testing of the significance of the effect of the law on women's wages while controlling for these other factors.

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Given a 20 question true/false test, the probability of getting at least 12 correct is 0.25. Therefore, the correct option is option 4.

To find the probability of getting at least 12 correct answers on a 20-question true/false test, we'll use the binomial distribution formula and the given answer choices.

The binomial probability formula is P(X=k) = C(n,k) * p^k * (1-p)^(n-k), where:

P(X=k) is the probability of getting k successes (correct answers)

C(n,k) is the number of combinations (n choose k)

n is the number of trials (questions)

k is the number of successes (correct answers)

p is the probability of success (0.5 for true/false questions)

To find the probability of getting at least 12 correct, we need to calculate P(X>=12). We can use a calculator or a binomial probability table to find this probability. Using a calculator, we get:

P(X>=12) = 1 - P(X<=11) = 1 - binomdist(11,20,0.5,true) ≈ 0.252

Therefore, the answer is option 4: 0.25, which is the closest choice to our calculated probability.

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The partial derivative of f(x, y) with respect to x, evaluated at a = (x=a, y=a), is fa = 0.

In this case, since a is not a variable in f, we cannot differentiate with respect to a.

The function f(x, y) is defined as f(x, y) = 5.23 + 8x y2 + sin(y).

The partial derivative of f with respect to x is fx = 15x2 + 40x4, which is not relevant to finding fa.

The partial derivative of f with respect to y is fy = 16xy + cos(y).

However, we are asked to find fa, which is the partial derivative of f with respect to a.

Since a is not one of the variables in f, we cannot take the partial derivative of f with respect to a, and therefore fa is equal to 0.

So, the answer is:

fa = 0.

It is important to note that when finding partial derivatives, we need to differentiate with respect to one variable at a time, holding all other variables constant.

In this case, since a is not a variable in f, we cannot differentiate with respect to a.

A partial derivative is a mathematical concept in multivariable calculus that represents the rate of change of a function with respect to one of its variables, while holding all other variables constant.

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The point estimate of the mean content of all bottles

the answer is c. 4.

The point estimate of the mean content of all bottles of cologne is the sample mean, which is 4 ounces. This is based on a random sample of 121 bottles, which showed an average content of 4 ounces.

The point estimate of the mean content of all bottles of cologne is the sample mean, which is 4 ounces.

This can be represented mathematically as: [tex]$\bar{x} = 4$[/tex],

where [tex]$\bar{x}$[/tex] is the sample mean.

The standard deviation of the population, denoted by $\sigma$, is given as 0.22 ounces but is not required to calculate the point estimate.

Therefore, the answer is c. 4.

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Answer:

x = 56

Step-by-step explanation:

We are given the following equation:
[tex]29 = 1 + \frac{1}{2} x[/tex]

We want to solve this equation for x.

To do that, we want to isolate x by itself on one side.

To start, we can subtract 1 from both sides.

[tex]29 =1 + \frac{1}{2} x[/tex]

-1     -1

__________________

[tex]28 = \frac{1}{2} x[/tex]

Now, we have the variables on one side, and numbers on the other, but we aren't done yet, because [tex]\frac{1}{2} x[/tex] is [tex]\frac{1}{2}[/tex] * x, not just x.

So, we can divide both sides by [tex]\frac{1}{2}[/tex] to get x by itself.

[tex]28 = \frac{1}{2} x[/tex]

÷[tex]\frac{1}{2}[/tex]     ÷[tex]\frac{1}{2}[/tex]

_____________

[tex]\frac{28}{\frac{1}{2} } = x[/tex]

56 = x

The point guaranteed to exist by the Mean Value Theorem is

c = ln(6/ln7).

B. The Mean Value Theorem applies because the function is continuous on [0,ln7] and differentiable on (0,ln7).

By the given function, we have:

f(x) = ex is continuous on [0,ln7] since it is a composition of continuous functions.

f(x) = ex is differentiable on (0,ln7) since its derivative, f'(x) = ex, exists and is continuous on (0,ln7).

Thus, by the Mean Value Theorem, there exists at least one point c in (0,ln7) such that:

f'(c) = (f(ln7) - f(0))/(ln7 - 0)

Plugging in the values, we get:

[tex]ec = (e^{ln7} - e^0)/(ln7 - 0)[/tex]

ec = (7 - 1)/ln7

ec = 6/ln7

Therefore, the point guaranteed to exist by the Mean Value Theorem is c = ln(6/ln7).

