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The gold is not the compound.

The information related to the compound is as follows

Therefore we can say that gold is not the compound.

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Answer:

The mass

Explanation:

the mass grams of 3.75 × 10 21 atoms of Li is

40. 21 atom of Li

Answer:

[tex]pH=12.3\\\\pOH=1.7\\[/tex]

[tex][H^+]=5x10^{-13}M[/tex]

[tex][OH^-]=0.02M[/tex]

Explanation:

Hello there!

In this case, according to the given ionization of magnesium hydroxide, it is possible for us to set up the following reaction:

[tex]Mg(OH)_2(s)\rightleftharpoons Mg^{2+}(aq)+2OH^-(aq)[/tex]

Thus, since the ionization occurs at an extent of 1/3, we can set  up the following relationship:

[tex]\frac{1}{3} =\frac{x}{[Mg(OH)_2]}[/tex]

Thus, x for this problem is:

[tex]x=\frac{[Mg(OH)_2]}{3}=\frac{0.03M}{3}\\\\x= 0.01M[/tex]

Now, according to an ICE table, we have that:

[tex][OH^-]=2x=2*0.01M=0.02M[/tex]

Therefore, we can calculate the H^+, pH and pOH now:

[tex][H^+]=\frac{1x10^{-14}}{0.02}=5x10^{-13}M[/tex]

[tex]pH=-log(5x10^{-13})=12.3\\\\pOH=14-pH=14-12.3=1.7[/tex]

Best regards!

The answer is It is NH3.....

Answer:

Dandelion seed

Explanation:

(I learnt it in camp)

Answer:

C Dandelion Seed

Explanation:

Dandelion Seed are light enough to be carried by the wind.

Answer:b

Explanation: the particles will soon dissolve which means that the particles are changing but the volume is staying the same and the concentration is changing

The  identification of the variables which  is correct is that the number of solute particles is being changed between the two solutions, but the volume and concentration of the solution is being held constant.

Variables are defined as any characteristics, number or quantity which can be measured . It can also be called as a data item . It is called as variable because they can vary and can have variety of values.

There are three types of variables 1) manipulated variable where in a condition is specified, 2) responding variable which is dependent on manipulated variable 3)controlled variable which do not change.

Example of manipulated variables are number of hours spent by a student studying , that of responding variable is result of a student and temperature is an example of controlled variable.

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#SPJ3

Answer:

V=0.430 Liters

Explanation:

First off you need to convert ml to l and celsius to kelvin, in order for them to be in the S.I.

So, 350.0mL is 0.350 L and 23.0 C is (273.15+23=) 296.15 K (you can ignore the 0.15)

From the equation pV=nRT, lets name this equation (1),  we can tell that the number of moles, pressure, and R, stay the same. The only thing changing is the volume, and temperature.

With the information given, let's figure out the pressure. From equation (1) if we solve it for the pressure of the gas, p=nRT/V => p=nR*296.15/0.350 => p=846.15 *nR

Now, we have to figure out the volume of the gas at 90.0 C (363.15 K), and solve equation (1) for volume, using the pressure we previously found.

v=nRT/p => v=nR*363.15/846.15*nR => (the nR's from top and bottom go away) v=0.429 L

Since we used 273.15 for the conversion of celsius to Kelvin, we could round up the number to

V=0.430 Liters

Answer:

neutrons is metal.......

Answer:

Si.

Explicación:

Sí, la aplicación de medidas de seguridad depende de las características de su entorno porque el entorno nos brinda para elegir las medidas de seguridad. Existen diferentes instrumentos utilizados para la seguridad de diferentes entornos. Algunas medidas de seguridad se aplican en un entorno mientras que el otro se aplica a otro entorno. Por ejemplo, el vallado es una medida de seguridad que se puede aplicar en el terreno pero no en el agua o cualquier zona fangosa, por lo que podemos decir que las características físicas deciden qué medida de seguridad se debe instalar en el entorno.

Answer:

i guess you mean its volume, so the answer is "shrunken" 3 times

Explanation:

from the equation pV=nRT, whatever happens to its pressure, the opposite happens to its volume.

Answer:

Answer is meter. ~~~~~~

Answer: heyyyooo

The bond polarity for each bond in a BH3 molecule is polar, due to the difference in electronegativities of the B and H atom. The molecular shape is trigonal planar, and the molecule is non-polar - because due to the symmetry of the molecule, the polarities cancel out.

Explanation:

hope this helps!

Answer:

0.96

Explanation:

Number of moles of Fe(III) = 3/1000 *  0.002 M = 6 * 10^-6 moles

Number of moles of SSA = 7/1000 * 0.02 = 1.4 * 10^-4 moles

Total number of moles =  6 * 10^-6 moles +  1.4 * 10^-4 moles

Mole fraction of SSA = number of moles of SSA/ total number of moles.

Mole fraction of SSA =  1.4 * 10^-4 moles/  6 * 10^-6 moles +  1.4 * 10^-4 moles

Mole fraction of SSA = 0.96

Answer:

Ball and stick models are three-dimensional models where atoms are represented by spheres of different colors and bonds are represented by sticks between the spheres. ... Space fill models are similar to ball and stick models in that they are three-dimensional models that represent atoms as colored spheres.

