Does coordinate s or coordinate t represent a greater number?

Answer:

  (-3, 4) is a solution

Step-by-step explanation:

The point (-3, 4) is inside the shaded area of the graph, so is a solution.

You can check in the inequality

  y > -2x -3

  4 > -2(-3) -3 . . . . substitute for x and y

  4 > 3 . . . . . . . true; the given point is a solution

Step-by-step explanation:

multiple 6 by 9 then 2 by 5 then subtract them

Answer:

44

Step-by-step explanation:

(6*9) - (2*5)

54 - 10

44

Answer:

The height is about 5 inches.

Step-by-step explanation:

The volume for a cone is [tex]\frac{1}{3}[/tex] × π × r² × h

The radius of the cone is 1.5

12= [tex]\frac{1}{3}[/tex] × π × 1.5² × h

12= [tex]\frac{1}{3}[/tex] × π × 2.25 × h

12=0.75×π×h

Divide both sides by 0.75

16=π×h

Divide both sides by π

5≈h

The height is about 5 inches.

Answer:

30 mph

Step-by-step explanation:

Distance travelled=300 miles

Time travelled=10hours

At a constant rate,k

Let distance travelled=d

Time travelled=t

Then,

d=kt

300=k*10

300=10k

k=300/10

=30

k=30mph

30 miles per hour

30 MPH                                                                                       ............................................................................................................

Answer:

[tex] m_{fresh}= 1000 \frac{Kg}{m^3} * 2.5x10^{-4} m^3 = 0.25 Kg[/tex]

And we can do a similar procedure for the sea water:

[tex] m_{sea}= \rho_{sea} V_{sea} [/tex]

And after convert the volume to m^3 we got:

[tex] m_{sea}= 1030 \frac{Kg}{m^3} * 1x10^{-4} m^3 = 0.103 Kg[/tex]

And then the density for the mixture would be given by:

[tex] \rho_{mixture}= \frac{m_{fresh} +m_{sea}}{v_{fresh} +v_{sea}}[/tex]

And replacing we got:

[tex] \rho_{mixt}= \frac{0.25 +0.103 Kg}{2.5x10^{-4} m^3 +1x10^{-4} m^3} = 1008.571 \frac{Kg}{m^3}[/tex]

Step-by-step explanation:

For this case we can begin calculating the mass for each type of water:

[tex] m_{fresh}= \rho_{fresh} V_{fresh} [/tex]

And after convert the volume to m^3 we got:

[tex] m_{fresh}= 1000 \frac{Kg}{m^3} * 2.5x10^{-4} m^3 = 0.25 Kg[/tex]

And we can do a similar procedure for the sea water:

[tex] m_{sea}= \rho_{sea} V_{sea} [/tex]

And after convert the volume to m^3 we got:

[tex] m_{sea}= 1030 \frac{Kg}{m^3} * 1x10^{-4} m^3 = 0.103 Kg[/tex]

And then the density for the mixture would be given by:

[tex] \rho_{mixture}= \frac{m_{fresh} +m_{sea}}{v_{fresh} +v_{sea}}[/tex]

And replacing we got:

[tex] \rho_{mixt}= \frac{0.25 +0.103 Kg}{2.5x10^{-4} m^3 +1x10^{-4} m^3} = 1008.571 \frac{Kg}{m^3}[/tex]

Answer:

The perimeter is

Step-by-step explanation:

perimeter is the whole distance you will go around the shape

Perimeter= 19 +3+(19-5)+(8-3)+5+8

= 19+3+14+5+5+8

= 54

For area, cut the triangle into small and big rectangle

Area = 19 * 3+ (8-3) * 5

= 57 + 25

= 82

Answer:

Step-by-step explanation:

A fluctuating electric current II may be considered a uniformly distributed random variable over the interval (9, 11)

[tex]p_1=\{^{\frac{1}{2}:9\leq i\leq 11}_{0:otherwise[/tex]

Now define

[tex]p = 2I^2[/tex]

[tex]\Rightarrow I^2=(\frac{p}{2} )\\\\\Rightarrow I=(\frac{p}{2} )^{\frac{1}{2} }\\\\\Rightarrow h^{-1}(p)=(\frac{p}{2} )^{\frac{1}{2}}[/tex]

[tex]\frac{dh^{-1}}{dp} =\frac{d[h^{-1}(p)]}{dp} \\\\=\frac{d(p/2)^{\frac{1}{2} }}{dp}[/tex]

[tex]=\frac{1}{2} \times \frac{1}{2} (\frac{p}{2} )^{{\frac{1}{2}-1} }\\\\=\frac{1}{4}(\frac{p}{2} )^{{\frac{1}{2}-1} }\\\\=\frac{1}{2}(\frac{2}{p} )^{{\frac{1}{2}} }[/tex]

using the transformation method, we get

[tex]f_p(p)=f_1(h^{-1}(p))|\frac{d[h^{-1}(p)]}{dp} |\\\\=\frac{1}{2} \times \frac{1}{4} (\frac{2}{p} )^{\frac{1}{2} }\\\\=\frac{1}{8} (\frac{2}{p} )^{\frac{1}{2} }[/tex]

[tex]f_p(p)=\{^{\frac{1}{8} (\frac{2}{p} )^{\frac{1}{2} },162\leqp\leq 242} }_{0,otherwise}[/tex]

Answer:

Step-by-step explanation:

image attached (representing first perpetuity on number line)

Present value is 7.21

[tex]7.21=\frac{1}{1-u^2} \\\\1-\frac{1}{7.21} =u^2\\\\\frac{6.21}{7.21} =(1+i)^{-2}\\\\(1+i)^2=\frac{7.21}{6.21} \\\\(i+1)=\sqrt{\frac{7.21}{6.21} }\\\\ i=\sqrt{\frac{7.21}{6.21} } -1\\\\=0.77511297[/tex]

image attached (representing second perpetuity on number line)

we have ,

[tex]7.21=\frac{Ru}{1-u^3}[/tex]

Here,

[tex]V=\frac{1}{1+i}[/tex]i

i = 0.077511297 + 0.01

[tex]\therefore V =\frac{1}{1.087511295} =(1.087511297)^-^1\\\\7.21=\frac{R(1.087511297)^-^1}{1-(1.087511297)^-^3} \\\\7.21=4.132664645R\\\\R=\frac{7.21}{4.132664645} \\\\R= 1.7446370\approx1.74[/tex]

Therefore, value of R is 1.74

Answer:

The percentage of the students who completed the poll preferred rock and roll music.

P(RR) = 0.1423 = 14.23 %

Step-by-step explanation:

Explanation:-

Given total number of students n(S) = 1960

Given the Students at a high school were polled to determine the type of music they preferred.

Rap 916

Alternative 46

Rock and Roll 279

Country 183

Jazz 32

Other 89

Let ' RR' be the event of Rock and Roll preferred music

given Rock and Roll = 279

n( RR) =  279

The percentage of the students who completed the poll preferred rock and roll music.

[tex]P(RR) = \frac{n(RR)}{n(s)} = \frac{279}{1960}[/tex]

P(RR) = 0.1423 = 14.23 %

Answer:

x <= 48

Step-by-step explanation:

Subtract 3 from both sides

x/12 <= 4

Multiply by 12

x <= 48

Answer:

Mega Gym charges a $384 registration fee and $2 each time the gym is used. Super Gym charges a fee of $6 every time the gym is used. What number of times, x, will Super Gym need to be used to exceed the cost of Mega Gym?

Step-by-step explanation:

Given: the inequality is [tex]384+2x<6x[/tex]

To find: the correct option

Solution:

Let x denotes number of times gym is used.

As Mega Gym charges a $384 registration fee and $2 each time the gym is used,

Total amount charged by Mega Gym = [tex]\$(384+2x)[/tex]

As Super Gym charges a fee of $6 every time the gym is used,

Total amount charged by Super Gym = [tex]\$\,6x[/tex]

In order to find number of times, x Super Gym is used such that cost of Super Gym exceeds the cost of Mega Gym,

Solve the inequality:

cost of Super Gym > cost of Mega Gym

[tex]6x>384+2x\\384+2x<6x[/tex]

So, the correct option is '' Mega Gym charges a $384 registration fee and $2 each time the gym is used. Super Gym charges a fee of $6 every time the gym is used. What number of times, x, will Super Gym need to be used to exceed the cost of Mega Gym? ''

Answer:

260 stickers

Step-by-step explanation:

Let Gareth's stickers be x.

Hence Cheryl sticker is 160+x;

If Cheryl gave 185 stickers

to Gareth, it means:

Cheryl has at the moment;

160 + x - 185 = x - 25

At this time when Gareth receives 185 he now has:

x+ 185

Also when he receives x +185, he has 3 times Cherry's meaning:

x+185 =3(x-25)

x + 185 = 3x -75

185 + 75 = 3x-2x

260= x

x = 260.

Hence Gareth has 260 stickers

Answer:

17.8 in x 21.8 in

Step-by-step explanation:

Given w=width and l=length

w*l=390

l=w+4, therefore w*(w+4)=390

w^2+4w=390

w^2+4w-390=0

Quadratic equation, solve as such

w=-21.8 or 17.8

Solution can't be negative so w=17.8 in

l=w+4 so l=21.8

Answer:

C

Step-by-step explanation:

You can plug in each combination to see what would work

C is the only combination that satisfies all the constraints: it earns him more than $800 and is less than 120 plates.

The combination of 40 plates of garlic shrimp was sold, and 80 plates of spicy shrimp were sold can Pedro sell to meet his goal.

Given that,

Pedro owns a shrimp truck near the beach.

He sells garlic shrimp for $8 a plate and spicy shrimp for $6 a plate.

Each day Pedro stocks enough shrimp to sell at most 120 plates total, but he would like to earn at least $800.

We have to determine,

Which combination of garlic shrimp plates and spicy shrimp plates can Pedro sell to meet his goal?

According to the question,

Let the x plates of garlic shrimp sold,

And y plates of spicy shrimp sold.

Each day Pedro stocks enough shrimp to sell at most 120 plates,

Then,

Plates of garlic shrimp + Plates of spicy shrimp = Total number of shrimp sell each day.

[tex]\rm x + y =120[/tex]

And He sells garlic shrimp for $8 a plate and spicy shrimp for $6 a plate.

He would like to earn at least $800.

Then,

Cost of garlic shrimp per plate + Cost of spicy shrimp per plate = Total earning,

[tex]\rm 8x + 6y = 800[/tex]

On solving both the equation,

[tex]\rm x+y = 120\\\\8x + 6y = 800[/tex]

From equation 1,

[tex]\rm y= 120-x[/tex]

Substitute the value of x in equation 2,

[tex]\rm 8x +6y = 800\\\\8(120-y) + 6y = 800\\\\960 - 8y + 6y = 800\\\\-2y = 800-960\\\\-2y = -160\\\\y = \dfrac{-160}{-2}\\\\y = 80[/tex]

Substitute the value of y in equation 1,

[tex]\rm x + y =120\\\\x +80=120\\\\x = 120-80\\\\x =40[/tex]

Hence, The combination of 40 plates of garlic shrimp was sold, and 80 plates of spicy shrimp were sold can Pedro sell to meet his goal.

For more details refer to the link given below.

https://brainly.com/question/475594

Answer:

a. 65  seats

b. $422.50

Step-by-step explanation:

We have the following two functions:

8 * x, {0 <= x <= 50}

x * (8 - 0.1 * (x - 50)), {x> 50}, solving we have:

-0.1 * x ^ 2 + 13 * x, {x> 50}

Now we derive both functions and we are left with:

8, {0 <= x <= 50}

-0.2 * x + 13 {x> 50}

we cannot equal to 0 the first function that is equal to 0, because it would be inconsistent, therefore we equal the second function to 0:

-0.2 * x + 13 = 0

0.2 * x = - 13

x = -13 / -0.2

x = 65

Now, test for increasing and decreasing on the intervals (0.65) and (65, infinity)

p '(60) = -0.2 * (60) + 13 = 1

since this value is positive the profit is increasing on (0.65)

p '(70) = -0.2 * (70) + 13 = -1

becuase this value is negative the profit is decreasing on (65, infinity)

Therefore 65 seats are needed to maximize profit

The maximum value would be:

P (65) = 0.1 * (65 ^ 2) + 13 * 65 = 422.5

That is, the maximum value is $ 422.50

Answer:

0.0908 [tex]m^{2}[/tex] (to 3 S.F.)

Step-by-step explanation:

Area = π[tex]r^{2}[/tex]

π * [tex]17^{2}[/tex] = 907.92

= 908 [tex]cm^{2}[/tex]

=0.0908 [tex]m^{2}[/tex]

Answer:

1

Step-by-step explanation:

x^2−2x=3

Take the coefficient of x

-2

Divide by 2

-2/2 =-1

Square it

(-1)^2 = 1

Add this to each side

Complete Question

Calculating conditional probability

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom.

Here are the results:

Bride :29

Groom :30

BOTH : 20

Given that a randomly selected guest is a friend of the groom, find the probability they are a friend of the bride.

P (bride | groom)​

Answer:

The probability is [tex]P(B|G) = \frac{2}{3}[/tex]

Step-by-step explanation:

The sample size is [tex]n = 80[/tex]

The friend of the groom are [tex]G = 30[/tex]

 The friend of the groom are [tex]B = 29[/tex]

 The friend of both bride and groom are [tex]Z = 20[/tex]

The probability that a guest is a friend of the bride is mathematically represented as

      [tex]P(B) = \frac{29}{80}[/tex]

The probability that a guest is a friend of the groom is mathematically represented as

       [tex]P(G) = \frac{30}{80}[/tex]

The probability that a guest is both a friend of the bride and a friend of the groom is mathematically represented as

       [tex]P(B \ n \ G) = \frac{20}{80}[/tex]

Now

    [tex]P(B|G)[/tex] is mathematically represented as

     [tex]P(B|G) = \frac{P(B \ n \ G)}{P(G)}[/tex]

     Substituting values

       [tex]P(B|G) = \frac{\frac{20}{80} }{\frac{30}{80} }[/tex]

      [tex]P(B|G) = \frac{2}{3}[/tex]

Answer:

the answer is 3/5

Step-by-step explanation:

on Khan

Answer:

The number of weeks it will take for the  beetle population to reach 236 is 28.75.

Step-by-step explanation:

If a quantity starts at size P₀ and grows by d every time period, then the

quantity after n time periods can be determined using explicit form:

[tex]P_{n} = P_{0} + d \cdot n[/tex]

Here,

d = the common difference, i.e. the amount  that the population changes each time n is increased by 1.

In this case it is provided that the original population of beetle was:

P₀ = 6; (week 0)

And the population after 8 weeks was,

P₈ = 86

Compute the value of d as follows:

[tex]P_{8} = P_{0} + d \cdot 8\\86=6+8d\\86-6=8d\\80=8d\\d=10[/tex]

Thus, the explicit formula for the beetle population after n weeks is:

[tex]P_{n}=P_{0}+8n[/tex]

Compute the number of weeks it will take for the  beetle population to reach 236 as follows:

[tex]P_{n}=P_{0}+8n\\\\236=6+8n\\\\8n=236-6\\\\8n=230\\\\n=28.75[/tex]

Thus, the number of weeks it will take for the  beetle population to reach 236 is 28.75.

Answer:

  C.  y ≤ 1

Step-by-step explanation:

The maximum value of the function is 1. So, the range is all values of y less than or equal to that.

  y ≤ 1

Answer:

(0,2)

Step-by-step explanation:

2:4 means one part is 2/(2+4)=1/3 of AB and the other part is 2/3 of AB

Add 1/3 of the distance from -2 to 4. (1/3)(4+2)=2. -2+2=0 The x coordinate is 0

Subtract 1/3 of the distance from 6 to -6, (1/3)6+6)=4 6-4=2 The y coordinate is 2

The point is (0,2)

Answer:

1/4

Step-by-step explanation:

Flip a fair two sided coin 4 times, the probability the first or last flip is a tail is

P = (1/2) x 1 x 1 x (1/2) = 1/4

(The probability of getting tail in first flip = 1/2, in the 2nd and 3rd flip, tail and head are both accepted, the probability of getting tail in last flip = 1/2)

Hope this helps!

Answer:

Step-by-step explanation:

In a survey of 1,000 adults living in a big city, 540 participants said that they prefer to get news from the Internet, 330 prefer to watch news on TV, and 130 are rarely interested in the current news. We want to test if the proportion of people getting the news from the Internet is more than 50%. By generating the randomization distribution, we find that the p-value is 0.0057. Choose the correct statement interpreting the p-value.

A.If the proportion of people getting the news from the Internet is not equal to 0.5 then there is a 0.0057 chance of seeing the sample proportion as extreme as the survey results.

B. If the proportion of people getting the news from the Internet is not equal to 0.54 then there is a 0.0057 chance of seeing the sample proportion as extreme as the survey results.

C. If the proportion of people getting the news from the Internet is equal to 0.54 then there is a 0.0057 chance of seeing the sample proportion less extreme compared to the survey results. р

D. If the proportion of people getting the news from the Internet is equal to 0.54 then there is a 0.0057 chance of seeing the sample proportion as extreme as the survey results.

E. If the proportion of people getting the news from the Internet is equal to 0.5 then there is a 0.0057 chance of seeing the sample proportion as extreme as the survey results.

The correct interpretation of P value will be:

if the proportion of people getting the news from internet is equal to 0.5 then there is a 0.0057 chance of seeing the sample proportion as extreme as survey results.

Answer:

16:0

Step-by-step explanation:

Answer:

[tex]x=\frac{5}{7}[/tex]

Step-by-step explanation:

[tex]3x - 2 = 3 - 4x[/tex]

Add [tex]2[/tex] and [tex]4x[/tex] on both sides of the equation.

[tex]3x - 2 +2+4x= 3 - 4x+2+4x[/tex]

[tex]3x+4x=-4x+5+4x[/tex]

[tex]7x=5[/tex]

Divide [tex]7[/tex] on both sides of the equation.

[tex]\frac{7x}{7}=\frac{5}{7}[/tex]

[tex]x=\frac{5}{7}[/tex]

Answer:

Dear User,

Answer to your query is provided below

(i) Total Loss = Rs.15

(ii) Loss percent = 5%

Step-by-step explanation:

Eggs purchased = 5x12 = 60

Total Cost = 60x5 = Rs 300

Eggs Broken = 10

Eggs Broken cost = 10x5= Rs. 50

Eggs sold = 60-10 = 50

Egg Sale cost = 50x5.70 = Rs 285

(i) Total Loss = C.p. - S.p. = 300 - 285 = 15

(ii) Loss Percent = (Loss/CP)x100 = (15/300)x100 = 5%

Answer:

0.9

Step-by-step explanation:

10% is equal to 0.1

The probability of having defective parts in a pile of parts is 0.1

Before the process is stopped, 1 part has to be defective.

In a pile of 9 parts, the probability that a part is defective 0.1 of 9, which is = 0.9 hence, approximately one (1) part will be defective in a pile of 9 parts and the process will be stopped.

Since there was no defective part among the first 6 parts, P(d) was 0

That is, probability of a defective part was zero.

Answer:

= ( $72.756, $110.804)

Therefore, the 90% confidence interval (a,b) = ( $72.756, $110.804)

Critical value at 90% confidence = 1.645

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = $91.78

Standard deviation r = $23.13

Number of samples n = 4

Confidence interval = 90%

Using the z table;

z(α=0.05) = 1.645

Critical value at 90% confidence = 1.645

Substituting the values we have;

$91.78+/-1.645($23.13/√4)

$91.78+/-1.645($11.565)

$91.78+/-$19.024425

$91.78+/-$19.024

= ( $72.756, $110.804)

Therefore, the 90% confidence interval (a,b) = ( $72.756, $110.804)

Answer:

3/5

Step-by-step explanation:

because there are more red than blue and the fraction is 3/5 and the probability to pick a red worm is a lot higher than the blue. well there are 4 red worms and 1 blue so it would be 3 red worms out of 5 in total. this is more than 1 blue over 5. 3/5 is more than 1/5

hope this helped

Answer: 3/5

Step-by-step explanation:

Since 4 red gummies you have four out of 5 chance of getting red gummies. Without replacement there are now 4 gummies left and 3 red gummies. There for 3 out of 4 chance of getting another red gummy. Since at same time multiply. 4/5*3/4 = 12/20

Which can be simplified to 3/5

Answer:

0.9544 = 95.44% probability that the researcher observes an average weight of the 100 people to be between 150 and 170.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

[tex]\mu = 160, \sigma = 50, n = 100, s = \frac{50}{\sqrt{100}} = 5[/tex]

Find the probability that the researcher observes an average weight of the 100 people to be between 150 and 170.

This is the pvalue of Z when X = 170 subtracted by the pvalue of Z when X = 150. So

X = 170

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{170 - 160}{5}[/tex]

[tex]Z = 2[/tex]

[tex]Z = 2[/tex] has a pvalue of 0.9772

X = 150

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{150 - 160}{5}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the researcher observes an average weight of the 100 people to be between 150 and 170.