hey guys please help me out with this...
god bless ty for all the help

Answer:  See below

Step-by-step explanation:

The basic form of an equation of a straight line in slope intercept form is y=mx+b, where m is the slope and b the y intercept (the value of y when x=0)

1) Slope = 8, y-intercept = 3

y=mx+b:  y = bx + 3

2) Slope= -2/3, y-intercept = 1

y=mx+b:  y = -(2/3)x + 1

Answer:

400x45.2=18080

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

[tex] \frac{70 - 35.24}{8.69} [/tex]

[tex] \frac{34.76}{8.69} [/tex]

[tex] = 4[/tex]

Answer:

( 3b + 5 )( b + 2 )

Step-by-step explanation:

3b^2 + 11b + 10

( 3b + 5 )( b + 2 )

Hopefully this helps!

Brainliest please?

Answer:

its 8.00

Step-by-step explanation:

Answer:

8.00

Step-by-step explanation:

Answer:

as following

Step-by-step explanation:

[tex](3y^3+5y^2-4y) (2y^2-6y-7) \\=y(3y^2+5y-4)(2y^2-6y-7)\\=y(6y^4-16y^3-21y^2+10y^3-30y^2-35y-8y^2+24y+28)\\=y(6y^4-6y^3-59y^2-11y+28)\\=6y^5-6y^4-59y^3-11y^2+28y[/tex]

Answer:

y = -x + 4

Step-by-step explanation:

y + 2 = -x - 1

y = - x - 1 - 2

y = -x - 3

Point: (-2,6)

Slope -1

y-intercept: 6 - (-1)(-2)

= 6- 2 = 4

The number of gallons it take to fill the tank is 3.625 gallon.

Given that, a 14.5-gallon gasoline tank is 3/4 full.

Let the number of gallons it take to fill the tank is x.

Now, the number of gallons of gasoline tank = 14.5×3/4

= 14.5×0.75

= 10.875

Here, 10.875+x=14.5

x=14.5-10.875

x=3.625

Therefore, the number of gallons it take to fill the tank is 3.625 gallon.

To learn more about the unitary method visit:

brainly.com/question/22056199.

#SPJ6

-2 ¼ + (5 ¾)= 5 ¾ -2 ¼

5-2= 3

3/4-1/4= 1/2

The solution is

e solution is3 and 1/2

Answer:

#8) y=2

#7) x=3

Hope helped

Answer: x = 560/3

Step-by-step explanation:

First! We are going to be using the PEMDAS method! If you have any questions about this method please go ahead and ask below! The first step in our equation is the P - parenthesis, so we are going to multiply [tex]\frac{3}{5}[/tex]  to everything inside of the parenthesis (x and -710)!

[tex]\frac{3}{5} (x -710) = -314[/tex]

[tex]\frac{3}{5}x+(\frac{3}{5}*-710)=-314[/tex]

[tex]\frac{3}{5}x -426 = -314[/tex]

Now, we are going to add 426 to both sides of the equation, to single out the "x" variable!

[tex]\frac{3}{5}x= 112[/tex]

Finally, let's multiply both sides by [tex]\frac{5}{3}[/tex] to cancel out the [tex]\frac{3}{5}[/tex] fractions, to get the "x" variable alone.

[tex]x=\frac{560}{3}[/tex]

↑This is our answer!

Hope this Helps! :)

Have any questions? Ask below in the comments and I will try my best to answer.

-SGO

Answer:

Step-by-step explanation:

what is the answer for a² – b² = (a-b)(a+b)

a² – b² = (a-b)(a+b)

a²- b² = a² - b²

this equation is always true

-----------------------------

check

a=1 and b=2

1²-2²=(1 - 2) * (1 + 2)

1 - 4 = 1 + (-4)

-3 = -3

Answers:

Part 1: 5

Part 2: 4/6 m

Part 3: [tex]5 \frac{1}{6}[/tex]

Part 4: 5

Part 5: 4/6 m

Step By Step Explanation:

math

Answer:

2989854

Step-by-step explanation:

Answer:

When you multiply two negatives, you get a positive solution.

7686x389

2,989,854

:)

Answer:

See below for answer.

Step-by-step explanation:

∠BCD is a right angle                           Given

∠ACB ≅∠CAD                                      Given

A is in the interior of ∠BCD                 Given

m ∠BCD =90°                                       Definition of right angle

m ∠ACD + m ∠ACD = m ∠BCD           Angle Addition Postulate

m ∠ACD + m ∠ACD = 90°                    Substitution

∠ACD is complementary to ∠ACD     Definition of complementary                                                                      

∠CAD is complementary to ∠ACD     If two angles are congruent, then their

                                                             complements are congruent.

Answer:

D

Step-by-step explanation:

Using the cosine ratio in the right triangle.

cos66° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{13}{x}[/tex] ( multiply both sides by x )

x × cos66° = 13 ( divide both sides by cos66° )

x = [tex]\frac{13}{cos66}[/tex] ≈ 32.0 ( to the nearest tenth )

Answer:

22

Step-by-step explanation:

2 + 3 + 8 + 1 + 9 + 10 - 11 +10 = ? can be evaluated from left to right, as follows:

   5    + 8 + 1 + 9 + 10 - 11 +10 = ?

          13 + 10 - 11 + 10, or

               23   - 11 + 10, or

                     12 + 10, or

                            22

Answer:

z= -1.178

Step-by-step explanation:

[tex]\frac{124-126}{\frac{7}{\sqrt{17} } }[/tex]

use technology to calculate.

if its correct please mark me brainliest, hope this helps!!!

From the hypothesis test, we have that:

At the null hypothesis, it is tested if her average is the same as the national of 514, hence:

[tex]H_0: \mu = 514[/tex]

At the alternative hypothesis, it is tested if it is different, hence:

[tex]H_1: \mu \neq 514[/tex]

A similar problem is given at https://brainly.com/question/24330815

Answer:

c

just took on edge

\

Step-by-step explanation:

Answer:

w = 63

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 interior angles.

w + 28 is an exterior angle of the triangle , then

w - 2 + w - 33 = w + 28 , that is

2w - 35 = w + 28 ( subtract w from both sides )

w - 35 = 28 ( add 35 to both sides )

w = 63

Answer:

x = 6 ± [tex]\sqrt{2}[/tex]

Step-by-step explanation:

To find the zeros equate f(x) to zero , that is

2(x - 6)² - 4 = 0 ( add 4 to both sides )

2(x - 6)² = 4 ( divide both sides by 2 )

(x - 6)² = 2 ( take square root of both sides )

x - 6 = ± [tex]\sqrt{2}[/tex] ( add 6 to both sides )

x = 6 ± [tex]\sqrt{2}[/tex]

The zeros are x = 6 - [tex]\sqrt{2}[/tex] , x = 6 + [tex]\sqrt{2}[/tex]

Answer:

Billy found the ring at -20 ft

Step-by-step explanation:

He started at 15 ft

He dove off the cliff, then swam 5 feet under the opposite of the cliff's elevation

The opposite of the cliff's elevation would be -15, and if he swam five feet under that, it would be -15 + -5 = -20

So, Billy found the ring at -20 ft

Rewrite the limand as

[tex]\dfrac{\tan^2(x)}{1 - \cos(x)} = \dfrac{\sin^2(x)}{\cos^2(x)(1 - \cos(x))}[/tex]

Multiply the numerator and denominator by 1 + cos(x). Then

[tex]\dfrac{\sin^2(x)}{\cos^2(x)(1 - \cos(x))} \cdot \dfrac{1+\cos(x)}{1+\cos(x)} = \dfrac{\sin^2(x)(1 + \cos(x))}{\cos^2(x)(1 - \cos^2(x))} \\\\= \dfrac{\sin^2(x)(1 + \cos(x))}{\cos^2(x)\sin^2(x)} \\\\ = \dfrac{1 + \cos(x)}{\cos^2(x)}[/tex]

As x goes to 0, the limand goes to (1 + 1)/1² = 2.

We are given with a limit :-

[tex]{\quad \blacktriangleright \blacktriangleright \blacktriangleright {\displaystyle \sf \lim_{x\to 0}\dfrac{\tan^{2}(x)}{1-\cos (x)}}}[/tex]

We know that ;

Using this , the above limit can be written as ;

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 0}\dfrac{\sin^{2}(x)}{\cos^{2}(x)\{1-\cos (x)\}}}[/tex]

Multiplying and dividing both numerator and denominator by [tex]{\sf 1+\cos (x)}[/tex]

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 0}\dfrac{\sin^{2}(x)\{1+\cos (x)\}}{\cos^{2}(x)\{1-\cos (x)\}\{1+\cos (x)\}}}[/tex]

We knows a identity that is

Using this we have ;

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 0}\dfrac{\sin^{2}(x)\{1+\cos (x)\}}{\cos^{2}(x)\{1-\cos^{2}(x)\}}}[/tex]

We knows another Trigonometric identity i.e ;

Now , using this we have ;

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 0}\dfrac{\cancel{\sin^{2}(x)}\{1+\cos (x)\}}{\cos^{2}(x)\cancel{\sin^{2}(x)}}}[/tex]

[tex]{:\implies \quad \displaystyle \sf \lim_{x\to 0}\dfrac{1+\cos (x)}{\cos^{2}(x)}}[/tex]

Putting the limit we have ;

[tex]{:\implies \quad \displaystyle \sf \dfrac{1+\cos (0)}{\cos^{2}(0)}}[/tex]

[tex]{:\implies \quad \displaystyle \sf \dfrac{1+1}{1^{2}} \quad \qquad \{\because \cos (0)=1\}}[/tex]

[tex]{:\implies \quad \displaystyle \sf \dfrac{2}{1}}[/tex]

[tex]{:\implies \quad {\displaystyle \therefore \quad \bf \underline{\underline{\lim_{x\to 0}\dfrac{\tan^{2}(x)}{1-\cos (x)}=2}}}}[/tex]

It would be (4, -5)

Hope this helps!