Answer:
There is pressure on both the in and outsides of the balloon: high inside and low outside, respectively. In terms of air mass, high pressure has greater activity and tends to move upward (balloon rises); whereas low presssure, being slower, descends (balloon descends).
Explanation:
during the spin cycle of a washing machine the cloth stick to the outer wall of the barrel as it spins at a speed of 65 m per second. the radius of the barrel is 0.35 m. what is the magnitude and direction of centripetal acceleration of the clothes which are located on the wall of the barrel
Hi there!
Centripetal acceleration can be written as:
[tex]a_c = \frac{v^2}{r}[/tex]
v = tangential velocity (m/s)
r = radius (m)
Plug in the given values:
[tex]a_c = \frac{65^2}{0.35} = \boxed{12071.43 \text{ m}/s^2}}}[/tex]
The centripetal acceleration vector ALWAYS points towards the CENTER POINT of the barrel.
Explain one way the pattern of the moon would be affected if the moon took longer time to orbit the earth
Each day the Moon's appearance changes depending on where it is in its earth orbit. The pattern of day and night is followed only due to the rotation of the earth.
What is the rotation of the Earth?The phrases revolution and rotation describe the various movements of the earth. Rotation is the tendency of the planet on its axis.
The movement of the earth around the sun is a definite path or orbit known as revolution. The earth's axis, a fictional line, makes a 6612° angle with its orbital plane.
The rotation of the earth on its axis does not cause night and day. The occurrence of night and day is caused by the rotation of the earth.
The lunar cycle begins when the Sun, Moon, and Earth are aligned (the Moon is between the Earth and the Sun, and the hemisphere of the Moon faces away from the Earth.
As a result, if the moon took longer to orbit the Earth, the pattern would be disrupted.
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when 15 newtons of force is applied to the 0.50 kg book, the friction keeps the book from sliding down the wall
The minimum force to keep the book from sliding is 15 N.
The minimum coefficient of friction to keep the book from sliding is 0.33.
The given parameters;
applied force, F = 15 Nmass of the book, m = 0.5 kgThe normal force on the book is calculated as;
[tex]F_n = mg\\\\F_n = 0.5 \times 9.8\\\\F_n = 4.9 \ N[/tex]
The minimum force to keep the book from sliding is calculated as;
[tex]F - F_s = 0\\\\F_s = F\\\\F_s = 15 \ N[/tex]
The minimum coefficient of friction to keep the book from sliding is calculated as;
[tex]\mu_s F = F_n\\\\\mu_s = \frac{F_n}{F} \\\\\mu_s = \frac{4.9}{15} \\\\\mu_s = 0.33[/tex]
"Your question is not complete, it seems to be missing the following information";
When a force of 15 newtons is applied to the 0.50 kg book, the friction keeps the book from sliding down the wall. What is the minimum force and minimum coefficient of friction to keep the book from sliding?
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9) How many valence electrons does this atom have?
A.2
B. 3
C.8
D. 13
Answer:
I think it's 2
Explanation:
Within each column, or group, of the table, all the elements have the same number of valence electrons. This explains why all the elements in the same group have very similar chemical properties. For elements in groups 1–2 and 13–18, the number of valence electrons is easy to tell directly from the periodic table.
A 25kg cannon ball is shot out of a 1600 kg cannon that is initially at rest . When fired the velocity of the cannon ball is 200m/s. What is the recoil velocity of the cannon?
The correct answer is the recoil velocity of the cannon is equal to 90m/s.
The recoil velocity of the cannon is equal to 3.125m/s.
What is law of conservation of linear momentum?According to this law, the sum of the momentum before and after the collision must be equal.
m₁ u₁ + m₂u₂ = m₁v₁ + m₂ v₂
where m₁ and m₂ is the mass of the collided bodies, u₁ and u₂ are initial speed while v₁ & v₂ is final speed.
Conservation of momentum is a characteristic held by an object where the total amount of momentum never changes.
Given the mass of the cannonball, m₁ = 25 Kg
The velocity of the cannonball, v₁ = 200 m/s
The mass of the cannon, m₂ = 1600 Kg
Assume that v₂ is the recoil velocity of the cannon.
