The probability that s+d > 3 and sd > 3 is 0.03.
SolutionPlot the inequalities
The region -5 ≤ s,d ≤ 5 is the square shaded in grey.
The region s + d > 3 is the region Q shaded to the right of the straight line.
The region sd > 3 is the region R shaded to the right of the curve d = 3/s.
Find the intersection of the three regions
From the figure, the region satisfying all the above three inequalities is the region to the left of the curve d = 3/s, bounded by the square region, i.e. the region R.
Probability of region R
The required probability is the Geometric probability of the intersection region R. It is calculated as
P(R) = ar(region R) / ar(square region P).
Calculate the areas of the regions
ar(region R) = area of the rectangle to the right in the first quadrant formed by dropping a vertical from point F - area under the curve d = 3/s in the first quadrant
[tex]\[\Rightarrow \;\; \mathrm{ar(\mathbf{R}) =} \int_{3/5}^5\frac{3}{s}ds = 25-3-3\ln\frac{25}{3} = 15.64.\][/tex]
ar(region P) = 25 × 25 = 625.
Calculate P(R)
The probability of the region R, P(R) = 15.64 / 625 = 0.025.
Rounding it to the hundredth place of decimal, P(R) = 0.03.
The probability that s+d >3 and sd>3, where -5 < s,d < 5, is 0.03.
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Disclaimer: The question was incomplete. Please find the full content below.
What is the probability that s + d > 3 and sd > 3, where -5 ≤ s,d ≤5? Write your answer as a decimal rounded to the hundredth place.
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Two buses leave a station at the same time and travel in opposite directions. One bus travels 14 miles faster than the other. If the two buses are 640 miles apart after 5 hours, what is the rate of each bus?
If the two buses are 640 miles apart after 5 hours. Then the rate of each bus will be 57 miles per hour and 71 miles per hour.
What is speed?The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.
We know that the speed formula
Speed = Distance/Time
Two buses leave a station at the same time and travel in opposite directions.
One bus travels 14 miles faster than the other.
Let x be the speed of first bus. Then the speed of the second bus will be (x + 14).
If the two buses are 640 miles apart after 5 hours.
Then the rate of each bus will be
Then the relative speed of the buses will be
S = x + x + 14
S = 2x + 14
Then the value of x will be
2x + 14 = 640 / 5
2x + 14 = 128
2x = 114
x = 57 miles per hour
Then the speed of the other bus will be
⇒ 57 + 14
⇒ 71 miles per hour
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Given: a || b, transversal k
Prove <3 = <6
By the property of corresponding angles ∠3 ≅ ∠5.
What is transversal line?In geometry, a transversal is any line that intersects two straight lines at distinct points.
If two parallel lines are cut by a transversal, then each pair of corresponding angles are equals.
That is, ∠3 = ∠5 and ∠4 = ∠6.
Therefore the given angles ∠3 and ∠5 are equal.
Hence ∠3 ≅ ∠5 .
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At the end of 2 years, P dollars invested at an interest rate r compounded annually increases to an amount, A dollars, given by the following formula. Upper A equals Upper P (1 plus r )squared Find the interest rate if $32 increased to $50 in 2 years. Write your answer as a percent.
The interest rate will be equal to 24% in 2 years.
What is compound interest?Compound interest is the interest levied on the interest. The formula for the calculation of compound interest is given as:-
Given that:-
Find the interest rate if $32 increased to $50 in 2 years.The interest rate will be calculated by using the following formula:-
[tex]A = P[1+\dfrac{r}{n}]^{nt}[/tex]
[tex]50=32[1+\dfrac{r}{1}]^{2}[/tex]
[tex]\dfrac{50}{32}=(1+r)^2[/tex]
1.56 = ( 1 + r )²
√1.56 = ( 1 + r )
r = 1.24 - 1
r = 0.24
r = 24%
Therefore interest rate will be equal to 24% in 2 years.
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What is the partial fraction decomposition of StartFraction 7 x squared + 14 Over (x squared + 3) squared EndFraction?
The final decomposition of the given partial fraction is; 7 + (-7/(x² + 3))
How to decompose partial fractions?We are given the polynomial fraction (7x² + 14)/(x² + 3) to decompose.
Now, due to the fact that the degree of the numerator is not less than the degree of the denominator, we will perform polynomial long division to get;
(7x² + 14)/(x² + 3) = 7 + (-7/(x² + 3))
Now, the second term (-7/(x² + 3)) cannot be decomposed further and as such, we say that our final decomposition of the given partial fraction is;
7 + (-7/(x² + 3))
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Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials and the probability of obtaining a success. Round your answer to four decimal places.
