Nam owns a used car lot. He checked the odometers of the cars and recorded how far they had driven. He then created both a histogram and a box plot to display this same data (both diagrams are shown below). Which display can be used to find how many vehicles had driven more than 200{,}000\,\text{km}200,000km200, comma, 000, start text, k, m, end text (kilometers)? Choose 1 answer: Choose 1 answer: (Choice A) A The histogram (Choice B) B The box plot Which display can be used to find that the median distance was approximately 140{,}000\,\text{km}140,000km140, comma, 000, start text, k, m, end text? Choose 1 answer: Choose 1 answer: (Choice A) A The histogram (Choice B) B The box plot

Answer:

5 units

Step-by-step explanation:

make h the subject

Answer:

1. Parameter because the value is a numerical measurement describing a characteristic of a population

Step-by-step explanation:

A parameter is a fixed measure which describes the whole population while a statistic is a characteristic of a sample (which is a portion of the target population).

In a study of all 1963 employees at a college, it is found that "40%" own a computer.

The study involved the entire population of employees in the college, therefore the result describes the computer owning characteristics of the whole population under study. It is therefore a parameter.

The correct option is 1.

Answer:

The answer is the first one on the bottom left.

Step-by-step explanation:

Answer:

(C) 10

Step-by-step explanation:

x+y−z=8

Subtract y from both sides

x-z= -y+8

Add z to both sides

x= -y+z+8

Subtract 8 from both sides

x-8= -y+z

x−y+z=12

Add y to both sides

x+z=12+y

Subtract z from both sides

x=y-z+12

Subtract 12 from both sides

x-12=y-z

Multiply both sides by -1

-x+12= -y+z

Combine equations:

x-8= -x+12

Add x to both sides

2x-8+12

Add 8 to both sides

2x=20

Divide both sides by 2

x=10

The answer is (C) 10.

Answer:

a) We can not estimate the probability.

b) Zero probability.

c) There is a probability between 95% and 99% that they have between 475 and 525 customers on a given day.

Step-by-step explanation:

a) We can not said nothing because we only know the average of customers per day. We need to know the probability distribution of the amount of customers per day to answer this question.

b) Now that we know that the variance is 100, although we do not know the exact distribution of the values, we can use the empirical rules to estimate the probability of having at least 700 customers on a given day.

If the variance is 100, the standard deviation is √100=10.

Applying the empirical rule (68-95-99.7 rule), we know that there is probability 0.15% of having at least 500+3*10=530 customers per day (more than 3 deviations from the mean).

Then, we can conclude that the probability of having at least 700 customers per day is zero.

c) To estimate this probability, we have to calculate how many deviations from the mean this values represent:

[tex]\Delta_1=475-500=-25=2.5\sigma\\\\\Delta_2=525-500=25=2.5\sigma[/tex]

We have an interval that have a width of ±2.5 deviations from the mean.

For 2 deviations from the mean, it is expected to have 95% of the data.

For 3 deviations from the mean, it is expected to have 99.7% of the data.

Then, for the interval 475 to 525, we can estimate a probability between 95% and 99%.

Answer:

320 x^6

Step-by-step explanation:

(5x^3)(4x)^3

5 x^3  * 4^3 * x*3

5x^3 *64x^3

320 x^6

Answer:

B

Step-by-step explanation:

= 5x^3  * 4^3 * x^3

= 5x^3 *64x^3

= 320x^6

Hope this helps!

Answer:

undefined.

Step-by-step explanation:

-2-5/-3-(-3)

-7/0

Undefined

Answer:

D

Step-by-step explanation:

Answer:

Step-by-step explanation:

cos X(tanX+cotX) =cscX​

cos X(sinx/cosx +cosx/sinx) =cscx

cos X (sin²+cos²/cossin)=cscx

cosx(1/cossin)=cscx

cross out cosines

1/sinx=cscx

Answer:

so we have an inequality for y -

7.995<y<8.005

Then now we need in inequality for x

(y-4)/5 = x

so that means that so if we have (7.995-4)/5 we get 3.995/5 = 7.99

so we have our first 7.99<x<b

Now we solve for b

So that means that 5.005/5 = 1.001

since we are changing it we switch our signs

from 7.99<x<1.001

we do 7.99>x>1.001

therefore

1.001<x<7.99

Answer:

0.795 [tex]\leq[/tex] y [tex]\leq[/tex] 0.805

Step-by-step explanation:

8 = 5x + 4

5x = 4

x = 4/5 or 0.800

therefore 0.800 + .005 and 0.800 - .005 =

0.795 [tex]\leq[/tex] y [tex]\leq[/tex] 0.805

Answer:

1/3 simplifed.

Step-by-step explanation:

To find the product of 3/7*7/9. We can multiply top and bottom. Top: 3*7=21 Bottom: 7*9=63. Our final answer is just the Top/Bottom= 21/63. We can also simplify this into 1/3 which is our final answer.

Answer:

Yes, Because every x-value corresponds to exactly one y-value.

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Answer:

Null hypothesis: [tex]\mu_1 \leq \mu_2[/tex]

Alternative hypothesis: [tex]\mu_1 > \mu_2[/tex]

The statistic is given by:

[tex]t= \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}}[/tex]

And replacing we got:

[tex] t=\frac{72.86-67.34}{\sqrt{\frac{15.98^2}{150} +\frac{35.67^2}{275}}}=2.194[/tex]

And the best option would be:

2.19

Step-by-step explanation:

We have the following info given:

n1 = 150 n2 = 275

[tex]\bar x_1 = 72.86, \bar x_2 = 67.34[/tex]

s1 = 15.98 s2 = 35.67

We want to test the following hypothesis:

Null hypothesis: [tex]\mu_1 \leq \mu_2[/tex]

Alternative hypothesis: [tex]\mu_1 > \mu_2[/tex]

The statistic is given by:

[tex]t= \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}}[/tex]

And replacing we got:

[tex] t=\frac{72.86-67.34}{\sqrt{\frac{15.98^2}{150} +\frac{35.67^2}{275}}}=2.194[/tex]

And the best option would be:

2.19

Answer:  The correct answer is:  " 2x² " .

________________________________

Step-by-step explanation:

________________________________

We are asked:  "What is the sum of:  "x + x² + 2" and "x² − 2 − x" ?

Since we are to find the "sum" ;

  →  We are to "add" these 2 (two) expressions together:

     →     (x + x² + 2) +  (x² − 2 − x) ;

Note:  Let us rewrite the above, by adding the number "1" as a coefficient to:  the values "x" ; and "x² " ;  since there is an "implied coefficient of "1" ;

            → {since:  "any value" ; multiplied by "1"; results in that exact same value.}.

            →     (1x + 1x² + 2) +  (1x² − 2 − 1x) ;

Rewrite as:

             →     1x + 1x² + 2) +  (1x² − 2 − 1x) ;

Now, let us add the "coefficient" , "1" ; just before the expression:

             "(1x² − 2 − 1x)" ;  

         {since "any value", multiplied by "1" , equals that same value.}.

And rewrite the expression; as follows:

            →     (1x + 1x² + 2) +  1(1x² − 2 − 1x) ;

Now, let us consider the following part of the expression:

                     →  " +1(1x² − 2 − 1x) " ;

________________________________

Note the distributive property of multiplication:

   →  " a(b+c) = ab + ac " ;

and likewise:

   →  " a(b+c+d) = ab + ac + ad " .

________________________________

So; we have:

→  " +1(1x² − 2 − 1x) " ;

  = (+1 * 1x²)  +  (+1 *-2) + (+1*-1x) ;

  =       + 1x²    +    (-2)     +  (-1x) ;

  =       +1x²    −    2   −  1x  ;

  ↔    ( + 1x²  −  1x  −  2)

Now, bring down the "left-hand side of the expression:

1x + 1x² + 2 ;

and add the rest of the expression:

     →  1x  +  1x²  +  2  +   1x²  −  1x  −  2 ;

________________________________

Now, simplify by combining the "like terms" ; as follows:

   +1x² + 1x² = 2x²  ;

   +1x −  1x = 0 ;  

   + 2 −  2  = 0 ;

________________________________

The answer is: " 2x² " .

________________________________

Hope this is helpful to you!

   Best wishes!

________________________________

Answer:

The correct answer is:  " 2x² " .

________________________________

Step-by-step explanation:

________________________________

We are asked:  "What is the sum of:  "x + x² + 2" and "x² − 2 − x" ?

Since we are to find the "sum" ;

 →  We are to "add" these 2 (two) expressions together:

    →     (x + x² + 2) +  (x² − 2 − x) ;

Note:  Let us rewrite the above, by adding the number "1" as a coefficient to:  the values "x" ; and "x² " ;  since there is an "implied coefficient of "1" ;

           → {since:  "any value" ; multiplied by "1"; results in that exact same value.}.

           →     (1x + 1x² + 2) +  (1x² − 2 − 1x) ;

Rewrite as:

            →     1x + 1x² + 2) +  (1x² − 2 − 1x) ;

Now, let us add the "coefficient" , "1" ; just before the expression:

            "(1x² − 2 − 1x)" ;  

        {since "any value", multiplied by "1" , equals that same value.}.

And rewrite the expression; as follows:

           →     (1x + 1x² + 2) +  1(1x² − 2 − 1x) ;

Now, let us consider the following part of the expression:

                    →  " +1(1x² − 2 − 1x) " ;

________________________________

Note the distributive property of multiplication:

  →  " a(b+c) = ab + ac " ;

and likewise:

  →  " a(b+c+d) = ab + ac + ad " .

________________________________

So; we have:

→  " +1(1x² − 2 − 1x) " ;

 = (+1 * 1x²)  +  (+1 *-2) + (+1*-1x) ;

 =       + 1x²    +    (-2)     +  (-1x) ;

 =       +1x²    −    2   −  1x  ;

 ↔    ( + 1x²  −  1x  −  2)

Now, bring down the "left-hand side of the expression:

1x + 1x² + 2 ;

and add the rest of the expression:

    →  1x  +  1x²  +  2  +   1x²  −  1x  −  2 ;

________________________________

Now, simplify by combining the "like terms" ; as follows:

  +1x² + 1x² = 2x²  ;

  +1x −  1x = 0 ;  

  + 2 −  2  = 0 ;

________________________________

The answer is: " 2x² " .

Step-by-step explanation:

Answer:

2c -2 = Steve's age 2 years ago

Step-by-step explanation:

Answer:

13.53% probability that no customers arrive in a five-minute period

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given time interval.

They arrive at a rate of two every five minutes

This means that [tex]\mu = 2[/tex]

What is the probability that no customers arrive in a five-minute period?

This is P(X = 0).

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353[/tex]

13.53% probability that no customers arrive in a five-minute period

Answer:

For k = 1:

=NEGBINOMDIST(0, 1, 0.666) = 0.6660

For k = 2:

=NEGBINOMDIST(1, 1, 0.666) = 0.2224

For k = 3:

=NEGBINOMDIST(2, 1, 0.666) = 0.0743

For k = 4:

=NEGBINOMDIST(3, 1, 0.666) = 0.0248

For k = 5:

=NEGBINOMDIST(4, 1, 0.666) = 0.0083

For k = 6:

=NEGBINOMDIST(5, 1, 0.666) = 0.0028

Step-by-step explanation:

The probability of obtaining a defective 10-year old widget is 66.6%

p = 66.6% = 0.666

The probability of obtaining a non-defective 10-year old widget is

q = 1 - 0.666 = 0.334

The random variable will be the number of items that must be tested before finding the first defective 10-year old widget.

The geometric distribution is given by

[tex]$P(X = k) = p \times q^{k - 1}$[/tex]

Solving manually:

For k = 1:

[tex]P(X = 1) = 0.666 \times 0.334^{1 - 1} = 0.666 \times 0.334^{0} = 0.666[/tex]

For k = 2:

[tex]P(X = 2) = 0.666 \times 0.334^{2 - 1} = 0.666 \times 0.334^{1} = 0.2224[/tex]

For k = 3:

[tex]P(X = 3) = 0.666 \times 0.334^{3 - 1} = 0.666 \times 0.334^{2} = 0.0743[/tex]

For k = 4:

[tex]P(X = 4) = 0.666 \times 0.334^{4 - 1} = 0.666 \times 0.334^{3} = 0.0248[/tex]

For k = 5:

[tex]P(X = 5) = 0.666 \times 0.334^{5 - 1} = 0.666 \times 0.334^{4} = 0.0083[/tex]

For k = 6:

[tex]P(X = 6) = 0.666 \times 0.334^{6 - 1} = 0.666 \times 0.334^{5} = 0.0028[/tex]

Using Excel function:

NEGBINOMDIST(number_f, number_s, probability_s)

Where

number_f = k - 1 failures

number_s = no. of successes

probability_s = the probability of success

For the geometric distribution, let number_s = 1

For k = 1:

=NEGBINOMDIST(0, 1, 0.666) = 0.6660

For k = 2:

=NEGBINOMDIST(1, 1, 0.666) = 0.2224

For k = 3:

=NEGBINOMDIST(2, 1, 0.666) = 0.0743

For k = 4:

=NEGBINOMDIST(3, 1, 0.666) = 0.0248

For k = 5:

=NEGBINOMDIST(4, 1, 0.666) = 0.0083

For k = 6:

=NEGBINOMDIST(5, 1, 0.666) = 0.0028

As you can notice solving manually and using Excel yields the same results.

