help me on this one too

Answer:

there is 3 vowels

Step-by-step explanation:

The ratio of the total number of vowels to letters in word eleven is 1:2

The quantitative relation between two amounts showing the number of times one value contains or is contained within the other. for example-"the ratio of computers to students is now 2 to 1"

Given here the word eleven where the number of vowels is 3 and total letters is 6

∴ 3:6=1:2

Hence, The ratio of the total number of vowels to letters in word eleven is 1:2

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Step-by-step explanation: check work provided down below!!

Answer:  i think it is b

Step-by-step explanation: the second option

Answer:

-12 is your Answer

Step-by-step explanation:

pls ,ark brainliest if right

Answer:

48msquare

Step-by-step explanation:

Area of triangle = 1/2 x b x h

1/2 x 12 x 8

Answer:

48m²

Step-by-step explanation:

8 times 12 divided by 2

Answer:

Start

Step-by-step explanation:

The measure of spread is the variation so we can use range:

Range of Start:

15 - 7 = 8

Range of End:

13 - 6 = 7

Start had a bigger value so it had the greater variation

Answer:

If a and b are the lengths of the legs of a right triangle and c is the length of the ... So, for example, to square the number 5 you multiply 5 • 5, and to square the number ... In any right triangle, the area of the square drawn from the hypotenuse is ... triangle if you know the length of the triangle's other two sides, called the legs.

the answer is :A. is answer or A(5, 4)=A(-5, 4), B(-5,-5)=B(5, 5), C(4, -1)=C(-4, 1)

Answer: to do that you would use slop x2- x1

-------- = rise/run = slope

Y2-x1

Step-by-step explanation:

Answer:

21cm^2

Step-by-step explanation:

1/2 5 x 6 = 15

1/2 x 4 x 3 = 6

15+6 = 21cm^2

If you was working out a missing angle you would 1/2 the longest lines and add them up then add the shortest line

ie) 1/2 6 = 3

1/2 3 5 = 2.5

36+ 25 = 61 sq rt

= 7.81

Then find your multiplier 6/5 =  1.2 you take this multiply by 10

12 and half it = 6 x 7.810 = 46.86 = your angle for the larger triangle.

The smaller triangle missing angle is same method but you keep the multiplier without multiplying by 10 or halfling it, you need to half the 2 sides first then add them to the smaller side found doing Pythagoras and find you r multiplier large side/ second largest side = x  then times x by the multiplier two sides halved and smaller side added. = 3 sq 4 sw = 9+16 = 25 sq = 5 large then + half 4 = 2 + 3

= 2.5+ 2 + 3 = 7.5

then 5/4 = 1.25

=1.25 x 10 = 12.5 then half it = 6.5 then multiply it by 7.5

=6.5 x 7.5 = 48.75 missing angle smaller triangle.

Answer:

24 and 8

Step-by-step explanation:

range=64-40=24

interquartile=50-42=8

Helping the other person get brainliest. Dont mind my response.

Answer:

the answer is 9

Step-by-step explanation:

Answer:

B. X=9

Step-by-step explanation:

hope this helped:)

Answer:

the answer is A.

Step-by-step explanation:

After multiplying the two fractions: [tex]\frac{-7}{4} * \frac{5}{3} = \frac{-35}{12} = -2\frac{11}{12}[/tex]

You might also want to consider that it's negative because it's BELOW sea level. If you are going down, that wount mean that it is negative. So after mltiplying and turning the result into a proper fraction, you get A as your final answer.

Answer:

-2 11/12 is correct as 12/12 + 12/12 + 11/12 = -35/12 so answer is converted to -2 11/12

Answer:

32 degrees

Step-by-step explanation:

Because the triangle is isosceles, 2 of its angles must equal each other:

15x - 31 = 9x + 11

---> x = 7

Plug 7 into either 15x - 31 and 9x + 11:

15(7) - 31 = 74 degrees

and

9(7) + 11 = 74 degrees

Add them together, and you get 148 degrees.

Finally, subtract 180 from 148 to get 32 degrees for angle S.

Answer:

I answered two.

Step-by-step explanation:

Answer:

Step-by-step explanation:    

Short answer No They are not congruent. The scale factor would be 1 if they were. JL and RT should both be the same length (they are opposite angles marked with 2 quarter circles). They are not equal. So the scale factor is not 1.

To get from JKL to RST you must multiply every length of JKL by = 20 / 25 or 4/5. So 15 * 4/5 = 12 which works. 4/5 * 20 = 16 which also works.

The two triangles are similar.

Answer:

I dont know

Step-by-step explanation:

Answer:

49 + 246 qrst

Step-by-step explanation:

Answer:

x ≥ 5

Step-by-step explanation:

2x+1≥11

2x + 1 - 1 ≥ 11 - 1

2x ≥ 10

2x/2 ≥ 10/2

x ≥ 5

Any value of x that is greater than or equal to 5 will be a solution of the inequality 2x + 1 ≥ 11. ( x = 5, x = 6, x = 10, etc. )

Given the inequality in the question:

2x + 1 ≥ 11

To find a value that is a solution of the inequality 2x + 1 ≥ 11, we need to find a number for x that makes the inequality true.

2x + 1 ≥ 11

Isolate the variable term by subtracting 1 from both sides of the inequality:

2x + 1 - 1 ≥ 11 - 1

2x ≥ 11 - 1

2x ≥ 10

Next, divide both sides by 2 to solve for x:

2x/2 ≥ 10/2

x ≥ 10/2

x ≥ 5

Therefore, the value that is a solution can be any number greater than or equal to 5.

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Answer:

yesssssirrrrr and 17998848 is the answer

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

Step-by-step explanation:

17998848 is the answer

Answer:

7

Step-by-step explanation:

7 out of 10 is left and Pedro needs a sign from each part left so the remaining which is 7 is used

Answer:

Answer:

Answer attached

Step-by-step explanation:

Answer:

Maybe. Either 2/4 or 1/4.

Step-by-step explanation:

If you flip a coin 100 times, ABOUT 50 percent will be heads up. Therefore it's not unlikely it up land heads up 2 out of 4 times, but its not unlikely it will be heads down either.

Answer:

0.18 cm²

Step-by-step explanation:

Given that a rectangle and a triangle have same perimeter . The sides of them are ,

[tex]\begin{cases} Square = 4cm , 4cm , 3cm \ and \ 3cm .\\ Triangle = 4cm , 5.8cm \ and \ 4.2cm \end{cases}[/tex]

We know that area of rectangle is product of length and breadth.

[tex]\implies Area = length \times breadth \\\\\implies Area = 4cm \times 3cm\\\\\implies \red{ Area = 12cm^2}[/tex]

Also we know that the area of triange is half the product of base and height . So that ,

[tex]\implies Area = \dfrac{1}{2}\times 5.8cm \times 4.2 cm \\\\\implies \red{ Area = 12.18 cm^2 }[/tex]

Therefore the difference between them is ,

[tex]\implies D = A_1 - A_1 \\\\\implies D = 12.18cm^2-12cm^2 \\\\\implies \red{D = 0.18 cm^2}[/tex]