Find x in the equation. 2 times x plus one fourth equals one fourth times x plus 2
HELP PLEASE!
I WILL MAKE YOU GENIUS!

Answers

Answer 1
Answer

x = 1

Step-by-Step Explanation

[tex]2x + \dfrac{1}{4} = \dfrac{1}{4}x + 2[/tex]

1. subtract (1/4)x from both sides

[tex]\dfrac{7}{4}x + \dfrac{1}{4} = 2[/tex]

2. subtract 1/4 from both sides

[tex]\dfrac{7}{4}x = \dfrac{7}{4}[/tex]

3. multiply both sides by the reciprocal of x's coefficient

The reciprocal of [tex]\frac{\bold{7}}{\bold{4}}[/tex] is [tex]\frac{\bold{4}}{\bold{7}}[/tex].

[tex]\left(\dfrac{\not4}{\not7}\right)\left(\dfrac{\not7}{\not4}x\right) = \left(\dfrac{\not7}{\not4}\right)\left(\dfrac{\not4}{\not7}\right)[/tex]

[tex]\boxed{x = 1}[/tex]


Related Questions

please do both will give brainliest and it's for 72 points

Answers

Step-by-step explanation:

Pick any of the two points...I'll use the first two

calculate slope:     m  = ( y1-y2) / (x1-x2) =  (-14 - -5) / (-2 -1) = -9/-3 = 3

   equation of a line in slope intercept form is y = mx+ b

      so now you have    y = 3x + b  

             sub in any of the x,y  points given (8,16)  to calculate 'b'

                             16 = 3 (8) + b

                                  b = -8

so your first line is     y = 3x - 8

In a similar fashion, for the second one   m = - 5/8    and b = 2

           y = -5/8 x + 2

It is kinda hard but just try it

Answers

Answer:

we 1st can get the weight of rat by

1 rat and 1 cat + 1 dog and rat = 30

2 rat + 1 cat + 1 dog = 30

Then 1 rat and cat measure 24 so

2 rat + 24 =30

2 rat + 24 =30 1 rat = 3 kg

2 rat + 24 =30 1 rat = 3 kg 1 cat + 1 rat = 10

2 rat + 24 =30 1 rat = 3 kg 1 cat + 1 rat = 101 cat + 3kg = 10

2 rat + 24 =30 1 rat = 3 kg 1 cat + 1 rat = 101 cat + 3kg = 101 cat = 7kg and

2 rat + 24 =30 1 rat = 3 kg 1 cat + 1 rat = 101 cat + 3kg = 101 cat = 7kg and 1 dog + 1 rat = 20 kg

2 rat + 24 =30 1 rat = 3 kg 1 cat + 1 rat = 101 cat + 3kg = 101 cat = 7kg and 1 dog + 1 rat = 20 kg 1 dog + 3kg = 20 kg

2 rat + 24 =30 1 rat = 3 kg 1 cat + 1 rat = 101 cat + 3kg = 101 cat = 7kg and 1 dog + 1 rat = 20 kg 1 dog + 3kg = 20 kg 1 dog = 17kg

so we get the weight of each now we r going to sum them 1 rat + 1 cat + 1 dog = x

1 rat + 1 cat + 1 dog = x 3 kg + 7 kg + 17 kg = x

1 rat + 1 cat + 1 dog = x 3 kg + 7 kg + 17 kg = x 27 kg = x ..... is the mass of 3 of them

Rat=3kg cat=7kg dog=17kg all three combined = 27kg

Let f: R+R be a function that satisfies O 0. (a) Show that the series cosh(f(n)) ne1 diverges regardless of the rule for f. (b) Show that the series ( f(n) 2n3 - 1 converges regardless"

Answers

As we have proved that the series cosh(f(n)) ne1 diverges regardless of the rule for f, and that the series f(n) 2n³ - 1 converges regardless of the rule for f.

The comparison test states that if the terms of a series can be bounded below by a divergent series, then the given series also diverges.

In this case, we can bound the terms of cosh(f(n)) below by the series eⁿ. To see why, note that cosh(x) >= 1 for all x > 0. Thus, we have cosh(f(n)) >= 1 for all n. On the other hand, we know that e^x > 1 for all x > 0. Therefore, we have eⁿ > 1 for all n.

Since eⁿ diverges by the assumption that f satisfies O<f(), the comparison test tells us that cosh(f(n)) ne1 also diverges. Thus, the series cosh(f(n)) ne1 diverges regardless of the rule for f.

Moving on to the second part of the question, we are asked to show that the series ( f(n) 2n3 - 1 converges regardless of the rule for f. Again, we can use the comparison test to show convergence.

We can bound the terms of the given series by the series 1/n². To see why, note that for all n > 1, we have f(n) > 0 since the domain of f is restricted to R+. Thus, we have f(n)² < f(n) 2n³ - 1. Dividing both sides by n⁶, we get f(n)²/n⁶ < ( f(n) 2n³ - 1)/n⁶.

Now, note that the series 1/n² converges by the p-test (which states that the series 1/nᵃ converges if p > 1).

Therefore, by the comparison test, the series ( f(n) 2n³ - 1 also converges regardless of the rule for f.

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Complete Question:

Let f: R+R be a function that satisfies O<f() So for all x > 0. (a) Show that the series cosh(f(n)) ne1 diverges regardless of the rule for f. (b) Show that the series ( f(n) 2n3 - 1 converges regardless of the rule for f.

What is a good percentage (in decimal form) to multiply your earning to estimate your paycheck?

Answers

To estimate your paycheck, a good percentage to multiply your earning by would be 0.75 or 75%. When calculating your paycheck, it's important to account for taxes, deductions, and other withholdings that may be taken out of your gross pay.  

This accounts for taxes, deductions, and other withholdings that are typically taken out of your paycheck before you receive your net pay. For example, if you earn $1,000 per pay period, multiplying by 0.75 would give you an estimated net pay of $750. However, keep in mind that this is just an estimate and your actual net pay may vary depending on your specific tax situation and other factors.

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In triangle ABC, angle B is a right angle. Give me measures of side BC and hypotenuse AC so that the measure of Angle A is greater than 75 degrees

Answers

In triangle ABC with a right angle at B, to make angle A greater than 75 degrees, you can choose BC = 1 unit and hypotenuse AC = 3 units.

In a right-angled triangle, the sine of an angle is the ratio of the length of the side opposite the angle to the length of the hypotenuse. In our case, sin(A) = BC/AC. To make angle A greater than 75 degrees, we need sin(A) > sin(75). Using a calculator, sin(75) ≈ 0.9659. So, we need BC/AC > 0.9659.

Let's take BC = 1 unit, then we need AC > 1/0.9659 ≈ 1.035 units. To keep it simple, we can choose AC = 3 units. Now, sin(A) = 1/3 ≈ 0.3333, and the corresponding angle A is around 19.47 degrees. Note that this is greater than 75 degrees, fulfilling the requirement.

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x-3 5. The function f(x)=- has X? - 8x+15 Math 1P97 Final Exam April 2010 page 3 of 19 a. a discontinuity at x = 3 only b. discontinuities at = 3 and x = 5 c. no discontinuities d. a discontinuity at x = 5 only e, none of the above

Answers

The correct option is: (d) a discontinuity at x = 5 only.

How to find which function f(x)=- has X?

The function f(x) is defined as:

[tex]f(x) = (x-3)/(x^2 - 8x + 15)[/tex]

The denominator of this function can be factored as:

[tex]x^2 - 8x + 15 = (x - 3)(x - 5)[/tex]

So the function can be rewritten as:

f(x) = (x - 3)/[(x - 3)(x - 5)]

Simplifying this expression, we get:

f(x) = 1/(x - 5)

Now it is clear that the function has a discontinuity at x = 5, since the denominator of the simplified expression becomes zero at that point.

Therefore, the correct option is:

d. a discontinuity at x = 5 only

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Mrs. Austin has 10 students in her class. She asked them whether they like football (F) or basketball (B). Sarah, Allen, kara, Todd said football. Joseph, Lydia, Matt said basketball. Caleb and Britney said they like both. Ethan said he didn't like either. 1. Define the universal set. 2. Define the two subsets. ​

Answers

1.The universal set is defined as {Sarah, Allen, Kara, Todd, Joseph, Lydia, Matt, Caleb, Britney, Ethan}.

2.Caleb and Britney are included in both subsets since they like both football and basketball.

1. The universal set (U) consists of all the students in Mrs. Austin's class. In this case, U = {Sarah, Allen, Kara, Todd, Joseph, Lydia, Matt, Caleb, Britney, Ethan}.

2. The two subsets are:
 a) The set of students who like football (F) = {Sarah, Allen, Kara, Todd, Caleb, Britney}
 b) The set of students who like basketball (B) = {Joseph, Lydia, Matt, Caleb, Britney}

Caleb and Britney are included in both subsets since they like both football and basketball.

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4 Il y f(x, y) da = Sot Shot Sot Staf (x, y) dxdy x D
Characteristics of the drawing of D, you can choose several answers:
1. It is the region in the first quadrant that is bounded from the right by the line x = 2
2. It is the region in the first quadrant that is bounded above by y = x
3. It is the region in the first quadrant that is bounded from the left by the line x = 0
4. It is the region in the first quadrant that is bounded above by y = x2
5. It is the region in the first quadrant that is bounded below by y = 0
6. It is the region in the first quadrant that is bounded below by y = 2
which of these 6 options is correct?

Answers

The correct option is option 3.

How to determine the boundaries of the region?

Based on the given integral, region D is in the first quadrant, and its boundaries are not explicitly given. However, we can deduce the boundaries of D by looking at the integrand. Since the integrand is f(x,y), we can see that we are integrating over the entire region D, which means that D must be the rectangle that contains all the other regions mentioned in the options.

Therefore, option 1 is not correct, as D is not bounded from the right by x=2, but rather extends indefinitely to the right. Option 2 is also not correct, as D extends beyond the line y=x. Option 4 is not correct either, as D is not bounded above by y=x^2, but rather extends beyond it. Options 5 and 6 are also not correct, as D extends beyond the lines y=0 and y=2.

Therefore, the correct option is option 3, which states that D is the region in the first quadrant that is bounded from the left by the line x=0. This is correct, as D extends indefinitely to the right, and is bounded from the left by x=0.

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Under which
transformation would AA'B'C', the wen 2.
image of AABC, not be congruent to AABC?
a. reflection over the y-axis
b.
rotation of 90° clockwise about the origin
c. translation of 3 units right and 2 units down
d. dilation with a scale factor of 2 centered at
the origin

Answers

The answer is a reflection over the y-axis

Please help me with this ASAP!

Answers

Answer:

19

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

x > -1 but drawn on a graph for inequality due tmr !!!

Answers

The graph of the inequality is on the image at the end.

How to graph an inequality?

Here we have an inequality on one variable which is:

x > -1

This is the set of all the numbers larger than -1.

To graph this, draw an open circle at x = -1 (the open circle means that the value x = -1 is not a solution of the inequality) and then draw a line that goes to the right of that circle (because x is larger than that).

The graph of the inequality should look like the one at the end of this answer

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consider light falling on a single slit, of width 1.2 μm, that produces its first minimum at an angle of 32.3°. randomized variables θ = 32.3° w = 1.2 μm

Answers

The wavelength of the light is approximately 0.687 μm.

Using the single slit diffraction formula, we have:

sin θ = (mλ) / w

where m is the order of the minimum, λ is the wavelength of the light, and w is the width of the slit.

We can rearrange the formula to solve for the wavelength of the light:

λ = (w sin θ) / m

Plugging in the given values, we get:

λ = (1.2 μm)(sin 32.3°) / 1 = 0.687 μm

Therefore, the wavelength of the light is approximately 0.687 μm.

The wavelength is the distance between two consecutive peaks or troughs in a wave. It is typically represented by the Greek letter lambda (λ) and is measured in meters or other units of length. The wavelength is an important characteristic of any wave, as it determines many of its properties, such as its speed and frequency.

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: Ben practises playing the Oboe daily.
The time (in minutes) he spends on
daily practice over 28 days is as follows:
10, 15, 30, 35, 40, 40, 45, 55, 60, 62,
64, 64, 66, 68, 70, 70, 72, 75, 75, 80,
82, 84, 90, 90, 105, 110, 120, 180
Find the median time.
Find the lower quartile.
Find the upper quartile.
Find the range.
a
b
c
d
(2 marks)
(2 marks)
(2 marks)
(2 marks)
e Determine whether there are any
outliers in the data.
(4 marks)
f Draw a box-and-whisker
the above data.
diagram for
(3 marks)

Answers

The values of given conditions are:

1. median=70

2. Lower quartile=40

3. Upper quartile=87

4. Range=170

5. IQR=47

6. Lower outlier threshold=-20.5

7. Upper outlier threshold=160.5

What is median?

In statistics, the median is the value separating the higher half from the lower half of a dataset. In other words, it is the middle value of a dataset when it is ordered in ascending or descending order.

Here,

To find the median time, we need to arrange the data in order from least to greatest and find the middle value.

10, 15, 30, 35, 40, 40, 45, 55, 60, 62, 64, 64, 66, 68, 70, 70, 72, 75, 75, 80, 82, 84, 90, 90, 105, 110, 120, 180

There are 28 values in the data set, so the median is the average of the 14th and 15th values:

Median = (70 + 70)/2

= 70

To find the lower quartile, we need to find the median of the lower half of the data set:

10, 15, 30, 35, 40, 40, 45, 55, 60, 62, 64, 64, 66, 68

There are 14 values in the lower half, so the lower quartile is the median of these values:

Lower quartile = (40 + 40)/2

= 40

To find the upper quartile, we need to find the median of the upper half of the data set:

72, 75, 75, 80, 82, 84, 90, 90, 105, 110, 120, 180

There are 14 values in the upper half, so the upper quartile is the median of these values:

Upper quartile = (84 + 90)/2

= 87

To find the range, we subtract the smallest value from the largest value:

Range = 180 - 10

= 170

To determine if there are any outliers in the data set, we need to calculate the interquartile range (IQR):

IQR = Upper quartile - Lower quartile

= 87 - 40

= 47

Any value that is more than 1.5 times the IQR below the lower quartile or above the upper quartile is considered an outlier.

Lower outlier threshold = Lower quartile - 1.5IQR

= 40 - 1.547

= -20.5

Upper outlier threshold = Upper quartile + 1.5IQR

= 87 + 1.547

= 160.5

To draw a box-and-whisker plot, we need to plot a box from the lower quartile to the upper quartile, with a line inside the box representing the median. We then draw whiskers extending from the box to the smallest and largest values that are not outliers. The box extends from 40 to 87, with a line at 70 representing the median. The whisker on the left extends to the smallest non-outlier value of 10, and the whisker on the right extends to the largest non-outlier value of 120.

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Line x is parallel to line y. Line z intersect lines x and y. Determine whether each statement is Always True.

Answers

Line x is perpendicular to line y. Line z crosses lines x and y. Only statements 3 and 4 are true.

∠6 = ∠8 is not true because they both lie on the same plane and makes an angle of 180° and can never be true. ∠6 = ∠1 is also not true because ∠1 is clearly obtuse angle and ∠6 is clearly acute angle so they cannot be equal. Hence, statement a and b are false.

∠7 = ∠3 is always true because they are corresponding angles and corresponding angles are always equal. m∠2 + m∠4 = 180° is also true because they lie on same plane and have common vertex and hence, they are supplementary angles and make a sum of 180°.  Hence, statement 3 and 4 is always true.

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Out of all the people who like chocolate, what is the relative frequency for selecting a teen?

Answers

The relative frequency for selecting a teen out of all the people who like chocolate is calculated by dividing the number of teens who like chocolate (N) by the total number of people who like chocolate (T).

To find the relative frequency for selecting a teen out of all the people who like chocolate, you need to follow these steps:

Step 1: Determine the total number of people who like chocolate (let's call this T).
Step 2: Determine the number of teens who like chocolate (let's call this N).
Step 3: Calculate the relative frequency by dividing the number of teens who like chocolate (N) by the total number of people who like chocolate (T).

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Find y such that
∫x^5 dx = ∫ x^y dx

Answers

The value of y that satisfies the equation [tex]\int x^5 dx = \int x^y dx[/tex] is y = -1.

We know that the indefinite integral of x^5 dx is (1/6) x^6 + C, where C is

the constant of integration. Therefore:

[tex]\int x^5 dx = (1/6) x^6 + C[/tex]

We want to find y such that [tex]\int x^5 dx = \int x^y dx[/tex]. Using the power rule of integration, the indefinite integral of [tex]x^y[/tex] dx is [tex](1/(y+1)) x^{(y+1)} + C[/tex], where C is the constant of integration. Therefore:

[tex]\int x^y dx = (1/(y+1)) x^{(y+1)} + C[/tex]

For these two integrals to be equal, we need:

[tex](1/6) x^6 + C = (1/(y+1)) x^{(y+1) } + C[/tex]

Subtracting C from both sides, we get:

[tex](1/6) x^6 = (1/(y+1)) x^{(y+1)}[/tex]

Multiplying both sides by (y+1), we get:

[tex](1/6) x^6 (y+1) = x^{(y+1)}[/tex]

Now, we can equate the powers of x on both sides:

[tex]x^6 (y+1) = x^{(y+1)}[/tex]

Using the fact that[tex]x^a \times x^b = x^{(a+b)}[/tex], we can simplify the left-hand side:

[tex]x^(6(y+1)) = x^{(y+1)}[/tex]

Now, we can equate the exponents on both sides:

6(y+1) = y+1

Simplifying, we get:

6y + 6 = y + 1

5y = -5

y = -1

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what is the gcf of 40 and 70​

Answers

Answer:

10

Step-by-step explanation:

40 = 10 × 4

70 = 10 × 7

GCF of 40 and 70 = 10

The mainsail of a boat has the dimensions shown. If the mainsail is a right triangle, what is the exact height of the mainsail shown?

a.) 2√6 feet
b.) 24 feet
c.) 4√78 feet
d.) 2√410 feet

Answers

Step-by-step explanation:

use Pythagorean theorem to find the height

c = 38 ft

a = 14 ft

a² + b² = c²

(14)² + b² = (38)²

b² = 1444 - 196

b² = 1248

b = √1248

b = √16 × 78

b = 4√78 feet

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If nori made 2% in interest on $5,000 and her brother Sean made 1% in interest on $10,000, who made more money in interest?

Answers

Answer: Nori

Step-by-step explanation:

2% of 5000 = 100

1% of 1000 = 10

1 1 = 2. F(x, y) = (xy2 + 1)i + (x2y – 2y)j, C:r(t) = (t + sin(zat), t + cos(art)), ostsi. (a) Verify that F is a conservative vector field. (b) Find a function f such that F= = Vf (c) Use part (a)

Answers

To verify that F is a conservative vector field, we need to check if its curl is zero.

First, let's find the curl of F:

curl F = (∂Q/∂x - ∂P/∂y)k

where P = xy^2 + 1 and Q = x^2y - 2y

∂Q/∂x = 2xy and ∂P/∂y = 2xy

So,

curl F = (2xy - 2xy)k = 0

Since the curl is zero, we can conclude that F is a conservative vector field.

To find a function f such that F = ∇f, we need to integrate the components of F with respect to their respective variables:

∂f/∂x = xy^2 + 1

f = (1/2)x^2y^2 + x + g(y)

Taking the partial derivative of f with respect to y, we get:

∂f/∂y = x^2 + g'(y) = x^2y - 2y

Integrating this with respect to y, we get:

g(y) = -y^2

So,

f = (1/2)x^2y^2 + x - y^2

Therefore,

F = ∇f = (∂f/∂x)i + (∂f/∂y)j

= (xy^2 + 1)i + (x^2y - 2y)j

Finally, using the conservative property of F, we can use the line integral to find the work done by F along the given curve C:

W = ∫C F · dr

= ∫C (∂f/∂x)dx + (∂f/∂y)dy

= f(r(ostsi)) - f(r(0))

= (1/2)(ostsi)^2(ostsi)^2 + ostsi - (ostsi)^2 - (-1)

= 1/2(ostsi)^4 + ostsi + 1

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Tanya made this graph that represents the total cost for each of the three locations. Depending on the number of students that attend. Which function represents the cost of the restaurant 

Answers

The functions that represents the cost are

(a) y = 8800, (b) y = 1900 + 4/7x and (c) y = 4800, x ≤ 150;  y = 1200 + 24x x > 150

Identifying the function that represents the cost

From the question, we have the following parameters that can be used in our computation:

The graph


The function (a) is a horizontal line that passes through y = 8800

So, the function is

y = 8800

The function (b) is a linear function that passes through

(0, 1900) and (175, 2000)

So, the function is

y = 1900 + 4/7x

The function c is a piecewise function with the following properties

Horizontal line of y = 4800 uptill x = 150Linear function of (150, 4800) and (200, 6000)

So, the function is

y = 4800, x ≤ 150

y = 1200 + 24x x > 150

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Solve the inequalities 1/3(2x-1)≤1-2/5(2-3x)

Answers

The solution to the inequality is x ≥ -1.

We solve the inequality 1/3(2x-1)≤1-2/5(2-3x).

Let's go step by step:
Begin by distributing the fractions to the terms inside the parentheses:
  (1/3 * 2x) - (1/3 * 1) ≤ 1 - (2/5 * 2) + (2/5 * 3x)
  (2x/3) - (1/3) ≤ 1 - (4/5) + (6x/5)
Combine like terms on each side of the inequality:
  (2x - 1)/3 ≤ (1 - 4/5) + 6x/5
  (2x - 1)/3 ≤ (1/5) + 6x/5.

To eliminate the fractions, find a common denominator, which in this case is 15.

Multiply each term by 15:
  15 * (2x - 1)/3 ≤ 15 * (1/5) + 15 * 6x/5
  5(2x - 1) ≤ 3 + 18x
Distribute and simplify:
  10x - 5 ≤ 3 + 18x
Move the variables to one side and constants to the other side:
  10x - 18x ≤ 3 + 5
  -8x ≤ 8
Divide both sides by -8 (remember to flip the inequality sign since we are dividing by a negative number):
  x ≥ -1.

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determine if each of the numbers below is a solution to the inequality 3x-2<2-2x

Answers

The solution set of the inequality 3x-2 < 2-2x is:

(4/5, ∞)

Which numbers are solutions for the inequality?

To find this we need to isolate the variable in the inequality.

Here we have:

3x - 2 < 2 - 2x

add 2x in both sides and add 2 in both sides, then we will get:

3x + 2x < 2 + 2

5x < 4

Now we can divide both sides by 5 to get:

x < 4/5

That is the inequality solved.

Then the solution set of the inequality is:

(4/5, ∞)

The set of all real numbers larger than 4/5.

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An 8-sided solid is labeled with faces 1, 2, 3, skip ,4, 5, 6, skip. what is the sample space for the number solid, and what is the probability of rolling a 1?

Answers

The sample space for the number solid is {1, 2, 3, 4, 5, 6} and the probability of rolling 1 is 1/6.

The sample space refers to the set of all possible outcomes of an experiment, while a sample value is a specific outcome in the sample space.

For the given 8-sided solid, the sample space would be {1, 2, 3, 4, 5, 6}, as the faces labeled "skip" are not counted as sample values.

Now, let's calculate the probability of rolling a 1. Probability is the likelihood of a particular outcome occurring, which can be calculated by dividing the number of successful outcomes (in this case, rolling a 1) by the total number of possible outcomes.

The total number of possible outcomes is 6 (1, 2, 3, 4, 5, and 6). There is only one successful outcome: rolling a 1.

So, the probability of rolling a 1 is:

P(1) = (Number of successful outcomes) / (Total number of possible outcomes)
P(1) = 1 / 6

Thus, the probability of rolling a 1 on this 8-sided solid is 1/6 or approximately 0.1667, or 16.67%.\

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I don't understand how to get the answer can someone help me?

Answers

Answer:

  C. R+S+T = 201°

Step-by-step explanation:

You want to know which of the offered angle relations is true regarding quadrilateral RSTU.

Angles

The sum of angles in a quadrilateral is 360°. You use this fact to find angle T. Then you can compute the various differences to see which one matches the answer choices.

  T = 360° -R -S -U = 55°

In the attached calculator display, we have done exactly that. We find ...

  T -R = 38° . . . . A is false

  S -T = 74° . . . . B is false

  R +S +T = 201° . . . . C is TRUE

  R +T +U = 231° . . . . D is false

Answer:

To answer your question, we need to use some properties of rectangles and triangles.

A rectangle has four right angles, so angle R = angle S = angle T = angle U = 90 degrees.

The sum of the angles in a triangle is 180 degrees, so we can find the values of a, b, c, d, e, and f by using this property. For example, a + b + angle S = 180, so a + b = 90. Similarly, c + d = 90, e + f = 90, and f + g + angle U = 180, so f + g = 30.

Now we can evaluate each statement and see which one is true.

A) The difference between the measures of LT and LR is 4°. This is false, because LT and LR are both sides of a rectangle, so they are equal in length. The difference between them is zero, not four.

B) The difference between the measures of 2S and LT is 95°. This is false, because 2S is an angle and LT is a length. They have different units and cannot be compared or subtracted.

C) The sum of the measures of LR, 2S, and LT is 201°. This is false, because LR and LT are lengths and 2S is an angle. They have different units and cannot be added together.

D) The sum of the measures of LR, LT, and ZU is 193°. This is true, because LR and LT are lengths of a rectangle, so they are equal. ZU is an angle that can be found by subtracting e and f from 90 (since they form a right triangle with ZU). So ZU = 90 - e - f = 90 - (90 - c - d) - (90 - a - b) = a + b + c + d - 90. We know that a + b = c + d = 90, so ZU = 90 - 90 = 0.

Therefore, the sum of LR, LT, and ZU is LR + LT + 0 = 2LR = 2(17) = 34 degrees.

The correct answer is D.

Step-by-step explanation:

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Un terreno de forma rectangular tiene un perímetro de 105 metros. Si el ancho es la mitad del largo, ¿Cuáles son las medidas del terreno? *

Answers

Sea "l" la medida del largo del terreno y "a" la medida del ancho del terreno.

De acuerdo con el problema, el ancho es la mitad del largo, es decir, a = l/2.

El perímetro de un rectángulo se calcula sumando las longitudes de sus cuatro lados, por lo que en este caso:

Perímetro = 2l + 2a = 2l + 2(l/2) = 3l

Sabemos que el perímetro es de 105 metros, entonces:

3l = 105

l = 105/3 = 35

Por lo tanto, el largo del terreno es 35 metros. Y, como el ancho es la mitad del largo, entonces:

a = l/2 = 35/2 = 17.5

Por lo tanto, el ancho del terreno es de 17.5 metros.

En resumen, las medidas del terreno son 35 metros de largo y 17.5 metros de ancho.

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rotation 90 degrees clockwise about the origin, ignore the dots i kinda started it then i got lost

Answers

When the points are rotated 90 degrees clockwise about the origin, the result is:

I: (1, -3)J: (-1, -5)H: (-3, -3)

How to rotate about the origin ?

To rotate a point 90 degrees clockwise about the origin, you can use the following rule: (x, y) becomes (y, -x). Let's apply this rule to the given points:

I - (3, 1)

Rotated I: (1, -3)

J - (5, -1)

Rotated J: (-1, -5)

H - (3, -3)

Rotated H: (-3, -3)

So, after a 90-degree clockwise rotation about the origin, the new coordinates of the points are:

I: (1, -3)

J: (-1, -5)

H: (-3, -3)

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Greta sells advertising space for her school yearbook. Last year, a quarter-page ad cost $110. This year, Greta's teacher asks her to mark down the price by 15% to attract more sponsors. Greta wants to know the price after the markdown. ​

Answers

The price of the advertisement that originally costs $110 after a 15% markdown is $ 83.5.

Original price = $110

Markdown percent = 15%

Reduce in price = 15% of 110

To calculate this, we divide the percent by 100 and multiply it by the number given. Like in the above case, we divide 15 by 100 to get 0.15 and multiply it by 110.

= 0.15 * 110 = 16.5

Price after markdown = original price - reduction in price

= 110 - 16.5

= $ 83.5

Thus, the price for a quarter-page ad of the school yearbook which used to be $110 has come down to $83.5 after a 15 % markdown to attract more sponsors.

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The ratio of mass to volume for a type of metal is 27 grams to 10 cubic centimeters. a sample of the metal has a mass of 81 grams

Answers

The volume of the sample of the metal is 30 cubic centimeters.

The volume of the sample of the metal can be calculated using the given ratio of mass to volume. Since the ratio is 27 grams to 10 cubic centimeters, we can set up a proportion:

27 grams / 10 cubic centimeters = 81 grams / x cubic centimeters

Solving for x, we get:

x = (81 grams x 10 cubic centimeters) / 27 grams
x = 30 cubic centimeters


The ratio of mass to volume is an important property of matter, known as density. It describes how tightly packed the particles in a substance are. In this case, the ratio of mass to volume for the metal is 27 grams to 10 cubic centimeters, meaning that a given amount of this metal will weigh 27 grams for every 10 cubic centimeters of space it takes up.

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Find the critical points for the function f(x, y) = x³ + y³ – 9x² – 3y - 6 = and classify each as a local maximum, local minimum, saddle point, or none of these. critical points: (give your points as a comma separated list of (x,y) coordinates.) classifications: (give your answers in a comma separated list, specifying maximum, minimum, saddle point, or none for each, in the same order as you entered your critical points)

Answers

The critical points and their classifications are:

(0, 1) - saddle point

(0, -1) - saddle point

(6, 1) - local minimum

(6, -1) - local minimum

To find the critical points of the function f(x, y) = x³ + y³ – 9x² – 3y - 6, we need to find the points where the partial derivatives of f with respect to x and y are zero.

∂f/∂x = 3x² - 18x = 3x(x - 6)

∂f/∂y = 3y² - 3 = 3(y² - 1)

Setting these partial derivatives equal to zero and solving for x and y, we get:

x = 0 or x = 6

y = ±1

So the critical points are (0, 1), (0, -1), (6, 1), and (6, -1).

To classify each critical point, we need to compute the second partial derivatives of f:

∂²f/∂x² = 6x - 18

∂²f/∂y² = 6y

∂²f/∂x∂y = 0

At (0, 1):

∂²f/∂x² = -18 < 0 (concave down)

∂²f/∂y² = 6 > 0 (concave up)

So (0, 1) is a saddle point.

At (0, -1):

∂²f/∂x² = -18 < 0 (concave down)

∂²f/∂y² = 6 > 0 (concave up)

So (0, -1) is a saddle point.

At (6, 1):

∂²f/∂x² = 18 > 0 (concave up)

∂²f/∂y² = 6 > 0 (concave up)

So (6, 1) is a local minimum.

At (6, -1):

∂²f/∂x² = 18 > 0 (concave up)

∂²f/∂y² = 6 > 0 (concave up)

So (6, -1) is a local minimum.

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