Using limits, it is found that the end behavior of the function is given as follows:
As x → -∞, f(x) → 4; as x → ∞, f(x) → 4.
How to find the end behavior of a function f(x)?The end behavior of a function f(x) is given by the limit of f(x) as x goes to infinity.
In this problem, the function is:
[tex]f(x) = \frac{8x - 1}{2x - 9}[/tex]
Considering that x goes to infinity, for the limits, we consider only the terms with the highest exponents in the numerator and denominator, hence:
[tex]\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} \frac{8x}{2x} = \lim_{x \rightarrow -\infty} 4 = 4[/tex].[tex]\lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{8x}{2x} = \lim_{x \rightarrow \infty} 4 = 4[/tex].Hence the correct statement is:
As x → -∞, f(x) → 4; as x → ∞, f(x) → 4.
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Answer:
D
Step-by-step explanation:
Which statement regarding the diagram is true?
m∠WXY = m∠YXZ
m∠WXY < m∠YZX
m∠WXY + m∠YXZ = 180°
m∠WXY + m∠XYZ = 180°
The statement m∠WXY + m∠YXZ = 180° is true.
ExplanationFrom the diagram, m∠WXY > m∠YXZ ⇒ m∠WXY ≠ m∠YXZ. So, option (a) is not true.
From the diagram, m∠WXY > 90° and m∠YZX < 90° ⇒ m∠WXY ≠ m∠YXZ. So, option (b) is not true.
The line WXZ is a straight line so ∠WXY and ∠YXZ are Linear pair. The sum of collinear angles is 180°. So, option (c) is correct.
From the diagram, m∠YXZ ≠ m∠XYZ but since m∠WXY + m∠YXZ = 180° ⇒ m∠WXY + m∠XYZ ≠ 180°. So, option (d) is not correct.
Option (c) is, thus, the correct option.
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Disclaimer: The question was incomplete. Please find the dull content below.
QuestionWhich statement regarding the attached diagram is true?
m∠WXY = m∠YXZ
m∠WXY < m∠YZX
m∠WXY + m∠YXZ = 180°
m∠WXY + m∠XYZ = 180°
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Name the relationship between x and y:
Answer:
They are the same angle.
Step-by-step explanation:
We have a diagonal line and two 180° parallel lines running through it. The x and y values should be identical because of the placement. The diagonal on the right and right above the 180° angle.
Option 2: Corresponding angles.
Hope this helps!
If not, I am sorry.
Is 50.2 a rational or an irrational number, why?
Answer:
Rational.
Step-by-step explanation:
[tex]\textbf{A rational number is a real number that can be expressed as}~ \dfrac{p}{q},\\\\\textbf{where}~ p~ \textbf{and}~ q~ \textbf{are integers.}\\\\ \boxed{50.2 = \dfrac{502}{10}}\\\\ \textbf{50.2 can be expressed as a ratio of two integers,}~ \textbf{so it is a rational number.}[/tex]
in a test out of 40,the marks of 15 students were 31,18,6,26,36,24,23,14,28,28,32,9,11,22,21.
a.calculate the mean mark for the test
b.express the mean mark as a percentage
Answer:
a. The mean mark for the test was 20.667.
b. The mean mark as a percentage is 51.6%.
Step-by-step explanation:
a. Calculate the mean mark for the test.
Add all of the scores from each student. [tex]31+18+6+26+36+24+23+14+28+28+32+9+11+22+2=310[/tex]Divide the sum by the amount of students who took the test.[tex]310/15=20.667[/tex]Therefore, the mean mark for the test was 20.667.b. Express the mean mark as a percentage.
Put mean mark and total possible marks in fraction form.[tex]\frac{20.667}{40}[/tex]Divide the numerator by the denominator (essentially changing the fraction into the decimal form). [tex]20.667/40=0.516[/tex]Multiply the quotient by 100. [tex]0.516*100=51.6[/tex]Therefore, the mean mark as a percentage is 51.6%What needs to be corrected in this construction of a line parallel to line AB passing through C?
A and B endpoints of line segment is intersected at point D with a transversal. D as center, arc 1 is drawn above intersecting transversal at point E, and at point F on the segment. E as center, arc 2 is drawn intersecting the transversal at point C.
A.
The first arc should pass through C.
B.
The first arc should be centered at C.
C.
The second arc should be centered at C.
D.
The second arc should cross the first arc.
E.
The second arc should be centered at F.
The option that needs to be corrected in this construction of a line parallel to line AB passing through C is C: the second arc should be centered at C.
Why should the second arc be centered at C?The second arc should be centered at C because as it crosses passing through Line C, it is seen that it was not touching or intersecting AB and so one can say that it is parallel to it.
