To show that Maria's claim is incorrect, we need to find a fraction that is located between 1/5 and 1/7 on a number line but does not have a denominator of 6.
One way to do this is to find the least common multiple (LCM) of 5 and 7, which is 35, and then find a fraction with a denominator of 35 that falls between 1/5 and 1/7.
To do this, we can find the equivalent fractions of 1/5 and 1/7 with a denominator of 35:
1/5 = 7/35
1/7 = 5/35
Now we need to find a fraction between 7/35 and 5/35. One such fraction is:
6/35
This fraction is located between 7/35 and 5/35 on the number line, but its denominator is 35, not 6. Therefore, Maria's claim is incorrect.
Another way to show that Maria's claim is incorrect is to find a counterexample by simply listing all the fractions between 1/5 and 1/7 and showing that not all of them have a denominator of 6. For example:
1/6, 1/7, 1/8, 1/9, 1/10, ..., 1/34, 1/35
As we can see, not all of these fractions have a denominator of 6, so Maria's claim is incorrect.
Answer:
13/70
Step-by-step explanation:
In order to show that Maria's claim is incorrect, we need to find a fraction that is located between 1/5 and 1/7 on a number line, but does not have a denominator of 6.
Let's find the common multiple (CM) of 5 and 7, which is 70, or 35. But this case try 70 and then find a fraction with a denominator of 70 that falls between 1/5 and 1/7.
equivalent fractions of 1/5 and 1/7 with a denominator of 70
1/7 < x < 1/5 , will be equivalent to 1/7 ( 10/10 ) < x < 1/5 ( (14/14)
10/70 < x < 14/70..
x is the fraction between 10/70 and 14 /70. Unknown fraction is:
13/70
This fraction is located between 10/70 and 14/70 on the number line, but its denominator is 70 , not 6. Therefore, Maria's claim is incorrect.
Megha bikes 20km north, 30km east, 20 km south and then 30 km west and then stopped. What is her displacement
Megha's total movement involves biking 20km north, 30km east, 20km south, and 30km west, resulting in a displacement of zero as she ends up back at her starting point.
Given that,
Megha bikes 20km north.
Megha then bikes 30km east.
After that, Megha bikes 20km south.
Lastly, Megha bikes 30km west.
Megha stops after completing the above movements.
Megha's displacement can be calculated by finding the straight-line distance between her starting point and ending point.
In this case,
She initially bikes 20km north, then 30km east, followed by 20km south, and finally 30km west.
Let's break it down:
The north and south distances cancel each other out, as she ends up back at her starting point vertically.
The east and west distances also cancel each other out, as she ends up back at her starting point horizontally.
Hence,
Megha's displacement is zero. She has returned to her original position.
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The base radius and height of a right circular cone are measured as 10 cm and 25 cm, respectively, with a possible error in measurement of as much as 0.1 cm in each dimension. Use differentials to estimate the maximum error in the calculated volume of the cone. (Hint: V = 1/3 πr²h)
The estimated maximum error in the calculated volume of the cone is 20π cubic centimeters.
How to estimate the maximum error in the calculated volume of the cone?Let V = (1/3)πr²h be the volume of the cone, where r and h are the base radius and height of the cone, respectively.
Let dr and dh be the possible errors in the measurements of r and h, respectively.
Then, the actual dimensions of the cone are (r+dr) cm and (h+dh) cm, respectively.
The differential of V is given by:
dV = (∂V/∂r)dr + (∂V/∂h)dh
We have:
∂V/∂r = (2/3)πrh and ∂V/∂h = (1/3)πr²
Substituting the given values, we get:
∂V/∂r = (2/3)π(10 cm)(25 cm) = 500π/3
∂V/∂h = (1/3)π(10 cm)² = 100π/3
Substituting into the differential equation, we get:
dV = (500π/3)dr + (100π/3)dh
Using the given maximum error of 0.1 cm for both r and h, we have:
|dr| ≤ 0.1 cm and |dh| ≤ 0.1 cm
Therefore, the maximum possible error in V is given by:
|dV| = |(500π/3)(0.1 cm) + (100π/3)(0.1 cm)|
|dV| = 50π/3 + 10π/3
|dV| = 60π/3
|dV| = 20π cm³
Therefore, the estimated maximum error in the calculated volume of the cone is 20π cubic centimeters.
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hello! are these correct?
if you can not see my answers :
1. right triangle
2. isosceles triangle
3. equilateral triangle
4. acute triangle
5. isosceles triangle
6. right triangle
( if im incorrect, please tell me the correct answer )
Answer: Yes those are correct good job
Step-by-step explanation:
Let
Ф(u, v) = (3u + 9v, 9u + 9v). Use the Jacobian to determine the area of
Ф(R) for: (a)R = [0,91 × [0, 6]
(b)R = [2,20] × [1, 17]
(a)Area (Ф(R)) =
(b) Area (Ф(R)) =
a) Area (Ф(R)) = 5184 (b) Area (Ф(R)) = 25920
Let J be the Jacobian of Ф. We have J = det(DФ) = det([3 9; 9 9]) = -72.
(a) For R = [0,9] × [0,6], we have
Ф(R) = {(3u+9v,9u+9v) | 0 ≤ u ≤ 9, 0 ≤ v ≤ 6}.
The area of Ф(R) is given by the double integral over R of the Jacobian:
Area (Ф(R)) = ∬R |J| dudv
= ∫0^9 ∫0^6 72 dudv
= 5184.
Therefore, the area of Ф(R) is 5184.
(b) For R = [2,20] × [1,17], we have Ф(R) = {(3u+9v,9u+9v) | 2 ≤ u ≤ 20, 1 ≤ v ≤ 17}. The area of Ф(R) is given by the double integral over R of the Jacobian:
Area (Ф(R)) = ∬R |J| dudv = ∫2^20 ∫1^17 72 dudv = 25920.
Therefore, the area of Ф(R) is 25920.
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Complete the proof that △QST≅△QRT.
The congruent triangles is solved and the triangles are congruent by AAS postulate
Given data ,
Let the two triangles be represented as ΔRQT and ΔTQS
And , the side TQ is the common side of both the triangles
Now , the measure of ∠TQR ≅ measure of ∠TQS ( given )
And , the measure of ∠TRQ ≅ measure of ∠TSQ ( given )
So , Two angles are the same and a corresponding side is the same (ASA: angle, side, angle)
Hence , the triangles are congruent by ASA postulate
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Use any method to determine whether the series converges а. น k2 sk (5 pts) b 6. Ex 2+(-1){ 5k (5 pts)"
To determine whether the series น k2 sk converges, we can use the Integral Test. Let f(x) = x2, then f'(x) = 2x. Since 2x is continuous, positive, and decreasing on [1,∞), In summary, the series Σ (1/k^2) converges, while the series Σ (2 + (-1)^{5k}) does not converge.
∫1∞ f(x) dx = ∫1∞ x2 dx = lim (t → ∞) [1/3 x3]1t = ∞
Since the integral diverges, the series น k2 sk also diverges.
b. To determine whether the series 2+(-1){ 5k converges, we can use the Alternating Series Test. The series has alternating signs and the absolute value of each term decreases as k increases. Let ak = 2+(-1){ 5k, then:
|ak| = 2+1/32k ≤ 2
Also, lim (k → ∞) ak = 0. Therefore, by the Alternating Series Test, the series 2+(-1){ 5k converges.
a. For the series Σ (1/k^2) (denoted as น k2 sk), we can use the p-series test. A p-series is a series of the form Σ (1/k^p), where p is a constant. If p > 1, the series converges, and if p ≤ 1, the series diverges. In this case, p = 2, which is greater than 1. Therefore, the series Σ (1/k^2) converges.
b. For the series Σ (2 + (-1)^{5k}), we can use the alternating series test. An alternating series is a series that alternates between positive and negative terms. In this case, the series alternates because of the (-1)^{5k} term. However, the series does not converge to zero as k goes to infinity, since there is a constant term 2. Therefore, the series Σ (2 + (-1)^{5k}) does not converge.
In summary, the series Σ (1/k^2) converges, while the series Σ (2 + (-1)^{5k}) does not converge.
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Why do Markets behave in the same ways as Individual Consumers?
Answer:
Markets behave the same way as individual customers because markets are made up of individual consumers.
Step-by-step explanation:
A right triangle has legs that are 17 centimeters and 28 centimeters long.
What is the length of the hypotenuse?
Enter your answer as a decimal, Round your answer to the nearest hundredth.
Answer: 4.5
Step-by-step explanation:
The height of Mount Rushmore is 5900 feet. What is the height of Mount Rushmore in
centimeters? (1 in = 2. 54 cm)
Answer:
the answer is 14,986 centimetres
The ratio of runners to walkers at the 10k fund-raiser was 5 to 7. if there
were 350 runners, how many walkers were there?
There were 490 walkers at the 10k fund-raiser.
The ratio of runners to walkers is 5:7, that means that the every five runners, there are 7 walkers so therefore we will use ratio formula.
If there have been 350 runners, we can use this ratio to discover what number of walkers there were:
5/7 = 350/x
Where x is the number of walkers.
To solve for x, we will cross-multiply:
5x = 7 * 350
5x = 2450
x = 490
Consequently, there were 490 walkers at the 10k fund-raiser.
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HERE IS A HARD QUESTION , COULD U PLEASE ANSWER B PLEASE? I DID A ! 1ST ANSWER WOULD BE MARKED BRAINLIEST AND GET 5/5 WITH A THANKS! ILL ALSO COMMENT ON YOUR ANSWER ! BUT IF IT ISNT CORRECT , I WONT MARK BRAINLIEST! Thank you for your answers!!!!
Answer:
D(6,4).
Step-by-step explanation:
The shape ABCD is a square.
By definition, the diagonals are equal.
The diagonal from A to C is 6 units long. Therefore, you should get your point D by drawing across from B to the right by 6.
D(6,4).
Caroline works in a department store selling clothing. She makes a guaranteed salary
of $200 per week, but is paid a commision on top of her base salary equal to 25% of
her total sales for the week. How much would Caroline make in a week in which she
made $1575 in sales? How much would Caroline make in a week if she made a dollars
in sales?
The amount made by Caroline is $593.75 and 200 + 0.25x when she made $1574 and $x in sales respectively.
The total amount will be given by the formula using percentage -
Total amount = Base salary + 25% × her total sales
Keep the value in equation when she made $1575
Total amount = 200 + 25% × 1575
Total amount = 200 + 393.75
Total amount = $593.75
Keep the value in equation when she made $x
Total amount = 200 + 25% × x
Total amount = 200 + 0.25x
Hence, the earned amount is $593.75 and 200 + 0.25x.
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The complete question is -
Caroline works in a department store selling clothing. She makes a guaranteed salary of $200 per week, but is paid a commision on top of her base salary equal to 25% ofher total sales for the week. How much would Caroline make in a week in which she made $1575 in sales? How much would Caroline make in a week if she made x dollars in sales?
The table shown below gives the approximate distance from the sun for a few different planets how much further (in km) from the sun is Saturn than Venus
The distance that shows how much farther (in km) from the sun is Saturn than Venus is: [tex]1.2 * 10^9[/tex] km.
How to calculate the distanceAccording to the table, the distance of Saturn from the Sun is [tex]1.4 * 10^{9}[/tex] and the distance of Venus from the Sun is [tex]1.1 * 10^{8}[/tex] .
Now to determine how much further from the Sun is Saturn than Venus, we will subtract the distance of the planet with the higher distance span from the one with the lower distance.
So our calculation will go thus:
[tex]1.4 * 10^9 - 1.1 * 10^8 = \\140000000 - 11000000 = 1290000000\\= 1.29 * 10^9[/tex]
From the calculation above, we can see how much further from the sun, is Saturn than Venus.
Complete Question:
The table shown below gives the approximate distance from the sun for a few different planets. How much farther (in km) from the sun is Saturn than Venus? Express your answer in scientific notation.
_______km
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Part C
What does the absolute value of the correlation coefficient say about the predictions in part B? How do you know? Write
an explanation of about one to two sentences.
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The shows that Luther can expect the speed to be 51 miles/hour when he throws 80 pitches and 64 miles/hour when he throws 54 pitches.
How to calculate the speed?The average speed of Luther's pitches when he throws 80 pitches will be:
y = -0.511x + 91.636
= -0.511(80) + 91.636
= 50.756
= 51
Also, the number of pitches that Luther can throw when the speed is 64 miles per hour will be:
y = -0.511x + 91.638
64 = -0.511x + 91.638
0.511x = 91.638 - 64
0.511x = 27.636
x = 54
Therefore, the number of pitches will be 54.
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Answer:
Because the absolute value of the correlation coefficient, 0.9672, is very close to 1, Luther can be very confident in the predictions.
Step-by-step explanation: Edmentum Answer
Part D
The rectangular bases of the treasure box will be cut from wooden planks
4 1/8 feet long and 4 1/8 feet wide. How many planks will Mr. Penny need for his
18 students to each
make one treasure box?
Answer:
Step-by-step explanation:
.PLEASEEEEEEEEEEEEEE
Answer:
#1 (176 - x)°
#2 m∠3 = m∠4 = 90°
Step-by-step explanation:
If a pair of parallel lines are cut by a transversal, there are several angles that are either equal to each other or are supplementary(angles add up to 180°).
For the specific questions...
For #1.
Angles ∠1 and ∠2 are supplementary angles since they are adjacent to each other and lie on the same straight line
Therefore
m∠1 + m∠2= 180°
Given m∠1 = (x + 4)° this becomes
(x + 4)° + m∠2 = 180°
m∠2 = 180° - (x + 4)°
= 180° - x° - 4°
= (176 - x)°
For #2
∠3 and ∠4 are supplementary angles so m∠3 + m∠4 = 180°
If m∠3 = m∠4 each of these angles must be half of 180°
So
m∠3 = m∠4 = 180/2 = 90°
A square pyramid is contained within a cone such that the vertices of the base of the pyramid are touching the edge of the cone. They both share a height of 20 cm. The square base of the pyramid has an edge of 10 cm. Using 3.14 as the decimal approximation for T, what is the volume of the cone? 1046.35 cubic centimeters 2093.33 cubic centimeters O 4185.40 cubic centimeters 06280.00 cubic centimeters
To find the volume of the cone, we first need to find its radius. Since the pyramid is contained within the cone such that the vertices of the base of the pyramid are touching the edge of the cone, the diagonal of the square base of the pyramid is equal to the diameter of the base of the cone. The diagonal of the square base of the pyramid is:
d = √(10^2 + 10^2) = √200 = 10√2 cm
Therefore, the diameter of the base of the cone is 10√2 cm, and the radius is 5√2 cm.
The volume of the cone can be calculated using the formula:
V = (1/3)πr^2h
where r is the radius of the base of the cone and h is the height of the cone.
Substituting the given values, we get:
V = (1/3)π(5√2)^2(20)
V = (1/3)π(50)(20)
V = (1/3)(1000π)
V = 1000/3 * π
Using 3.14 as the decimal approximation for π, we get:
V ≈ 1046.35 cubic centimeters
Therefore, the volume of the cone is approximately 1046.35 cubic centimeters. The answer is A.
X-1 if x < 2 Let f(x)=1 if 2sxs6 X+4 if x > 6 a. Find lim f(x). X-+2 b. Find lim f(x). X-6 Select the correct choice and, if necessary, fill in the answer box to complete your choice. O A. lim = X-2 O B. The limit is not - oo or co and does not exist. Select the correct choice and, if necessary, fill in the answer box to complete your choice. O A. lim = X-6 OB. The limit is not - oor oo and does not exist.
a. The limit does not exist.
b. The limit is equal to 4.
a. To find the limit as x approaches 2, we need to evaluate the left-hand and right-hand limits separately and check if they are equal.