From the law of conservation of momentum: P(initial) = P (final)
m₁ v₁ = m₂ v₂
25 × 200 = 1600 × v₂
v₂ = 3.125 m/s
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The first bag you load into your vehicle from the pick-stage cart is the first bag you need to open on your route.
The given statement is false because the first bag you load into the vehicle will be at the bottom during the trip.
During a pick-stage cart, the first bad you load into the vehicle is always placed on the bottom, while subsequent bags are arranged on top of the first bag, all inside the vehicle.
At any point on your route, any bad you tend to open becomes the last bag you load into the vehicle because the first bag is far below the bottom.
Thus, we can conclude that the given statement is false because the first bag you load into the vehicle will be at the bottom during the trip.
"Your question is not complete, it seems to be missing the following information";
The first bag you load into your vehicle from the pick-stage cart is the first bag you need to open on your route. False/True
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A 100-g block slides back and forth on a frictionless surface between two springs, as shown in Fig. 7.18. The left-hand spring has k = 110 N/m and its maximum compression is 21 cm.The right-hand spring has
k = 240 N/m. Find (a) the maximum compression of the right-hand spring and (b) the speed of the block as it moves between the springs.
(a) Energy is conserved at every point in the block's motion, so the potential energy P stored in the first spring at its maximum compression is the same as is stored in the second spring.
The total work performed on the block by the first spring is
W = -1/2 (110 N/m) (0.21 m²) = -2.4255 J
The work performed by the second spring is the same, so
W = -1/2 (240 N/m) x²
Solve for x :
x² = -2W/(240 N/m) = 0.0202125 m²
x ≈ 0.14 m = 14 cm
(b) By the work-energy theorem, the total work performed by either spring on the block as the spring is compressed is equal to the change in the block's kinetic energy. The restoring force of the spring is the only force involved. At maximum compression, the block has zero velocity, while its kinetic energy and hence speed is maximum just as it comes into contact with either spring.
W = 0 - K
W = -1/2 (0.10 kg) v²
v² = -2W/(0.10 kg) = 48.51 m²/s²
v ≈ 7.0 m/s
demonstrate how souni wave works
Answer:
Explanation:
Sound waves exist as variations of pressure in a medium such as air. They are created by the vibration of an object, which causes the air surrounding it to vibrate. The vibrating air then causes the human eardrum to vibrate, which the brain interprets as sound.
explain why oxygen-16 and 16/8o are not considered isotopes
Answer:
Each oxygen isotope has 8 protons but a different amount of neutrons. The mass of an isotope is represented by its isotope number. As a result, oxygen 16 has eight protons and eight neutrons, oxygen 17 has eight protons and nine neutrons, and oxygen 18 has eight protons and ten neutrons.
Explanation:
sjkdvsndjkvnisdvnuisbvibsdv.
Answer:
hello!
Explanation:
A 0.25 kg ball is suspended from a light 0.65 m string as shown. The string makes an angle of 31° with the vertical. Let U = 0 when the ball is at its lowest point (θ = 0).
a) What is the gravitational potential energy, in joules, of the ball before it is released?
b) What will be the speed of the ball, in meters per second, when it reaches the bottom?
Explanation:
a) The height of the ball h with respect to the reference line is
[tex]h = L - L\cos{31°} = L(1 - \cos{31°})[/tex]
so its initial gravitational potential energy [tex]U_0[/tex] is
[tex]U = mgh = mgL(1 - \cos{31°})[/tex]
[tex]\:\:\:\:\:=(0.25\:\text{kg})(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31})[/tex]
[tex]\:\:\:\:\:=0.23\:\text{J}[/tex]
b) To find the speed of the ball at the reference point, let's use the conservation law of energy:
[tex]\Delta{K} + \Delta{U} = 0 \Rightarrow K_0 + U_0 = K + U[/tex]
We know that the initial kinetic energy [tex]K_0,[/tex] as well as its final gravitational potential energy [tex]U[/tex] are zero so we can write the conservation law as
[tex]mgL(1 - \cos{31°}) = \frac{1}{2}mv^2[/tex]
Note that the mass gets cancelled out and then we solve for the velocity v as
[tex]v = \sqrt{2gL(1 - \cos{31°})}[/tex]
[tex]\:\:\:\:\:= \sqrt{2(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31°})}[/tex]
[tex]\:\:\:\:\:= 1.3\:\text{m/s}[/tex]
Answer:
a. 0.23J
b. 1.35 m/s
Explanation:
a. U = mgh where where m = mass of the object, g = acceleration due to gravity, and h = height
h = L - Lcos(θ) where L = length of the rope, and θ = angle with respect to vertical.
Therefore, U = mg(L - Lcos(θ))
U = 0.25 * 9.8 (0.65m - 0.65cos(31° ))
U = 0.2275 ≈ 0.23J
The gravitational potential energy of the ball before it is released = 0.23J
b. To determine the velocity of the object at the bottom of its motion, all of the energy has gone from gravitational potential into kinetic since at the bottom, the problem says that U = 0. The kinetic energy of an object is given by the following equation:
[tex]K.E=\frac{I}{2}*mv^{2}[/tex]
where m = mass of the object and v = velocity of the object. Since we know that all of the energy was transferred into kinetic energy at the bottom, we can conclude that:
[tex]0.2275=\frac{1}{2} *0.25*v^{2}[/tex]
[tex]v^{2}=\frac{2*0.2275}{0.25}[/tex]
[tex]v^{2}=1.82[/tex]
[tex]v=\sqrt{1.82}=1.3491\\[/tex] ≈ [tex]1.35m/s[/tex]
Therefore, the speed of the ball when it reaches the bottom = 1.35m/s
You wear lead to protect you from ____.
1. microwaves
2. gamma rays
3.x_rays
4. infrared
The weight of the atmosphere above 1 m- of
Earth's surface is about 100.000 Ņ. Density, of
course, becomes less with altitudd- But suppose
the density of air were a constant 1.2 kg/m?
Answer:
1.09 kg.m
Explanation:
no need
A power plant running at 39 % efficiency generates 330 MW of electric power. Part A At what rate (in MW) is heat energy exhausted to the river that cools the plant
516.154 megawatts of heat are exhausted to the river that cools the plant.
By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river ([tex]Q_{out}[/tex]), in megawatts:
[tex]Q_{out} = Q_{in} - W[/tex]
[tex]Q_{out} = \left(\frac{1}{\eta}-1 \right)\cdot W[/tex](1)
Where:
[tex]\eta[/tex] - Efficiency.[tex]W[/tex] - Electric power, in megawatts.If we know that [tex]\eta = 0.39[/tex] and [tex]W = 330\,MW[/tex], then the energy rate exhausted to the river is:
[tex]Q_{out} = \left(\frac{1}{0.39}-1 \right)\cdot (330\,MW)[/tex]
[tex]Q_{out} = 516.154\,MW[/tex]
516.154 megawatts of heat are exhausted to the river that cools the plant.
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If a block is sitting in a shelf 5 foot high and the same size block is sitting on the shelf above it at 6 feet high. Which has more potential energy? Explain your reasoning.
Answer:
Explanation:
Assuming that not only is the size of the two blocks the same but the MASS is also the same, then the higher block will have more potential energy.
Potential energy is equal to the amount of work required against gravity to position a mass
Work is a force times a distance. PE = W = Fd
As each block has the same mass, they each create the same force which would be their weight mg
PE = W = Fd = mgd
so potential energy is directly proportional to the height of each block
the lower block has potential energy PE = Fd = mg(5)
while the upper block has potential energy PE = mg(6)
above a reference frame origin, possibly the floor.
It is possible that the higher block has less potential energy then the lower block if only the size is considered. If the higher block is a one foot cube of ice at 57.2 lbs and the lower block is a one foot cube of copper at 559 lbs then the lower mass would have much more potential energy because of its much greater mass.
559(5) = 2795 ft•lb of potential energy
57.2(6) = 343.2 ft•lb of potential energy
9. Two spheres, one of mass 4.0 x 107 kg and the other of mass 8.0 x 107 kg are separated by a
distance of 400.0 m. The force of gravity between them is
a) 1.3 N b) 530 N c) 1.8 x 104 N
d) 5.1 x 1021 N
e) 5.3 x 1022 N
Hi there!
