- A type of elevator called a cage is used to raise and lower miners in a mine
shaft. Suppose the cage carries a group of miners down the shaft. If the
unbalanced force on the cage is 60.0 N, and the mass of the loaded cage is
1.50 10 kg, what is the acceleration of the cage?

Answers

Answer 1
Answer: 0.00276 m/s^2


Related Questions

A boxer hits a punching bag and gives it a change in momentum of 12 kg multiplied by m divided by s over 7.0ms what is the magnitude of the net force on the punching bag

Answers

Answer:

1714N

Explanation:

The change in momentum of an object is the product of mass and the change in velocity

The magnitude of the netforce can be calculated using 12kg/7.0ms

But we can convert 7ms to "s" = 7× 10^-3s

F= Force = 12/7×10^-3= 1714N

Hence, the magnitude of the net force on the punching bag is 1714N

I need help with this, Help me

Answers

Answer:

283.78

Explanation:

A key lime pie in a 10.00 in diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the pie plate moves through a distance of 208 in. Express the angular distance that the pie plate has moved through in revolutions, radians, and degrees. A) Find the angular distance in revolutions, radians and degrees. B)If the pie is cut into 5 equal slices, express the angular size of one slice in radians, as a fraction of .

Answers

Answer:

A

  The distance in revolutions is [tex]n = 7 \ revolutions[/tex]

    The distance in degrees  is  [tex]\theta =2529 ^ o[/tex]

   The distance in radian is  [tex]\theta_{radian } = 44.15 \ rad[/tex]

B

  [tex]\theta_a = 1.26 \ rad[/tex]

Explanation:

From the question we are told that

  The diameter of the pie is  [tex]d = 10.00 \ in[/tex]

  The distance covered by the rim  is  [tex]D = 208 \ in[/tex]

   The number which the pie is divided into  is  k = 5

Generally the radius of the pie is mathematically represented as

      [tex]r = \frac{d}{2}[/tex]

=>  [tex]r = \frac{10}{2}[/tex]

=>  [tex]r = 5 \ in[/tex]

Generally the distance covered by the rim is mathematically represented as

    [tex]D= 2 \pi r n[/tex]

=>  [tex]208 = 2* 3.142 * 5 * n[/tex]

=> [tex]n = 7 \ revolutions[/tex]

Generally converting to  degrees

     [tex]\theta = n * 360[/tex]

=>  [tex]\theta = 7 * 360[/tex]

=>  [tex]\theta =2529 ^ o[/tex]

Generally converting to  radian

   [tex]\theta_{radian } = \frac{\theta * \pi}{180 }[/tex]

=>[tex]\theta_{radian } = \frac{2520 * 3.142 }{180}[/tex]

=>[tex]\theta_{radian } = 44.15 \ rad[/tex]

Generally the angular size of one piece of the pie is  

      [tex]\theta_a = \frac{2 * \pi }{ k}[/tex]

=> [tex]\theta_a = \frac{2 * 3.142}{ 5}[/tex]

=> [tex]\theta_a = 1.26 \ rad[/tex]

(a) The angular distance is 0.168 revolution, 1.056 radians and 60.5⁰.

(b) The angular size of one slice in radians is 2π radian.

The given parameters;

diameter of the pie, d = 10 mradius of the pie, r = 5 mdistance traveled by the rim, d = 208 in = 5.28 m

The angular distance traveled by the pie plate is calculated as follows;

2πr = 5.28

[tex]2\pi = \frac{5.28}{r} \\\\2 \pi = \frac{5.28}{5} \\\\2\pi = 1.056 \ rad\\\\\frac{1 \ rev}{2\pi \ rad } \times 1.056 \ rad = 0.168 \ rev[/tex]

[tex]1.056 \ rad \times \frac{360^0}{2\pi \ rad} = \ 60.5^0[/tex]

Thus, the angular distance is 0.168 revolution, 1.056 radians and 60.5⁰.

The circumference of the pie is calculated as follows;

C = 2πr

C = 2π x 5

C = 10π

Diving the pie into 5 equal slice;

[tex]Fraction \ of \ one \ part \ in \ radian= \frac{10\pi}{5} = 2\pi\ radian[/tex]

Thus, the angular size of one slice in radians is 2π radian.

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what is focus of convex​

Answers

A convex lens is thicker at the centre than at the edges. When parallel rays of light pass through a convex lens the refracted rays converge at one point called the principal focus.

Answer: lens is thicker at the central egde

Explanation:

would someone just answer this now?

Answers

Answer:

x=36.5 m

Explanation:

Rectangular Components of a Vector

A vector can be expressed as an ordered pair (x,y) where x is the x-coordinate, and y is the y-coordinate of a rectangular system.

It can also be given as a magnitude-angle pair (r,θ) where θ is measured from the positive x-axis. It's also known as polar coordinates.

The conversion from polar to rectangular coordinates is:

[tex]x=r\cos \theta[/tex]

[tex]y=r\sin\theta[/tex]

We are given the vector as a magnitude r=47.3 m and at an angle θ=39.4°. The x-component of the vector is:

[tex]x=47.3\cos (39.4^\circ)[/tex]

Using a scientific calculator to find the trigonometric function:

[tex]x=47.3\cdot 0.7716[/tex]

x=36.5 m

A car of mass 500 kg travelling at 36 km/hr brought to
rest over a distance of 40m find the average retraldation and
average braking force​

Answers

Answer:

Explanation:

mass, m = 500 kg

initial velocity, u = 36 km/h = 10 m/s

final velocity, v = 0

distance, s = 40 m

[tex]v^{2} = u^{2} + 2as[/tex]

[tex]0^{2} = 10 ^{2} +[/tex] 2 × a × 40

0 = 100 + 80 a

- 80a = 100 - 0

-80a = 100

a = -100 / 80

a = -1.25 m/[tex]s^{2}[/tex]

force, f = ?

mass = 500 kg

acceleration = -1.25 m/s^2

f = ma

= 500 × -1.25

= -625 N

Hope this helps

plz mark as brainliest!!!!!!!

whats the net force​

Answers

Answer:

13 N to the left

Explanation:

the right side adds up to 1550 13 less than the other side. the box will then be pushed left with 13 newtons of force.

What is SI unit for distance

Answers

Answer:

meter

The SI unit of distance and displacement is the meter [m].

Explanation:

have advancedd

Answer:

meter

Explanation:

it is meter I hope this is helpful

A ball is thrown vertically upwards with a velocity of 50 m/s. calculate
(a) the maximum height to which it rises.
(b) the total time it takes to return to the surface of earth. (take g =10 m/s2 )

Answers

Answer:

Given, For a vertically thrown upward,

          Initial velocity (u) = 50m/s

          Final velocity (v) = 0m/s { ∵ the body is thrown vertically upward }

          Acceleration due to gravity(a) = -(g)= -10m/s²

          Height reached (h) = ? , Time taken (t) = ?

We know that,v² = u²+2as

           or,        0² = (50)²+2×(-10)×h      { ∵ s=h }

           or,        0   = 2500+(-20h)

           or,        0   = 2500-20h

           or,        20h  = 2500

           or,        h   = [tex]\frac{2500}{20\\}[/tex]

                  ∴     h   = 125metres

Also,       v  =  u + at

      or,    0  =  50+(-10)×t

      or,    0  = 50-10t

      or,    10t = 50

      or,    t   = [tex]\frac{50}{10}[/tex]

              ∴   t   = 5seconds   ANS

Hence, The height reached by the ball is 125m and time taken is 5secs.

   

How does a battery supply electrical energy to a circuit?
A. Chemical reactions in a battery cause positively and negatively
charged particles to separate and become concentrated at the
battery terminals.
B. Chemical reactions in a battery cause positively and negatively
charged particles to concentrate in the center of the battery.
C. The force of attraction between positively and negatively charged
particles generates electrical energy within the battery.
O
D. Negatively charged particles that are concentrated at the negative
terminal are repelled from one another, forcing them into a
conducting wire.
ko

Answers

Answer: A.

Explanation:

took the test just now

A battery supplies electrical energy to a circuit Chemical reactions in a battery cause positively and negatively charged particles to separate and become concentrated at the battery terminals. The correct option is A.

What is a chemical reaction?

A chemical reaction is a process in which one or more substances, also known as reactants are converted to one or more different substances, known as products. A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products

Chemical reactions in a battery cause positively and negatively charged particles to separate and become concentrated at the battery terminals resulting in the transformation into electrical energy therefore the correct option is A.

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HELPP!! Does anybody have the answer key to Lab Report: Conservation of Linear Momentum for my online class for physics?? WILL GIVE 80points

Answers

Answer:

Try copy and pasting the intructions it into google, and it should pop up if it exists.

Hope this helps.

Explanation:

Answer:

Send me the download of the lab and I will complete it for you

please help!!! I will mark brainly.
A parachute on a drag-race car opens and changes the velocity of the car from 75 meters per second to 25 meters per second in just 5 seconds. Calculate the acceleration of the car.

Answers

Explanation:

v = u + at

25 = 75 + a * 5

25 = 75 + 5 a

a = 25 - 75/5

a = -50/5

a = -10m/sec^2

please mark me as a brainelist

Describe the importance that keystone species have in the environment. What would happen if these species disappeared? How would it affect the local ecosystems?

Answers

Answer:

See the answer below

Explanation:

The keystone species of an environment are those species of organisms that are highly influential to the functioning of the ecosystem without whom the ecosystem would be drastically affected, lose its structure, or cease to exist totally.

The influence of keystone species in an environment is disproportionately high when compared to their population in the environment. If keystone species disappeared from an environment, such an environment will find it difficult to perform ecosystem functions with an entirely different structure. In some cases, the ecosystem might cease to exist in its entirety because the species that hold it together are no longer present.

A ball thrown vertically upward reaches a maximum height of 30 meters above the surface of Earth. At its maximum height, the speed of the ball is

Answers

Answer:

0 m/s

Explanation:

In this problem,

A ball thrown vertically upward reaches a maximum height of 30 meters above the surface of Earth. We need to find the speed of the ball at the maximum height. When an object reaches its maximum height, after then it starts to decrease its speed. As a result, the speed of the ball will be equal to 0 m/s.

The speed of the ball thrown upwards is zero when the object reaches maximum height.

The given parameter:

maximum height, h = 30 m

The velocity of an object thrown upwards decreases with time because the object is moving against gravity, and the eventually becomes zero when the object reaches maximum height.

[tex]v_f = v_0 - gt= 0[/tex]

Thus, the speed of the ball thrown upwards is zero when the object reaches maximum height.

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The energy released or absorbed by a substance during a change of state

Answers

Answer:

Specific latent heat or specific vaporation vaporization heat

on:

Uses mass only do to no temperature change only state

wo models of the same compound are shown.

A top line labeled Model A saying C subscript 2 H subscript 4 O subscript 2. A bottom image with 2 C's connected by 1 black line. The left C has 3 H's connected to it by 1 black line each and the right C has 2 Os attached to it, the top O by two black lines and the bottom O by 1 black line. The bottom O also has an H attached to it by 1 black line.
In what way is Model B better than Model A?

Model B shows the types of elements in the compound, but Model A does not.
Model B shows the three-dimensional shape of the molecule, but Model A does not.
Model B shows how the atoms in the molecule are connected, but Model A does not.
Model B shows the number of atoms of each element in the molecule, but Model A does not.

Answers

Sorry I didn’t understand

Answer:

its c. , Remember that the answer isnt B. Cause here is proof.

Explanation:

Go to the roller coaster simulation and click on the “launch” button. Pay attention to the pie chart as the roller coaster moves and fill in the blank. Be sure to keep this website open because there will be several questions related to it. The kinetic energy as the roller coaster goes downhill.

Answers

Answer:

increases

Explanation:

Answer:

increases

Explanation:

Describe the motion of an object in which it's speed is constant but the velocity is changing?​

Answers

Answer:

To summarize, an object moving in uniform circular motion is moving around the perimeter of the circle with a constant speed. While the speed of the object is...

What is the magnitude of the initial velocity?

Answers

Magnitude of initial velocity

To calculate the magnitude of the velocity at any point in time, multiply the constant acceleration rate times the time difference and then add it to the initial velocity. As an example, if you dropped a rock off a cliff, its velocity increases by 32 feet per second, every second.

Hope this helps you a lot ...Good day :)

Answer:

magnitude of initial velocity

Explanation:

To calculate the magnitude of the velocity at any point in time, multiply the constant acceleration rate times the time difference and then add it to the initial velocity. As an example, if you dropped a rock off a cliff, its velocity increased by 32 feet per second, every second

Which of these determines an objects ability to sink or float in water?

Group of answer choices

1A. Density

B. Volume

C. Mass

D. Weight

Answers

Answer:

C. Density

Explanation:

Which of the following are examples of Multiple Intelligences:

•being good at sales

•being good at rapping or beatboxing

•being good at math

•all the above

Answers

Answer: All of the above.

Explanation:

Answer : all of the above

An object on Earth weighs 150 N. What is its mass?
15 g
150 kg
150 g
15 kg​

Answers

Answer:

15kg

Explanation:

mass = weight / gravitational field strength

mass = 150 / 9.8 = 15kg (nearest whole no)

The mass of the object on earth whose weight is 150 N will be 15.3 Kg

What is Mass?

Mass is the amount of matter present inside a body. It is defined as the product of density and volume. It remains constant through out the universe. Mathematically -

M = ρV

where -

M is Mass

ρ is density

V is volume

Given is your weight on earth which is equivalent to 150 N.

We know that the weight of of an object is a force exerted by the earth towards its center. It can be written as -

W = mg

Weight of the object = [W] = 150 N

Acceleration due to gravity on earth = [g] = 9.8 m/s²

Substituting the values -

150 = m x 9.8

m = 150/9.8

m = 15.3 Kg

Therefore, the mass of the object on earth whose weight is 150 N will be 15.3 Kg.

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define pressure. write it's Si unit.

Answers

Hi :)

Pressure is the force applied perpendicular to the surface of an object per unit area

The SI unit of pressure is N/m^2

Hope this helps!
The SI unit of pressure is N/m^2

Moon A has a mass of 3M and a radius of 2R. Moon B has a mass of 4M and a radius of R. What is the ratio of the force of gravitational attraction of Moon A for Moon B to the force of gravitational attraction of Moon B for Moon A?

A.) 1:1
B.) 1:5.3
C.) 5.3:1
D.) 0.75:4

Answers

Answer:

c

Explanation:

5.3" (and any subsequent words) was ignored because we limit queries to 32 words.

Under what conditions do rocks experience the strongest physical weathering?

Answers

Answer:

correct me if im wrong but i think its erosion because they are being broken down.

A subway car moves at a constant speed of 10 m/s over a period of 10 s. What is the instantaneous speed halfway through this motion​

Answers

Answer:  10 m/s

We're told the speed is constant, so it's not changing throughout the time period given to us. So throughout the entire interval, the speed is 10 m/s.

