Tasheena's grade percentage in the class so far is approximately 71.00935%.
How do you find percentages?The percentage can be calculated by dividing the value by the total value, and then multiplying the result by 100.
To compute Tasheena's grade percentage in the class so far, we can calculate the weighted average of her scores based on the weightage of each component of the final grade.
Given:
Quizzes: 15% weightage
Exams: 55% weightage
Projects: 25% weightage
Attendance: 5% weightage
Tasheena's scores:
Quizzes: 117 out of 150 points
Exams: 74, 86, and 91 on the first three exams (each worth 100 points)
Projects: 29 out of 25 possible points
Attendance: Perfect attendance
Let's calculate Tasheena's grade percentage:
Quizzes:
Tasheena's quiz score percentage = (117 / 150) * 100 = 78%
Exams:
Tasheena's exam average = (74 + 86 + 91) / 3 = 83.67
Tasheena's exam score percentage = (83.67 / 100) * 55 = 46.017%
Projects:
Tasheena's project score percentage = (29 / 25) * 100 = 116%
Attendance:
Tasheena's attendance score percentage = 100% (since she had perfect attendance)
Now, let's calculate the weighted average of Tasheena's scores:
Weighted average = (Quizzes weightage * Quiz score percentage) + (Exams weightage * Exam score percentage) + (Projects weightage * Project score percentage) + (Attendance weightage * Attendance score percentage)
= (15% * 78%) + (55% * 46.017%) + (25% * 116%) + (5% * 100%)
= 11.7% + 25.30935% + 29% + 5%
= 71.00935%
Hence, Tasheena's grade percentage in the class so far is approximately 71.00935%.
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Express the following probability as a simplified fraction and as a decimal.
If one person is selected from the population described in the table, find the probability that the person is or .
Note that the following probability as a simplified fraction and as a decimal is: 0.88617886178 and 109/123
How is this so?Note that the key phrase here is “given that this person is a man.”
This means that all we are interested in is the row labeled Male.
Married Never Div Widowed Total
Male 69 40 11 3 123
We are asked to find the probability that the person was either Married or Never. So the fraction you want is (69 + 40) / 123.
⇒ (69 + 40) / 123.
⇒ 109/123
or 0.886179
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Full Question:
Although part of your question is missing, you might be referring to this full question:
Express the following probability as a simplified fraction and a decimal.
if one person is selected from the population described in the table, find the probability that the person has never been married or is married, given that this person is a man.
Married Never Married Divorced Widowed Total
Male 69 40 11 3 123
Female 67 33 20 5 125
Total 136 73 31 8 248
Question 1.Express the probability as a simplified fraction
limit x->oo (sqrt(x^2-9x+1)-x)=?
I solved it up until -9x+1/((√x^2-9x+1)+x) but I don't know what to do after this.
Note that the limit of the expression as x approaches infinity is 1/2.
How did we arrive at this conclusion ?start by multiplying both the numerator and denominator by the conjugate expression
√ (x ² - 9x + 1) + x,
this will eliminates the root in the numerator
lim x->∞ [(√(x ² - 9x + 1) - x) * (√(x² - 9x + 1) + x)] / (√(x² - 9x + 1) + x)
Expanding the numerator
lim x- >∞ [(x² - 9x + 1) - x^2] / (√(x² - 9x + 1) + x)
Simplifying further:
lim x->∞ [(1 - 9/x + 1/ x²)] / (√(1 - 9/x + 1 /x²) + 1)
we can see that the 1/x ² term approaches zero, and the expression simplifies to
lim x->∞ [(1 - 0)] / (√(1 - 0) + 1)
= 1/2
So it is correct to state that the limit of the expression as x approaches infinity is 1/2.
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I have no idea how to solve this problem.
(a) The domain of f of g is {1, 8}.
(b) The range of f of g is {0, 1}.
What is the domain and range of f of g?The domain of f of g consists of all the inputs in the domain of g that are also in the domain of f.
(a) Domain of f of g:
The inputs in the domain of g that are also in the domain of f are 1, and 8. Therefore, the domain of f of g is {1, 8}.
To find the range of f of g, we need to apply the function composition f(g(x)) to each input in the domain of f of g, and collect all the outputs.
(b) Range of f of g:
The range of f of g consists of all the outputs obtained by applying f(g(x)) to each input in the domain of f of g.
We have:
f(g(1)) = f(8) = 0
f(g(4)) = f(2) = 1
f(g(8)) = f(0) = 1
Therefore, the range of f of g is {0, 1}.
Thus, in set notation, the domain of f of g is {1, 8}, and the range of f of g is {0, 1}.
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Which choice is the correct graph of |x|< 3
The graph that shows the solution set for the given inequality is the one in option B.
Which one is the graph of the given inequality?Here we want to identify the graph of the inequality:
|x| ≤ 3
So, the absolute value of x is smaller or equal to 3, that means that the graph of the solution set is a segment whose endpoints are closed circles at x = -3 and x = 3.
(We use closed circles because these values are also solutions for the inequality).
With that in mind, we can see that the correct option in this case will be graph B.
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For the function value f(−9)=6, write a corresponding ordered pair.
Answer:
(-9, 6) This ordered pair is used to find the function value f(-9)=6
or the given function value, write a corresponding ordered pair.
Step-by-step explanation:
For the given function value, write a corresponding ordered pair.
f(-9) = 6
The ordered pair of each function can be written as (x,y).
For any function, for example, g(x)= 10x, the input is x, and the output y is 10x. So ordered pair is (x,10x)
The given function value is: f(-9) = 6
Here input x=-9 and y value is 6
So, he corresponding ordered pair is (-9, 6)
On a sample tray, 3 out of 6 cake samples are chocolate.
What is the probability that a randomly selected piece of cake will be chocolate?
Write your answer as a fraction or whole number.
The probability that a randomly decided piece of cake maybe chocolate is 1/2 or half of or 0.
The proportion of chocolate cakes to all other cakes can be used to calculate the probability that a person will pick a chocolate cake from the pattern tray.
In this case, there are 3 chocolate cakes out of a total of 6 cakes.
So the probability of selecting a chocolate cake is:
3/6 = 1/2 (Dividing the numerator and denominator by their greatest common factor, in this case, 3 will simplify the fraction 3/6.)
Therefore, the probability of selecting a chocolate cake is 1/2 or 0.5 when expressed as a decimal.
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Sketch the graph of the following function. Describe how
the graph can be obtained from the graph of the basic
exponential function ex.
f(x) = 2 (4-ex)
Use the graphing tool to graph the equation.
someone help pls, im not sure what to put in the little box for the vertical shift and vertical shrink
The vertical shift and vertical shrink of the exponential function are 2 and 1/2 respectively and the graph of the function is attached below
An exponential function is defined by the formula f(x) = ax, where the input variable x occurs as an exponent. The exponential curve depends on the exponential function and it depends on the value of the x.
The vertical shift and vertical shrink of the function f(x) = 1/2(4 - eˣ) are 2 and 1/2
The vertical shift = 2
vertical shrink = 1/2
Kindly find the attached graph below
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combine like terms 6x^2 - 10x + 21x - 35 = 6x^2 + 11x - 35
Answer:
Step-by-step explanation:
6x² - 10x + 21x - 35 = 6x² + 11x - 35
6x² - 6x² + 11x - 11x - 35 + 35 = 0
0 = 0
The equation is an identity. Its solution set is {all real numbers}.
Here are five spinners with orange and white sectors. Each spinner is divided into equal sectors. A a) b) a) For one of the spinners, the probability of spinning orange is Which spinner is this? B A b) For two of the spinners, the probability of spinning orange is more than 40%. Which two spinners are these?
Spinner B is the spinner that has a probability of 1/3 of spinning orange.
How to find the he probability of spinning orange is more than 40%a) For one of the spinners, the probability of spinning orange is 1/3. To identify which spinner this is, we need to find the spinner that has exactly one orange sector out of three total sectors.
From the given spinners, Spinner B is the only spinner that has one orange sector out of three, so Spinner B is the spinner that has a probability of 1/3 of spinning orange.
b) For two of the spinners, the probability of spinning orange is more than 40%. To find these spinners, we need to look for the spinners that have at least three orange sectors out of a total of eight sectors (since 3/8 is greater than 40%).
From the given spinners, Spinner A and Spinner C both have three orange sectors out of eight total sectors, so they are the two spinners for which the probability of spinning orange is more than 40%.
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50 Points! Multiple choice algebra question. Photo attached. Thank you!
Answer: C {m | m > 2}
Step-by-step explanation:
write the number in exponential form with the base of 2
2^3m-4 > 2^2
compare the exponents = 3m-4 >2
move the constant to the right and then change the sign
3m> 2+4 add
3m>6 divide
m>2
What is 0.08% written as a decimal?
PLEASE HELP WITH THE IMAGE!! DUE TOMORROW!!!
The calculations of the down payments, monthly income or payments are as follows:
Part 1:
Annual income = $226,000
Federal Tax = $62,582
State Tax = $16,385
Local Tax = $5,537
Healthcare = $4,520
Yearly income = $136,976
Monthly income = $11,414.67.
Part 2:
Down payment = $150,000
The amount to borrow (Mortgage loan) = $600,000
Estimated interest = $810,000
Total installment payments = $1,410,000
Monthly payment = $3,916.67.
Part 3:
Down payment = $2,902.50
Mortgage loan = $16,447.50
Estimated interest = $3,700.69
Interest + Mortgage loan = $20,148.19
Monthly payment = $335.80.
Part 1:
Annual income = $226,000
Federal Tax:
25% of $89,350 = $22,337.50
28% of $97,000 = $27,160.00
33% of $39,650 = $13,084.50
Total federal tax = $62,582
State Tax = 7.25% of $226,000 = $16,385
Local Tax = 2.45% of $226,000 = $5,537
Healthcare = 2% of $226,000 = $4,520
f) Total of Federal, State, Local, and Healthcare = $89,024
Yearly income = $136,976 ($226,000 - $89,024)
Monthly income = $11,414.67 ($136,976 ÷ 12)
Part 2:
a) House price = $750,000
b) Down payment = 20%
= $150,000 ($750,000 x 20%)
c) Mortgage loan = $600,000 ($750,000 - $150,000)
d) Interest rate = 4.5%
Number of mortgage years = 30 years
Mortgage period in months = 360 months (30 x 12)
Estimated interest = $810,000 ($600,000 x 4.5% x 30)
Interest + Mortgage loan = $1,410,000 ($600,000 + $810,000)
Monthly payment = $3,916.67 ($1,410,000 ÷ 360)
Part 3:
Price of car = $19,350
Down payment = 15%
= $2,902.50 ($19,350 x 15%)
Mortgage loan = $16,447.50 ($19,350 - $2,902.50)
Number of years = 5 years
Mortgage period in months = 60 months (5 x 12)
Estimated interest = $3,700.69 ($16,447.50 x 4.5% x 5)
Interest + Mortgage loan = $20,148.19 ($16,447.50 + $3,700.69)
Monthly payment = $335.80 ($20,148.19 ÷ 60)
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What does the circled portion represent in the confidence interval formula?
p±z.
O Sample proportion
O Margin of error
p(1-p)
n
Confidence interval
O Sample Size
The circled portion in the confidence interval formula p ± z represents the Margin of Error, which plays a crucial role in interpreting the range of plausible values for the population parameter.
In the confidence interval formula p ± z, the circled portion represents the Margin of Error.
The Margin of Error is a critical component of a confidence interval and quantifies the level of uncertainty in the estimate.
It indicates the range within which the true population parameter is likely to fall based on the sample data.
The Margin of Error is calculated by multiplying the critical value (z) by the standard deviation of the sampling distribution.
The critical value is determined based on the desired level of confidence, often denoted as (1 - α), where α is the significance level or the probability of making a Type I error.
The Margin of Error accounts for the variability in the sample and provides a measure of the precision of the estimate.
It reflects the trade-off between the desired level of confidence and the width of the interval.
A larger Margin of Error indicates a wider confidence interval, implying less precision and more uncertainty in the estimate.
Conversely, a smaller Margin of Error leads to a narrower confidence interval, indicating higher precision and greater certainty in the estimate.
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what are the answers to these questions?
The height and radius that minimize the amount of material needed to manufacture the can are both approximately 6.39 cm.
The total surface area of the can is therefore:
A = 2πr² + 2πrh
We know that the volume of the can is 810 cm³, which is given by:
V = πr²h
We can solve this equation for h to get:
h = V/(πr²)
Substituting this expression for height h into the equation for the surface area, we get:
A = 2πr² + 2πr(V/(πr²))
Simplifying, we get:
A = 2πr² + 2V/r
Now we have an equation for the surface area of the can in terms of the radius, r.
To minimize the surface area, we need to take the derivative of this equation with respect to r, set it equal to zero, and solve for r.
dA/dr = 4πr - 2V/r² = 0
Solving for radius r, we get:
[tex]r = (810/\pi)^1^/^3[/tex]
r=∛810/3.14
r=6.35 cm
Now find h:
h = 810/πr²
h=810/3.14×6.35²
h=810/126.6
h=6.39 cm
Hence, the height and radius that minimize the amount of material needed to manufacture the can are both approximately 6.39 cm.
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Apply the nearest neighbor algorithm to the graph above starting at vertex A. Give your answer as a list of vertices, starting and ending at vertex A. Example: ABCDA
Starting at vertex A and using the nearest neighbor algorithm, the path is: A-C-B-D-A, with a total distance of 95. This means visiting vertices in the order A, C, B, D, and back to A, and the total distance traveled is 95 units.
The nearest neighbor algorithm is used to find the shortest path between a set of points. Here are the steps to apply the algorithm in this case
Start at vertex A. Look for the closest neighboring vertex to A. In this case, the closest vertex is B, which is 7 units away from A. Move to vertex B and mark it as visited. Look for the closest neighboring vertex to B that has not been visited. In this case, the closest vertex is C, which is 11 units away from B.
Move to vertex C and mark it as visited. Look for the closest neighboring vertex to C that has not been visited. In this case, the closest vertex is D, which is 18 units away from C. Move to vertex D and mark it as visited.
Look for the closest neighboring vertex to D that has not been visited. In this case, the closest vertex is B, which is 15 units away from D. Move to vertex B and mark it as visited.
Look for the closest neighboring vertex to B that has not been visited. In this case, the closest vertex is E, which is 20 units away from B. Move to vertex E and mark it as visited.
Look for the closest neighboring vertex to E that has not been visited. In this case, the closest vertex is A, which is 24 units away from E. Move to vertex A and mark it as visited. All vertices have been visited, so the algorithm is complete.
The list of vertices visited, starting and ending at A, is A, B, C, D, B, E, A and the distance is 95.
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PLSSS HELP AND PLEASE SHOW WORK ASWELL
Collin has 100 feet of fencing to enclose a pen for his puppy. He is
trying to decide whether to make the pen
circular or square. He plans to use all of the
fencing.
Part A.) If Collin uses all of the fencing, what
would be the area of each pen? Use 3.14
for pie. Round to the nearest hundredth if
necessary.
Part B.) To have the largest possible area for the pen, which pen should Collin build?
Answer:
A.
circular: ≈ 795.77 square feet
square: 625
Step-by-step explanation:
the circular pen would have a larger area.
Solving for the radius, we have:
r = 100 / (2 × 3.14) = 15.92 feet (rounded to two decimal places)
Therefore, the area of the circular pen would be:
Area = πr^2 = 3.14 × (15.92 ft)^2 ≈ 795.77 square feet
For a square pen with side length s, the perimeter is given by:
4s = 100
s = 25
The area of a square pen with side length s is given by:
A = s^2 = 25^2 = 625
Find m/_U. Write your answer as an integer or as a decimal rounded to the nearest tenth.
The measure of angle U = 41.83 degree.
In the given right angle triangle
VW = 6
UV = 9
Since sinΘ = (opposite side)/(hypotenuse)
Therefore,
sin U = VW/UV
= 6/9
= 0.667
Take inverse of sin both sides
∠U = arcsin(0.667)
= 41.83
Hence ∠U = 41.83 degree
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Romero Company has a target capital structure that consists of $3.3 million of debt capital, $3.5 million of preferred stock financing, and $4.3 million of common equity. The corresponding weights of its debt, preferred stock, and common equity financing that should be used to compute its weighted cost of capital (rounded to the nearest wo decimal places) are:
The weights of the debt, preferred stock, and common equity financing are 28.6%, 30.4%, and 41.0%, respectively.
To calculate the weighted cost of capital (WACC), the proportion of each component of capital structure is needed. The weight of each component of the capital structure is determined by dividing the market value of the component by the total market value of all the components of the capital structure.
In this case, the total market value of the company's capital structure is the sum of the market value of debt, preferred stock, and common equity.
The weights for each component are calculated as follows:
Weight of debt = Market value of debt / Total market value of capital structure
= $3.3 million / ($3.3 million + $3.5 million + $4.3 million)
= 0.286 or 28.6%
Weight of preferred stock = Market value of preferred stock / Total market value of capital structure
= $3.5 million / ($3.3 million + $3.5 million + $4.3 million)
= 0.304 or 30.4%
Weight of common equity = Market value of common equity / Total market value of capital structure
= $4.3 million / ($3.3 million + $3.5 million + $4.3 million)
= 0.410 or 41.0%
These weights can be used to calculate the weighted cost of capital for Romero Company.
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Write the equation of a line perpendicular to y = −5/9x + 4 and that passes through point (-5,-4) in slope intercept form.
Answer: y = (9/5)x + 5.
Step-by-step explanation:
The slope of the given line is -5/9. The slope of a line perpendicular to it would be the negative reciprocal of -5/9, which is 9/5. Using the point-slope form of a line, we can write the equation of the line as y - (-4) = (9/5)(x - (-5)). Simplifying this equation gives y + 4 = (9/5)x + 9. Solving for y, we get y = (9/5)x + 5. This is the equation of the line in slope-intercept form.
In summary, the equation of a line perpendicular to y = −5/9x + 4 and that passes through point (-5,-4) is y = (9/5)x + 5.
At 10.30 a.m, a van left Town X travelling at an average speed of 64 Km/h.
At 11.15 a.m., a car left Town X, travelling on the same road at an average speed of
80 Km/h.
a) At what time did the car catch up with the van?
b) How far from Town X did each vehicle travel when they passed each other?
Answer:
a) 2:15 pm
b) 240 km
Step-by-step explanation:
You want to know the time and place where a car leaving at 11:15 a.m. at 80 km/h catches up with a van leaving at 10:30 a.m. at 64 km/h.
Head startThe van travels for 11:15 -10:30 = :45, or 3/4 hour, before the car starts. This gives it a distance advantage of (3/4 h)(64 km/h) = 48 km.
Closing speedThe speed at which that distance is reduced is the difference between the car speed and the van speed:
80 km/h -64 km/h = 16 km/h
Closing timeThe time it takes for the head-start distance to be reduced to zero is ...
time = distance/speed
time = (48 km)/(16 km/h) = 3 h
a) Meeting timeThree hours after the car leaves, it will catch up with the van. That time is ... 11:15 +3:00 = 14:15 = 2:15 p.m.
b) Meeting distanceIn 3 hours, the car travels (3 h)(80 km/h) = 240 km.
Note that the van has been traveling 3 3/4 hours, so will have also traveled (3 3/4 h)(64 km/h) = 240 km. The two vehicles need to be in the same place at the same time if they are to pass each other.
__
Additional comment
The attached graph shows the two vehicles will have traveled 240 km when they mean at 2:15 pm. The horizontal axis is hours after midnight. The vertical axis is kilometers from town X. The relation graphed is distance = speed × time.
uppose that you are told that the Taylor series of f(x)=x3ex2
about x=0
is
x3+x5+x72!+x93!+x114!+⋯.
Find each of the following:
ddx(x3ex2)∣∣∣x=0=
d7dx7(x3ex2)∣∣∣x=
a. Using Taylor series d(x³eˣ²)/dx about x = 0 is x⁴.
b. Using Taylor series d⁷(x³eˣ²)/dx⁷ about x = 0 is x¹⁰.
What is a Taylor series expansion?A Taylor series is a polynomial expansion of a function about a given point. It is given by f(x - a) = ∑(x - a)ⁿfⁿ(x - a)/n! where
a = point where f(x) is evaluated fⁿ(a) = nth derivative of f(x) about a and n is a positive integerGiven that the Taylor series of the function f(x) = x³eˣ² about x = 0 is
f(x) = x³ + x⁵ + x⁷/2! + x⁹/3! + x¹¹/4!, (1) we proceed to find the given variables
a. To find d( x³eˣ²)/dx about x = 0, the Taylor series expansion about x = 0 is given by
f(x - a) = ∑(x - a)ⁿfⁿ(a)/n!
f(x - 0) = ∑(x - 0)ⁿf(0)/n!
f(x) = ∑xⁿf(0)/n!
f(x) = x⁰f(x)/0! + xf(x)/1! + x²f(x)/2! + x³f(x)/3! + ....
f(x) = f(x) + xf¹(x) + x²f²(x)/2! + x³f³(x)/3! + ....(2)
Since fⁿ(x) is the nth derivative of f(x), and we desire f¹(x) which is the first derivative of f(x). Comparing equations (1) and (2), we have that
x⁵ = xf¹(x)
f¹(x) = x⁵/x
= x⁴
So, d( x³eˣ²)/dx about x = 0 is x⁴.
b. To find d⁷( x³eˣ²)/dx⁷ about x = 0, the Taylor series expansion about x = 0 is given by
f(x - a) = ∑(x - a)ⁿfⁿ(a)/n!
f(x - 0) = ∑(x - 0)ⁿf(0)/n!
f(x) = ∑xⁿf(0)/n!
f(x) = x⁰f(x)/0! + xf(x)/1! + x²f(x)/2! + x³f(x)/3! + ....
Expanding it up to the 8 th term, we have that
f(x) = f(x) + xf¹(x) + x²f²(x)/2! + x³f³(x)/3! + x⁴f⁴(x)/4! + x⁵f⁵(x)/5! + x⁶f⁶(x)/6! + x⁷f⁷(x)/7!.....(3)
Now expanding equation (1) above to the 8th term by following the pattern, we have that
f(x) = x³ + x⁵ + x⁷/2! + x⁹/3! + x¹¹/4! + x¹³/5! + x¹⁵/6! + x¹⁷/7!.....(4)
Since fⁿ(x) is the nth derivative of f(x), and we desire f⁷(x) which is the seventh derivative of f(x). Comparing equations (3) and (4), we have that
x⁷f⁷(x)/7! = x¹⁷/7!
f⁷(x) = x¹⁷/x⁷
= x¹⁰
So, d⁷( x³eˣ²)/dx⁷ about x = 0 is x¹⁰.
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Cami cut 17 1\2
inches off a rope that was 50 inches long. How is the length of the remaining rope in inches written in decimal form?
After Cami cut 17¹/₂ inches of a rope that was 50 inches long, the length of the remaining rope in inches, written in decimal form, is 32.5 inches.
How is the remaining length of the rope determined?To determine the remaining length of the rope, we apply subtraction operation.
However, since the cut rope was expressed in fractions, we can convert it to decimals before the subtraction.
The total length of the rope = 50 inches
The cut portion of the rope = 17¹/₂ inches
The remaining portion = 32¹/₂ inches or 32.5 inches (50 - 17¹/₂)
Thus, the remaining portion of the rope after Cami cut 17¹/₂ inches is 32.5 inches.
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y= +- 3/5 is equivalent to?
The equivalent value of the expression is y = + 3/5 and y = -3/5
Given data ,
Let the expression be represented as A
Now , the value of A is
y = ±3/5
On simplifying the equation , we get
y = +3/5
And, y = -3/5
Now , the decimal values of y are
y = ±0.6
Hence , the expression is y = ±0.6
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Find the measure of EB
The measure of angle subtended by the arc EB is 96 ⁰.
