Answer:
2.920
Explanation:
This question tests your knowledge of approximation. If we look at the place values after the decimal point, we have, .915. This corresponds to hundredth, tenth and unit.
Since we have 9.15, in rounding it to the nearest tenth, we have to round it up to .920.
Hence, the weight of the flour to the nearest tenth is 2.920.
Which has the lowest pH?
water
baking soda
bleach vinegar
Answer:
c. baking soda
Explanation:
Kinds of matter with label and example
Answer:
Liquid: water
Solid: Rocks
Gas: Air
Explanation:
If a chemical reaction leaves you with a new
substance, what do you
think a physical
change/reaction will be?
Answer:
Explanation:
During a physical temperature change, one substance, such as water will be heated. Because one compound is mixed in with another. Therefore, these reactants produce a product. When the reactants are mixed, the temperature change caused by the reaction is an indicator of a chemical change.
5) Which of these are intensive properties?
a substance has a volume of 5.4 mL
a substance has a mass of 1.25 g
a substance has a density of 4.13 g/cm3
a substance has a melting point of 40°C
a substance is very malleable (it can be hammered into a shape)
6) Which of these are extensive properties?
a substance has a melting point of 40°C
a substance is very malleable (it can be hammered into a shape)
a substance has a volume of 5.4 mL
a substance has a mass of 1.25 g
a substance has a density of 4.13 g/cm3
Answer:
For number 5 it is the 2nd one some stants has a mass of 1.25 g And the 2nd 1 number 6It is the 1st 1A subject has a melting point of 40
Electronegativity and ionization energy __________ from left to right within a period and __________ from top to
bottom within a group.
Answer:
C, increases/decreases
Explanation:
As you move down a group on the periodic table, the electronegativity of an element decreases because the increased number of energy levels puts the outer electrons very far away from the pull of the nucleus.
Why don't solids, liquids, and gases leave Earth's atmosphere? A) Only gases can leave the atmosphere. B) Matter on Earth is destroyed and recycled. C) Gravity keeps all matter on Earth.
Answer:
The answer is C) Gravity keeps all matter on Earth.
Explanation:
I took the test and this was correct!
(Not a fake answer like some, I promise!)
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Answer:
omggggggggg that is sooo confusing what grade are you in?
A homogeneous mixture is:
A. composed of only one type of element.
B. composed of different parts that are indistinguishable in their color, texture, or appearance.
C. composed of different parts that are distinguishable in their color, texture, or appearance.
D. composed of atoms bonded together.
Answer: A homogeneous mixture is a solid, liquid or gaseous mixture that has the same proportions of its components throughout any given sample.
Explanation:
A homogeneous mixture is composed of different parts that are indistinguishable in their color, texture, or appearance.
What is the difference between homogenous and heterogeneous mixtures?
The extent of the elements' mixing together and the uniformity of their composition distinguish heterogeneous mixtures from homogeneous ones.
Homogenous mixtureWhen the elements that make up a combination are evenly distributed throughout the mixture, the mixture is said to be homogenous. The combination has a constant composition throughout. In a homogeneous mixture, only one phase of matter is visible at any given time. In a homogenous mixture, you would not see a liquid and a gas or a liquid and a solid.Examples: air, sugar water, steel, etc.Heterogeneous mixtureA heterogeneous mixture is one in which the constituent parts are not uniform or have discrete areas with various qualities. The various samples from the mixture differ from one another. In a heterogeneous mixture, even though two or more regions have the same state of matter, you can always distinguish between them by looking at their unique qualities.Examples: Cereal in milk, vegetable soup, blood, etc.Learn more about homogenous and heterogeneous mixtures here:
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Which is a feature of a single replacement reaction?
Substance XYZ breaks down into X and YZ.
Substance G reacts with compound XY to form GY and X.
Substance X burns rapidly in the presence of oxygen.
Substance QR and GT exchange ions with each other.
