The total entropy change of the steam during this process is 24.885 kJ/K.
During this process, the system undergoes a phase change from a saturated liquid-vapor mixture to a saturated vapor. The initial state can be determined using a steam table, which shows that at 225 kPa, the saturation temperature of water is 120.23°C. Therefore, the initial state is a mixture of liquid water and steam at 120.23°C with 80% of the mass in the liquid phase.
When the electric resistance heater vaporizes all of the liquid, the system transitions to a state of saturated vapor at the same pressure of 225 kPa and temperature of 120.23°C. The total entropy change of the steam during this process can be calculated using the formula:
ΔS = m * s_final - m * s_initial
where ΔS is the total entropy change, m is the mass of the steam, s_final is the specific entropy of the final state, and s_initial is the specific entropy of the initial state.
At the initial state, using the steam table, the specific entropy of the saturated liquid-vapor mixture can be found to be 1.5875 kJ/kg-K. At the final state, the specific entropy of the saturated vapor can also be found to be 7.2925 kJ/kg-K.
Therefore, the total entropy change of the steam is:
ΔS = 4.2 kg * (7.2925 kJ/kg-K - 1.5875 kJ/kg-K)
ΔS = 24.885 kJ/K
Therefore, the total entropy change of the steam during this process is 24.885 kJ/K.
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Calculate the mass (in grams) of an ionic compound (molar mass 153. 5g/mol) that is dissolved
in 100 g H2O if the 0. 531 M solution formed has a density of 1. 094 g/mL.
The mass of the ionic compound dissolved in 100 g of water is 7.44 grams.
To solve this problem, we need to use the formula:
m = n x M x MW
where m is the mass of the compound in grams, n is the number of moles of the compound, M is the molarity of the solution, and MW is the molar mass of the compound.
First, we need to calculate the number of moles of the compound dissolved in 100 g of water:
density of solution = mass of solution / volume of solution
volume of solution = mass of solution / density of solution = 100 g / 1.094 g/mL = 91.29 mL = 0.09129 L
moles of compound = M x volume of solution = 0.531 mol/L x 0.09129 L = 0.0485 mol
Now, we can calculate the mass of the compound:
m = n x M x MW = 0.0485 mol x 153.5 g/mol = 7.44 g
Therefore, the mass of the ionic compound dissolved in 100 g of water is 7.44 grams.
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What mass in grams of hydrogen gas is produced if 20. 0 mol of zn are added to excess hydrochloric acid according to the equation
zn(s) +2hcl(aq) --> zncl₂(aq) + h₂(g)?
First, we need to use stoichiometry to find out how many moles of hydrogen gas are produced. From the balanced chemical equation, we can see that for every 1 mole of zinc (Zn), 1 mole of hydrogen gas (H2) is produced. Therefore, if we have 20.0 mol of Zn, we will also produce 20.0 mol of H2.
Next, we can use the formula for the mass of a gas:
mass = molar mass x number of moles
The molar mass of hydrogen gas is approximately 2.02 g/mol. Therefore, the mass of 20.0 mol of hydrogen gas would be:
mass = 2.02 g/mol x 20.0 mol
mass = 40.4 g
So, 40.4 grams of hydrogen gas are produced when 20.0 mol of Zn are added to excess hydrochloric acid.
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When water boils, what are the bubbles composed of?.
When water boils, the bubbles are composed of water vapor or steam.
The bubbles form when the water is heated to its boiling point and the water molecules gain enough thermal energy to overcome the intermolecular forces holding them together in the liquid state.
As the water molecules escape into the gaseous state, they form bubbles that rise to the surface of the liquid and release the steam into the atmosphere.
The bubbles are filled with water vapor, which is less dense than liquid water and has a higher thermal energy due to the increased molecular motion in the gas phase. Once the bubbles reach the surface, they burst and release the steam into the air.
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Calculate the mass (amu) of 75 atom of AL
The atomic mass of aluminum (Al) is approximately 26.98 amu. Therefore, the mass of one Al atom is 26.98 amu.
To calculate the mass of 75 Al atoms, we can multiply the mass of one Al atom by 75:
Mass of 75 Al atoms = 75 atoms x 26.98 amu/atom
Mass of 75 Al atoms = 2024.5 amu
Therefore, the mass of 75 Al atoms is 2024.5 amu.
Describe an experiment that can be conducted to show that living materials contain water
One simple experiment that can be conducted to demonstrate that living materials contain water is heating of simple matter.
What is the experiment to demonstrate presence of water?The following experimental procedure deminstrates the presence of water on living matter.
Collect a sample of plant leaf Weigh the sample and record its initial weight.Place the sample in a dry, airtight container and heat it in an ovenRemove the container from the oven and allow it to cool to room temperature in a desiccator.Weigh the sample again and record its final weight.If the sample contains water, the final weight will be less than the initial weight, indicating that some of the water has been lost due to the heating process.
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PLEASE HELP. Complete the following table.
[H3O+] [OH−] pOH pH Acidic or Basic
1. 0×10−8 1. 0×10−6 6. 00 8. 00 basic
_____ _____ _____ 3. 05 _____
9. 7×10−9 _____ _____ _____ _____
_____ _____ _____ 13. 79 _____
_____ 9. 6×10−11 _____ _____ _____
Part A
Complete the first column of the table.
Part B
Complete the second column of the table.
Part C
Complete the third column of the table.
Part D
Complete the fourth column of the table.
Part E
Complete the fifth column of the table
The answer to the part A, B, C, D and E are as follows-
Part A: [tex][H3O+] [OH−] pOH[/tex] pH Acidic or Basic
1.0×10−8 1.0×10−6 6.00 8.00 basic
1.0×10−5 1.0×10−9 9.00 5.00 acidic
9.7×10−9 1.0×10−5 5.00 8.99 basic
[tex]1.0×10−14 1.0×10^14 14.00 0.00 neutral\\1.0×10^−3 1.04×10^−11 11.98 2.00 acidic[/tex]
Part B:
[tex][H3O+] [OH−] pOH[/tex] pH Acidic or Basic
1.0×10−8 1.0×10−6 6.00 8.00 basic
1.0×10−5 1.0×10−9 9.00 5.00 acidic
9.7×10−9 1.0×10−5 5.00 8.99 basic
[tex]1.0×10−14 1.0×10^14 14.00 0.00 neutral\\1.0×10^−3 1.04×10^−11 11.98 2.00 acidic[/tex]
Part C:
[tex][H3O+] [OH−] pOH[/tex]pH Acidic or Basic
1.0×10−8 1.0×10−6 6.00 8.00 basic
1.0×10−5 1.0×10−9 9.00 5.00 acidic
9.7×10−9 1.0×10−5 5.00 8.99 basic
[tex]1.0×10−14 1.0×10^14 14.00 0.00 neutral\\1.0×10^−3 1.04×10^−11 11.98 2.00 acidic[/tex]
Part D:
[tex][H3O+] [OH−] pOH[/tex]pH Acidic or Basic
1.0×10−8 1.0×10−6 6.00 8.00 basic
1.0×10−5 1.0×10−9 9.00 5.00 acidic
9.7×10−9 1.0×10−5 5.00 8.99 basic
[tex]1.0×10−14 1.0×10^14 14.00 0.00 neutral\\1.0×10^−3 1.04×10^−11 11.98 2.00 acidic[/tex]
Part E:
[tex][H3O+] [OH−] pOH[/tex]pH Acidic or Basic
1.0×10−8 1.0×10−6 6.00 8.00 basic
1.0×10−5 1.0×10−9 9.00 5.00 acidic
9.7×10−9 1.0×10−5 5.00 8.99 basic
[tex]1.0×10−14 1.0×10^14 14.00 0.00 neutral\\1.0×10^−3 1.04×10^−11 11.98 2.00 acidic[/tex]
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why do you think the h-bonds only last a short time before breaking and reforming?
Answer:
because they are poorly made
Explanation:
A rigid container of N2 has a pressure at 378 kPa at a temperature of 413 K. What is the new pressure at 273 K?
The new pressure at 273 K, given that the initial pressure was 378 KPa, is 249.9 KPa
How do i determine the new presssure?The following parameters were obtained from the question:
Initial pressure (P₁) = 378 KPaInitial temperature (T₁) = 413 KNew temperature (T₂) = 273 KNew pressure (P₂) = ?The new pressure of the gas at 273 K can be obtained as shown below:
P₁ / T₁ = P₂/ T₂
378 / 413 = P₂ / 273
Cross multiply
413 × P₂ = 378 × 273
413 × P₂ = 103194
Divide both sides by 413
P₂ = 103194 / 413
P₂ = 249.9 KPa
Thus, from the above calculation, we can conclude the new pressure at 273 K is 249.9 KPa
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Suppose digital technology, gold jewelry, and paper money caused the need for silver to no longer exist. would silver still be considered an ore? discuss
Yes, silver would still be considered an ore even if its demand and usage in digital technology, gold jewelry, and paper money decreased to the point of non-existence. Silver is a naturally occurring metallic element that is found in various ores, and its classification as an ore is based on its physical and chemical properties, regardless of its market demand. Therefore, even if the uses of silver in various industries decline, it would still be classified as an ore.
An ore is a naturally occurring mineral or rock containing valuable substances, typically metals, that can be extracted through mining and processed for various purposes. Even if the demand for silver decreases due to digital technology, gold jewelry, and paper money, it would not change the fact that silver is a naturally occurring material containing a valuable metal. The classification of silver as an ore is independent of its current or potential use in human activities.
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The mass of marshmallow and a food holder weighs 5. 08 g. After burning the marshmallow, the marshmallow and food holder have a mass of 5. 00 g. Determine the mass of food burned. (Don't forget units. )
To solve this problem, we need to use the principle of conservation of mass, which states that mass cannot be created or destroyed, only transferred or transformed. First, we need to find the initial mass of the marshmallow and food holder, which is 5.08 g. Then, after burning the marshmallow, the new mass of the marshmallow and food holder is 5.00 g.
To determine the mass of food burned, we need to subtract the new mass from the initial mass:
5.08 g - 5.00 g = 0.08 g
Therefore, the mass of food burned is 0.08 g.
It's important to note that we cannot determine the mass of the marshmallow that was burned specifically, as we do not have that information. However, we can determine the total mass of food burned.
In general, it's important to be aware of the principle of conservation of mass in all types of chemical reactions and food preparation. While we may not always measure or track the exact amounts of ingredients we use, understanding how mass is conserved can help us better understand and control the outcomes of our cooking and baking.
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If you started with 20. 0 g of a radioisotope and waited for 3 half-lives to pass, then how much would remain?
After three half-lives have passed, 2.50 g of the radioisotope would remain out of the initial 20.0 g.
If a radioisotope has a half-life of t, then the amount of the radioisotope that remains after n half-lives can be calculated using the formula:
[tex]N = N0 * (1/2)^n[/tex]
where N0 is the initial amount of the radioisotope.
If three half-lives have passed, then n = 3. Using the given initial amount of 20.0 g, we can calculate the amount that remains after three half-lives as follows:
[tex]N = N0 * (1/2)^n\\N = 20.0 g * (1/2)^3[/tex]
N = 20.0 g * (1/8)
N = 2.50 g
Therefore, after three half-lives have passed, 2.50 g of the radioisotope would remain out of the initial 20.0 g.
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Consider this question posed at the beginning of the task:
do two magnets create magnetic force fields that allow them to interact without touching?
did the investigation answer the question? explain whether the investigation gave enough evidence to support the idea
that invisible magnetic force fields exist.
ments
Yes, two magnets can create magnetic force fields that allows them to interact without touching.
Magnetic forces are non contact forces; they pull or push on objects without touching them. Magnets are only attracted to a few 'magnetic' metals and not all matter. Yes, the investigation did answer the question about whether two magnets create magnetic force fields that allow them to interact without touching.
The investigation provided enough evidence to support the idea that invisible magnetic force fields exist:
The investigation involved observing how two magnets interact with each other without touching. The magnets were brought closer together until they interacted, and then they were moved further apart. This process was repeated several times, and the results were observed and recorded. During the investigation, it was observed that the magnets interacted with each other even when they were not touching. This interaction occurred because the magnets created magnetic force fields that allowed them to interact with each other even when they were not in direct contact. This is because the interaction between the magnets could not be explained by any other means except through the existence of magnetic force fields.
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In a boiling pot of water are a metal spoon and a wooden spoon of equal masses/size. Which spoon would likely be more painful (higher in temperature) to grab? Assume that both spoons have been in the same pot of boiling water for the same amount of time. Explain this phenomena using the following terms: Heat, Mass, Temperature, Specific Heat Capacity, Heat Flow. Consider all possible factors in your explanation
When we place a metal spoon and a wooden spoon of equal masses/size in a boiling pot of water for the same amount of time, the metal spoon would likely be more painful to grab than the wooden spoon. This is because of the differences in their specific heat capacities.
Specific heat capacity is the amount of heat required to raise the temperature of a substance by 1 degree Celsius per unit mass. Metals have a lower specific heat capacity than wood, which means that they require less heat to increase their temperature than wood does.
As a result, the metal spoon would heat up more quickly than the wooden spoon in the boiling water.
Heat flow is the transfer of thermal energy from one object to another due to a temperature difference between them. In this case, heat flows from the boiling water to the spoons. The metal spoon would conduct heat better than the wooden spoon due to its higher thermal conductivity.
This means that the metal spoon would transfer heat more quickly from the boiling water to your hand, making it more painful to grab.
Mass is also a factor to consider as it affects the amount of heat absorbed by the spoons. However, since the spoons have equal masses, mass does not play a significant role in this scenario.
In summary, the metal spoon would likely be more painful to grab because it has a lower specific heat capacity and higher thermal conductivity than the wooden spoon, which causes it to heat up more quickly and transfer heat more efficiently from the boiling water to your hand.
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The most energy-intensive process (i.e. requires the most energy) in a cell is
dna replication..
carbohydrate synthesis.
transcription.
lipid catabolism.
translation.
DNA replication is the most energy-intensive process in a cell. Option A is correct.
The replication of DNA requires the unwinding of the double helix structure and the separation of the two strands, which is facilitated by enzymes such as helicases. The replication process also involves the synthesis of new nucleotide strands, which requires the input of energy in the form of ATP (adenosine triphosphate) molecules.
While other cellular processes such as transcription, translation, and lipid catabolism also require energy, DNA replication is particularly energy-intensive due to the large size of the DNA molecule and the complexity of the replication machinery involved.
Additionally, errors in the DNA replication process can lead to mutations that can have serious consequences for the cell and the organism as a whole, so the replication process must be tightly regulated and closely monitored, which also requires energy expenditure.
Hence, A. is the correct option.
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--The given question is incomplete, the complete question is
"The most energy-intensive process (i.e. requires the most energy) in a cell is A) DNA replication B) carbohydrate synthesis C) transcription D) lipid catabolism. E) translation."--
2AgNO3(ag) + Cu(s)---> 2Ag (s) + Cu(NO3)2 (aq)
How many moles of Ag will be produced from 3.50 g of Cu?
A total of 0.1102 moles of Ag will be produced from 3.50 g of Cu.
To determine the number of moles of Ag produced from 3.50 g of Cu, we need to use stoichiometry.
From the balanced chemical equation, we see that 1 mole of Cu reacts with 2 moles of Ag to produce 1 mole of Cu(NO₃)₂ and 2 moles of Ag.
First, we need to convert 3.50 g of Cu to moles by dividing by its molar mass, which is 63.55 g/mol.
3.50 g Cu / 63.55 g/mol = 0.0551 mol Cu
Next, we use the stoichiometry ratio to determine the number of moles of Ag produced:
0.0551 mol Cu x (2 mol Ag / 1 mol Cu) = 0.1102 mol Ag
In summary, we use stoichiometry to determine the number of moles of Ag produced from 3.50 g of Cu by first converting the mass of Cu to moles, and then using the stoichiometry ratio from the balanced chemical equation.
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One isotope of element J has an atomic mass of 78. 92u and a relative abundance of 50. 69%. The other major isotope of element J has an atomic mass of 80. 92u and a relative abundance of 49. 31%. Calculate the average atomic mass element J
The average atomic mass of element J is 79.854u as it determines the properties and behavior of the element in various chemical and physical processes.
To calculate the average atomic mass of element J, we need to use the formula:
Average atomic mass = (mass₁ × % abundance₁ + mass₂ x % abundance₂) ÷ 100
where mass₁ and mass₂ are the atomic masses of the two isotopes and % abundance₁ and % abundance₂ are their respective relative abundances.
Substituting the values given in the problem, we get:
Average atomic mass of J = (78.92u x 50.69% + 80.92u x 49.31%) ÷ 100
= (40.05148u + 39.80252u) ÷ 100
= 79.854u
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Which refers to a phenomenon that occurs as solar radiation is absorbed by Earth’s surface and re-radiated into the atmosphere, where it gets trapped and warms the Earth? energy budgeting greenhouse effect solar circulation incoming radiation
The phenomenon being referred to in this question is the greenhouse effect.
This effect occurs as solar radiation is absorbed by Earth's surface and re-radiated into the atmosphere. Some of this energy gets trapped in the atmosphere by greenhouse gases such as carbon dioxide, methane, and water vapor. This trapped energy warms the Earth, leading to global climate change.
To explain further, the Earth has an energy budgeting system where incoming radiation from the sun is balanced by outgoing radiation from the Earth's surface and atmosphere. However, due to human activities such as burning fossil fuels and deforestation, the concentration of greenhouse gases in the atmosphere has increased.
