Charles Montesquieu believed that the
Legislative Branch should do what?
A. Make laws
B. Enforce laws
C. Interpret laws
elles sone. All Rights Resed.​

Answer:

33600

Explanation:

Let M = ABE16

and N = DF416

In hexadecimal representation: 10 = A, 11 = B, 12 = C, 13 = D, 14 = E, 15 = F

Step 1: Find the 15's complement of N

 F  F  F  F  F

- D  F  4  1  6

2  0  B  E  9

Step 2: Add 15's complement of N to M

  A  B  E  1  6

+ 2  0  B  E  9  

  C  C  9  F  F

Step 3: Find the 15's complement of CC9FF

 F  F   F  F  F

- C  C  9  F  F

 3   3  6  0  0

Therefore, ABE16 - DF416 using 15's complement is 33600

Answer:

When you sign into a website, you have to enter a password and username most of the time, which will allow the website to know that you have checked in and it is you, who is using your account.

Answer:

B

Explanation:

all url's begin with https://

Answer:

The following assumption will be made for this assignment;

The program is written in Java and it uses comments to explain difficult lines. The program is as follows

import java.util.*;

public class Tests

{

public static void main(String [] args)

{

 //Declare variables

 Scanner input = new Scanner(System.in);

 String firstname, lastname;

 //Prompt user for name

 System.out.print("Enter Lastname: ");

 lastname = input.next();

 System.out.print("Enter Firstname: ");

 firstname = input.next();

 char grade;

 //Declare Array

 int[] Scores = new int[5];

 //Initialize total scores to 0

 int total = 0;  

  //Decalare Average

  double   average;

 //Prompt user for scores

 for(int i =0;i<5;i++)

 {

  System.out.print("Enter Score "+(i+1)+": ");

  Scores[i] = input.nextInt();

  //Calculate Total Scores

  total+=Scores[i];

 }

 //Calculate Average

 average = total/5.0;

 //Get Letter Grade

 if(average>75)

 {

 grade = 'A';

 }

 else if(average>65)

 {

 grade = 'B';

 }

 else if(average>55)

 {

 grade = 'C';

 }

 else if(average>45)

 {

 grade = 'D';

 }

 else if(average>40)

 {

 grade = 'E';

 }

 else

 {

 grade = 'F';

 }

 //Print Student Results

 System.out.print("Fullname: "+lastname+", "+firstname);

 System.out.print('\n');

 System.out.print("Total Scores: "+total);

 System.out.print('\n');

 System.out.print("Average Scores: "+average);

 System.out.print('\n');

 System.out.print("Grade: "+grade);

}

}

See Attachment for .java file

Answer:

a) tie the exception condition to a processing step

Explanation:

Numbering exception conditions, in a fully developed use case description is helpful to tie the exception condition to a processing step

The fully developed use case description is useful for the documentation of the context, purpose, description, conditions, and workflow of each use case. Activity diagrams give a graphical image of the use case workflow and serve the purpose of illustrating the alternative paths through a business process.

Answer:

This program is written using python

It uses less comments (See explanation section for more explanation)

Also, see attachments for proper view of the source code

Program starts here

#Prompt user for price of package 1

price1 = int(input("Enter Price 1: "))

while(price1 <= 0):

     price1 = int(input("Enter Price 1: "))

#Prompt user for weight of package 1

weight1 = int(input("Enter Weight 1: "))

while(weight1 <= 0):

     weight1 = int(input("Enter Weight 1: "))

#Calculate Unit of Package 1

unit1 = float(price1/weight1)

print("Unit cost of Package 1: "+str(unit1))

#Prompt user for price of package 2

price2 = int(input("Enter Price 2: "))

while(price2 <= 0):

     price2 = int(input("Enter Price 2: "))

#Prompt user for weight of package 2

weight2 = int(input("Enter Weight 2: "))

while(weight2 <= 0):

     weight2 = int(input("Enter Weight 2: "))

#Calculate Unit of Package 2

unit2 = float(price2/weight2)

print("Unit cost of Package 2: "+str(unit2))

#Compare units

if unit1 > unit2:

     print("Package 1 has a better price")

elif unit1 == unit2:

     print("Both Packages have the same price")

else:

     print("Package 2 has a better price")

Explanation:

price1 = int(input("Enter Price 1: ")) -> This line prompts the user for price of package 1

The following while statement is executed until user inputs a value greater than 1 for price

while(price1 <= 0):

     price1 = int(input("Enter Price 1: "))

weight1 = int(input("Enter Weight 1: ")) -> This line prompts the user for weight of package 1

The following while statement is executed until user inputs a value greater than 1 for weight

while(weight1 <= 0):

     weight1 = int(input("Enter Weight 1: "))

unit1 = float(price1/weight1) -> This line calculates the unit cost (per weight) of package 1

print("Unit cost of Package 1: "+str(unit1)) -> The unit cost of package 1 is printed using this print statement

price2 = int(input("Enter Price 2: ")) -> This line prompts the user for price of package 2

The following while statement is executed until user inputs a value greater than 1 for price

while(price2 <= 0):

     price2 = int(input("Enter Price 2: "))

weight2 = int(input("Enter Weight 2: ")) -> This line prompts the user for weight of package 2

The following while statement is executed until user inputs a value greater than 1 for weight

while(weight2 <= 0):

     weight2 = int(input("Enter Weight 2: "))

unit2 = float(price2/weight) -> This line calculates the unit cost (per weight) of package 2

print("Unit cost of Package 2: "+str(unit2)) -> The unit cost of package 2 is printed using this print statement

The following if statements compares and prints which package has a better unit cost

if unit1 > unit2:

     print("Package 1 has a better price")

elif unit1 == unit2:

     print("Both Packages have the same price")

else:

     print("Package 2 has a better price")

Answer:

A. 20 30

Explanation:

Given

Linked list: 10, 20, 30, 40, 50, 60

Required

The output of the following code segment

pCur = head->next;

cout << pCur->data << " ";

cout << pCur->next->data << endl;

A linked list operates by the use of nodes which begins from the head to the next node, to the next, till it reaches the last;

The first line of the code segment; "pCur = head->next; " shifts the node from the head to the next node

The head node is the node at index 0 and that is 10;

This means that the focus has been shifted to the next at index 1 and that is 20;

So, pCur = 20

The next line of the code segment; cout << pCur->data << " "; prints pCur and a blank space

i.e. "20 " [Take note of the blank space after 20]

The last line "cout << pCur->next->data << endl; " contains two instructions which are

1. pCur = next->data;

2. cout<<pCur->data;

(1) shifts focus to the next node after 20 ; This gives pCur = 30

(2) prints the value of pCur

Hence, the output of the code segment is 20 30

Answer:

Explanation:

The objective of this question and what we are meant to do is to compute a short program in C++ that will display the information given in the question.

Let get started!.

C ++ Program Code.

#include <iostream>

#include<string>

using namespace std;

int main()

{

string name,email,hometown,highschool,previousColleges,mathOrCSCource,lastMathOrCSCource,CompType,ExtraCur,FavBook

,planAfterGrad,phone;

//Reading Data

cout<<"Name:";

getline(cin,name);

cout<<"Phone:";

getline(cin,phone);

cout<<"Email:";

getline(cin,email);

cout<<"HomeTown:";

getline(cin,hometown);

cout<<"High School(s):";

getline(cin,highschool);

cout<<"Previous Colleges:";

getline(cin,previousColleges);

cout<<"List of math/CS Cources:";

getline(cin,mathOrCSCource);

cout<<"When,Where and what was your last math or CS course:";

getline(cin,lastMathOrCSCource);

cout<<"Type(s) of computer you are confident working with:";

getline(cin,CompType);

cout<<"ExtraCurricular Activities (job,club,sports,etc.):";

getline(cin,ExtraCur);

cout<<"Favourite books,movies,music:";

getline(cin,FavBook);

cout<<"What you plan to do after Graduation:";

getline(cin,planAfterGrad);

//Printing data

cout<<"--------------------Printing Data---------------------------"<<endl;

cout<<"Name:"<<name<<endl;

cout<<"Phone:"<<phone<<endl;

cout<<"Email:"<<email<<endl;

cout<<"HomeTown:"<<hometown<<endl;

cout<<"High School(s):"<<highschool<<endl;

cout<<"Previous Colleges:"<<previousColleges<<endl;

cout<<"List of math/CS Cources:"<<mathOrCSCource<<endl;

cout<<"When,Where and what was your last math or CS course:"<<lastMathOrCSCource<<endl;

cout<<"Type(s) of computer you are confident working with:"<<CompType<<endl;

cout<<"ExtraCurricular Activities (job,club,sports,etc.):"<<ExtraCur<<endl;

cout<<"Favourite books,movies,music:"<<FavBook<<endl;

cout<<"What you plan to do after Graduation:"<<planAfterGrad<<endl;

return 0;

}

Answer:

yooooooooooooooooooooo

Explanation:

Answer:

=PMT(C6,C8,C4)

Put that in cell c9

Then use the lower right of the cell to drag it from D9:F9

In this exercise we have to use excel knowledge, so we have to:

=PMT(C6,C8,C4) in the cell C9 and extended to D9:F9

PMT, one of the financial functions, calculates the payment for a loan based on constant payments and a constant interest rate. Use the Excel Formula Coach to figure out a monthly loan payment.

For this we need to put the form as:

=PMT(C6,C8,C4)

See more about excel at brainly.com/question/12788694

Answer:

Explanation:

To begin, i will like to break this down to its simplest form to make this as simple as possible.

Let us begin !

Here statement can be translated as: ∃x (P(x) ∧ M(x))

we require the Negation: ¬∃x (P(x) ∧ M(x))

De morgan's law can be stated as:

1) ¬(a ∧ b) = (¬a ∨ ¬b)

2) ¬(a v b) = (¬a ∧ ¬b)

Also, quantifiers are swapped.

Applying De Morgan's law, we have: ∀x (¬P(x) ∨ ¬M(x)) (∃ i swapped with ∀ and intersecion is replaced with union.)

This is the translation of above

English: Every patient was either not given the placebo or did not have migrane(or both).

cheers i hope this helped !!

Answer:

Here is the Python program.

characters = 0

words = 0

lines = 0

def file_stats(in_file):

   global lines, words, characters

   with open(in_file, 'r') as file:

       for line in file:

           lines = lines + 1

           totalwords = line.split()

           words = words + len(totalwords)

           for word in totalwords:

               characters= characters + len(word)

file_stats('created_equal.txt')

print("Number of lines: {0}".format(lines))

print("Number of words: {0}".format(words))

print("Number of chars: {0}".format(characters))

Explanation:

The program first initializes three variables to 0 which are: words, lines and characters.

The method file_stats() takes in_file as a parameter. in_file is the name of the existing text file.

In this method the keyword global is used to read and modify the variables words, lines and characters inside the function.

open() function is used to open the file. It has two parameters: file name and mode 'r' which represents the mode of the file to be opened. Here 'r' means the file is to be opened in read mode.

For loop is used which moves through each line in the text file and counts the number of lines by incrementing the line variable by 1, each time it reads the line.

split() function is used to split the each line string into a list. This split is stored in totalwords.

Next statement words = words + len(totalwords)  is used to find the number of words in the text file. When the lines are split in to a list then the length of each split is found by the len() function and added to the words variable in order to find the number of words in the text file.

Next, in order to find the number of characters, for loop is used. The loop moves through each word in the list totalwords and split each word in the totalwords list using split() method. This makes a list of each character in every word of the text file. This calculates the number of characters in each word. Each word split is added to the character and stored in character variable.

file_stats('created_equal.txt')  statement calls the file_stats() method and passes a file name of the text file created_equal.txt as an argument to this method. The last three print() statements display the number of lines, words and characters in the created_equal.txt text file.

The program along with its output is attached.

Answer:

Output device

Explanation:

Im pretty sure that correct

Answer:

Please follow the code indentation for the python program.

Explanation:

Answer: Provided in the explanation section

Explanation:

import java.util.Scanner;

public class commission

{

   public static void main(String[] args) {

      Scanner input = new Scanner(System.in);

        int totals[]={0,0,0,0,0,0,0,0,0};          

      int n,sales,i,index;

       double salary;

        System.out.print("how many salesmen do you have? ");                          

      n=input.nextInt();

        for(i=1;i<=n;i++)

           {System.out.print("Salesman "+i+" enter sales: ");

            sales=input.nextInt();

            salary=200+(int)(.09*sales);

               System.out.printf("Salary=$%.2f\n",salary);

            index=(int)salary/100-2;

            if(index>8)

                index=8;

            totals[index]++;

            }

        System.out.println("SUMMARY\nSALES\t\tCOUNT");

        for(i=0;i<8;i++)

           System.out.println("$"+(i*100+200)+"-"+(i*100+299)+"\t"+totals[i]);

        System.out.println("$1000 and over\t"+totals[i]);

       }                                

   }

cheers i  hope this helped !!      

Answer:

Raid

Explanation:

Answer: Provided in the explanation section

Explanation:

The Question says;

Identify a logical operation (along

with a corresponding mask) that, when

applied to an input string of 8 bits,

produces an output string of all 0s if and

only if the input string is 10000001.​

The Answer (Explanation):

XOR, exclusive OR only gives 1 when both the bits are different.

So, if we want to have all 0s, and the for input only 10000001, then we have only one operation which satisfies this condition - XOR 10000001. AND

with 00000000 would also give 0,

but it would give 0 with all the inputs, not just 10000001.

Cheers i hope this helped !!

Explanation:

search engine because it helps to search find what you are expecting to search in the google.

Answer:

Given

The above lines of code

Required

Rearrange.

The code is re-arrange d as follows;.

#include<iostream>

int main()

{

int userNum;

scanf("%d", &userNum);

if (userNum > 0)

{

printf("Positive.\n");

}

else

{

printf("Non-positive, converting to 1.\n");

userNum = 1;

printf("Final: %d\n", userNum);

}

return 0;

}

When rearranging lines of codes. one has to be mindful of the programming language, the syntax of the language and control structures in the code;

One should take note of the variable declarations and usage

See attachment for .cpp file

Answer:

Following are the algorithm to this question:

Find_Heavier_Coins(Coin[9]):

   i) Let Coin[] Array represent all Coins.  

   ii) Divide coin[] into 3 parallel bundles and each has three coins, example 0-2, 3-5, 6-8 indicate a1 a2 a3

   iii) Randomly select any two bundles and place them in balance [say a1 and a2]

   iv) If Weigh of a1 and a2 has same:

           // checking that if a3 has heavier coin

           Choose any two 6-8 coins and place them onto balance [say 6 and 8]

           If those who weigh has the same weight:

               Third coin is coin heavier [say 7]

           else:  

               The coin [6 or 8] is the one which is heavier on the balance

       else:

           //The coin has the package which would be heavier on the balance [say a1]

           Select any two coins on balance from of the heavier package [say 0 and 1]

   If they weigh the same weight:

       Third coin is coin heavier [say 2]

   else:

       The coin that is heavier on the balance is the [or 0]

Explanation:

In the above-given algorithm code, a method Find_Heavier_Coins is declared which passes a coin[] array variable in its parameters. In the next step, if conditional block is used that checks the values which can be described as follows:

Answer:

Explanation:

I have written the Python program based on your requirements.

Just give the path of the input file and the path for the output file correctly where you want to place the output file.

In, my code - I have given my computer's path to the input and output file.

You just change the path correctly

My code works perfectly and I have tested the code with your inputs.

It gives the exact output that you need.

I have attached the Output that I got by running the below program.

Code:

month_list={ "january":"1","february":"2", "march":"3","april":"4", "may":"5", "june":"6","july":"7", "august":"8", "september":"9","october":"10", "november":"11", "december":"12"} input_file=open('C:\\Users\\Desktop\\inputDates.txt', 'r') output_file=open('C:\\Users\\Desktop\\parsedDates.txt','w') for each in input_file: if each!="-1": lis=each.split() if len (lis) >=3: month=lis [0] day=lis[1] year=lis [2] if month.lower() in month_list: comma=day[-1] if comma==',': day=day[:len (day)-1] month_number=month_list[month.lower()] ans-month_number+"/"+day+"/"+year output_file.write (ans) output_file.write("\n") output_file.close() input_file.close()

- O X parsedDates - Notepad File Edit Format View Help 3/1/1990 12/13/2003

- X inputDates - Notepad File Edit Format View Help March 1, 1990 April 2 1995 7/15/20 December 13, 2003 -1

cheers i hope this helped !!

In this exercise we have to use the knowledge in computer language to write a code in python, like this:

the code can be found in the attached image

to make it simpler we have that the code will be given by:

month_list ={"january": "1", "february": "2", "march": "3", "april": "4", "may": "5", "june": "6", "july": "7", "august": "8", "september": "9", "october": "10", "november": "11", "december":"12"}

input_file = open ('C:\\Users\\Desktop\\inputDates.txt', 'r') output_file =

open ('C:\\Users\\Desktop\\parsedDates.txt', 'w') for each

in input_file:if each

 !="-1":lis = each.split ()if len

   (lis) >= 3:month = lis[0] day = lis[1] year = lis[2] if month

    .lower ()in month_list:comma = day[-1] if comma

    == ',': day = day[:len (day) - 1] month_number =

 month_list[month.lower ()]ans - month_number + "/" + day + "/" +

 year output_file.write (ans) output_file.write ("\n") output_file.

 close ()input_file.close ()

See more about python at brainly.com/question/26104476

Answer:

Insertion query for first row :

INSERT into Invoice_Line_Items (invoice_sequence, account_number, line_item_amount, line_item_description) Values (1, 160, '$180.23', "Hard drive Exchange");

Insertion query for second row :

INSERT into Invoice_Line_Items (invoice_sequence, account_number, line_item_amount, line_item_description) Values (2, 527, '$254.35', "Server update");

Explanation:

* In SQL for insertion query, we use INSERT keyword which comes under DML (Data manipulation Language).

* Statement is given below -

INSERT into Table_name  (column1, column2, ....column N) Values (value1, value2, .....value N);

* With the use of INSERT query we can insert value in multiple rows at a same time in a table which reduces our work load.

Answer:

total = 0

count = 0

while(True):

   grade = float(input("Enter a grade: "))

   if grade < 0:

       break

   else:

       total += grade

       count += 1

average = total/count

print("The average is: " + str(average))

Explanation:

*The code is in Python.

Initialize the total and count as 0

Create a while loop that iterates until a specific condition is met inside the loop

Inside the loop, ask the user to enter a grade. If the grade is smaller than 0, stop the loop. Otherwise, add the grade to the total and increment the count by 1.

When the loop is done, calculate the average, divide the total by count, and print it

Answer and Explanation:

Therefore, the load-balancing requirements for keeping about the same number of threads would be retained and the meaningful matter of top priority thread would also be retained.

Based on the information given, it is important to give higher priority to the queue that contains the high priority thread.

Also, once an element from the high priority queue is dequeued, then dequeue one thread from the queue containing low priority thread and this will be enqueued into the queue having high priority thread in order to balance the number of threads.

Since the priority queue automatically adjusts the thread, hence the removal of the thread from one priority queue to another is not a problem.

Learn more about threads on:

https://brainly.com/question/8798580

Answer:

A.) True is the answer hope it helps

Answer:

There are a total of 8 page faults.

Explanation:

In FIFO page replacement, the requests are executed as they are received. The solution is provided in the attached figure. The steps are as follows

Look for the digit in the pages. if they are available, there is no page fault. If the digit does not exist in the page frames it will result in an error.

Answer:

i think html

Explanation:

Answer:

Web browser

Explanation: