Find the distance between (-5,6)and (3,2).

Answer:

Step-by-step explanation:

Understanding the problem:

x -----> number of munchkins

y -----> number of yema

Devise a plan:

x + y ≥ 10

3x + 2y ≥ 50

Carry out:

y ≥ -x + 10 ------------(I)

3x + 2y  ≥ 50

       2y ≥ -3x + 50

        y ≥ [tex]\frac{-3}{2}+\frac{50}{2}[/tex]

       [tex]y \geq \frac{-3}{2}x + 25[/tex]

Answer:

Understanding the problem:

x -----> number of munchkins

y -----> number of yema

Devise a plan:

x + y ≥ 10

3x + 2y ≥ 50

Carry out:

y ≥ -x + 10 ------------(I)

Answer:

Perpendicular lines are lines that cross perfectly to create a 90 degree angle! Kinda like a big cross. with a right angle in the center area

Step-by-step explanation:

Answer:

11

Step-by-step explanation:

Answer:

yes they are perpendicular to eachother because when both the lines cross it makes a right angle 90 degrees making it perpendicular

Step-by-step explanation:

Answer:   it is 1.25

hope i helped

Answer:

1.25

Step-by-step explanation:

yeah

Step-by-step explanation:

Answer:25.1

Step-by-step explanation:

Answer:

0.3²+3

=3.27

Step-by-step explanation:

please mark me as brainliest

Answer:

[tex] A_{sector} \approx \: 80.38 \: {ft}^{2} [/tex]

Step-by-step explanation:

[tex] A_{sector} = \frac{ \theta}{360 \degree} \times \pi {r}^{2} \\ \\ A_{sector} = \frac{144 \degree}{360 \degree} \times 3.14 \times {(8)}^{2} \\ \\ A_{sector} = 0.4 \times 3.14 \times {(8)}^{2} \\ \\ A_{sector} = 80.384 \\ \\ A_{sector} \approx \: 80.38 \: {ft}^{2} [/tex]

It is located in quadrant 4 hope this helps

yup if I'm not mistaken it's supposed to be iv

Answer:

90°grados es la respuesta

Answer:

She can put fill 2 “2/5 pound bags” and will have 1/5 pounds of raisins remaining.

Step-by-step explanation:

First we change the 2/5 into common denominators by multiplying by 2 and we go from 2/5–>4/10. Now that we have this we can see how many times 4 goes into 9 which is 2 so we know that she can fill 2 “2/5 pound bags.” But 4/10x2=8/10 and since we have 9/10 pounds of raisins we subtract 8/10 from 9/10 to get a difference of 1/10. So we have 1/10 pounds of raisins remaining and she can fill 2 full bags of “2/5 pound bags.”

Answer:

4x-y+3

Step-by-step explanation:

When we are given two points and asked to find the equation of the line, we must find the slope first. After that, it is the same three steps: substitute, distribute, solve for y. You should now be able to write the equation of a line in: point-slope form, slope-intercept form, or standard form

Answer:

c

Step-by-step explanation:

you would do

m = money overall

(m*1.08) +3000= you would do that twelve times

Step-by-step explanation:

For A

The name of two similar triangles is ABC and CED.

For b

If two pairs of corresponding angles in a pair of triangles are congruent, then the triangles are similar. We know this because if two angle pairs are the same, then the third pair must also be equal. When the three angle pairs are all equal, the three pairs of sides must also be in proportion.

Here

< BAC = < CED ( given)

<ACB = < ECD ( vertically opposite angles)

the answer would be,

[tex]u > \frac{3x}{7} - \frac{9x - 7i}{21} [/tex]

sorry. if wrong.

but hope it helps anyways.

Answer:

To calculate this you just have to calculate a rule of three with both gas tanks, so if the dad´s car holds 12 gallons of gas, and the mom´s car holds 50% more that means 150% of in the rule of three: So the total amount of gallons that the mom´s car tank can hold is 18 gallons.

Answer:

47.065

Step-by-step explanation:

The formula for area of a circle is A = πr^2

Since the diameter is double the radius, divide 3 in half to get 1.5.

Then plug your numbers into the equation and remember to start with exponents.

3.14 x 1.5^2  or  3.14 x (1.5 x 1.5)

Answer:

7.07 cm

Step-by-step explanation:

Area of a circle = πr²

{diameter = 3 cm ; radius = 3/2 = 1.5 cm}

πr²

= 3.14 x (1.5)²

=3.14 x 2.25

= 7.07 cm (approx)

Answer:

(4-9)+2=5

Step-by-step explanation:

hope it's it's right

Answer:

[tex]2\frac{1}{4}[/tex]

Step-by-step explanation:

Question has missing details (See attachment).

Given

[tex]Orange\ Juice = 1\frac{1}{4}quart[/tex]

[tex]Pineapple\ Juice = 2\frac{1}{2}quart[/tex]

[tex]Seltzer = 1\frac{1}{2}quart[/tex]

Required

Determine how much juice than seltzer used.

To do this, we first calculate the total amount of juice

[tex]Juice = Orange + Pineapple[/tex]

[tex]Juice = 1\frac{1}{4} + 2\frac{1}{2}[/tex]

[tex]Juice = \frac{5}{4} + \frac{5}{2}[/tex]

Take LCM

[tex]Juice = \frac{5+10}{4}[/tex]

[tex]Juice = \frac{15}{4}[/tex]

Then subtract the amount of seltzer used.

[tex]Juice - Seltzer = \frac{15}{4}-1\frac{1}{2}[/tex]

[tex]Juice - Seltzer = \frac{15}{4}-\frac{3}{2}[/tex]

Take LCM

[tex]Juice - Seltzer = \frac{15 - 6}{4}[/tex]

[tex]Juice - Seltzer = \frac{9}{4}[/tex]

[tex]Juice - Seltzer = 2\frac{1}{4}[/tex]

The amount of juice used more than seltzer is [tex]2\frac{1}{4}[/tex]

Answer: 3 3/4 quarts

Hope this helps

Answer: No, it is equal.

Step-by-step explanation:

No, small ....... otherwise your question is wrong......

=>4320/1000=4.32

////////////??????????

=>(,)-------(.).......4(.)32/4(,)32

Which is this?

Answer:

3

Step-by-step explanation:

Answer:

[tex]P(x=3) = 0.1318[/tex]

Step-by-step explanation:

The question illustrates a binomial distribution and the given parameters are:

Given

[tex]n = 6[/tex] -- sample size

[tex]p = 0.75[/tex] --- probability of success

[tex]r = 3[/tex] --- half of the participant

Using the binomial probability formula, we have:

[tex]P_x = ^nC_xp^x(1-p)^{n-x}[/tex]

For x = 3, the probability is:

[tex]P(x=3) = ^6C_3*0.75^3 * (1-0.75)^{6-3}[/tex]

[tex]P(x=3) = 20*0.75^3 * 0.25^3[/tex]

[tex]P(x=3) = 0.1318[/tex]

Answer: 12 adult tickets where sold

Step-by-step explanation:

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

Given value:

[tex]\to f_X (x) \ \ xe^{-x} \ , \ x>0[/tex]

For point a:

Moment generating function of X=?

Using formula:

[tex]\to M(t) =E(e^{tx})= \int^{\infty}_{-\infty} \ e^{tx} f(x) \ dx[/tex]

[tex]M(t) = \int^{\infty}_{-\infty} \ e^{tx}xe^{-x} \ dx = \int^{\infty}_{0} \ xe^{(t-1)x} \ dx[/tex]

integrating the values by parts:

[tex]u = x \\\\dv = e^{(t-1)x}\\\\dx =dx \\\\v= \frac{e^{(t-1)x}}{t-1}\\\\M(t) =[\frac{e^{(t-1)x}}{t-1}]^{-\infty}_{0} -\int^{\infty}_{0} \frac{e^{(t-1)x}}{t-1} \ dx\\\\[/tex]  

        [tex]= \frac{1}{t-1} (0) - [\frac{e^{(t-1)x}}{(t-1)^2}]^{\infty}_{0}\\\\=\frac{1}{(t-1)^2}(0-1)\\\\=\frac{1}{(t-1)^2}\\\\[/tex]

Therefore, the moment value generating by the function is [tex]=\frac{1}{(t-1)^2}[/tex]

In point b:

[tex]E(X^n)=?[/tex]

Using formula: [tex]E(X^n)= M^{n}_{X}(0)[/tex]

form point (a):

[tex]\to M_{X}(t)=\frac{1}{(t-1)^2}[/tex]

Differentiating the value with respect of t

[tex]M'_{X}(t)=\frac{-2}{(t-1)^3}[/tex]

when [tex]t=0[/tex]

[tex]M'_{X}(0)=\frac{-2}{(0-1)^3}= \frac{-2}{(-1)^3}= \frac{-2}{-1}=2\\\\M''_{X}(t)=\frac{(-2)(-3)}{(t-1)^4}\\\\M''_{X}(0)=\frac{(-2)(-3)}{(0-1)^4}= \frac{6}{(-1)^4}= \frac{6}{1}=6\\\\M''_{X}(t)=\frac{(-2)(-3)}{(t-1)^4}\\\\M''_{X}(0)=\frac{(-2)(-3)}{(0-1)^4}= \frac{6}{(-1)^4}= \frac{6}{1}=6\\\\M'''_{X}(t)=\frac{(-2)(-3)(-4)}{(t-1)^5}\\\\M''_{X}(0)=\frac{(-2)(-3)(-4)}{(0-1)^5}= \frac{24}{(-1)^5}= \frac{24}{-1}=-24\\\\\therefore \\\\M^{K}_{X} (t)=\frac{(-2)(-3)(-4).....(k+1)}{(t-1)^{k+2}}\\\\[/tex]

[tex]M^{K}_{X} (0)=\frac{(-2)(-3)(-4).....(k+1)}{(-1)^{k+2}}\\\\\therefore\\\\E(X^n) = \frac{(-2)(-3)(-4).....(n+1)}{(-1)^{n+2}}\\\\[/tex]

Answer: The first one

Step-by-step explanation:

-6c + 11d = 20

-6c + 11d = 20

They're the same equation meaning they'll be on the same line. They would have infinite solutions.

Answer: The first one

Step-by-step explanation:

-6c + 11d = 20

-6c + 11d = 20