If P(A)=0.4, P(A and B)=0.2,and P(A or B)=0.5, What is P(B)

Answer:

B and G

Step-by-step explanation:

Square and rectangle

Step-by-step explanation:

[tex]y = {x}^{2} - 18 \\ y + 18 = {x}^{2} \\ square \: root \: both \: sides \: \\ \sqrt{y + 18} = \sqrt{ {x}^{2} } [/tex]

[tex]x = \sqrt{y + 18} [/tex]

Answer:

√y + 18 = x

Step-by-step explanation:

Let us solve it now.

y = x² - 18

Take -18 to the left side

y + 18 = x²

Now remove the square of x

√y + 18 = x

Step-by-step explanation:

x and x+2 are the numbers

x(x+2)=143

x²+2x-143=0

x²+13x-11x-143=0

x(x+13)- 11(x+13)=0

(x+13). (x-11)=0

x+13=0. x=-13

x-11=0. x=11

Answer: V=4778.4 cm³

Step-by-step explanation:

[tex]V=\pi r^2\frac{h}{3}[/tex] is the formula for volume. Since we are given the height and radius, we can directly plug it into the equation

[tex]V=\pi (13)^2(\frac{27}{3})[/tex]

[tex]V=169\pi (9)[/tex]

[tex]V=1521\pi[/tex]

[tex]V=4778.4cm^3[/tex]

Answer:

(a) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 23%    

    Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] [tex]\neq[/tex] 23%

(b) We conclude that the mean percentage is  different from 23 and the manufacturing process will be re-calibrated.

(c) P-value is 0.6%.

Step-by-step explanation:

We are given that a certain manufactured product is supposed to contain 23% potassium by weight.

A sample of 10 specimens of this product had an average percentage of 23.2 with a standard deviation of 0.2.

Let [tex]\mu[/tex] = mean percentage of potassium by weight.

(a) Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 23%      {means that the mean percentage is equal to 23 and the manufacturing process will not be re-calibrated}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] [tex]\neq[/tex] 23%     {means that the mean percentage is  different from 23 and the manufacturing process will be re-calibrated}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

                                T.S. =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean percentage = 23.2

            s = sample standard deviation = 0.2

            n = sample of specimens = 10

So, the test statistics  =  [tex]\frac{23.2-23}{\frac{0.2}{\sqrt{10} } }[/tex]  ~ [tex]t_9[/tex]

                                     =  3.162

The value of t test statistic is 3.162.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical value of -2.262 and 2.262 at 9 degree of freedom for two-tailed test.

(b) Since our test statistic doesn't lie within the range of critical values of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean percentage is  different from 23 and the manufacturing process will be re-calibrated.

(c) The P-value of the test statistics is given by;

            P-value = P( [tex]t_9[/tex] > 3.162) = 0.006 or 0.6%

(a) Null Hypothesis,  [tex]H_o:\mu[/tex]: = 23%    

   Alternate Hypothesis, [tex]H_A:\mu\neq[/tex] : 23%

(b) We conclude that the mean percentage is  different from 23 and the manufacturing process will be re-calibrated.

(c) P-value is 0.6%.

The hypothesis that there is no significant difference between specified populations, any observed difference being due to sampling or experimental error.

We are given that a certain manufactured product is supposed to contain 23% potassium by weight.

A sample of 10 specimens of this product had an average percentage of 23.2 with a standard deviation of 0.2.

Let  = mean percentage of potassium by weight.

(a) Null Hypothesis, [tex]H_o:\mu[/tex]:  = 23%      {means that the mean percentage is equal to 23 and the manufacturing process will not be re-calibrated}

Alternate Hypothesis,  [tex]H_A:\mu\neq[/tex]:   23%     {means that the mean percentage is  different from 23 and the manufacturing process will be re-calibrated}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

[tex]TS=\dfrac{X-\mu}{\frac{s}{\sqrt{n}}}[/tex]   ~ [tex]t_{n-1}[/tex]

where,  = sample mean percentage = 23.2

           s = sample standard deviation = 0.2

           n = sample of specimens = 10

So, the test statistics  =   [tex]\dfrac{23.2-23}{\frac{0.2}{\sqrt{10}}}[/tex] ~ [tex]t_g[/tex]

                                    =  3.162

The value of t test statistic is 3.162.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical value of -2.262 and 2.262 at 9 degree of freedom for two-tailed test.

(b) Since our test statistic doesn't lie within the range of critical values of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean percentage is  different from 23 and the manufacturing process will be re-calibrated.

(c) The P-value of the test statistics is given by;

           P-value = P( [tex]t_g[/tex] > 3.162) = 0.006 or 0.6%

Hence ,

(a) Null Hypothesis,  [tex]H_o:\mu[/tex]: = 23%    

   Alternate Hypothesis, [tex]H_A:\mu\neq[/tex] : 23%

(b) We conclude that the mean percentage is  different from 23 and the manufacturing process will be re-calibrated.

(c) P-value is 0.6%.

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Answer:

2000

Step-by-step explanation:

2500 / 100 = 25 (1%)

25 X 20 =500 (20%)

2500 - 500 =2000

Answer:

5x^3(to the power of 3)

Step-by-step explanation:

10x^5/2x^2

divide the 10/2 like normal to get 5

x^5/x^2 (subtract the powers 5-2 when dividing powers)

you would get 5x^3

Answer:

2

Step-by-step explanation:

the vertical axis would be h, the plant's height, and the horizontal axis would be m, the number of months. This would make statement 2 the only valid statement.

statement 1: Incorrect, as the vertical axis is the height

statement 2: correct, as h depends on m

statement 3: incorrect, as the domain is the horizontal and represents the number of months

statement 4: incorrect, as h = f(m)

Answer:

[tex] f(x+h) = 3(x+h)^2 +(x+h) +2= 3(x^2 +2xh+h^2) +x+h+2[/tex]

[tex]f(x+h) = 3x^2 +6xh +3h^2 +x+h+2= 3x^2 +6xh +x+h+ 3h^2 +2[/tex]

And replacing we got:

[tex] lim_{h \to 0} \frac{3x^2 +6xh +x+h+ 3h^2 +2 -3x^2 -x-2}{h}[/tex]

And if we simplfy we got:

[tex] lim_{h \to 0} \frac{6xh +h+ 3h^2 }{h} =lim_{h \to 0} 6x + 1 +3h [/tex]

And replacing we got:

[tex]lim_{h \to 0} 6x + 1 +3h = 6x+1[/tex]

And the bet option would be:

C. 6x + 1

Step-by-step explanation:

We have the following function given:

[tex] f(x) = 3x^2 +x+2[/tex]

And we want to find this limit:

[tex] lim_{h \to 0} \frac{f(x+h) -f(x)}{h}[/tex]

We can begin finding:

[tex] f(x+h) = 3(x+h)^2 +(x+h) +2= 3(x^2 +2xh+h^2) +x+h+2[/tex]

[tex]f(x+h) = 3x^2 +6xh +3h^2 +x+h+2= 3x^2 +6xh +x+h+ 3h^2 +2[/tex]

And replacing we got:

[tex] lim_{h \to 0} \frac{3x^2 +6xh +x+h+ 3h^2 +2 -3x^2 -x-2}{h}[/tex]

And if we simplfy we got:

[tex] lim_{h \to 0} \frac{6xh +h+ 3h^2 }{h} =lim_{h \to 0} 6x + 1 +3h [/tex]

And replacing we got:

[tex]lim_{h \to 0} 6x + 1 +3h = 6x+1[/tex]

And the bet option would be:

C. 6x + 1

Answer:

6x+1

Step-by-step explanation:

Plato :)

Answer:

DIDNT UNDERSTAND THE QUESTION PROPERLY BRO..

KEEP THE QUESTION AGAIN

Answer:

10,080 different ways that the letters of "misspell" can be arranged.

Step-by-step explanation:

Number of arrangents of the letters of a word:

A word has n letters.

The are m repeating letters, each of them repeating [tex]r_{0}, r_{1}, ..., r_{m}[/tex] times

So the number of distincts ways the letters can be arranged is:

[tex]N_{A} = \frac{n!}{r_{1}! \times r_{2}! \times ... \times r_{m}}[/tex]

In this question:

Misspell has 8 letters, with s and l repeating twice.

So

[tex]N_{A} = \frac{8!}{2!2!} = 10080[/tex]

10,080 different ways that the letters of "misspell" can be arranged.

Answer:

q = 0.5 quarts of 100% antifreeze

Step-by-step explanation:

q = quarts of pure antifreeze

Set this up as a weighted combination of the mixtures.

(100%)(q) + (10%)(4) = (20%)(q + 4)

100q + 40 = 20(q + 4)

5q + 2 = q + 4

4q = 2

q = 0.5 quarts of 100% antifreeze

Answer:

it is the mode.

Step-by-step explanation:

i. e 5 is the most occuring number in the set of data listed above

Answer:

No, the events are not mutually exclusive because they share the common outcomes of the student working and playing volleyball on certain days.

Step-by-step explanation:

A and B are mutually exclusive events if they cannot occur at the same time. This means that A and B do not share any outcomes and P(A AND B)=0.

In this case, A and B have outcomes in common since the student both works and plays volleyball on Tuesdays and Thursdays. Thus, the events are not mutually exclusive.  

Answer:

c

Step-by-step explanation:

Answer:

[tex]9.5[/tex]

Step-by-step explanation:

[tex]\sqrt{64}+\frac{6}{-2\left(-2\right)}[/tex]

[tex]\sqrt{64}+\frac{6}{2 \times 2}[/tex]

[tex]8+\frac{6}{4}[/tex]

[tex]\frac{19}{2}[/tex]

[tex]=9.5[/tex]

Answer:

Hello!

I hope that this is the answer you are looking for

=8.09320

That is the rounded answer.

I hope that helped you!

Step-by-step explanation:

Answer:

y = 12 + 6x

y = 12x

Step-by-step explanation:

From the information provided, the following equations are derived:

y = 12 + 6x    ------- Eqn 1

y = 12x          ------- Eqn 2

Since Eqns 1 and 2 have the same subject, we equate them to solve for x. We have:

12x = 12 + 6x

Putting like terms together, we have:

12x - 6x = 12 ⇒ (12 - 6)x = 12

6x = 12 ⇒ x = 2

x = 2

Substitute x into Eqn 1 or 2

Eqn 1

y = 12 + 6x

y = 12 + 6(2) = 12 + 12

y = 24

Eqn 2

y = 12x

y = 12(2)

y = 24

It means that it will take Ms. Ironperson and Mr. Thoro 2 days apiece to produce the same number of posters at the current rate (which is 24 posters). Both Ms. Ironperson and Mr. Thoro will individually take 2 days to produce 24 Avenger posters apiece.

Answer: It’s to change the shape of a function

Step-by-step explanation:

To change the shape of a function, you need to stretch or compress it.

In math terms, you can stretch or compress a function horizontally by multiplying x by some number before any other operations. To stretch the function, multiply by a fraction between 0 and 1. To compress the function, multiply by some number greater than 1.

By definition, a function has one possible output for any given input. So if you want your function defined as some y=f(x), then not every shape can be written as a function. Any shape that has two points directly above each other (relative to the x-axis) cannot be written as a function, even a piecewise one.

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Answer:

5

Step-by-step explanation:

Since this is a right triangle we can use trig functions

sin theta = opp /hyp

sin 30 = x / 10

10 sin 30 = x

10 * 1/2 = x

5 =x

Answer:

£135 is the correct answer.

Step-by-step explanation:

Let C be the cost of table.

And let R be the radius of table.

Cost of table is directly proportional to square of radius.

As per question statement:

[tex]C\propto R^{2}[/tex] or

[tex]C=a\times R^2 ....... (1)[/tex]

where [tex]a[/tex] is the constant to remove the [tex]\propto sign[/tex].

It is given that

[tex]C_1 =[/tex] £60 and [tex]R_1 = 50\ cm[/tex]

[tex]C_2 = ?[/tex] when [tex]R_2= 75\ cm[/tex]

Putting the values of [tex]C_1[/tex] and [tex]R_1[/tex] in equation (1):

[tex]60=a \times 50^2 ....... (2)[/tex]

Putting the values of [tex]C_2[/tex] and [tex]R_2[/tex] in equation (1):

[tex]C_2=a \times 75^2 ....... (3)[/tex]

Dividing equation (2) by (3):

[tex]\dfrac{60}{C_2}= \dfrac{a \times 50^2}{a \times 75^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{50^2}{75^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{2^2}{3^2}\\\Rightarrow \dfrac{60}{C_2}= \dfrac{4}{9}\\\Rightarrow C_2 = 15 \times 9 \\\Rightarrow C_2 = 135[/tex]

So, £135 is the correct answer.

Answer:

9

Equivalent Fractions with the LCD

4 7/9 = 43/9

2 2/3 = 24/9

For the denominators (9, 3) the least common multiple (LCM) is 9.

Therefore, the least common denominator (LCD) is 9.

4 7/9 = 43/9 × 1/1 = 43/9

2 2/3 = 8/3 × 3/3 = 24/9

Hope this helps :)

The least common denominator of 4 7/9 and 2 2/3 is 9.

Given data:

To find the least common denominator (LCD) of 4 7/9 and 2 2/3, we need to first convert both fractions to their equivalent forms with a common denominator.

The given fractions are:

4 7/9 = 4 + 7/9

2 2/3 = 2 + 2/3

To find a common denominator, we need to find the least common multiple (LCM) of the denominators 9 and 3, which is 9.

Now, let's convert the fractions to their equivalent forms with a denominator of 9:

4 7/9 = (4 * 9)/9 + (7/9) = 36/9 + 7/9 = 43/9

2 2/3 = (2 * 9)/9 + (2/3) = 18/9 + 2/3 = 20/9

The fractions 4 7/9 and 2 2/3 are now expressed with a common denominator of 9.

Hence, the least common denominator (LCD) of 4 7/9 and 2 2/3 is 9.

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Answer:

Hello!

I believe this is what you are looking for:

x=3

33=27

32=9

S=Surface area

V=Volume

L=Length

R=Radius

I hope this helped.  If not, please let me know.  I will try my best again. :)

Step-by-step explanation:

Answer:

x = ±5

Step-by-step explanation:

x^2 – 9 = 16

Add 9 to each side

x^2 – 9+9 = 16+9

x^2 = 25

Take the square root of each side

sqrt(x^2) = ±sqrt(25)

x = ±5

Answer:

[tex]x = 5 \: \: \: or \: \: x = - 5[/tex]

Step-by-step explanation:

[tex] {x}^{2} - 9 = 16 \\ {x}^{2} = 16 + 9 \\ {x}^{2} = 25 \\ x = \sqrt{25} \\ x = 5 \\ x = - 5[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

Between 0.01 and 0.20

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

In this problem, we have that:

[tex]n = 500, p = 0.05[/tex]

So

[tex]\mu = E(X) = np = 500*0.05 = 25[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{500*0.05*0.95} = 4.8734/tex]

Find the probability of winning at least 30 times.

Using continuity correction, this is [tex]P(X \geq 30 - 0.5) = P(X \geq 29.5)[/tex]. So this is 1 subtracted by the pvalue of Z when X = 29.5. Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{29.5 - 25}{4.8734}[/tex]

[tex]Z = 0.92[/tex]

[tex]Z = 0.92[/tex] has a pvalue of 0.8212

1 - 0.8212 = 0.1788

So the correct option is:

Between 0.01 and 0.20

Answer:

An equation is basically a way to show a relationship of variables (x,y,a,b, etc) and numbers.

Step-by-step explanation:

Answer:

Shown by explanation.

Step-by-step explanation:

An equation shows a relationship between variables and other factors by defining the variables that are dependent and independent and how these dependent variables are related to the independent variables, this is usually as a result of a prescribed experiment where the relationship of this variables are investigated.

Also remember conditions that favour this experiment must be taken into consideration. And the experiment must always be performed under such conditions.

Answer:

work is shown and pictured

Answer: x<3

Step-by-step explanation:

Answer:

1.54

Margin of error M.E = 1.54

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

x+/-M.E

Where M.E = margin of error

M.E = zr/√n

Given that

Standard deviation r = 1.93

Number of samples n = 6

Confidence interval = 95%

z(at 95% confidence) = 1.96

Substituting the values we have;

M.E = (1.96×1.93/√6) = 1.544321633166

M.E = 1.54 (to 2 decimal place)

Margin of error M.E = 1.54

Answer:

170m

Step-by-step explanation:

The answer to the above question is letter d which is 170 m. To get the 170 m, kindly check the below solution: 

x^2 + 13x = 1764 so x = -49 and 36, we take 36 as its the positive value. And the other side is 49. Now use 2(l+b) to find perimeter. You get (36+49)*2 = 170

Answer:

Step-by-step explanation:

Null hypothesis: u = 10

Alternative hypothesis: u =/ 10

Using the formula: t = (x - u) / (s /√n)

Where x = 12, u = 10, s = 5 and n = 25

t= (12-10) / (5/√25)

t = (2)/(5/5)

t = 2/1= 2

t = 2.0

At a 0.01 level of significance with a degree of freedom of 24, the p-value is 0.0569, which is greater than 0.01 we will fail to reject the null and conclude that parents do not read more than the average number of books to their children

Answer:

C

Step-by-step explanation:

-8 14 = 42 (He subtracted 14 from 42)

-8p = 28 (Which is how he got 28)

p = -3.5 (He took 28 divide by -8 which got him -3.5)

Answer:

C

Step-by-step explanation:

C