Answer: C
Explanation:
I took a quiz on this.
The nurse discovers that one of her assigned clients is bleeding excessively from an abdominal incision. The nurse gives specific prescriptions to an unlicensed assistive personnel (UAP) to attend to the other clients and tells another nurse to call the primary health care provider immediately. In this situation, the nurse is implementing which leadership style?
What is the representative particle for boron?
The molecule is the representative particle of molecular compounds. It is also the representative particle of diatomic elements.
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-1
1 point
Which is not a force that causes erosion and deposition?
carbonation
1
glaciers
waves
2
water
3
Mineral reaction to stress
Answer:
Tenacity describes the reaction of a mineral to stress such as crushing, bending, breaking, or tearing. ... The majority of all minerals are brittle. An example is Quartz. (Minerals that are not brittle may be referred to as Nonbrittle minerals.)
A 11.1-g sample of granite initially at 76.0°C is immersed into 22.0 g of water initially at 22.0°C. What is the final temperature of both substances when they reach thermal equilibrium? (For water, Cs=4.18J/g⋅∘C and for granite, Cs=0.790J/g⋅∘C.)
Answer:
[tex]T_f=26.7\°C[/tex]
Explanation:
Hello.
In this case, when two substances at different temperature are placed in contact in an isolated container, we can say that the heat lost by the hot substance is gained by the cold substance. In such a way, since granite is at 76.0 °C and water at 22.0 °C we infer granite is hot and water is cold, so we write:
[tex]Q_{granite}=-Q_{water}[/tex]
In terms of mass, specific heat and change in temperature, we write:
[tex]m_{granite}C_{granite}(T_f-T_{granite})=-m_{water}C_{water}(T_f-T_{water})[/tex]
Thus, since the temperature is the same for both substance, we can solve for it as shown below:
[tex]T_f=\frac{m_{granite}C_{granite}T_{granite}+m_{water}C_{water}T_{water}}{m_{granite}C_{granite}+m_{water}C_{water}}[/tex]
By plugging in each variable, we obtain:
[tex]T_f=\frac{11.1g*0.790\frac{J}{g\°C} *76.0\°C+22.0g*4.18\frac{J}{g\°C} *22.0\°C}{11.1g*0.790\frac{J}{g\°C} +22.0g*4.18\frac{J}{g\°C}}\\\\T_f=26.7\°C[/tex]
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Calculate the mass percentage of NaClNaCl in a solution containing 1.50 gg of NaClNaCl in 50.0 gg of water.
Answer:
%m/m = 2.9 %
Explanation:
The mass percentage (m/m %) of a solution is calculated as follows:
m/m % = mass of solute/ mass of solution x 100
The solution is composed by : solute + solvent. In this case, the solute is NaCl and the solvent is water. We have:
mass of solute = 1.50 g
mass of solvent = 50.0 g
mass of solution = mass of solute + mass of solvent = 1.50 g = 50.0 g = 51.5 g
Thus, the mass percentage of NaCl in the solution is :
% m/m = (1.50 g)/(51.5 g) x 100 = 2.91 % ≅ 2.9 %
-
How many different sublevels are in the second energy level?
A. 2
B. 1
C. 4
D. 3
SI
Answer:
A: 2
Explanation:
Level one has one sublevel, whereas a Level two has two sublevels.
Which of the following is an example of sp3 d2 hybridization?
A. C₂H6
B. PC15
C. 1F7
D. SFO
what the equipment of diffusion?
Answer:
liquid
a semi permeable membrane
oxygen
Explanation:
plz give me brainiest
How many moles are in 1.29 x 1024 hydrogen atoms in HF
Answer:
No. Moles = 2.142 mole
Calculate the pH at 25 degrees celsius of a 0.39 M solution of pyridinium chloride (c5h5nhcl) . Note that pyridine (c5h5n) is a weak base with a pkb of 8.77 .
Round your answer to 1 decimal place.
Answer:
[tex]pH=2.3[/tex]
Explanation:
Hello!
In this case, since pyridinium chloride has a pKb of 8.77 which is a Kb of 1.70x10⁻⁹ and therefore a Ka of 5.89x10⁻⁵ which means it tends to be acidic, we write its ionization via:
[tex]C_5H_5NHCl(aq)+H_2O(l)\rightleftharpoons C_5H_5NCl^-(aq)+H_3O^+(aq)[/tex]
Because it is a Bronsted base which donates one hydrogen ion to the water to produce hydronium. Thus, we write the equilibrium expression with the aqueous species only:
[tex]Ka=\frac{[C_5H_5NCl^-][H_3O^+]}{[C_5H_5NHCl]}[/tex]
In terms of the reaction extent [tex]x[/tex], we write:
[tex]5.89x10^{-5}=\frac{x*x}{0.39-x}[/tex]
Thus, solving for [tex]x[/tex] we obtain:
[tex]x_1=-0.0048M\\\\x_2=0.0048M[/tex]
Clearly the solution is 0.0048 M because to negative values are not allowed, therefore, since it equals the concentration of hydronium which defines the pH, we write:
[tex]pH=-log([H_3O^+])=-log(0.0048)\\\\pH=2.3[/tex]
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Identify the common indicators that a chemical reaction has occurred.
a. A color change
b. A phase change
c. Precipitate being formed
d. A solid being dissolved
e. A change in temperature
f. Bubbles being produced
Answer:
a. A color change
c. Precipitate being formed
e. A change in temperature
f. Bubbles being produced
Explanation:
Two types of changes occur namely: physical changes and chemical changes. A physical change does not affect the chemical composition of the substance involved. Physical changes include change of state etc.
However, on the other hand, a chemical change alters the chemical composition of the substances involved, hence, leading to the formation of new product(s). It is also called a chemical reaction. Since a new product is formed from the alteration of the chemical nature of the reacting substances, the following changes or indicators will be present or evident in a chemical reaction:
- color change of substance
- Precipitate being formed i.e. solid deposit
- A change in temperature
- Bubbles being produced (evolution of gas)
Does anybody know these questions ?
Answer:
proton 5
Explanation:
I think it is fluorine
Water can be an atom.
True
False
true because I asked my sister
Answer:
false
Explanation:
yep
Given 700 ml of oxygen at 7 ºC and 80.0 cm Hg pressure, what volume does it take at 27 ºC and 50.0 cm Hg pressure?
Answer:
I think that it might be 2.7
Explanation:
When do chemical reactions occur?
Answer:
When the molecular composition changes.
Explanation:
A physical change is a change in size or appearance that can usually be reversed; a chemical change cannot be reversed easily and changes the atomic composition of something.
When a solution of ammonium sulfate is added to a
solution of lead(II) nitrate, Pb(NO3)2, a white
precipitate, lead(II) sulfate, forms. Write a balanced
net ionic equation for this reaction. Both ammonium
sulfate and lead(II) nitrate, Pb(NO3)2 exist as
dissociated ions in aqueous solution.
Answer:
Explanation:
(NH4)2SO4+Pb(NO3)2...............PbSO4+2NH4NO3
The balanced net ionic equation for the reaction between ammonium sulfate (NH₄)2SO₄ and lead(II) nitrate Pb(NO₃)₂, resulting in the formation of lead(II) sulfate (PbSO₄), can be written as follows:
[tex]2NH_{4+} + SO_{4}^2- + Pb^{2+} + NO_{3-} + PbSO_{4} (s) + 2NH_{4+} + 2NO_{3-}[/tex]
In this equation, the ammonium cation (NH₄₊) and nitrate anion (NO₃₋) are spectator ions, meaning they appear on both sides of the equation and do not participate in the actual chemical reaction. Therefore, they are not included in the net ionic equation.
The net ionic equation represents only the species that undergo a change, which in this case is the sulfate anion (SO₄²⁻) and the lead(II) cation (Pb²⁺), leading to the formation of the white precipitate, lead(II) sulfate (PbSO₄).
Therefore, the balanced net ionic equation can be wriiten as:
[tex]2NH_{4+} + SO_{4}^2- + Pb^{2+} + NO_{3-} + PbSO_{4} (s) + 2NH_{4+} + 2NO_{3-}[/tex]
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Calculate the pH of a solution with a [H 3 O + ]=5.6x10 -9 M.
Answer:
8.3
Explanation:
pH is the measure of the H+ or H30 (they r the same thing) ions in a solution. it is equal to -log[H+]. [H+]= Molar concentration of H+ ions.
hlo good evening everyone
Answer:
hi
Explanation:
Hello good evening' but for me it's a good night
Explanation:
Anyway, thank you for the points have a great day!
trioxocarbonate iv acid
Answer:
Trioxocarbonate (iv) are salts derived from trioxocarbonate (iv) acid when it reacts with metals and metallic oxides. All trioxocarbonate (iv) salts of Sodium (Na), Potassium (K) and Ammonium(NH4+) are soluble while all others are insoluble.
Production of 6.5 grams of C2H2 requires consumption of how many grams of H2O
Answer:
C
Explanation:
Grams 3/4
Answer:
9g
Explanation:
number of moles × the moleculars mass
If 8.500 g CH is burned and the heat produced from the burning is added to 5691 g of water at 21 °C, what is the final
temperature of the water?
The final temperature = 36 °C
Further explanationThe balanced combustion reaction for C₆H₆
2C₆H₆(l)+15O₂(g)⇒ 12CO₂(g)+6H₂O(l) +6542 kJ
MW C₆H₆ : 78.11 g/mol
mol C₆H₆ :
[tex]\tt \dfrac{8.5}{78.11}=0.109[/tex]
Heat released for 2 mol C₆H₆ =6542 kJ, so for 1 mol
[tex]\tt \dfrac{0.109}{2}\times 6542=356.539~kJ/mol[/tex]
Heat transferred to water :
Q=m.c.ΔT
[tex]\tt 356.539=5.691~kg\times 4.18~kj/kg^oC\times (t_2-21)\\\\t_2-21=15\rightarrow t_2=36^oC[/tex]
What isotope does the model show? ASAP
1. lithium-6
2. lithium-7
3. beryllium-7
4. beryllium-4
Answer:
Lithium 7
Explanation:
An isotope is based off the number of neutrons present 3+4=7
Look on the periodic table to find the element number
A mixture of nitrogen and xenon gases contains nitrogen at a partial pressure of 417 mm Hg and xenon at a partial pressure of 427 mm Hg. What is the mole fraction of each gas in the mixture
Answer:
0.4941, 0.5059
Explanation:
[tex]P_N[/tex] = Partial pressure of nitrogen = 417 mm Hg
[tex]P_{Xe}[/tex] = Partial pressure of xenon = 427 mm Hg
Total pressure in the system is given by
[tex]P=P_N+P_{Xe}\\\Rightarrow P=417+427=844\ \text{mm Hg}[/tex]
Mole fraction is given by
[tex]X_N=\dfrac{P_N}{P}\\\Rightarrow X_N=\dfrac{417}{844}\\\Rightarrow X_{N}=0.4941[/tex]
For xenon
[tex]X_{Xe}=1-0.4941=0.5059[/tex]
or
[tex]X_{Xe}=\dfrac{P_{Xe}}{P}\\\Rightarrow X_{Xe}=\dfrac{427}{844}\\\Rightarrow X_{Xe}=0.5059[/tex]
So, mole fraction of nitrogen is 0.4941 and xenon is 0.5059.
When carbon dioxide is dissolved in an aqueous solution of sodium hydroxide, the mixture reacts to yield aqueous sodium carbonate and liquid water. Determine the net ionic equation for this process.
Answer:
CO + 2NaOH(aq) ---------- Na2CO3 + H2O
When carbon dioxide is dissolved in an aqueous solution of sodium hydroxide, the mixture reacts to yield aqueous sodium carbonate and liquid water. The net ionic equation is CO + [tex]2OH^{-}[/tex] → [tex]CO^{2-} _{3}[/tex]
What is the net ionic equation?The molecular formula for a process known as the net ionic equation only includes the species which are really involved in the reaction. In double displacement reactions, and redox reactions, including acid-base neutralization processes, the net ionic equation would be frequently employed.
When carbon dioxide is dissolved in an aqueous solution of sodium hydroxide, the mixture reacts to yield aqueous sodium carbonate and liquid water.
CO + 2NaOH → [tex]Na_{2} CO_{3} + H_{2}O[/tex]
The ionic equation can be written as:
CO + [tex]2Na^{+} + 2OH^{-}[/tex] → [tex]2Na^{+} + CO^{2-} _{3}[/tex]
Hence, the net ionic equation is CO + [tex]2OH^{-}[/tex] → [tex]CO^{2-} _{3}[/tex]
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need help thx if you take the time to help me out
Answer:
A is the only neutral atom there.
Explanation:
It consists of 6 atoms 6 neutrons and 6 electrons which means it is neutral. I am currently in chemistry.
What is O?
(A)Metal
(B)Metalloid
(C)Nonmetal
(D)None of the above
Answer:nonmetal
Explanation: gggg
.
As you move from left to right, the atomic number of each element increases
by
Answer:
Ionization Energy increases from left to right on the periodic table. Atomic radius decreases moving left to right on the periodic table.
Atomic size gradually decreases from left to right across a period of elements. This is because, within a period or family of elements, all electrons are added to the same shell.
The pH of a solution prepared by mixing 50.0 mL of 0.125 M KOH and 50.0 mL of 0.125 M HCl is ________.
Answer:
7
Explanation:
This question is a neutralization reaction.
50 ml of 0.125 M of KOH = (50 x 0.125) = 6.25 ml
In this same way, 50 ml of 0.125M of HCl = 50x0.125
= 6.25 ml
Then KOH is going to neutralise the HCl fully suvh that the pH of the medium is going to be 7
(H+) + (OH-) = H2O
Then Kw = [H=][OH-]
= [H+]² = 10^-14
Such that [H+] = 10^-7
The pH would be = -log [H+]
= -log[10^-7]
When inputted on a calculator this gives us 7
= 7
This is our answer
compare the size of I, I+ and I-
umm explanation pls so i answee