What is the measure of arc angle EB?The measure of angle subtended by the arc EB is calculated by applying the following formula.
Based on the angle of intersecting chord theorem, the theory states that, the angle formed by the intersection of two chords at the circumference of a circle is equal to half of the difference between the arc angles of the two chords.
We will have the following equation;
m∠ECB = ¹/₂( 7x + 6 - (4x + 16))
25 x 2 = 7x + 6 - 4x - 16
50 = 3x - 10
60 = 3x
x = 60/3
x = 20
The measure of arc angle EB is calculated as follows;
m∠EB = 4x + 16
m∠EB = 4(20) + 16
m∠EB = 96 ⁰
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Samantha gets paid $18.50 for each soccer game she referees. If she is a referee for 12 games and spends $59.99 for a new pair of cleats, how much money
does she have?
Answer:
$162.01
Step-by-step explanation:
amount of money she earns: 12($18.50) = $222
spends $59.99
amount of money after her purchase: $222-$59.99=$162.01
A card is drawn from a deck of 52 cards. What is the probability that it is a 3 or a spade?
Answer:
P = 4/13 = 0.308
Step-by-step explanation:
3 cards 3
13 spade cards (includes the card 3 of spades)
[tex]P=(3+13)/52= 16/52 = 4/13=0.308[/tex]
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Factor completely:
[tex] {5x}^{2} + 14x - 3[/tex]
Answer:
[tex]\Large \boxed{(5x - 1)(x + 3)}[/tex]
Step-by-step explanation:
To factor the expression [tex] {5x}^{2} + 14x - 3 [/tex], we need to find two numbers that multiply to give the coefficient of [tex] {x}^{2} [/tex] (which is 5)
And add up to give the coefficient of x (which is 14).
These two numbers are 5 and 3. We can then rewrite the expression as follows:
[tex]\boxed{{5x}^{2} + 14x - 3 = (5x - 1)(x + 3)}[/tex].
Therefore, the factored form of the expression is [tex](5x - 1)(x + 3)[/tex]
real-estate agent conducted an experiment to test the effect of selling a staged home vs. selling an empty home. To do so, the agent obtained a list of 10 comparable homes just listed for sale that were currently empty. He randomly assigned 5 of the homes to be "staged," meaning filled with nice furniture and decorated. The owners of the 5 homes all agreed to have their homes staged by professional decorators. The other 5 homes remained empty. The hypothesis is that empty homes are not as appealing to buyers as staged homes and, therefore, sell for lower prices than staged homes. The mean selling price of the 5 empty homes was $150,000 with a standard deviation of $22,000. The mean selling price of the 5 staged homes was $175,000 with a standard deviation of 35,000. A dotplot of each sample shows no strong skewness and no outliers.
Real-estate agent tested the effect of staging on home sale prices. Out of 10 comparable homes, 5 were staged. Staged homes sold for $15k more on average, with no skewness or outliers.
Based on the information given, the real-estate agent conducted an experiment to test the effect of selling a staged home vs. selling an empty home.
The hypothesis is that empty homes sell for lower prices than staged homes. The agent randomly assigned 5 empty homes to be staged and obtained a list of 10 comparable homes.
The mean selling price of the 5 empty homes was $150,000 with a standard deviation of $22,000. The mean selling price of the 5 staged homes was $175,000 with a standard deviation of 35,000. There was no strong skewness or outliers in the dot plots of the two samples.
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y + 6 < 10 or 2y - 3> 9
Answer:
2y - 3> 9 it is not y + 6< 10
A bug crawls 5 1/2 feet in 28.6 seconds. At that pace, how many seconds does it take the bug to crawl one foot?
Answer:
5.2 seconds
Step-by-step explanation:
To get one foot, we need to divide by 5.5
Set up a proportion:
[tex]\frac{5.5}{5.5}=\frac{28.6}{5.5}[/tex]
Solve:
[tex]1ft.=5.2secs.[/tex]