Answer:use mathematic pathway to calualte
Step-by-step explanation:
Do the measures of center make sense? A. Only the mode makes sense since the data is nominal. B. All the measures of center make sense since the data is numerical. C. Only the mean, median, and midrange make sense since the data is nominal. D. Only the mean, median, and mode make sense since the data is numerical.
Answer:
A. Only the mode makes sense since the data is nominal.
Step-by-step explanation:
Hello!
The objective of the study was to determine if deficiency of carbon dioxide in the soil affects the phenotype of peas.
The variable of study is X: Phenotype of a pea grown in soil with carbon dioxide deficiency.
Possible values of Phenotype codes:
1= smooth-yellow
2= smooth-green
3= wrinkled-yellow
4= wrinkled-green
The absolute frequencies for each phenotype are:
f(1)= 3
f(2)= 4
f(3)= 6
f(4)= 1
n= 14
a) Mean:
X[bar]= (∑xifi)/n= [(1*3)+(2*4)+(3*6)+(4*1)]/14= 33/14= 2.357= 2.36
The average value is always within range of definition of the variable but it does not necessarily correspond to an observation.
b) Median:
To determine the value that corresponds to the median you have to calculate its position:
For even samples the position is:
PosMe= n/2= 14/2= 7
Then you have to arrange the data from least to greatest, in this case, starting from the first category, you have to determine where the seventh observation is within the observed absolute frequencies. The phenotype that corresponds to the 7th observation is 2= smooth-green.
Me= 2= smooth-green.
c) Mode:
The mode corresponds to the most observed category/ value of the variable, i.e. the category with the most observations is 3= wrinkled-yellow
Md= 3= wrinkled-yellow
d) Midrange: (1 + 4)/2= 2.5
e)
As you can see the variable is qualitative and categorical. Even if all central tendency measurements can be calculated, truth is that the only one that shows any valuable information regarding the data set is the mode.
I hope this helps!
The relationship between ttt and rrr is expressed by the equation 2t+3r+6=02t+3r+6=02, t, plus, 3, r, plus, 6, equals, 0. If rrr increases by 444, which of the following statements about ttt must be true?
Question:
The relationship between t and r is expressed by the equation 2t+3r+6 = 0. If r increases by 4, which of the following statements about t must be true?
Answer:
The value of t is reduced by 6 when the value of r is increased by 4
Step-by-step explanation:
Given
[tex]2t + 3r + 6 = 0[/tex]
Required
What happens when r is increased by 4
[tex]2t + 3r + 6 = 0[/tex] -------- Equation 1
Subtract 2t from both sides
[tex]2t + 3r + 6 - 2t = 0 - 2t[/tex]
[tex]3r + 6 = - 2t[/tex] --- Equation 2
When r is increased by 4, equation 1 becomes
[tex]2T + 3(r+4) + 6 = 0[/tex]
Note that the increment of r also affects the value of t; hence, the new value of t is represented by T
Open bracket
[tex]2T + 3r+12 + 6 = 0[/tex]
Rearrange
[tex]2T + 3r+6 +12 = 0[/tex]
Substitutr -2t for 3r + 6 [From equation 2]
[tex]2T -2t +12 = 0[/tex]
Make T the subject of formula
[tex]2T = 2t - 12[/tex]
Divide both sides by 2
[tex]\frac{2T}{2} = \frac{2t - 12}{2}[/tex]
[tex]T = t - 6[/tex]
This means that the value of t is reduced by 6 when the value of r is increased by 4
An English teacher needs to pick 10 books to put on her reading list for the next school year, and she needs to plan the order in which they should be read. She has narrowed down her choices to 4 novels, 6 plays, 8 poetry books, and 4 nonfiction books. Step 1 of 2 : If she wants to include no more than 3 poetry books, how many different reading schedules are possible? Express your answer in scientific notation rounding to the hundredths place.
Answer:
the number of possible reading schedules is 1.064301638 × 10¹²
Step-by-step explanation:
Given that :
The English teacher needs to pick 10 books to put on her reading list for the next school year.
If the English teacher picks at most 3 poetry books i.e no more than 3 poetry books from 8 books. and other books are picked from (6+4+4 ) = 14 books
Thus; the number of ways to pick the books are :
[tex]\left[\begin{array}{c}8\\0\\ \end{array}\right] \ \left[\begin{array}{c}14\\10\\ \end{array}\right]+ \left[\begin{array}{c}8\\1\\ \end{array}\right] \left[\begin{array}{c}14\\9\\ \end{array}\right] + \left[\begin{array}{c}8\\2\\ \end{array}\right] \left[\begin{array}{c}14\\8\\ \end{array}\right] + \left[\begin{array}{c}8\\3\\ \end{array}\right] \left[\begin{array}{c}14\\7 \\ \end{array}\right][/tex]
[tex]= [ \dfrac{8!}{0!(8-0)!}* \dfrac{14!}{10!(14-10!)} ] + [ \dfrac{8!}{1!(8-1)!}* \dfrac{14!}{9!(14-9)!}]+ [ \dfrac{8!}{2!(8-2)!}* \dfrac{14!}{8!(14-8)!}] + [ \dfrac{8!}{3!(8-3)!}* \dfrac{14!}{7!(14-7)!}][/tex]
[tex]= [ 1*1001]+[8*2002]+[28*3003]+[56*3432][/tex]
[tex]\mathbf{= 293293}[/tex]
However, to determine how many reading schedules that are possible we use the relation:
Number of ways to pick a book × [tex]^{10}P_{10}[/tex]
[tex]= 293293* \dfrac{10!}{(10-10)!}[/tex]
= 293293 × 10!
= 1.064301638 × 10¹²
Thus , the number of possible reading schedules is 1.064301638 × 10¹²
What is the slope of a line that is perpendicular to the line y = x + 5?
Answer:
-1.
Step-by-step explanation:
The standard form of a line can be written y = mx + b where m is the slope.
y = x + 5 can be written as y = 1x + 5 which shows that the slope is 1.
If the slope of a line is m then the slope of a line perpendicular to it is -1/m.
So the required slope is -1/1 = -1.
Answer:
-1
Step-by-step explanation:
the line is exactly opposite like a mirror image when it is perpendicular,
so the gradient of the first line is 1 (because there is no number beside x, the gradient would be 1), that means the opposite of 1 would be -1.
The answer is -1
Avantraveling 20 miles per hour can stop in 60 feet. If a van is traveling 32 miles per hour what is it’s stopping distance
If the inter-quartile range is the distance between the first and third quartiles, then the inter-decile range is the distance between the first and ninth decile. (Deciles divide a distribution into ten equal parts.) If IQ is normally distributed with a mean of 100 and a standard deviation of 16, what is the inter-decile range of IQ
Answer:
The inter-decile range of IQ is 40.96.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 100, \sigma = 16[/tex]
First decile:
100/10 = 10th percentile, which is X when Z has a pvalue of 0.1. So it is X when Z = -1.28.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-1.28 = \frac{X - 100}{16}[/tex]
[tex]X - 100 = -1.28*16[/tex]
[tex]X = 79.52[/tex]
Ninth decile:
9*(100/10) = 90th percentile, which is X when Z has a pvalue of 0.9. So it is X when Z = 1.28.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]1.28 = \frac{X - 100}{16}[/tex]
[tex]X - 100 = 1.28*16[/tex]
[tex]X = 120.48[/tex]
Interdecile range:
120.48 - 79.52 = 40.96
The inter-decile range of IQ is 40.96.
Given the two parallel lines determine the value of x
Answer:
D. 150°
Step-by-step explanation:
x= 150°
Choice D
A professor gives her 100 students an exam; scores are normally distributed. The section has an average exam score of 80 with a standard deviation of 6.5. What percentage of the class has an exam score of A- or higher (defined as at least 90)? Type your calculations along with your answer for full credit; round your final percentage to two decimal places.
Answer:
6.18% of the class has an exam score of A- or higher.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 80, \sigma = 6.5[/tex]
What percentage of the class has an exam score of A- or higher (defined as at least 90)?
This is 1 subtracted by the pvalue of Z when X = 90. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{90 - 80}{6.5}[/tex]
[tex]Z = 1.54[/tex]
[tex]Z = 1.54[/tex] has a pvalue of 0.9382
1 - 0.9382 = 0.0618
6.18% of the class has an exam score of A- or higher.
Determine whether the following procedure is a binomial experiment.
If it is not, explain why. Drawing 5 marbles from a bag with 10 red, 8 green and 12 yellow marbles without replacement and finding out how many of these five are green.
a. Yes, this is a binomial experiment.
b. No, the outcomes cannot be classified into two categories.
c. No, the trials are not independent
Answer:
C. The trails are not independent.
The probability of drawing one marble will not be independent of others thus option (c) is correct.
What is probability?The probability of an event occurring is defined by probability.
Probability is also called chance because if you flip a coin then the probability of coming head and tail is nothing but chances that either head will appear or not.
As per the given,
Drawing 5 marbles from a bag with 10 red, 8 green, and 12 yellow marbles without replacement.