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Xe2 means "X is an element of the set {2}". So, Xe2 means "the number of utilized stations is 2".
P(X=4) means "the probability that the number of utilized stations is exactly 4".

So, P(X+4)=0.15 means "the probability that the number of utilized stations plus 4 is equal to 4, which is equal to 0.15". This is not a meaningful statement.
The probability that the number of utilized stations is exactly 2 is given by P(X=2), which is equal to 0.2.
An event in which the number of utilized stations is exactly 2 is the event {X=2}.

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The expected number of times that both coins have come up tails will be 0.5 or 50%.

The probability of both coins coming up tails on a single flip is 1/4, since each coin has a 1/2 probability of coming up tails and the events are independent. If we flip the coins n times, the number of times both coins come up tails is a binomial random variable with parameters n and 1/4.

The expected value of a binomial random variable is given by np, where p is the probability of success on a single trial. In this case, we have p = 1/4, so the expected number of times that both coins come up tails in n flips is n(1/4). Therefore, if we flip the coins twice simultaneously, the expected number of times that both coins come up tails is (2)*(1/4) = 0.5.

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The three statements that describe weight are: B) Changes on different planets. C) Measured in kilograms (although technically weight is usually measured in Newtons).   F) Measured in Newtons.

Weight is the force caused by gravity on an object in mathematics.

It is estimated in Newtons and is relative to an article's mass, with the speed increase because of gravity as the proportionality steady.

Explanation:

Weight is the force that gravity puts on an object.

The weight of an object can change depending on the strength of gravity on different planets or celestial bodies.

Weight is commonly measured in Newtons, which is the SI unit of force. While mass is measured in kilograms, weight is technically measured in Newtons, which is equivalent to the mass multiplied by the acceleration due to gravity.

Option D is incorrect, as the amount of matter in a substance is referred to as mass, not weight.

Option A is incorrect because weight changes with gravity.

Option E is incorrect because even in the absence of gravity, an object still has mass and therefore still has weight, but the weight would be zero because there is no force of gravity acting on the object.

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a. The z-score of x = 3 is -4.00.

b. Rounding to two decimal places, the z-score of x = 5 is 0.00.

a. To find the z-score of x = 3, we use the formula:

z = (x - μ) / σ

where x is the given value, μ is the mean, and σ is the standard deviation.

Substituting the given values, we get:

z = (3 - 5) / 0.5

z = -4

Rounding to two decimal places, the z-score of x = 3 is -4.00.

b. To find the z-score of x = 5, we use the same formula:

z = (x - μ) / σ

Substituting the given values, we get:

z = (5 - 5) / 0.5

z = 0

Rounding to two decimal places, the z-score of x = 5 is 0.00.

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The chance of getting two 1s when rolling two dice is 1/36. This can be answered by the concept of Probability.

The probability of getting a 1 on the first die is 1/6, as mentioned in the question. And the probability of getting a 1 on the second die, given that the first die is a 1, is also 1/6, as mentioned in the question.

To find the probability of both events happening, we multiply the probabilities of each event occurring. So the probability of getting a 1 on the first die and then getting a 1 on the second die is (1/6) × (1/6) = 1/36.

Therefore, the correct answer is 1/36.

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For a population with a normal distribution, the mean (μ) is 27.5 and the standard deviation (σ) is 71.5. When drawing a random sample of size n=180, the mean of the distribution of sample means (μ¯x) is equal to the population mean (μ). Therefore, μ¯x = 27.5.
The standard deviation of the distribution of sample means (σ¯x) is calculated by dividing the population standard deviation (σ) by the square root of the sample size (n).
σ¯x = σ / √n = 71.5 / √180 ≈ 5.33 (rounded to 2 decimal places)
So, the mean of the distribution of sample means is 27.5, and the standard deviation of the distribution of sample means is 5.33.

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For a moving particle with velocity at time t is v(t) = t² -t - 6 (m/s), the displacement and distance of particle during the time period 1≤t≤4, are equal to -4.5 m and 1.16 m respectively.

We have a particle moves along a line. Velocity of particle at time t, v(t) = t² - t - 6, We have to calculate the displacement of the particle during the time period 1≤t≤4 and along with it calculate distance traveled during this time period. Using integration for determining the displacement, d[tex]= \int_{1}^{4} v(t)dt[/tex]

[tex]= \int_{1}^{4} ( t² - t -6)dt[/tex]

[tex]=[\frac{t³}{3} - \frac{t²}{2} - 6t]_{1}^{4}[/tex]

[tex]= [ \frac{4³}{3} - \frac{4²}{2} - 6×4 - \frac{1³}{3} + \frac{1²}{2} + 6×1][/tex]

[tex]= 21 - 18 - \frac{15}{2}[/tex]

= -4.5

Thus, the displacement of this object is -4.5 units of distance. Now, To determine the distance traveled, we need to consider all of the movement to be positive. So, v(t) = t² - t - 6

= t² + 2t - 3t - 6

= t( t + 2) - 3( t + 2)

= ( t + 2) (t -3)

so, v(t) > 0 for t [ 3, 4] and v(t) < 0 , [ 1, 3] so, distance [tex]= \int_{1}^{4} v(t)dt[/tex]

[tex]= \int_{1}^{3} - ( t² - t -6)dt + \int_{3}^{4} ( t² - t -6)dt [/tex]

[tex]=[-\frac{t³}{3} + \frac{t²}{2} + 6t]_{1}^{3} + [\frac{t³}{3} -\frac{t²}{2} - 6t]_{3}^{4}[/tex]

[tex]=[-\frac{3³}{3} + \frac{3²}{2} + 18 +\frac{1³}{3} - \frac{1²}{2} - 6 ] + [\frac{4³}{3} -\frac{4²}{2} - 24 - \frac{3³}{3} +\frac{3²}{2} + 18][/tex]

[tex]=[\frac{11}{3} + 6 + \frac{1}{2} ][/tex]

= 1.166 m

Hence, required value is 1.16m.

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The approximate volume of the given cylindrical container which has 3 balls is 63.62 in³, under the condition that tennis ball has a diameter of about 3 inches. Then, the required answer is 64 in³ which is Option A.

Now

The volume of a tennis ball is approximately

[tex]4/3 * \pi * (diameter/2)^{3}[/tex]

=[tex]4/3 * \pi * (1.5)^{3}[/tex]

= 14.137 in³.

Therefore, 3 balls are present in the container.

The diameter of a tennis ball = 3 inches,

Radius = 1.5 inches.

The height of the cylindrical container can be evaluated by multiplying the diameter of a tennis ball by three

Now,  three tennis balls are kept on top of each other.

Then, the height of the cylindrical container

3 × 3 = 9 inches.

The radius = 1.5 inches.

The volume of a cylinder = [tex]V = \pi * r^2 * h[/tex]

Here,

 V = volume,

r = radius

h = height.

Staging the values

[tex]V = \pi * (1.5)^{2} * 9[/tex]

= 63.62 in³.

The approximate volume of the given cylindrical container which has 3 balls is 63.62 in³, under the condition that tennis ball has a diameter of about 3 inches. Then, the required answer is 64 in³ which is Option A.

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The zeros of P(x) are x = 0 with multiplicity 3 x = √7i with multiplicity 1 x = -√7i with multiplicity 1

What is polynomial?

A polynomial is a mathematical expression consisting of variables and coefficients, which are combined using arithmetic operations such as addition, subtraction, multiplication, and non-negative integer exponents

First, let's factor out the common factor of x³ from the polynomial:

P(x) = x⁵ + 7x³ = x³(x² + 7)

So, the zeros of P(x) are the zeros of x³ and the zeros of x² + 7.

The only real zero of x³ is x = 0 with multiplicity 3.

The zeros of x² + 7 can be found using the quadratic formula:

x = (-b ± √(b² - 4ac))/2a

where a = 1, b = 0, and c = 7. Plugging in these values, we get:

x = ±√(-7)

Since the square root of a negative number is imaginary, the zeros of x²+ 7 are complex numbers. Specifically, they are:

x = ±√7i with multiplicity 1 each.

Therefore, the complete factorization of P(x) is:

P(x) = x³(x² + 7) = x³(x - √7i)(x + √7i)

The zeros of P(x) are:

x = 0 with multiplicity 3 x = √7i with multiplicity 1 x = -√7i with multiplicity 1

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The equation of the circle centered at the origin with a radius of 12 is x² + y² = 144.

In order to find the equation of a circle centered at the origin with a radius of 12, we need to use the standard form equation of a circle, which is:

(x - h)² + (y - k)² = r²

Where (h,k) represents the center of the circle, and r represents the radius.

In this case, since the circle is centered at the origin, h = 0 and k = 0. Also, since the radius is 12, we can substitute r = 12 in the above equation to get:

x² + y² = 12²

Simplifying further, we get:

x² + y² = 144

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