Answer:

Option 2: 6KCl + Ca₃(PO₄)₂

Explanation:

K₃PO₄ + CaCl₂ → Ca₃(PO₄)₂ + KCl

Balancing the equation,

2K₃PO₄ + 3CaCl₂ → Ca₃(PO₄)₂ + 6KCl

∴ the correct formula and coefficients of the products in the equation are,

6KCl + Ca₃(PO₄)₂

Answer:

Because of the gravity of the Earth

Answer:

The molar concentration of base Cb = 14.2777M

Explanation:

Volume of acid Va = 38.70cm^3,

Concentration of acid NaO4 C_a= 1.90M

Volume of Base Vb = 10.30cm^3

Also, Equation of the reaction

H2SO4 + 2NaOH = Na2SO4 + 2H2O

No of mole of acid Na = 1

No of mole of base Nb = 2

CaVa/CbVb = Na/Nb

Cb = CaVaNb/VbNa

Cb = 1.9×38.7×2/(10.30×1)

Therefore, Cb = 14.2777M

The molar concentration of base Cb = 14.2777M

Answer:

Option D

Explanation:

As we know at

PV = nRT

at STP,

Pressure is  1 atm and temperature is 273 K

[tex]\frac{P_2}{P_1} = \frac{T_2}{T_1} \\P_2 = 1*(428 )/273\\P_2 = 1.567[/tex]

Hence, option D is correct

Answer:  [tex]P_4O_{10}[/tex] is the limiting reagent

66.6 g of [tex]H_3PO_4[/tex] will be formed.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]  [tex]\text{Moles of} P_4O_{10}=\frac{40g}{284g/mol}=0.14moles[/tex]

[tex]\text{Moles of} H_2O=\frac{30g}{18g/mol}=1.7moles[/tex]

[tex]P_4O_{10}+6H_2O\rightarrow 4H_3PO_4[/tex]  

According to stoichiometry :

1 mole of [tex]P_4O_{10}[/tex] require 6 moles of [tex]H_2O[/tex]

Thus 0.14 moles of [tex]P_4O_{10}[/tex] will require=[tex]\frac{6}{1}\times 0.14=0.84moles[/tex]  of [tex]H_2O[/tex]

Thus [tex]P_4O_{10}[/tex] is the limiting reagent as it limits the formation of product and [tex]H_2O[/tex] is the excess reagent.

As 1 mole of [tex]P_4O_{10}[/tex] give = 4 moles of [tex]H_3PO_4[/tex]

Thus 0.17 moles of [tex]P_4O_{10}[/tex] give =[tex]\frac{4}{1}\times 0.17=0.68moles[/tex]  of [tex]H_3PO_4[/tex]

Mass of [tex]H_3PO_4=moles\times {\text {Molar mass}}=0.68moles\times 98g/mol=66.6g[/tex]

Thus 66.6 g of [tex]H_3PO_4[/tex] will be formed.

Answer:

the guy above is wrong

Explanation:

i just did the test and got it wrong

Answer:

The Moon orbits the Earth which orbits the Sun.

Explanation:

Answer: The freezing point depression is [tex]1.86^0C[/tex]

Explanation:

Depression in freezing point is given by:

[tex]\Delta T_f=K_f\times m[/tex]

[tex]\Delta T_f[/tex] = Depression in freezing point

[tex]K_f[/tex] = freezing point constant = [tex]1.86^0C/m[/tex]

m= molality = [tex]\frac{\text {moles of solute}}{\text {mass of solvent in kg}}=\frac{2mol}{2kg}=1m[/tex]

[tex]\Delta T_f=1.86mol/kg^0C\times 1m[/tex]  

[tex]\Delta T_f=1.86^0C[/tex]  

Thus freezing point depression is [tex]1.86^0C[/tex]

Answer:

280 liters at STP are in 8.0*10² grams of sulfur dioxide.

Explanation:

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

In this case, the molar mass of sulfur dioxide, that is, the mass of one mole of the substance, is 64 g/mole.

You can apply the following rule of three: if by definition of molar mass 64 grams of sulfur dioxide are contained in 1 mole, 8.0*10² grams are contained in how many moles?

[tex]amount of moles=\frac{8*10^{2}grams*1 mole }{64 grams}[/tex]

amount of moles= 12.5 moles

Now you can apply a new rule of three: if by STP conditions 1 mole of any gas occupies a volume of 22.4 liters, 12.5 moles will occupy how much volume?

[tex]volume=\frac{12.5 moles*22.4 L}{1 mole}[/tex]

volume= 280 L

280 liters at STP are in 8.0*10² grams of sulfur dioxide.

Answer:

electrons

galvanic

half-

electrode

Explanation:

I got it right :)

The words that complete each of the blanks in the question are;

A voltaic cell is one that produces energy by a sponteanous chemical reaction. A voltaic cell is a type of electrochemical cell.

The following are the words that complete the individual blanks';

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A and B are true.

C and D are false.

Out of the given four statements, A and B are only correct.

Explanation:

So from this, we can conclude that out of the given four statements, A and B are only correct.

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