Cameron is standing on the edge of a 60 m high cliff. He horizontally throws a football
with an initial velocity of 10 m/s. How long does it take for the football to hit the
ground?

Answers

Answer 1

Answer:34.6 m/s

Explanation: It is asking how long meaning the answer is in time


Related Questions

Question 2 (1 point)
70 cm are equivalent to how many m? State your answer using Scientific Notation.
70 x 10^-2 m
b
7.5 x 10^-2 m

ОООО
с
.75 X 10^-2 m
d
0.75 x10^-2 m
uction

Answers

Answer:

A) 70 x 10^-2

Explanation:

it would be 70 times negative 100 which equals 0.70

Use the worked example above to help you solve this problem. The amount of charge that passes through a filament of a certain lightbulb in 2.09 s is 1.56 C. (a) Find the current in the bulb. A (b) Find the number of electrons that pass through the filament in 5.24 s. electrons (c) If the current is supplied by a 12.0-V battery, what total energy is delivered to the lightbulb filament

Answers

Answer:

a)  i = 0.746 A, b)   # _electron = 2.44 10¹⁹ electrons,  c)   E = 1.87 10⁴ J

Explanation:

a) The definition of current is the charge per unit of time

           i = Q / t

           i = 1.56 / 2.09

           i = 0.746 A

b) Let's look for the cargo in passing at this time

           i = Q / t

           Q = i t

            Q = 0.746 5.24

            Q = 3.904 C

an electron has a charge e = -1.6 10⁻¹⁹ C, let's use a direct proportions rule

            # _electron = 3.904 C (1 electron / 1.6 10⁻¹⁹)

            # _electron = 2.44 10¹⁹ electrons

the number of electrons has to be an integer

           

c) In this part you are asked to calculate the power

            P = V i

            P = 12 0.746

            P = 8.952 W

            P = E/t

            E = P t

            E = 8.952 2.09

            E = 1.87 10⁴ J

unlike punishment, reinforcement ____

A. indicates what not to do
B. promotes discrimination
C. promotes generalization
D. indicate what to do​

Answers

Answer:

B...................

The answer would be A.indicates what not to do

Hope this helps

Have a great day/night

Feel free to ask any questions

Determine the speed of sound on a cold winter day (Temperature = 3ºC). *

Answers

Answer:

Temperature and Speed of Sound

Temperature of AirSpeed of Sound Waves (m/s)0 °C33120 °C343100 °C386

Explanation:

A 50kg mass is sitting on a frictionless surface. An unknown constant force pushes the mass for 2 seconds until the mass reaches a velocity of 3m/s. What was the force acting on the mass?​

Answers

Answer:

75N

Explanation:

a = v/t = 3/2

F = ma = 50(3/2) = 75

A girl and a boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy is closer to the center. Who has greater angular displacement?
a) boy
b) girl
c) both have the same angular displacement

Answers

Answer:

c) both have the same angular displacement

Explanation:

In this scenario, girl and a boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy is closer to the center. Therefore, both have the same angular displacement.

a jogger runs around a quarter of a full track in 10 seconds what is the period of teh motion around teh track

Answers

40 seconds

Explanation:

a quarter is 1/4 so to go the full thing requires you do it 4 time, and sense it takes 10 seconds to do a 1/4 you'd have to multiply 10 by 4.

I have a problem in this questions?

Answers

Answer:

8.46E+1

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = 39 C

Charge 2 (q₂) = –53 C

Force (F) of attraction = 26×10⁸ N

Electrical constant K) = 9×10⁹ Nm²/C²

Distance apart (r) =?

The distance between the two charges can be obtained as follow:

F = Kq₁q₂ / r²

26×10⁸ = 9×10⁹ × 39 × 53 / r²

26×10⁸ = 1.8603×10¹³ / r²

Cross multiply

26×10⁸ × r² = 1.8603×10¹³

Divide both side by 26×10⁸

r² = 1.8603×10¹³ / 26×10⁸

r² = 7155

Take the square root of both side

r = √7155

r = 84.6 m

r = 8.46E+1 m

HELP PLEASE
(Look at the picture)

Answers

Answer:

what is that?

