As mentioned in problem 1.2 from Chapter 1, if you stand on one leg the load exerted on the hip joint is 2.4 times your body weight. Assuming a simple cylindrical model for the implant, calculate the corresponding stress (in MPa) on a hip implant in a individual with a hip implant with a cross-sectional area of If the hip implant is made of Ti6Al4V (124 GPa elastic modulus), what is the strain for the given loading conditions?

Answer:

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Answer:

W_net = mg + 2mgh/r

Explanation:

The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.

Now, gravitational force is; F_g = mg

While centripetal force is; F_c = mv²/r

Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.

Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.

Thus;

F_c = 2mgh/r

Where;

m is ball mass

r is tube radius

h is fall height

Thus, the net force will be;

F_net = F_g + F_c

Now, Net force would be equal to the net weight that will be read on the scale.

Thus;

W_net = F_net = F_g + F_c

W_net = mg + 2mgh/r

At its lowest point, the net force of the bowling ball is equal to its net weight and this is given by [tex]F_{net} = mg + \frac{2mgh}{r}[/tex]

Given the following data:

To write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the given variables:

In this scenario, there are two (2) forces acting on the bowling ball and these include:

Mathematically, centripetal force is given by this formula:

[tex]F_c = \frac{mv^2}{r}[/tex]     .....equation 1.

Mathematically, gravitational force is given by this formula:

[tex]F_g= mg[/tex]    ....equation 2.

Where:

Next, we would derive an expression for the velocity of the ball by applying the Law of Conservation of energy:

[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\V^2=2gh[/tex] .....equation 3.

Substituting eqn. 3 into eqn. 2, we have:

[tex]F_c = \frac{m(2gh)}{r}\\\\F_c = \frac{2mgh}{r}[/tex]

At its lowest point, the net weight of the bowling ball is equal to its net force and this is given by this mathematical expression:

[tex]W_{net} = F_{net} = F_g + F_c\\\\F_{net} = mg + \frac{2mgh}{r}[/tex]

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The speed of the train is 150 Km/h.

Speed can be defined as the distance travelled over a period of time. Mathematically, it can be expressed as:

Speed = Distance / Time

With the above formula, we can obtain the speed of the train as shown below:

Speed = Distance / Time

Speed = 600 / 4

Speed = 150 Km/h

Therefore, the speed of the train is 150 Km/h.

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Answer:The charge becomes nuetral

Explanation:

Whenever electrons are transferred between objects, neutral matter becomes charged. When an atom loses electrons, it becomes a positively charged ion, or cation. When an atom gains electrons, it becomes a negative charged ion, or anion.

Given parameters:

Mass of the body  = 200g

Force on the body  = 10N

Unknown parameters:

Acceleration produced by the force  = ?

To solve this problem we must first define force in terms of mass and acceleration. This is possible due to the Newton's first law of motion.

  Force  = mass x acceleration

Here the unknown is acceleration and we can easily solve for it.

But we must take the mass to kilogram in order for it to cancel out.

        1000g  = 1 kg

        200g  = x kg =   [tex]\frac{200}{1000}[/tex]   = 0.2kg

Now input the parameters and solve;

         10  = 0.2 x acceleration

   Acceleration  = [tex]\frac{10}{0.2}[/tex]   = 50m/s²

The acceleration produced by the body is 50m/s²

Answer:

Explanation:

Cardinality of a set is the number of elements in that set. Given the set.

F= {mango, apple, banana, orange)​, we are to determine the cardinality of the set i.e the amount of fruit present in the set. Cardinality of the set F is represented as n(F).

Since there are 4 different fruit in the given set F, hence the cardinality of the set F is n(F) = 4

Answer:

Falling from the Sears Tower

• After 5 seconds, the ball falling from the

Sears Tower will have fallen

distance = ½ • 32 ft/s2 • (5 s)2 = 16 • 25

= 400 feet.

• We can turn the formula around to figure

out how long it would take the ball to fall all

the way to the ground (1450 ft)

Ætime = square root of (2 x distance/g)

Explanation:

Answer:

volume about 1.3 million Earths could fit inside the Sun the mass of the Sun is 1.989 X 10 to the 30 kg about 333000 times the mass of the Earth

Explanation:

step-by-step explanation hope this answer your question

Answer:

Its convergent

Explanation:

There areas where plates move toward each other and collide Also known as compressional pr destructive boundaries.

Answer:

64 m/s

Explanation:

64m/s is the answer of question

64/m/s the answer

Answer:

a) F = 9.69 N

b) F = 10.88 N

c) F = 8.51 N

Explanation:

a) The kinetic frictional force when the elevator is stationary is the following:

[tex] F_{k} = \mu_{k}N = \mu(mg) [/tex]    

Where:

F(k) is the kinetic frictional force

N is the normal force = mg

m: is the mass = 2.60 kg

g: is the gravity = 9.81 m/s²

μ(k) is the coefficient of kinetic friction = 0.380

[tex] F_{k} = \mu(mg) = 0.380*2.60 kg*9.81 m/s^{2} = 9.69 N [/tex]    

b) When the elevator is accelerating upward with acceleration "a" equal to 1.20 m/s²

[tex] F_{k} = \mu_{k}N = \mu[m(g + a)] [/tex]    

The normal is equal to mg plus ma because the elevator is accelerating upward

[tex] F_{k} = \mu m(g + a) = 0.380*2.60 kg(9.81 m/s^{2} + 1.20 m/s^{2}) = 10.88 N [/tex]    

c) When the elevator is accelerating downward with a =1.20 m/s² we can find the kinetic frictional force similar to the previous case:

[tex] F_{k} = \mu m(g - a) = 0.380*2.60 kg(9.81 m/s^{2} - 1.20 m/s^{2}) = 8.51 N [/tex]    

I hope it helps you!

Answer:

32m

Explanation:

v=u+at

v=0+2×4

v=8m/s

d=vt

d=8×4

d=32m

Answer:

C

Explanation:

Static electricity is what makes your hair stand up when you rub a balloon against it or gives you a shock from your doorknob. In static electricity, electrons are moved around mechanically (i.e. by someone rubbing two things together).

HOPE THIS HELPED AND LETTER D MADE ME LAUGH

Answer:

the correct order of events is: 5 7 6 3 4 1 2

Explanation:

In this exercise, you order the events to solve the problem of the electric field created by a line of charge a line of charge

the order of events is

a) We define a reference   5

b) cut the line into segments each one is a charge differential  7

c) find the vector of the position of charges  6

d) find the point where field  is calculated   3

e) find the distance between each charge point and point of interest   4

f) insert Coulomb's law 1

f) perform the integral of line 2

therefore the correct order of events is: 5 7 6 3 4 1 2

Answer:

when gravitational force suddenly disappears, then only centrifugal force will be acting and velocity is tangential to the orbit and hence, the satellite will fly off tangentially with same velocity v.

Astroid one has less asked her to. Able to use enough force to not only change or keep it self go in the same direction.

(a) If the initial speed both asteroids before collision is the same, then the asteroid with greater mass will have more momentum before collision while the asteroid with lesser mass will have greater momentum after collision.

(b) The force of the impact depends of the velocity change and time of collision of the asteroids.

According to the principle of conservation of linear momentum, the sum of the momentum of each asteroid  before collision must equal the sum of their momentum after collision.

[tex]m_1 u_1 + m_2 u_2 = m_1v_1 + m_2 v_2[/tex]

where;

If the initial speed both asteroids before collision is the same, then the asteroid with greater mass will have more momentum before collision while the asteroid with lesser mass will have greater momentum after collision to conserve the momentum.

The force of the impact depends of the velocity change and time of collision of the asteroids.

[tex]F = \frac{m\Delta v}{t}[/tex]

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Answer:

it gets colder

Explanation:

because if you put anything on a table top it will become colder

Answer:

transition metal, and inner transition metals groups are numbered 1-18 from left to right

Answer:

6.12 m/s

Explanation:

In order to solve this we have two parts of this problem, first we have the time that the pizza dough spent going upwards and after that we have a free fall from there, so we will use the free fall formula after we figured out whats the final height the dough reached after being thrown from Francesco's height which is 6ft3inches or 1.90 meters

We first have to find out how much time the dough spent in the air before reaching 0 as final speed and then started the free falling:

The formula would be:

[tex]Vf=Vo-at\\0=1-(-9.81t)\\1=9.81t\\t=\frac{1}{9.81}\\t=.101[/tex]

The formula to find out final height would be:

[tex]y = \frac{ h + Vy (t-gt^{2})}{2} \\[/tex]

Now we just insert the values we know

[tex]y = h+ \frac{ Vy (t-gt^{2})}{2} \\\\y = 1.90 +\frac{ .101-(-9.81)(.101)^{2})}{2} \\\\y=1.91[/tex]

So from 1.91 meteres the free fal started we have to just calculate the final velocity with the formula for free fall and velocity:

[tex](vf)^{2} =Vo^2 +2ad[/tex]

Since Vo is 0 because we are talking about free falling we just insert the values we know:

[tex](vf)^{2} =Vo^2 +2ad\\(vf)^{2} =2ad\\(vf)^{2} =2(9.81)(1.91)\\vf=\sqrt{37.4742} \\Vf=6.12m/s[/tex]

So the final speed that the dough hit the ground with is 6.12 m/s

Answer:

b) 0 = y₀ + 0 - ½ g t² ,  v₀ₓ = x / t

c)  v₀ₓ = 30.31 m / s

Explanation:

This is a projectile launching exercise, in your statement you have units of several systems, we are going to reduce everything to the SI system

   v = 35 mph (0.447 m / s / 1 mph) = 15.645 m / s

   y₀ = 75 m

A) In the attachment we can see a diagram of the movement of the vehicle in its fall

B) let's find the time for the fall to the base of the cliff (y = 0)

        y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²

when the vehicle leaves the cliff it goes horizontally, so its vertical speed is zero (v_{oy} = 0)

         0 = y₀ + 0 - ½ g t²

         t = √2y₀ / g

with this time we can use the equation of motion on the x axis

         x = v₀ₓ t

         v₀ₓ = x / t

C) we perform the calculations

            t = √ (2 30 / 9.8)

            t = 2.474 s

           v₀ₓ = 75 / 2.474

           v₀ₓ = 30.31 m / s

D) as we can see, the vehicle speed when leaving the cliff is almost twice the allowed speed (15.6 m / s)

therefore the city is not responsible for the accident

Answer:

[tex]a_{x} = 0.342 \frac{m}{ {s}^{2} } \: "x \: component \: of \: acceleration"

\: \\ a_{y} = 1.02 \: \frac{m}{ {s}^{2} } \: "y \: component \: of \: acceleration" [/tex]

Explanation:

Given a mass of 63.9kg with a total applied force of 125 N at a 31.5° inclination relative to the horizontal and vertical, and a horizontal resistance force of 84.8 N. The components of acceleration can be calculated as follows:

Force = mass × acceleration

Vertical component of a vector = vector × Sin(angle)

Horizontal component of a vector = vector × Cos(angle)

extra:

V = √x^2+y^2

θ (angle, "theta") = arctan or inverse tan(y/x) (For this instance. Theta is usually an angle measure though)

x = V cos θ

y = V sin θ

____________________

To find the vertical component of acceleration we must first take the vector quantity of our force which is 125 N (Newtons) and it's angle of 31.5°.

Vertical force = 125 × sin(31.5 degrees) = 125 × 0.5225 = 65.312 N [aka the normal force]

This works because force is a vector, it has both direction(by the angle of force), and magnitude(it's quantity).

Then take the force equation, and rearrange it to solve for the upward acceleration: F = m × a → a = F/m.

a = 65.312/63.9 ≈ 1.02 m/s^2.

Then for the horizontal acceleration, take the cosine for the horizontal part

Answer: Planets A and B have a rocky mantle and an iron core. They are at a distance of 1 AU or less from the Sun. This means they are relatively close to the Sun. There are the properties of inner (terrestrial) planets. So planet A and B are inner planets.

Explanation:

Planet C is composed if the gases hydrogen and helium. It has a high mass and is much farther from 1 AU from the sun. These properties are consistent with the outer planets. So, planet C is an outer (gas giant) planet.

Answer:

Planets A and B have a rocky mantle and an iron core. They are at a distance of 1 AU or less from the Sun. This means they are relatively close to the Sun. There are the properties of inner (terrestrial) planets. So planet A and B are inner planets.

Explanation:

Answer:

8.5

Explanation:

to find efficiency take the ratio between the output and input

85/100=output/input

Answer:

In the event of a disease caused by an unknown pathogen, it is hard to know which reagent to pick. ... EM, though it may not be able to identify a virus beyond the family level, at least ... Negative staining of stool specimens from these cattle demonstrated a ... This results in a fuzzy halo around the particles in negative stains.Explanation: