Pythagorean Theorem help quickly please

Pythagorean Theorem Help Quickly Please

Answers

Answer 1

Using the Pythagorean theorem, the height of the ramp in the given diagram is 8.9 ft

Pythagorean theorem: Calculating the height of the ramp

From the question, we are to determine how high the ramp is

From the Pythagorean theorem which states that "in a right triangle, the square of the longest side, that is hypotenuse, equals sum of squares of the two other sides".

In the given diagram,

We have a right triangle

The measure of the hypotenuse is 21 ft

One of of the side measures 19 ft

Now, we will calculate x

By the Pythagorean theorem, we can write that

h² + 19² = 21²

h² = 21² - 19²

h² = 441 - 361

h² = 80

h = √80

h = 8.94427 ft

h ≈ 8.9 ft

Hence, the ramp is 8.9 ft high

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Related Questions

5 points


You need to change a blown outdoor lightbulb on your house. The bulb is 5m up, but you have a 1m reach when you are on the top rung of the ladder. If you need 3m of


space off the house for the ladder's base for stability, what is the minimum height of the ladder in meters?

Answers

The minimum height of the ladder needed to change the blown outdoor lightbulb is 5 meters.

To determine the minimum height of the ladder needed to change a blown outdoor lightbulb that is 5m up, we need to consider the following terms:

1. The bulb's height (5m)


2. Your reach when on the top rung of the ladder (1m)


3. The required space off the house for the ladder's base for stability (3m)

First, subtract your reach from the bulb's height: 5m - 1m = 4m. This means the ladder needs to reach at least 4 meters up the wall.

Next, we need to use the Pythagorean theorem to find the ladder's minimum height. The theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the ladder) is equal to the sum of the squares of the lengths of the other two sides (the distance from the house and the height up the wall).

Let's denote the ladder's height as L, the distance from the house as A (3m), and the height up the wall as B (4m).

According to the Pythagorean theorem, we have:
L² = A² + B²

Substitute the values for A and B:
L² = (3m)² + (4m)²
L² = 9m² + 16m²
L² = 25m²

Now, find the square root to get the minimum height of the ladder:
L = √25m²
L = 5m

So, the minimum height of the ladder needed to change the blown outdoor lightbulb is 5 meters.

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Clara's class is preparing for a field trip. Her teacher purchased bottled water for the trip and asked Clara to stock a cooler with 2 bottles for every student who is going. 5 of the students didn't turn in permission slips and aren't going on the trip. So, Clara stocks the cooler with 38 bottles of water.

Which equation can you use to find the total number of students, n, in Clara's class?

Answers

The equation that can be used to find the total number of students would be n = 19 + 5.

How to find the equation ?

It is acknowledged that Clara provided 2 bottles per each pupil joining her on the excursion. Denote, by using ‘x’, the quantity of learners present; we can then inscribe the succeeding formula:

2x = 38

By resolving this mathematical principal, the total number of students attending the event is revealed.

x = 38 / 2

x = 19

Currently, 19 individuals are confirmed to embark upon the outing, due to five individuals failing to furnish required consent forms and will be absent. Subsequently, we may deduce the quantity of pupils (designated as ‘n’) in Clara’s class:

n = 19  (students going on the trip ) + 5 ( students not going )

n = 19 + 5

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Triangle PQR has vertices at the following coordinates: P(0, 1), Q(3, 2), and R(5, -4). Determine whether or not triangle PQR is a right triangle. Show all calculations for full credit.


Will give Brainliest! No links! Will report

Answers

Triangle PQR is not a right triangle.

To determine whether triangle PQR is a right triangle, we need to check if any of its angles is a right angle (90 degrees). We can use the slope formula to find the slopes of the sides of the triangle and check if any of the slopes are negative reciprocals (perpendicular) to each other.

Let's calculate the slopes of the sides PQ, QR, and RP:

Slope of PQ = (y₂ - y₁) / (x₂ - x₁)

= (2 - 1) / (3 - 0)

= 1 / 3

Slope of QR = (y₂ - y₁) / (x₂ - x₁)

= (-4 - 2) / (5 - 3)

= -6 / 2

= -3

Slope of RP = (y₂ - y₁) / (x₂ - x₁)

= (1 - (-4)) / (0 - 5)

= 5 / (-5)

= -1

Now, let's check if any of the slopes are negative reciprocals of each other. We can compare the products of the slopes:

Product of PQ slope and QR slope = (1/3) * (-3) = -1

Product of QR slope and RP slope = (-3) * (-1) = 3

Product of RP slope and PQ slope = (-1) * (1/3) = -1/3

Since the product of the slopes of QR and RP is not equal to -1, triangle PQR is not a right triangle.

Therefore, triangle PQR is not a right triangle.

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What kind of triangle has angles that measure 47, 70, and 63 degrees

Answers

Answer:

Acute triangle

Step-by-step explanation:

angles that are less than 90° are called acute

This triangle has 3 acute angles, so it is an acute triangle

HELP!!!



What is the unit rate of this graph?

BLUE: 200 beats/minute
TEAL: 75 beats/minute
YELLOW: 100 beats/minute
RED: 150 beats/minute

Answers

75 beats/minute is the answer

Which expressions are equivalent to 6\cdot6\cdot6\cdot6\cdot66⋅6⋅6⋅6⋅66, dot, 6, dot, 6, dot, 6, dot, 6 ?

Answers

The expressions equivalent to 6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66 are 1296\cdot396\cdot2376 and 839808\cdot36.

Find out which expression is equivalent to the given expressions?

We can use the associative property of multiplication to group the factors in different ways while preserving their product. For example, we can group the first four 6's together and then multiply by the remaining 6 and 66:

6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66 = (6\cdot6\cdot6\cdot6)\cdot(6\cdot66)\cdot(6\cdot6\cdot66)

= 1296\cdot396\cdot2376

Alternatively, we can group the last two 6's together and then multiply by the remaining factors:

6\cdot6\cdot6\cdot6\cdot66\cdot6\cdot6\cdot6\cdot66 = (6\cdot6\cdot6\cdot6\cdot66)\cdot(6\cdot6)

= 839808\cdot36 is the equivalent expression.

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PLEASE HURRY DUE IN 2 HOURS

Explain how the shapes shown have been sorted.


Two groups of shapes. In group A, one shape has four equal side lengths of three, and no right angles. The opposite sides are parallel. Two shapes have two pairs of opposite equal side lengths. One shape has side lengths of four and eight. The other side lengths are three and two. Opposite sides are parallel, and there are no right angles. In group B there are three four sided shapes. One has opposite equal side lengths of seven and four and four right angles. One shape has four equal side lengths of three and four right angles. One shape has one set of opposite parallel sides and one right angle. None of the side lengths in the last shape are equal.



The image is below if you don't want to read all that, And PLEASE actually answer the question.

Answers

The figure with opposite sides are parallel and equal is parallelogram.

From the group A:

In first image opposite sides are parallel and equal.

One pair of parallel sides = 4 units and the another pair of parallel sides = 8 units

So, it is parallelogram.

In second image opposite sides are parallel and all the sides are equal.

So, it is rhombus.

In third image opposite sides are parallel and equal.

One pair of parallel sides = 3 units and the another pair of parallel sides = 2 units

So, it is parallelogram.

From the group B:

In first image opposite sides are parallel and equal.

One pair of parallel sides = 4 units and the another pair of parallel sides = 7 units and all angles measures equal to 90°.

So, it is rectangle.

In second image one pair of opposite sides are parallel.

So it is trapezium.

In third image opposite sides are parallel and all sides equal.

All angles measures equal to 90°.

So it is square.

Therefore, the figure with opposite sides are parallel and equal is parallelogram.

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Luis tiene una mochila de ruedas que mide 3.5 pies de alto cuando se extiende el mango. Al hacer rodar su mochila, la mano de Luis se encuentra a 3 pies del suelo. ?Qué ángulo forma su mochila con el suelo? Aproxima al grado más cercano.

Answers

The backpack forms an angle of approximately 15 degrees with the ground.

What is Pythagorean theorem?

The Pythagorean theorem is a fundamental concept in mathematics that relates to the lengths of the sides of a right triangle.

To find the angle that Luis's backpack forms with the ground, we can use the inverse tangent function.

The height of the backpack when the handle is extended is 3.5 feet, and the distance from the ground to Luis's hand is 3 feet. So the opposite side of the triangle is 3.5 - 3 = 0.5 feet, and the adjacent side is the distance from Luis's hand to the backpack, which we can call x.

Using the tangent function, we have:

tan(theta) = opposite/adjacent

tan(theta) = 0.5/x

To solve for x, we can use the Pythagorean theorem:

x² + 3² = (3.5)²

x² = 3.5² - 3²

x² = 3.25

x = sqrt(3.25)

x ≈ 1.8 feet

Now we can substitute x into our tangent equation and solve for theta:

tan(theta) = 0.5/1.8

theta = arctan(0.5/1.8)

theta ≈ 15 degrees

Therefore, the backpack forms an angle of approximately 15 degrees with the ground.

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-8
Find the distance, d, of AB.
A = (-7, -7) B = (-3,-1)
-6 -4
A
-2
B -2
-4
-6
-8
d = √x2-x1² + y2 - Y₁|²
d = [?]
Round to the nearest tenth.
Distance

Answers

Step-by-step explanation:

Using the distance formula:

d = √[(x2 - x1)² + (y2 - y1)²]

where A = (x1, y1) and B = (x2, y2), we can find the distance between points A and B as follows:

d = √[(-3 - (-7))² + (-1 - (-7))²]

d = √[4² + 6²]

d = √52

d ≈ 7.2

Therefore, the distance between points A and B is approximately 7.2 units, rounded to the nearest tenth.

Now that you learned how to calculate the probabilities of each player winning the "maximum game" in the video, let's look at the probabilities of another game. this is how it works: we roll two dice and calculate the multiplication of the two numbers we rolled. --if it is a multiple of 6, i win --if it is not a multiple of 6, you win. here is an example: if you get 3 and 4, the multiplication is 12. twelve is a multiple of 6, so i win! 1. which player would win if you get 2 and 5 in the dice? me or you? 2. which player would win if you get 4 and 2 in the dice? 3. which player would win if you get 1 and 6 in the dice?

Answers

1) If you get 2 and 5, the multiplication is 10, which is not a multiple of 6. so, you would win.

2) If you get 4 and 2, the multiplication is 8, which is not a multiple of 6. so, you would win.

3) If you get 1 and 6, the multiplication is 6, which is a multiple of 6. so, I would win.

1) How to find  the probability?

The question asks about probability  which player would win if the numbers rolled are 2 and 5. To answer this, we calculate the product of 2 and 5, which is 10. Since 10 is not a multiple of 6, the person who did not roll the dice (i.e., "you") would win.

2) How to find  the probability?

The question asks which player would win if the numbers rolled are 4 and 2. We calculate the product of 4 and 2, which is 8. Since 8 is not a multiple of 6, "you" would win again.

3) How to find  the probability?

The question asks which player would win if the numbers rolled are 1 and 6. We calculate the product of 1 and 6, which is 6. Since 6 is a multiple of 6, the person who rolled the dice (i.e., "me") would win.The game described in the question involves rolling two dice and calculating the multiplication of the two numbers rolled. The outcome of the game depends on whether the product is a multiple of 6 or not.

The solution also provides a general explanation of how to calculate the probability of rolling a multiple of 6 with two dice. To do this, we count the number of ways to roll each multiple of 6 (there are two ways to roll a 6, one way to roll a 12, and no ways to roll an 18) and divide by the total number of possible outcomes (which is 36, since there are 6 possible outcomes for each die and 6*6=36 possible combinations of two dice). This gives us a probability of 1/12, or approximately 0.0833, for rolling a multiple of 6. We can then calculate the probability of not rolling a multiple of 6 by subtracting this probability from 1, which gives us 11/12, or approximately 0.9167.

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In rhombus YZAB, if YZ=12, find AB.​

Answers

The length of side AB is also 12 units.

What is a rhombus?

A rhombus is a four-sided quadrilateral with all sides of equal length. It is also known as a diamond or a lozenge. In a rhombus, opposite sides are parallel, and opposite angles are equal. Additionally, the diagonals of a rhombus bisect each other at right angles, meaning they intersect at a 90-degree angle and divide each other into two equal segments.

Since a rhombus has all sides of equal length, we know that YZ = AB. Therefore, if YZ = 12, we have:

AB = YZ = 12

So the length of side AB is also 12 units.

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PLS HLEP AND SHOW WORK I WILL MATK BRAINLYEST

Answers

Answer:
38. (A) True
39. (B) False

Step-by-step explanation:

The set of people working in the summer consists of both female an male since there is no determiner to show that the 80% of students are a specific gender. Therefore, the answer to the first question is True (A).

My expression for finding the probability of being female and working part time in summer only is:
[tex]\frac{84}{100} \\\\ \\ \\ \\[/tex][tex](\frac{1}{2} *\frac{80}{100})\\[/tex][tex]=\frac{42}{125}[/tex] which is also equal to 0.336. Therefore the second question is false.




Please forgive me if I'm wrong but I'm open to any correction or criticisms.

to
Mrs. James, a sixth grade teacher, recorded how many minutes
each student reported reading over winter break.
Time spent reading (min.)
0
H
200.
What was the upper quartile of the time spent reading?
minutes
Submit
100
H
300.
400
+
500

Answers

The upper quartile of the time spent reading is 300.

We have,

The upper quartile, also known as the third quartile, is a measure of central tendency that divides a data set into four equal parts.

It represents the data point that separates the top 25% of the data from the bottom 75%.

Now,

From the box pot.

Median = 250

Lower quartile = 100

Upper quartile = 300

Thus,

The upper quartile is 300.

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solve this and I will give u brainlist.

Answers

We can use basic trigonometry to solve this problem. If we draw a right triangle with the angle of inclination as one of the acute angles, then the opposite side of the triangle is the height of skyscraper B, and the adjacent side is the horizontal distance between the two buildings.

We can use the tangent function to find the length of the adjacent side:

tan(14.4) = opposite / adjacent

tan(14.4) = 1472 / adjacent

adjacent = 1472 / tan(14.4)

adjacent = 6163.6 feet (rounded to one decimal place)

Therefore, the distance from skyscraper A to skyscraper B is approximately 6163.6 feet.

R1 and R2 be relations on a set A represented by the matrices ?

Answers

R1 and R2 are relations on a set A, which means they define a set of ordered pairs of elements in A. The matrices that represent R1 and R2 can be thought of as a way to visualize these ordered pairs.



Each row and column of the matrix corresponds to an element in A. If there is a 1 in the ith row and jth column of the matrix for R1, then (i,j) is an ordered pair in R1. Similarly, if there is a 1 in the ith row and jth column of the matrix for R2, then (i,j) is an ordered pair in R2.

If there is a 0 in a particular position in the matrix, then the corresponding pair is not in the relation.

Let R1 and R2 be relations on a set A. These relations can be represented by matrices M1 and M2, respectively, with dimensions |A|x|A|, where |A| is the cardinality of set A. The elements of the matrices M1 and M2 are binary, indicating whether there is a relation between the corresponding elements of set A in R1 and R2, respectively. If there is a relation, the matrix element will be 1, and if there is no relation, the matrix element will be 0.

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solve for the value of x .
80(x+15)
=60

Answers

Answer:

x = [tex]\frac{-57}{4}[/tex]

Step-by-step explanation:

solve for the value of x .

80(x+15)=60

80(x + 15) = 60

80x + 1200 - 60 = 0

80x + 1140 = 0

80x = -1140

x = -1140/80

x = [tex]\frac{-57}{4}[/tex]

Answer:

-14.25

Step-by-step explanation:

Given: 80 (x+15) = 60

Solution: On opening the brackets, we get

> 80x + 80 * 15 = 60

> 80x + 1200 = 60

Then, taking 1200 to the other side of the equation,

80x = 60 - 1200

Therefore, 80x = -1140

Now, dividing both sides by 80, we get:

80x/80 = -1140/80

So, x= -14.25

Hope this helps!

Each letter in these following problems will be transformed into a number based on their number in the alphabet. Solve these following problems based on this information.

1) n + e
2) t-j
3) d x e
4) p/b

Answers

The solution to the problems are given below:

n + e = 14 + 5 = 19t - j = 20 - 10 = 10d x e = 4 x 5 = 20p / b = 16 / 2 = 8

How to solve

Giving each of the letters numbers based on their numerical position on the English alphabet, we can solve below:

n (14) + e (5) = 14 + 5 = 19

t (20) - j (10) = 20 - 10 = 10

d (4) x e (5) = 4 x 5 = 20

p (16) / b (2) = 16 / 2 = 8

It can be seen that with the letter e for example is the 5th letter of the alphabet and the value is used to compute the addition of the problem.


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Nate jumped 26 inches. Maria jumped 32 inches.


How much farther did Maria jump than Nate?


Drag numbers and symbols to the lines. Write an equation to represent the problem. Use for the unknown.


26


32
.


+

Answers

Maria jumped 6 inches farther than Nate.

To see why, we can subtract Nate's jump height from Maria's jump height:

32 - 26 = 6

So Maria jumped 6 inches farther than Nate did.

To represent this problem mathematically, we can use the equation:

Maria's jump height - Nate's jump height = the difference in their jump heights

Or, using variables:

M - N = D

Where M represents Maria's jump height, N represents Nate's jump height, and D represents the difference between their jump heights. Plugging in the numbers from the problem, we get:

32 - 26 = D

Simplifying, we get:

6 = D

So D, the difference between their jump heights, is 6 inches.

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PLEASE HELP MEH



A 1,700-foot support wire is attached to


the top of an 800-foot radio tower.


1,700 ft


800 ft


А


B


A scale drawing of the tower and wire is


drawn using the scale 1 inch: 250 feet.


On the scale drawing, what is the length,


in inches, of AB? (8. 1B, 8. 1F)


F


15 in.


Make sure to


use the scale.


G 7. 5 in.


H


6 in.


J 18 in.

Answers

We know that the length of AB on the scale drawing is 10 inches

Using the scale of 1 inch: 250 feet, we can find the length of AB on the scale drawing by multiplying the actual length of AB by the scale factor.

The actual length of AB is the sum of the height of the tower (800 ft) and the length of the support wire (1,700 ft), which is 2,500 ft.

Multiplying 2,500 ft by the scale factor of 1 inch: 250 feet, we get:

2,500 ft ÷ 250 ft/inch = 10 inches

Therefore, the length of AB on the scale drawing is 10 inches.

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(1) Begin with a 1-by-1 square, J. Attach squares which are half as wide (and half as tall) to the middle of each side of Jį to form J2. Attach squares half as wide as those squares to every . outer edge of J2 in order to make J3. Repeat. F F2 F3 (a) Find the area of Jg. (b) If we continue in this way forever, does the area of Joo converge? If so, what does it converge to?
Previous question

Answers

Starting with a 1-by-1 square, a sequence of squares J1, J2, J3, ... is created by attaching squares half as wide as the previous squares to the outer edges of each successive square. The area of J∞, the limit of this sequence, is 4/3.

To find the area of J1, we simply calculate the area of the original 1-by-1 square, which is 1.

To find the area of J2, we need to attach squares half as wide (and half as tall) to the middle of each side of J1. The area of each attached square is (1/2)² = 1/4, so the total area added to J1 is 4(1/4) = 1. Thus, the area of J2 is 1 + 4(1/4) = 2.

To find the area of J3, we need to attach squares half as wide as the squares added in the previous step to every outer edge of J2. The area of each attached square is (1/4)² = 1/16, so the total area added to J2 is 4(1/16) = 1/4. Thus, the area of J3 is 2 + 4(1/4) = 3.

We can continue this process to find the areas of J4, J5, and so on. In general, the area of Jn is equal to the area of the previous square plus the area added by the attached squares, which is 4(1/2^(n-1))^2 = 1/2^(2n-2). Therefore, the area of Jn is 1 + 1/4 + 1/16 + ... + 1/4^(n-1) = (4/3)(1 - 1/4^n).

As n approaches infinity, the area of Jn approaches the limit of (4/3)(1 - 0) = 4/3. Therefore, the area of J∞, the limit of the sequence, is 4/3.

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2. Rectangle WXYZ with vertices W(-3,-4), X(0,-5), Y(-2,-11),


and Z(-5, -10); 180° rotation about N(2,-3)

Answers

The rectangle WXYZ after a 180° rotation about the point N(2,-3) is W(3,-2), X(0,-1), Y(2,5), and Z(5,4).

To perform a 180° rotation about the point N(2,-3), we can follow these steps:

1. Translate the rectangle and the point N to the origin by subtracting their respective coordinates from each vertex and point.

2. Perform the rotation by multiplying the coordinates of each vertex and point by the 2x2 rotation matrix:

  [cos(180°) -sin(180°)]

  [sin(180°) cos(180°)]

  which simplifies to:

  [-1  0]

  [ 0 -1]

3. Translate the rectangle and the point N back to their original positions by adding their respective coordinates to each vertex and point.

Let's apply these steps to rectangle WXYZ and point N:

1. Translate the rectangle and point N to the origin:

W' = (-3 - 2, -4 + 3) = (-5, -1)

X' = (0 - 2, -5 + 3) = (-2, -2)

Y' = (-2 - 2, -11 + 3) = (-4, -8)

Z' = (-5 - 2, -10 + 3) = (-7, -7)

N' = (2 - 2, -3 + 3) = (0, 0)

2. Perform the rotation using the matrix:

  [-1  0]

  [ 0 -1]

W'' = [-1  0] * [-5, -1] = [5, 1]

     [0 -1]

X'' = [-1  0] * [-2, -2] = [2, 2]

     [0 -1]

Y'' = [-1  0] * [-4, -8] = [4, 8]

     [0 -1]

Z'' = [-1  0] * [-7, -7] = [7, 7]

     [0 -1]

N'' = [-1  0] * [0, 0] = [0, 0]

     [0 -1]

3. Translate the rectangle and point N back to their original positions:

W = [5 - 2, 1 - 3] = (3, -2)

X = [2 - 2, 2 - 3] = (0, -1)

Y = [4 - 2, 8 - 3] = (2, 5)

Z = [7 - 2, 7 - 3] = (5, 4)

N = [0 + 2, 0 + 3] = (2, 3)

Therefore, the rectangle WXYZ after a 180° rotation about the point N(2,-3) is W(3,-2), X(0,-1), Y(2,5), and Z(5,4).

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Find the absolute maximum and minimum values of f(x,y) = x^2 + 2y^2 on the square [0,1] x [0,1]

Answers

Answer:

The maximum is when both X and y = 1.The maximum value of the function is 3.When both X and YY are equal to 0, the minimum value is 0

The absolute maximum value is 3 and the absolute minimum value is 0.

To find the absolute maximum and minimum values of f(x,y) = x^2 + 2y^2 on the square [0,1] x [0,1], we need to consider both the interior and the boundary of the square.

First, check for critical points in the interior by finding the partial derivatives and setting them equal to zero:

fx = 2x and fy = 4y

Setting them equal to zero, we have:
2x = 0 => x = 0
4y = 0 => y = 0

The only critical point in the interior is (0,0).

Next, evaluate f(x,y) on the boundary of the square [0,1] x [0,1]. The boundary consists of four segments: x=0, x=1, y=0, and y=1.

1. x=0: f(0,y) = 2y^2 (for y in [0,1])
2. x=1: f(1,y) = 1 + 2y^2 (for y in [0,1])
3. y=0: f(x,0) = x^2 (for x in [0,1])
4. y=1: f(x,1) = x^2 + 2 (for x in [0,1])

Now, compare the values of f at the critical point and boundary points to find the absolute maximum and minimum:

Absolute minimum: f(0,0) = 0
Absolute maximum: f(1,1) = 3

So the absolute maximum value is 3 and the absolute minimum value is 0.

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find the area of each polygon below b=6 h=9 ft h =10cm b = 8 h=8m b=9m

Answers

To find the area of a polygon, we need to know the length of its base and its height. Once we have these measurements, we can use the formula:

Area = (1/2) x Base x Height

where "Base" refers to the length of the base of the polygon, and "Height" refers to the length of a perpendicular line drawn from the base to the opposite vertex.

Using this formula, we can find the areas of the polygons with the given measurements:

For the first polygon with base b=6 ft and height h=9 ft, we have:

Area = (1/2) x 6 ft x 9 ft = 27 ft^2

For the second polygon with base b=10 cm and height h=8 m, we need to convert the height to centimeters to keep the units consistent:

Height = 8 m x 100 cm/m = 800 cm

Then, we can calculate the area as:

Area = (1/2) x 10 cm x 800 cm = 4000 cm^2

For the third polygon with base b=8 m and height h=8 m, we have:

Area = (1/2) x 8 m x 8 m = 32 m^2

For the fourth polygon with base b=9 m and height h=5 m, we have:

Area = (1/2) x 9 m x 5 m = 22.5 m^2

Therefore, the areas of the polygons are:

- 27 ft^2
- 4000 cm^2
- 32 m^2
- 22.5 m^2

Pls help, answer both of the questions with explanation.

Answers

A). X is adults y is child
4x + 7y = £45
1y = 2x

B) answer: adult ticket: £6
adult tickets become child tickets
4x = 8y
8y + 7y = £45
15y = £45
Y = 3
Adult is double
X= £6

This is my math hw someone help pls ?

Answers

in order for you to find the hypotenuse you must use cos(59)=45
45/cos(59)

For which values of k would be the pruduct of k/3x12 be greater than 12

Answers

The product (k/3) x 12 is greater than 12 for values of k greater than 3.

To determine the values of k for which the product (k/3) x 12 is greater than 12, follow these steps:

Step 1: Set up the inequality:
(k/3) x 12 > 12

Step 2: Simplify the inequality by dividing both sides by 12:
(k/3) > 1

Step 3: Multiply both sides by 3 to solve for k:
k > 3

So, the product (k/3) x 12 is greater than 12 for values of k greater than 3.

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The Phillips family bought 8 bags of cookies. Each bag had 17 cookies. They have since eaten 29 of the cookies. How many cookies do they have left?

Answers

Answer:107

Step-by-step explanation:8*17-29=107 so our answer is 107

Let X be the number of screws delivered to a box by an automatic filling device.

Assume = 1000 and

2 = 25. There are problems with too many screws going

into the box or too few screws going into the box.

a. How many units to the right of is 1009? (5 marks)

b. What X value is 2. 6 units to the left of ? (4 marks​

Answers

There are approximately 0.1480 standard deviations (or 3.7 screws) to the right of the mean when there are 1009 screws in the box.  When the automatic filling device delivers 1065 screws to the box, there are approximately 2.6 standard deviations (or 65 screws) to the left of the mean.

To answer this question, we need to use the normal distribution formula.


a. To find how many units to the right of 1000 is 1009, we need to calculate the z-score:

z = (X - μ) / σ

where X = 1009, μ = 1000, and σ = 25.

z = (1009 - 1000) / 25 = 0.36

Using a standard normal distribution table or calculator, we can find that the probability of getting a z-score of 0.36 or higher is 0.3520.

To convert this probability to units to the right of the mean, we subtract it from 0.5 (which represents the area to the left of the mean):

units to the right = 0.5 - 0.3520 = 0.1480

Therefore, there are approximately 0.1480 standard deviations (or 3.7 screws) to the right of the mean when there are 1009 screws in the box.

b. To find the X value that is 2.6 units to the left of the mean, we can rearrange the formula:

X = μ - zσ

where z = -2.6 (since we want units to the left of the mean) and μ and σ are the same as before.

X = 1000 - (-2.6) * 25 = 1065

Therefore, when the automatic filling device delivers 1065 screws to the box, there are approximately 2.6 standard deviations (or 65 screws) to the left of the mean.

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A company had a profit of $4,758 in January and a profit of -$3,642 in February. The company's profits for the months of March through May


were the same in each of these months. By the end of May, the company's total profits for the year were -$1,275.


What were the company's profits each month from March through May? Enter the answer in the box.

Answers

The company's profits for March through May were each -$797.

What was the company's profits for March through May?

Let's start by adding the profits for January and February:

Profit for January + Profit for February = $4,758 + (-$3,642) = $1,116

We know that the company's profits for March through May were the same in each of these months, so let's call this common profit "X". Therefore, the total profit for these three months would be:

3 * X = 3X

Adding up the profits for all five months gives us the total profit for the year:

$1,116 + 3X = -$1,275

Subtracting $1,116 from both sides gives us:

3X = -$2,391

Dividing both sides by 3 gives us:

X = -$797

Therefore, the company's profits for March through May were each -$797.

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solve the equation |4x +9|=|6-5x|​

Answers

|4x +9|=|6-5x|

4x+5x=6-9

9x=-3

x=-3/9

x=-1/3

Answer:

x = 15

x = - ⅓

Step-by-step explanation:

|4x+9| = |6-5x|

4x+9=6-5x or 4x+9=-6+5x

Lets do the first one first

4x+9=6-5x

9x=-3

x= -3/9 = -1/3

4x+9=-6+5x

15=x

So the two solutions are x = 15 and x = -⅓

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