Physics High School

An island reports that in the year 2000 there were 240 babies born. That same year, 100 individuals died.
What is the growth rate for this island?(Show your work and indicate if it is positive or negative.)

Answers

Answer 1

Answer:

+ 140

Explanation:

You can show the natural growth rate by subtracting the death rate from the birth rate during one year and converting this into a percentage.

Here it would be:

240 - 100 = + 140

// if you want to convert it to percentage, you need to know the size of the population

it would be

140 / (population size) * 100 %

Related Questions

A 1-kg book is at rest on a desk. Determine the force the desk exerts on the book
​

Answers

Answer:

[tex]\displaystyle F_n = 9.8 \ N[/tex]

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right

Physics

Forces

SI Unit: Newtons N

Free Body Diagrams

Gravitational Force: [tex]\displaystyle F_g = mg[/tex]

m is mass (in kg)g is Earth's gravity (9.8 m/s²)

Normal Force: [tex]\displaystyle F_n[/tex]

Newton's Law of Motions

Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motionNewton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)Newton's 3rd Law of Motion: For every action, there is an equal and opposite reactionExplanation:

Step 1: Define

1 kg book at rest

Step 2: FBD

See Attachment

Draw a free body diagram to label the forces acting upon the book. We see that we would have gravitational force from Earth pointing downwards and normal force from the surface of the desk pointing upwards.

Since the book is not moving, we know that ∑F = 0 (sum of forces equal to 0).

Step 4: Find Normal Force

Define Forces [Newton's Law of Motions]:                                                 [tex]\displaystyle \sum F = 0[/tex][Newton's Law of Motions] Substitute in forces:                                         [tex]\displaystyle F_g - F_n = 0[/tex][Newton's Law of Motions] [Addition Property of Equality] Isolate [tex]\displaystyle F_n[/tex]:     [tex]\displaystyle F_g = F_n[/tex][Newton's Law of Motions] Substitute in [tex]\displaystyle F_g[/tex]:                                               [tex]\displaystyle mg = F_n[/tex][Newton's Law of Motions] Rewrite:                                                             [tex]\displaystyle F_n = mg[/tex][Newton's Law of Motions] Substitute in variables:                                   [tex]\displaystyle F_n = (1 \ kg)(9.8 \ \frac{m}{s^2})[/tex][Newton's Law of Motions] Multiply:                                                             [tex]\displaystyle F_n = 9.8 \ N[/tex]

A force of 100 N will exert the greatest pressure on an area of

Answers

Answer:

It will apply the greatest pressure of an area of 1.

Explanation:

To find pressure use the formula P = F/A

P = 100/1

P = 100

Answer:

10 N / cm^2

Explanation:

The Formiula is P = F / A

P = presure

F = Force in Newtons

A = area.

The answer is the smaller the area the larger the pressure.

The smallest area you have given us is 10 cm^2

The Pressure = 100N / 10 cm^2

Pressure = 10 N/cm^2  

Note: the units are not exactly standard units, but I've given the answer the way the question offers the units.

compare the liquid pressure at the surface of a swimming pool and the bottom of the swimming pool

Answers

Answer:

The pressure difference is equal to the product of density , height and g

Given that h is height difference between bottom and surface of a pool

P  

b

​  

−P  

s

​  

=dgh

Density d of water is 1

So we get P  

b

​  

−P  

s

​  

=gh

Therefore option A is correct

Explanation:

If the mass of a 1.8 g paperclip was able to be completely converted to energy, how much energy would you obtain?

Answers

Answer:

[tex]E=1.62\times 10^{14}\ J[/tex]

Explanation:

Given that,

The mass of the paperclip, m = 1.8 g = 0.0018 kg

We need to find the energy obtained. The relation between mass and energy is given by :

[tex]E=mc^2[/tex]

Where

c is the speed of light

So,

[tex]E=0.0018\times (3\times 10^8)^2\\\\E=1.62\times 10^{14}\ J[/tex]

So, the energy obtained is [tex]1.62\times 10^{14}\ J[/tex].

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