Looking at the other lines, we will see that they are all touching AB and are not running parallel to it.
Hence, The option that needs to be corrected in this construction of a line parallel to line AB passing through C is C: the second arc should be centered at C.
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Point p has coordinates (-4,-2) and point q has coordinates (4,3) calculate the shortest distance between P and Q. Give your answer to 1 decimal place
Answer:
distance = 9.4 units
Step-by-step explanation:
* using the distance formula *
d =
[tex] \sqrt{(x2 - x1 )^{2} + (y2 - y1)^{2} } [/tex]
[tex] \sqrt{( - 4 - 4) ^{2} + ( - 2 - 3) ^{2} } [/tex]
= 9.4 units
Work out the equation of line B. Give your answer in the form y = mx + c, where m and care integers or fractions in their simplest forms. Work out the equation of line B. Give your answer in the form y = mx + c , where m and care integers or fractions in their simplest forms .
Answer:
y = -3x + 1
Step-by-step explanation:
the line crosses the y-axis at (0,1) then c = 1
The points (0,1) and (1,-2) lie on the line then
m = slope = [(-2)-1]÷(1-0) = [-3]÷(1) = -3÷1 = -3
Therefore,
The equation of the line is : y = -3x + 1
What is y + 1 = -2x - 3 in standard form
[tex]y+1=-2x-3\\y=-2x-4\\y+2x=4[/tex]
The volume of the cube is given as V= x³, where x is the side length of the cube. Find the domain of the volume of
the cube.
Answer: None of the choices
Step-by-step explanation:
1. It couldn't be integers (whole numbers positive or negative), because a cube couldn't have a negative volume.
2. It could be natural numbers, but the problem is, that a volume could have decimal values, for example, 3.62 meters cubed which a natural number doesn't support.
3. Set of whole numbers is the same as integers, so it can't be that.
4. None of the choices, which in my opinion is the correct one.
I'm not sure it is correct, but I hope I helped you!
Find the coordinates of the intersection of the diagonals of parallelogram HJKL with the given vertices: H(-1, 4), J(3, 3), K(3, -2), L(-1, -1). (Drawing a picture helps!)
thank you!
Answer:
(1, 1)
Step-by-step explanation:
Given vertices of the parallelogram:
H = (-1, 4)J = (3, 3)K = (3, -2)L = (-1, -1)Therefore the parallel sides are:
[tex]\sf \overline{HJ} \parallel \overline{LK}\:\: \textsf{ and }\:\: \overline{LK} \parallel \overline{HL}[/tex]
Therefore, the diagonals of the parallelogram are:
[tex]\sf \overline{LJ} \:\: \textsf{ and }\:\:\overline{HK}[/tex]
To find the coordinates of the intersection of the diagonals, either:
draw a diagram (see attached) and determine the point of intersection of the diagonals from the diagram, ordetermine the midpoint of either diagonal (as the diagonals of a parallelogram bisect each other, i.e. divide into 2 equal parts).Midpoint between two points
[tex]\textsf{Midpoint}=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)\quad \textsf{where}\:(x_1,y_1)\:\textsf{and}\:(x_2,y_2)\:\textsf{are the endpoints}}\right)[/tex]
To find the midpoint of diagonal LJ, define the endpoints:
[tex](x_1,y_1)=L=(-1, -1)[/tex][tex](x_2,y_2)=J=(3,3)[/tex]Substitute the defined endpoints into the formula and solve:
[tex]\begin{aligned} \implies \textsf{Midpoint of LJ} & =\left(\dfrac{3-1}{2},\dfrac{3-1}{2}\right)\\ & =\left(\dfrac{2}{2},\dfrac{2}{2}\right)\\ & =\left(1,1\right) \end{aligned}[/tex]
Therefore, the coordinates off the intersection of the diagonals of parallelogram HJKL are (1, 1).
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Check the order
HJKLMeans H,J and K,L are adjacent coordinates
Hence HK and JL are diagonals
We know diagonals of a parallelogram bisect each other so midpoint of any diagonal would be the intersection point
Midpoint of HK
(x1+x2/2,y1+y2/2)(-1+3/2,4-2/2)(2/2,2/2)(1,1)Simplify the expression.
Answer:
D
Step-by-step explanation:
Given that the expression “p dollars for every q items” describes a unit price, which statement must be true?
Which expression is equivalent to
i need help asap
Question 4(Multiple Choice Worth 4 points)
(06.06)
A rectangle with width of 5. There is a vertical line that splits rectangle into two sections with different lengths. One length is x the other is 3.
5(x + 3) represents the area of the rectangle above. Which expression below is equivalent by the Distributive Property?
By the distributive property, 5(x+3) is equal to 5x + 15.
how do you solve this pls
Step-by-step explanation:
The equation of a exponential function is
[tex]a \times (b) {}^{x} [/tex]
where a is the y value of the y intercept, b is the constant rate of change.
Here the y intercept is (0,4), the y value of the y intercept is 4.
So a=4
The graph passes through point (1,2) so
[tex]h(x) = 4 \times b {}^{x} [/tex]
Plug in 1 for x, 2 for h(x)
[tex]2 = 4 \times {b}^{1} [/tex]
Anything to the first power is itself so
[tex]2 = 4 \times b[/tex]
Isolate b.
[tex] \frac{1}{2} = b[/tex]
So our function is
[tex]4 \times ( \frac{1}{2} ) {}^{x} [/tex]
Answer:
[tex]h(x)=4\left(\dfrac{1}{2}\right)^x[/tex]
Step-by-step explanation:
Exponential Function
General form of an exponential function:
[tex]y=ab^x[/tex]
where:
a is the initial value (y-intercept).b is the base (growth/decay factor) in decimal form.x is the independent variable.y is the dependent variable.From inspection of the given diagram, the defined points on the curve are:
(0, 4)(1, 2)As one of the defined points is the y-intercept (0, 4) then:
[tex]\implies a=4[/tex]
Substitute the found value of a and the point (1, 2) into the general form of an exponential function and solve for b:
[tex]\begin{aligned}h(x)=ab^x & \\\implies h(1)=4b^1 & = 2\\4b & = 2\\b & = \dfrac{2}{4}\\b & =\dfrac{1}{2} \end{aligned}[/tex]
Finally, substitute the found values of a and b into the general formula to complete the equation for the function h(x):
[tex]\implies h(x)=4\left(\dfrac{1}{2}\right)^x[/tex]
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1. inverse of a conditional Formed by exchanging the hypothesis and the conclusion and negating both of them. 2. contrapositive of a conditional A statement formed by interchanging the hypothesis and the conclusion in a conditional statement. 3. converse of a conditional A new statement formed by negating both the hypothesis and the conclusion.
See below for the vocabularies and their correct definition
Missing part of the questionMatch the following vocabulary
How to match the vocabulary?The terms are given as:
inverse of a conditionalcontrapositive of a conditional converse of a conditionalTo get the inverse of a conditional, the hypothesis and the conclusion are negated, without interchanging them.
So, we have:
Inverse of a conditional ⇒ A new statement formed by negating both the hypothesis and the conclusion.
To get the contrapositive of a conditional, the hypothesis and the conclusion are negated, after interchanging them.
So, we have:
Contrapositive of a conditional ⇒ Formed by exchanging the hypothesis and the conclusion and negating both of them.
To get the converse of a conditional, we simply interchange the hypothesis and the conclusion, without negating them
So, we have:
Converse of a conditional ⇒ A statement formed by interchanging the hypothesis and the conclusion in a conditional statement.
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Answer:
The answer is Convers because it literally takes the hypothesis and the conclusion and interchanges them.
Step-by-step explanation:
3. Angle r* = 2wº. What is the measure of angle rº1 Show your work. 125⁰ Thangle A wo Wo Triangle B 125⁰ 3. Angle r * = 2wº . What is the measure of angle rº1 Show your work . 125⁰ Thangle A wo Wo Triangle B 125⁰
Answer:
r = 290°
Step-by-step explanation:
Exterior angle property:In a triangle, exterior angles equals the sum of interior opposite angle.
In triangle A,
x + 90 = 125 {Exterior angle property}
x = 125 - 90
x = 35°
In triangle B,
y + 90 = 125
y = 125 - 90
y = 35°
x + y + r = 360 {Complete angle}
35 + 35 + r = 360
70 +r = 360
r = 360 - 70
r = 290°
Given triangle ABC, A=105°, a=10cm, b=7cm, find B,C and c.
The value of the side c will be 5.56 cm and angle C is 32.49° and angle B is 42.51°.
What is law of cosine?Let there is a triangle ABC such that |AB| = a units, |AC| = b units, and |BC| = c units and the internal angle A is of θ degrees, then we have:
a² + b² – 2ab cos C = c²
Given triangle ABC, A = 105°, a = 10 cm, b = 7 cm.
Then we have
7² + c² – (2 · 7 · c) cos 105° = 10²
c² + 3.62c – 51 = 0
On solving, we have
c = 5.56
Then the angle C will be
10² + 7² – 2 · 7 · 10 · cos C = 5.56²
149 – 140 cos C = 30.91
cos C = 0.8435
C = 32.49°
We know that
∠A + ∠B + ∠C = 180°
105° + ∠B + 32.49° = 180°
∠B = 42.51°
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its math please help me
Answer:
460
Step-by-step explanation:
if you look at the values you'll notice the next month is just half their value
7360 / 2 = 3680
3680 / 2 = 1840
1840 / 2 = 920
so
920 / 2 = 460 which should be month 5
Find the general term for the sequence 6, 9, 12, 15, .... n + 5 3 n + 3 4 n + 2 6 n + 3
The general term for the arithmetic sequence is aₙ = 3 + 3n
How to find the general term of an arithmetic sequence?The general term of an arithmetic sequence is as follows:
aₙ = a + (n - 1)d
where
a = first termd = common differencen = number of termsTherefore,
a = 6
d = 9 - 6 = 3
aₙ = 6 + (n - 1)3
aₙ = 6 + 3n - 3
aₙ = 3 + 3n
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two negative integers have the sum of -12 and the product of 11 what are the integers
Answer:
-1 and -11
Step-by-step explanation:
"sum" means we're adding.
-1 + -11 = - 12
"product" means we're multiplying.
-1 × -11 = 11
A car manufacturer has parked some new cars in 2 car parks.In the first car park there are 60 cars in the ratio 1 red car for every 2 blue cars and 3 silver cars.In the second car park there are 80 cars in the ratio 2 blue cars for every 3 red cars and 5 silver cars.
11. How many red cars are there altogether?
12.How many blue cars are there altogether?
13.How many silver cars are there together?
(PLS BE FAST!!)
The number of red car altogether is 34
The number of blue cars altogether is 36
The number of silver car altogether 70
How to use the ratio to find the number of cars?The car manufacturer has parked some cars in 2 car parks .
The first car park has 60 cars.
In the ratio 1 :2:3
Therefore,
red car = 1 / 6 × 60 = 10 cars
blue car = 2 / 6 × 60 = 20 cars
Silver car = 60 - 30 = 30 cars
The second car park has 80 cars.
The ratio are
In the ratio 3:2 5
Therefore,
red cars = 3 / 10 ×80 = 24
blue cars = 2 / 10 × 80 = 16
silver cars = 5 / 10 × 80 = 40
Therefore,
The number of red car altogether is 24 + 10 = 34 red car
The number of blue cars altogether is 20 + 16 = 36 blue cars
The number of silver car altogether is 30 + 40 = 70 silver cars
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A coin toss is used to determine which team will receive the ball at the beginning of a football game. The Cougars always choose tails in the toss. What are the odds in favor of the Cougars losing the toss in exactly two of three games?
3:5
3:8
5:3
8:3
The odds in favor of the Cougars losing the toss in exactly two of three games is 3:8 option second is correct.
What is probability?It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
We have:
A coin toss is used to determine which team will receive the ball at the beginning of a football game.
The Cougars always choose tails in the toss.
There will total of 8 cases and in 8 cases there will be three cases in which exactly two heads will come so,
3:8
The cases = {TTT, TTH, THT, HTT, HHT, HTH, HHT, HHH}
Thus, the odds in favor of the Cougars losing the toss in exactly two of three games is 3:8 option second is correct.
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Expressions - Part 1
16÷(2+1/2)² ?
From the given expression, the equivalent expression would be 64/25.
What are equivalent expressions?Those expressions that might look different but their simplified forms are the same expressions are called equivalent expressions.
To derive equivalent expressions of some expression, we can either make it look more complex or simple. Usually, we simplify it.
Given;
16÷(2+1/2)²
16÷(5/2)²
16÷(25/4)
16 x (4/25)
= 64 / 25
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HELP ME PLEASE AND JUST GIVE ME THE ANSWER NO EXPLANATION
The missing end of the line segment [tex]\overline {GH}[/tex] whose midpoint is M(x, y) = (5, 3) and known endpoint is G(x, y) = (1, -5) is the point H(x, y) = (9, 11).
How to locate the missing end of a line segment
In this question we know an end and a midpoint of a line segment. The missing end can be found from the following formula:
M(x, y) = G(x, y) + 0.5 · [H(x, y) - G(x, y)]
M(x, y) = 0.5 · G(x, y) + 0.5 · H(x, y)
0.5 · H(x, y) = M(x, y) - 0.5 · G(x, y)
H(x, y) = 2 · M(x, y) - G(x, y) (1)
If we know that M(x, y) = (5, 3) and G(x, y) = (1, -5), then the coordinates of the point H are:
H(x, y) = 2 · (5, 3) - (1, -5)
H(x, y) = (10, 6) - (1, -5)
H(x, y) = (9, 11)
The missing end of the line segment [tex]\overline {GH}[/tex] whose midpoint is M(x, y) = (5, 3) and known endpoint is G(x, y) = (1, -5) is the point H(x, y) = (9, 11).
