How far is the portion of her route from A to D? Round to the nearest whole number. Explain. I NEED IT BY TONIGHT SO PLSS SOMEONE HELP ME!
Answers
9514 1404 393
Answer:
A to D is about 2087 ft
Step-by-step explanation:
For the portion of the path of interest, the sine and cosine relations apply.
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
__
AB is the adjacent side to the angle marked 33°, with hypotenuse 975 ft.
cos(33°) = AB/(975 ft)
AB = (975 ft)cos(33°) ≈ 817.70 ft
BC is the opposite side in the same triangle.
sin(33°) = BC/(975 ft)
BC = (975 ft)sin(33°) ≈ 531.02 ft
CD is the hypotenuse of the right triangle BCD. The side BC that we know is opposite the given angle, so the sine relation applies.
sin(46°) = BC/CD
CD = BC/sin(46°)
CD = (531.02 ft)/sin(46°) ≈ 738.21 ft
__
Now we know the segments of the path of interest:
A–D = AB +BC +CD
A–D = 817.70 ft + 531.02 ft + 738.21 ft = 2086.93 ft
A–D ≈ 2087 ft
_____
Additional comments
The attachment shows all of the segments computed working counterclockwise from A. The angles in triangle DEF are computed using the Law of Sines from sides DF and DE and angle DEF. Segments EG and GH are computed using the Law of Cosines.
When we get to points F, G, H, we find that there is some inconsistency with the locations that would be computed working clockwise using AB and angle BFA. This inconsistency shows up in an error in the 119° angle in the attached figure.
This means that segments on the back side of the route, along path EFGHA, will vary somewhat depending on how they're computed.
We assume that points B, C, F, G are collinear.
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Answer: He completes 2 4/5 rows per hour
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We should divide the work completed by the amount of work done per hour.
So, 140/(2 4/5) =
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in 10 years time a father Will be twice as old as his daughter.10 years ago he was six time as old as his daughter.How old is each now
Answers
Answer:
Step-by-step explanation:
let fathers age now be x
daughters age now be y
10 years hence
(x+10)= 2(y+10)
x+10 = 2y+20
x-2y=10
10 years ago
(x-10)= 6(y-10)
x-10 = 6y-60
x-6y=-50
x-2y=10
x-6y=-50
subtract the equations
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substitute y in x-2y=10
so x=40 present father's age
pls mark brainliest
Answer:
Let the age 10 years ago of daughter be ( x years ) and age of father would be ( 6x years )
After 10 years, age of father = ( 6x + 10 + 10 )
= ( 6x + 20 ) years
And Age of daughter will be = ( x + 10 + 10 )
= ( x + 20 ) years
ATQ,
6x + 20 = 2( x + 20 )
=> 6x + 20 = 2x + 40
=> 6x - 2x = 40 - 20
=> 4x = 20
=> x = 5
Hence, Present age of daughter = ( x + 10 )
= ( 5 + 10 )
= 15 years
Present age of father = ( 6x + 10 )
= 6( 5 ) + 10
= 30 + 10
= 40 years
Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Answer
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25
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Money Raylin already has = $22
Money she needs :
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Answers
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Given data
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Help?
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This question will be graded by your teacher. *
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Vhur answer
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Answers
Answer:
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Find the simplest form
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Answers
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Step-by-step explanation:
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Step-by-step explanation:
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A.
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B.
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C.
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Answers
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We know that
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Answer:
i hope this helps
Step-by-step explanation:
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Step-by-step explanation:
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Answers
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Step-by-step explanation:
Because 9 is a rich numbers uwill borrow one to the other side so it will become 1.0000
Answer:
1 is round off of 0.9271to the nearest whole number.
Please help me with this
Answers
Answer:
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Step-by-step explanation:
Hi there!
To find the answer, use inverse operations to solve.
Multiply 7/15 by 3/7 to isolate the unknown number.
7/15 * 3/7 is equal to 0.2, which can be simplified into fraction form as 1/5.
I hope this helps!
:)