This increase in greenhouse gases has disrupted the balance of the energy budgeting system, leading to an overall warming of the Earth.
Solar circulation also plays a role in the greenhouse effect, as it affects the distribution of heat and energy around the planet. As the Earth's surface warms, air and water move around the globe, distributing heat and energy. This solar circulation helps to regulate the Earth's temperature, but it can also contribute to changes in climate patterns and weather events.
In summary, the greenhouse effect is a phenomenon that occurs as solar radiation is absorbed by the Earth's surface and re-radiated into the atmosphere. This trapped energy warms the Earth, leading to global climate change.
The greenhouse effect is a result of an imbalance in the Earth's energy budgeting system, caused by the increase in greenhouse gases in the atmosphere. Solar circulation also plays a role in regulating the Earth's temperature and climate patterns.
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Answer:
greenhouse Effect (B , edge 2023)
Explanation:
What type of a reaction is this?
HBr (aq) + KOH (aq) KBr (aq) + H2O (l)
combustion
synthesis
single replacement
double replacement
Answer: Double Replacement
Explanation:
Two elements are being switched around in this reaction, H and K, so it is a double replacement. The K from potassium hydroxide replaces the H in hydrobromic acid, becoming potassium bromide, and the H from hydrobromic acid replaces the K in potassium hydroxide, becoming water.
What is the partial pressure of so2 in equilibrium with air and solid cao if po2 in air is 0. 21 atm?.
The partial pressure of SO₂ in equilibrium with the air and solid CaO if PO₂ in the air is 0.21 atm is 1.41 atm.
To determine the partial pressure of SO₂ in equilibrium with the air and solid CaO, we need to use the equation:
CaO(s) + SO₂(g) ⇌ CaSO₃(s)
This equation represents the equilibrium reaction between solid CaO, gaseous SO₂, and solid CaSO₃. At equilibrium, the partial pressures of SO₂ and O₂ in the air will determine the equilibrium constant of the reaction.
Assuming that the pressure of O₂ in the air is 0.21 atm, we can use the ideal gas law to calculate the partial pressure of SO₂:
PV = nRT
where P is the partial pressure of SO₂, V is the volume of the system, n is the number of moles of SO₂, R is the ideal gas constant, and T is the temperature.
At equilibrium, the reaction quotient Qc is equal to the equilibrium constant Kc:
Qc = [CaSO₃]/[CaO][SO₂]
Kc = [CaSO₃]/[CaO][SO₂]
Since CaO is solid, its concentration is constant, so we can write:
Kc = [CaSO₃]/[SO₂]
At equilibrium, Qc = Kc, so we can use this equation to solve for the partial pressure of SO₂:
Kc = [CaSO₃]/[SO₂]
Kc = 0.71 (at 1000 K)
[CaSO₃] = 1 (assuming that the CaO is fully reacted)
[SO₂] = [CaSO₃]/Kc = 1/0.71 = 1.41 atm
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According to the lab introduction in your laboratory manual, the equation for sodium
carbonate dissolving in water is:
3
Na2CO3 + 2H20 – 2Na+ + 2OH- + H2CO3
When this process occurs, sodium carbonate does not 100% separate into ions.
There is always some sodium carbonate in solution.
Based on this reaction, explain whether Sample A or Sample B is most alkaline and
why.
Sample A or Sample B cannot be definitively determined as more alkaline based on the given information. The equation for sodium carbonate dissolving in water shows that it produces both sodium ions (Na⁺) and hydroxide ions (OH⁻), which are the ions responsible for making a solution alkaline.
However, the fact that not all of the sodium carbonate dissociates into ions means that the concentration of alkaline ions in the solution will be less than the total concentration of sodium carbonate added. Therefore, the alkalinity of a sample cannot be determined solely based on the amount of sodium carbonate present.
Other factors, such as the presence of other alkaline substances or the pH of the solution, would need to be considered to determine which sample is more alkaline.
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Determine the final pressure of a sample of a gas measured initially at 1. 00 atm and 25ºC if it is heated to 50ºC
The final pressure of the gas sample is 1.09 atm when heated to 50ºC.
The final pressure of a gas sample initially at 1.00 atm and 25ºC when heated to 50ºC can be calculated using the ideal gas law:
P₁ × V₁ ÷ T₁ = P₂ × V₂ ÷ T₂
where P₁, V₁, and T₁ are the initial pressure, volume, and temperature of the gas, respectively, and P₂, V₂, and T₂ are the final pressure, volume, and temperature of the gas, respectively.
Assuming that the volume of the gas remains constant, V₁ = V₂, and rearranging the ideal gas law, we get:
P₂ = P₁ (T₂ ÷ T₁)
Substituting the values, we get:
P₂ = (1.00 atm) × (323 K) ÷ (298 K) = 1.09 atm
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you are separating anthracene from benzoic acid via an extraction between ethyl acetate and a basic aqueous solution in a separatory funnel. how would you recover the benzoic acid? group of answer choices collect the top layer, dry with na2so4, filter to remove the na2so4, and evaporate the solvent. collect the bottom layer, dry with na2so4, filter to remove the na2so4, and evaporate the solvent. collect the top layer and add hcl to precitipate the compound. collect the bottom layer and add hcl to precipitate the compound. collect the top layer and add naoh to precipitate the compound. collect the bottom layer and add naoh to precipitate the compound.
To recover the benzoic acid, collect the bottom layer, dry it with [tex]Na_{2} SO_{4}[/tex], filter to remove [tex]Na_{2} SO_{4}[/tex], and evaporate the solvent. The option 4 is correct.
This is because benzoic acid is a carboxylic acid and will react with the basic aqueous solution to form a water-soluble carboxylate salt. As a result, benzoic acid will be in the aqueous layer, which is the bottom layer. Ethyl acetate is the organic solvent and will form the top layer. By collecting the bottom aqueous layer, we can isolate the benzoic acid. Drying the solution with [tex]Na_{2} SO_{4}[/tex] removes any remaining water, and evaporating the solvent leaves behind the solid benzoic acid. Option 4 is correct answer.
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--The complete Question is, you are separating anthracene from benzoic acid via an extraction between ethyl acetate and a basic aqueous solution in a separatory funnel. how would you recover the benzoic acid? group of answer choices
1. collect the top layer, dry with na2so4,
2. filter to remove the na2so4, and evaporate the solvent.
3. collect the bottom layer, dry with na2so4,
4. collect the bottom layer and add hcl to precipitate the compound.
5. collect the top layer and add hcl to precitipate the compound. --
Consider the following intermediate chemical equations. 2H (g) + O2(g) â 2H, O( H (9)+F (9) ⺠2HF(g) In the final chemical equation, HF and O2 are the products that are formed through the reaction between H2O and F2. Before you can add these intermediate chemical equations, you need to alter them by multiplying the O second equation by 2 and reversing the first equation. O first equation by 2 and reversing it. O first equation by (12) and reversing the second equation. Second equation by 2 and reversing it. â
The correct set of modifications to the given chemical equations is to multiply the second equation by 2 and reverse it, option D is correct.
To obtain the final chemical equation, we need to cancel out the reactants that appear as intermediates in the two given chemical equations. In this case, we need to cancel out H₂ and F₂. The second equation shows that one H₂ molecule reacts with one F₂ molecule to produce two HF molecules. Therefore, we need two molecules of the second equation, which can be achieved by multiplying it by 2.
However, the second equation has to be reversed before multiplying it by 2. This is because, in the final chemical equation, we need to form HF and O₂ from H₂O and F₂, whereas the given second equation shows the formation of HF from H₂ and F₂, option D is correct.
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The complete question is:
Consider the following intermediate chemical equations.
2H₂(g) + O₂(g) → 2H₂O(l)
H₂(g) + F₂(g) → 2HF(g)
In the final chemical equation, HF and O₂ are the products that are formed through the reaction between H₂O and F₂. Before you can add these intermediate chemical equations, you need to alter them by multiplying the:
A) second equation by 2 and reversing the first equation.
B) first equation by 2 and reversing it.
C) first equation by (1/2) and reversing the second equation.
D) second equation by 2 and reversing it.
a solution of the weak acid ha ha is prepared by dissolving 2.70 g 2.70 g of ha ha in 100.0 ml 100.0 ml water. the solution is titrated, and the equivalence point is reached after 32.1 ml 32.1 ml of 0.500 m naoh 0.500 m naoh is dispensed. calculate the molar mass of ha.
The molar mass of HA is approximately 168.48 g/mol.
To calculate the molar mass of HA, we need to use the balanced chemical equation for the reaction between HA and NaOH:
[tex]HA + NaOH[/tex] → [tex]NaA + H2O[/tex]
From the equation, we can see that 1 mole of HA reacts with 1 mole of NaOH to produce 1 mole of NaA. At the equivalence point of the titration,
[tex]moles of NaOH = (0.500 mol/L) * (0.0321 L) = 0.01605 mol[/tex]
Since the initial solution was prepared by dissolving 2.70 g of HA in 100.0 ml of water, we can calculate the initial concentration of HA in units of moles per liter:
[tex]moles\ of HA = (2.70 g / molar\ mass\ of HA) = (0.0270 kg / molar\ mass\ of HA)[/tex]
[tex]initial\ concentration\ of\ HA = moles\ of\ HA / (0.100 L) = moles\ of\ HA / 1000 mL[/tex]
Setting the moles of NaOH equal to the moles of HA, we can solve for the molar mass of HA:
moles of NaOH = moles of HA
[tex]0.01605\ mol = (0.0270 kg / molar\ mass\ of HA) / 0.100 L[/tex]
[tex]molar\ mass\ of\ HA = (0.0270 kg / 0.01605 mol) / 0.100 L = 168.48 g/mol[/tex]
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An iron reacts with oxygen to produce iron (ii) oxide. if you have 23.1 g of iron and 53.22 g of oxygen, what is the maximum amount of product formed in grams?
The maximum amount of iron (II) oxide that can be formed is 176.9 g if 23.1 g of iron reacts with 53.22 g of oxygen to produce iron (ii) oxide.
The balanced chemical equation for the reaction between iron and oxygen to produce iron (II) oxide is:
4Fe + 3O₂ → 2Fe₂O₃
From the equation, we can see that 4 moles of iron react with 3 moles of oxygen to produce 2 moles of iron (II) oxide.
Calculate the number of moles of each reactant using their respective molar masses:
Number of moles of iron = 23.1 g ÷ 55.845 g/mol
= 0.414 moles
Number of moles of oxygen = 53.22 g ÷ 32 g/mol
= 1.663 moles
Since the stoichiometric ratio of iron to oxygen is 4:3, we can see that oxygen is the limiting reactant because there are only 3 moles of oxygen available for every 4 moles of iron required.
Number of moles of Fe₂O₃ = 2 ÷ 3 × 1.663
= 1.108 moles
Mass of Fe₂O₃ = 1.108 moles × 159.69 g/mol
= 176.9 g
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Help what’s the answer?
This problem can be solved using Boyle's Law, which posits that the pressure of any given gas will be inversely proportional to its volume when temperature is kept as a constant.
What will be the final volume of the given methane gas ?Mathematically Boyle's Law can be expressed as:
P₁V₁ = P₂V₂
where P₁ and V₁ are the initial pressure and volume, respectively, and P₂ and V₂ are the final pressure and volume, respectively.
We are given that:
P₁ = 1.15 atm
V₁ = 640 mL
T = 23.9 °C (which is 297.05 K, using the Kelvin temperature scale)
We need to find V₂ when P₂ = 1.43 atm.
Using Boyle's Law, we can set up the following equation:
P₁V₁ = P₂V₂
(1.15 atm)(640 mL) = (1.43 atm)(V₂)
Solving for V₂:
V₂ = (1.15 atm)(640 mL) / (1.43 atm)
V₂ = 514.69 mL
Therefore, the final volume of the methane gas is 514.69 mL when compressed at constant temperature until its pressure is 1.43 atm.
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4
A local pet store expands and begins selling exotic organisms. The exotic organisms are
easy to care for when they are younger, but become very difficult to control as they get
older. The owners often decide to release their new pets into the local environment
rather than continue to care for them. The released animals do not have any natural
enemies and their population expands unchecked. How will this affect the biodiversity of
the ecosystem?
F
It introduces an invasive species, which will increase the biodiversity of the
ecosystem.
It introduces an invasive species, which will decrease the biodiversity of the
G
ecosystem.
H It introduces a native species which will not affect the biodiversity of the ecosystem.
It reintroduces a native species, which will decrease the biodiversity of the
ecosystem.
The scenario described in the question is an example of the negative impact that can result from introducing exotic organisms into an ecosystem.
Exotic organisms, also known as invasive species, are non-native species that are introduced to an ecosystem and can outcompete native species, disrupt natural ecological processes, and cause harm to the environment and economy.
When the exotic organisms are released into the local environment, they have no natural predators, and their population can increase unchecked, causing a decrease in biodiversity.
This is because the invasive species may outcompete and displace native species, reduce the availability of resources, and alter the habitat. The result is a homogenization of the ecosystem, where there are fewer different types of species and less overall diversity.
In summary, introducing exotic organisms can have a negative impact on biodiversity in an ecosystem, which can have cascading effects on the health and stability of the ecosystem. It is important to carefully manage and monitor the introduction of exotic organisms to prevent these negative impacts.
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PLEASE HELP!!
if 9. 45 moles of C2H2 are burned how many moles of O2 are needed?
To determine the number of moles of O2 needed to burn 9.45 moles of C2H2, we first need to write down the balanced chemical equation for the combustion of acetylene (C2H2):
2 C2H2 + 5 O2 → 4 CO2 + 2 H2O
From this equation, we can see that 5 moles of O2 are required to burn 2 moles of C2H2. To find out how many moles of O2 are needed for 9.45 moles of C2H2, we can use a simple proportion:
(5 moles O2 / 2 moles C2H2) = (x moles O2 / 9.45 moles C2H2)
To solve for x (moles of O2 needed), simply cross-multiply and divide:
x = (5 moles O2 * 9.45 moles C2H2) / 2 moles C2H2
x ≈ 23.63 moles O2
Therefore, approximately 23.63 moles of O2 are needed to burn 9.45 moles of C2H2.
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A piston in an engine is designed to have a maximum volume of 0.885 l when fully expanded and a minimum volume of 0.075 l when fully depressed. if the gas causes the piston to exceed its maximum volume, it will fail. in a testing situation, a hydrocarbon gas is combusted while the piston is depressed, causing the internal temperature to increase very rapidly from 171°c to 5934°c. will the piston fail? show
To determine if the piston will fail, we need to calculate the volume of the gas at the higher temperature and see if it exceeds the maximum volume of the piston.
First, we need to assume that the gas behaves ideally and follows the gas laws. We can use the ideal gas law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
We know the initial volume of the gas is 0.075 L and the initial temperature is 171°C, which is 444 K (since we need to convert to Kelvin). We don't know the pressure or the number of moles, but we can assume they remain constant.
Next, we need to calculate the final volume of the gas when it is heated to 5934°C, which is 6207 K. We know that the pressure and number of moles remain constant, so we can rearrange the ideal gas law to solve for V:
V = nRT/P
We can plug in the values for n, R, P, and T, and solve for V:
V = (n x R x 6207 K) / P
Now we need to check if this final volume exceeds the maximum volume of the piston, which is 0.885 L. If it does, then the piston will fail.
To convert the final volume from liters to cubic centimeters (cc), we can multiply by 1000:
V = (n x R x 6207 K x 1000) / P
V = (n x 8.31 J/mol K x 6207 K x 1000) / P
V = (n x 51476870 J/mol) / P
Assuming the pressure remains constant, we can set the initial and final volumes equal to each other and solve for n:
n x 8.31 J/mol K x 444 K = n x 51476870 J/mol x 6207 K
n = (8.31 J/mol K x 444 K) / (51476870 J/mol x 6207 K)
n = 2.34 x 10^-7 mol
Now we can plug in the value for n and solve for the final volume:
V = (2.34 x 10^-7 mol x 8.31 J/mol K x 6207 K x 1000) / 1 atm
V = 1.42 cc
Since the final volume of the gas is only 1.42 cc, which is much smaller than the maximum volume of the piston (0.885 L or 885 cc), the piston will not fail.
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An ecosystem is a term used by scientists to describe a specific level of organization in an environment. Which of the
following lists make up an ecosystem? (AKS 6a)
A soil, air, sunlight, rocks, rain
O B. Different populations of wildebeest
O C. Leaopards, giraffes, antelope, hyenas
OD. Rain, grass, worms, jackals, lions, sunlight
An ecosystem is an interconnected set of living and non-living components that interact and influence each other to form a functional unit.
Here all options are correct
As such, it is a complex system of energy and material exchanges between its components. A list of components that make up an ecosystem can include soil, air, sunlight, rocks, rain, and different populations of living organisms. The living components of an ecosystem include plants, animals, and microorganisms, such as worms and jackals. These organisms interact and depend on each other for survival, such as the leopards, giraffes, antelope, and hyenas that rely on the grass and other plants that are watered by the rain.
The sunlight provides energy for photosynthesis, which is essential for the production of food and oxygen. The rocks, soil, and air in the environment provide the physical structure that allows different organisms to interact and thrive. All of these components contribute to the health of an ecosystem, and each component plays an important role in maintaining the balance of the ecosystem.
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