Find the value of sin theta, if tan theta = 4; 180 < theta <270.

a. -4 (square root)17/ 17
b. -4
c. -1/4
d. (square root)7/ 4

Please select the best answer from the choices provided
Ο Α
O B
О С
O D

Find The Value Of Sin Theta, If Tan Theta = 4; 180 &lt; Theta &lt;270.a. -4 (square Root)17/ 17 B. -4c.

Answers

Answer 1

Answer:  You can use the identity THE PICTURE THAT I PUT THERE

The sign is negative because the angle is in the 3rd quadrant.  This corresponds to ...  a. -(4√17)/17

Find The Value Of Sin Theta, If Tan Theta = 4; 180 &lt; Theta &lt;270.a. -4 (square Root)17/ 17 B. -4c.
Answer 2

value of sin ( theta ) = -4 (square root of ) 17 / 17

What are Trigonometry Functions ?

Real functions which relate to an angle of a right angled triangle to ratios of two side length.

Given

tan (theta) = 4`

sin(theta) = tan (theta ) / (1 + tan ^ theta)^(1/2)

sin(theta) = 4/(1+(4)^2)^(1/2)

                = 4/ (17)^ (1/2)

                multiplying  and dividing by 17 ^ (1/2), we get

                =  -4 (17) ^ (1/2) / 17 ( negative since angle is in third quadrant and tan is negative in that quadrant )

option a) -4 (square root of ) 17 / 17

Learn more about Trigonometry Functions:

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Answers

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Number of e-books Eli needs to read per month is Greater than 6

Step-by-step explanation:

Given - Over the next 17 months, Eli needs to read more  than 102 e-books.

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To find - Solve the inequality to find the  number of e-books Eli needs to  

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Answers

Answer:

The coordinates of the intersection of the diagonal of the parallelogram are [tex]M(x,y) = (3,2)[/tex].

Step-by-step explanation:

Diagonals are represented by line segments GJ and KH. Since quadrilateral is a parallelogram, then coordinates of the intersection are located at midpoint of each diagonal ([tex]M(x,y)[/tex]). That is:

[tex]M(x,y) = G(x,y) + \frac{1}{2}\cdot \overrightarrow {GJ}[/tex]

[tex]M(x,y) = G(x,y) +\frac{1}{2}\cdot [J(x,y)-G(x,y)][/tex] (1)

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[tex]M(x,y) = (1,3) +\frac{1}{2}\cdot (4,-2)[/tex]

[tex]M(x,y) = (1,3) +(2,-1)[/tex]

[tex]M(x,y) = (3,2)[/tex]

There is another form:

[tex]M(x,y) = K(x,y) +\frac{1}{2}\cdot \overrightarrow{KH}[/tex]

[tex]M(x,y) = K(x,y) + \frac{1}{2}\cdot [H(x,y)-K(x,y)][/tex] (2)

If we know that [tex]K(x,y) = (2, 1)[/tex] and [tex]H(x,y) = (4,3)[/tex], the coordinates of the intersection of the diagonals of the parallelogram are:

[tex]M(x,y) = (2,1) + \frac{1}{2}\cdot [(4,3)-(2,1)][/tex]

[tex]M(x,y) = (2,1) + \frac{1}{2} \cdot (2,2)[/tex]

[tex]M(x,y) = (2,1) + (1,1)[/tex]

[tex]M(x,y) = (3,2)[/tex]

Therefore, the coordinates of the intersection of the diagonal of the parallelogram are [tex]M(x,y) = (3,2)[/tex].

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