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Answer:

89

Step-by-step explanation:

so u have 5 miles in 45 mins so u do 45 x 2 then u get 89 minutes

Answer:

Stephanie can run 5 miles in

= 45 minutes

She can run 1 mile in

= 45/5

= 9 minutes

So, she can run 10 miles in

= 10×9

= 90 minutes or 1 hr 30 minutes

(a) There are 2 sequences of length 1 that fit the bill: 0 and 1. So if [tex]b_n[/tex] is the number of permissible sequences, then [tex]b_1=2[/tex].

To the sequence 0, we can attach either 0 or 1 at the end, while the sequence 1 must be followed by 0. Then the permissible sequences of length 2 are 00, 01, and 10, so [tex]b_2=3[/tex].

Now consider a sequence of length n + 1, of which there are [tex]b_{n+1}[/tex].

• If the last digit is 0, then we got this sequence by simply joining 0 to one of [tex]b_n[/tex] sequences. In other words, there are [tex]b_n[/tex] permissible sequences of length n + 1 that end in 0.

• If the last digit is 1, then the previous digit must have been 0. Put another way, we join 01 to a permissible sequence of length n - 1 (there are [tex]b_{n-1}[/tex] of them). So there are [tex]b_{n-1}[/tex] permissible sequences of length n + 1 that end in 1.

These cases are mutually exclusive, so the number of (n + 1)-length permissible sequences is given by

[tex]\begin{cases}b_1 = 2 \\ b_2 = 3 \\ b_{n+1} = b_n + b_{n-2} & \text{for }n\ge2\end{cases}[/tex]

(b) The reasoning for a permissible ternary sequence is similar. Let [tex]t_n[/tex] be the number of sequences of length n not containing 11.

We first note that [tex]t_1 = 3[/tex], since we can have 0, 1, or 2; and [tex]t_2 =  8[/tex], since we can have 00, 01, 02, 10, 12, 20, 21, or 22.

Consider a sequence of length n + 1 ([tex]t_{n+1}[/tex] of these).

• If the last digit is 0, then we joined 0 to a permissible sequence of length n. So there are [tex]t_n[/tex] permissible sequences of length n + 1 ending in 0.

• If the last digit is 1, then the last two digits must be either 01 or 21. Since there are 2 choices for the n-th digit, there are [tex]2t_{n-1}[/tex] permissible sequences of length n + 1 ending in 1.

• If the last digit is 2, then we essentially have the same situation as if the sequence ended in 0, so there are [tex]t_n[/tex] sequences of length n + 1 ending in 2.

Then the recurrence for ternary permissible sequences is

[tex]\begin{cases}t_1 = 3 \\ t_2 = 8 \\ t_{n+1} = 2t_n + 2t_{n-1} & \text{for }n\ge2\end{cases}[/tex]

a.

The number of outlets​ in 2007 are 1008 outlets

Since  the number of outlets​ A(t) at these alternative fueling stations t years after 2005 is [tex]A(t) = 233(2.08)^{t}[/tex] with t = 0 corresponding to 2005.

To find the number of outlets in 2007, we substitute t = 2 into the equation.

So,

[tex]A(t) = 233(2.08)^{t}\\A(2) = 233(2.08)^{2}\\A(2) = 233(4.3264)\\A(2) =1008.0512[/tex]

A(2) ≅ 1008 outlets (we round down to the nearest whole number since we can only have a whole number of outlets).

So, the number of outlets​ in 2007 are 1008 outlets

b.

The number of outlets in 2009 are 4361 outlets

To find the number of outlets in 2009, we substitute t = 4 into the equation.

So,

[tex]A(t) = 233(2.08)^{t}\\A(4) = 233(2.08)^{4}\\A(4) = 233(18.72)\\A(4) =4361.23[/tex]

A(4) ≅ 4361 outlets (we round down to the nearest whole number since we can only have a whole number of outlets).

So, the number of outlets in 2009 are 4361 outlets

c.

The number of outlets in 2010 are 9071 outlets

To find the number of outlets in 2010, we substitute t = 5 into the equation.

So,

[tex]A(t) = 233(2.08)^{t}\\A(5) = 233(2.08)^{5}\\A(5) = 233(38.93)\\A(5) = 9071.36[/tex]

A(5) ≅ 9071 outlets (we round down to the nearest whole number since we can only have a whole number of outlets).

So, the number of outlets in 2010 are 9071 outlets

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Answer:

35%

Step-by-step explanation:

21/60*100 =2100/60 it is equal to 35%

to calculate percent it is number over total answer multiplied by hundred

brainiest, please

Answer:

30 / 23

Step-by-step explanation:

to divide two fractions, multiply by the reciprocal.

The reciprocal of 1/5 is 5/1. We will rewrite the equation as:

[tex]\frac{6}{23}[/tex] times [tex]\frac{5}{1}[/tex]

6 x 5 = 30

23 x 1 = 23

the answer is 30 / 23

The Quotient is 30/23.

One of the four fundamental mathematical operations, along with addition, subtraction, and multiplication, is division. Division is the process of dividing a larger group into smaller groups so that each group contains an equal number of things.

Given:

6/23 divided by 1/5

As, division is not possible in fraction so we will perform the multiplication

= 6/23 ÷ 1/5

= 6/23 x 5

= 30/ 23

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#SPJ5

Answer:

Step-by-step explanation:

Given:

Use the given formula and find d:

Answer:

im not sure sorry

Step-by-step explanation:

Answer:

The error she made was multiplyng by 7. This would affect her calculations as 7 in percentage form is represented as 700%. The 700% interest would basically mean she owes 7 times the amount she borrowed. The correct number would be 0.07 because 0.07 represents 7% which is the interest. Another error that was made was multiplying 2 to the entire equation. The only thing that needs to be doubled is the interest as every year the interest takes 7%. The correct way would be to put 0.07*2 in paranthesis. The correct equation is

I = 600(0.07*2)

Answer: 8 days your welcome (:

Answer:

8 days

1day = $8.08

$8.08 * 8 = $64.64 so this is wrong.

$260/$8.08= about 31 days.

Answer:

x = 100

Step-by-step explanation:

[tex]\frac{x}{5}=20[/tex]

[tex]5*\frac{x}{5} =20*5[/tex]

x = 20 * 5

x = 100

Hope This Helps

Answer:

63

Step-by-step explanation:

27/6=4.5

14*4.5=63

Explanation:

The n is a placeholder for a number. Writing 2n means we multiply by 2.

For example, if Irene is n = 20 years old, then Tom is 2n = 2*20 = 40 years old.

Answer:

C = (A*P - 8.4Y -330T + 200I) / 100

Step-by-step explanation:

P = (8.4Y + 330T + 100C -200I ) / A

now we have to calculate completed passes C for given P, Y, T, I, A

A*P = 8.4Y + 330T -200I +100C

100C = A*P - 8.4Y - 330T + 200I

C = (A*P - 8.4Y -330T + 200I) / 100

I just solved the equation for C

Answer:

i need points and this is a long question from before

thanks for the points

Step-by-step explanation:

Answer:

42%

Step-by-step explanation:

26 - 15 = 11

Take your decrease and divide it by the original price:

11/26 = 0.4230

Multiply 0.4230 by 100 to find the percent:

42.3

Round your answer and you would get -

42%

Answer:

42%

Step-by-step explanation:

You divide 15 by 26 and get 0.5769 and it continues with other numbers. to the nearest percent is 58. Then you subtract it from 100 and get 42%.

Answer:

$8.91

Step-by-step explanation:

Multiply $4.95 times 0.80 ( convert 80% to a decimal ) and that will equal 3.96 .

Then , since you're marking it up , you're gonna add the 3.96 to 4.95 which will equal $8.91 .

:)

Answer:

32,020

Explanatiojn:

Answer:

22

Step-by-step explanation:

Answer:

Graph.

y=x+6y=x+17

Step-by-step explanation:

Answer:

A. 6 percent of 600 is 360.

Step-by-step explanation:

Multilply 6 x 600 =36

Answer:

A.The sales tax on a $600 phone is $36.

Step-by-step explanation:

$600 * 0.06= 636

Answer:

A = 22

B = 19

Explanation:

Numbers one and two will be a variable A and B respectively.

A + B = 41 Equation one

A + B = 5 Equation two

Isolate one of the variables. Let's use A

A + B = 41 = A = 41 - B

Now replace the A in Equation two.

(41 - B) - B = 5

Simplify: 41 - 2B = 5

Isolate variable: 38 = 2B --> B = 19

Use the value of B to find A

A = 41 - B = 41 - 19 = 22

So the answer is A = 22 and B =19

Answer:

Step-by-step explanation:

Given equation:

Complete square as follows:

Step-by-step explanation:

We need to solve the equation using completing the square method .

=> x² - 2x - 31 = 0

=> x² -2*1*x + 1² - 1² - 31 = 0

=> ( x -1)² - 32 = 0

=> (x+1)² = 32

=> x +1 = ±√32

=> x = ±4√2 - 1

We want to find the unit rate of the bottles of water given that we know that the cost of 12 bottles is $10.32, we will find that the unit rate is:

r = 1.16 (bottles/$)

The unit rate is defined as the rate of change per unit, in this particular case, the unit rate would be the cost of every single bottle of water.

Here, we do know that for $10.32, you get 12 bottles.

The unit rate is just given by the quotient between these two values:

(12 bottles)/($10.32) = 1.16 (bottles/$)

Meaning that the cost of every single bottle is $1.16

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Dividing the ratio of red and blue cars:

96 /24 = 4

There are 4 times as many blue cars as red cars.

Multiply the number of red cars by the scale factor:

96 red x 4 = 384 blue cars

Answer:

384 blue cars

Step-by-step explanation:

Here's how I do all of this in my head:

Divide 96 by 24:

96 ÷ 24 = 4

Now that we know that the number we need is 4, all we have to do is multiply both factors by 4.

96 × 4 = 384

24 × 4 = 96 (which is the number we're looking for)

So now that we have 96 red cars, we can see that there's 384 blue cars, which will be your answer.

I hope I helped, and a Branliest is always appreciated! ☺

Answer:

The answer is 6.5

Step-by-step explanation:

Answer:

dddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd

Step-by-step explanation:

Answer:

....................

Answer:

D. y = −x2 − 4x + 1

Step-by-step explanation:

Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Down

Vertex:  ( − 2 ,  5 )

Focus:  ( − 2 ,  19 /4 )

Axis of Symmetry:  x= − 2

Directrix:  y = 21 /4

x                     y

− 4                   1

− 3                   4

− 2                   5

− 1                    4

0                     1

The joint distribution of the numbers of the three colours in the sample without replacement is:

[tex]\mathbf{P(A=a,B=b,C=c) = \dfrac{\Big( ^{p}_{ A} \Big) \Big( ^{q}_{ B} \Big) \Big( ^{r}_{ C} \Big) }{ \mathbf{\Big( ^{p+q+r}_{ \ \ \ n} \Big) } }\ \ \ \ where; n = A+B+C}[/tex]

Let consider A, B, and C to denote the three variables that are black, white, and red balls in the sample.

i.e.

Now, the numbers of ways 'n' balls are chosen without replacement in an urn that comprises of p black balls, q white balls, and r red balls can be computed as follows:

[tex]\mathbf{\implies \Big( ^{p+q+r}_{ \ \ \ n} \Big) }[/tex]

Now, the number of ways whereby A black balls can be chosen from p black balls is expressed as:

[tex]\mathbf{\implies \Big( ^{p}_{ A} \Big) }[/tex]

The number of ways whereby B white balls can be chosen from q white balls is expressed as:

[tex]\mathbf{\implies \Big( ^{q}_{ B} \Big) }[/tex]

The number of ways whereby C red balls can be chosen from r red balls is expressed as:

[tex]\mathbf{\implies \Big( ^{r}_{ C} \Big) }[/tex]

Therefore, we can conclude that the joint distribution of the numbers of the three colours in the sample without replacement is:

[tex]\mathbf{P(A=a,B=b,C=c) = \dfrac{\Big( ^{p}_{ A} \Big) \Big( ^{q}_{ B} \Big) \Big( ^{r}_{ C} \Big) }{ \mathbf{\Big( ^{p+q+r}_{ \ \ \ n} \Big) } }\ \ \ \ where; n = A+B+C}[/tex]

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Given that a survey asked the question, "Do you think a vaccination should be mandatory to enter shopping areas?" to a random sample of 1068 Jordanians, and the results showed that 71.2% responded that vaccination should mandatory, to determine which of the following is an observation, a variable, a sample statistic (value calculated based on the observed sample), or a population parameter, the following statistical reasoning must be performed:

(a) A Jordanian that was asked the question.

-An observation, as the person questioned is part of the study and therefore, it is an individual observation that makes up the trend.

(b) The response of the Jordanian.

-A variable, since it is one of the two possible answers that the survey has.

(c) 71.2%.

-A population parameter, because it represents a specific percentage with respect to the total population.

(d) The percentage of all Jordanians who agreed with the statement that vaccination should be mandatory to enter shopping areas.

-A sample statistic, since it is a statistical element that arises from the survey.

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