consider the time taken to completion time (in months) for the construction of a particular model of homes: 4.1 3.2 2.8 2.6 3.7 3.1 9.4 2.5 3.5 3.8 Find the mean, median mode, first quartile and third quartile. Find the outlier?​

Answers

Answer 1

Sum

Mean = (4.1 + 3.2 + 2.8 + 2.6 + 3.7 + 3.1 + 9.4 + 2.5 + 3.5 + 3.8) / 10

Mean = 36.7 / 10

Mean = 3.67

To find the median, we need to put the values in order:

2.5, 2.6, 2.8, 3.1, 3.2, 3.5, 3.7, 3.8, 4.1, 9.4

The middle number is the median, which is 3.35 in this case (3.2+3.5)/2.

To find the mode, we look for the value that appears most often. In this case, there is no mode as no value appears more than once.

To find the first quartile (Q1), we need to find the value that separates the bottom 25% of the data from the top 75%. We can do this by finding the median of the lower half of the data:

2.5, 2.6, 2.8, 3.1, 3.2

The median of this lower half is 2.8, so Q1 = 2.8.

To find the third quartile (Q3), we need to find the value that separates the bottom 75% of the data from the top 25%. We can do this by finding the median of the upper half of the data:

3.7, 3.8, 4.1, 9.4

The median of this upper half is 3.95, so Q3 = 3.95.

To find the outlier, we can use the rule that any value more than 1.5 times the interquartile range (IQR) away from the nearest quartile is considered an outlier. The IQR is the difference between Q3 and Q1:

IQR = Q3 - Q1

IQR = 3.95 - 2.8

IQR = 1.15

1.5 times the IQR is 1.5 * 1.15 = 1.725.

The only value that is more than 1.725 away from either Q1 or Q3 is 9.4. Therefore, 9.4 is the outlier in this data set.

Answer 2

Answer:

Step-by-step explanation:

Mean is the average of the data vales : 38.7 (sum of all values) divided by 10 (the number of values).  Mean = 38.7/10 = 3.87

Median is the "middle" number" = put the date in order and find the middle value:

2.5, 2.6, 2.8, 3.1, 3.2, 3.5, 3.7, 3.8, 4.1, 9.4, since there is no middle data value, find the average of the 2 in the middle.

3.2 + 3.5/2 = 6.7 ÷ 2 = 3.35 - median

All values appear once so there is no mode.

First quartile is the middle of the lower set of data = 2.8

Third quartile is the middle of the upper set = 3.8

The outlier is 9.4.

How to calculate the outlier:

First you need the IQR which is the diffence of Q3 - Q1,

so the IQR is 3.8- 2.8 = 1

Outliers are the quartile + or - (1.5)(IQR)

Q1 -(1.5)(1) = 2.8 - 1.5 = 1.3

Q3 - (1.5)(1)= 3.8 + 1.5 =4.5

So anything below 1.3 or above 4.5 is an outlier.

There is one 9.4


Related Questions

Find the degree of the monomial. 3a^8b^7

Answers

The degree is 8 because it is the biggest exponent

Consider the line y = -8x + 7.
Find the equation of the line that is perpendicular to this line and passes through the point (-5, 3).
Find the equation of the line that is parallel to this line and passes through the point (-5, 3).

Answers

The equation of the line that is parallel to the line that passes through the point (7, 6) is y = 8x - 50.

What is a line?

A line is an object in geometry that is indefinitely long and has neither breadth nor depth nor curvature.

Since lines can exist embedded in two, three, or higher dimensions environments, they are one-dimensional objects.

The term "line" can also be used to describe a line segment in daily life that contains two locations that serve as its ends.

So, the lines with the same slope but a different y-intercept are said to be parallel.

Therefore, we must use the same slope to plug in the point (7, 6) and solve for the y-intercept.

We thus have:

y = 8x + b

6 = 8(7) + b

6 = 56 + b

b + 56 = 6

b + 56 - 56 = 6 - 56

b = -50

The equation is: y = 8x - 50

Therefore, the equation of the line that is parallel to the line that passes through the point (7, 6) is y = 8x - 50.

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Correct question:

Consider the line y = 8x - 4. Find the equation of the line that is parallel to this line and passes through the point (7, 6).

I need help i don't know how to do this please

Answers

The size of matrix cM is given as follows:

9 x 10.

What happens when a matrix is multiplied by a constant?

When a matrix is multiplied by a constant, we have that every element in the matrix is multiplied by the constant. Hence, the dimension of the matrix remains constant.

The parameters for this problem are given as follows:

Constant c.Matrix M of dimensions 9 x 10.

Hence the size of matrix cM is given as follows:

9 x 10.

(same size as the original matrix, as we simplify multiply each element in the matrix by the constant, hence the dimensions remain the same).

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A swimming pool holds 450, 000 L
of water and has two drainage
pipes.
Pipe A, by itself, can drain the pool
in 150 minutes. Pipe B, by itself, can
drain the pool in 225 minutes.
If you turned on both pipes at the
same time, how many minutes
would it take to drain the pool?

Answers

Using a linear equation, the minutes it would take both pipes to drain the swimming pool that holds 450,000 liters is 90 minutes.

What is a linear equation?

A linear equation is an equation of a straight line written in the form of y = mx +b, where m is the slope.

The quantity of water the swimming pool holds = 450,000 liters

The drainage time of Pipe A working alone = 150 minutes

Drainage rate of Pipe A = 3,000 liters per minute (450,000 ÷ 150)

The drainage time of Pipe B working alone = 225 minutes

Drainage rate of Pipe B = 2,000 liters per minute (450,000 ÷ 225)

The drainage rate of the combined pipes = 5,000 liters per minute (3,000 + 2,000)

Let the number of minutes for both pipes to drain the pool = x

Therefore, the linear equation is 5,000x = 450,000

x = 90 minutes (450,000 ÷ 5,000)

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Which number is the greatest? 20 -100 -45 50

Answers

50 is the greatest number.

If GI and JL are parellel lines and m

Answers

The measure of angle IHE is 23°.

Since DF and GI are parallel, we know that angle HJF is congruent to angle GHJ. Therefore, we have:

mHJF = mGHJ = 134°

We can now use this information to find the measure of angle IHE. To do this, we need to use the fact that the sum of the angles in a straight line is 180°. Since H, J, F, and I lie on a straight line, we have:

mHJF + mFJI + mIHE = 180°

Substituting the values we know, we get:

134° + mFJI + mIHE = 180°

Simplifying the equation, we get:

mFJI + mIHE = 46°

We still need to find the measure of angle FJI. To do this, we can use the fact that the angles in a triangle add up to 180°. Triangle GHJ is a straight line, so its angles add up to 180°. Therefore, we have:

mGHJ + mHJF + mFJI = 180°

Substituting the values we know, we get:

134° + mFJI + mFJI = 180°

Simplifying the equation, we get:

2mFJI = 46°

Dividing both sides by 2, we get:

mFJI = 23°

Finally, we can substitute this value back into our earlier equation to find the measure of angle IHE:

mFJI + mIHE = 46°

23° + mIHE = 46°

Subtracting 23° from both sides, we get:

mIHE = 23°

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Complete Question:

If DF and GI are parallel lines and mGHJ = 134°, what is mIHE?

The architect stands 6 feet from a climbing frame looking up at the top of the frame at an angle of 63.43

Answers

The value of the height of the entire climbing frame is 11.99 feet

How to determine the value

To determine the value, we need to know the different trigonometric identities.

These identities are;

tangentcotangentcosecantsecantcosinesine

From the information given, we have that;

In the triangle, the parameters are;

Hypotenuse is the distance between the architect and frame

The angle is 63.43

Adjacent is 6 feet

Using the tangent identity, we have;

tan 63.43 = h/6

cross multiply, we get;

h = tan (63. 43) × 6

Find the tangent value and substitute, we have;

h = 1. 99 × 6

Multiply the values, we have;

h = 11. 99 feet

Then, the height of the entire climbing frame is 11. 99 feet

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Complete question:

'The architect stands 6 feet from climbing frame, looking up at the top of the frame at an angle of 63.43" It is 5 and half feet from ground to the architect's eyes: The vertical distance from eye level to the top of the climbing frame is feet: The height of the entire climbing frame is feet:'

6 yards 2 feet 5 inches equals

Answers

Answer:

245 inches

Step-by-step explanation:

Yards->Inches

1 yard = 36 inches

Therefore, 6 yards = 36 x 6 = 216 inches

Feet->Inches

1 feet = 12 inches

Therefore, 2 feet = 2 x 12 = 24 inches

Adding all inches,

=> 216 + 24 + 5

=> 245 inches

A population of rabbits is increasing at a rate of 1.5% per month. If there are 60 rabbits today, how many will there be after 10 months? Round to the nearest whole.

Answers

If population of rabbits is increasing at a rate of 1.5% per month, after 10 months, there will be approximately 71 rabbits in the population.

To solve this problem, we need to use the formula for exponential growth:

A = P(1 + r)ᵗ

where A is the final amount, P is the initial amount, r is the growth rate as a decimal, and t is the time period. In this case, we have P = 60, r = 0.015 (1.5% expressed as a decimal), and t = 10.

Plugging these values into the formula, we get:

A = 60(1 + 0.015)¹⁰

A ≈ 71

t's important to round to the nearest whole, so we can't be exact, but we know the answer will be somewhere between 70 and 72 rabbits.

Exponential growth is a model that assumes continuous growth over time, which may not be entirely accurate in real-world scenarios.

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PLEASE HELP ME QUICK!!!

Answers

Answer:

Option D.   [tex]g(x)=5(0.8)^{x}+2[/tex]

Step-by-step explanation:

Main concepts

Concept 1: identifying horizontal asymptote

Concept 2: assuring decreasing exponential function

Concept 1. identifying horizontal asymptote

Any exponential function of the form [tex]y=a*b^x[/tex] has a horizontal asymptote on the x-axis.  A constant (positive or negative) added to the end of the exponential expression will shift the graph of the exponential function up (if positive) or down (if negative) the number of units equal to the magnitude of the number.  Since the original function f(x) has a "+2" at the end, it has been shifted up 2 units.  Thus, we can eliminate answers A and C from feasible answers since they each shift the exponential function up 3 units, not 2.

Concept 2. assuring decreasing exponential function

Exponential functions of the form [tex]y=a*b^x[/tex] increase or decrease based on the value of "b".

If "b" is between 0 and 1 (a "small" number), the function will decrease.If "b" is larger than 1 (a "big" number), the function will increase.

Observe that the graph of the function f(x) is decreasing, and the value of b=0.5.

To ensure that g(x) also decreases, the b-value must be between 0 and 1, which eliminates option B.

Option D is the correct answer because the value of "b" is between 0 and 1 (making the graph of the function a decreasing exponential), and the number added at the end is "+2", causing the horizontal asymptote to be at a height of positive 2.

A map shows the vertices of a campsite are (25,10), (25,-5), (-5,-5), and (-5,10). The vertices of your tent are (0,-3), (0,6), (10,6), and (10,-3). The coordinates are measured in feet. What percent of the campsite is not covered by your tent?

Answers

The percent of the area that is not covered is 80 percent

How to calculate the area that is not covered

In mathematics area is defined as the absolute or total space that an object or shape occupies. It is usually measured using centimeters, cm ² square or the use of meter square m ².

area of tent

= (10 - 0) * (6 - (-3))

= 90

The area of the campsite would be:

(25 - (-5) x (10 - (-5))

= 450

Then the area would be 450 - 90

= 360

the percentage that is not covered by tent = 360 / 450 x 100

= 80 percent

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I understand the lower and upper class limits but there are only one number but I don't know what to do

Answers

The class mark of the modal class is: 25

How to solve

From the given histogram, the following Frequency Distribution is obtained:

Class Interval Mid point Frequency

625-675 650 3

676-726 701 5

727 - 777 752 7

778 - 828 803 8

829 - 879 854 6

880 - 930 905 2

931 - 981 956 0

982 - 1032 1007 1

b. To find the lower class limit of the first class:

First class: 625

c. The upper limit of the first class is:

First class: 676

The class mark of the modal class is:

The modal class is: 803

The class mark is upper limit + lower limit/2

Thus, 828-778/2

=> 50/2

The class mark of the modal class is: 25

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if my circular garden requires 2 cups of water per 10 square feet, how many cups of water do i need when the radius is 3 feet​

Answers

6 cups of water, since the area is 3.14r^2 which is 28.26 feet. And then 2 cups per each 10 feet so 4 and then if we round for the remaining 8.26 feet, 6 cups total.

Find the probability that
event A or B takes place.

Answers

The probability that event A or B takes place is P ( A ∪ B ) = 6/17

Given data ,

Let the probability that event A or B takes place is P ( A ∪ B )

Now , the probability of A is P ( A ) = 2/17

And , the probability of B is P ( B ) = 4/17

where P ( A ∩ B ) = 0

On simplifying the equation , we get

P ( A ∪ B ) = P ( A ) + P ( B ) - P ( A ∩ B )

So , P ( A ∪ B ) = 2/17 + 4/17

P ( A ∪ B ) = 6/17

Hence , the probability is 6/17

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.If $10,000 is deposited in an account earning 5 ¾ % interest compounded monthly. How much money will be in the account in 5 years.

Answers

The total amount in the acount in 5 years is approximately $13,321.76.

What is the accrued amount in the account in 5 years?

The formula accrued amount in a compounded interest is expressed as;

[tex]A = P( 1 + \frac{r}{n} )^{n*t}[/tex]

Where A is accrued amount, P is principal, r is interest rate and t is time.

Given that:

Principal P = $10,000Compounded monthly n = 12Time t = 5 yearsInterest rate r = 5 3/4% = 5.75%Accrued amount A = ?

First, convert R as a percent to r as a decimal

r = R/100

r = 5.75/100

r = 0.0575

Plug the given values into the above formula and solve for A.

[tex]A = P( 1 + \frac{r}{n} )^{n*t}\\\\A = 10000( 1 + \frac{0.0575}{12} )^{(12*5)}\\[/tex]

A = $13,321.76

Therefore, the accrued amount is $13,321.76.

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Plsss help meeee quick

Answers

Answer:

B

Step-by-step explanation:

Lateral surface contains B,C and D (because A and E are bases)

A (lateral surface area) = 70 + 70 + 56 = 196 cm^2

3.4 The rectangular box has the length of 8x² and the breadth of 6x² - 4x 3.4.1 What is the area of the box? 3.4.2 Factorise the area of the box? 3.4.3 If x = 2 what will be the value of the length and the breadth?​

Answers

Answer:

3.4.1) (8x^2)(6x^2 - 4x) = 48x^4 - 32x^2

3.4.2) 48x^4 - 32x^2 = (16x^2)(3x^2 - 2)

3.4.3) Length = 16(2^2) = 16(4) = 64

Width = 3(2^2) - 2 = 3(4) - 2

= 12 - 2 = 10

Area = 64(10) = 640

Johnny's cafe serves desserts. One serving of ice cream and two servings of blueberry pie provides 790 calories. Three servings of ice cream and two serving of blueberry pie provides 1290 calories

Answers

The caloric content for ice cream C is 250 calories while the caloric content for ice cream B is 270 calories.

How to determine the caloric content

To determine the caloric content, we will assign algebraic notations to each of the dessert types.

1 Icecream + 2 Blueberry pie =   790 calories

3 icecream + 2 Blueberry pie = 1290 calories

Now the first equation will be subtracted from the second equation as follows:

2 icecream = 500 calories

So, 1 ice cream is 250 calories.

Also, since, 1 icecream serving equals 250 calories, 2 Blueberry pies = 790 - 250 = 540 calories, and 1 Blueberry pie equals 270 calories.

Complete question:

Johnny's cafe serves desserts. One serving of ice cream and two servings of blueberry pie provides 790 calories. Three servings of ice cream and two servings of blueberry pie provides 1290 calories. Find the caloric content of each item.

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I need help please can somebody help me please

Answers

The values of the matrices operations are [tex]4G + 2F = \left[\begin{array}{ccccc}34&-4&-42&-18&48\\-42&-8&16&30&8\\24&32&4&34&34&-12&-32&-12&-42&-20\end{array}\right][/tex] and [tex]4D - 3B= \left[\begin{array}{ccccc}31&6&34&-14&-57\\-19&-27&-18&18&27\\47&14&-1&-40&9&10&12&-19&-15&-58&-14&-23&10&-8&10\end{array}\right][/tex]

Evaluating the matrices operations

From the question, we have the following parameters that can be used in our computation:

[tex]G = \left[\begin{array}{ccccc}8&-5&-7&-1&10\\-6&-7&1&9&2\\4&6&3&7&5&-4&-3&0&-10&-9\end{array}\right][/tex]

Also, we have

[tex]F = \left[\begin{array}{ccccc}1&8&-2&-5&9\\-9&10&6&-3&0\\4&5&-4&3&7&2&-10&-6&-1&-8\end{array}\right][/tex]

Using the above as a guide, we have

[tex]4G + 2F = 4\left[\begin{array}{ccccc}8&-5&-7&-1&10\\-6&-7&1&9&2\\4&6&3&7&5&-4&-3&0&-10&-9\end{array}\right] + 2 \left[\begin{array}{ccccc}1&8&-2&-5&9\\-9&10&6&-3&0\\4&5&-4&3&7&2&-10&-6&-1&-8\end{array}\right][/tex]

Evaluate the sum

[tex]4G + 2F = \left[\begin{array}{ccccc}34&-4&-42&-18&48\\-42&-8&16&30&8\\24&32&4&34&34&-12&-32&-12&-42&-20\end{array}\right][/tex]

Next, we have

[tex]D = \left[\begin{array}{ccccc}7&-6&3&-8&-9\\2&-9&-6&6&9\\8&2&5&-10&-3&10&-3&-4&3&-7&1&-2&4&-5&-2\end{array}\right][/tex]

Also, we have

[tex]B = \left[\begin{array}{ccccc}-1&-10&-8&-6&7\\9&-3&-2&2&3\\-5&-2&7&0&-7&10&-8&1&9&10&6&5&2&-4&-9\end{array}\right][/tex]

The matrix expression is then represented as

[tex]4D - 3B= 4\left[\begin{array}{ccccc}7&-6&3&-8&-9\\2&-9&-6&6&9\\8&2&5&-10&-3&10&-3&-4&3&-7&1&-2&4&-5&-2\end{array}\right] - 3\left[\begin{array}{ccccc}-1&-10&-8&-6&7\\9&-3&-2&2&3\\-5&-2&7&0&-7&10&-8&1&9&10&6&5&2&-4&-9\end{array}\right][/tex]

Evaluate

[tex]4D - 3B= \left[\begin{array}{ccccc}31&6&34&-14&-57\\-19&-27&-18&18&27\\47&14&-1&-40&9&10&12&-19&-15&-58&-14&-23&10&-8&10\end{array}\right][/tex]

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Bob has saved $600 each month for the last 3 years
to make a down payment on a house. The account
earned an interest rate of 0.50 percent per month.
How much money is in Bob's account?

Answers

Answer:

300

Step-by-step explanation:

A company produces two products, A and B. At
least 30 units of product A and at least 10 units of
product B must be produced. The maximum
number of units that can be produced per day is
80. Product A yields a profit of $15 and product B
yields a profit of $8. Let a = the number of units of
product A and b = the number of units of product
B.
What objective function can be used to maximize
the profit?
P=
DONE✔
a+
b

Answers

The objective function that can be used to maximize the profit is Profit = 15a + 8b

Let a is the number of units of product A and b is the number of units of product B.

Profit = 15a + 8b

This function represents the total profit earned by producing a units of product A and b units of product B

Given that the profit per unit of product A is $15 and the profit per unit of product B is $8.

To maximize the profit, we would need to find the values of a and b that satisfy the constraints given in the problem and maximize the value of the objective function

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The mean monthly salary of female employees of a company is 3750 Birr, while the mean monthly salary of male employees is 4500 Birr. It is known that the mean monthly salary of male and female employees combined is 4000 Birr. a) What is the ratio of the number of female employees to male employees? b) What percentage of employees are females?​

Answers

Let the number of female employees in the company be represented by f, and the number of male employees be represented by m.

a) We can use the information given to set up the following equation:

(3750f + 4500m)/(f + m) = 4000

Multiplying both sides by f + m, we get:

3750f + 4500m = 4000(f + m)

Expanding and simplifying, we get:

250f = 500m

Dividing both sides by 250, we get:

f/m = 2/1

Therefore, the ratio of the number of female employees to male employees is 2:1.

b) The total number of employees is f + m. To find the percentage of employees that are female, we can use the ratio we found in part a) to write:

f/(f + m) = 2/(2+1) = 2/3

Multiplying by 100%, we get:

females as a percentage = (2/3) x 100% = 66.67%

Therefore, approximately 66.67% of the employees are females.

Find the volume of the cone shown. Use 3.14 for pi. Round your answer to the nearest hundredth.

Answers

Answer: 100.48 cubic feet

Step-by-step explanation:

Find the consumers' surplus at a price level of $1 for the price-demand equation

p= D(x) = 20-0.1x
where p is the price and x is the demand. Do not include a dollar sign or any commas in your answer.

Answers

The consumers' surplus at a price level of $1 for the price-demand equation is -1072.5.

Given that price-demand equation p= D(x) = 20-0.1x, we need to find the consumers' surplus at a price level of $1.

So,

From the equation we have,

20-0.1x = 1

0.1x = 19

x = 190

Therefore, the equilibrium point = (190, 1) = (xe, Pe)

Now,

Cs = [tex]\int\limits^{x_e}_0 {D(x)} \ dx\, -Pexe[/tex]

[tex]\int\limits^{190}_0 {20-0.1x} \ dx\, -(190)[/tex]

= 20-0.1{9025}-190

= -1072.5

Hence the consumers' surplus at a price level of $1 for the price-demand equation is -1072.5

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Trundle wheels are used to measure distances along the ground.
The radius of the trundle wheel is 30 cm.
Jim wants to work out the distance between two junctions on a road.
He rolls the trundle wheel between the two junctions.
The trundle wheel rotates exactly 48 times.
Work out the distance between the two junctions.
Give your answer in metres correct to the nearest metre.

Answers

The distance between the two junctions is, 90 meters, when rounded off to the nearest meter.

:: Radius of trundle wheel = 30 cm = 0.3 meter (as 100 cm = 1 m)

:: No. of rotations = 48

:: Circumference of a circle = ( 2 x π x r )

where, r is radius of the circle

So, as,

Distance between junctions = [ (circumference of trundle wheel) x (no. of rotations) ]

Therefore,

Distance = (2 x π x 0.3) x (48)

Distance = 2 x (3.14) x 0.3 x 48

Distance = 90.432 meters

When rounded off to the nearest meter,

Distance = 90 meters.

So, The distance between the two junctions is, 90 meters, when rounded off to the nearest meter.

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The cost of a pen is $15. Find the cost of 162 pens

Answers

Answer: 15 x 162 = 2430$

So the cost of one pen is $15, we have to find the cost of 162 pens that will cost $15 each.

162 x $15 = $2,430

The cost of 162 pens is $2,430. (Without tax)

A local radio station is running a contest were 35 people have qualified. From these qualifiers, 3 will be randomly selected to win a trip to the Bahamas. How many different possibilities are there for the outcome of this contest?

Answers

Answer:

39270

Step-by-step explanation:

When the first person is picked, there is a 1 in 35 chance that it will be Person 1. If they are selected, that leaves 34 people left in the pool. After Person 2 is selected, there are 33 people left in the pool for Person 3.

35*34*33=39270

What is 2 1/4 divided by 1 1/2?

Answers

Answer:

2 1/4 divided by 1 1/2 is equal to 9/2 or 4 1/2.

Step-by-step explanation:

To divide 2 1/4 by 1 1/2, we first need to convert both mixed numbers to improper fractions:

2 1/4 = (2 × 4 + 1) / 4 = 9 / 4

1 1/2 = (1 × 2 + 1) / 2 = 3 / 2

Now we can divide by multiplying by the reciprocal of the second fraction:

(9/4) / (3/2) = (9/4) * (2/3)

We can simplify this multiplication by canceling the common factor of 3 in the numerator of the second fraction and the denominator of the first fraction:

(9/4) * (2/3) = (33/4) * (2/13) = 9/2

So 2 1/4 divided by 1 1/2 is equal to 9/2 or 4 1/2.

Answer:

[tex]\boxed{\sf \dfrac{3}{2}}.[/tex]

Step-by-step explanation:

1. Write the expression.

[tex]\sf \dfrac{2\dfrac{1}{4} }{1\frac{1}{2} }[/tex]

2. Convert the mixed fractions into improper fractions.

[tex]\sf 2\dfrac{1}{4}\Longrightarrow\dfrac{4}{4} +\dfrac{4}{4} +\dfrac{1}{4} =\dfrac{4+4+1}{4} =\dfrac{9}{4}[/tex]

[tex]1\dfrac{1}{2} =\dfrac{2}{2} +\dfrac{1}{2} =\dfrac{2+1}{2} =\dfrac{3}{2}[/tex]

3. Rewrite the division.

[tex]\sf \dfrac{\dfrac{9}{4} }{\dfrac{3}{2} }[/tex]

4. Rewrite again using the properties of fractions.

• Check the attached image.

[tex]\dfrac{9}{4} *\dfrac{2}{3}[/tex]

5. Calculate and simplify.

[tex]\dfrac{9*2}{4*3} =\dfrac{18}{12} \\ \\\dfrac{18/2}{12/2} =\dfrac{9/3}{6/3}=\boxed{\sf \dfrac{3}{2}} .[/tex]

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Models that represent z+9=14 ASAP

Answers

To represent z+9=14, we can start by subtracting 9 from both sides of the equation:

z + 9 - 9 = 14 - 9

Simplifying the left side of the equation gives:

z = 5

Therefore, the solution to the equation z+9=14 is z=5.

A spinner divided into three equal sections marked A A and Z is spun 570 times approximately how many times will it be expected to land on an A

Answers

If a spinner divided into three equal sections marked A A and Z is spun 570 times .  The number of  times it will be expected to land on an A is 380 times.

How to find the Expected number of time ?

Since the spinner has three equal sections in which two of them are marked A.  The probability of landing on an A in a single spin will be 2/3  while the probability of landing on Z  will be 1/3.

So,

Expected number of time E(A) =Number of spins x Probability of landing on A

Expected number of time E(A) = 570 x (2/3)

Expected number of time E(A)  = 380

Therefore the Expected number of time E(A) is 380 times.

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