Left-hand limit: lim f(x) as x approaches 2 from the left
We have f(x) = x - 1 for x < 2. So, as x approaches 2 from the left, f(x) approaches 1.
Right-hand limit: lim f(x) as x approaches 2 from the right
We have f(x) = 1 for 2 ≤ x ≤ 6 and f(x) = x + 4 for x > 6. So, as x approaches 2 from the right, f(x) approaches 6.
Since the left-hand and right-hand limits are not equal, the limit as x approaches 2 does not exist.
b. To find the limit as x approaches 6, we need to evaluate the left-hand and right-hand limits separately and check if they are equal.
Left-hand limit: lim f(x) as x approaches 6 from the left
We have f(x) = 1 for 2 ≤ x ≤ 6 and f(x) = x + 4 for x > 6. So, as x approaches 6 from the left, f(x) approaches 1.
Right-hand limit: lim f(x) as x approaches 6 from the right
We have f(x) = x + 4 for x > 6. So, as x approaches 6 from the right, f(x) approaches 10.
Since the left-hand and right-hand limits are not equal, the limit as x approaches 6 does not exist.
Therefore, the correct choices are:
a. The limit is not -oo or co and does not exist.
b. lim = 4.
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a time capsule has been buried 98m away from the cave at a bearing of 312 degrees how far west of the cave is the time capsule buried? give your answer in 1 decimal places
If a time capsule has been buried 98m away from the cave at a bearing of 312. the time capsule is buried about 82.2 meters west of the cave.
What is the time capsule?To find how far west the time capsule is buried, we need to find the horizontal component of the displacement vector that points from the cave to the location of the time capsule. We can use trigonometry to do this:
cos(312°) = adjacent/hypotenuse
The hypotenuse is the distance between the cave and the time capsule, which is 98m. The adjacent side represents the horizontal distance between the two points, which is what we want to find. Rearranging the equation, we get:
adjacent = cos(312°) x hypotenuse
adjacent = cos(312°) x 98
adjacent ≈ 82.2
Therefore, the time capsule is buried about 82.2 meters west of the cave.
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MARKING BRAINLEIST IF CORRECT PLS ANSWER ASAP
Answer:
7.6 cm
Step-by-step explanation:
[tex]a^{2}[/tex] + [tex]b^{2}[/tex] = [tex]c^{2}[/tex]
[tex]a^{2}[/tex] + [tex]6.5^{2}[/tex] = [tex]10^{2}[/tex]
[tex]a^{2}[/tex] + 42.25 = 100 Subtract 42.25 from both sides
[tex]a^{2}[/tex] = 57.57
[tex]\sqrt{\a^{a} }[/tex] = [tex]\sqrt{57.57}[/tex]
a ≈ 7.6
Helping in the name of Jesus.
Answer:
7.6 cm
Step-by-step explanation:
a^2+ b^2=c^2
a^2+6.5^2=10^2
a^2+42.25=100 subtract 42.25 from both sides
a^2=57.57
a=√57.57
a=7.6 cm
Color the stars, so it is unlikely impossible to choose a red one.
22. Katie is 6 feet tall and casts a shadow that is 2. 5 feet. If the palm tree next to her casts a shadow of 8. 75 feet at the
same time of day, how tall is the palm tree?
Please help me this due today
No links or I will report you
The palm tree is 21 feet tall.
To find the height of the palm tree, we can use the concept of similar triangles, where the ratio of corresponding sides is equal. In this case, the terms we need are Katie's height, her shadow length, the palm tree's shadow length, and the palm tree's height.
Step 1: Set up the proportion using the given information.
(Katie's Height / Katie's Shadow Length) = (Palm Tree Height / Palm Tree Shadow Length)
Step 2: Plug in the given values.
(6 ft / 2.5 ft) = (Palm Tree Height / 8.75 ft)
Step 3: Solve for Palm Tree Height.