In without replacement, the remaining balls in each draw will go to be decreased thus they will be dependent events so binomial distribution will not be applied.
Hence "One marble's likelihood of being drawn won't be independent of the other marbles".
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Every product manufactured by a company goes through 6 different tests before being shipped out. It is known that the probability that a product passes any single test is 0.9 and the tests are independent. Only those products that pass the first three tests and also pass at least one of the three remaining tests are shipped out. Find the probability that a manufactured product is shipped out.
Answer:
The Probability that the product is shipped out is 0.7283
Step-by-step explanation:
Here, we are given that, a product passes through 6 tests before it is shipped out and a product is shipped out only if it passes all the first 3 tests and at least 1 of the remaining 3 tests.
We have P(pass)= 0.9, is the Probability of passing any test.
Which implies, P(fail)= 1- 0.9= 0.1
We have to find the Probability that the product is shipped out.
P(product is shipped out) = P(it passes first 3 tests )*P(passes at least 1 of the remaining 3 tests) •••••••••••(i)
We can take the product as the tests are Independent.
Now, let us obtain
P(it passes first 3 tests ) = P(pass)*P(pass)*P(pass)
=P(pass)]^3 = (0.9)^3 = 0.729
Hence, P( it passes first 3 tests)= 0.729 •••••••(ii)
Now,
P(passes at least 1 of the remaining 3 tests)
= 1-P(fails all the 3 remaining tests)
= 1-(0.1)^3 = 1 - 0.001 = 0.999
Hence,
P(passes atleast 1 of the remaining 3 tests)=0.999 ••••••••(iii)
Now, substituting the 2nd and 3rd equations in the first equation, we have;
P(product is shipped out) = P(it passes first 3 tests )*P(passes at least 1 of the remaining 3 tests)
= (0.729)*(0.999)
= 0.728271
= 0.7283
Assume that random guesses are made for nine multiple choice questions on an SAT test, so that there are nequals9 trials, each with probability of success (correct) given by pequals0.55. Find the indicated probability for the number of correct answers. Find the probability that the number x of correct answers is fewer than 4.
Answer:
[tex]P(X=0)=(9C0)(0.55)^9 (1-0.55)^{9-0}=0.000757[/tex]
[tex]P(X=1)=(9C1)(0.55)^9 (1-0.55)^{9-1}=0.0083[/tex]
[tex]P(X=2)=(9C2)(0.55)^9 (1-0.55)^{9-2}=0.0407[/tex]
[tex]P(X=3)=(9C3)(0.55)^9 (1-0.55)^{9-3}=0.1160[/tex]
And adding we got:
[tex] P(X < 4) = 0.000757 +0.0083+0.0407 +0.1160= 0.2626[/tex]
Step-by-step explanation:
Let X the random variable of interest "number of correct answers", on this case we now that:
[tex]X \sim Binom(n=9, p=0.55)[/tex]
The probability mass function for the Binomial distribution is given as:
[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]
Where (nCx) means combinatory and it's given by this formula:
[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]
And we want to find this probability:
[tex] P(X < 4) =P(X=0) +P(X=1) +P(X=2) +P(X=3) [/tex]
And we can find the individual probabilities:
[tex]P(X=0)=(9C0)(0.55)^9 (1-0.55)^{9-0}=0.000757[/tex]
[tex]P(X=1)=(9C1)(0.55)^9 (1-0.55)^{9-1}=0.0083[/tex]
[tex]P(X=2)=(9C2)(0.55)^9 (1-0.55)^{9-2}=0.0407[/tex]
[tex]P(X=3)=(9C3)(0.55)^9 (1-0.55)^{9-3}=0.1160[/tex]
And adding we got:
[tex] P(X < 4) = 0.000757 +0.0083+0.0407 +0.1160= 0.2626[/tex]
When each of the following is divided by 8, only ?_ has a remainder that is a prime number. A) 548 B) 569 C) 678 D) 778
Answer:
the answer you are looking for is D 778
A tree is 12 feet tall and casts a shadow 9 feet long. A building nearby casts a shadow that measures 24 feet. How tall is the building?
(Hint: Draw a picture and Set up a proportion)
The building height is 32 feet.
Let us consider that building height is x feet.
From attached diagram shown below,
Two triangles are formed.
Apply law of similarity of triangles.
Corresponding sides are in equal proportion.
[tex]\frac{x}{24}=\frac{12}{9} \\\\9x=12*24\\\\x=\frac{12*24}{9}=32 feet[/tex]
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Which statement about the two-way frequency table is true?
Answer:
Which statements?
Step-by-step explanation:
Can you write the statements please?
Which expressions are equivalent to 64^1Check all that apply
The right answers are:
4^38^22^6Hope it helps.
please see the attached picture for full solution
Good luck on your assignment
7. Find all geometric sequences such that the sum of the first two terms is 24 and the sum of the first
three terms is 26.
Answer:
Step-by-step explanation:
Let the first term is n, then the second term must be an where a is a common ratio, and the third term is a^2 n
so, n + an = 24
n + an + a^2 n = 26
solve for a, then solve for n
If f(3x − 1) = 6x − 1, find f(x) and f(0)
f(3x - 1) = 6x - 1
Rewrite 6x - 1 as a function of 3x - 1:
6x - 1 = 6x - 2 + 1 = 2(3x - 1) + 1
That is,
f(3x - 1) = 2(3x - 1) + 1
which means
f(x) = 2x + 1
and so
f(0) = 2*0 + 1 = 1
Please help! Correct answer only, please! The following information matrices shows how many of each vehicle type sold and the bonus amount each salesperson receives for selling that type of vehicle for the car dealership for the week. What does the element LaTeX: A_{2,3}A 2 , 3represent? A. Mark sold 2 vans B. Scott sold 1 Van C. Mark sold 4 trucks D. Kelly sold 2 trucks
Answer: B) Scott sold 1 van
Step-by-step explanation:
A₂,₃ represents: matrix A - 2nd row - 3rd column
The second row is Scott and and the 3rd row is Vans
If you look at Scott - Vans, you will see that Scott sold 1 van.
2009-2202+1234-2 equals
Step-by-step explanation:
1039
This is the correct answer
A cola manufacturer invited consumers to take a blind taste test. Consumers were asked to decide which of two sodas they preferred. The manufacturer was also interested in what factors played a role in taste preferences. Suppose the manufacturer wanted to test to determine if the males preferred its brand more than the females. Using the test statistic given in the printout, compute the appropriate p-value for the test.
A. 0.0340
B. 0.0171
C. 04681
D. 0.2119
Answer: B. 0.0171
Step-by-step explanation:
The question is incomplete. The complete question is:
A cola manufacturer invited consumers to take a blind taste test. Consumers were asked to decide which of two sodas they preferred. The manufacturer was also interested in what factors played a role in taste preferences. Below is a printout comparing the taste preferences of men and women.
HYPOTHESIS: PROP. X = PROP. Y
SAMPLES SELECTED FROM soda(brand1,brand2)
males (sex=0, males) (NUMBER = 115)
females (sex=1, females) (NUMBER = 56)
X = males
Y = females
SAMPLE PROPORTION OF X = 0.422018
SAMPLE SIZE OF X = 109
SAMPLE PROPORTION OF Y = 0.25
SAMPLE SIZE OF Y = 52
PROPORTION X - PROPORTION Y = 0.172018
Z = 2.11825
Suppose the manufacturer wanted to test to determine if the males preferred its brand more than the females. Using the test statistic given, for a one-sided test, compute the appropriate p-value for the test.
Solution:
Looking at the statement, "Suppose the manufacturer wanted to test to determine if the males preferred its brand more than the females", it shows that it is a right tailed test. Since the test statistic is already known, we would find the probability value for the area above the test statistic or z score from the normal distribution table. From the table,
p value = 0.983
The required p value above the z score is
1 - 0.983 = 0.0171
the appropriate p-value for the test is 0.0171
a is directly proportional to b. When a is 6, b is 72. Find b when a is 8. 3
Answer:
a) "K" is proportional Constant K= 0.0833
b) The value of b = 99.639
Step-by-step explanation:
Explanation :-
Given 'a' is directly proportional to 'b'
a ∝ b
a = k b ....(i)
where "K" is proportional Constant
Case(i):-
when a =6 and b=72
a = k b
⇒ 6 = k (72)
⇒ [tex]K = \frac{6}{72} = \frac{1}{12} = 0.0833[/tex]
Case(ii):-
Given a = 8.3
a = k b
⇒ 8.3 = 0.0833 ×b
⇒ [tex]b = \frac{8.3}{0.0833} = 99.639[/tex]
Final answer:-
a)"K" is proportional Constant K= 0.0833
b) The value of b = 99.639
Determine whether the given value of the variable is a solution of the inequality.
Answer:
Yes, [tex]\frac{3}{4}[/tex] is a solution of the inequality.
Step-by-step explanation:
Solution of an inequality is given by the values of the variable t ≥ [tex]\frac{2}{3}[/tex]
Or t ≥ 0.67
If a solution of this inequality is t = [tex]\frac{3}{4}[/tex]
Or t = 0.75
Since, on a number line 0.75 > 0.67
Therefore, [tex]\frac{3}{4}[/tex] will be a solution of the inequality.
If ABC ~ DEF what is the scale factor of abc to def
Answer:
It might be 1/3 but I'm not 100% sure
The required scale factor of ABC to DEF is 1/3.
Scale factor of ABC to DEF to determine.
What is scale factor?The scale factor is defined as the ratio of modified change in length to
Here, Triangle ABC is similar to triangle DEF. So, the ratio of the same sides describe the scale factor.
Scale factor = EF/BC
= 7/21
= 1/3
Thus, the required scale factor of ABC to DEF is 1/3.
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Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!
Answer: h = -(16t + 3)(t - 2)
h(0) = 6
h(1) = 19
h(2) = 0
Step-by-step explanation:
Factor the equation by finding two numbers whose
product = a×c and sum = b, then replace the b value with those two numbers and factor the equation.
h = -16t² + 29t + 6
a=-16 b=29 c=6 a×c = -96 b = 29
32 × -3 = 96 32 + (-3) = 29
h = -16t² + 32t -3t + 6
h = -16t(t - 2) -3(t - 2)
h = (-16t - 3) (t - 2)
h = -(16t + 3)(t - 2)
h(0) = -[16(0) + 3] [0 - 2]
= -(3)(-2)
= 6
h(1) = -[16(1) + 3] [1 - 2]
= -(19)(-1)
= 19
h(2) = -[16(2) + 3] [2 - 2]
= -(35)(0)
= 0
Presenting historical information without hypothesis tests or exploratory analysis is:_________.
a) predictive statistics
b) prescriptive statistics
c) descriptive statistics
d) inferential statistics
Answer:
c) descriptive statistics
Correct. When we present information without any type of hypothesis we are describing the information
Step-by-step explanation:
We know that we are presenting historical information without any hypothesis and we need to find the right term, let's analyze one by one
a) predictive statistics
False. We can't predict if we are using historical information because predict is for the future and that not applied here.
b) prescriptive statistics
False. This term not exists in reality the most similar term is prescriptive analytic who analyze a series of scenarios fr an information given
c) descriptive statistics
Correct. When we present information without any type of hypothesis we are describing the information
d) inferential statistics
False. If we don't have any hypothesis we can't apply any inferential study and for this case is not the correct option
A clothing store determines that in order to sell x shirts, the price per shirt should be p(x)=100−x dollars. Getting x shirts from the supplier costs the store C(x)=1,600+20x dollars. If the store’s revenue from selling x shirts is R(x)=x⋅p(x), for what value of x will the store’s cost and revenue be equal?
Answer:
x= -40
Step-by-step explanation:
Cost
C(x)=1,600+20x
P(x)=100-x
Revenue=x*p(x)
=x*(100-x)
=100x-x^2
Cost=Revenue
1600+20x=100x-x^2
1600+20x-100x+x^2=0
1600-80x+x^2=0
Solve using quadratic formula
Formula where
a = 1, b = 80, and c = 1600
x=−b±√b2−4ac/2a
x=−80±√80^2−4(1)(1600) / 2(1)
x=−80±√6400−6400 / 2
x=−80±√0 / 2
The discriminant b^2−4ac=0
so, there is one real root.
x= −80/2
x= -40
Translate the phrase into a variable expression. Use the letter d to name the variable. If necessary use the asterisk for multiplication and the slash for division The numbers of dollars Paul owes plus 16..
Answer:
This can be written as d + 16 because plus means addition.
Which table represents a function?
1. You have a home business selling designer necklaces. You have done
some market research, which shows that at a price of $40 you can sell
500 per week, and at a price of $60 you can sell 400 per week. Assuming
that the relationship between price and quantity sold is linear, find the
price that maximizes revenue. You must use methods that we developed
and practiced in the course. You will be graded not only on your answer
but on the clarity of your presentation.
Answer:
The price that maximizes the profits from the sale of the product is $60.
Step-by-step explanation:
Since selling necklaces at $ 40 allows a total amount of 500 sales per week, while a price of $ 60 allows 400 sales at the same time, the following calculations must be made to determine the price that maximizes sales performance:
40 x 500 = $ 20,000
60 x 400 = $ 24,000
50 x 450 = $ 22,500
55 x 425 = $ 23,375
58 x 410 = $ 23,780
59 x 405 = $ 23,895
As can be seen from the calculations developed, the price that maximizes the profits from the sale of the product is $60.
Hey what’s the correct answer for this?
Answer:
A
Step-by-step explanation:
Well first find the proportion of the sector of the major Arc(shaded area) and then Multiply by area of the circle πr²