Explanation:

i dont know what us that sorry

Suppose you need to design a clipper circuit to clip off the portions of an input voltage that fall above +5 V or below +2 V. Assume that diodes having a constant forward drop of 0.7 V are available. Ideal Zener diodes of any breakdown voltage required are available. Dc voltage sources of any value needed are available.

Answers

Answer:

attached below

Explanation:

The required design for a clipper circuit is attached below

From the attached circuit  

It can be seen that the battery voltage needs to be high so that it will be in forward bias considering the assumption that the diodes have a constant forward drop of 0.7 V.

hence  4.3 has to be  >2.7

Three adjacent keys on a piano (F, F-sharp, and G) are struck simultaneously, producing frequencies of 349, 370, and 392 Hz. What beat frequencies are produced by this discordant combination?

Answers

Answer:

21 Hz, 43 Hz and 22 Hz

Explanation:

The computation of the beat frequencies that are generated by this discordant combination is as follows:

As we know that

beat frequencies = |f_1  - f_2|

So

For the first one

= |349 Hz - 370 Hz|

= 21 Hz

For the second one

= |349 Hz - 392 Hz|

= 43 Hz

And, for the third one

= |370 Hz - 392 Hz|

= 22 Hz

During the nineteenth century, biologists knew that South America and Africa contained similar fossils. These fossils let them to believe that a temporary land bridge between South America and Africa allowed ancient species to move between both continents. In the twentieth century, evidence showed that South America and Africa were once part of the same larger continent and that there were no land bridges between them. How should biologists respond to the new geological finding?
A. Biologists should reject the geological finding, because it is new.
B. Biologists should ask physicists what to do, because physics is a more exact science.
C. Biologists should reject the belief in ancient species, because there were no land bridges.
D. Biologists should update the history of life, because it should include the new geological finding.
Explain

Answers

The answer id D........

Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of 0.152 N when their center-to-center separation is 60.9 cm. The spheres are then connected by a thin conducting wire. When the wire is removed, the spheres repel each other with an electrostatic force of 0.0395 N. Of the initial charges on the spheres, with a positive net charge, what was (a) the negative charge on one of them and (b) the positive charge on the other

Answers

Answer:

a) lets take the positive charge to be

q1 = 3.13 * 10^-6 C

b) lets take the negative charge to be

q2 = 3.13 * 10^-6 C

Explanation:

Given data:

electrostatic force between Two identical conducting spheres = 0.152 N

Center-to-center separation = 60.9 cm = 60.9 * 10^-2 m

When wire is removed

electrostatic force between the spheres ( repelling force ) = 0.0395 N

Determine the negative and positive charges on the identical spheres

q1, q2 = 6.26 * 10^-12 C  ( positive net charge )

lets take the positive charge to be

q1 = 3.13 * 10^-6 C

lets take the negative charge to be

q2 = 3.13 * 10^-6 C

since q1,q2 = 6.26 * 10^-12 C

attached below is detailed solution

What is a black hole's escape velocity?

Answers

ANSWER

The simplest definition of a black hole is an object that is so dense that not even light can escape its surface. If we squished the Earth's mass into a sphere with a radius of 9 mm, the escape velocity would be the speed of light. Just a wee-bit smaller, and the escape velocity is greater than the speed of light.

HopeItHelps!

Soda pop cane are made of aluminum having thickness of 0.12 mm. They are typically kept at a temperature of 4°C in refrigerator. Such cane has height of 4.83 inch and diameter of 2.6 inch. Suppose you bought such a cold soda pop and brought into the class where the temperature is 25°C.

Required:
Calculate the rate of heat transfer of the coke cane to the surroundings.

Answers

Answer:

Explanation:

For flow of heat through conduction , the formula is

Q = KA( T₂ -T₁ ) / d where K is thermal conductivity of material , A is surface area , T₂ - T₁ is temp diff .

Thermal conductivity of aluminum is 205 W /m.s

Surface area of cane = 2π r² + 2π r h where r is radius and h is height of cane .

A = 2π r ( r + h )

= 2 x 3.14 x 1.3 x .0254 ( 1.3 x .0254 + 4.83 x .0254 )

= .20736 ( .033 + .12268 )

A = .03228 m²

thickness d = .12 x 10⁻³ m

Putting the values ,

Q = 205 x .03228 x ( 25 - 4 ) / .12 x 10⁻³

= 1158 x 10³ J /s

In the Styrofoam ball investigation, it is likely that the charges on the ball and rod are
?
A. the same
B. opposite
C. constantly changing.

Answers

Answer:

answer = opposite

they are not changing being in a place as being they-self

the same would not be true because its different then the Styrofoam and it could only be different and its make the most sense aswell.

Both ball and rod has opposite charges on their bodies because of presence of different charges on it.

What are the charges on ball and rod?

In the Styrofoam ball investigation, it is likely that the charges on the ball and rod are opposite because Styrofoam ball is negatively charged due to the presence of electrons while on the other hand, the rod is positively charged because of lining of positive charges on the rod.

So we can conclude that both ball and rod has opposite charges on their bodies because of presence of different charges on it.

Learn more about charges here: https://brainly.com/question/25923373

#SPJ2

Linear Motion is the most basic type of motion. Question 2 options: True False

Answers

True................

Question 3 (5 points)
Yissel was going to be late to Mr. Scharff's science class. Just as the bell was about to ring. Vissel ran the last little bit of the hallway at 2.47
meters/second for 8 seconds to beat the bell. How far away was Yissel from Mr. Scharff's classroom when she started to run?

Answers

I am yissell what’s up by the way I was I was 10 meters of stairs from his room has to go down the stairs and wait to finish exit ticket

Two loudspeakers, A and B are driven by the same amplifier and emit sinusoidal waves in phase. Speaker B is 2.00 m to the right of speaker A. The frequency of the sound waves produced by the loudspeakers is 206 Hz. Consider a point P between the speakers and along the line connecting them, a distance x to the right of A. Both speakers emit sound waves that travel directly from the speaker to point P. For what values of x will:

a. destructive interference occur at P
b. constructive interference occur at P

Answers

Answer:

a) 0, ±1.65  b)  ± 0.825m

Explanation:

This is a sound interference exercise, it can be described by the path difference between the two waves

for the case of constructive interference

          Δr = 2n λ/ 2                   n = 0, 1, 2 ...

for the case of destructive interference

          Δr = (2n + 1) λ/ 2

the speed of sound is related to the wavelength

          v = λ f

          λ = v / f

          λ= 340/206

          λ = 1.65 m

let's set a reference system in the center between the two speakers

a) let's find the distances for constructive interference

            Δr = 2n 1.65 / 2

            Δr = 1.65 n

* the first interference occurs at n = 0

          Δr = 0

therefore the interference in the center is maximum

* n = 1

          Dr = 1.65 m

the second inference occurs at 1.65 m from the center, therefore there is a right wing and a left wing,

We do not have any more interference between the speakers because

n = 2 Δr = 3.3m this distance can be from the speaker

b) let's look for the destructive interference points

           Δr = (2n + 1) 1.65 / 2

           Δr = (2n + 1) 0.825

m = 0       Δr = 0.825m

m = 1        Δr = 2,475m

We can see that we only have the first destructive interference, one on each side.

Suppose the particle is placed at the 40V equipotential surface along the line connecting the two central positive and negative charges.
(Hint: The electric field can be obtained using the 40V and 30V potential difference lines.)

1. What is the force on the charged particle if q=80μC? (mN) (m-milli 10-3)

2. What is the force on the charged particle if it is now located at the 0V potential difference line? (mN)

Answers

Answer:

Hello some part of your question is missing below is the missing part

2.  What is the force on the charged particle if it is now located at the 0V potential difference line? (mN) (hint: The electric field can be obtained as above using the 0V and -10V equipotential lines.)

answer :

1) 0.8 mN

2) 0.8 mN

Explanation:

Given data:

1) Calculate the force on the charged particle

q = 80 μC , Va = 30v , Vb = 40v, ∝ = 1 m

E = ( Δv ) / ∝

   = ( Vb - Va ) / ∝

F = qE

  = 80 μC * ( 40 - 30 ) / 1 m

  = 800 μC

F = 0.8 mN

2) Calculate the force on the charged particle when it is located at 0V

Va = -10V , Vb = 0V, q = 80 μC,  ∝ = 1 m

F = qE

   where E = ( 0 - ( -10 ) / 1  

F = 80 μC *  ( 0 - ( -10 ) / 1

  = 800 μC = 0.8 mN

What is the speed of a vehicle that travels 50 meters in 5 seconds m/s

Answers

Answer:

10m/s

Explanation:

S=D/T

S=50m/ 5sec (make sure to write correct units, they sometimes mark you on that in physics)

S=10 m/sec (be careful of what the units that they want the answer in, different story if it was m/min

10m/s (meters per second)

How can you explain the process of reflection based from your experience?​

Answers

Answer:

Reflection brings learning to life. Reflective practice helps learners find relevancy and meaning in a lesson and make connections between educational experiences and real life situations. It increases insight, and creates pathways to future learning. Reflection is called by many different names in the education field including processing, reviewing, and debriefing. I personally have moved towards referring to this key ingredient in teaching and group facilitation as reflection or reflective practice.

Explanation:

Physical quantities are generally not purely numerical: They have a particular dimension or combination of dimensions associated with them. Thus, your height is not 74, but rather 74 inches, often expressed as 6 feet 2 inches. Although feet and inches are different units they have the same dimension--length.

Required:
a. Find the dimensions [V] of volume.
b. Find the dimensions [v] of speed.

Answers

Answer:

a, The dimension of volume is L³

b. The dimension of speed = L/T

Explanation:

The three fundamental quantities are Mass, Length and time. Other physical quantities are obtained from or derived from these three. These other quantities are known as derived quantities. The units of the fundamental quantities are Kilogram (kg) for Mass, meters for length, and second for time.

In the given question:

a. Volume = length * breadth * height

since breadth and height all measure length, the dimension of volume becomes:

volume = length * length * length = L³

Thus, the dimension of volume is L³

b. Speed, v = distance/time

Distance measures length, therefore, the dimension of speed will be:

Speed = length / time = L/T

Therefore, the dimension of speed = L/T

Explain why two electric charges of the same magnitude, when on a collision course with each other, won't actually collide


(serious answers only)

Answers

Answer:

Explanation:

When two charges of equal magnitude and sign approach each other, they interact through Coulomb's law

             

          F = [tex]k \frac{q_ 1q_2}{z^2 }[/tex]k q1 q2 / r2

In you case the house are of equal magnitude and sign

          q1 = q2 = q

          F = k q2 / r2

Let's analyze this expression, the charge is repulsive on each charge, when they are on a collision course as they approach they feel an electric field opposite to their direction of movement, this field decreases its speed, the closer they get, the greater the repulsive force. , up to the point where this force is equal to or greater than the impulse, therefore the point where the velocity reaches zero, for this reason the particles do not actually touch

A car comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to try leaping it with his car. The side the car is on is 21.3 m above the river, whereas the opposite side is a mere 2.3 m above the river. The river itself is a raging torrent 54.0 m wide. 1. How fast should the car be traveling just as it leaves the cliff in order to just clear the river and land safely on the opposite side? 2. What is the speed of the car just before it lands safely on the other side?

Answers

Answer:

Explanation:

1 ) Let the initial horizontal velocity of car be v .

For vertical displacement

vertical displacement h = 21.3 - 2.3 = 19 m

Time taken to fall by 19 m be t

19 = 1/2 x 9.8 t² ( initial downward velocity is zero )

t = 1.97 s

This is also the time taken to cover horizontal displacement of 54 m which is width of river .

horizontal speed v = 54 / 1.97 m /s

v = 27.41 m /s

2 )

At the time of landing on other side , car will have both vertical and horizontal speed .

vertical speed

v = u + gt

= 0 + 9.8 x 1.97 = 19.31 m /s

horizontal speed will remain same as  the initial speed = 27.41 m /s

Resultant speed = √ ( 27.41² + 19.31² )

= √ ( 751.3 + 372.87)

= 33.52 m /s

How do spectroscopes help with studying of distance stars?

It measures the distance of faraway stars.
It collects sound waves from distant stars.
It breaks apart lights that comes from stars faraway.
It gives a clear image of the shape of stars.

Answers

Answer:

You take the light from a star, planet or galaxy and pass it through a spectroscope, which is a bit like a prism letting you split the light into its component colours. "It lets you see the chemicals being absorbed or emitted by the light source. From this you can work out all sorts of things," says Watson

What is the momentum if the mass is 1.5 kg and the velocity is 4 m/s?

Answers

Answer:

6

Explanation:

momentum = mass * velocity

momentum = 1.5 * 4

momentum = 6

4. Which of these is exerted by an engine?
(1 Point)
Thrust
Water resistance
Friction
Air resistance

Answers

Air resistance is exerted by an engine

An accelerometer has a damping ratio of 0.5 and a natural frequency of 18,000 Hz. It is used to sense the relative displacement of a beam to which it is attached. (a)If an impact to the beam imparts a vibration at 4500 Hz, calculate the dynamic error and phase shift in the accelerometer output. (b)Calculateits resonance frequency.(c)What isthe maximumpossiblemagnitude ratio that the system can achieve

Answers

Answer:

A) i) Dynamic error ≈ 3.1%

   ii) phase shift ≈ -12°

B) 79971.89 rad/s

Explanation:

Given data :

Damping ratio = 0.5

natural frequency = 18,000 Hz

a) Calculate the dynamic error and phase shift in accelerometer output at an impart vibration of 4500 Hz

i) Dynamic error

This can be calculated using magnitude ratio formula attached below is the solution

dynamic error ≈ 3.1%

ii)  phase shift

This phase shift can be calculated using frequency dependent phase shift formula

phase shift ≈ -12°

B) Determine resonance frequency

  Wr = 2[tex]\pi[/tex] ( 18000 [tex]\sqrt{0.5}[/tex] ) = 79971.89 rad/s

C) The maximum magnitude ratio that the system can achieve

Write a conclusion to this lab in which you discuss when a person on a roller coaster ride would have sensations of weightlessness and when they would have sensations of weightiness. In your discussion, talk about accelerations and forces. Then finish off your conclusion by using Newton's second law to explain why such accelerations and force conditions cause these sensations.

Answers

Answer:

he lower part of the curve     N = M (g + v² / r)

upper part of the curve          N = m (v² /r -g)

Explanation:

In a roller coaster there is a long climb that allows the car to acquire gravitational potential energy, when this energy is converted into kinetic energy, there is a raven, in these curves we have two parts the lower part, where you have a feeling of great weight and another in the upper part where you have a feeling of weightlessness.

These sensations can be explained using Newton's second law, let's apply it to the lower part of the curve

         N-W = m a

acceleration is centripetal

        a = v² / r

we substitute

        N = mg + m v² / r

        N = M (g + v² / r)

In this part the apparent weight is increased by the speed of the body squared, it feels like a lot of fart.

In the upper part of the curve the force of gravity continues to act downwards, the normal that is the reaction of the surface also goes downwards, the centripetal acceleration pointing towards the center of the curve has a vertical downward direction

        -N -W = -m a

         N = ma -W

         N = m (v² / r -g)

In this case we see that the normal that gives the sensation decreases, which is why we feel a loss of weight, in the case of v2 / r = g, the request is total and the sensation of weightlessness.

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