Find the perimeter of each figure

Answer:

-----------------------------

AB is vertical with same x-coordinates, and BC is horizontal with same y-coordinates.

Hence this is a right triangle.

Its area is:

The following expression is equivalent to [tex]x^{-5/3}[/tex] as option B that is 1/∛x⁵.

A fraction is a numerical representation of a part or a portion of a whole. It is expressed as one integer (numerator) divided by another integer (denominator), separated by a horizontal line.

Here,

We can rewrite [tex]x^{-5/3}[/tex]as [tex](1/ x^{^(5/3)})[/tex].

The negative exponent in the numerator tells us that we need to move the term to the denominator of a fraction and change the sign of the exponent to make it positive. Similarly, the fractional exponent in the denominator indicates that we need to take the reciprocal of the term and change the sign of the exponent to make it positive.

Therefore, we can rewrite [tex]x^{-5/3}[/tex] as:

[tex](1/ x^{^(5/3)})[/tex]

or

[tex]x^{-5/3}[/tex] = [tex](1/ x^{^(5/3)})[/tex]

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Complete question:

Which of the following is equivalent to [tex]x^{-5/3}[/tex]?

The given identity (P+1/P-1 + P+1/P+1)-(P-1/P+2 + P+1/P-2)=-4(2p² + 1)/(p²-4) (p² - 1) is proven below

Given the following equation

(P+1/P-1 + P+1/P+1)-(P-1/P+2 + P+1/P-2)=-4(2p² + 1)/(p²-4) (p² - 1)

We start by simplifying the left-hand side of the equation:

(P+1/P-1 + P+1/P+1)-(P-1/P+2 + P+1/P-2)= [(P²+1)/(P(P-1))] + [(P²+1)/(P(P+1))] - [(P²-1)/((P+2)P)] - [(P²+1)/((P-2)P)]

Next, we have the following steps to simplify the expression

= [(P³ + P² + P + 1)/(P(P²-1))] - [(P³ - 3P)/(P(P²-4))]

= [(P³ + P² + P + 1)(P²-4) - (P³ - 3P)(P²-1)]/[(P(P²-1))(P(P²-4))]

= [(P⁵ - 3P³ + P³ - 3P² + P² - 4P + P² - 4P - 4 + P³ - 3P)/(P⁴ - 5P² + 4)]

= [P⁵ - 2P³ - 6P² - 8P - 4]/[(P²-4)(P²-1)]

= -4(2p² + 1)/(p²-4) (p² - 1)

Hence, the given identity is proven.

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Answer:

f'(x) = 2x, so f'(-2) = 2(-2) = -4.

Answer:

Step-by-step explanation:

After organizing the data, the researcher must present them so they can be understood by those who will benefit from reading the study. The most useful method of presenting the data is by constructing statistical charts and graphs. There are many different types of charts and graphs, and each one has a specific purpose.

This chapter explains how to organize data by constructing frequency distributions

and how to present the data by constructing charts and graphs. The charts and graphs

illustrated here are histograms, frequency polygons, ogives, pie graphs, Pareto charts,

and time series graphs. A graph that combines the characteristics of a frequency distribution and a histogram, called a stem and leaf plot, is also explained.

Section 2–2 Organizing Data 35

2–3

Objective

Organize data using

frequency

distributions.

1

2–2 Organizing Data

Suppose a researcher wished to do a study on the number of miles that the

employees of a large department store traveled to work each day. The researcher

first would have to collect the data by asking each employee the approximate distance the

store is from his or her home. When data are collected in original form, they are called

raw data. In this case, the data are

1 2 6 7 12 13 2 6 9 5

18 7 3 15 15 4 17 1 14 5

4 16 4 5 8 6 5 18 5 2

9 11 12 1 9 2 10 11 4 10

9 18 8 8 4 14 7 3 2 6

Since little information can be obtained from looking at raw data, the research

Answer:

c

Step-by-step explanation:

its ez

The angle measures for this problem are given as follows:

θ = 150º and θ = 330º.

The trigonometric expression for this problem is given as follows:

[tex]\theta = \arctan{\left(-\frac{\sqrt{3}}{3}\right)}[/tex]

The solution to the arctangent function is the angle which has the given tangent value.

The angle on the first quadrant with a tangent value of sqrt(3)/3 is given as follows:

θ = 30º.

The quadrants in which the tangent is negative are given as follows:

2nd and 4th.

Hence the equivalent angles are given as follows:

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a) The formula relating y to t is: y = 45.1 * e^(-0.693/19 * t) b) there will be approximately 30.1 mg of the substance present after 9 minutes.

(a) The general formula for exponential decay is y = y0 * e^(-kt), where y is the amount at time t, y0 is the initial amount, k is the decay constant, and e is Euler's number.

To find the decay constant, we can use the fact that the half-life is 19 minutes. The formula for half-life is t1/2 = ln(2) / k, where ln(2) is the natural logarithm of 2.

Substituting t1/2 = 19 and ln(2) = 0.693 into the formula gives:

19 = 0.693 / k

k = 0.693 / 19

So the formula relating y to t is:

y = 45.1 * e^(-0.693/19 * t)

(b) To find how much will be present in 9 minutes, we can plug t = 9 into the formula we found in part (a):

y = 45.1 * e^(-0.693/19 * 9) ≈ 30.1 mg

So, there will be approximately 30.1 mg of the substance present after 9 minutes.

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For the function "f (x) = 120/x²", the domain of the function "f" is (b) All non zero real numbers.

The "Domain" of a function is the set of all possible "input-values" for which the function is defined. In this case, the function is defined as:

f (x) = 120/x²

The only restriction on the input values is that the denominator cannot be equal to zero, because division by zero is undefined.

So, the domain of the function f is all non-zero real numbers.

Therefore, the correct option is (b): All non-zero real numbers.

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The given question is incomplete, the complete question is

Given that f (x) = 120/x², What is the domain of the function f ?

(a) only positive integers,

(b) All non zero real numbers,

(c) only negative integers,

(d) All real numbers including zero.

Step-by-step explanation:

m ∠WXY = 72°

m ∠ 1 = m ∠ 2 + 6°

m ∠WXY = m ∠ 1 + m ∠ 2

72° = (m ∠ 2 + 6°) + m ∠ 2

72° = 2 × (m ∠ 2) + 6°

2 (m ∠ 2) = 72° - 6°

2 (m ∠ 2) = 66°

(m ∠ 2) = 33°

18. C

(m / 2) - 6 = (m / 4) + 2

---Multiply everything by the LCM of the denominators

---LCM = 4

2m - 24 = m + 8

m - 24 = 8

m = 32

19. A

k / 12 = 25 / 100

---We can simplify 25/100

---We want to simplify enough to where the denominator of 25/100 is a multiple or factor of 12

k / 12 = 1 / 4

---4 x 3 = 12, 1 x 3 = 3

k = 3

20. A

9 / 5 = 3x / 100

---Cross multiply and solve algebraically

(5 * 3x) = (9 * 100)

15x = 900

x = 60

Hope this helps!

The value of the 3 × f( - 4 ) - 3 × g( - 2 ) is 40

Given the following expression 3 × f( - 4 ) - 3 × g( - 2 ), to find the required values, we can assume that;

f( - 4 ) = 15

g( - 2 ) = 5

Substitute the given parameters into the expression to have:

3 × f(- 4 ) - 3 × g(- 2) = 3 × 15 - 3 × 5

= 45 - 5

= 40

Hence the value of the 3 × f( - 4) - 3 × g( - 2) is 40

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Answer:

x=38.6

Step-by-step explanation:

x=b/cos(alpha)

x=30/cos(39⁰)

x=38.602

The solution of the equation is x = -1.

Given is an equation we need to solve it,

3x/4 + 3 - 2x = -1/4 + x/2 +5

Multiplying the equation by 4 both the sides,

3x + 12 - 8x = -1 + 2x + 20

Combining the like terms,

3x - 8x - 2x = 20 - 1 - 12

3x - 10x = 7

-7x = 7

x = -1

Hence the solution of the equation is x = -1.

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The surface area of the rectangular prism is 210 in²

An equation is an expression that shows the relationship between numbers and variables using mathematical operators.

The surface area of a rectangular prism is the sum of each area for the surface.

Hence:

Surface area = 2(8 in * 5 in) + 2(5 in * 5 in) + 2(8 in * 5 in) = 210 in²

The surface area of the prism is 210 in²

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The value of the variable a in the equation is 5 from the calculation here.

We need to square of a number is described as a number that when multiplied by itself give the original number.

Also, index forms are described as those mathematical forms that are used to represent numbers that are too large or small.

From the information given, we have the equation;[tex]a^2[/tex]=25

find the square root of value of 25,

We have;25 = [tex]5^2[/tex]

Substitute the value, we get;[tex]a^2[/tex] =  [tex]5^2[/tex]

Take out the similar factor, this is their exponents.

We then have;

a = 5

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Complete question;

Find the value of a in the equation;a² = 25

Answer:

----------------------

Use the following identities:

Apply the identities to the given expression:

Answer:

i think its b sorry if  it's wrong

Step-by-step explanation:

The Surface area of the composite figure is calculated as approximately: 234 sq. cm

The surface area of the composite figure is the area surrounding the faces of the solid as a whole. Therefore, we have:

Surface area (SA) = Surface area of the square prism + surface area of the square pyramid - 2(area of base)

Area of base = area of square = 6 * 6 = 36 sq. cm.

Surface area of the square prism = 2a² + 4ah

a = 6 cm

h = 4 cm

Plug in the values:

Surface area of the square prism = 2(6²) + 4*6*4

= 72 + 96

= 168 sq. cm.

Surface area of the square pyramid = 2bs + b²

b = side length = 6 cm

s = slant height = √(8² + 3²) = 8.5 cm

Plug in the values:

Surface area of the square pyramid = 2 * 6 * 8.5 + 6² = 138 sq. cm.

Surface area of the composite figure = 168 + 138 - 2(36) = 234 sq. cm

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Answer:

Assuming you meant to write "x^2 - 4x - 12", there are a few equivalent forms that you could use to represent this expression. One common form is:

(x - 6)(x + 2)

Step-by-step explanation:

This is the factored form of the expression, which shows that it can be written as a product of two linear factors. To see why this is true, you can use the distributive property to expand the product:

(x - 6)(x + 2) = x(x + 2) - 6(x + 2) = x^2 + 2x - 6x - 12 = x^2 - 4x - 12

Answer:

$2,631.55

Step-by-step explanation:

To find the total amount in the account after 6 years, we can use the compound interest formula.

[tex]\boxed{\sf A=P\left(1+\dfrac{r}{n}\right)^{nt}}[/tex]

where:

Given values:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=2000\left(1+\dfrac{0.046}{4}\right)^{4 \cdot 6}[/tex]

[tex]\implies \sf A=2000\left(1+0.0115\right)^{24}[/tex]

[tex]\implies \sf A=2000\left(1.0115\right)^{24}[/tex]

[tex]\implies \sf A=2000\left(1.3157739...\right)[/tex]

[tex]\implies \sf A=2631.54794...[/tex]

Therefore, the total amount after 6 years is $2,631.55 rounded to the nearest cent.

Answer:

The correct answer is C, Graph D.

x^2 - 4x + 4 = (x - 2)^2.

The probability of Caleb selecting a 5 on the first selection and then selecting a 5 on the second selection after returning the card to the deck and shuffling is 1/9.

There are a total of 12 cards, out of which 4 are 5s. Since Caleb returns the card to the deck and shuffles it, the selection of the first card does not affect the probability of selecting a 5 on the second selection.

Therefore, the probability of selecting a 5 on the first selection is 4/12 = 1/3, and the probability of selecting a 5 on the second selection is also 4/12 = 1/3.

Since the events are independent, we can multiply the probabilities to find the probability of both events occurring:

P(selecting a 5 on first selection and selecting a 5 on second selection) = P(selecting a 5 on first selection) x P(selecting a 5 on second selection)

= (1/3) x (1/3)

= 1/9

Therefore, the probability that Caleb selects a 5 on the first selection, returns the card to the deck, shuffles the cards, and then draws a 5 on the second selection is 1/9.

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Answer:

All lines are parallel.

Step-by-step explanation:

Get each equation in Slope-Intercept form:

  1. Divide both sides by 3: [tex]y=-\frac{4}{3}x+\frac{7}{3}[/tex]

  2. No change

  3. Subtract 8x and divide by 6 on both sides: [tex]y=-\frac{4}{3}x-\frac{2}{3}[/tex]

Notice:

a. All slopes are -4/3

b. All y-intercepts are different

Answer: 34,650 permutations

For the given function 'g':

domain = (-4, -2) ∪ (1, 3]

range = (-5, 4]

If the function is defined as f(x) = y, then the values of x for which the value of function exists, the set of that values is said to be the domain of the function f.

If the function is defined as f(x) = y, then the set of all possible values of the function that is the set of all possible values of y is said to be the range of the function f.

Here given the graph of 'g'.

From the graph we can see that for -4 < x < -2 and 1 < x [tex]\le[/tex] 3 the function has graph.

So the domain = (-4, -2) ∪ (1, 3]

And it is clear that the value of y lies between -5 < y [tex]\le[/tex] 4.

So the range = (-5, 4].

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The value of expression 14a +7+ 5b+ 2a + 10b will be 16a + 15b + 7

Since Expression is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

We are given the expression as;

14a +7+ 5b+ 2a + 10b

Combine like terms;

14a + 2a + 10b +7+ 5b

16a + 15b + 7

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There are 1100 many ways can be done that is when catering service offers 5 appetizers, 11 main courses, and 4 desserts.

Given that,

A catering service offers 5 appetizers, 11 main courses, and 4 desserts. A customer is to select 4 appetizers, 9 main courses, and 3 desserts for a banquet.

We have to find how many ways can this be done.

We know that,

Number of appetizers offered = 5

Number of appetizers customer is to select = 4

Number of main courses offered = 11

Number of main courses customer is to select = 9

Number of desserts offered = 4

Number of desserts the customer is to select = 3

So,

To determine the number of ways this can be selected,

By using the combination formula that is

[tex]^nC_r = \frac{n!}{r!(n-r)!}[/tex]
[tex]^nC_r = ^5C_4\times ^{11}C_9\times^4C_3[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 = \frac{5!}{4!(5-4)!} \times \frac{11!}{9!(11-9)!}\times \frac{4!}{3!(4-3)!}[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 = \frac{5!}{4!1!} \times \frac{11!}{9!2!}\times \frac{4!}{3!1!}[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 = \frac{5!}{4!} \times \frac{11!}{9!(2)}\times \frac{4!}{3!}[/tex]

[tex]^5C_4\times ^{11}C_9\times^4C_3 =[/tex] 5 × 11 × 5 × 4

[tex]^5C_4\times ^{11}C_9\times^4C_3 =[/tex] 1100

Therefore, There are 1100 many ways this can be done.

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