(6 ft / 2.5 ft) * 8.75 ft = Palm Tree Height
2.4 * 8.75 ft = Palm Tree Height
Step 4: Calculate the height.
21 ft = Palm Tree Height
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What is a way you can find the vaule of x
Answer:To find the value of x, bring the all the variable to the left side and bring all of the remaining values to the right side. You then simplify the values to find the answer.
Step-by-step explanation:
Answer:
im not sure bud because i don't know what is the full question?
Step-by-step explanation:
In a class of students, the following data table summarizes how many students passed a test and complete the homework due the day of the test. What is the probability that a student chosen randomly from the class passed the test and completed the homework? Passed the test Failed the test Completed the homework 11 3 Did not complete the homework 2 5
The probability that a student chosen randomly from the class passed the test or completed the homework is 20/27.
What is the probability?The probability that a student chosen randomly from the class passed the test or completed the homework is calculated as follows:
Let the probability that a student completed the homework be P(B).
Also, let the probability that a student passed the test be P(A)
P(A or B) = P(A) + P(B) - P(A * B)
From the data table:
The number of students who passed the test = 18
The number of students who completed the homework = 17
The number of students who both passed the test and completed the homework = 15.
Total number of students = 27
P(A) = 18/27
P(B) = 17/27
P(A*B) = 15/27
Therefore,
P(A or B) = 18/27 + 17/27 - 15/27
P(A or B) = 20/27
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the sales tax rate in your city is 7.5%. What is the total amount you pay for a $6.84 item.
Answer:
$7.35
Step-by-step explanation:
"The times for the mile run of a large group of male college students are approximately Normal with mean 7. 06 minutes and standard deviation 0. 75 minutes. Use the 68-95-99. 7 rule to answer the following questions. (Start by making a sketch of the density curve you can use to mark areas on. ) (a) What range of times covers the middle 95% of this distribution
According to the 68-95-99.7 rule, approximately 68% of the distribution falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations.
In this case, the mean is 7.06 minutes and the standard deviation is 0.75 minutes. Therefore, the range of times that covers the middle 95% of the distribution would be from the mean minus two standard deviations (7.06 - 2 x 0.75 = 5.56 minutes) to the mean plus two standard deviations (7.06 + 2 x 0.75 = 8.56 minutes).
In other words, 95% of the male college students' mile run times are expected to fall between 5.56 and 8.56 minutes. This means that most of the students' mile run times will be within this range, and only a small percentage will be outside of it.
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Find the average x-coordinate of the points in the prism D={(x,y,z):0 ≤ x ≤ 6,0 ≤ y ≤ 18-3x, 0 ≤ z ≤ 4}. The average x-coordinate of the points in the prism is (Simplify your answer.)
The average x-coordinate of the points in the prism is 3.
What is a prism?A prism is a polyhedron that has two parallel and congruent polygonal bases that are linked by parallelogram faces that are lateral. The height of the prism is the perpendicular distance between the bases.
The formula for calculating the average x-coordinate of the points in the prism D = {(x,y,z):0 ≤ x ≤ 6,0 ≤ y ≤ 18-3x, 0 ≤ z ≤ 4} is$$\frac{\text{sum of all x-coordinates}}{\text{number of vertices}}$$
The vertices of a prism are the points where two adjacent edges meet. There are eight vertices in a rectangular prism, and the x-coordinate of each vertex is either 0 or 6. The x-coordinates of the vertices are $$0,0,0,0,6,6,6,6.
$$The sum of all the x-coordinates is 24. Thus, the average x-coordinate of the points in the prism is$$\frac{24}{8}=\boxed{3}.
$$Hence, the average x-coordinate of the points in the prism is 3.
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Consider a metal plate on [0,1] ×[0,1] with density rho(x,y) = αx
+ βy g/cm2, where α and β are positive constants. Show that the
center of mass must lie on the line x + y = 7/6 .
The center of mass of the metal plate with density rho(x,y) = αx+ βy g/cm2 must lie on the line x + y = 7/6.
To find the center of mass of the metal plate, we need to calculate the coordinates of its centroid (X, Y). The coordinates of the centroid are given by:
X = (1/M) ∬(R) x ρ(x,y) dA, Y = (1/M) ∬(R) y ρ(x,y) dA
where M is the total mass of the plate, R is the region of integration (0 ≤ x ≤ 1, 0 ≤ y ≤ 1), and dA is the differential area element.
We can calculate the total mass M of the plate as follows:
M = ∬(R) ρ(x,y) dA = α/2 + β/2 = (α + β)/2
Using the given density function, we can calculate the integrals for X and Y:
X = (1/M) ∬(R) x ρ(x,y) dA = (2/αβ) ∬(R) x(αx+βy) dA = (2/3)(α+β)
Y = (1/M) ∬(R) y ρ(x,y) dA = (2/αβ) ∬(R) y(αx+βy) dA = (2/3)(α+β)
Thus, the coordinates of the centroid are (X, Y) = ((2/3)(α+β), (2/3)(α+β)).
Now, if we substitute X + Y = (4/3)(α+β) into the equation x + y = 7/6, we get:
x + y = 7/6
2x + 2y = 7/3
2(x+y) = 4/3(α+β)
x+y = (2/3)(α+β)
which shows that the centroid lies on the line x + y = 7/6. Therefore, the center of mass must also lie on this line.
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Pls Answer Soon!
A college professor asked every student in his statistics class to flip a coin 100 times and report how many times the coin landed on heads. The results followed a normal distribution, with a mean of 50 and a standard deviation of 5.
If there were 70 students in the class, how many of the students most likely got heads between 45 times and 60 times?
Round your answer to the nearest whole number of students
57 students most likely got heads between 45 and 60 times.
To determine the number of students who got heads between 45 and 60 times, we'll use the normal distribution properties. First, we need to calculate the z-scores for 45 and 60:
Z = (X - μ) / σ
For 45 heads:
Z1 = (45 - 50) / 5 = -1
For 60 heads:
Z2 = (60 - 50) / 5 = 2
Next, we need to find the probability that a student falls between these z-scores. We can do this by looking up the z-scores in a standard normal distribution table or using a calculator. The probabilities corresponding to these z-scores are:
P(Z1) = 0.1587
P(Z2) = 0.9772
Now, subtract P(Z1) from P(Z2) to get the probability of a student's result falling between 45 and 60 heads:
P(45 ≤ X ≤ 60) = P(Z2) - P(Z1) = 0.9772 - 0.1587 = 0.8185
Finally, multiply this probability by the total number of students (70) and round to the nearest whole number:
Number of students = 0.8185 * 70 ≈ 57
So, approximately 57 students most likely got heads between 45 and 60 times.
To learn more about probability, refer below:
https://brainly.com/question/30034780
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1. Sanchez deposited $3,000 with a bank in a 4-year certificate of deposit yielding 6% interest
compounded daily. Find the interest earned on the investment. (4pts)
The compound interest generated on the investment is roughly $813.67, which is the solution to the question based on compound interest.
What is Principal?The initial sum of money invested or borrowed, upon which interest is based, is referred to as the principle. The principal is then periodically increased by the interest, often monthly or annually, to create a new principal sum that will accrue interest in the ensuing period.
Using the compound interest calculation, we can determine the interest earned on Sanchez's investment:
[tex]A = P(1 + \frac{r}{n} )^{(n*t)}[/tex]
where A is the overall sum, P denotes the principal (the initial investment), r denotes the yearly interest rate in decimal form, n denotes the frequency of compounding interest annually, and t denotes the number of years.
In this case, P = $3,000, r = 0.06 (6%), n = 365 (compounded daily),
and t = 4.
Plugging in the values, we get:
[tex]A = 3000(1 + \frac{0.06}{365} )^{(365*4)}[/tex]
A= $3813.67
The difference between the final amount and the principal is the interest earned.
Interest = A - P
Interest = $3813.67 - $3000
Interest = $813.67
As a result, the investment's interest yield is roughly $813.67.
To know more about compound interest, visit:
brainly.com/question/20406888
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