On a coordinate plane, a right triangle has points A (negative 5, negative 6), B (negative 5, negative 2), C (negative 2, negative 2).
Examine the right triangle ABC. Which rise and run would create a similar right triangle on the same line?
a rise of 6 and a run of 8
a rise of 8 and a run of 6
a rise of 6 and a run of 5
a rise of 5 and a run of 6

Answer:

For every 92 cats in the city pound, there are 144 dogs.

OR

For every 144 dogs in the city pound, there are 92 cats

Step-by-step explanation:

You didn't provide the options, so that was my best shot at it.

Answer:

[tex]222cm^{2}[/tex]

Step-by-step explanation:

First we will find the length of BD.

By Pythagoras' Theorem,

[tex]c^{2} =a^{2} +b^{2} \\BD^{2} = AD^{2} +AB^{2} \\BD^{2} =12^{2} +16^{2} \\BD^{2} = 144+256\\BD^{2} =400\\BD = \sqrt{400} \\=20cm[/tex]

Now we will find Angle ADB.

[tex]\frac{AB}{sin(Angle ADB)} =\frac{BD}{Sin(AngleBAD)} \\\frac{16}{sin(AngleADB)} =\frac{20}{sin(90)} \\20sin(AngleADB)=16sin(90)\\20sin(AngleADB)=16\\sin(AngleADB)=\frac{16}{20} \\sin(AngleADB)=0.8\\AngleADB=sin^-1(0.8)\\=53.130deg\\[/tex]

Now we will find Area of triangle BCD

[tex]Angle BDC = 90 - Angle ADB = 90 - 53.130 = 36.87deg\\\\\\Area of Triangle BCD \\= \frac{1}{2} (BD)(CD)sin(AngleBDC)\\=\frac{1}{2} (20)(21)sin(36.87)\\= 126cm^{2}[/tex]

Then we will find the area of triangle BAD

[tex]=\frac{1}{2} (16)(12)\\= 96cm^{2} \\[/tex]

Area of quadrilateral = Area of Triangle BCD + Area of Triangle BAD

= 126+96

= [tex]222cm^{2}[/tex]

Answer:

Step-by-step explanation:

it is a trapezoid

so

A = ½ (a + b) h

A = ½ (16 + 21) × 12

A = ½ 37 × 12

A = ½ 444

A = 222 cm²

Answer:

x= 2/3, -2/3

Step-by-step explanation:

9x² = 4

To solve this quadratic, divide each side by 9

x^2 = 4/9

Take the square root of each side

sqrt(x^2) = sqrt(4/9)

x = ±2/3

Answer:

x = ± [tex]\frac{2}{3}[/tex]

Step-by-step explanation:

9x² = 4 ( divide both sides by 9 )

x² = [tex]\frac{4}{9}[/tex] ( take square root of both sides )

x = ± [tex]\sqrt{\frac{4}{9} }[/tex] = ± [tex]\frac{\sqrt{4} }{\sqrt{9} }[/tex] = ± [tex]\frac{2}{3}[/tex]

x = - [tex]\frac{2}{3}[/tex] , x = [tex]\frac{2}{3}[/tex]

Answer: [tex]\frac{1}{2} \frac{2}{17} \frac{7}{12}[/tex]

Step-by-step explanation:

The solution to a given word problem by writing it as an equation is k = 253/232

The process of expressing word problems in mathematical forms takes a logical and chronological approach while taking the variables and arithmetic operations given into consideration.

From the given information, to express the word problem in mathematical form, we have:

Making k the subject of the equation, we have:

k = 253/232

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Answer:

[tex]5^{\circ}[/tex]

Step-by-step explanation:

[tex]~~~~~~~\tan \theta = \cot 85^{\circ}\\\\\implies \tan \theta = \tan\left(90^{\circ} - 85^{\circ} \right)\\\\\implies \tan \theta = \tan 5^{\circ}\\\\\implies \theta = 5^{\circ}[/tex]

x=  10, NL= 8 , NP = 12

A secant is a line that intersects a curve at a minimum of two distinct points.

Using secant theorem,

NL* NM = NP* NO

(3+5)*3 = (2+x)*2

24=  (2+x)*2

12= 2+x

x= 12-2

x= 10

So, NP= 2+x

     NP = 12

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The given expression is [tex]\frac{-4}{5} \times \frac{3}{7} \times \frac{15}{16} \times (\frac{-14}{9})[/tex].

We need to simplify the given expression.

In mathematics, a rational number is a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.

Now group the rational numbers [tex](\frac{-4}{5}\times \frac{15}{16} ) \times (\frac{3}{7}\times (\frac{-14}{9}))[/tex]

[tex]=(\frac{-4}{16}\times \frac{15}{5} ) \times (\frac{3}{9}\times (\frac{-14}{7}))[/tex]

[tex]=(\frac{-1}{4}\times \frac{3}{1} ) \times (\frac{1}{3}\times (\frac{-2}{1}))[/tex]

[tex]=(\frac{-3}{4} ) \times (\frac{-2}{3})=\frac{1}{2}[/tex]

Therefore, the simplified value of the given expression is [tex]\frac{1}{2}[/tex].

