I forgot please help me out here. Is 25 fl oz greater than 1 pint, or 1 pint greater than 25 fl oz. Please help me out thank you so much

Answers

Answer 1

The 25 fluid ounces is greater than one pint is correct statement .

Relation between fluid ounces and pint ,

There are 16 fluid ounces in one pint.

Conversion of fluid ounces to pint

This implies that,

1 fluid ounces is equal to  one by sixteen pint.

To be precise,

25 fluid ounces is equal to 25 / 16pints

⇒  25 fluid ounces is equal to 1.5625.

However, since 1.5625 is greater than 1,

This implies that 25 fluid ounces is greater than 1 pint.

So, 25 fluid ounces is greater than 1 pint.

Because 25 is greater than 16.

And 1 pint is not greater than 25 fluid ounces.

Therefore, the 25 fluid ounces is greater than one pint.

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Related Questions

Juanita is making a ribbon as shown 4 cm 15 cm 3 cm explain two different ways you can find the area of the ribbon then find the area of the ribbon ​

Answers

Answer:

6

Step-by-step explanation:

A=hbb/2=4·3/2=6

To find a triangle's area, use the formula area = 1/2 * base * height. Choose a side to use for the base, and find the height of the triangle from that base. Then, plug in the measurements you have for the base and height into the formula

or

The area of a triangle is the space enclosed within the three sides of a triangle. It is calculated with the help of various formulas depending on the type of triangle and is expressed in square units like, cm2, inches2, and so on.

Emmanuel weighs 150 pounds and he has normal liver function. It will take him approximately ________ hours to metabolize one standard drink

Answers

Emmanuel weighs 150 pounds and he has normal liver function. It will take him approximately 1 hour to metabolize one standard drink. Metabolism of alcohol is primarily done in the liver where it is broken down into acetaldehyde, which is then further broken down into water and carbon dioxide.

The liver can only metabolize a certain amount of alcohol per hour, which is why it takes time for the body to process and eliminate alcohol. However, other factors such as age, gender, body composition, and food consumption can also affect how quickly alcohol is metabolized.

It is important to drink responsibly and be aware of how alcohol can affect your body.

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The city is 30 miles long and two-thirds as wide, and 555,000 citizens currently live there. The mayor calculates that the minimum number of people who would have to move outside the city for adequate services to be maintained is 75,000. Enter the maximum population density , in citizens per square mile , that is assumed in the mayor's calculation

Answers

The maximum population density evaluated is 1200 citizens per square mile, under the condition that the city is 30 miles long and two-thirds as wide, and 555,000 citizens currently live there.

Now to evaluate the maximum population density that is considered in the mayor's calculation is
Let us first calculate the area of the city which is (2/3) × (30 miles)
= 20 miles.
So, now we can calculate the current population density which is
555,000 / (20 × 20)
= 1387.5 citizens per square mile.
Hence the mayor evaluates that at least 75,000 people must transfer out of the city for adequate services to be exercised, we can find the new population as
555,000 - 75,000
= 480,000 citizens.
Therefore, the new population density would be 480,000 / (20 × 20)
= 1200 citizens per square mile

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the length of a retangle is 5 more than twoce its width its perimter is 88 feet find the dimensions use p=2l+2w

Answers

If length of rectangle is 5 more than twice it's width and having perimeter as 88 feet, then the dimensions of the rectangle are, length is 31 feet, width is 13 feet.

Let width of the rectangle be represented as = "w" feet.

It is given that, the length of rectangle is 5 more than twice it's width,

So, Length can be represented as "2w + 5" in feet;

We use formula for perimeter of rectangle, which is "P = 2Length + 2Width", where P = perimeter, L = length, and W = width.

In this case, we know that the perimeter is 88 feet, so we substitute the values,

We get,

⇒ 88 = 2(2w + 5) + 2w;

⇒ 88 = 4w + 10 + 2w,

⇒ 88 = 6w + 10,

⇒ 78 = 6w,

⇒ w = 13,

So the width is 13 feet. We use this value of width to find length of the rectangle:

⇒ L = 2w + 5,

⇒ L = 2(13) + 5,

⇒ L = 31

Therefore, the dimensions of the rectangle are 31 feet by 13 feet.

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The average price of a two-bedroom apartment in the uptown area of a prominent American city during the real estate boom from 1994 to 2004 can be approximated by p(t) = 0.17e⁰.¹⁰ᵗ million dollars (0 ≤ t ≤ 10) where t is time in years (t = 0 represents 1994). What was the average price of a two-bedroom apartment in this uptown area in 2002, and how fast was it increasing? (Round your answers to two significant digits.) p(8) = $ million p' (8) = $ million per yr

Answers

In 2002, the average price of a two-bedroom apartment in the uptown area was approximately $0.316 million, and it was increasing at a rate of about $0.0328 million per year.

To find the average price of a two-bedroom apartment in 2002 (t=8), you need to evaluate the given function p(t) = 0.17e^(0.10t) at t=8:

p(8) = 0.17e^(0.10 * 8)

p(8) = 0.17e^0.8 ≈ 0.316 million dollars

To find the rate at which the price was increasing in 2002, you need to find the derivative of the function p(t) with respect to t, and then evaluate it at t=8:

p'(t) = d/dt (0.17e^(0.10t))
p'(t) = 0.17 * 0.10 * e^(0.10t)

Now, evaluate p'(t) at t=8:

p'(8) = 0.17 * 0.10 * e^(0.10 * 8)
p'(8) ≈ 0.0328 million dollars per year

So, in 2002, the average price of a two-bedroom apartment in the uptown area was approximately $0.316 million, and it was increasing at a rate of about $0.0328 million per year.

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Convert the number 35/4 into decimal form rounded to the nearest hundred. ​

Answers

Answer: 8.75

Step-by-step explanation:

We know that 4 goes into 35 eight times.

        35 - (4 * 8) = 3

Next, we know that 3/4 is equal to 0.75 by dividing.

This leaves us with 8.75. Eight wholes and a part of 0.75.

Question: Nora needs to cut some equal pieces of yarn for her Science project. The piece of yarn she has is 67. 6 inches long. Each piece of yarn must be 1. 3 inches in lenght. How many pieces of yarn will Nora have. ​

Answers

Nora will be able to cut 52 equal pieces of yarn for her Science project.

To find out how many equal pieces of yarn Nora can cut for her Science project, we need to divide the total length of the yarn by the length of each piece.

Total length of yarn: 67.6 inches
Length of each piece: 1.3 inches

Step 1: Divide the total length by the length of each piece.
67.6 inches ÷ 1.3 inches = 52

Nora will have 52 equal pieces of yarn, each 1.3 inches long, for her Science project.

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find cif a = 2.74 mi, b = 3.18 mi and ZC = 41.9°. Enter c rounded to 2 decimal places. C= mi Assume LA is opposite side a, ZB is opposite side b, and ZC is opposite side c.

Answers

Cif a = 2.74 mi, b = 3.18 mi and ZC = 41.9° and c^2 = a^2 + b^2 - 2ab*cos(C)where C is the angle opposite to side c, c comes to be ≈ 4.26 mi.

The Law of Cosines is a numerical formula that relates the side lengths and points of any triangle. It expresses that the square of any side of a triangle is equivalent to the number of squares of the other different sides short two times the result of those sides and the cosine of the point between them. To get side c, we can use the law of cosines, which states that c² = a² + b² - 2ab cos(C).
Plugging in the given values, we get:
c² = (2.74)² + (3.18)² - 2(2.74)(3.18)cos(41.9°)
c² ≈ 18.126
Taking the square root of both sides, we get:
c ≈ 4.26 mi
Rounding to 2 decimal places, c ≈ 4.26 mi.
Therefore, the answer is: c ≈ 4.26 mi.

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Describe and correct the error a student made in finding the domain for the quotient when f(x) = 2x² - 3x + 1 and g(x) = 2x - 1.




So the domain is all real numbers.​

Answers

The student is correct that the domain of a quotient is typically all real numbers, except for the values of x that make the denominator equal to zero.

However, it's important to check whether the denominator of the quotient, g(x), can ever be zero. In this case, the denominator is 2x - 1. Setting this equal to zero, we get:

2x - 1 = 0
2x = 1
x = 1/2

Therefore, the only value of x that is not in the domain of the quotient is x = 1/2. The correct domain for the quotient is all real numbers except x = 1/2.

So the correct domain is:

x ≠ 1/2

It's important to double-check for such possible errors while finding the domain of a function.

Let x, y, and z represent three rational numbers, such that y is 512 times x and z is 50. 25 more than x. If y=15. 5, what is the value of z?

Answers

If x, y, and z represent three rational numbers, such that y is 512 times x and z is 50. 25 more than x and y = 15.5 , then value of z = 50.280.

Let x, y, and z represent three rational numbers, such that y is 512 times x and z is 50.25 more than x. If y = 15.5, the value of z can be found as follows:

Find the value of x.
Since y is 512 times x, we have the equation:
y = 512x
Substitute y with 15.5:
15.5 = 512x

Now, divide both sides by 512 to find x:
x = 15.5 / 512
x ≈ 0.0302734375

Find the value of z.
Since z is 50.25 more than x, we have the equation:
z = x + 50.25
Substitute x with the value we found (x = 0.0302734375):
z ≈ 0.0302734375 + 50.25
z ≈ 50.2802734375

So, the value of z is approximately 50.2802734375.

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for each rectangle find the radio of the longer side to shorter side​

Answers

[tex]\cfrac{\stackrel{\textit{longer side}}{12}}{\underset{\textit{shorter side}}{3\sqrt{3}}}\implies \cfrac{4}{\sqrt{3}}\implies \cfrac{4}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}}\implies \cfrac{4\sqrt{3}}{3}[/tex]

Let the region r be the area enclosed by the function f(x)=x^2+1 and g(x)=2x+1. if the region r is the base of a solid such that each cross section perpendicular to the x axis is a square, find the volume of the solid.

Answers

The volume of the solid is 32/15 cubic units.

How to find volume of the solid?

To find the volume of the solid, we need to integrate the area of each square cross section perpendicular to the x-axis over the interval [a, b], where a and b are the x-coordinates of the intersection points of f(x) and g(x):

First, we find the intersection points of the two functions:

x²+1 = 2x+1

x² - 2x = 0

x(x-2) = 0

x = 0 or x = 2

So, a = 0 and b = 2.

Next, we find the side length of each square cross section. Since the cross section is a square, the side length is equal to the difference between the y-coordinates of the functions f(x) and g(x) at each x:

Side length = f(x) - g(x) = (x²+1) - (2x+1) = x² - 2x

Finally, we integrate the area of each square cross section over the interval [0, 2] to get the volume of the solid:

V = ∫[0,2] (x² - 2x)² dx

V = ∫[0,2] (x⁴- 4x³ + 4x²) dx

V = [1/5 x⁵ - 1 x⁴ + 4/3 x³] [0,2]

V = (1/5 x⁵ - 1 x⁴ + 4/3 x³)|[0,2]

V = (1/5(2⁵) - 1(2⁴) + 4/3(2³)) - (1/5(0⁵) - 1(0⁴) + 4/3(0³))

V = (32/5 - 16/3)

V = 32/15

Therefore, the volume of the solid is 32/15 cubic units.

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The probability of an event is given. Find the odds in favor of the event.


0. 5

Answers

The odds in favor of the event are 1.

The probability of an event is the ratio between the total number of favorable outcomes and the total number of outcomes.

The odds in favor of an event are the ratio of the total number of favorable outcomes and the total number of unfavorable outcomes. If the probability of the event is given, we can find the odds in favor by using the formula of odds in favor:

odds in favor = probability of event/probability of not event

In this case question, the probability of an event is given as 0.5 which means that the total number of favorable outcomes is 50 out of 100

So the probability of not having an event is also 0.5 (the other half of the part.)

So, odds in favor = 0.5/0.5 = 1

The probability of the happening of an event is the same as the probability of not happening of an event. This means that the odds in favor of the event are 1 to 1, or simply 1.

Therefore,  the odds in favor of the event are 1.

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Find the equation for the plane through the points Po(-3,- 2,4), Qo(-5, - 1,2), and Ro(1,1,5). C. Using a coefficient of 7 for x, the equation of the plane is (Type an equation.)

Answers

The equation for the plane through the points Po(-3,-2,4), Qo(-5,-1,2), and Ro(1,1,5) is:

3x - 3y + 2z - 11 = 0

Using a coefficient of 7 for x, the equation of the plane is:

21x - 3y + 2z - 11 = 0

To find the equation of the plane, we can use the cross product of the vectors formed by the points Qo-Po and Ro-Po.

Let's call the vector formed by Qo-Po "u" and the vector formed by Ro-Po "v". Then, we can find the normal vector to the plane by taking the cross product of "u" and "v":

u = Qo - Po = (-5+3, -1+2, 2-4) = (-2,1,-2)

v = Ro - Po = (1+3, 1+2, 5-4) = (4,3,1)

n = u x v = (1(2) - (-2)(3), (-2)(4) - 1(1), (-2)(3) - 1(4)) = (8,-7,-10)

Now that we have the normal vector to the plane, we can find the equation of the plane by using the point-normal form of the equation of a plane:

n · (P - Po) = 0

where "·" denotes the dot product, P is any point on the plane, and Po is one of the given points on the plane.

Let's use the point Po(-3,-2,4) to find the equation of the plane:

n · (P - Po) = 0

(8,-7,-10) · (x+3, y+2, z-4) = 0

8(x+3) - 7(y+2) - 10(z-4) = 0

8x - 7y - 10z + 11 = 0

So the equation of the plane through the points Po, Qo, and Ro is:

3x - 3y + 2z - 11 = 0

To use a coefficient of 7 for x, we can simply multiply both sides of the equation by 7:

21x - 21y + 14z - 77 = 0

Simplifying, we get:

21x - 3y + 2z - 11 = 0

Therefore, the equation of the plane with a coefficient of 7 for x is 21x - 3y + 2z - 11 = 0.

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In ΔSTU, t = 3. 4 cm, u = 6. 9 cm and ∠S=21°. Find the area of ΔSTU, to the nearest 10th of a square centimeter.

Answers

4.20 cm² is the area of the triangle STU to the nearest 10th of a square centimeter.

Given, t = 3.4 cm, u = 6.9 cm and ∠S = 21°

We know that the formula for the area of the triangle = 1/2 * t*u *sin(S)

Substituting the values

Area = 1/2 × 3.4 × 6.9 × sin(21°)

Area = 11.73 × sin(21°)

Area = 11.73 ×  0.3583

Area = 4.2016

Rounding to the nearest 10th of a square centimeter .

Area = 4.20 cm²

Hence, 4.20 cm² is the area of the triangle STU to the nearest 10th of a square centimeter.

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(Dilations MC)
Triangle ABC with vertices at A(-3, -3), B(3, 3), C(0, 3) is dilated to create triangle A'B'C' with vertices at A(-6, -6), B(6, 6), C(0, 6). Determine the scale factor used.
02
1|2
03
-in

Answers

The scale factor used is 2.

What is triangle?

It is one of the simplest polygon shapes and is commonly used in mathematics and geometry. The sum of the internal angles of a triangle is always 180 degrees.

Define vertices of triangle?

The vertices of a triangle are the three points in a two-dimensional (2D) or three-dimensional (3D) space that define the corners or corners of the triangle. In a 2D plane, the vertices are typically denoted as A, B, and C, and in a 3D space, they can be represented as (x1, y1, z1), (x2, y2, z2), and (x3, y3, z3) where (x, y, z) are the coordinates of each vertex along the x, y, and z axes respectively. The vertices of a triangle are connected by three line segments, known as edges, to form the sides of the triangle. The combination of the three vertices and the edges connecting them determines the shape and size of the triangle.

To find the scale factor used to dilate triangle ABC to A'B'C', we can compare the corresponding side lengths of the two triangles.

The distance between A(-3, -3) and B(3, 3) is √((3-(-3))^2 + (3-(-3))^2) = 6√2.

The distance between A'(-6, -6) and B'(6, 6) is √((6-(-6))^2 + (6-(-6))^2) = 12√2.

So the scale factor used to dilate triangle ABC to A'B'C' is:

scale factor = length of corresponding side in A'B'C' / length of corresponding side in ABC

            = (12√2) / (6√2)

            = 2

Therefore, the scale factor used is 2.

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A large diamond with a mass of 481. 3 grams was recently discovered in a mine. If the density of the diamond is g over 3. 51 cm, what is the volume? Round your answer to the nearest hundredth. ​

Answers

The volume of the large diamond is approximately 3.51 cm³.

To find the volume of the large diamond with a mass of 481.3 grams and a density of (g/3.51 cm), you can use the formula:

Volume = Mass / Density

The volume of the large diamond, we can use the formula Volume = Mass / Density. Given that the mass is 481.3 grams and the density is (g/3.51 cm), we can substitute these values into the formula.

Simplifying the equation, we find that the volume is equal to 3.51 cm³. This means that the large diamond occupies a space of approximately 3.51 cubic centimeters.


1. First, rewrite the density as a fraction: g/3.51 cm = 481.3 g / 3.51 cm³
2. Next, solve for the volume by dividing the mass by the density: Volume = 481.3 g / (481.3 g / 3.51 cm³)
3. Simplify the equation: Volume = 481.3 g * (3.51 cm³ / 481.3 g)
4. Cancel out the grams (g): Volume = 3.51 cm³

So, the volume of the large diamond is approximately 3.51 cm³, rounded to the nearest hundredth.

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Answer:

Step-by-step explanation:

Density = mass

               volume  

We have density (3.51 cm) and we have mass (481.3)

We need to solve for V (volume)

3.51 =     481.3

               V

Multiply both sides by V to clear the fraction:

3.51 V = 481.3

Divide both side by 3.51

3.51 V = 481.3

3.51         3.51

V = 137.122cm³

rounded to 137.12 cm³

. Select two choices that are true about the function f(x)
A There is an asymptote at x = 0.
☐ B There is a zero at 23.
OC
There is a zero at 0.
D
There is an asymptote at y = 23.
23x+14
x

Answers

Answer:

A. There is an asymptote at x = 0.

D. There is an asymptote at y = 23.

Evan bought 7 books on sale for 45.50 the regular price of the 7 books 57.75 how much did evan save per books buying them on salw

Answers

Evan saved $1.75 per book by buying them on sale.

Evan bought 7 books on sale for $45.50, with a regular price of $57.75. What was the per-book savings?

To find out how much Evan saved per book by buying them on sale, you can use the following formula:

Savings per book = (Regular price per book - Sale price per book)

First, you need to find the regular price per book:

Regular price per book = (Total regular price of 7 books) / 7

Regular price per book = 57.75 / 7

Regular price per book = 8.25

Next, you need to find the sale price per book:

Sale price per book = (Total sale price of 7 books) / 7

Sale price per book = 45.50 / 7

Sale price per book = 6.50

Now, you can find the savings per book:

Savings per book = (Regular price per book - Sale price per book)

Savings per book = (8.25 - 6.50)

Savings per book = 1.75

Therefore, Evan saved $1.75 per book by buying them on sale.

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2. Calculate the volume of the solid by calculating the triple integral: 6 pts •1 r2-2y dzdydx y = d x=0 +2=2 =3 y 3 =0

Answers

The volume of the solid is given by V = 9r/2 - 3.

To calculate the volume of this solid, we will use a triple integral, which involves integrating a function of three variables over a three-dimensional region. The triple integral is denoted by ∭f(x, y, z) dV, where f(x, y, z) is the function we are integrating, and dV is the volume element.

In our problem, the function f(x, y, z) is equal to 1, which means we are integrating a constant function. Therefore, we can simplify the triple integral to V = ∭dV, where V represents the volume of the solid.

To evaluate the triple integral, we need to determine the limits of integration for each variable. We are given the limits for x, y, and z, so we can set up the triple integral as follows:

V =  ∫₂⁰ ∫₃⁰ r2-2y 1 dz dy dx

We integrate first with respect to z, then y, and finally x.

Integrating with respect to z, we get:

V = ∫₂⁰ ∫₃⁰[r2-2y - 1] dy dx

Simplifying the integral, we get:

V =  ∫₂⁰ [r2y - y2]dy dx

Integrating with respect to y, we get:

V = ∫₂⁰ [(r2/2)y2 - (1/3)y3]dy

Simplifying the integral, we get:

V = [(r/2)(3)2 - (1/3)(3)3] - [(r2/2)(0)2 - (1/3)(0)3]

V = 9r/2 - 3

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HELPPPPPPPPPp WILL GIVE BRAINLEISTTT!!!

Answers

Answer:

100

Step-by-step explanation:

i think this is right

100 I’m pretty bad at this so let me know if it’s wrong….

Guided practice

it's not letter c. -2.6

state what number you would subtract from each side of the inequality to solve the inequality.


5.7 ≥ k + 3.1


a.
3.1


b.
5.7


c.
–2.6

Answers

The value of k that is less than or equal to 2.6

To solve the inequality 5.7 ≥ k + 3.1, you should subtract 3.1 from each side of the inequality.

To isolate the variable k, we need to perform the same operation on both sides of the inequality. In this case, we need to subtract 3.1 from each side:

5.7 - 3.1 ≥ k + 3.1 - 3.1

This simplifies to:

2.6 ≥ k

Therefore, the correct answer is:

k ≤ 2.6

We subtracted 3.1 from each side to isolate the variable k, resulting in the inequality k ≤ 2.6. This means that any value of k that is less than or equal to 2.6 will satisfy the original inequality 5.7 ≥ k + 3.1.

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y= 3x-2 y= 9x+ 10 find x, y​

Answers

Answer:

(-2,-8)

Step-by-step explanation:

First, we have to make these linear equations into standard form:

-3x+y=-2

and

9x-y=-10

Now we tell my using elimination method, we can cross out the y variables because when added(y+(-y)) is just 0, so we just cross them out

Add liked terms

6x=-12

Solve for X:

X=-2

Plug 2 for X in any equation (lets do -3x+y=-2)

Plug in -2 for X:

-3(-2)+y=-2

Thus we get 6+y=-2

Solve for Y:

y=-8

Now that we have both our variables, we know that the answer is (-2,-8)

Can someone please answer numbers 12, 13, 14, and 15?

Answers

Answers

11 - DGE & FGC

12- BGC & CGD

13 - AGD

14 - FGE & AGF ***** there are no angle measurements or right angle indicator so this is based on a visual assumption that those angles sum 90 degrees making it complementary

15 - FGC

See attachment

The area of the shaded region under the curve of a function f(x) = ax + b on the interval [ 0, 4 ] is 16 square units.

Answers

The area of the given region under the curve of a function f(x) = ax + b on the interval [0, 4] is 16 square units. So, all the options satisfy the value of a and b except (7, -9).

How to find the area of a region?

The area of the given region under the curve of a function f(x) = ax + b on the interval [0, 4] is 16 square units.

f(x) is a linear function, the area under the curve on the interval [0,4] is a trapezoid with a height of 4 and bases of lengths f(0) and f(4).

The area of a trapezoid is the height times the average of the bases.

a. f(x)=-2x+8  f(0)=8, f(4)=0;

  area = 4(8/2) = 16

b. f(x)=x+2; f(0)=2, f(4)=6;

  area = 4(8/2) = 16

c. f(x)=3x-2; f(0)=-2, f(4)=10;

   area = 4(8/2) = 16

d. f(x)=5x-6; f(0)=-6, f(4)=14;

   area = 4(8/2) = 16

e. f(x)=7x-9; f(0)=-9, f(4)=19;

    area = 4(10/2) = 20

Thus, The area is NOT 16 for choice e.

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PLS HELP ASAP 50 POINTS AND BRAINLEIST!!!
Explain how the arc BX, central angle BCX, and inscribed BNX are connected. what are the relationships between them?

Answers

Answer:

See explanation.

Step-by-step explanation:

The arc BX, central angle BCX, and inscribed angle BNX are connected through the following relationships:

1. The central angle BCX subtends the arc BX. This means that the central angle is formed by two radii connecting the center of the circle to the endpoints of the arc BX.

2. The inscribed angle BNX subtends the same arc BX. This means that the inscribed angle is formed by two chords connecting a point on the circumference of the circle to the endpoints of the arc BX.

3. The relationship between the central angle BCX and the inscribed angle BNX is given by the Inscribed Angle Theorem, which states that the measure of an inscribed angle is half the measure of the central angle subtending the same arc. In other words, if θ is the measure of the central angle BCX and α is the measure of the inscribed angle BNX, then:

[tex]\alpha =\frac{1}{2}[/tex] θ

The circumstances if the base of the cone is 12π cm. If the volume of the cone is 96π, what is the height
pleaseee helppp!!

Answers

Hence, the cone is 8/3 cm tall as we can get the height using the following formula for a cone's volume.

what is volume ?

A three-dimensional object's volume is a measurement of how much space it takes up. It is a real-world physical number that can be expressed in cubic measurements like cubic metres (m3), cubic centimetres (cm3), or cubic feet (ft3). Physics, chemistry, architecture, and mathematics all use the idea of volume extensively. Volume is frequently used to refer to the amount of space that an object or substance takes up, for instance the amount of a container, the volume of either a liquid, or the quantity of a gas. Depending on an object's shape, a different formula is required to determine its volume.

given

The formula V = (1/3)r2h, where V is the volume, r is the radius of the base, and h is the height, can be used to determine the volume of a cone.

Hence, by multiplying the circumference by two, we can determine the radius of the base:

12π / 2π = 6

Thus, the base's radius is 6 cm.

Also, we are informed that the cone's volume is 96. As a result, we can get the height using the following formula for a cone's volume:

V = (1/3)r2h

96 = (1/3)(6/2)h

96 = 36 h

96 / 36 = 8/3

Hence, the cone is 8/3 cm tall as we can get the height using the following formula for a cone's volume.

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You have a machine which can paint 20 bikes per hour. you purchase two additional, identical machines. how many bikes can you now paint per hour

Answers

The total number of bikes that can be painted in an hour would be 60 bikes.

With three identical machines,

the number of bikes machine can paint per hour = 20,

the number of machines bought again = 2,

so the total number of machines will be = 3,

when there are two same machines the productivity will be = 20 * 3 = 60 bikes.

This is because each machine works independently and can paint bikes simultaneously.

By adding two additional machines to the existing one,

the productivity of the painting process can be significantly increased. The new machines will not only increase the overall capacity but also reduce the turnaround time required for painting a large number of bikes.

By investing in additional machines,

the business can increase its output and generate more revenue,

which can be used to expand the operations further.

It's important to note that the investment in additional machines needs to be justified by the demand for painted bikes and the expected return on investment.

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If x -1/x=3 find x cube -1/xcube​

Answers

Answer:

Sure. Here are the steps on how to solve for x^3 - 1/x^3:

1. **Cube both sides of the equation x - 1/x = 3.** This will give us the equation x^3 - 3x + 1/x^3 = 27.

2. **Subtract 1 from both sides of the equation.** This will give us the equation x^3 - 1/x^3 = 26.

3. **The answer is 26.**

Here is the solution in detail:

1. **Cube both sides of the equation x - 1/x = 3.**

```

(x - 1/x)^3 = 3^3

```

```

x^3 - 3x + 1/x^3 = 27

```

2. **Subtract 1 from both sides of the equation.**

```

x^3 - 1/x^3 - 1 = 27 - 1

```

```

x^3 - 1/x^3 = 26

```

3. The answer is 26.

The spies of Syracuse report that enemies are marching towards the city. Archimedes needs to build death rays and claws to defend the city with. He'll need at least 10 machines but the city only gave him 3000 lbs of gold to build the machines with. A claw costs 200 lbs of gold to build while a death ray is worth 350 lbs of gold. Write a system of inequalities to find a possible number of claws and death rays that Archimedes can build. â

Answers

Possible number of death rays (D) and claws (C) that Archimedes can build are given by the following system of inequalities: 350D + 200C ≤ 3000. D, C ≥ 0

The first inequality represents the fact that the total amount of gold used to build the machines cannot exceed the 3000 lbs of gold given by the city. The second inequality ensures that the number of death rays and claws cannot be negative.

To explain this system, let us assume that Archimedes builds x death rays and y claws. The amount of gold required to build x death rays and y claws is given by 350x + 200y. The first inequality ensures that this value cannot exceed 3000 lbs of gold. The second inequality ensures that the number of death rays and claws cannot be negative.

Therefore, the solution to this system of inequalities gives us all the possible combinations of death rays and claws that Archimedes can build with the given amount of gold.

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