Answer:PAST she studied
Present: she walks home, they leave the door open, I walked home, he made a list.
Future: It will open next week, she will walk home.
Explation:Its obvious
A 100-g block slides back and forth on a frictionless surface between two springs, as shown in Fig. 7.18. The left-hand spring has k = 110 N/m and its maximum compression is 21 cm.The right-hand spring has
k = 240 N/m. Find (a) the maximum compression of the right-hand spring and (b) the speed of the block as it moves between the springs.
(a) Energy is conserved at every point in the block's motion, so the potential energy P stored in the first spring at its maximum compression is the same as is stored in the second spring.
The total work performed on the block by the first spring is
W = -1/2 (110 N/m) (0.21 m²) = -2.4255 J
The work performed by the second spring is the same, so
W = -1/2 (240 N/m) x²
Solve for x :
x² = -2W/(240 N/m) = 0.0202125 m²
x ≈ 0.14 m = 14 cm
(b) By the work-energy theorem, the total work performed by either spring on the block as the spring is compressed is equal to the change in the block's kinetic energy. The restoring force of the spring is the only force involved. At maximum compression, the block has zero velocity, while its kinetic energy and hence speed is maximum just as it comes into contact with either spring.
W = 0 - K
W = -1/2 (0.10 kg) v²
v² = -2W/(0.10 kg) = 48.51 m²/s²
v ≈ 7.0 m/s
How much force is required to swing a 3 kg mass in a circle with a radius of 1.5 m at a speed of 5 m/s?
The force that is required to swing the mass is 50 Newton.
Given the following data:
Mass = 3 kgRadius = 1.5 metersSpeed = 5 m/sTo find the amount of force that is required to swing the mass, we would use centripetal force formula:
Mathematically, centripetal force is given by the formula:
[tex]F_c = \frac{mv^2}{r}[/tex]
Where:
m is the mass.v is the speed.r is the radius.Substituting the parameters into the formula, we have;
[tex]F_c = \frac{3 \times 5^2}{1.5}\\\\F_c = \frac{3 \times 25}{1.5}\\\\F_c = \frac{75}{1.5}\\\\F_c = 50[/tex]
Centripetal force = 50 Newton
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A 0.25 kg ball is suspended from a light 0.65 m string as shown. The string makes an angle of 31° with the vertical. Let U = 0 when the ball is at its lowest point (θ = 0).
a) What is the gravitational potential energy, in joules, of the ball before it is released?
b) What will be the speed of the ball, in meters per second, when it reaches the bottom?
Explanation:
a) The height of the ball h with respect to the reference line is
[tex]h = L - L\cos{31°} = L(1 - \cos{31°})[/tex]
so its initial gravitational potential energy [tex]U_0[/tex] is
[tex]U = mgh = mgL(1 - \cos{31°})[/tex]
[tex]\:\:\:\:\:=(0.25\:\text{kg})(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31})[/tex]
[tex]\:\:\:\:\:=0.23\:\text{J}[/tex]
b) To find the speed of the ball at the reference point, let's use the conservation law of energy:
[tex]\Delta{K} + \Delta{U} = 0 \Rightarrow K_0 + U_0 = K + U[/tex]
We know that the initial kinetic energy [tex]K_0,[/tex] as well as its final gravitational potential energy [tex]U[/tex] are zero so we can write the conservation law as
[tex]mgL(1 - \cos{31°}) = \frac{1}{2}mv^2[/tex]
Note that the mass gets cancelled out and then we solve for the velocity v as
[tex]v = \sqrt{2gL(1 - \cos{31°})}[/tex]
[tex]\:\:\:\:\:= \sqrt{2(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31°})}[/tex]
[tex]\:\:\:\:\:= 1.3\:\text{m/s}[/tex]
Answer:
a. 0.23J
b. 1.35 m/s
Explanation:
a. U = mgh where where m = mass of the object, g = acceleration due to gravity, and h = height
h = L - Lcos(θ) where L = length of the rope, and θ = angle with respect to vertical.