Answer:
Its B
Explanation:
Because im just built different
The statement featuring the single replacement reaction has been statement B.
The single replacement reaction has been defined as the reaction of the highly reactive element with the compounds, that results in the formation of the new compound with the replacement of the less reactive element.
The single replacement reaction can be given as:
G + XY [tex]\rightarrow[/tex] GY + X
In the reaction, G being more reactive than X has been able to displace X and forms bond with Y. Thus, statement featuring the single replacement reaction has been B.
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The following initial rate data are for the reaction of nitrogen dioxide with carbon monoxide:
NO2 + CO --> NO + CO2
Experiment [NO2]o, M [CO]o, M Initial Rate, Ms-1
1 0.374 0.300 8.39×10-2
2 0.374 0.600 8.39×10-2
3 0.749 0.300 0.337
4 0.749 0.600 0.337
Complete the rate law for this reaction in the box below.
Use the form k[A]m[B]n , where '1' is understood for m or n and concentrations taken to the zero power do not appear. Don't enter 1 for m or n
Rate= ________________
From these data, the rate constant is _________ M-1s-1.
Answer:
7.47 × 10^-1 M-1 s-1
Explanation:
Using the form k[A]^m[B]^n we arrive at the fact that the rate constant of the reaction can be written in the form;
Rate = k[NO2] [CO] where both m and n =1
We can use data from any of the experiments to establish the rate constant hence;
From experiment 1
[NO2] = 0.374M
[CO] = 0.300 M
R= 8.39 × 10^-2
Hence k =8.39 × 10^-2 / [0.374] [0.300]
k= 7.47 × 10^-1 M-1 s-1
1. The elements in a compound
a. Combine by reacting with each other
b. Join in a specific ratio
c. Can be separated using chemical means
d. All of the above
Answer:
d.All of the above
Explanation:
They can do all of the above
WILL GIVE BRAINLEIST
For this assignment, you will develop a model that shows a roller coaster cart in four different positions on
a track. You will then use this model to discuss the changes in potential, kinetic, and thermal energy of
the cart as it moves along the track.
Answer:
This should help :)
Explanation:
The cart has a lot of potential energy, little kinetic energy, and little thermal energy when it is in position A. The kinetic energy and potential energy both rise as the cart moves towards position B, while the thermal energy rises as thermal energy from the track is transmitted to the cart through friction
What is Kinetic energy ?
Kinetic energy, which may be seen in the movement of an object, particle, or group of particles, is the energy of motion.
The cart has a lot of kinetic energy, little potential energy, and little thermal energy after it reaches position C. The cart has some thermal energy and a high potential energy at point D.
It also has a low kinetic energy. Gravity, momentum, and friction are all connected with potential energy, kinetic energy, and thermal energy, respectively.
Position A is when the potential energy is at its highest, and its kinetic energy is at its peak in position C and at its lowest in position A, whereas thermal energy is at its peak in position B and at its lowest in position A.
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Please help if you can !
Answer:
7630
Explanation:
eAnswer:
Explanation:
Math
How many grams of chloride are there in 256 g of magnesium chloride?
Given :
Mass of given magnesium chloride, m = 256 g.
To Find :
How many grams of chloride are there in 256 g of magnesium chloride.
Solution :
Molecular formula of magnesium chloride is [tex]MgCl_2[/tex].
Molecular formula of [tex]MgCl_2[/tex] is, M = 95.211 g/mol .
Mass of chlorine in 1 mol of [tex]MgCl_2[/tex] is , m = 35.5 × 2 = 71 g.
So, amount of chlorine in 256 gram [tex]MgCl_2[/tex] :
[tex]m =\dfrac{71\times 256}{95.211}\\\\m = 190.90\ g[/tex]
Hence, this is the required solution.
An unknown compound containing tellurium and bromine is analyzed
and it is determined that 28.53% of the compound by mass is
composed of tellurium.
How many moles of Te are present in 100.00 g of the compound?
Answer:
The correct answer is 0.22 mol Te.
Explanation:
First, we have to calculate the mass of Te in the sample. We simply multiply the sample mass by the percentage of Te (28.53%= 28.53/100)
100.00 g x 28.53/100 = 28.53 g Te
The molar mass of Te is 127.60 g. Thus, the mass of 1 mol of Te is 127.60 g. With this, we calculate how many moles of Te there are in 28.53 g of Te:
28.53 g Te x 1 mol Te/127.60 g Te= 0.223 mol ≅ 0.22 mol
Sort each of the following elements by effective nuclear charge, Zeff, from smallest to largest:
Sn, Rb, Sb, In, and Sr
Answer:
Rb = +1 , Sr = +2, In= +3, Sn = +4, Sb= +5
Explanation:
Formula:
Zeff = Z - S
Z = atomic number
S = number of core shell or inner shell electrons
For Sn:
Electronic configuration:
Sn₅₀ = [Kr] 4d¹⁰ 5s² 5p²
Zeff = Z - S
Zeff = 50 - 46
Zeff = +4
For Rb:
Electronic configuration:
Rb₃₇ = [Kr] 5s¹
Zeff = Z - S
Zeff = 37 - 36
Zeff = +1
For Sb:
Electronic configuration:
Sb₅₁ = [Kr] 4d¹⁰ 5s² 5p³
Zeff = Z - S
Zeff = 51 - 46
Zeff = +5
For In:
Electronic configuration:
In₄₉ = [Kr] 4d¹⁰ 5s² 5p¹
Zeff = Z - S
Zeff = 49 - 46
Zeff = +3
For Sr:
Electronic configuration:
Sr₃₈= [Kr] 5s²
Zeff = Z - S
Zeff = 38 - 36
Zeff = +2
PLEASE HELP ASAP! WILL MARK YOU AS BRAINLIEST!!!
Answer:
what are the options?
Explanation:
Is a venus fly trap non-living?
Which scientist proposed the idea of the 'nucleus' after the unexpected results of his students’ gold foil experiment?
Group of answer choices
Democritus
Dalton
Bohr
Rutherford
Answer:
D
Explanation:
The nucleus was postulated as small and dense to account for the scattering of alpha particles from thin gold foil, as observed in a series of experiments performed by undergraduate Ernest Marsden under the direction of Rutherford and German physicist Hans Geiger in 1909.
Find the volume of an object with a density of 12.8 g/mL and a mass
of 123 g
Answer:
The answer is 9.60 mLExplanation:
The volume of a substance when given the density and mass can be found by using the formula
[tex]volume = \frac{mass}{density} \\[/tex]
From the question
mass = 123 g
density = 12.8 g/mL
We have
[tex]volume = \frac{123}{12.8} \\ = 9.609375...[/tex]
We have the final answer as
9.60 mLHope this helps you
Which science is the study of living organisms? physics astronomy chemistry biology
Answer:
biology
Explanation:
biology is the study of living g things
Answer:
The answer you would be looking for is Biology
Unit for mass, volume and density
Answer:
kg, m^3, kg/m^3
Explanation:
the SI units for these are:
mass: kilogram
volume: cubic meter
density: kilogram per cubic meter
How many atoms are in 3.2 pg of Ca? The molar mass of Ca is 40.08
g/mol.
Answer:
4.81×10¹⁰ atoms.
Explanation:
We'll begin by converting 3.2 pg to Ca to grams (g). This can be obtained as follow:
1 pg = 1×10¯¹² g
Therefore,
3.2 pg = 3.2 pg × 1×10¯¹² g / 1 pg
3.2 pg = 3.2×10¯¹² g
Therefore, 3.2 pg is equivalent to 3.2×10¯¹² g
Next, we shall determine the number of mole in 3.2×10¯¹² g of Ca. This can be obtained as follow:
Mass of Ca = 3.2×10¯¹² g
Molar mass of Ca = 40.08 g/mol
Mole of ca=.?
Mole = mass /molar mass
Mole of Ca = 3.2×10¯¹² / 40.08
Mole of Ca = 7.98×10¯¹⁴ mole.
Finally, we shall determine the number of atoms present in 7.98×10¯¹⁴ mole of Ca. This can be obtained as illustrated below:
From Avogadro's hypothesis,
1 mole of Ca contains 6.02×10²³ atoms.
Therefore, 7.98×10¯¹⁴ mole of Ca will contain = 7.98×10¯¹⁴ × 6.02×10²³ = 4.81×10¹⁰ atoms.
Therefore, 3.2 pg of Ca contains 4.81×10¹⁰ atoms.
What do organs combine to form? organ systems cells tissues organisms
Answer:
the answer is {organisms}
Answer:
organisms
Explanation: I took the test
Calculate the number of moles in 144 g of P.
Solving the Sequence of an Oligopeptide From Sequence Analysis Data Analysis of the blood of a catatonic football fan revealed large concentrations of a psychotoxic octapeptide. Amino acid analysis of this octapeptide gave the following results: 2 Ala 1 Arg 1 Asp 1 Met 2 Tyr 1 Val 1 NH4 1 The following facts were observed: a. Partial acid hydrolysis of the octapeptide yielded a dipeptide of the structure C O C N H H COOH H3C CH3 CH3 C CH H3 N b. Chymotrypsin treatment of the octapeptide yielded two tetrapeptides, each containing an alanine residue. c. Trypsin treatment of one of the tetrapeptides yielded two dipeptides. d. Cyanogen bromide treatment of another sample of the same tetrapeptide yielded a tripeptide and free Tyr. e. N-terminal analysis of the other tetrapeptide gave Asn. What is the amino acid sequence of this octapeptide
Answer:
The amino sequence of an octapeptide can be determined by :
i.Amino acids present in the peptide
ii.By the behaviour shown by the treatment of these material with different biological and chemical reactions
As shown ammonium was released from the peptide,which shows that the peptide contains either Asn or Gln.
As there is presence of Asp in the amino acid analysis which indicates that the octapeptide contains Asp.
Acid hydrolysis hydrolyzes the peptide bonds which yields a Ala-Val which is the result of partial acid hydrolysis.
Chymotrypsin is on the C-terminal side of the aromatic amino acids Phe, Tyr, and Trp. The peptide has Tyr which indicates that the two present tetrapeptides after chymotrypsin treatment are fourth and eighth amino acids i-e N--Tyr-C and Tyr as the fourth amino acid and Ala-Val somewhere in the octapeptide
As Arg is only present on the C terminal side of the Trypsin cleavage therefore Arg must be the second or the sixth amino acid for the two dipeptides to form as a result of arginine treatment of a tetrapeptide
Cyanogen bromide cleaves on the C-terminal side of Met residues. For free Tyr to be produced from cyanogen bromide treatment of one of the tetrapeptides, Met must be either the third or seventh amino acid. Because Ala was present in both tetrapeptides, Ala must be either the first or fifth amino acid, present in the same tetrapeptide as Arg and Met,i-e N.-Tyr-C and Ala-Val somewhere in the octapeptide and Ala-Arg-Met as the first, second, and third or fifth, sixth, and seventh amino acids and Tyr as the fourth amino acid.
One of the tetrapeptides contains Ala-Val as its second and third amino acids and Asn as its N-terminal amino acid. Therefore two combinations are possible as below
N-Asn-Ala-Val-Tyr-Ala-Arg-Met-Tyr-C or N-Ala-Arg-Met-Tyr-Asn-Ala-Val-Tyr-C
Answer:
The amino aciid sequence of an octapeptide can be determined from the amino acids that are present in the peptide and from the results of different chemical and biological treatments.
One equivalent of ammonium was released fro the peptide, indicating that the peptide contains either Asn or Gln. The presence os Asp in the amino analysis indicates that the octapeptide contains Asn.
A) Acid hydrolysis hydrolyzes peptide bonds. The dipeptide Ala-Val is obtained by partial acid hydrolysis. The indicates that Ala-Val is present in the peptide
B) Chymotrypsin cleaves on the C-terminal side of the aromatic amino acids. Phe, Tyr, and Trp. The peptide contains only Tyr. The presence of tetrapeptides after the treatment of ohymotrypsin indicates that Tyr is the fourth and eighth amino acids.
N-Tyr-C and Tyr present as the fourth amino acid. in constrast, Ala-Val is present in the octapeptide
C) Trpsin cleaves on the C-terminal side of Arg and Lys residues. only Arg is present in the octapeptide. Arg must be the second or sixth amino acid, for two dipeptide to be formed from arginine during the treatment of one tetrapeptide.
D) Cyanogen bromide cleaves on the C-terminal side of Met residues. For free Tyr to be produced from cynogen bromide treatment of one of the tetrapeptides, Met must be either the third or seventh amino acid. Because Ala is present in both tetrapeptides, Ala must be either the first or fifth amino acid, present in the same tetrapeptide as Arg and Met.
In addition, presence of N-...-Tyr-C and Ala-Val in the octapeptide and Ala-Arg-Met as the first, second, third or fifth, sixth or seventh amino acids and Tyr as the fourth amino acid.
E) One of the tetrapides contains Asn as its N-terminal amino acid, and Ala-Val as its second and third amino acids. Two octapeptides are possible from this peptide analysis.
The amino acid sequence of the octapeptide is the following:
N-Asn-Ala-Val-Tyr-Ala-Arg-Met-Tyr-C:
N-Ala-Arg-Met-Tyr-Asn-Ala-Val-Tyr-C:
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Which of the following elements would be expected to have the highest electronegativity?
1. As
2. Li
3. P
4. Al
5. Ge
Answer:
option (3) P is the correct answer.
Explanation:
electronegativity of As is 2.0
electronegativity of Li is 1.0
Electronegativity of P is 2.1
Electronegativity of Al is 1.5
electronegativity of Ge is 1.6
So P (phosphorus) would be expected to have highest electronegativity.
Electronegativity measures the Capability of an atom to pull the shared paired of electrons.
Electronegativity is determined by the following factors
nuclear charge.
the number and the location of different electrons inside the atomic shells.
Ionic crystals have high boiling points because:
A. They do not have high boiling points.
B. breaking ionic bonds requires a large amount of energy.
C. the structure has a large surface area to absorb heat quickly.
D. the positive and negative charges prevent them from absorbing heat quickly.
The answer would be B.
whats the meaning
Speed ?
and the
meaning of
of Motion?
Which of the following describes a nonmetal
A:brittle shiny and solid at room temperature
B:brittle dull and low density
C:malleable shiny and able to conduct electricity
D:malleable dull and solid liquid or gas at room temperature
Answer:
b is the answer
Explanation:
non metals are not shiny, brittle, unmalleable, and are poor conductors of thermal energy and electrical current.
A nonmetal is brittle, dull, and low in density.
• Non-metals refer to the elements that produce negative ions by gaining or accepting electrons. The non-metals generally possess 4, 5, 6, or 7 electrons in their valence shell. The non-metals are those, which are devoid of all the metallic properties.
• The non-metals in their solids-state are brittle, thus, they lack ductility and malleability exhibited by the metals.
• The non-metals are not shiny like metals, they are dull in color.
• The non-metals seem to possess low density, primarily as non-metals seem to prevail either in a liquid or solid-state. The non-metals lack the dense and closed packing in the lattice, which is seen in metals.
Thus, non-metals are brittle, dull, and low in density.
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