Answer:

Step-by-step explanation:

Let x be a random variable representing the number of guesses made for the sat questions.

Since the probability of getting the correct answer to a question is fixed for any number of trials and the outcome is either getting it correctly or not, then it is a binomial distribution. The probability of success, p = 0.2

Probability of failure, q = 1 - p = 1 - 0.2 = 0.8

the probability that the number x of correct answers is fewer than 4 is expressed as

P(x < 4)

From the binomial distribution calculator,

P(x < 4) = 0.97

Answer:

4.50 is for two scoops and a normal cone. Upgrades on cone is $0.50 and any additional toppings are also $0.50

Answer:5 × t = 6

Step-by-step explanation:

Step 1: 4.50 + 0.50 = 5

Step 2: We has 5t is 5 × t

Step 3: 5 × t = 6

Answer:

Step-by-step explanation:

3/4=24 so 1/4= 24÷3= 8

1/4=8

So to get 4/4 or Cameron's age it is 8×4=32yrs

[tex]answer \\ 32 \: years \: old \\ solution \\ mary's \: age = 24 \\ let \: cameron's \: age \: be \: x \\ given \\ \frac{3}{4} x = 24 \\ or \: x = 24 \times \frac{4}{3} \\ x = 32 \\ hope \: it \: helps[/tex]

Answer 9 is in the domain of f g

Step-by-step explanation:

Answer:

6e+52

Step-by-step explanation:

cAlCuLaToR

Answer:

6e+52

Step-by-step explanation:

multiply

Answer:

  4u²

Step-by-step explanation:

  [tex]\dfrac{12u^3 + 48u^2v}{3u+12v}=\dfrac{12u^2(u+4v)}{3(u+4v)}=\boxed{4u^2}[/tex]

Common factors cancel from numerator and denominator. The one factor that might make the expression undefined is given as non-zero, so no additional restrictions apply.

Answer:

slope = 3/2

Step-by-step explanation:

3x-2y=6

Get this equation in the form y = mx+b where m is the slope and b is the y intercept

Subtract 3x from each side

3x-3x-2y=-3x+6

-2y = -3x+6

Divide each side by -2

-2y/-2 = -3x/-2 +6/-2

y = 3/2x -3

The slope is 3/2 and the y intercept is -3

Answer:

3/2

Step-by-step explanation:

I got this answer by putting it in the form y=mx+b

Step 1: Subtract 3x from each side

-2y = -3x+6

Step 2: Divide each side by -2

y = 3/2x -3

The slope is 3/2 and the y intercept is -3 because m is the slope and b is the y-intercept.

Answer:

Step-by-step explanation:

I= P*r*t

I = 12000* 7% *4

Total interest paid was $3360.

Answer: $3,360

Step-by-step explanation:

Answer:

d. There is not enough evidence to support the hypothesis that the proportion of Uniformian voters has decreased.

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that there is a significant drop in allegiance to the Uniformian Party in Bowie County.

Then, the null and alternative hypothesis are:

[tex]H_0: \pi=0.62\\\\H_a:\pi<0.62[/tex]

The significance level is 0.05.

The sample has a size n=196.

The sample proportion is p=0.57.

The standard error of the proportion is:

[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.62*0.38}{196}}\\\\\\ \sigma_p=\sqrt{0.001202}=0.035[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.57-0.62+0.5/196}{0.035}=\dfrac{-0.047}{0.035}=-1.369[/tex]

This test is a left-tailed test, so the P-value for this test is calculated as:

[tex]\text{P-value}=P(z<-1.369)=0.0855[/tex]

As the P-value (0.0855) is greater than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that there is a significant drop in allegiance to the Uniformian Party in Bowie County.

Answer:

let the two number is x and y

x + y = 4 1/2 .....(i)

x - y = 3 1/4 ......(ii)

adding question (i) and (ii)

x + y = 9/2

x - y = 31/4

=> 2x = 31/4

x = 8/31

substituting the value x in equation 1

8/31 + y = 9/ 2

y = 9/2 - 8/31

y =203/62

the value of x = 8/31

y = 203/62

Answer:

C.

Step-by-step explanation:

Measure of arcURN = 270°

In radians:

270° = 270π/180

270° = 3π/2

Now

Area of sector = 1/2r²∅

= 1/2(10)²(3π/2)

= 50(3π/2)

= 75π

Answer:

2 wild cards

Step-by-step explanation:

Typical would mean most often

2 wild cards shows up 6 times which is most often