P ( X > 2 ) , n = 5 , p = 0.7
The value of the probability P(x > 2) is 0.8369
How to evaluate the probability?The given parameters are:
n = 5
p =0.7
The probability is calculated as:
[tex]P(x) = ^nC_x *p^x * (1 - p)^x[/tex]
Using the complement rule, we have:
P(x > 2) = 1 - P(0) - P(1) - P(2)
Where:
[tex]P(0) = ^5C_0 *0.7^0 * (1 - 0.7)^5[/tex]
P(0) = 1 *1 * (1 - 0.7)^5 = 0.00243
[tex]P(1) = ^5C_1 *0.7^1 * (1 - 0.7)^4[/tex]
P(1) = 5 *0.7^1 * (1 - 0.7)^4 = 0.02835
[tex]P(2) = ^5C_2 *0.7^2 * (1 - 0.7)^3[/tex]
P(2) = 10 *0.7^2 * (1 - 0.7)^3 = 0.1323
Recall that:
P(x > 2) = 1 - P(0) - P(1) - P(2)
So, we have:
P(x > 2) = 1 - 0.00243 - 0.02835 - 0.1323
Evaluate
P(x > 2) = 0.83692
Approximate
P(x > 2) = 0.8369
Hence, the value of the probability P(x > 2) is 0.8369
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Graph the line passing through (6, 1) whose slope is m = 3.
Answer: [tex]y=3x-17[/tex]
Step-by-step explanation:
use point-slope form:
[tex]y_{1} -y=m(x_{1} -x)[/tex]
[tex]y-1=3(x-6)[/tex]
[tex]y-1=3x-18[/tex]
[tex]y=3x-17[/tex]
Answer:
equation: y = 3x - 17
[image attached]
Step-by-step explanation:
we know that the equation for a line is y = mx + b
we are given a point, (6, 1)
remember that a point is (x, y)
we can plug these sample x and y values into our equation, replacing x and y
y = mx + b
1 = m6 + b
we know that m = 3 [this was a given], so we can plug this into our equation
1 = (3)(6) + b
1 = (18) + b
1 = 18 + b [we can now solve for "b"]
1 = 18 + b
-18 - 18
-17 = b
so, we can re-write our equation so that we can graph it:
y = 3x - 17
we can now plug in x-values to graph this:
(you'll see these written in the table on the graph)
y = 3(0) - 17
y = -17
y= 3(1) - 17
y = 3 - 17
y = -14
y = 3(2) - 17
y = 6 - 17
y = -11
y = 3(3) - 17
y = 9 - 17
y = -8
y = 3(4) - 17
y = 12 - 17
y = -5
y = 3(-1) - 17
y = -3 - 17
y = -20
y = 3(-2) - 17
y = -6 - 17
y = -23
y = 3(-3) - 17
y = -9 - 17
y = -26
[there is an image attached of my graph]
hope this helps!! :)
Mr. Garret has a total of 20 students in his class. The number of female students is 4 less than twice the number of male students. How many female and how many male students does he have?
Answer:
8 male, 12 female
Step-by-step explanation:
male = x
female = 2x - 4
2x - 4 + x = 20
3x - 4 = 20
3x = 24
x = 8
2(8) - 4 = 12
there are 8 male, 12 female
What is the equation of the line of symmetry for the parabola represented by the equation y=−2(x−7)2+11?
Enter your answer as the correct equation, like this: x = 42
Answer:
I think its x = 7
I belive it is
Exponential function f is represented by the table. x -2 -1 0 1 2 f(x) -46 -22 -10 -4 -1 Function g is represented by the equation. Which statement correctly compares the two functions on the interval [-1, 2]? A. Both functions are increasing, but function f increases at a faster average rate. B. Only function f is increasing, but both functions are negative. C. Both functions are increasing, but function g increases at a faster average rate. D. Only function f is increasing, and only function f is negative.
Both functions are increasing, but function g increases at a faster average rate.
The correct option is (C)
What is an increasing function?If the slope of a function is continuously increasing or constant in an interval, the function is known as an increasing function.
let f(x) = [tex]ab^{x} +c[/tex] and x=0 , f(0)= -10
-10=a+c
Now,
f(x) = -33/5*[tex](\frac{1}{11} )^{x}[/tex] - 17/5
f '(x)>0
So, x is increasing function.
g(x) = -18/3*[tex](\frac{1}{11} )^{x}[/tex] +2
g'(x) =-18[tex](\frac{1}{3} )^{x}[/tex]ln(1/3)
ln 1/3<0
So, g'(x)>0
So, g(x) is an increasing function.
For any x ∈ f(x) and x ∈ g(x)
Since, g increases at a faster rate.
Hence, Both functions are increasing, but function g increases at a faster.
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A rectangular fence has a perimeter of 184 feet. The length is four feet less than three times the width. Find the length and the width. = 2+2
Answer:
lenth = 68 [ft]; width=24 [ft].
Step-by-step explanation:
1) if the length is 'l' and the width - 'w', then it is possible
2) to write the condition 'The length is four feet less than three times the width' as 3w-4=l;
3) to write the given perimeter as 2(w+l)=184.
4) then it is possible to make up the system:
[tex]\left \{ {{2(w+l)=184} \atop {3w-4=l}} \right. \ = > \ \left \{ {{w+l=92} \atop {3w-l=4}} \right. \ = > \ \left \{ {{w=24} \atop {l=68}} \right.[/tex]
What is the value of x for the regular polygon shown below?
2x + 4
36
please help me :((((((
Answer:
Answer D
Step-by-step explanation:
It says to divide f(x)/g(x), which is displayed in D and if we find the domain it would be x is not equal to -1/4
let p be the perimeter of a rectangle, and let one side of the rectangle be x
PLEASE SHOW WORK
That is the length in terms of p and x.
L = p/2 - x
How to get the length of the other side in terms of x and p?
For a rectangle of length L and width W, the perimeter is:
P = 2*(L + W).
Here we know that the perimeter is p, so P = p, and let's say that the width is x.
Then we can write:
p = 2*(L + x)
Solving for L:
L = p/2 - x
That is the length in terms of p and x.
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Step 2 of 2 : Suppose a sample of 782 suspected criminals is drawn. Of these people, 548 were not captured. Using the data, construct the 98% confidence interval for the population proportion of people who are captured after appearing on the 10 Most Wanted list.
98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list
(0.6625, 0.7388).
What is confidence interval?A confidence interval is the mean of your estimate plus and minus the variation in that estimate.
Given sample, n= 782
As, 548 were not captured.
x= 548
So, p= 548/ 782
p = 0.7007
q= 1- 0.7007 = 0.2993
98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list
Now,
α = 1 - 0.98 = 0.02
α/2 = 0.02/2 = 0.01
For confidence level of 98% , z is 2.33
Now,
(0.70007 - 2.33√ (0.7007(0.2993))/782 , 0.70007 + 2.33 √(0.7007(0.2993))/782
= (0.6625, 0.7388)
Hence, 98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list
(0.6625, 0.7388).
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Help solve and get 20 pts! (Math)
Which of the following staements must be true about this diagram check all that apply
Answer:Since, according to the Exterior Angle theorem, In a triangle the sum of any two adjacent interior angles is equal to the exterior angle of the triangle.
And, here is the exterior angle of the triangle, while , , and are the interior angles of the triangle.
Thus, according to the theorem,
.
⇒
and
Therefore, options B, C, E are correct.
Prove that < AOD and < BOD are supplementary
Angle AOD and < BOD are supplementary since they are both right angles which equal 180°.
What is a supplementary angle?It should be noted that a supplementary angle simply means an angle that adds up to 180°.
In this case, the angles given are both rights angles. This will be:
= 90° + 90°
= 180°
In this case, Angle AOD and < BOD are supplementary since they are both rights angles which equal 180°.
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Lydia writes the equation below with a missing value.
y = 5 x minus box
She puts a value in the box and says that the equation represents a direct variation. Which explains whether the equation could represent a direct variation?
If she puts 0 in the box she would have a direct variation.
If she puts 5 in the box she would have a direct variation.
The equation is not of the form y = k x, so it cannot represent a direct variation.
The equation has a minus sign, so it cannot represent a direct variation.
If she puts 0 in the box she would have a direct variation.
Lydia writes the equation y = 5x - __ with a missing value.
She puts a value in the box and says that the equation represents a direct variation.
We have to choose the correct option from the given options that explain that the equation could represent a direct variation.
When two variables are such that one is a constant multiple of the other, we said they are in Direct variation.
What is the direct variation?
In form of y = ax, where y and x are in direct variation.
Consider the given equation y = 5x - __
For the equation to be in direct variation the value of the missing term has to be 0.
then the equation becomes,
y = 5x
Thus, If she puts 0 in the box she would have a direct variation.
Option (a) is correct.
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Answer:
a
Step-by-step explanation:
You are given that cos(A)=−35, with A in Quadrant II, and cos(B)=817, with B in Quadrant I. Find cos(A−B). Give your answer as a fraction.
