Glucose, C₂H12O6, is a product of photosynthesis.
It has the following structure.
HICIO
HICIOH
HOIC-H
HICIOH
HICIOH
HICIOH
I
H
How many chiral centres does the molecule have?
A 1
B2
C 4
D 6

Answers

Answer 1

Answer:

C

Explanation:

four chiral centers


Related Questions

Acid rain is caused by which of the following?
excess carbon dioxide
deforestation
nitrogen compounds in the soil
nitrogen compounds in the air

Answers

Answer:

nitrogen compounds in the air

Explanation:

NH4Cl + AgNO3 → AgCl + NH4NO3

Answers

A N S W E R :

It's a balanced equation!This is a precipitation reaction.AgCl is the formed precipitate.

What are the blue and yellow circles, the red circles, and the darkest blue ?

Answers

Answer:

The Red Circles: Liquid, Blue and Yellow Circles: Solid, and Purple Circles: Gas

Explanation:

Should be it based on the picture and given information.

A balloon inflated in a room at 240C
has a volume of 4.00L. The balloon is then
heated to a temperature of 580C. What is
the new volume

Answers

Answer:

4.458 L

Explanation:

Assuming the pressure remains constant  and assuming 24° C and 58° C

V1/T1  = V2/T2       Where T is in Kelvin

V1/T1  *  T2  = V2

4 / ( 273.15 +24)    *    ( 273.15 + 58)    =  4.458 L

(06.06 MC)

How does extreme pressure affect the volume occupied by a real gas compared to the predictions of the ideal gas law? (3 points)

The true volume of the gas will be higher than predicted by the ideal gas law because the volume of the actual particles is more significant under high pressure.

The true volume of the gas will be higher than predicted by the ideal gas law because the attraction between the particles is weaker under high pressure.

The true volume of the gas will be lower than predicted by the ideal gas law because the volume of the actual particles is more significant under high pressure.

The true volume of the gas will be lower than predicted by the ideal gas law because the attraction between the particles is weaker under high pressure.

Answers

Answer: The true volume of the gas will be lower than predicted by the ideal gas law because the volume of the actual particles is more significant under high pressure.

Coffe is a solution of organic substance in water

Answers

Answer:

Verdadero!
no se en que mas quieres que te ayude? o cual realmente quieres que sea la respuesta?

Calculate the theoretical yield in , grams AlI₃, aluminum iodide, from the complete reaction of 113 grams I₂ according to the following balanced chemical equation: 2Al(s) + 3I₂(s) → 2AlI₃(s)

Answers

121 g [tex]AlI_{3}[/tex] aluminum iodide, from the complete reaction of 113 grams I₂ according to the following balanced chemical equation:

2Al(s) + 3I₂(s) → 2[tex]AlI_{3}[/tex]

As per the given balanced equation,

3 moles of [tex]I_{2}[/tex] are used to give 2 moles of [tex]AlI_{3}[/tex].

Atomic weight of iodine is 127 gm/ mole

So, molecular weight of iodine molecule = 254 gm/ mole

There for , we can say that 1 mole o iodine molecule contain 254 g

So ,Given 113 gm iodine contains how many moles?

  Moles of iodine = 113/254 = 0.44 moles

from the equation we can say that 3 moles of iodine used to give 2 moles of aluminum iodide.

So, 0.44 moles of iodine gives how many moles of aluminum iodide ?

   Moles of aluminum iodide = 0.44 × 2 ÷  3

                                             = 0.2965 moles

Molecular weight of one mole of aluminum iodide = atomic weight of Al + 3( atomic weight of iodine )

      = 408 gm

∴ 1 mole of aluminum iodide = 408 gm

so, 0.2965 moles of aluminum iodide = ?

            = 0.2964 × 408

            = 121 gm  Aluminum iodide formed.

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What is the pH of 0.0025M H2SO4

Answers

Answer:

pH=2.3

Explanation:

One H2SO4 molecule produce two H+ ions.

So conc. of H+ = 2(0.0025)

=0.005

Now, pH=-log (conc. of H+)

=-log(0.005)

=2.3

How does temperature affect Keq of a reaction

Answers

In an endothermic reaction, Keq increases as the temperature increases and vice versa.

In an exothermic reaction, Keq decreases as the temperature increases and vice versa.

Keq is the equilibrium constant of a reaction. The equilibrium constant is independent of the concentrations of the reactants and productsThe only factor that the equilibrium constant depends on is the temperature of the system of reactionIn an endothermic reaction, energy is gainedSo a higher temperature is more favourable in an endothermic reactionAs a result, more products are formed at a higher temperature, leading to a higher value of KeqIn an exothermic reaction, energy is releasedSo a lower temperature is more favourable in an exothermic reactionAs a result, fewer products are formed at a higher temperature, leading to a lower value of Keq

Therefore, the temperature is the only factor that affects the equilibrium constant of a reaction.

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Fill in the coefficients that will balance the following reaction:

(Note: Use 1 as coefficient where appropriate)

Fe(HCO3)3 + CaO → Fe2O3 + Ca(HCO3)2

Answers

Answer:

2 Fe(HCO₃)₃ + 3 CaO ---> 1 Fe₂O₃ + 3 Ca(HCO₃)₂

Explanation:

The unbalanced equation:

Fe(HCO₃)₃ + CaO ---> Fe₂O₃ + Ca(HCO₃)₂

Reactants: 1 iron, 3 hydrogen, 3 carbon, 10 oxygen, 1 calcium

Products: 2 iron, 2 hydrogen, 2 carbon, 9 oxygen, 1 calcium

As you can see, the reaction is clearly unbalanced because the number of each element on both sides is different. The best way to go about balancing an equation is by trying to first balance an element located in only one molecule on either side. For example, I started trying to balance  iron. After balancing iron, I looked to balance other elements that would have been affected by the new coefficient (i.e., hydrogen, carbon).

The balanced equation:

2 Fe(HCO₃)₃ + 3 CaO ---> 1 Fe₂O₃ + 3 Ca(HCO₃)₂

Reactants: 2 iron, 6 hydrogen, 6 carbon, 21 oxygen, 3 calcium

Products: 2 iron, 6 hydrogen, 6 carbon, 21 oxygen, 3 calcium

Now, with these coefficients, the quantity of each element on both sides is the same.

Why is there a delay for the tides to react to the Moon's and Sun's gravitational effect?
A. Gravity is one of the slower forces in nature having to travel great distances.
B. The gravitational forces must overcome inertia and friction for the tides to take effect on water.
C. Water is relatively immune to the force of gravity delaying the tidal process.
D. There is no delay because the effects of gravity is constantly acting on bodies of water.

Answers

There is no delay because the effects of gravity are constantly acting on bodies of water. Hence, option D is correct.

What is the gravitational effect?

Gravitation or just gravity is the force of attraction between any two bodies.

The Moon exerts over twice the gravitational pull of the Sun on Earth's tides because of its proximity to Earth. -The lunar tidal bulges are about twice the size of the solar tidal bulges. -The Sun's contribution to the tides is less than that of the Moon.

When the sun and moon are perfectly unaligned (they form a 90-degree angle relative to the earth), there are still tides because the moon's gravitational gradient is stronger than the sun's. The sun's gravitational gradient never completely cancels out the moon's.

Hence, option D is correct.

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The pKb value for aqueous ammonia at 25


is 4.8.


What is the correct pKa value for the ammonium ion at this temperature? (Kb denotes the base dissociation constant and Ka denotes the acid dissociation constant.)

Answers

The value of pka for [tex]NH_3[/tex] in an aqueous solution is 9.2.

What is Kb?

Kb denotes the base dissociation constant.

pKa + pKb =14  at 25 degree celcius.

pKa + 4.8 =14

pKa = 9.2

pKb is the negative base-10 logarithm of the base dissociation constant (Kb) of a solution.

It is used to determine the strength of a base or alkaline solution.

The value of pka for [tex]NH_3[/tex] in an aqueous solution is 9.2.

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please help with this answe i do not how to to do it it

Answers

Answer:

1.20 M (3 s.f.)

Explanation:

In this question, we are trying to find the concentration of KCl after dilution. Note that the number of moles of KCl does not change.

[tex]g \div \frac{g}{mol} = g \times \frac{mol}{g} = mol[/tex]

Number of moles of KCl

= 44.7 ÷74.55

= 0.59960 mol (5 s.f.)

New volume

= 500 mL

= (500 ÷1000) L

= 0.5 L

Concentration after dilution

= 0.59960 ÷0.5

= 1.1992 mol/L

= 1.20 M (3 s.f.)

* M is the symbol for Molarity, which is also equal to mol/L

Hybridization of bromine in SF4 and arsenic in SF2

Answers

Answer:

The answer is C

Which reaction is endothermic

Answers

Answer:

Option 3

Explanation:

Heat is absorbed, so the reaction is endothermic.

- How many grams are in 1.4 x 10¹5 atoms of calcium?

Answers

Answer:

40 g= 6.022×10²³

x=1.4×10¹⁵

x=40g×6.022×10²³/1.4×10¹⁵

x=17.77×10⁸


A substance decomposes with a rate
constant of 9.05 x 10-4 s¹. How long does
it take for 15.0% of the substance to
decompose?

Answers

Answer:

The time required to decompose the substance is 360 seconds.

What net force is required to cause a 12,000 kg airplane to accelerate at a rate of 5.2 m/s

Answers

The answer is 624000N

Which of the following best describes a neutralization reaction?

Answers

Answer:

A

The H+ from acid and OH- from base forms water, the other parts form the salt.

6. Give the balanced full reaction and calculate the E° for galvanic cells based on the
following reactions. Draw diagrams indicating; the anode, cathode, flow of electrons,
salt bridge
(a) Zn^2 (aq) + 2e- = Zn(s)
Pb²(aq) + 2e- → Pb(s)
(b) Cr2O7 + 14H + 6e- 2Cr³+ 7H₂O
H₂O2 + 2H+ + 2e- →2H₂O

Answers

Electrochemical cell is one in which energy is released by a chemical action.

What is an electrochemical cell?

An electrochemical cell is one in which energy is released by a chemical action.

Now we have the reaction;

Zn^2 (aq) + 2e- = Zn(s)

Pb²(aq) + 2e- → Pb(s)

and

Cr2O7 + 14H + 6e- 2Cr³+ 7H₂O

H₂O2 + 2H+ + 2e- →2H₂O

In the first case, the Ecell is obtained from;

(-0.13 V) - (-0.76 V)

= 0.63 V

In the second case;

1.78 V - 1.33 V

= 0.45 V

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What are the noble gas configurations for
-Li
-Na
-K

Answers

The noble gas configurations for

Li= [He] 2s¹, Na=[Ne] 3s¹ and K =[Ar] 4s¹.

Noble gas configurations are the term for the electronic configurations of the atoms for which the electronic configuration becomes very larger i.e, for the higher atomic numbers.

For the noble gas electronic configurations, the noble gas, which is before that atom is written.

So, the Lithium can be represented as [He] 2s¹.

So, the Sodium can be represented as [Ne] 3s¹.

So, the Potassium can be represented as [Ar] 4s¹.

Hence, the noble gas configurations for Lithium= [He] 2s¹, Sodium=[Ne] 3s¹ and potassium =[Ar] 4s¹.

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Part E
From the observations of the simulation, which strategy was most effective for quickly and efficiently producing ammonia? Why do you think this strategy is most effective?

Answers

The production of ammonia will be favored at high pressure and low temperature.

What is an exothermic reaction?

The term exothermic reaction has to do with a reaction in which the forward reaction is favored at lower temperatures.

Now looking at the reaction coordinate and the equation of the reaction, we know that the production of ammonia will be favored at high pressure and low temperature.

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How many grams of hydrogen gas are produced from 2.50 mol of water?
__Ca(s) + __H2O(l) → __Ca(OH)2(aq) + __H2(g)

Answers

Answer:

2.52 g H₂

Explanation:

To find the mass of hydrogen gas, you need to (1) convert moles H₂O to moles H₂ (via mole-to-mole ratio from reaction coefficient) and then (2) convert moles H₂ to grams H₂ (via molar mass from periodic table values). When multiplying the given value by the mole-to-mole ratio, you need to use the coefficients of the balanced equation. An reaction is balanced once there is an equal amount of each element on both sides.

(Step 1)

The unbalanced equation:

Ca(s) + H₂O(l) ----> Ca(OH)₂(aq) + H₂(g)

Reactants: 1 calcium, 2 hydrogen, 1 oxygen

Products: 1 calcium, 4 hydrogen, 2 oxygen

The balanced equation:

1 Ca(s) + 2 H₂O(l) ----> 1 Ca(OH)₂(aq) + 1 H₂(g)

Reactants: 1 calcium, 4 hydrogen, 2 oxygen

Products: 1 calcium, 4 hydrogen, 2 oxygen

(Step 2)

Molar Mass (H₂): 2(1.008 g/mol)

Molar Mass (H₂): 2.016 g/mol

(Step 3)

 2.50 moles H₂O              1 mole H₂                  2.016 g
---------------------------  x  -------------------------  x  ----------------------  =  2.52 g H₂
                                        2 moles H₂O                1 mole

Question 9 of 10
What is an open system?
OA. A system that allows energy to move in and out but not mass
B. A system that allows energy and mass to move in and out of it
XA

Answers

Answer:

The answer is B an open system allows energy and mass to move in and out of it

Hope it helps

Chemistry: Please make sure to answer each question. Thank you in advance.


Create a diagram of your electroplating apparatus (an electrolytic cell). Then submit your drawing with the following terms labeled correctly. Or, beginning with the positive terminal of the battery and ending with the negative terminal of the battery, describe the path that the electricity takes and where each of the following occurs:

anode
cathode
copper strip
battery
positive terminal
negative terminal
place where oxidation occurs
place where reduction occurs
electrolyte solution
coin (or nail)
direction of electron flow

Answer:

(Score for Question 2: ___ of 7 points)

Describe the results of your procedure with the coin.

Answer:

(Score for Question 1: ___ of 6 points)

Write the two half-reactions that occur in this electroplating process. Be sure to include the states of the elements or ions.

Answer:

Answers

The electroplating process of the coin results in the coating of the coin with copper metal.

What is electroplating?

Electroplating is the process of using coating the surface of a metal with another one electrolytic cell.

The electroplating of the coin is done using copper as the anode and the coin as the cathode. The electrolyte is copper sulfate solution.

Oxidation occurs at the anode with the copper metal being converted to copper (ii) ions.

Reduction occurred at the cathode as the copper (ii) ions in the solution accept electrons to become copper metal and the coin being coated with copper.

The half-reactions are shown below:

At the anode:

[tex]Cu(s) \rightarrow Cu^{2+}(aq) + 2e^{-}[/tex]

At the cathode:

[tex]Cu^{2+}(aq) + 2e{-} \rightarrow Cu(s)[/tex]

Therefore, the electroplating process of the coin results in the coating of the coin with copper metal.

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Question 3:

The force of gravity between a planet and its moon is 371 N. If the planet has a mass of 4 x 1022 kg and the moon has a mass of 5 x 105 kg, what is the distance between their centers?

Answers

Answer:

=6×10^7metre

Explanation:

By using formula,

F=GMm/d^2

When 50.0 g iron(III) oxide reacts with carbon monoxide, 32.5 g iron is produced. What is the percent yield of the reaction?
Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)

Answers

Answer:

92.9%

Explanation:

You have been given the actual yield of the reaction. First, you need to find the theoretical yield of the reaction. To do this, you need to (1) convert grams Fe₂O₃ to moles Fe₂O₃ (via molar mass from periodic table values), then (2) convert moles Fe₂O₃ to moles Fe (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe to grams Fe (via molar mass).

Once you have found the theoretical yield, you need to use the percent yield equation to calculate the final answer. This number should have 3 sig figs to match the given values.

(Step 1)

Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)

Molar Mass (FeO₃): 159.684 g/mol

1 Fe₂O₃(s) + 3 CO(g) ---> 2 Fe(s) + 3 CO₂(g)


Molar Mass (Fe):
55.845 g/mol

50.0 g Fe₂O₃           1 mole              2 moles Fe           55.845 g
--------------------  x  ------------------  x  ---------------------  x  ----------------  = 35.0 g Fe
                               159.684 g         1 mole Fe₂O₃          1 mole

(Step 2)

                                 Actual Yield
Percent Yield  =  ---------------------------  x  100%
                             Theoretical Yield

                                32.5 g Fe
Percent Yield  =  ----------------------  x  100%  =  92.9%
                                35.0 g Fe

Preparation of ammonia gas

Answers

Answer:

Ammonia is easily made in the laboratory by heating an ammonium salt, such as ammonium chloride NH4Cl with a strong alkali, such as sodium hydroxide or calcium hydroxide.

The gas may also be made by warming concentrated ammonium hydroxide.

Explanation:

2NH4Cl + Ca(OH)2 → CaCl2 + 2H2O + 2NH3(g)

Select only one most suitable description

Answers

I believe it's a pure element

In what way does ocean water move globally?
A. Along warm-water currents from warmer regions to colder regions
B. Along cold-water currents from the equator to the Poles
C. Along cold-water currents from warmer regions to colder regions
D. Along longshore currents from the equator to the Poles.

Answers

Answer:

A. Along warm-water currents from warmer regions to colder regions

\

Explanation:

A because I did it already
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