Please help look at the picture below

The mass of the iron III oxide produced from the stoichiometry of the reaction is  1.22 g.

We have the reaction equation as;

[tex]2Fe(s)+3H_{2}O(g)--- > Fe_{2}O_{3} (s)+3H_{2} (g)[/tex]

The number of moles of the water vapor is obtained from;

PV = nRT

P = pressure of the gas

V = volume of the gas

n = Number of moles of the gas

R - gas constant

T = Temperature of the gas

n = PV/RT

n = 0.121 * 5/0.082 * 323.2

n = 0.605/26.5

n = 0.0228 moles

Then;

3 moles of water vapor produces 1 mole of iron III oxide

0.0228 moles of water vapor produces 0.0228 * 1/3

= 0.0076 moles

Mass of iron III oxide produced = 0.0076 moles * 160 g/mol

= 1.22 g

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Answer: The calcium ion has a 2+ charge and the phosphate ion has a 3- charge.

Answer: The final pressure inside the tank is 8.41 kPa.

Explanation: We can use the combined gas law to solve this problem, which relates the pressure, volume, and temperature of a gas:

(P1V1)/T1 = (P2V2)/T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

We are given P1 = 25.0 kPa, T1 = -50 C = 223 K, and V1 is unknown. We also know that the temperature decreases by a factor of three, so T2 = T1/3 = 223/3 K.

To find V2, we need to assume that the steel container is rigid and its volume remains constant. Therefore, V1 = V2, and we can cancel out the volume from the equation:

P1/T1 = P2/T2

Substituting the values, we get:

P2 = P1 * T2 / T1 = 25.0 * (223/3) / 223 = 8.41 kPa

Therefore, the final pressure inside the tank is 8.41 kPa.

Answer:

So if pressure of a gas is increased by 25%, the volume of a gas is decreased by 25%.

Explanation:

Answer:The pressure of 1.0 x 10^-5 mm Hg is equivalent to 1.33322 x 10^-3 Pa.

Explanation:

The pressure of 1.0 x 10^-5 mm Hg is equivalent to 1.33322 x 10^-3 Pa.

An aqueous magnesium chloride solution is made by dissolving 7.40 moles of MgCl₂ in sufficient water so that the final volume of the solution is 4.80 L. the molarity of the MgCl₂ solution is equal to 1.54 M.

Molarity is a unit of concentration, which measures the number of moles of a solute per liter of a solution. To calculate molarity, one divides the amount of solute (in moles) by the total volume of the solution (in liters). In chemistry, molarity is often used to measure concentrations of acids, bases, and other solutes in solutions. This unit of concentration is important in lab work, as it allows scientists and researchers to accurately measure and predict the behavior of solutions.

Molarity (M) = /[tex]\frac{moles of solute}{liters of solution }[/tex]

Molarity (M) =  [tex]\frac{7.4mol}{4.8L}[/tex]

Molarity (M) = 1.54 M

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Benzene has a combustion energy of -3.11 kJ/g.

The balanced formula for benzene combustion is

[tex]6CO_2 + 3H_2O from C_6H_6 + 15O_2[/tex]

We may use the stoichiometric ratio of benzene to oxygen, 1:15, to calculate how much oxygen is necessary to burn 0.500 g of benzene:

O2:15 moles:1 mole [tex]C_6H_6[/tex]

0.000476 moles C6H6: 0.00714 moles [tex]O_2[/tex].

3266 kJ/mol of energy is released during the combustion of one mole of benzene. The energy produced as a result of burning 0.000476 moles of benzene is:

E = 3266 kJ/mol 0.000476 moles.

ΔE = -1.556 kJ

determine how much energy the water has absorbed:

q = m × c × ΔT

According to the preceding question, if the water's beginning temperature is 25.0°C and its end temperature is 36.2°C, the temperature change is:

ΔT = 36.2°C - 25.0°C

ΔT = 11.2°C

Now that the values have been substituted, we can determine how much heat the water has absorbed:

250.0 g, 4.184 J/g, 11.2°C, and q

q = 11,126.4 J

The combustion energy per gramme of benzene may then be calculated by converting the units of E to kJ/g as follows:

ΔE = -1.556 kJ / 0.500 g

ΔE = -3.11 kJ/g

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The combustion energy of benzene is -3.11 kJ/g.

What is  Combustion Energy?

The energy released when a specific quantity of a substance burns entirely in oxygen is known as the heat of combustion of the substance.

Calculation-

1 mole of O2 in 15 moles

0.00714 moles: 0.000476 moles of C6H6.

The form of the energy is:

E is 3266 kJ per mole, or 0.000476 moles.

ΔE = -1.556 kJ

tally up the energy that the water has absorbed:

q = m × c × ΔT

The shift in temperature is:

ΔT = 36.2°C - 25.0°C

ΔT = 11.2°C

How much heat the water has absorbed can be calculated:

4.184 J/g, 11.2 °C, 250.0 g, and q

q = 11,126.4 J

By changing the units of E to kJ/g, it is possible to compute the combustion energy per gramme as follows:

ΔE = -1.556 kJ / 0.500 g

ΔE = -3.11 kJ/g

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Magnesium bromide is the limiting reagent, and the amount of [tex]MgCl_{2}[/tex] formed will be limited by the amount of magnesium bromide available. The excess reactant will be sodium chloride.

What is limiting reagent?

To determine which of the two reactants, magnesium bromide or sodium chloride, is the limiting reagent, we need to calculate the amount of product that can be formed from each reactant and compare the results.

Let's assume that magnesium bromide and sodium chloride react to form magnesium chloride and sodium bromide, and the balanced chemical equation for the reaction is:

[tex]MgBr_{2}[/tex] + 2NaCl → 2NaBr + [tex]MgCl_{2}[/tex]

The molar masses of each compound are:

The first step is to calculate the number of moles of each reactant, given that we have 2 grams of each:

moles of [tex]MgBr_{2}[/tex] = 2 g / 184.11 g/mol = 0.01085 mol

moles of NaCl = 2 g / 58.44 g/mol = 0.03423 mol

Now, we can use the stoichiometry of the balanced equation to calculate the theoretical yield of product for each reactant:

Using [tex]MgBr_{2}[/tex]: 0.01085 mol [tex]MgBr_{2}[/tex] x (1 mol [tex]MgCl_{2}[/tex] / 1 mol [tex]MgBr_{2}[/tex]) x (95.21 g [tex]MgCl_{2}[/tex] / 1 mol [tex]MgCl_{2}[/tex]) = 1.034 g [tex]MgCl_{2}[/tex]

Using NaCl: 0.03423 mol NaCl x (1 mol [tex]MgCl_{2}[/tex] / 2 mol NaCl) x (95.21 g [tex]MgCl_{2}[/tex] / 1 mol [tex]MgCl_{2}[/tex]) = 1.633 g [tex]MgCl_{2}[/tex]

From the above calculation, we can see that the theoretical yield of [tex]MgCl_{2}[/tex] is lower when magnesium bromide is used as the reactant (1.034 g), compared to when sodium chloride is used (1.633 g). Therefore, magnesium bromide is the limiting reagent, and the amount of [tex]MgCl_{2}[/tex] formed will be limited by the amount of magnesium bromide available. The excess reactant will be sodium chloride.

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Complete question is: if given 2 grams of magnesium bromide and sodium chloride; magnesium bromide would be the limiting reagent.

The limiting reagent would be the magnesium bromide because it is present in the smallest quantity.

Magnesium is a silvery-white chemical element and is the ninth most abundant element in the universe. It is a key component of chlorophyll and is essential for plant and animal life. Magnesium is also an important mineral for human health, playing a role in over 300 biochemical processes in the body. It is involved in energy production, DNA and RNA synthesis, and muscle, nerve, and enzyme function. Magnesium is found in many foods, including green leafy vegetables, nuts, seeds, and whole grains. Magnesium supplements are also available and are commonly used to help prevent or treat magnesium deficiency.

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The mass of Kr in a 9.95 L cylinder at 91.2 ∘C and 4.50 bar is 1.24 g.

In order to find the mass of Kr, we must utilize the Ideal Gas Law equation:

PV = nRT

n = PV/RT

T = 91.2 + 273.15 = 364.35 K and R = 8.314 J/(mol*K)

n = (4.50 bar) * (9.95 L) / (8.314 J/(mol*K) * 364.35 K)

n = 0.01478 mol.

actual mass of Kr

mass = n * molar mass

molar mass of Kr = 83.798 g/mol

mass = 0.01478 mol. * 83.798 g/mol

mass = 1.24 g.