We can use the gravitational force equation:
[tex]F_g = \frac{Gm_1m_2}{r^2}[/tex]
Where:
G = Gravitational Constant
m₁ = mass of one sphere (kg)
m₂ = mass of the other sphere (kg)
r = distance between the spheres (m)
Plug in the given values into the equation:
[tex]F_g = \frac{(6.67*10^{-11})(4.0*10^7)(8.0*10^7)}{400^2} = \boxed{1.334 N}[/tex]
Thus, the correct answer is A.
When converted to a household measurement, 9 kilograms is approximately equal to a) 9000 grams. b) 9000 ounces. 19.8 ounces. d) 19.8 pounds.
Answer:
9000 grams which is also very close to 19.8 pounds
so answers a) and d) are correct
Explanation:
9 kg(1000 gm/kg) = 9000 gms
9 kg(2.205 lb/kg) = 19.845 lb
I guess it rather depends on whose household you are in. One in the US would probably use 19.8 lb while one in Canada might use 9000 gm.
answers please
5 pointss
Answer:
1.a shadow is caused by an object blocking light so that it does not reach a surface. The area in shadow appears black because there is no light falling on it----it appears dark. In fact most shadows are not totally black because light usually bounces around the obstruction off other objects.
2.Shadow gives us the shape about the object and we can know the nature of that image by it's shadow. ... As shadow is complete with the all features of objects like it's shape, size and everything; This helps to know whether the shape of the object. Hence, Shadow tells us about the shape of the object.
3.The bird or an airplane flying high in the sky do not cast their shadow on the ground because they are at very high altitude due to which the ground which acts as screen for the shadow is far away and in absence of the screen the shadow cannot be formed.
Explanation:
BY Roses_are_Rosie
3) A 60. kg person is in an elevator. The elevator starts from rest and then accelerates upwards at 2.0 m/s^2 for 4.0 seconds. Calculate the work done by the normal force on the person. *
Answer is 1.1 x 10^4 J
Answer:
WD = 11328 J → 1.1 × 10⁴ (to 2 sig figs)
Explanation:
WD = work done (J)
F = force (N), i.e. the normal force on the person
W = weight (N)
s = displacement (m)
m = mass (kg) = 60
a = acceleration (m/s²) = 2
g = gravity (m/s²) = 9.8
t = time (s) = 4
u = initial velocity (m/s) = 0
The formulas or equations that are relevant ate:
WD = F × s
F = m × a
W = m × g → note: this is simply a variation of the formula F = ma
s = ut + ¹/₂.at²
We want to find WD, so we need to know the force and the displacement (or distance);
Firstly, we want to find the normal force on the person in the elevator;
The downwards force the person produces on the elevator is the weight of the person, which is:
W = 60 × g
W = 60 × 9.8
W = 588
We are told the elevator is accelerating upward, so we can construct an equation to find F with the formula F = ma:
F - W = 60 × 2
F - 588 = 120
F = 708
Note: illustrations may be helpful to understand this, as has been shown in the picture
We also need displacement, which we use the formula s = ut + ¹/₂at²:
s = 0(4) + ¹/₂(2)(4)²
s = 16 m
Now we have F and s, we can calculate WD:
WD = 708 × 16
WD = 11328 J → This can be rounded to 1.1 × 10⁴ to 2 significant figures
how does spatial pattern of heights illustrate the relationship between temperature density and the rate of vertical pressure change
The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.
Generally, the relationship between temperature, density and rate of vertical pressure is given as;
[tex]\rho = \frac{PM}{RT}[/tex]
[tex]\frac{dP}{dz} = -\rho g\\\\[/tex]
where;
ρ is densityT is temperaturedP is rate of change of vertical pressureThus, from the formula above, we can conclude the following relationship between temperature, density and the rate of vertical pressure change in spatial pattern of heights.
The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.
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What is the gravitational potential energy of a circus performer with a mass of 50 kg walking on a tightrope 10 m above the ground
Answer:
5000 J
Explanation:
GPE = mgh
50*10*10
= 5000 J
The gravitational potential energy of the circus performer walking on the tightrope above the ground is 4900J.
Given the data in the question;
Mass of circus performer; [tex]m = 50kg[/tex]Distance from ground level; [tex]h = 10m[/tex]Gravitational potential energy; [tex]U = ?[/tex]Gravitational Potential EnergyGravitational potential energy is simply the potential energy an object possesses relative to another object due to gravity.
It is expressed as;
[tex]U = mgh[/tex]
Where m is mass, h is height or distance from the other massive object and g is the gravitational field ( [tex]g = 9.8m/s^2[/tex] )
To determine the gravitational potential energy of circus performer, we substitute our values into the expression above.
[tex]U = mgh\\\\U = 50kg\ *\ 9.8m/s^2\ *\ 10m\\\\U = 4900kgm^2/s^2\\\\U = 4900J[/tex]
Therefore, the gravitational potential energy of the circus performer walking on the tightrope above the ground is 4900J.
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what is the magnitude of its velocity just before it strikes the ground, if the bottle was thrown straight out horizontally from the tower with a speed of 11.8 m/s?
There's not enough given information to find the answer.
The horizontal velocity has no effect on anything that happens vertically. To find the object's vertical speed when it hits the ground, we need to know what height it was dropped from, and that's not given in the question.
Since the bottle is falling vertically, the vertical displacement s is the height of the tower from which it was thrown.
If a bottle is thrown horizontally from a tower, its initial vertical velocity is 0 m/s since there is no vertical component to its initial velocity. The only force acting on the bottle in the vertical direction is gravity, which causes it to accelerate downward at a rate of approximately 9.81 m/s² (assuming Earth's gravity).
Since the initial vertical velocity is 0 m/s and the acceleration is 9.81 m/s², you can use the following kinematic equation to find the magnitude of its velocity just before it strikes the ground:
v2=u2+2as
Where:
v is the final vertical velocity (which we're trying to find)
u is the initial vertical velocity (0 m/s)
a is the acceleration due to gravity (-9.81 m/s², negative because it's acting downward)
s is the vertical displacement (which is the height of the tower)
Since the bottle is falling vertically, the vertical displacement
s is the height of the tower from which it was thrown.
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Select all of the following that are involved in translation:
amino acids
tRNA
mRNA
ribonucleotides
deoxyribonucleotides
RNA Polymerase
Answer:
Amino Acids
tRNA
mRNA
ribonucleotides
Explanation:
Amino Acids
- During translation, an mRNA sequence is read using the genetic code, which is a set of rules that defines how an mRNA sequence is to be translated into the 20-letter code of amino acids, which are the building blocks of proteins.
tRNA
- At the beginning of translation, the ribosome and a tRNA attach to the mRNA. The tRNA is located in the ribosome's first docking site. This tRNA's anticodon is complementary to the mRNA's initiation codon, where translation starts. The tRNA carries the amino acid that corresponds to that codon. ransfer ribonucleic acid (tRNA) is a type of RNA molecule that helps decode a messenger RNA (mRNA) sequence into a protein. tRNAs function at specific sites in the ribosome during translation, which is a process that synthesizes a protein from an mRNA molecule.
mRNA
- Translation is the process by which a protein is synthesized from the information contained in a molecule of messenger RNA (mRNA). ... Then a transfer RNA (tRNA) molecule carrying the amino acid methionine binds to what is called the start codon of the mRNA sequence.
ribonucleotides
- During transcription, a ribonucleotide complementary to the DNA template strand is added to the growing RNA strand and a covalent phosphodiester bond is formed by dehydration synthesis between the new nucleotide and the last one added.
How much force is required to swing a 3 kg mass in a circle with a radius of 1.5 m at a speed of 5 m/s?
The force that is required to swing the mass is 50 Newton.
Given the following data:
Mass = 3 kgRadius = 1.5 metersSpeed = 5 m/sTo find the amount of force that is required to swing the mass, we would use centripetal force formula:
Mathematically, centripetal force is given by the formula:
[tex]F_c = \frac{mv^2}{r}[/tex]
Where:
m is the mass.v is the speed.r is the radius.Substituting the parameters into the formula, we have;
[tex]F_c = \frac{3 \times 5^2}{1.5}\\\\F_c = \frac{3 \times 25}{1.5}\\\\F_c = \frac{75}{1.5}\\\\F_c = 50[/tex]
Centripetal force = 50 Newton
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According to Washington, is a strong central government important?