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Answer:
its A
Step-by-step explanation:
Write as an algebraic expression and then simplify if possible :
the sum of x and x+3
Answer:
2x + 3.
Step-by-step explanation:
x + x + 3
= 2x + 3.
Answer:
2x+3
Step-by-step explanation:
x+x+3=2x+3
sum means to add both expression together and we can see there are 2 x's so we can add them and get 2x+3
If ADAB
ACBA,
ZDAB = 35° and ZCBA = 8x + 3
A
D
x = [?]
X
C
B
Answer:
x=4
Step-by-step explanation:
We are given that the triangles are congruent.
Specifically, the order of the letters gives that the angles ∠DAB and ∠CBA are corresponding parts of the two congruent triangles. Since corresponding parts of congruent triangles are themselves congruent, ∠DAB ≅ ∠CBA. Thus, m∠DAB = m∠CBA.
Given the expressions for the two angles, we can substitute into the equation, and solve for the requested variable.
[tex]m\angle DAB=m\angle CBA\\(35)=(8x+3)\\(35)-3=(8x+3\!\!\!\!\!\!\!\!\!\!{--})-3 \!\!\!\!\!\!\!\!\!\! {--}\\32=8x\\\dfrac {32}{8}=\dfrac {8x\!\!\!\!\!\!\! {-}}{8\!\!\!\! {-}}\\4=x[/tex]
PLEASE HELPPP!!
Solve the system of equations.
Answer:
x= 4
y= -2
Step-by-step explanation:
[tex]-3y+5x=26\\-2y-5x=-16[/tex]
Solve by using the Elimination Method.
[tex]-5y=10\\\\\frac{-5y}{-5} =\frac{10}{-5} \\\\y=-2[/tex]
Now plug y into one of the original equation.
=======================================
[tex]-2y-5x=-16[/tex]
[tex](-2*-2)-5x=-16[/tex]
[tex]4-5x=-16[/tex]
[tex]4-5x+5x=-16+5x[/tex]
[tex]4+16=-16+5x+16[/tex]
[tex]20=5x\\\\\frac{20}{5} =\frac{5x}{5} \\\\x=4[/tex]
=======================================
[tex]\left \{ {{x=4} \atop {y=-2}} \right.[/tex]
5.)(2x + 8) - (4y + 1)
6.)-5x * (3x^2 - 2x - 1)
5) 2x + 8 - 4y - 1 = 2x - 4y + 7
6) -5x(3x² - 2x - 1) = -15x³ + 10x² + 5x
Find the area and perimeter.
The figure shows a triangle. One side is given by 4 x minus 3 units. The second side is given by x plus 9 units. The third side is equal to 8 units. The height from the third side is given by 3 x units.
Hint: The height of a non-right triangle is the length of the segment of a line that is perpendicular to the base and that contains the opposite vertex
Answer:
Area=12x square units; Perimeter=5x+14 units
Step-by-step explanation:
Recall the formulas for area and perimeter of a triangle:
Area of a triangle is half of the product of a base its corresponding height:
[tex]A=\frac{1}{2}bh[/tex]
Perimeter is the sum of all of the side lengths:
[tex]P=a+b+c[/tex]
In arbitrary triangles ABC, the sides are labeled across from a vertex with a matching lowercase letter. So, in my diagram, side "b" is the bottom with length "8". Side "b" is also the base, so the corresponding height is the perpendicular line segment that connects side "b" with vertex "B", which measures "3x"... 3 times some unknown value.
Side "a" is length "4x-3", and side "c" is length "x+9".
In this situation, where the sides have their specific relationship with "x" and the height is exactly triple "x", solving for x (and thus exact numerical values for the Perimeter and Area) involves trying to relate the two equations, possibly done with Heron's formula for area, or with trigonometry. Ultimately, it involves solving a 4th degree polynomial to get an exact answer, which is not what the question intends, so we'll leave the Area and Perimeter in terms of x (meaning there will still be "x" in our expressions to represent the Area and Perimeter).
Area
[tex]A=\frac{1}{2}bh\\A=\frac{1}{2}(8)(3x)\\A=12x[/tex]
So the Area of the triangle equals 12x square units.
Perimeter
[tex]P=a+b+c\\P=(4x-3)+(8)+(x+9)\\P=5x+14[/tex]
So the Perimeter of the triangle equals 5x+14 units