Therefore, U = mg(L - Lcos(θ))
U = 0.25 * 9.8 (0.65m - 0.65cos(31° ))
U = 0.2275 ≈ 0.23J
The gravitational potential energy of the ball before it is released = 0.23J
b. To determine the velocity of the object at the bottom of its motion, all of the energy has gone from gravitational potential into kinetic since at the bottom, the problem says that U = 0. The kinetic energy of an object is given by the following equation:
[tex]K.E=\frac{I}{2}*mv^{2}[/tex]
where m = mass of the object and v = velocity of the object. Since we know that all of the energy was transferred into kinetic energy at the bottom, we can conclude that:
[tex]0.2275=\frac{1}{2} *0.25*v^{2}[/tex]
[tex]v^{2}=\frac{2*0.2275}{0.25}[/tex]
[tex]v^{2}=1.82[/tex]
[tex]v=\sqrt{1.82}=1.3491\\[/tex] ≈ [tex]1.35m/s[/tex]
Therefore, the speed of the ball when it reaches the bottom = 1.35m/s
He drives 150 meters in 18 seconds. Assuming constant speed, what is his speed in meters per second?
Answer:
Explanation:
Givens
d = 150 meters
t = 18 seconds
r (rate) = ?
Formula
r = d/t
Solution
r = 150/18
r = 8.33 m/s
A trapeze artist performs an aerial maneuver. While in a tucked position, as shown in figure A, she rotates about her center of mass at a rate of 6.27 rad/s. Her moment of inertia about this axis is 17.9 kg⋅m2. A short time later, the aerialist is in the straight position, as shown in figure B. If the moment of inertia about her center of mass in this position is now 33.1 kg⋅m2, what is her rotational speed in revolutions per minute (rpm)?
The rotational speed of the trapeze artist is 32.372 revolutions per second.
In this question we should apply the principle of angular momentum conservation to determine the final angular speed of the trapeze artist, since there are no external forces acting on the trapeze artist:
[tex]I_{A}\cdot \omega_{A} = I_{B}\cdot \omega_{B}[/tex] (1)
Where:
[tex]I_{A}[/tex], [tex]I_{B}[/tex] - Initial and final moments of the trapeze artist, in kilograms-square meter.
[tex]\omega_{A}[/tex], [tex]\omega_{B}[/tex] - Initial and final angular speeds, in radians per second.
If we know that [tex]I_{A} = 17.9\,kg\cdot m^{2}[/tex], [tex]I_{B} = 33.1\,kg\cdot m^{2}[/tex] and [tex]\omega_{A} = 6.27\,\frac{rad}{s}[/tex], then the final angular speed is:
[tex]\omega_{B} = \frac{I_{A}}{I_{B}}\times \omega_{A}[/tex]
[tex]\omega_{B} = \frac{17.9\,kg\cdot m^{3}}{33.1\,kg\cdot m^{2}}\times 6.27\,\frac{rad}{s}[/tex]
[tex]\omega_{B} = 3.390\,\frac{rad}{s}[/tex] ([tex]32.372\,rpm[/tex])
The rotational speed of the trapeze artist is 32.372 revolutions per second.
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What is the gravitational potential energy of a circus performer with a mass of 50 kg walking on a tightrope 10 m above the ground
Answer:
5000 J
Explanation:
GPE = mgh
50*10*10
= 5000 J
The gravitational potential energy of the circus performer walking on the tightrope above the ground is 4900J.
Given the data in the question;
Mass of circus performer; [tex]m = 50kg[/tex]Distance from ground level; [tex]h = 10m[/tex]Gravitational potential energy; [tex]U = ?[/tex]Gravitational Potential EnergyGravitational potential energy is simply the potential energy an object possesses relative to another object due to gravity.
It is expressed as;
[tex]U = mgh[/tex]
Where m is mass, h is height or distance from the other massive object and g is the gravitational field ( [tex]g = 9.8m/s^2[/tex] )
To determine the gravitational potential energy of circus performer, we substitute our values into the expression above.
[tex]U = mgh\\\\U = 50kg\ *\ 9.8m/s^2\ *\ 10m\\\\U = 4900kgm^2/s^2\\\\U = 4900J[/tex]
Therefore, the gravitational potential energy of the circus performer walking on the tightrope above the ground is 4900J.
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9) How many valence electrons does this atom have?
A.2
B. 3
C.8
D. 13
Answer:
I think it's 2
Explanation:
Within each column, or group, of the table, all the elements have the same number of valence electrons. This explains why all the elements in the same group have very similar chemical properties. For elements in groups 1–2 and 13–18, the number of valence electrons is easy to tell directly from the periodic table.
Sin is the ____________________________ of the law. 1 John 3:4.
Answer:
transgression
Explanation:
what is the magnitude of its velocity just before it strikes the ground, if the bottle was thrown straight out horizontally from the tower with a speed of 11.8 m/s?
There's not enough given information to find the answer.
The horizontal velocity has no effect on anything that happens vertically. To find the object's vertical speed when it hits the ground, we need to know what height it was dropped from, and that's not given in the question.
Since the bottle is falling vertically, the vertical displacement s is the height of the tower from which it was thrown.
If a bottle is thrown horizontally from a tower, its initial vertical velocity is 0 m/s since there is no vertical component to its initial velocity. The only force acting on the bottle in the vertical direction is gravity, which causes it to accelerate downward at a rate of approximately 9.81 m/s² (assuming Earth's gravity).
Since the initial vertical velocity is 0 m/s and the acceleration is 9.81 m/s², you can use the following kinematic equation to find the magnitude of its velocity just before it strikes the ground:
v2=u2+2as
Where:
v is the final vertical velocity (which we're trying to find)
u is the initial vertical velocity (0 m/s)
a is the acceleration due to gravity (-9.81 m/s², negative because it's acting downward)
s is the vertical displacement (which is the height of the tower)
Since the bottle is falling vertically, the vertical displacement
s is the height of the tower from which it was thrown.
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A constant force of 8.0 N is exerted for 4.0 s on a 16-kg object initially at rest. The change in speed of this object will be:
The change in speed of this object is 3m/s
According to Newton's second law;
F = ma
F = mv/t
Given the following parameters
Force F = 8.0N
mass m = 16kg
time t = 4.0s
Required
speed v
Substitute the given parameters into the formula
v = Ft/m
v = 8 * 6/16
v = 48/16
v = 3m/s
Hence the change in speed of this object is 3m/s
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Select all of the following that are involved in translation:
amino acids
tRNA
mRNA
ribonucleotides
deoxyribonucleotides
RNA Polymerase
Answer:
Amino Acids
tRNA
mRNA
ribonucleotides
Explanation:
Amino Acids
- During translation, an mRNA sequence is read using the genetic code, which is a set of rules that defines how an mRNA sequence is to be translated into the 20-letter code of amino acids, which are the building blocks of proteins.
tRNA
- At the beginning of translation, the ribosome and a tRNA attach to the mRNA. The tRNA is located in the ribosome's first docking site. This tRNA's anticodon is complementary to the mRNA's initiation codon, where translation starts. The tRNA carries the amino acid that corresponds to that codon. ransfer ribonucleic acid (tRNA) is a type of RNA molecule that helps decode a messenger RNA (mRNA) sequence into a protein. tRNAs function at specific sites in the ribosome during translation, which is a process that synthesizes a protein from an mRNA molecule.
mRNA
- Translation is the process by which a protein is synthesized from the information contained in a molecule of messenger RNA (mRNA). ... Then a transfer RNA (tRNA) molecule carrying the amino acid methionine binds to what is called the start codon of the mRNA sequence.
ribonucleotides
- During transcription, a ribonucleotide complementary to the DNA template strand is added to the growing RNA strand and a covalent phosphodiester bond is formed by dehydration synthesis between the new nucleotide and the last one added.
A person walks 32∘ north of west for 94m and 35∘ east of south for 122m. What is the magnitude of his displacement?
Answer:
n
Explanation:
Một xe có khối lượng 20000kg chuyển động dần đều dưới tác dụng của lực 600N,vận tốc ban đầu của xe bằng 15m/s.hỏi :
a,gia tốc của xe
b,sau bao lâu xe dừng lại
c,đoạn đường xe đã chạy được kể từ lúc hàm cho đến khi dừng hẳn.
Answer:
please vote and heart please and follow me because I have no followers yet
The weight of the atmosphere above 1 m- of
Earth's surface is about 100.000 Ņ. Density, of
course, becomes less with altitudd- But suppose
the density of air were a constant 1.2 kg/m?
Answer:
1.09 kg.m
Explanation:
no need
Thermal is to heat as ___ is to water.
drain
waste
dilute
absorb
Answer:Thermal is to heat as absorb is to water.
Explanation:
Water is able to absorb heat - without increasing much in temperature - better than many substances. This is because for water to increase in temperature, water molecules must be made to move faster within the water; this requires breaking hydrogen bonds, and the breaking of hydrogen bonds absorbs heat.
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In the circuit, the capacitor is fully charged when switch is closed. Calculate the time needed for the potential energy stored by the circuit to be equally distributed between the capacitor and inductor. The capacitance is =20.0 mF and inductance is =45.0 H .
We have that for the Question "In the circuit, the capacitor is fully charged when switch is closed. Calculate the time needed for the potential energy stored by the circuit to be equally distributed between the capacitor and inductor. The capacitance is =20.0 mF and inductance is =45.0 H ." it can be said that the time required is
[tex]T=0.745s[/tex]From the question we are told
In the circuit, the capacitor is fully charged when switch is closed. Calculate the time needed for the potential energy stored by the circuit to be equally distributed between the capacitor and inductor. The capacitance is =20.0 mF and inductance is =45.0 H .
Generally the equation for the Time is mathematically given as
[tex]T=\sqrt{LC}*\frac{\pi}{4}[/tex]
[tex]T=\sqrt{20*10^{-3}*45}*\frac{\pi}{4}[/tex]
[tex]T=0.745s[/tex]
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during the spin cycle of a washing machine the cloth stick to the outer wall of the barrel as it spins at a speed of 65 m per second. the radius of the barrel is 0.35 m. what is the magnitude and direction of centripetal acceleration of the clothes which are located on the wall of the barrel
Hi there!
Centripetal acceleration can be written as:
[tex]a_c = \frac{v^2}{r}[/tex]
v = tangential velocity (m/s)
r = radius (m)
Plug in the given values:
[tex]a_c = \frac{65^2}{0.35} = \boxed{12071.43 \text{ m}/s^2}}}[/tex]
The centripetal acceleration vector ALWAYS points towards the CENTER POINT of the barrel.
The Israelites grumbled 11 times against God. True or False?
Answer:
This is not a question about physics.
Anyway. Eleven times seems underrated.
Answer:
True
Explanation:
Because they didn't always appreciate the work of God
The LANDSAT C Earth resources satellite has a nearly circular orbit with an eccentricity of 0.00132. At perigee the satellite is at an altitude (measured from the earth's surface) of 417km. a) Calculate its altitude at apogee. b) Calculate its period. c) Calculate the velocity at perigee.
We have that for the Question it can be said that
altitude at apogee = [tex]434.96km[/tex]period = [tex]5585.41s[/tex]velocity at perigee = [tex]7.67km/s[/tex]From the question we are told
The LANDSAT C Earth resources satellite has a nearly circular orbit with an eccentricity of 0.00132. At perigee the satellite is at an altitude (measured from the earth's surface) of 417km.
Generally the equation for perigee radius is mathematically given as
[tex]r_p = R_E+Z_P\\\\=6378+417\\\\=6795km[/tex]
the equation for orbit is
[tex]r_p = \frac{h^2}{u}*\frac{1}{1+e}\\\\6795 = \frac{h^2}{398600}*\frac{1}{1+0.00132}\\\\h = 52077.5km^2/s[/tex]
the equation for velocity at perigee is mathematically given as
[tex]V_p = \frac{h}{r_p}\\\\= \frac{52077.5}{67.95}\\\\=7.67km/s[/tex]
the equation for Apagee radius is mathematically given as
[tex]r_a = \frac{h^2}{u} * \frac{1}{1-e}\\\\= \frac{52077.5^2}{398600} * \frac{1}{1-0.00132}\\\\= 6812.97km[/tex]
the equation for altitude at Apagee is mathematically given as
[tex]Z_a = r_a - R_E\\\\=6812.97-6378\\\\=434.96km[/tex]
the equation for period
[tex]Period T = \frac{2\pi}{u^2} * (\frac{h}{\sqrt1-e^2})^3\\\\= \frac{2\pi}{398600^2} * (\frac{52077.5}{\sqrt1-0.00132^2})^3\\\\= 5585.41s[/tex]
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9. Two spheres, one of mass 4.0 x 107 kg and the other of mass 8.0 x 107 kg are separated by a
distance of 400.0 m. The force of gravity between them is
a) 1.3 N b) 530 N c) 1.8 x 104 N
d) 5.1 x 1021 N
e) 5.3 x 1022 N
Hi there!
We can use the gravitational force equation:
[tex]F_g = \frac{Gm_1m_2}{r^2}[/tex]
Where:
G = Gravitational Constant
m₁ = mass of one sphere (kg)
m₂ = mass of the other sphere (kg)
r = distance between the spheres (m)
Plug in the given values into the equation:
[tex]F_g = \frac{(6.67*10^{-11})(4.0*10^7)(8.0*10^7)}{400^2} = \boxed{1.334 N}[/tex]
Thus, the correct answer is A.
Why do heavier objects roll down slopes faster than lighter objects? (Assuming they are the same shape)
Answer:
because of the friction against the object
Explanation:
The first bag you load into your vehicle from the pick-stage cart is the first bag you need to open on your route.
The given statement is false because the first bag you load into the vehicle will be at the bottom during the trip.
During a pick-stage cart, the first bad you load into the vehicle is always placed on the bottom, while subsequent bags are arranged on top of the first bag, all inside the vehicle.
At any point on your route, any bad you tend to open becomes the last bag you load into the vehicle because the first bag is far below the bottom.
Thus, we can conclude that the given statement is false because the first bag you load into the vehicle will be at the bottom during the trip.
"Your question is not complete, it seems to be missing the following information";
The first bag you load into your vehicle from the pick-stage cart is the first bag you need to open on your route. False/True
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An object of mass is used to provide tension in a 6.0 ‑m‑long string that has a mass of 0.252 kg, as shown. A standing wave that has a wavelength equal to 1.5 m is produced by a source that vibrates at 24 Hz.
The tension on the string at the given length and mass is 54.43 N.
The given parameters:
length of the string, L = 6.0 mmass of the string, m = 0.252 kgwavelength, λ = 1.5 mfrequency of the source, F = 24 HzThe speed of the wave is calculated as follows;
[tex]v= f\lambda\\\\v = 24 \times 1.5\\\\v = 36 \ m/s[/tex]
The tension on the string is calculated as follows;
[tex]v = \sqrt{\frac{T}{\mu} } \\\\v = \sqrt{\frac{T}{M/l} } \\\\v = \sqrt{\frac{Tl}{M} } \\\\v^2 = \frac{Tl}{M} \\\\T = \frac{v^2 M}{l} \\\\T = \frac{(36)^2 \times 0.252}{6} \\\\T = 54.43 \ N[/tex]
Thus, the tension on the string at the given length and mass is 54.43 N.
"Your question is not complete is seems to be missing the following information;"
An object of mass is used to provide tension in a 6.0 ‑m‑long string that has a mass of 0.252 kg, as shown. A standing wave that has a wavelength equal to 1.5 m is produced by a source that vibrates at 24 Hz. Determine the tension on the string.
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A power plant running at 39 % efficiency generates 330 MW of electric power. Part A At what rate (in MW) is heat energy exhausted to the river that cools the plant
516.154 megawatts of heat are exhausted to the river that cools the plant.
By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river ([tex]Q_{out}[/tex]), in megawatts:
[tex]Q_{out} = Q_{in} - W[/tex]
[tex]Q_{out} = \left(\frac{1}{\eta}-1 \right)\cdot W[/tex](1)
Where:
[tex]\eta[/tex] - Efficiency.[tex]W[/tex] - Electric power, in megawatts.If we know that [tex]\eta = 0.39[/tex] and [tex]W = 330\,MW[/tex], then the energy rate exhausted to the river is:
[tex]Q_{out} = \left(\frac{1}{0.39}-1 \right)\cdot (330\,MW)[/tex]
[tex]Q_{out} = 516.154\,MW[/tex]
516.154 megawatts of heat are exhausted to the river that cools the plant.
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3) A 60. kg person is in an elevator. The elevator starts from rest and then accelerates upwards at 2.0 m/s^2 for 4.0 seconds. Calculate the work done by the normal force on the person. *
Answer is 1.1 x 10^4 J
Answer:
WD = 11328 J → 1.1 × 10⁴ (to 2 sig figs)
Explanation:
WD = work done (J)
F = force (N), i.e. the normal force on the person
W = weight (N)
s = displacement (m)
m = mass (kg) = 60
a = acceleration (m/s²) = 2
g = gravity (m/s²) = 9.8
t = time (s) = 4
u = initial velocity (m/s) = 0
The formulas or equations that are relevant ate:
WD = F × s
F = m × a
W = m × g → note: this is simply a variation of the formula F = ma
s = ut + ¹/₂.at²
We want to find WD, so we need to know the force and the displacement (or distance);
Firstly, we want to find the normal force on the person in the elevator;
The downwards force the person produces on the elevator is the weight of the person, which is:
W = 60 × g
W = 60 × 9.8
W = 588
We are told the elevator is accelerating upward, so we can construct an equation to find F with the formula F = ma:
F - W = 60 × 2
F - 588 = 120
F = 708
Note: illustrations may be helpful to understand this, as has been shown in the picture
We also need displacement, which we use the formula s = ut + ¹/₂at²:
s = 0(4) + ¹/₂(2)(4)²
s = 16 m
Now we have F and s, we can calculate WD:
WD = 708 × 16
WD = 11328 J → This can be rounded to 1.1 × 10⁴ to 2 significant figures
If a block is sitting in a shelf 5 foot high and the same size block is sitting on the shelf above it at 6 feet high. Which has more potential energy? Explain your reasoning.
Answer:
Explanation:
Assuming that not only is the size of the two blocks the same but the MASS is also the same, then the higher block will have more potential energy.
Potential energy is equal to the amount of work required against gravity to position a mass
Work is a force times a distance. PE = W = Fd
As each block has the same mass, they each create the same force which would be their weight mg
PE = W = Fd = mgd
so potential energy is directly proportional to the height of each block
the lower block has potential energy PE = Fd = mg(5)
while the upper block has potential energy PE = mg(6)
above a reference frame origin, possibly the floor.
It is possible that the higher block has less potential energy then the lower block if only the size is considered. If the higher block is a one foot cube of ice at 57.2 lbs and the lower block is a one foot cube of copper at 559 lbs then the lower mass would have much more potential energy because of its much greater mass.
559(5) = 2795 ft•lb of potential energy
57.2(6) = 343.2 ft•lb of potential energy
car is traveling with a velocity of 40 m/s and has a mass of 1120 kg. The car has
_______________ energy.
Answer:896000 J
Explanation: K.E = 1/2*m*v^2
Answer:
The car has Kinetic energy. 896000 Joules
Explanation:
Kinetic energy formula: 1/2 (mass)(speed)^2
First you multiply 1120 by 1/2 and get 560
Then you take the square root of 40 ([tex]40x^{2}[/tex]) and get 1600
Finally to get the answer multiply 560 by 1600 and your final answer should be 896000 Joules
What are last two commandments? Please write them down.
The Second Commandment refers to: The second of the Ten Commandments, which is: "Thou shalt have no other gods before me. Thou shalt not make unto thee any graven image" under the Talmudic division of the third-century Jewish Talmud.
Answer:
Thou shalt love the Lord thy God with all thy heart, and with all thy soul, and with all thy mind. This is the first and great commandment. And the second is like unto it, Thou shalt love thy neighbor as myself.
Explanation:
A slender rod of length 80.0 cm and 0.600 kg has its center of gravity at its geometrical center. But its density is not uniform; it increases by the same amount from the center of the rod out to either end. You want to determine the moment of inertia Icm of the rod for an axis perpendicular to the rod at its center, but you don't know its density as a function of distance along the rod, so you can't use an integration method to calculate Icm. Therefore, you make the following measurements: You suspend the rod about an axis that is a distance d (measured in meters) above the center of the rod and measure the period T (measured in seconds) for small-amplitude oscillations about the axis. You repeat this for several values of d. When you plot your data as T2−4π2d/g versus 1/d, the data lie close to a straight line that has slope 0.470 m⋅s2. What is the value of Icm for the rod?
Answer:
Icm = 0.0701 kgm^2
Explanation:
When converted to a household measurement, 9 kilograms is approximately equal to a) 9000 grams. b) 9000 ounces. 19.8 ounces. d) 19.8 pounds.
Answer:
9000 grams which is also very close to 19.8 pounds
so answers a) and d) are correct
Explanation:
9 kg(1000 gm/kg) = 9000 gms
9 kg(2.205 lb/kg) = 19.845 lb
I guess it rather depends on whose household you are in. One in the US would probably use 19.8 lb while one in Canada might use 9000 gm.