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Answer:

65.4

Step-by-step explanation:

5 × 6 = 30 square meter

30 × 2.18 = 65.4

Answer:

f(x) = (x/8)^2       for x ≥ 0

Step-by-step explanation:

y = 8 sqrt x      switch   x and y

x = 8 sqrt y       now solve for y

(x/8)^2 = y

The approximate distance in km between her house and her job is 9 km.

The map is a scale drawing of the places mentioned. A scale drawing is a smaller image of a larger place or diagram.

The scale of the map = 8cm : 12km

Distance between the house and the job = (12 x 6) / 8 = 9m

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Answer:

D. 240

Step-by-step explanation:

6 types of backpacks = 6

4 types of binders = 4

5 types of pencils = 5

2 types of notebook paper= 2

6×4×5×2=

24×10=

240

The number of possible outcomes will be 240. The correct option is D.

Expression in maths is defined as the relation of numbers variables and functions by using mathematical signs like addition, subtraction, multiplication and division.

Given that there are 6 types of backpacks, 4 types of binders, 5 types of pencils, and 2 types of notebook paper.

6 types of backpacks = 6

4 types of binders = 4

5 types of pencils = 5

2 types of notebook paper= 2

The number of possible outcomes will be calculated as:-

N = 6×4×5×2

N = 24×10

N = 240

Therefore, there will be 240 possible outcomes. The correct answer is D.

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Step-by-step explanation:

hope you can understand

Answer:

the algebraic expression is; x+15

Answer:

1

Step-by-step explanation:

(2-0) / (6-4)

2/2

xxxxxxxx

Answer:

1

Step-by-step explanation:

Answer:

x=5

\

Step-by-step explanation:

Answer:

x = 0

Step-by-step explanation:

Line segment UV and line segment VW together form line segment UW.

UV + VW = UW

(5 + x) + (6) = (2x + 11)

5 + x + 6 = 2x + 11

x + 11 = 2x + 11

x + 11 - 11 = 2x + 11 - 11

x = 2x

x - x = 2x - x

0 = x

You can also verify the result by substituting x with our result 0.

5 + x + 6 = 2x + 11

5 + (0) + 6 = 2(0) + 11

11 + 0 = 0 + 11

11 = 11

Left side of the equation is the same as the right side of the equation, therefore the result x = 0 is correct.

Answer:

19-73 19-73 and a very nice little

Step-by-step explanation:

19-73 19-73 and he changed

Answer:

k = g + a

Step-by-step explanation:

g = k - a ( add a to both sides )

g + a = k , that is

k = g + a

A mixed number in simplest form, in the box is 40  5/8 cm^3.

We have given that,

The figure contains a right rectangular prism. The length of the prism is labeled 6 and one-half centimeters, the width is labeled 2 and one-half centimeters, and the height is labeled 2 and one-half centimeters.

The figure is a rectangular prism, so the formula would be Volume = length x width x height.

length = 6 .5cm

width  =  2.5cm

height  =  2.5cm

If you plug everything you have in the problem into the volume equation, you would get

volume = 6.5cm x 2.5cm x 2.5 cm.

Without a calculator first, turn the mixed numbers into improper fractions.

6 .5=13/2

2.5 = 5/2

Volume = 13/2  x 5/2   x 5/2

When you multiply everything together you should get.

As a mixed number, that would be 40 5/8.

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If [tex]f(x)[/tex] has a removable discontinuity at [tex]x=a[/tex], then the limit

[tex]\displaystyle \lim_{x\to a} \frac{f(x)}{x-a}[/tex]

exists and is finite.

A non-removable discontinuity at [tex]x=b[/tex] would entail a non-finite limit,

[tex]\displaystyle \lim_{x\to b} \frac{f(x)}{x-b} = \pm\infty[/tex]

or the limit does not exist (which could be due to the limits from either side of [tex]x=b[/tex] not matching or existing).

For a rational function, we want

[tex]f(x) = \dfrac{p(x)}{q(x)}[/tex]

where [tex]p[/tex] and [tex]q[/tex] are polynomials in [tex]x[/tex]. To get a removable discontinuity at [tex]x=a[/tex], both [tex]p[/tex] and [tex]q[/tex] must be divisible by [tex]x-a[/tex], and the limit of their quotient after removing these factors still exists. That is,

[tex]\displaystyle \lim_{x\to a} f(x) = \lim_{x\to a} \frac{p(x)}{q(x)} = \lim_{x\to a}  \frac{(x-a)p^*(x)}{(x-a)q^*(x)} = \lim_{x\to a} \frac{p^*(x)}{q^*(x)} = \frac{p^*(a)}{q^*(a)}[/tex]

On the flip side, we get a non-removable discontinuity [tex]x=b[/tex] if [tex]p[/tex] is not divisible by [tex]x-b[/tex], in which case

[tex]\displaystyle \lim_{x\to b} f(x) = \lim_{x\to b} \frac{p(x)}{q(x)} = \lim_{x\to b}  \frac{p(x)}{(x-b)q^*(x)} = \frac{p(b)}{0\times q^*(b)}[/tex]

and this is undefined.

Suppose [tex]f(x)[/tex] has a non-removable discontinuity at [tex]x=-5[/tex] and a removable one at [tex]x=4[/tex]. Then one such function could be

[tex]f(x) = \dfrac{x-4}{(x-4)(x+5)} = \dfrac{x-4}{x^2+x-20}[/tex]

4x² + 6x = 12

We move all the terms to the left:

The value of Δ is greater than zero, so the equation has two solutions

We use the following formulas to compute our solutions:

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{x_{1}=\dfrac{-b-\sqrt{\Delta} }{2a }| \ x_{2}=\dfrac{-b+\sqrt{\Delta} }{2a } } \end{gathered}$}[/tex]

The end solution:

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57} } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{x_{1}=\dfrac{-b-\sqrt{\Delta} }{2a}=\dfrac{-(6)-2\sqrt{57} }{2*4}=\dfrac{-6-2\sqrt{57} }{8} } \end{gathered}$}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{x_{1}=\dfrac{-b+\sqrt{\Delta} }{2a}=\dfrac{-(6)+2\sqrt{57} }{2*4}=\dfrac{-6+2\sqrt{57} }{8} } \end{gathered}$}[/tex]

Answer:

  (a)  18%

Step-by-step explanation:

The debt to credit ratio is found by dividing his debt by his credit limit.

__

  ratio = debt/credit limit = $1551.42/$8619.00 ≈ 0.18 = 18%

Quentin's debt to credit ratio is 18%.

Based on the table, a possible taxable income for a taxpayer that's filing with the Single filing status in the 33% federal income tax bracket is $300,000.

Taxation is the involuntary fees that are levied on individuals or business firms by the government of a particular country, so as to generate revenues that can be used to fund public projects, institutions and activities.

In this scenario, we can infer and logically deduce that a possible taxable income for a taxpayer that is filing with the Single filing status in the 33% federal income tax bracket is $300,000.

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Answer:

This mapping isn't a function.

Step-by-step explanation:

A mapping specifies a relation between two sets of items (input and output). For example, a mapping of the form [tex]\lbrace (x_{0},\, y_{0}),\, (x_{1},\, y_{1})\rbrace[/tex] would map the input [tex]x_{0}[/tex] to output [tex]y_{0}[/tex] and map the input [tex]x_{1}[/tex] to output [tex]y_{1}[/tex].

A function is a mapping where each input is associated with exactly one output.

Note that both [tex](2,\, 1)[/tex] and [tex](2,\, 4)[/tex] are in the mapping given in this question. The input [tex]2[/tex] is mapped to more than one outputs. Thus, this mapping isn't a function.

Answer:

D.) Yes, because it passes the vertical line test.

Step-by-step explanation:

For a function to be a function, there must be one output for every input. IN other words, there must be one "y" value for every "x" value. One can see if a graph passes this test by performing the vertical line test.

In this case, the line on the graph passes the test and represents a function. Again, this is because each "x" value has only one "y" value.

Yes, The graph is function because it passes the vertical line test.

We have to given that,

A graph of function is shown in image.

Since, A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

And, The vertical line test is used to determine if a graph of a relationship is a function or not. if you can draw any vertical line that intersects more than one point on the relationship, then it is not a function.

Hence, By given graph,

it passes the vertical line test.

So, Graph shown is a function.

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An equation is formed of two equal expressions. The correct option is B.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The complete option is:

Which values of a and b make the equation true?

[tex]\dfrac{(2xy)^4}{4xy}=4x^ay^b[/tex]

A)a = 0, b = 0

B)a = 3, b = 3

C)a = 4, b = 4

D)a = 5, b = 5

The given equation can be simplified as shown below,

[tex]\dfrac{(2xy)^4}{4xy}=4x^ay^b\\\\\dfrac{2^4 \times x^4 \times y^4}{4xy}=4x^ay^b\\\\\dfrac{16x^4y^4}{4xy} = 4x^ay^b\\\\4x^{(4-1)}y^{(4-1)} = 4x^ay^b\\\\4x^3y^3 = 4x^ay^b[/tex]

Now, comparing the two sides of the equation, the value of a and b should 3 for the equation to be satisfied.

Hence, the correct option is B.

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Answer:

So none of these would be a perfect square but the closet one to it would be 65

Step-by-step explanation: