la componente "cubica" será aquella que tenga un exponente igual a 3.
¿como identifico una X Cubica en un polinomio?
Un polinomio tiene la forma general:
[tex]p(x) = a_n*x^n + ... + a_1*x^1 + a_0[/tex]
Donde todos los exponentes de x son numeros naturales.
Particularmente, la componente "cubica" será aquella que tenga un exponente igual a 3.
Entonces, por ejemplo, en:
[tex]p(x) = 4*x^5 + 2*x^4 + 5*x^3[/tex]
La parte cubica será:
[tex]5*x^3[/tex]
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Under her cell phone plan, Sarah pays a flat cost of $69 per month and $4 per gigabyte. She wants to keep her bill at $83.80 per month. Write and solve an equation that can be used to determine g, the number of gigabytes of data Sarah can use while staying within her budget.
Answer:
83.80 = 69 + 4x
x = 3.7
Sarah can use up to 3.7 gigabytes per month to stay within her budget
Step-by-step explanation:
83.80 = 69 + 4x
14.8 = 4x
x = 3.7
The number of gigabytes of data Sarah can use while staying within her budget is 3.7 gigabyte.
Given that, Sarah pays a flat cost of $69 per month and $4 per gigabyte.
What is an equation?In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
Let the number of gigabyte be g.
69+4g=83.80
The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.
Now, 4g=83.80-69
⇒ 4g=14.8
⇒ g=14.8/4
⇒ g=3.7 gigabyte
Therefore, the number of gigabytes of data Sarah can use while staying within her budget is 3.7 gigabyte.
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what is the square root of 36/196
√36/169
Answer:
The square root of 36/196 is 3/7.
The square root of 36/169 is 6/13.
!!! TIME SENSITIVE !!! Determine the period.
Answer:
A wave period is the measure of the time it takes for the wave cycle to complete.
The period of the wave is 2 seconds.
Identify the method that will be used to solve for x for each equation.
4x = 20
x 119
5x + 6x = 22
5(x - 2) = 30
The solution of the equation 4x = 20, x – 11 = 9, 5x + 6x = 22, and 5(x – 2) = 30 will be 5, 20, 2, and 8.
What is the solution of the equation?The solution of the equation means the value of the unknown or variable.
The equations are given below.
4x = 20
x = 5
x – 11 = 9
x = 20
5x + 6x = 22
11x = 22
x = 2
5(x – 2) = 30
x – 2 = 6
x = 8
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Convert 203 yards into meters.
Hint: 1 yard=0.91 meters
203 yards=[blank]−−−−−− meters
Enter your answer as a number that correctly fills in the blank.
Round the answer to two decimal places, like this: 45.53
Answer:
184.73
Step-by-step explanation:
1 yard = 0.91m
203 yard=?
(203x0.91)/1=184.73.
+1(415) 450-6164
Based on an architectural drawing, a roof slopes to a drain along the function represented in the table that defines the edge of slope, where x is the horizontal distance in feet and f(x) is the vertical distance in feet.
If the drain is at the minimum point, how far is it from the wall defined by the y-axis?
0 feet
8 feet
80 feet
160 feet
The distance from the wall defined by the y-axis will be 8 feet. Then the correct option is B.
What is the equation of line?The equation of line is given as
y = mx + c
Where m is the slope and c is the y-intercept.
The table is given below.
Then the equation of the line will be
(y – 8) = [(8 – 6) / (0 – 20)](x – 0)
y = -0.1x + 8
If the drain is at the minimum point.
Then the distance from the wall defined by the y-axis will be 8 feet.
Then the correct option is B.
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Which set of graphs can be used to find the solution set to 3e* > >-x?m
The green-colored area of the graph attached below shows the solution set to 3eˣ>(-1/2)x.
Inequality is the relationship between two expressions showing the relationships like greater than, lesser than, lesser than equals to, and greater than equals to.
Here assume f is a function which is given by f(x)=3eˣ
and g be another function which is given by g(x)= (-1/2)x
Here we have to find the solution graph showing the relationship
f(x) > g(x)
Let at point (a,b) the f(x) and g(x) meet each other.
After that intersection point, g(x) will decrease as g(x) is a decreasing function. and f(x) will increase.
So in the solution set will contain the area where g(x) is larger than f(x).
Therefore the solution graph of this inequality is the green-colored area as shown below,
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a list of 8 numbers has a mean of 6. work out the total of the numbers.
Answer:
48
Step-by-step explanation:
The mean of a number is the sum of all the numbers divided by how many numbers there are. We can set up this formula: [tex]mean = \frac{sum}{amountnumbers}[/tex].
When we plug our values into this equation, we get: [tex]6 = \frac{sum}{8}[/tex]. Solving this equation gets us sum = 6 * 8 = 48
18 A student has 273 matchsticks with which to make a pattern of nested triangles. Fig. 18.9 shows the first three triangles. Fig. 18.9 If all the matchsticks are used, how many matchsticks will each side of the biggest triangle contain? 18 A student has 273 matchsticks with which to make a pattern of nested triangles . Fig . 18.9 shows the first three triangles . Fig . 18.9 If all the matchsticks are used , how many matchsticks will each side of the biggest triangle contain ?
The number of matchsticks that each side of the biggest triangle contains is; 137 matchsticks
How to find the biggest side of a triangle?We know that for a diagram to be a triangle, then two smallest sides must not be greater than the third side.
Now, if there are 273 matchsticks, then the greatest side of the triangle must not be less than 273/2 = 136.5 ≈ 137
Thus, the largest side will have at least 137 matchsticks
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Given the image below DY EY FY are perpendicular bisectors of triangle ABC
The value of FY in the triangle will be 30.11
How to calculate the value?From the information given, the value of BE will be:
= [tex]\sqrt{64.2}[/tex]² - [tex]\sqrt{51.2}[/tex]²
= 38.7
From the triangle, DY will be
= [tex]\sqrt{64.22}[/tex]² - [tex]\sqrt{61.7}[/tex]²
= 17.7
AY will be:
= [tex]\sqrt{61.7}[/tex]² + [tex]\sqrt{17.7}[/tex]²
= 64.2
FY will now be:
= [tex]\sqrt{64.2 - 56.7}[/tex]²
= 30.11
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Find x and y.
help please ty:)
Please, make sure you understand the solution:
We can notice that x + (x - 28) = 90
2x - 28 = 90
2x = 118
x = 59
Now for y:
We can notice that y + 90 + x = 180
y + 90 + 59 = 180
y + 149 = 180
y = 180 - 149
y = 31
decrease 2155.45 by 18.5 round 2dp
The solution is 1756.69
What is number system?A number system is defined as a system of writing to express numbers. It is the mathematical notation for representing numbers of a given set by using digits or other symbols in a consistent manner.
We have to find the 18.5% of 2155.45.
So,
2155.45 * 0.185 = 398.75825
Now, subtract
21.55.45 - 398.75825
= 1756.69175
Hence, the value is 1756.69
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find the arc length of a sector with a radius of 4 feet and a central angle of 6°
Answer:
24 ft.
Step-by-step explanation:
Radius = 4 ft
Central angle = 6°
Arc length = radius × central angle
= 4 × 6°
= 24 ft.
Point A is located at (−2, 2), and point M is located at (1, 0). If point M is the midpoint of segment AB, find the location of point B.
(−0.5, 1)
(4, −2)
(−5, 4)
(−1, 1)
Answer:
B. (4, -2)
Step-by-step explanation:
Please see attachment.
Hope this helps!
If not, I am sorry.
What are the zeros of this function?
My square patio is tiled with square tiles, all the same size. All the tiles are gray, except the tiles along the two diagonals, which are all yellow. (The corners are yellow, the center is yellow, and all the tiles along the diagonal in between are yellow.) If there are $89$ yellow tiles, how many gray tiles are there
Answer:
1936
Step-by-step explanation:
We can start by removing the center tile, because all four diagonals over lap on that tile. We'll add it back later. 88/4=22. which means there are 22 tiles per half, 44+1(the center tile) total tiles per side, which means there are a total of 1936 tiles.
AOPS ANSWER:
Suppose that we have a square with dimensions [tex]$e \times e$[/tex]. The diagonals each have [tex]$e$\\[/tex] tiles. If [tex]$e$\\[/tex] is even, the number of yellow tiles is [tex]$2e$[/tex], because the [tex]2[/tex] diagonals don't intersect. If [tex]$e$[/tex] is odd, then the number of yellow tiles is [tex]$e+e-1=2e-1$[/tex]. (We have to subtract [tex]1[/tex] because the center tile is counted [tex]2[/tex] times). We know that there are [tex]89[/tex] yellow tiles, which is an odd number, so [tex]$89=2e-1$[/tex]. This implies that [tex]$e = 45$[/tex]. So the dimensions of the floor are [tex]$45 \times 45$[/tex], or [tex]2025\\[/tex] square units. Since all of the other tiles are gray, there are [tex]$2025-89=\boxed{1936}$[/tex] gray tiles.
Work out (6 × 10²) ÷ (3 × 105)
Give your answer in standard form.
Answer: 40/21
Step-by-step explanation:
[tex]3 \times 105=315\\\\6 \times 10^{2}=600\\\\\implies \frac{6 \times 10^{2}}{3 \times 105}=\frac{600}{305}=\boxed{\frac{40}{21}}[/tex]
What must be the value of x so that lines a and b are parallel lines cut by transversal f? 10 20 22 32.
Answer: Option 3 or C. 22
Step-by-step explanation:
I got the answer correct on Edge 2022 quiz. Trust me the answer is correct I screenshot it using the prt sc key then uploaded it. The proof is in the pic below. :)
The graph below shows the solution to which system of inequalities?
OA. y> 2 and y≤ x
B. x> 2 and y≤ x
C. y≥ 2 and y< x
D. y≤ 2 and y< x
Answer:
C
Step-by-step explanation:
The horizontal line, y=2, is solid and shaded above, so it represents
[tex]y \geqslant 2[/tex]
The slanted line, y=x is dashed and shaded below, so it represents y<x.
What is another way to write
MP
Answer:
I am not completely sure if this is correct, but I believe the answer should be PM.
This is because the order of the letters that represents a point can be swapped, since they are still forming the same line.
Find the missing side of each triangle. Leave your answers in simplest radical form.
2√3 m
A) √ 19 m
c) √5 m
O a
a
Ob b
Oc
√7m
C
Od d
B) √17 m
D) √√2 m
Answer:
C [tex]\sqrt{5}[/tex]
Step-by-step explanation:
Use pythagorean theorem.
[tex]x^{2}[/tex] +[tex]\sqrt{7} ^{2}[/tex] = (2[tex]\sqrt{3}) ^{2}[/tex]
[tex]x^{2}[/tex] + 7 = 12 Subtract 7 from both sides
[tex]x^{2}[/tex] = 5 Take the square root of both sides to solve
x = [tex]\sqrt{5}[/tex]
What is the value of y in the equation 2(2y - 12) = 0?
04
06
07
08
Hey there!
2(2y - 12) = 0
2(2y) + 2(-12) = 0
4y - 24 = 0
ADD 24 to BOTH SIDES
4y - 24 + 24 = 0 + 24
SIMPLIFY IT!
4y = 0 + 24
4y = 24
4y/4 = 24/4
SIMPLIFY IT!
y = 24/4
y = 6
Therefore, your answer should be:
y = 06 (Option B.)
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Answer:
y=6 (06) should be your answer
Step-by-step explanation:
4y-24=0
After you simply the first equation in the parenthesis, you then move the 24 to the 0,
4y=24
The answer becomes positive 24 because when you move things across the equal sign you switch the sign
y=6
Then divide 24 by 4 to isolate y, which then gives you the answer 6.
Jamaal knows that it is certain that he will win the election because he is the only person who is running for class treasurer. which value represents the probability that he will win the election? 0 one-fourth three-fourths 1
The correct answer is option D which is the probability is 1.
The complete question is given below:-
Jamaal knows that it is certain that he will win the election because he is the only person who is running for class treasurer. Which value represents the probability that he will win the election?
0
1/4
3/4
1
What is probability?Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
The probability of Event E is given by,
P = favourable outcomes / Total outcomes
Jamaal is the only candidate running in the class treasurer election.
There for Total No. of outcomes = 1
Here Event E is Jamaal winning the Election.
So, No. of favorable outcome = 1
P(E) = 1 / 1
P(E) = 1
This type of event is called a SURE EVENT Because the probability of a sure event is always 1.
The Probability of Jamaal winning the election is 1. So, Option D is correct.
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The probability that he will win the election will be 1. Then the correct option is D.
What is probability?Its basic premise is that something will almost certainly happen. The percentage of favorable events to the total number of occurrences.
The value of the probability of an event will be varying from zero to one.
Jamaal knows that it is certain that he will win the election because he is the only person who is running for class treasurer.
Then the probability that he will win the election will be
If the event will certainly happen, then the probability will be one.
P = 1
Then the correct option is D.
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Select all numbers that are a solution of the inequality.
Every month a salesperson adds 7 new accounts. The algebraic expression that represents the number of new accounts that he will add in m months is _____.
The algebraic expression that represents the number of new accounts that he will add in m months is x ≥ 7m.
What is inequality?Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.
Every month, a salesperson adds 7 new accounts.
Let m be the number of the month and x be the number of the accounts.
Then the inequality equation will be
x ≥ 7m
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Which statement could be used to explain why f(x) = 2x – 3 has an inverse relation that is a function?
The graph of f(x) passes the vertical line test.
f(x) is a one-to-one function.
The graph of the inverse of f(x) passes the horizontal line test.
f(x) is not a function.
If g(x) is the inverse of f(x), what is the value of f(g(2))?
–6
–3
2
5
Answer:
1st q answer is f(x) is one- to -one function and 2nd q answer is 2
Answer:
1) f(x) is one - to - one function2) 2Step-by-step explanation:
inverse of f(x)Let f(x) = y
y = 2x - 3
x = y + 3 / 2
inverse of f(x) = x + 3 / 2
g(x) = inverse of f(x)f [g(2)]
f [2+3/2]
f [5/2]
(2×5/2)-3
5-3
= 2
Therefore f [g(2)] = 2which statements about square roots are true ?check all that apply
Two measures of two supplementary angles are in the ratio of 2.3 find the measurments of the two angles.
Answer:
The angles are 72° and 108°
Step-by-step explanation:
Supplementary angles add up to 180°
Ratio of supplementary angles = 2 : 3
The angles are 2x , 3x
2x + 3x = 180
5x = 180
x = 180 ÷ 5
x = 36°
2x = 2*36 = 72°
3x = 3*36 = 108°
Find the maxima and minima of the following function:
[tex]\displaystyle f(x) = \frac{x^2 - x - 2}{x^2 - 6x + 9}[/tex]
To find the maxima and minima of the function, we need to calculate the derivative of the function. Note, before the denominator is a perfect square trinomial, so the function can be simplified as
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f(x) = \frac{x^2 - x - 2}{(x - 3)^2}} \end{gathered}$}[/tex]
So the derivative is:
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f'(x) = \frac{(2x - 1)(x - 3)^2 - 2(x - 3)(x^2 - x - 2)}{(x - 3)^4} } \end{gathered}$}[/tex]
Simplifying the numerator, we get:
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f'(x) = \frac{(x - 3)(-5x + 7)}{(x - 3)^4} = \frac{-5x + 7}{(x - 3)^3} } \end{gathered}$}[/tex]
The function will have a maximum or minimum when f'(x) = 0, that is,
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f'(x) = \frac{-5x + 7}{(x - 3)^3} = 0 } \end{gathered}$}[/tex]
which is true if -5x + 7 = 0. Then x = 7/5.
To determine whether x = 7/5 is a maximum, we can use the second derivative test or the first derivative test. In this case, it is easier to use the first derivative test to avoid calculating the second derivative. For this, we evaluate f'(x) at a point to the left of x = 7/5 and at a point to the right of it (as long as it is not greater than 3). Since 1 is to the left of 7/5, we evaluate:
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f(1) = \frac{-5 + 7}{(1 - 3)^3} = \frac{2}{-8} < 0} \end{gathered}$}[/tex]
Likewise, since 2 is to the right of 7/5, then we evaluate:
[tex]\large\displaystyle\text{$\begin{gathered}\sf \displaystyle \bf{\frac{-10 + 7}{(2 - 3)^3} = \frac{-3}{-1} > 0} \end{gathered}$}[/tex]
Note that to the left of 7/5 the derivative is negative (the function decreases) and to the right of 7/5 the derivative is positive (the function increases).
The value of f(x) at 7/5 is:
[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle f\left(\tfrac{7}{5}\right) = \frac{\tfrac{49}{25} - \tfrac{7}{5} - 2}{\tfrac{49}{25} - 6 \cdot \tfrac{7}{5} + 9} = -\frac{9}{16} } \end{gathered}$}[/tex]
This means that [tex]\bf{\left( \frac{7}{5}, -\frac{9}{16} \right)}[/tex] is a minimum (and the only extreme value of f(x)).
[tex]\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]
Answer:
[tex]\text{Minimum at }\left(\dfrac{7}{5},-\dfrac{9}{16}\right)[/tex]
Step-by-step explanation:
The local maximum and minimum points of a function are stationary points (turning points). Stationary points occur when the gradient of the function is zero. Differentiation is an algebraic process that finds the gradient of a curve.
To find the stationary points of a function:
Differentiate f(x)Set f'(x) = 0Solve f'(x) = 0 to find the x-valuesPut the x-values back into the original equation to find the y-values.[tex]\boxed{\begin{minipage}{5.5 cm}\underline{Quotient Rule for Differentiation}\\\\If $y=\dfrac{u}{v}$ then:\\\\$\dfrac{\text{d}y}{\text{d}x}=\dfrac{v \dfrac{\text{d}u}{\text{d}x}-u\dfrac{\text{d}v}{\text{d}x}}{v^2}$\\\end{minipage}}[/tex]
[tex]\text{Given function}: \quad \text{f}(x)=\dfrac{x^2-x-2}{x^2-6x+9}[/tex]
Differentiate the function using the Quotient Rule:
[tex]\text{Let }u=x^2-x-2 \implies \dfrac{\text{d}u}{\text{d}x}=2x-1[/tex]
[tex]\text{Let }v=x^2-6x+9 \implies \dfrac{\text{d}v}{\text{d}x}=2x-6[/tex]
[tex]\begin{aligned}\implies \dfrac{\text{d}y}{\text{d}x} & =\dfrac{(x^2-6x+9)(2x-1)-(x^2-x-2)(2x-6)}{(x^2-6x+9)^2}\\\\& =\dfrac{(2x^3-13x^2+24x-9)-(2x^3-8x^2+2x+12)}{(x^2-6x+9)^2}\\\\\implies \text{f}\:'(x)& =\dfrac{-5x^2+22x-21}{(x^2-6x+9)^2}\\\\\end{aligned}[/tex]
Set the differentiated function to zero and solve for x:
[tex]\begin{aligned}\implies \text{f}\:'(x)& =0\\\\\implies \dfrac{-5x^2+22x-21}{(x^2-6x+9)^2} & = 0\\\\-5x^2+22x-21 & = 0\\\\-(5x-7)(x-3) & = 0\\\\\implies 5x-7 & = 0 \implies x=\dfrac{7}{5}\\\\\implies x-3 & = 0 \implies x=3\end{aligned}[/tex]
Put the x-values back into the original equation to find the y-values:
[tex]\implies \text{f}\left(\frac{7}{5}\right)=\dfrac{\left(\frac{7}{5}\right)^2-\left(\frac{7}{5}\right)-2}{\left(\frac{7}{5}\right)^2-6\left(\frac{7}{5}\right)+9}=-\dfrac{9}{16}[/tex]
[tex]\implies \text{f}(3)=\dfrac{\left(3\right)^2-\left(3\right)-2}{\left(3\right)^2-6\left(3\right)+9}=\dfrac{4}{0} \implies \text{unde}\text{fined}[/tex]
Therefore, there is a stationary point at:
[tex]\left(\dfrac{7}{5},-\dfrac{9}{16}\right)\:\text{only}[/tex]
To determine if it's a minimum or a maximum, find the second derivative of the function then input the x-value of the stationary point.
If f''(x) > 0 then its a minimum.If f''(x) < 0 then its a maximum.Differentiate f'(x) using the Quotient Rule:
Simplify f'(x) before differentiating:
[tex]\begin{aligned}\text{f}\:'(x) & =\dfrac{-5x^2+22x-21}{(x^2-6x+9)^2}\\\\& = \dfrac{-(5x-7)(x-3)}{\left((x-3)^2\right)^2}\\\\& = \dfrac{-(5x-7)(x-3)}{(x-3)^4}\\\\& = -\dfrac{(5x-7)}{(x-3)^3}\\\\\end{aligned}[/tex]
[tex]\text{Let }u=-(5x-7) \implies \dfrac{\text{d}u}{\text{d}x}=-5[/tex]
[tex]\text{Let }v=(x-3)^3 \implies \dfrac{\text{d}v}{\text{d}x}=3(x-3)^2[/tex]
[tex]\begin{aligned}\implies \dfrac{\text{d}^2y}{\text{d}x^2} & =\dfrac{-5(x-3)^3+3(5x-7)(x-3)^2}{(x-3)^6}\\\\& =\dfrac{-5(x-3)+3(5x-7)}{(x-3)^4}\\\\\implies \text{f}\:''(x)& =\dfrac{10x-6}{(x-3)^4}\end{aligned}[/tex]
Therefore:
[tex]\text{f}\:''\left(\dfrac{7}{5}\right)=\dfrac{625}{512} > 0 \implies \text{minimum}[/tex]
please please help ME!!!
Answer:
720 Course Schedules
Step-by-step explanation:
When you choose the first course, there are 6 to choose from. When you scoose the second, there are only 5. This keeps going until the 6th course where there is only 1 choice.
You multiply these choices together. You should get 6×5×4×3×2×1
6×5=30
30×4=120
120×3=360
360×2=720
720×1=720
You then end up with 720 course schedules.
What is the solution to the system of equation
Answer:
[tex]x=(-2,\frac{5}{3} )[/tex]
Step-by-step explanation:
1) We will use the matrix method to solve this problem.
[tex]\left[\begin{array}{ccc}-2/3&1&3\\1&0&-2\\\end{array}\right][/tex]
2) Swap Row₁ and Row₂ to make row reduction easier.
[tex]\left[\begin{array}{ccc}1&0&-2\\-2/3&1&3\\\end{array}\right][/tex]
3) Apply to Row₂ : Row₂ + [tex]\frac{2}{3}[/tex] Row₁.
[tex]\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\end{array}\right][/tex]
4) Simplify rows.
[tex]\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\\\end{array}\right][/tex]
Note: The matrix is now in row echelon form.
The steps below are for back substitution.
5) Apply Row₁ : Row₁ - 0 Row₂.
[tex]\left[\begin{array}{ccc}1&0&-2\0\\0&1&5/3\end{array}\right][/tex]
6) Simplify rows.
[tex]\left[\begin{array}{ccc}1&0&-2\\0&1&5/3\\\end{array}\right][/tex]
Note: The matrix is now in reduced row echelon form.
7) Therefore,
[tex]x=-2\\x=\frac{5}{3}[/tex]