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The volume of carbon dioxide is produced at 31.0 ∘C and 0.995 atm is 119,786 L

We must ensure that you have a balanced chemical equation

We can multiply 611 * 16 and divide by the 2. We have 4888 moles  CO2.

We determine the  volume by using ideal gas law

(PV=nRT).

P = 0.995 atm

V = x

n = 4888 mol CO2

T = 24.0C + 273 K = 297 K

R = 0.0821 (L*atm)/(mol*K)

PV =

nRT  

V  = (nRT)/P

V = ((4888 mol)(0.0821 L*atm/mol*K)(297K))/(0.995 atm)

V = 119,786 L

Therefore, the volume of carbon dioxide is produced at 31.0 ∘C and 0.995 atm is 119,786 L

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Five is the total number of peaks due to singly charged ions in the complete mass spectrum of chlorine, [tex]Cl_{2}[/tex]

How many peaks do [tex]Cl_{2}[/tex]'s molecular ions have?

The mass spectra of compounds with a single chlorine atom show two molecular ion peaks. This is because there are two isotopes of chlorine, 35Cl and 37Cl.

The molecular ion and fragment ions will both have peaks in the mass spectrum. When a mass spectrum is interpreted, a specific molecule can be located, confirmed, or its quantity can be calculated. the base summit of a mass spectrum's tallest (strongest) peak, caused by the ion with the highest relative abundance

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Five is the total number of peaks due to singly charged ions in the complete mass spectrum of chlorine, [tex]Cl_{2}[/tex].

How many peaks do 's molecular ions have?

The mass spectra of compounds with a single chlorine atom show two molecular ion peaks. This is because there are two isotopes of chlorine, 35Cl and 37Cl.

The molecular ion and fragment ions will both have peaks in the mass spectrum. When a mass spectrum is interpreted, a specific molecule can be located, confirmed, or its quantity can be calculated. the base summit of a mass spectrum's tallest (strongest) peak, caused by the ion with the highest relative abundance

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Answer:

66 grams of ice would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C.

Explanation:

To calculate the amount of ice that would have to melt to lower the temperature of 352 mL of water from 15 °C to 0 °C, we need to use the formula:

Q = m_water * c_water * ΔT_water + m_ice * Lf

where,
Q = the amount of heat transferred,
m_water = the mass of water, c_water is the specific heat capacity of water,
ΔT_water = the change in temperature of water, m_ice = the mass of ice,
Lf = the specific latent heat of fusion of ice.

First, let's calculate the amount of heat transferred to the water:

Q = m_water * c_water * ΔT_water
Q = 352 g * 1.0 cal/(g*°C) * (15-0) °C
Q = 5,280 cal

Next, we can use the specific latent heat of fusion of ice, which is 80 cal/g, to calculate the amount of heat required to melt the ice:

Q = m_ice * Lf
Q = m_ice * 80 cal/g
m_ice = Q / Lf
m_ice = 5,280 cal / 80 cal/g
m_ice = 66 g

5.61 liters of hydrogen gas would be produced when 4.50 g of aluminum reacts with concentrated hydrochloric acid at STP

The volume of the hydrogen gas that will be produced at STP is calculated as follows;

Molar mass of Al = 26.98 g/mol

Number of moles of Al = 4.50 g / 26.98 g/mol

Number of moles of Al = 0.167 mol

The number of moles of H₂ produced is calculated as follows;

Number of moles of H₂ = (3/2) x 0.167 mol = 0.2505 mol

Volume of H₂ at STP = 0.2505 mol x 22.4 L/mol = 5.61 L

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Answer: i dont quite know but its A or C

Explanation:

i dont quite know because the "table" is not provided hope this helps! <3

Answer:

115.6 kJ/mol

Explanation:

The ΔG of a reaction can be calculated using the following equation:

ΔG = ΔG° + RT ln(Q)

where:

ΔG° is the standard free energy change, which is given as 137.0 kJ/mol in this case

R is the gas constant, which is 8.314 J/(mol·K)

T is the temperature in Kelvin, which is 25°C + 273.15 = 298.15 K

Q is the reaction quotient, which is the ratio of the concentrations of the products to the concentrations of the reactants, each raised to their stoichiometric coefficients.

From the chemical equation given, the stoichiometric coefficients of Mg2+ and PO43- are 3 and 2 respectively. Therefore, the reaction quotient can be expressed as:

Q = [Mg2+]^3 [PO43-]^2

Substituting the given initial concentrations of Mg2+ and PO43- into the reaction quotient expression, we get:

Q = (0.65 M)^3 (0.43 M)^2 = 0.011 M^5

Now we can calculate the ΔG of the reaction:

ΔG = ΔG° + RT ln(Q)

ΔG = (137.0 kJ/mol) + (8.314 J/(mol·K) × 298.15 K) × ln(0.011 M^5)

ΔG = 137.0 kJ/mol - 21.38 kJ/mol

ΔG = 115.6 kJ/mol

Therefore, the ΔG for the reaction at 25°C and the given initial concentrations of Mg2+ and PO43- is 115.6 kJ/mol.

Yes, we can use the moles of reactants and products at equilibrium instead of their concentrations to calculate the equilibrium constant because the molar amount of a substance is directly proportional to its concentration.

The equilibrium constant of a chemical reaction is a numerical value that relates the concentrations (or pressures) of the reactants and products at equilibrium.

The equilibrium constant expression for the hypothetical reaction, A + B ⇌ X + 2Y, is given by:

[tex]Kc = [X][Y]^2 / [A][B][/tex]

where [X], [Y], [A], and [B] represent the equilibrium concentrations of X, Y, A, and B, respectively.

Yes, we can use the moles of reactants and products at equilibrium instead of their concentrations to calculate the equilibrium constant. This is because the molar amount of a substance is directly proportional to its concentration. So, if we know the moles of reactants and products at equilibrium, we can easily calculate their concentrations, and hence the equilibrium constant.

If the initial ratio of CH₃COOH and C₂H₅OH is adjusted to 2:1, it will change the equilibrium constant value. This is because the equilibrium constant depends on the relative concentrations of reactants and products at equilibrium. When the initial ratio of reactants is changed, the equilibrium concentrations of reactants and products will also change to reach a new equilibrium position. As a result, the equilibrium constant value will also change.

In general, it is difficult to predict the exact effect of changing the initial ratio of reactants on the equilibrium constant value without knowing the specific reaction and its reaction quotient. However, we can say that increasing the concentration of one reactant relative to the other will tend to shift the equilibrium position in the direction that consumes that reactant. As a result, the equilibrium constant value may increase or decrease depending on the specific reaction.

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To determine the (gt-l) strength of an HCl solution: HCI Strength = HCI Molarity HCI -M mol wt. 36,5 Result: HCl solution molarity HCl solution strength = 2.

We know the volume of acid (which we took originally) and the volume of base (which we recorded at the endpoint), as well as the concentration of base, so we can compute the concentration of acid. As a result, the endpoint of an acid-base titration is measured by a change in colour.  Titration is a volumetric measurement.

The pH of the solution generated by adding one drop of 2 M HCl to 100 mL of water would thus be 3.

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The addition of hydrochloric acid to a reaction mixture can serve several purposes, depending on the specific reaction and its conditions such as: (1) To provide protons (H⁺), (2) To adjust the pH of the reaction mixture, (3) To remove impurities or byproducts.

(1) To provide protons (H⁺) for acid-catalyzed reactions: HCl is a strong acid, meaning it readily donates protons to other molecules. In some reactions, the presence of HCl can accelerate the reaction by increasing the concentration of protons in the reaction mixture. This can facilitate bond-breaking and bond-forming steps in the reaction mechanism.

(2) To adjust the pH of the reaction mixture: In some reactions, it may be necessary to maintain a specific pH range for the reaction to proceed optimally. By adding HCl, the pH of the reaction mixture can be lowered, making the environment more acidic. Conversely, the addition of a base such as sodium hydroxide (NaOH) can raise the pH of the reaction mixture.

(3) To remove impurities or byproducts: In some reactions, the addition of HCl can help to remove impurities or byproducts that may interfere with the desired reaction. For example, HCl can be used to remove metal oxides or hydroxides from a reaction mixture.

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Answer:

Explanation:

In distillation, q is defined as the moles of liquid flow in the stripping section per mole of feed introduced. The values of q for saturated liquid feed and for saturated vapor feed are 0 and infinity, respectively.

The proximity of unsaturated groups (C=C, C=O, aromatic) and electronegative atoms (O, N, halogen) has an impact on the proton NMR chemical shift. Electronegative groups shift to the left (down field; ppm rise).

The chemical shift in nuclear magnetic resonance (NMR) spectroscopy refers to the atomic nucleus' resonant frequency in relation to a standard in a magnetic field. The location and quantity of chemical changes frequently serve as diagnostic indicators of molecular structure.

You take into account the chemically non-equivalent proton(s) one at a time while making chemical shift predictions. Find the origin of each proton or proton pair that is not chemically comparable. Whether the proton(s) is/are linked to a methyl, methene, or methine determines the beginning point.

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The number of MnO2(s) that  should be added to excess HCl(aq) to obtain 105 mL Cl2(g) at 25 °C and 765 Torr is 0.939 g of  MnO2.

MnO2(s) + 4HCl(aq) ==> MnCl2(aq) + 2H2O(l) + Cl2(g)  ...  balanced equation

The first step is to  find how many moles of Cl2 gas is to be obtained:

Ideal gas law

PV = nRT

P = pressure = 705 torr x 1 atm/760 torr = 0.928 atm

V = volume = 285 ml = 0.285 L

n = moles = ?

R = gas constant = 0.0821 Latm/Kmol

T = temperature in K = 25C + 273 = 298K

n = moles = PV/RT = (0.928)(0.285) / (0.0821)(298)

n = 0.0108 moles of Cl2

We now apply dimensional analysis and the stoichiometry of the balanced equation and  solve for moles and grams of MnO2.

0.0108 mol Cl2 x 1 mol MnO2 / mol Cl2 = 0.0108 moles

0.0108 mol MnO2 x 86.9 g/mol MnO2 = 0.939 g

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3 is the coefficient in front of carbon dioxide in the balanced chemical equation

What does a balanced formula equation mean?

A balanced chemical equation is one in which the mass of the reactants and products are equal, and each element has an equal number of atoms on both sides of the equation.

Different numbers of atoms from various elements can be found in reactants and products in unbalanced chemical equations. When utilizing a constant, a balanced equation is crucial since the coefficients transform into the powers of the concentrations of the reactants and products. The constant must be accurate for the equation to be balanced.

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The products of the hydrolysis reaction is Carboxylic acid + Alcohol.

A hydrolysis process occurs when a larger molecule splits into many smaller ones. An alcohol and a carboxylic acid are created when an ester is hydrolyzed by an acid. When an ester experiences basic hydrolysis, two products are created: an alcohol and a carboxylate salt (saponification).

The hydrolysis (a cleavage reaction with water) that all carboxylic acid derivatives go through to produce carboxylic acids unites them all. with the hydroxide ion to produce an alcohol and a carboxylate salt. When a powerful acid is then added to the reaction mixture, the carboxylic acid itself is created.

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Answer: A. Partially melted snowfield.

Explanation:

Answer:

so you hit a 360

Explanation:

and you need to eats the food

The work done by a A person uses their muscles and puts in a force of 5 Newtons (N) to move a box a distance of 10 meters, but the box did not move is 50 Nm. Thus, to move the box work of more than 50Nm needs to be done. The correct option to this question is C.

Work done(W) = Force(F)× distance(D)

Substituting the value in above equation,

W= 5×10

W= 50 Nm

The energy that is transmitted to or from an item by applying force along a displacement is referred to as work in physics. The work is defined as the sum of the force intensity and the distance traveled for a constant force acting in the direction of motion.

The product of the force component acting in the displacement's direction and its size is known as the work done by a force. Formula. By multiplying Force and Distance in the direction of the force, one can determine work. W = F × d.

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Complete question: A person uses their muscles and puts in a force of 5 Newtons (N) to move a box a distance of 10 meters, but the box did not move. How much work was done? (Hint: W=FxD)

Responses

A. 5 Nm

B. 500 Nm

C. 50Nm

D. 0 Nm

1 mole=6.022×1023 molecules. Mass of 6.022×1023 atoms of silver (Ag)=108g (Given, atomic mass is 108g) ⸫ Mass of one atom of Silver =108 / 6.022×1023g.=1.79×10-22g

An element's mass number is determined by the sum of its proton and neutron counts: Protons and neutrons together make up mass. Simply deduct the number of protons, or atomic number, from the mass number to get how many neutrons each atom has.

The atomic number (Z) is equal to the number of protons in the atom's nucleus. In a neutral atom, there are exactly as many electrons as protons.

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Answer:

The molecular weight of sodium chloride is 58.44 which corresponds with 1 mole. The molar concentration is the number of moles in 1L of solvent. In our case - a solution of 0.25M has 0.25moles/1L of water.