Answer:
According to Washington, the most important factor in sustaining the independence of the United States was protecting the unity of the states. ... Members of the Democratic-Republican Party believed that a strong federal government would not respect the rights of the states and the people.
Explanation:
Brainliest please!
Have a good day!
:)
The Israelites grumbled 11 times against God. True or False?
Answer:
This is not a question about physics.
Anyway. Eleven times seems underrated.
Answer:
True
Explanation:
Because they didn't always appreciate the work of God
An object of mass is used to provide tension in a 6.0 ‑m‑long string that has a mass of 0.252 kg, as shown. A standing wave that has a wavelength equal to 1.5 m is produced by a source that vibrates at 24 Hz.
The tension on the string at the given length and mass is 54.43 N.
The given parameters:
length of the string, L = 6.0 mmass of the string, m = 0.252 kgwavelength, λ = 1.5 mfrequency of the source, F = 24 HzThe speed of the wave is calculated as follows;
[tex]v= f\lambda\\\\v = 24 \times 1.5\\\\v = 36 \ m/s[/tex]
The tension on the string is calculated as follows;
[tex]v = \sqrt{\frac{T}{\mu} } \\\\v = \sqrt{\frac{T}{M/l} } \\\\v = \sqrt{\frac{Tl}{M} } \\\\v^2 = \frac{Tl}{M} \\\\T = \frac{v^2 M}{l} \\\\T = \frac{(36)^2 \times 0.252}{6} \\\\T = 54.43 \ N[/tex]
Thus, the tension on the string at the given length and mass is 54.43 N.
"Your question is not complete is seems to be missing the following information;"
An object of mass is used to provide tension in a 6.0 ‑m‑long string that has a mass of 0.252 kg, as shown. A standing wave that has a wavelength equal to 1.5 m is produced by a source that vibrates at 24 Hz. Determine the tension on the string.
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Please help
Which statement is true in this situation?
Answer:
b
Explanation:
because the of F frick is the same of the size of F app
A trapeze artist performs an aerial maneuver. While in a tucked position, as shown in figure A, she rotates about her center of mass at a rate of 6.27 rad/s. Her moment of inertia about this axis is 17.9 kg⋅m2. A short time later, the aerialist is in the straight position, as shown in figure B. If the moment of inertia about her center of mass in this position is now 33.1 kg⋅m2, what is her rotational speed in revolutions per minute (rpm)?
The rotational speed of the trapeze artist is 32.372 revolutions per second.
In this question we should apply the principle of angular momentum conservation to determine the final angular speed of the trapeze artist, since there are no external forces acting on the trapeze artist:
[tex]I_{A}\cdot \omega_{A} = I_{B}\cdot \omega_{B}[/tex] (1)
Where:
[tex]I_{A}[/tex], [tex]I_{B}[/tex] - Initial and final moments of the trapeze artist, in kilograms-square meter.
[tex]\omega_{A}[/tex], [tex]\omega_{B}[/tex] - Initial and final angular speeds, in radians per second.
If we know that [tex]I_{A} = 17.9\,kg\cdot m^{2}[/tex], [tex]I_{B} = 33.1\,kg\cdot m^{2}[/tex] and [tex]\omega_{A} = 6.27\,\frac{rad}{s}[/tex], then the final angular speed is:
[tex]\omega_{B} = \frac{I_{A}}{I_{B}}\times \omega_{A}[/tex]
[tex]\omega_{B} = \frac{17.9\,kg\cdot m^{3}}{33.1\,kg\cdot m^{2}}\times 6.27\,\frac{rad}{s}[/tex]
[tex]\omega_{B} = 3.390\,\frac{rad}{s}[/tex] ([tex]32.372\,rpm[/tex])
The rotational speed of the trapeze artist is 32.372 revolutions per second.
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What are last two commandments? Please write them down.
The Second Commandment refers to: The second of the Ten Commandments, which is: "Thou shalt have no other gods before me. Thou shalt not make unto thee any graven image" under the Talmudic division of the third-century Jewish Talmud.
Answer:
Thou shalt love the Lord thy God with all thy heart, and with all thy soul, and with all thy mind. This is the first and great commandment. And the second is like unto it, Thou shalt love thy neighbor as myself.
Explanation:
