hence of other wise find the radius of a circle when A= 88/63 leave your answer as a fraction in its simplest form

Answer:

the Answers are : B and E

Step-by-step explanation:

From the given quadratic equation [tex]x^2 + 10x + 25 = 7[/tex] Thus, the solution is x = -1 and -9.

Suppose that the given quadratic equation is

[tex]ax^2 + bx + c = 0[/tex]

Then its roots are given as:

[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

We have been given a quadratic equation

[tex]x^2 + 10x + 25 = 7[/tex]

[tex]x^2 + 10x + 25 - 7=0\\\\x^2 + 10x + 18[/tex]

The solution of the given equation;

[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\x = \dfrac{-10 \pm \sqrt{10^2 - 4\times 18}}{2}\\\\x = \dfrac{-10 \pm \sqrt{100- 36}}{2}\\\\x = \dfrac{-10 \pm \sqrt{64}}{2}\\\\x = \dfrac{-10 \pm 8}{2}\\[/tex]

Therefore, the solution are x = -1 and -9.

Learn more about finding the solutions of a quadratic equation here:

https://brainly.com/question/3358603

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Answer:

(a) The probability that all five have used a computer while under the influence of alcohol is 0.0021.

(b) The probability that at least one has not used a computer while under the influence of alcohol is 0.9979.

(c) The probability that none of the five have used a computer while under the influence of alcohol is 0.1804.

(d) The probability that at least one has used a computer while under the influence of alcohol is 0.8196.

Step-by-step explanation:

We are given that among 25- to 30-year-olds, 29% say they have used a computer while under the influence of alcohol.

Suppose five 25- to 30-year-olds are selected at random.

The above situation can be represented through the binomial distribution;

[tex]P(X = x) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.........[/tex]

where, n = number of trials (samples) taken = Five 25- to 30-year-olds

            r = number of success

            p = probability of success which in our question is probability that

                  people used a computer while under the influence of alcohol,

                   i.e. p = 29%.

Let X = Number of people who used computer while under the influence of alcohol.

So, X ~ Binom(n = 5, p = 0.29)

(a) The probability that all five have used a computer while under the influence of alcohol is given by = P(X = 5)

               P(X = 5)  =  [tex]\binom{5}{5}\times 0.29^{5} \times (1-0.29)^{5-5}[/tex]

                              =  [tex]1 \times 0.29^{5} \times 0.71^{0}[/tex]

                              =  0.0021

(b) The probability that at least one has not used a computer while under the influence of alcohol is given by = P(X [tex]\geq[/tex] 1)

Here, the probability of success (p) will change because now the success for us is that people have not used a computer while under the influence of alcohol = 1 - 0.29 = 0.71

SO, now X ~ Binom(n = 5, p = 0.71)

               P(X [tex]\geq[/tex] 1)  =  1 - P(X = 0)   

                              =  [tex]1-\binom{5}{0}\times 0.71^{0} \times (1-0.71)^{5-0}[/tex]

                              =  [tex]1 -(1 \times 1 \times 0.29^{5})[/tex]

                              =  1 - 0.0021 = 0.9979.

(c) The probability that none of the five have used a computer while under the influence of alcohol is given by = P(X = 0)

               P(X = 0)  =  [tex]\binom{5}{0}\times 0.29^{0} \times (1-0.29)^{5-0}[/tex]

                              =  [tex]1 \times 1 \times 0.71^{5}[/tex]

                              =  0.1804

(d) The probability that at least one has used a computer while under the influence of alcohol is given by = P(X [tex]\geq[/tex] 1)

               P(X [tex]\geq[/tex] 1)  =  1 - P(X = 0)   

                              =  [tex]1-\binom{5}{0}\times 0.29^{0} \times (1-0.29)^{5-0}[/tex]

                              =  [tex]1 -(1 \times 1 \times 0.71^{5})[/tex]

                              =  1 - 0.1804 = 0.8196

Answer:

x>−6 and x<7

Step-by-step explanation:

Let's solve your inequality step-by-step.

|−2x+1|<13

Solve Absolute Value.

|−2x+1|<13

We know−2x+1<13and−2x+1>−13

−2x+1<13(Condition 1)

−2x+1−1<13−1(Subtract 1 from both sides)

−2x<12

−2x

−2

<

12

−2

(Divide both sides by -2)

x>−6

−2x+1>−13(Condition 2)

−2x+1−1>−13−1(Subtract 1 from both sides)

−2x>−14

−2x

−2

>

−14

−2

(Divide both sides by -2)

x<7

Answer:

x>−6 and x<7

Answer: Y=3x -7

Y=x-1

X=Y=

Step-by-step explanation:

Answer:

The solution is [tex]\:\left(-\frac{17}{10},\:-\frac{1}{10}\right)[/tex].

Step-by-step explanation:

An inequality is a mathematical relationship between two expressions and is represented using one of the following:

To find the solution of the inequality [tex]0>\:20x+2>\:-32[/tex] you must:

[tex]\mathrm{If}\:a>u>b\:\mathrm{then}\:a>u\quad \mathrm{and}\quad \:u>b\\\\0>20x+2\quad \mathrm{and}\quad \:20x+2>-32[/tex]

First, solve [tex]0>20x+2[/tex]

[tex]\mathrm{Switch\:sides}\\\\20x+2<0\\\\\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}\\\\20x+2-2<0-2\\\\\mathrm{Simplify}\\\\20x<-2\\\\\mathrm{Divide\:both\:sides\:by\:}20\\\\\frac{20x}{20}<\frac{-2}{20}\\\\\mathrm{Simplify}\\\\x<-\frac{1}{10}[/tex]

Next, solve [tex]20x+2>-32[/tex]

[tex]20x+2-2>-32-2\\\\20x>-34\\\\\frac{20x}{20}>\frac{-34}{20}\\\\x>-\frac{17}{10}[/tex]

Finally, combine the intervals

[tex]x<-\frac{1}{10}\quad \mathrm{and}\quad \:x>-\frac{17}{10}\\\\-\frac{17}{10}<x<-\frac{1}{10}[/tex]

The interval notation is [tex]\:\left(-\frac{17}{10},\:-\frac{1}{10}\right)[/tex] and the graph is:

Answer:

 3x ≤ -6

Step-by-step explanation:

"At most" means "less than or equal to." If x represents the number, then you have ...

  (three) times (a number) (is at most) negative 6 . . . . . English

      3       ·         x                ≤           -6 . . . . . . . . . . . . . . . . Math

__

  3x ≤ -6

Answer:

3x ≤ -6

Step-by-step explanation:

Answer:

  A.  6.67 in

Step-by-step explanation:

  length/width = 4/3 = x/5

Multiply by 5:

  5(4/3) = x = 20/3 = 6 2/3

The length of the chalkboard is 6.67 inches.

Answer:

I made is clear for you, now you may match each one

Step-by-step explanation:

f(1)= 11, f(n)= 3*f(n-1)

⊕ middle

f(1)= -18, f(n)= f(n-1)+21

f(1)= -18, f(n)= f(n-1) + 22

f(1)= -18, f(n)= 2*f(n-1)

⊕ bottom

f(1)= -18, f(n)= 6*f(n-1)

⊕ top

f(1)= 11, f(n)= f(n-1) + 22

Answer:

Fastest wind speed ever recorded

That is, however, a patch on the top speed ever reached by an aircraft, a record held by the Lockheed Blackbird, which tickled 2,193mph in 1976

Step-by-step explanation:

The puzzle are: 21, 30, 15, 333.

Clock:

Clock time=9 o'clock+9 o'clock+3 o'clock

Clock time=21

Calculator:

Calculator 1=1+2+3+4=10

Calculator 2=1+2+3+4=10

Calculator 3=1+2+3+4=10

Calculator=10+10+10

Calculator=30

Bulb:

The 3 bulb has 5 light each which represent the brightness of the 3 bulb.

Bulb=15+(15-15)

Bulb =15+0

Bulb=15

Fourth puzzle

Clock+Calculator×Bulb

9 o'clock+(1+2+2+4)× [3 bulb(3 bulb×4 light)]

9+9×(3×12)

Apply BODMAS

9+9×36

9+324

=333

Inconclusion the puzzle are: 21, 30, 15, 333.

Learn more about puzzle here:https://brainly.com/question/16999211

Answer:

csc ø = 5/3 ; sec ø = 5/4

Step-by-step explanation:

cot ø = adj/opp

adj = 4

opp = 3

after that, we must find the hypotenuse by using phytagoras theorem

hpy² = adj² + opp²

hpy² = 4² + 3²

hpy² = 25

hpy = 5

now let's find the other

csc ø (not scs) = hyp/opp = 5/3

sec ø = hyp/adj = 5/4

Answer:

The Answer is : 9(x2 + 6x + 9) = 103

Step-by-step explanation:

Option D on edge2020 i got a 100 on the quiz

The resulting quadratic equation is [tex](x+3)^2-103/9=0[/tex]

Given the quadratic equation [tex]9x^2 + 49x = 22 - 5x[/tex]

Write in standard form:

[tex]9x^2 + 49x = 22 - 5x\\ 9x^2 + 49x + 5x -22= 0\\ 9x^2+54x-22=0[/tex]

Divide through by 9

[tex]x^2+6x-22/9=0\\ [/tex]

complete the square to have:

[tex]x^2+6x-22/9+3^2-3^2=0\\ x^2+6x+3^2-9-22/9 = 0\\ (x+3)^2-103/9=0[/tex]

Hence the resulting quadratic equation is [tex](x+3)^2-103/9=0[/tex]

Learn more on completing the square here: https://brainly.com/question/1596209

Answer:

A

Step-by-step explanation:

We can see that Function A's y coordinate doubles every time. The function A = f(x) = 5(2)^x. It is an exponential growth function, and therefore y can never be 0. This means that A does not have an x-intercept.

Function B is a rational function. x cannot be 0, since that would result in an undefined number. This also means that B does not have an x-intercept.

Answer:

y = [tex]y_{1}[/tex] + rise * 2/5

Step-by-step explanation:

Answer:

1.2 km

Step-by-step explanation:

The first thing that we should go over is the formula for the area of a trapezoid.

Recall that it is [tex]A= \frac{b_1 +b_2}{2} *h[/tex]

From this image, we have the following information

[tex]b_1=2.5\\\\b_2=1.5\\\\A=2.4[/tex]

Now, we can plug this information into our formula and then solve for h.

[tex]2.4=\frac{2.5+1.5}{2} *h\\\\2.4=\frac{4}{2} *h\\\\2.4=2h\\\\h=1.2[/tex]

Another method that can be employed is to use the pythagorean theorem.

A trapezoid can be be broken into a rectangle and two triangles.

If we look at the difference in the sizes of the bases, the bottom base is 1 km larger. This means that the base of each triangle would be 0.5 km long.

As we have two side lengths of the triangle, we can now use the Pythagorean theorem to find the third side, which is h.

[tex](1.3)^2=h^2+(0.5)^2\\\\h^2=1.69-0.25\\\\h=\sqrt{1.44} \\\\h=1.2[/tex]

Answer:

h=1.2 km

Step-by-step explanation:

This is the formula of a Trapezium

A=[tex]\frac{h(a+b)}{2}[/tex]

[tex]2.4=\frac{(2.5+1.5)h}{2}\\ 2.4=\frac{4h}{2}\\ 2.4*2=4h\\4.8=4h\\h=1.2[/tex]

Answer:

[tex]Perimeter\ of\ the\ Garden\ =2(l1*b1)[/tex]

[tex]Area\ of\ the\ garden\ =l1*b1[/tex]

Step-by-step explanation:

Let assume the l1 is the length of the garden and b1 is the breadth of garden then

[tex]Perimeter\ of\ the\ Garden\ = 2 ( L ength + Breadth )\\Perimeter\ of\ the\ Garden\ =2(l1*b1)[/tex]

Now,

[tex]Area\ of\ Garden\ = Length * Breadth[/tex]

[tex]Area\ of\ the\ garden\ =l1*b1[/tex]

Answer:

Ok, for f(x) = x^2 we have only one x-intercept (actually, two equal x-intercepts) at x = 0.

Now, for g(x) = (x - 2)^2 - 3

First, let's analyze the transformations.

When we have g(x) = f(x - a) this means that we moved "a" units to the right (if a is positive)

When we have g(x) = f(x) + a, this means that (if a > 0) we move the graph "a" units up.

In this case we have both those transformations:

g(x) = f(x - 2) - 3

this means that we move 2 units to the right, and 3 units down (because the number is negative)

now we can find the roots of g(x) as:

g(x) = (x - 2)^2 - 3 = x^2 - 4x  + 4 - 3 = x^2 - 4x + 1 = 0

using the Bhaskara's equation:

[tex]x = \frac{4 +-\sqrt{4^2 - 4*1*1} }{2*1} = \frac{4 +- 3.5}{2}[/tex]

then the roots are:

x = (4 + 3.5)/2 = 3.75

x = (4 - 3.5)/2 = 0.25

Here we have two different x-intercepts

Answer:

8

Step-by-step explanation:

The other patterns go with the two factors on top (2 x 3 = 6 and 3 x 3 = 9).

So, 2 x 4 = 8

Answer: [tex]y = 121[/tex]

[tex](y+57) = 178[/tex]

[tex]y+57= 178[/tex]

[tex]y = 178 -57[/tex]

[tex]y = 121[/tex]

d-Denis

e-Earl

d+e=42

e+8=d

e+8+e=42

2e+8=42

2e=34

e=17

d=17+8=25

Denis is 25 and Earl is 17

Answer

Earl is 17 years old.

Denis is 25 years old.

See? Easy!

Step-by-step explanation:

Step-by-step explanation:

9 + 1/6 + 2 1/12

9 + 2.25

11.25

Answer:

8.55 days for a decay rate parameter of 8.1% per day

Step-by-step explanation:

Assuming a decay rate parameter of  8.1% per day

the general equation for radioactive decay is;

N = N₀e^(-λt)

x - decay constant (λ) - rate of decay 

t-  time 

N - amount remaining after t days , since we are calculating the half life, amount of time it takes for the substance to to be half its original value, its N₀/2

N₀ - amount initially present 

substituting the values 

N₀/2 = N₀e^(-0.081t)

0.5 = e^(-0.081t)

ln (0.5) = -0.081t

-0.693 = -0.081t

t = 0.693 / 0.081  = 8.55

half life of substance is 8.55 days 

Answer:

nickels- 5, quarters- 11

Step-by-step explanation:

nickel= 5 p,  quarter= 25 p

5x+25(x+6)= 300

30x+150=300

30x=150

x=150/30

x=5 nickels

x+6= 11 quarters

Answer:

299.97 is the actual answer

Step-by-step explanation:

I took the test.

Answer:

a)0.2240

b)0.5768

Step-by-step explanation:

Given:

µ=3

Poison probability is given by :

[tex]f_k=\frac{\mu^ke^-^\mu}{k!}[/tex]

a) Evaluating at k=3

[tex]f(3)=\frac{3^3e^-^3}{3!} \approx 0.2240[/tex]

b)Evaluating at k=0,1,2:

[tex]f(0)=\frac{3^0e^-^3}{0!} \approx 0.0498[/tex]

[tex]f(1)=\frac{3^1e^-^3}{1!} \approx 0.1494[/tex]

[tex]f(2)=\frac{3^2e^-^3}{2!} \approx 0.2240[/tex]

Use complement rule:

P(x≥3)= 1 - f(0) - f(1) - f(2)= 1- 0.0498 - 0.1494 - 0.2240 =0.5768

Answer:

z(65) = (65-64.2)/[2.81/sqrt(60)] = 0.8/(0.3279)

Step-by-step explanation:

Using the normal probability distribution and the central limit theorem, it is found that there is a 0.0154 = 1.54% probability that the mean height for the sample is greater than 65 ​inches.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem:

The probability that the mean height for the sample is greater than 65 ​inches is 1 subtracted by the p-value of Z when X = 65, thus:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]Z = \frac{65 - 64.3}{\frac{2.81}{\sqrt{75}}}[/tex]

[tex]Z = 2.16[/tex]

[tex]Z = 2.16[/tex] has a p-value of 0.9846.

1 - 0.9846 = 0.0154

0.0154 = 1.54% probability that the mean height for the sample is greater than 65 ​inches.

A similar problem is given at https://brainly.com/question/24663213

Hey there! Welcome to Brainly! I"m happy to help!

The unit rate is how much there is of something per  one unit. The word per basically means divided or a fraction. So, if something was a, the unit rate would be a/1.

Therefore, the unit rate is C) a rate with one in the denominator.

I hope that this helps! Have a wonderful day!

Answer:

[tex]the \: answer \: is \: d.(x + 4) {}^{2} = 8(y + 4)[/tex]