Expand cos(A - B) with the identity
cos(A - B) = cos(A) cos(B) + sin(A) sin(B)
A is in quadrant II, so sin(A) > 0, and B is in quadrant I, so sin(B) > 0. Using the Pythagorean identity, we get
cos²(A) + sin²(A) = 1 ⇒ sin(A) = + √(1 - (-3/5)²) = 4/5
cos²(B) + sin²(B) = 1 ⇒ sin(A) = + √(1 - (8/17)²) = 15/17
Then
cos(A - B) = (-3/5) × 8/17 + 4/5 × 15/17 = 36/85
cos (A - B) is 36/85
How to simply the identity
Expand cos(A - B) with the identity
You get, cos(A - B) = cos(A) cos(B) + sin(A) sin(B)
Since A is in quadrant II, so sin(A) > 0,
B is in quadrant I, so sin(B) > 0.
Using the Pythagorean identity, we get
cos²(A) + sin²(A) = 1
Make sin A the subject of formula
[tex]sin(A)^{2}[/tex] = ([tex]\sqrt{(1 - (-3/5}[/tex])²)
Find the square root of both sides, square root cancels square
[tex]sin A[/tex] = 4/5
Repeat the same for the second value
[tex]sin A^{2} = \sqrt{(1- 8/17)^2}[/tex]
[tex]sin A[/tex] = 15/17
Substitute values into cos(A - B)
cos(A - B) = cos(A) cos(B) + sin(A) sin(B) = (-3/5) * 8/17 + 4/5 * 15/17
cos (A - B) = 36/85
Therefore, cos (A - B) is 36/85
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An auto mechanic charges (C) an initial fee of $50 and then $40 per hour. The graph of this model would be:
a curved line that increases but then decreases.
a straight line that decreases only.
a straight line that increases only.
None of these choices are correct.
The graph of this model would be a straight line that increases only option third is correct.
What is a line graph?A line graph is a graph made up of segments of straight lines that connect the depicted data points.
We have:
An auto mechanic charges (C) an initial fee of $50 and then $40 per hour.
Let T be the total fee and h is the number of hours
T = 50 + 40h
The above equation represents a graph of a straight line as the slope of the line is positive.
m = 50
Thus, the graph of this model would be a straight line that increases only option third is correct.
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Find the slope of a line perpendicular to a line through the given points. E(5, 7), F(3, 1)
Answer: -1/3
Step-by-step explanation:
The slope of the given line is [tex]\frac{7-1}{5-3}=\frac{6}{2}=3[/tex].
Thus, since perpendicular lines have slopes that are negative reciprocals of each other, the answer is -1/3
Which of the following is NOT a rational expression?
The expression that is not rational is the first one:
[tex]f(x) = \frac{6x}{4}[/tex]
Which of the given expressions is not rational?A rational expression is something of the form:
[tex]f(x) = \frac{q(x)}{p(x)}[/tex]
Such that q(x) can be any polynomial, and p(x) is a polynomial of at least degree 1.
This means that we need to have the variable "x" on the denominator.
Then is easy to recognize the expression that is not rational, is the one that does not have x on the denominator, which is the first one:
[tex]f(x) = \frac{6x}{4}[/tex]
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Answer: B
Step-by-step explanation:
I took the test and this was the correct answer
Which statements about the system are true? Select two options.
y=-x-4
3y - x = -7
O The system has one solution.
O The system consists of parallel lines.
O Both lines have the same slope.
Both lines have the same y-intercept.
The equations represent the same line.
The system of equation has one solution
How to determine the true statements?The equations are given as:
y = -x - 4
3y -x = -7
Rewrite the first equation as:
y + x = -4
Add y + x = -4 to the second equation to eliminate x
4y = -11
Divide by 4
y = -11/4
Substitute y = -11/4 in y + x = -4
-11/4 + x = -4
Make x the subject
x = -4 + 11/4
Evaluate
x = -5/4
The above means that the system of equation has one solution
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Option A and B. The system has one solution and the system consists of parallel lines.
Slope of the linesThe slope of the lines is calculated as follows;
y = -x - 4
slope = - 1
3y - x = -7
3y = x - 7
y = x/3 - 7/3
slope = 1/3
Solution of the equationsy = -x - 4 ----(1)
3y - x = -7 ----(2)
solve (1) and (2)
3(-x - 4) - x = -7
-3x -12 - x = -7
-4x = 5
x = -5/4
y = -5/4 - 4
y = -5.25
Thus, the system has one solution and the system consists of parallel lines.
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Find two functions defined
implicity by this equation:
(x − 5)² − 3(y + 2)² = 4
Answer:
[tex] \frac{dy}{dy} = \frac{x - 5}{3y + 6} [/tex]
What are the values for y when x is 2, 4, and 6?
y = 20x + 7
Design a real life activity for the Intermediate Phase in which learners will be required to apply the associative property of multiplication over addition.
The associative property of adding or multiplying can be represented by (a + b) + c = a + (b + c) and a * (b * c) = (a * b) * c
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
The associative property states that when adding or multiplying it can be represented by:
(a + b) + c = a + (b + c)
For multiplication:
a * (b * c) = (a * b) * c
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What is the value for y?
What is the value of x?
Enter your answer in the box.
x =
Equiangular triangle A B C. Angles A, B, and C are marked congruent. The length of side A C is labeled as 5 x minus 22. The length of side A B is labeled as 4 x minus 10. The length of side B C is labeled as 3 x plus 2.
Enter your answer in the box.
y =
An isosceles triangle A B C with horizontal base B C and vertex A is above the base. Side A C and C B are labeled with single tick mark. All the three angles are labeled. Base angles C A B is labeled as 50 degrees and angle C B A is labeled as 2x degrees. The angle A C B is labeled left parenthesis 5 y plus 10 right parenthesis degrees.
1. The value of x in the equilateral triangle is: 12
2. x = 25; y = 14
What is an Equilateral Triangle?If a triangle has three sides that are marked congruent, then the triangle is an equilateral triangle.
1. Since triangle ABC is an equilateral triangle and its sides are equal, therefore:
5x - 22 = 3x + 2 [congruent sides]
Solve for x
5x - 3x = 22 + 2
2x = 24
2x/2 = 24/2
x = 12
The value of x is: 12.
2. Base angles of an isosceles triangle are congruent, therefore:
2x = 50
x = 50/2
x = 25
Thus, using the triangle sum theorem, we have:
2x + 50 + 5y + 10 = 180
Plug in the value of x and find y
2(25) + 50 + 5y + 10 = 180
50 + 50 + 5y + 10 = 180
110 + 5y = 180
5y = 180 - 110
5y = 70
y = 70/5
y = 14
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The function f(x) = 40(0.9)x represents the deer population in a forest x years after it was first studied. What was the deer population when it was first studied?
a. 44
b.40
c. 36
d.49
Answer:
36
Step-by-step explanation:
40*.9
The table below shows the results of a screening program organized by Level 300 students of the department physiotherapy of the College Health Sciences of the University of Ghana. Complete the table and answer the questions below it using your understanding of probability and its applications to biomedical data.
True Diagnosis for presence of E. Coli
Test results Disease No Disease Total
Positive 35 15
Negative 10 60
Total
a. What is the efficiency of the test? 3 marks
b. What is the sensitivity of the screening kit? 3 marks
c. What is the specificity of the screening kit? 3 marks
d. What is the predictive value (PPV) of the test? 3 marks
e. What is the negative predictive value (NPV) of the test? 3 marks
(15 marks)
2. In double blinded randomized control trial for hypertensive patients attending Cocoa Clinic, thirty (30) 50-59-year-old were admitted into an intervention program for 6 weeks. During the trial, the average improvement in their systolic blood pressure was 15. The average improvement in systolic blood pressure in the general population of hypertensive patients is 20 with a standard deviation of 2.
i. What are the null and alternative hypotheses in this RCT? (2 marks)
ii. What tail is required in this test? (2 marks)
iii. What is the most appropriate statistical test for this study? (2 marks)
iv. State the assumptions of the test. (2 marks)
v. Test the above hypothesis using the appropriate statistical tool (7 marks)
Critical value =3.6
44. What percent of Mary Brown's year-to-date
gross pay has been withheld for federal tax
purposes?
A. 10%
B 13%
C. 17%
D. 20%
45. For the pay period covered on this
paycheck, what percent of Mary Brown's
gross pay was withheld for all taxes and
voluntary dues?
A 10%
B. 13%
C 17%
D. 20%
Based on the amount of federal taxes withheld till date, the percent of Mary Brown's year-to-date that have been withheld is A. 10%.
The percent of the gross pay that has been withheld for all taxes and voluntary dues is C. 17%.
How much federal taxes have been withheld?= Fed tax till date / YTD Gross
= 662.26 / 6,318.17
= 10%
How much taxes and voluntary dues have been withheld?= (Fed tax + ST Tax + Med tax + Vol Due) / Current gross
= (111.42 + 17.09 + 12.25 + 2.5) / 845.10
= 17%
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