According to an online survey by Harris Interactive for job site CareerBuilder, more than half of IT (information technology) workers say they have fallen asleep at work (InformationWeek, September 27, 2007). Sixty-four percent of government workers admitted to falling asleep on the job. Consider the following contingency table that is representative of the survey results.

Slept on the Job IT Professional Government Professional
Yes 155 256
No 145 144

1. Convert the contingency table into a joint probability table. (Round the intermediate calculations and final answers to 4 decimal places.)
2. What is the probability that a randomly selected worker is an IT professional? (Round the intermediate calculations and final answers to 4 decimal places.)
3. What is the probability that a randomly selected worker slept on the job? (Round the intermediate calculations and final answers to 4 decimal places.)
4. If a randomly selected worker slept on the job, what is the probability that he/she is an IT professional? (Round the intermediate calculations and final answers to 4 decimal places.)
5. If a randomly selected worker is a government professional, what is the probability that he/she slept on the job? (Round the intermediate calculations and final answers to 4 decimal places.)
6. Are the events "IT Professional and Slept on the Job" independent? Explain.

Answer:

Follows are the solution to this question:

Step-by-step explanation:

[tex]Frequency\ total = 155 + 256 + 144 + 145 = 700;[/tex]

In point (1):

Now that it is possible to obtain the joint distribution as:                                                                                                                              

                                 [tex]IT\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ G \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Total[/tex]

[tex]Yes \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{155}{700} = 0.2214\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{256}{700} = 0.3657 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.5871\\\\No \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{145}{700} = 0.2071\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \frac{144}{700} = 0.2057\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.4128\\\\Total \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.4285 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.5714\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1[/tex]

In point (2):

Likely that now It (the IT column total throughout the table above) seems to be the random individual selected = 0.4285;

Here, 0.4285 is the necessary probability.

In point (3):

The way of its worker's sleep at work =0.5871 ( first row total in the above table )

Here 0.5871 was its required probability.

In point (4):

In this as employee slept at work, he is likely to also be from IT to be calculated with:

[tex]=\frac{\text{probability he was just an IT-former but was asleep at work}}{ \text{possibly he worked at work}}\\\\=\frac{0.2214}{0.5871} \\\\ =0.3771 \text{was its probability required here}.[/tex]

In point (5):

In an individual is also an official government, its chance of getting sleep at work is measured when:

[tex]= \frac{\text{Probability he is professional in business slept at work}}{\text{or that he is officially in business}} \\\\= \frac{0.3657}{0.5714}\\\\ = 0.6400 \text{is the required probability here}.[/tex]

In point (6):

[tex]\to P(IT) \ P(Yes) = 0.4285 \times 0.5871 = 0.2516 \\\\\to P(IT and Yes ) = 0.2214 \\\\[/tex]

Therefore, 2 cases aren't independent, because P(IT) P(Yes) is not the same as P(IT and Yes), which also implies that P(IT|Yes) is not the same as P (IT), therefore "[tex]\text{No because P("IT " | "Yes")} \neq P("IT")[/tex]" is correct.

what is 3,000 + 200 + .4 + .06 in standard from

Find the perimeter of the figure. Round to the nearest tenth.
answer.
3 ft
3 ft
20 ft
5 ft
14 ft
Perimeter
feet

someone pls answer this-

4% of what number is 39

HELP PLZ!!!! I will give brainlest
Mr. Olejnik's son is going for a bike ride on his new bike. The cold weather has the tires deflated. Normal pressure is between 35 psi and 60 psi. (50 is ideal). The back tire is currently at 18 psi. If Mr. Olejnik increase the tire pressure by 250%, will this be too much?



Help Please :)

Please please give answer for this question

The number of measles cases increased 33.7% to 220 cases this year. What was the number of cases prior to the increase?

Hello - I'm trying to find the answer for $6,000 x 10% x (1/12) to find the monthly interest rate

which is the product of 15 5\12 A. 5 5\12 B. 6 1\4 C. 7 1\12 D. 7 3\4

A 40-foot pipe is cut into three sections. The longest section is three times as long as the shortest, and the middle-sized section is 5 feet longer than the shortest. Complete the diagram
by giving a and b as expressions involving x. Do not solve the problem.
P = 40 ft
12
X
b
21
X
P
1
a
Length of
middle-sized
Length of
shortest
section
Length of
longest
section
section

If a restaurant purchases organic food there is a 66% chance it will go bankrupt. If a restaurant does not purchase organic food there is a 64% chance it will go bankrupt. Only 12% of businesses purchase organic food. When a restaurant goes bankrupt what is the probability it purchased organic food

Let me know guys pls

A group of 1,254 people are going on a boat tour. If each boat holds 8 people, how many boats will they need?

The average temperature on the surface of the earth is 15 degrees. On the surface of Mars, the average temperature is -50 degrees. What is the difference in these two temperatures? degrees​

There are four primary strategies for determining the area of two-dimensional figures and shapes: a) counting square units, b) subdividing the shape into pieces, finding the areas of the pieces and adding the areas together, c) enclosing the shape in a rectangle, finding the area outside of the shape but inside the rectangle and subtracting, and d) using a formula. Explain each strategy. Use an example for each.

Mother plans to buy 1/2 kilogram of chicken and 2/5 kilogram of beef How many kilograms of meat does she plan to buy?​

How many 1/3 inch cubes does it take to fill a box with width 2 2/3
inches, length 3 1/3 inches, and height 2 1/3 inches?

solve the formula for q

p = 2n + 8q

a. q = p - 2n
b. q = 2n - p / 8
c. q = 2p - n
d. q = 2n - p
e. q = p -2n / 8

please & thank you!!!​

<CEB and BED are adjacent angles ehat is the side common to the two angles?​

Pl help it’s for a grade

1000-(864%2+336%3+648%2)=
​

In the following question, the domain of discourse is a set of students at a university. Define the following predicates: E(x): x is enrolled in the class T(x): x took the test Translate the following English statements into a logical expression with the same meaning.

a. Someone took the test who is enrolled in the class.
b. All students enrolled in the class took the test.
c. Everyone who took the test is enrolled in the class.
d. At least one student who is enrolled in the class did not take the test.

1. Given A = {1,2,3,4}, B ={1,2,4,5), C={3,4,6}, D= {7,8}. U={1,2,3,4,5,6,7,8,9}
What is A UB? Bn C? CD? A'? (A U B)

Instant brainliest please help.

Find the perimeter and area of a rectangle of cardboard measuring 14.1 cm by 6.5 cm

A computer laboratory manager was in charge of purchasing new battery packs for her lab of laptop computers. She narrowed her choices to two models that were available for her machines. Since the models cost about the same, she was interested in determining whether there was a difference in the average time the battery packs would function before needing to be recharged. She took two independent samples and computed the following summary information: Battery Pack Model 1 Battery Pack Model 2Sample Size 9 9Sample Mean 5 hours 5.5 hoursStandard Deviation 1.5 hours 1.3 hoursUsing the null and alternate hypothesis:H0:mu1-mu2=0 vs. Ha: mu1-mu2 not equal 0Calculate the test statistic for this test.

If gasoline costs $3.28 per gallon, how much would 15.5 gallons cost?

In 2002, the population of a town was approximately 34,050. In 2012,
the population of the town had increased to approximately 56,800. Based
on a linear model, what will be the approximate population of the town
in 2020?
Answer choices
A. 52,250
B. 75,000
C. 79,550
D. 99,850

solve

1. 1/3n=4
what is n?
​

aplicaciones de la geometría en la vida​