The distance that shows how much farther (in km) from the sun is Saturn than Venus is: [tex]1.2 * 10^9[/tex] km.
How to calculate the distanceAccording to the table, the distance of Saturn from the Sun is [tex]1.4 * 10^{9}[/tex] and the distance of Venus from the Sun is [tex]1.1 * 10^{8}[/tex] .
Now to determine how much further from the Sun is Saturn than Venus, we will subtract the distance of the planet with the higher distance span from the one with the lower distance.
So our calculation will go thus:
[tex]1.4 * 10^9 - 1.1 * 10^8 = \\140000000 - 11000000 = 1290000000\\= 1.29 * 10^9[/tex]
From the calculation above, we can see how much further from the sun, is Saturn than Venus.
Complete Question:
The table shown below gives the approximate distance from the sun for a few different planets. How much farther (in km) from the sun is Saturn than Venus? Express your answer in scientific notation.
_______km
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Find the coordinates of a point P on the line and a vector v parallel to the line. X-7 - Y + 2 = 2 + 6 = 5 4 P(x, y, z) = V ="
To find the coordinates of point P on the line, we can solve for x and y in the equation X-7 - Y + 2 = 2 + 6 = 5. Adding 7 to both sides, we get X - Y + 2 = 12. Subtracting 2 from both sides, we get X - Y = 10. We can choose any value for x, and then solve for y using this equation. For example, if we choose x = 0, then y = -10.
So the coordinates of point P on the line could be (0, -10, z), where z is any real number.
To find a vector v parallel to the line, we can take two points on the line and find the vector between them. For example, we could use the points (0, -10, 0) and (1, -9, 0). The vector between these points is (1-0, -9-(-10), 0-0) = (1, 1, 0).
So a vector v parallel to the line is v = (1, 1, 0).
To find the coordinates of a point P on the line and a vector v parallel to the line, we first need to rewrite the given equation in a more standard form. The equation provided seems to be incorrect, but let's assume it's meant to be in the format of Ax + By = C, then we can proceed as follows:
1. Identify the normal vector of the line (A, B): Since the given equation is X - Y = 3 (combining the constants), the normal vector is (1, -1).
2. Determine the direction vector of the line, which is perpendicular to the normal vector. One possible direction vector is the one obtained by swapping the components and negating one of them, so v = (1, 1).
3. To find a point P on the line, we can choose a value for either x or y and solve for the other coordinate. Let's choose x = 0, then we have 0 - Y = 3, which gives Y = -3. Therefore, P(x, y) = (0, -3).
In summary, the point P on the line is (0, -3), and a vector v parallel to the line is (1, 1).
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A third candle, in the shape of a right circular cone, has a volume of 16 cubic inches and a radius of 1. 5 inches. What is the height, in inches, of the candle? Round your answer to the nearest tenth of an inch.
The height of the right circular cone ,candle is approximately 6.8 inches.
To find the height of the third candle, which is a right circular cone with a volume of 16 cubic inches and a radius of 1.5 inches, we will use the formula for the volume of a cone: V = (1/3)πr^2h, where V is the volume, r is the radius, and h is the height.
1. Substitute the given values into the formula: 16 = (1/3)π(1.5)^2h
2. Simplify the equation: 16 = (1.5^2 * π * h) / 3
3. Solve for h:
a. Multiply both sides by 3: 48 = 1.5^2 * π * h
b. Divide by π: 48/π = 1.5^2 * h
c. Divide by 1.5^2: (48/π) / 1.5^2 = h
4. Calculate the height, and round to the nearest tenth: h ≈ 6.8 inches
The height of the candle is approximately 6.8 inches.
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The distance from Earth to Mercury is 9.21×10^7 kilometers. How long would it take a rocket, traveling at 3.35×10^4 kilometers per hour to travel from Earth to Mercury? Round your answer to the nearest whole number of hours.
it would take approximately 2,749 hours for a rocket traveling at 3.35×10⁴ kilometers per hour to travel from Earth to Mercury.
what is approximately ?
Approximately means "about" or "roughly". It is used to indicate that a number or value is not exact, but rather an estimate or approximation. When a value is given as approximately a certain number
In the given question,
To calculate the time it would take a rocket traveling at 3.35×10⁴ kilometers per hour to travel from Earth to Mercury, we need to divide the distance between Earth and Mercury by the speed of the rocket:
Time = Distance / Speed
Distance = 9.21×10⁷kilometers
Speed = 3.35×10⁴ kilometers per hour
Time = 9.21×10⁷ km / (3.35×10⁴ km/h)
Time = 2,748.66 hours
Rounding this value to the nearest whole number of hours gives:
Time = 2,749 hours
Therefore, it would take approximately 2,749 hours for a rocket traveling at 3.35×10⁴ kilometers per hour to travel from Earth to Mercury.
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A circle with center (7,3) and radius of 5 is graphed below with a square inscribed in
the circle.
Part A: Dillon and Chelsey are discussing how to write the equation of a tangent line
to circle A through point B. Both agree that they start the problem by drawing the
radius AB and find the slope of that segment. They also know that a tangent line is
perpendicular to the radius.
The area of the shaded region is (9/500)π.
To find the area shaded below in circle K, we first need to find the radius of the circle.
Let O be the center of the circle, and let N be the midpoint of segment LM. We can draw a radius ON to segment LM such that it is perpendicular to LM, and then draw another radius OL to point L. This forms a right triangle LON with the hypotenuse equal to the radius of circle K.
Since segment LM is given to have a length of 11/9π, we can find the length of LN by dividing it in half:
LN = (11/9π)/2 = 11/18π
We can then use trigonometry to find the length of OL:
sin(55°) = OL / LN
OL = LN sin(55°)
OL = (11/18π) sin(55°)
Next, we can use the Pythagorean theorem to find the length of ON:
ON² = OL² + LN²
ON² = [(11/18π) sin(55°)]² + [11/18π]²
ON ≈ 1.022
Therefore, the radius of circle K is approximately 1.022.
The area of the shaded region can now be found by subtracting the area of sector LOM from the area of triangle LON:
Area of sector LOM = (110/360)π(1.022)² ≈ 0.317π
Area of triangle LON = (1/2)(11/18π)(1.022) ≈ 0.326π
Area of shaded region = (0.326π) - (0.317π) = (9/500)π
So the area of the shaded region is (9/500)π.
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Mr. Ali has 15. 8 litres of juice. He fills equal numbers of 400 ml and 1 litre juice bottles to sell. If Mr. Ali has 3200 ml of juice left,how many equal numbers of juice bottles did he fill?
Mr. Ali filled 6 of the 400 ml juice bottles and 8 of the 1 liter juice bottles.
First, convert 15.8 liters to milliliters:
15.8 L = 15,800 mL
Let x be the number of 400 ml juice bottles filled, and let y be the number of 1 liter juice bottles filled.
The total amount of juice filled can be represented as:
400 ml/bottle * x + 1000 ml/bottle * y = 15,800 ml
Simplifying, we get:
4x + 10y = 158
We also know that there are 3200 ml of juice left:
400 ml/bottle * (x - 3200/400) + 1000 ml/bottle * y = 0
Simplifying, we get:
x + 2.5y = 28
We now have two equations with two variables. Solving for x and y, we get:
x = 6
y = 8
Therefore, Mr. Ali filled 6 of the 400 ml juice bottles and 8 of the 1 liter juice bottles.
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Let x and y be the numbers represented on the number line.
1. Ifp is the product of x and y, what point can represent p on the number line?
2. Use the information from (1) to find the point representing qon the number line if q is the
quotient of x and y. Explain your reasoning.
To find the point representing the product p of x and y on the number line, locate x and y on the number line and find their product. To find the point representing the quotient q of x and y on the number line, locate x and the reciprocal of y (1/y) on the number line, and find their product.
If p is the product of x and y, the point on the number line that represents p can be found by locating x and y on the number line and then finding their product. For example, if x is at 2 and y is at -3, then their product p is (-6) and is located at the point on the number line that corresponds to -6 which corresponds to point P.
To find the point representing q on the number line if q is the quotient of x and y, we can use the fact that the quotient is the same as the product of x and the reciprocal of y.
In other words, q = x / y = x * (1/y). Therefore, if we locate x and 1/y on the number line, their product gives us the point representing q. For example, if x is at 4 and y is at -2, then 1/y is -1/2 and is located at -2 on the number line. The product of 4 and -1/2 is -2, which corresponds to the point on the number line that represents q.
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HELP!!! A lake currently has a depth of 30 meters. As sediment builds up in the lake, its depth decreases by 2% per year.
This situation represents [exponential growth or exponential decay]
The rate of growth or decay, r, is equal to [. 98 or. 02 or 1. 02]
So the depth of the lake each year is [1. 02 or. 98 or. 02]
times the depth in the previous year.
It will take between [11 and 12 or 9 and 10 or 3 and 4 or 5 and 6]
years for the depth of the lake to reach 26. 7 meters
This situation represents exponential decay because the depth of the lake decreases over time.
Exponential decay is a mathematical term used to describe the process of decreasing over time at a constant rate where the amount decreases by a constant percentage at regular intervals. It is a type of exponential function where the base is less than 1.
In other words, the quantity is decreasing by a fixed percentage at regular intervals.
The rate of decay, r, is equal to 0.98 because the depth decreases by 2% per year.
So the depth of the lake each year is 0.98 times the depth in the previous year. It will take between 5 and 6 years for the depth of the lake to reach 26.7 meters.
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The table shows the purchases made by two customers at a meat counter. you want to buy 2 pounds of sliced ham and 3 pounds of sliced turkey. can you determine how much you will pay? explain.
The cost of purchasing 2 pounds of sliced ham and 3 pounds of sliced turkey from the meat counter is $30.95.
The table provided shows the purchases made by two customers at a meat counter. To determine how much you will pay for 2 pounds of sliced ham and 3 pounds of sliced turkey, you need to first look at the prices listed in the table. For sliced ham, the price per pound is $4.99, and for sliced turkey, the price per pound is $6.99.
To calculate the cost of 2 pounds of sliced ham, you can multiply the price per pound ($4.99) by the number of pounds (2), which gives you a total cost of $9.98. Similarly, to calculate the cost of 3 pounds of sliced turkey, you can multiply the price per pound ($6.99) by the number of pounds (3), which gives you a total cost of $20.97.
Therefore, the total cost for 2 pounds of sliced ham and 3 pounds of sliced turkey would be $9.98 + $20.97 = $30.95.
In conclusion, by using the prices listed in the table, it is possible to determine the cost of purchasing 2 pounds of sliced ham and 3 pounds of sliced turkey from the meat counter. It is important to remember to multiply the price per pound by the number of pounds needed for each item, and then add the costs together to get the total price.
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$3,900 at 1% compounded
annually for 6 years
_____________________________
A = P (1 + 1%) n = 3,900 (1 + 1%) ⁶= $4,139.92_____________________________
Solich sandwich shop had the following long-term asset balances as of december 31, 2021: accumulated cost depreciation book value land $ 77,000 − $ 77,000 building 442,000 $ (83,980 ) 358,020 equipment 245,000 (46,400 ) 198,600 patent 160,000 (64,000 ) 96,000 solich purchased all the assets at the beginning of 2019 (3 years ago). the building is depreciated over a 20-year service life using the double-declining-balance method and estimating no residual value. the equipment is depreciated over a 10-year useful life using the straight-line method with an estimated residual value of $13,000. the patent is estimated to have a five-year service life with no residual value and is amortized using the straight-line method. depreciation and amortization have been recorded for 2019 and 2020. problem 7-7a part 1 required: 1. for the year ended december 31, 2021, record depreciation expense for buildings and equipment. land is not depreciated. (if no entry is required for a transaction/event, select "no journal entry required" in the first account field.)
No journal entry is required for the land since it is not depreciated.
To record depreciation expense for buildings and equipment for the year ended December 31, 2021, we need to calculate the depreciation amounts for each asset based on their respective methods.
For the building, we will use the double-declining-balance method. The annual depreciation expense is calculated as (2 / 20) x $442,000 = $44,200. Since depreciation has already been recorded for 2019 and 2020, the accumulated depreciation balance for the building as of December 31, 2020 is $83,980. Therefore, the 2021 depreciation expense for the building is $44,200 - $83,980 = $(-39,780). We record this as follows:
Building Depreciation Expense: $39,780
Accumulated Depreciation - Building: $39,780
For the equipment, we will use the straight-line method. The annual depreciation expense is calculated as ($245,000 - $13,000) / 10 = $23,200. Since depreciation has already been recorded for 2019 and 2020, the accumulated depreciation balance for the equipment as of December 31, 2020 is $46,400. Therefore, the 2021 depreciation expense for the equipment is $23,200, and we record it as follows:
Equipment Depreciation Expense: $23,200
Accumulated Depreciation - Equipment: $23,200
No journal entry is required for the land since it is not depreciated.
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In an expansion of (2a-5b)^2 the coefficient of ab is
In the expansion of the given expression, (2a - 5b)², the coefficient of ab is -20
Determining the coefficient of a term in an expansion
From the question, we are to determine the coefficient of ab in the expansion of the given expression.
The given expression is
(2a - 5b)²
To determine the coefficient of ab, we will expand the expression
Expand the expression
(2a - 5b)²
(2a - 5b)(2a - 5b)
Applying the distributive property, we get
2a(2a - 5b) -5b(2a - 5b)
Distribute the expression outside
4a² - 10ab - 10ab + 25b²
Simplify the expression
4a² - 20ab + 25b²
Hence, the coefficient of ab is -20
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a) ¿Cuál es el coeficiente del término 23x5?
Answer:
El coeficiente del término 23x^5 es 23.
Step-by-step explanation:
8. Brock placed a 20 foot ladder against the side of the house. The base of the ladder was 6 foot from the base of the house. How high does the ladder reach on the side of the house? Draw a picture and solve. (Round to tenth)
Step-by-step explanation:
1st i think u divide 20 and 6 and then round tht to the tenth place because we already know our answer is going to be a decimal bc 6 cant go into 20.
A backyard swimming pool has a diameter of 16 feet and a height of 4 feet. A hose is used to fill the pool with a flow rate of 30 gallons per minute. A. How long will it take to fill the pool? B. If h represents the depth of the water, find dh/dt
Hose will take about 63.7 minutes to fill the pool and the the depth of the water is increasing at a rate of about 0.0079 feet per minute.
First, let's find the volume of the pool. The pool is in the shape of a cylinder with a height of 4 feet and a diameter of 16 feet, so its radius is half of the diameter, or 8 feet. The volume of a cylinder is given by
V = πr^2h
Plugging in the values, we get
V = π(8 ft)^2(4 ft)
V = 256π cubic feet
Next, let's convert the flow rate to cubic feet per minute. One gallon is equal to 0.1337 cubic feet, so the flow rate is
30 gallons/min x 0.1337 ft^3/gallon = 4.011 ft^3/min
Finally, we can use the formula
time = volume/flow rate
Plugging in the values, we get
time = 256π ft^3 / 4.011 ft^3/min
time ≈ 63.7 minutes
So it will take about 63.7 minutes to fill the pool.
Let's use the formula for the volume of a cylinder again to relate the volume of the water in the pool to its depth
V = πr^2h
We can solve this formula for h
h = V/πr^2
Taking the derivative of both sides with respect to time, we get
dh/dt = d/dt (V/πr^2)
The radius of the pool does not change, so we can treat it as a constant and take it out of the derivative
dh/dt = (1/πr^2) dV/dt
We know the flow rate is constant at 4.011 cubic feet per minute, so the rate of change of the volume of water in the pool is
dV/dt = 4.011
Plugging in the values, we get
dh/dt = (1/π(8 ft)^2) (4.011 ft^3/min)
dh/dt ≈ 0.0079 ft/min
So the depth of the water is increasing at a rate of about 0.0079 feet per minute.
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Solve for x.
2x²8x+5=0
Enter your answers in the boxes.
x = |or x =
T
We can solve the quadratic equation 2x² - 8x + 5 = 0 by using the quadratic formula, which states that for an equation of the form ax² + bx + c = 0, the solutions are given by:
x = (-b ± sqrt(b² - 4ac)) / 2a
In this case, a = 2, b = -8, and c = 5. Substituting these values into the formula, we get:
x = (-(-8) ± sqrt((-8)² - 4(2)(5))) / (2(2))
x = (8 ± sqrt(64 - 40)) / 4
x = (8 ± sqrt(24)) / 4
x = (8 ± 2sqrt(6)) / 4
Simplifying the expression by factoring out a common factor of 2 in the numerator and denominator, we get:
x = (2(4 ± sqrt(6))) / (2(2))
x = 4 ± sqrt(6)
Therefore, the solutions to the equation 2x² - 8x + 5 = 0 are:
x = 4 + sqrt(6) or x = 4 - sqrt(6)
How many years would it take for the price of pizza’s ($8.00) to triple with a growth rate of 1.05? Explain how you found your answer.
It would take 1.53 years for the price of pizza to triple with a growth rate of 1.05.
Calculating the number of yearsTo find the number of years it takes for the price of pizza to triple with a growth rate of 1.05, we need to use the formula for exponential growth:
A = P(1 + r)^t
Where:
A = final amount (triple the original price, or 3*$8 = $24)
P = initial amount ($8)
r = growth rate (1.05)
t = time in years
Substituting the values into the formula, we get:
$24 = $8(1 + 1.05)^t
Simplifying:
3 = (1 + 1.05)^t
Taking the logarithm of both sides with base 10:
log(3) = t*log(1 + 1.05)
t = log(3) / log(1 + 1.05)
Using a calculator, we get:
t ≈ 1.53
Therefore, it would take approximately 1.53 years for the price of pizza to triple with a growth rate of 1.05.
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15 POINTS IM GOING TO BE BROKE AFTER THESE QUESTIONS
Two cars leave from the same location with one car traveling north and the other traveling west. When the northbound car has traveled 18 miles, the straight-line distance between the two cars is 30 miles. How far has the westbound car traveled?
We know that the westbound car has traveled 24 miles.
When the northbound car has traveled 18 miles and the straight-line distance between the two cars is 30 miles, you can use the Pythagorean theorem to determine the distance the westbound car has traveled. The theorem states that a² + b² = c², where a and b are the legs of a right triangle and c is the hypotenuse.
In this case, the northbound car's distance (18 miles) represents one leg (a) and the westbound car's distance represents the other leg (b). The straight-line distance between the cars (30 miles) represents the hypotenuse (c). The equation can be set up as follows:
18² + b² = 30²
Solving for b:
324 + b² = 900
b² = 900 - 324
b² = 576
b = √576
b = 24
So, the westbound car has traveled 24 miles.
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This data is an example of (?)
The given data is an example of a nonlinear function. Therefore, the answer is A.
The given data consists of two sets of numbers, X and Y, where each value of X has a corresponding value of Y. We can observe that the points do not lie on a straight line. Instead, the plotted points form a curved shape, which indicates that the relationship between X and Y is not a linear function.
A linear function is a function where the relationship between the input variable (X) and output variable (Y) is a straight line. In this case, we can observe that as the value of X increases, the value of Y increases at an increasing rate, which means the relationship between X and Y is not linear.
In particular, the relationship between X and Y is a quadratic function since the values of Y are the squares of the corresponding values of X.
Therefore, the answer is A.
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The Volume, V, in liters, of air in the lungs is approximated by the the model, V = -0.0374+3 +0.1525+2 +0.1729t, during a five second respiratory cycle. In here, t is measured in second
The model approximates the volume, V, in liters, of air in the lungs during a five-second respiratory cycle using the equation V = -0.0374t + 3 + 0.1525t^2 + 0.1729t.
The given equation represents a mathematical model for estimating the volume of air in the lungs during a respiratory cycle. It is a quadratic equation with three terms: -0.0374t, 0.1525t^2, and 0.1729t.
The term -0.0374t represents the linear decrease in volume over time, indicating that the volume decreases by 0.0374 liters for every second of the respiratory cycle.
The term 0.1525t^2 represents the quadratic relationship between volume and time squared, indicating that the rate of change of volume with respect to time is influenced by the square of time.
The term 0.1729t represents the linear increase in volume over time, indicating that the volume increases by 0.1729 liters for every second of the respiratory cycle.
Overall, this model provides an approximation of the volume of air in the lungs during a five-second respiratory cycle, taking into account both linear and quadratic relationships with time.
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Find the area of the composite figure.Round Your Answer To The Nearest Hundreth if needed
Answer:
[tex]A = 68.75 \text{ square inches}[/tex]
Step-by-step explanation:
First, we need to identify the trapezoid's dimensions:
base 1 = 16
base 2 = 11.5
height = 5
Then, we can plug these values into the trapezoid area formula:
[tex]A = \dfrac{b_1+b_2}{2} \cdot h[/tex]
[tex]A = \dfrac{16 + 11.5}{2} \cdot 5[/tex]
[tex]A = \dfrac{27.5}{2} \cdot 5[/tex]
[tex]A = \dfrac{137.5}{2}[/tex]
[tex]\boxed{A = 68.75 \text{ square inches}}[/tex]
At the beginning of the summer, the water level in an underground well was -3 feet. During the hot summer months, the water level fell 4 feet. The expression -3 -4 gives the water level in feet at the end of the summer.
What was the water level at the end of the summer?
Answer:
-7 feet
Step-by-step explanation:
-3-4 = -7, so it is -7 feet
Use the Evaluation Theorem to compute the following definite integrals: (a) e^3 - e (b) 0 (c) 295/6
To use the Evaluation Theorem to compute the definite integrals, follow these steps:
Step 1: Identify the function and the interval
In this case, we have three separate integrals to evaluate:
(a) ∫(e^3 - e) dx
(b) ∫0 dx
(c) ∫295/6 dx
Step 2: Find the antiderivative of the function
(a) The antiderivative of (e^3 - e) is (e^3x/3 - ex) + C.
(b) The antiderivative of 0 is simply C, where C is the constant of integration.
(c) The antiderivative of 295/6 is (295/6)x + C.
Step 3: Evaluate the antiderivative at the given interval
(a) Since no specific interval is given, we cannot evaluate the integral using the Evaluation Theorem.
(b) Since no specific interval is given, we cannot evaluate the integral using the Evaluation Theorem.
(c) Since no specific interval is given, we cannot evaluate the integral using the Evaluation Theorem.
What are definite Intregal's: Definite integral is the area under a curve between two fixed limits.we can say that the definite integral that represents the area of the surface generated by revolving the curve on the indicated interval about the x-axis. Unfortunately, without specific intervals, we cannot use the Evaluation Theorem to compute the definite integrals. Please provide the intervals for each integral, and we can help you compute them.
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Geometry question I need help with:
We denote triangle ABC, angle A measures 90°, angle B measures 30° and angle C measures 60°.
We apply the cosine of 30 degrees, becuase m(∡A) = 90° and find the hypotenuse of triangle ABC:
cos = (adjacent side) / (hypotenuse)
⇔ cos B = AB/BC ⇔
⇔ cos 30° = 8√3/v ⇔
⇔ √3/2 = 8√3/v ⇔
⇔ √3 • v = 2 • 8√3 ⇔
⇔ v√3 = 16√3 ⇔
⇔ v = 16√3 ÷ √3 ⇔
⇔ v = 16 millimeters
Hope that helps! Good luck! :)
Assinale a alternativa que melhor julga a sentença abaixo:
"as frações 3/9 e 7/18 são equivalentes, pois representam a mesma parte do todo"
( ) verdadeiro
( ) falso
ajuda pfvrrrrrrr
The statement is true as 3/9 and 7/18 represent the same part of the whole.
How to determine if the fractions 3/9 and 7/18 are equivalent?A sentença é falsa. As frações 3/9 e 7/18 não são equivalentes, pois não representam a mesma parte do todo. Para determinar se duas frações são equivalentes, é necessário simplificar as frações e verificar se os resultados são iguais.
No caso das frações 3/9 e 7/18, podemos simplificar ambas dividindo o numerador e o denominador pelo máximo divisor comum (MDC).
A fração 3/9 pode ser simplificada dividindo ambos por 3, resultando em 1/3. Já a fração 7/18 não pode ser simplificada ainda mais. Portanto, as frações 3/9 e 7/18 não são equivalentes, pois não representam a mesma parte do todo.
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Find the sum of the first 36 terms of the following series, to the nearest integer.
7,12,17....
To the nearest integer, the sum of the first 36 terms of the given series is 3,402.
Given series is 7, 12, 17,,,. we have to find the sum of the first 36 terms of the series.
We can observe that the series is an arithmetic sequence.
Here, [tex]a_{1}=7[/tex]
d = 12 - 7 = 5
and n = 36
We know that the formula for the nth term of A.P. is
[tex]a_{n}=a_{1}+(n-1)d[/tex]
[tex]a_{36}=7+(36-1)5[/tex]
= 7 + 35*5
= 7 + 175
[tex]a_{36}=182[/tex]
We know the sum of n terms in A.P. is
[tex]S_{n}=\frac{n}{2}(a_{n}+a_{1})[/tex]
[tex]S_{36}=\frac{36}{2}(7+182)[/tex]
= 18(189)
= 3,402
Hence, the sum of the first 36 terms of the given series is 3,402.
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Answer:
< 3 = 3x + 105°
Step-by-step explanation:
There is remot angle theory which is the exterior angle is congrent to the other non adjecent angle in triangle.
so <1 + <EDF = <3
(3x + 15 ) ° + 90° = <3
3x°+ 105° = <3
< 3 = 3x + 105° .... so the measur of angle 3 interms of x is 3x + 105°
Find ∫∫D 2xy dA, where D is the region between the circle of radius 2 and radius 5 centered at the origin that lies in the first quadrant. Find the exact value.
The exact value of the double integral ∫∫D 2xy dA is 0.
To evaluate the double integral ∫∫D 2xy dA, where D is the region between the circles of radius 2 and 5 centered at the origin that lies in the first quadrant, we need to use polar coordinates.
In polar coordinates, the region D is defined by 2 ≤ r ≤ 5 and 0 ≤ θ ≤ π/2. The double integral can be expressed as:
∫∫D 2xy dA = ∫θ=0^(π/2) ∫r=[tex]2^5 2r^3[/tex] cosθ sinθ dr dθ
Solving the inner integral with respect to r, we get:
∫r=[tex]2^5[/tex] 2[tex]r^3[/tex] cosθ sinθ dr = [r^4 cosθ sinθ]_r=[tex]2^5 = 5^4[/tex] cosθ sinθ - [tex]2^4[/tex] cosθ sinθ
Substituting this result into the double integral expression and solving the remaining integral with respect to θ, we get:
∫∫D 2xy dA = ∫θ=0^(π/2) (5^4 cosθ sinθ - 2^4 cosθ sinθ) dθ
= [5^4/2 sin(2θ) - 2^4/2 sin(2θ)]_θ=0^(π/2)
= (5^4/2 - 2^4/2) sin(π) - 0
= (5^4/2 - 2^4/2) * 0
= 0
Therefore, the exact value of the double integral ∫∫D 2xy dA is 0.
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More help please????
The value of sin(θ) = √15/4
The value of csc(θ) = [tex]\sqrt[4]{\frac{15}{15} }[/tex]
The value of sec(θ) = 4
The value tan(θ) = ±√15
The value of cot(θ) = ±√15/15
How to find the value using the trigonometric ratioWe can use the identity sec²(theta) - 1 = tan²(theta) to find the value of tan(theta).
Given sec(θ) = 4, we have:
sec²(θ) = 4² = 16
Then, using the identity:
tan²(θ) = sec²(θ) - 1 = 16 - 1 = 15
Taking the square root of both sides, we get:
tan(θ) = ±√(15)
Since sec(θ) is positive, we know that cos(theta), which is the reciprocal of sec(θ), is also positive. This tells us that θ is in the first or fourth quadrant, where sin(θ) is also positive.
Therefore:
sin(θ) = √(1 - cos²θ))
= √(1 - (1/16))
= √15/16)
= √(15))/4
Using the reciprocal identities, we can find the values of csc(θ) and cot(θ):
csc(θ) = 1/sin(θ)
= 4√(15)
[tex]\sqrt[4]{\frac{15}{15} }[/tex]
cot(θ)
= 1/tan(θ)
= ±√(15)/15
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Find the value(s) of k for which u(x.t) = e-³sin(kt) satisfies the equation Ut=4uxx
When k = 0, both sides of the equation equal 0:
3cos(0) = 4(0)sin(0)
3 = 0
There are no other values of k for which the equation holds true, the only value of k that satisfies the given equation is k = 0.
To find the value(s) of k for which u(x, t) = e^(-3)sin(kt) satisfies the equation Ut = 4Uxx, we first need to calculate the partial derivatives with respect to t and x.
[tex]Ut = ∂u/∂t = -3ke^(-3)cos(kt)Uxx = ∂²u/∂x² = -k^2e^(-3)sin(kt)[/tex]
Now, we will substitute Ut and Uxx into the given equation:
[tex]-3ke^(-3)cos(kt) = 4(-k^2e^(-3)sin(kt))[/tex]
Divide both sides by e^(-3):
[tex]-3kcos(kt) = -4k^2sin(kt)[/tex]
Since we want to find the value(s) of k, we can divide both sides by -k:
3cos(kt) = 4ksin(kt)
Now we need to find the k value that satisfies this equation. Notice that when k = 0, both sides of the equation equal 0:
3cos(0) = 4(0)sin(0)
3 = 0
Since there are no other values of k for which the equation holds true, the only value of k that satisfies the given equation is k = 0.
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The population of dolphins in the Gulf of Mexico has been decreasing at a rate of 4% every 10
years. In 2020 there were 4,670 dolphins. If things continue this way, how many dolphins will there
be in the year 2100?
The number of dolphins that will be there in the year 2100 is 1003, under the condition that in the Gulf of Mexico has been decreasing at a rate of 4% every 10
years.
Here the population of dolphins in the Gulf of Mexico in 2020 was 4,670.The rate of decrease is 4% every 10 years.
Therefore, the population would decrease by 4% every 10 years.
We want to evaluate the population in 2100, which is 80 years from now, which is eight 10-year periods.
Now, we have to calculate the population after eight 10-year periods.
Each period would decrease the population by 4%.
Hence, the population after eight periods is
4670 × (1 - 0.04)⁸
= 4670 × (0.96)⁸
= 1003
Then, if things progress like this, the population of dolphins in the Gulf of Mexico in the year 2100 will be close to 1000.
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