Select the correct answer
All of the following will help you safely cool foods EXCEPT:
A After a meal put leftovers in a deep container so the food cools down more slowly.
B Put cold foods away immediately after purchasing.
c.
Nestle a bowl of cold food in a slightly larger bowl of ice during a picnic.
D. Transfer cold foods directly from the refrigerator to the cooler when going out.
If someone knows this answer please help me

Answers

Answer:

I may be a little late, but it's A i got it right on the exam

Explanation:

All of the following will help you safely cool foods except after a meal put leftovers in a deep container so the food cools down more slowly, therefore the correct answer is option A.

What is thermal energy?

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

The option that will help you safely cool foods is by putting cold foods away immediately after purchasing, Nestle a bowl of cold food in a slightly larger bowl of ice during a picnic, and Transferring cold foods directly from the refrigerator to the cooler when going out.

The right response is A, option a since all of the options will help you safely cool meals, with the exception of putting leftovers in a deep container after a meal to allow them to cool more slowly.

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ILL GIVE YOU ANYTHING TO ANSWER THIS!! IM HELPING MY CRUSH AND IDK THE ANSWER TO THIS PLZ HELP!

Answers

C is your answer. PH is an acidic trait used to define just how acidic an acid is. Since you are classifying an acid it would go in C with PH.

What is the common property of the elements pinctogen

Answers

Answer:

The pnictogens consist of two non-metals, two metalloids, one metal, and one element with unknown chemical properties. All the elements in the group are solids at room temperature, except for nitrogen which is gaseous at room temperature.


9. An object is launched at a velocity 40m/s in adirection making an angle of 60° upward with the horizontal.

a)what is the maximum height reached by the object?
b)what is the time of the object?
c)what are the horizontal and vertical componenet of vectors?

Answers

Answer:

a) 61.224 m

b) t = 7.070 seconds

c) horizontal component = 20 m/s; vertical component = 34.641 m/s

Note: I rounded all of these values to the nearest thousandth but if you want the precise values please read the explanation below.

Explanation:

Horizontal and Vertical Components:

Let's start this problem by solving for the horizontal and vertical components of the initial velocity vector.

We can solve for these x- and y-components by using the formulas:

h. component: [tex]v_i \times cos \theta[/tex]v. component: [tex]v_i \times sin \theta[/tex]

Where [tex]v_i[/tex] is the initial velocity (here it's given to us: 40 m/s) and [tex]\theta[/tex] is the angle at which the object is launched above the horizontal (it's also given to us: 60°).

Substitute these given values into the formulas to solve for the horizontal and vertical components:

h. component = [tex]40 \times $cos(60)[/tex] v. component = [tex]40 \times $sin(60)[/tex]

Input these values into a calculator and you will get:

h. component  = 20 m/sv. component = 34.641 m/sTime of the Object:

Now we want to solve for the time t of the object before finding the maximum height of the object. In other words, the max height of the object is its vertical displacement at half of the time t we're about to find.

In order to solve for t, we can use one of the constant acceleration equations we are given in Physics. This equation is:

[tex]v_f=v_i+at[/tex]

The time t is always solved for by using the vertical (y-direction) motion of the object in projectile motion, so therefore, we are going to be using this equation in terms of the y-direction.

[tex](v_f)_y = (v_i)_y + a_yt[/tex]

Time is the same regardless of the x- or y- direction.

Now, we don't necessarily know the final velocity of the projectile, but we do know its final velocity in the y-direction at the very top of the trajectory, which is 0 m/s.

We can use this to our advantage and solve for only half of the time t, then multiply it by 2 at the end to get the full time that the object is in the air.

We have already solved for [tex](v_i)_y[/tex], which is the vertical component. We know that an object in projectile motion has an acceleration of -g in the y-direction, so we use -9.8 m/s² for a.

[tex]0=(40\times $sin(60)) + (-9.8)t[/tex]

Subtract the vertical component from both sides of the equation.

[tex]-(40 \times $sin(60))= -9.8t[/tex]

Divide both sides of the equation by -9.8 in order to solve for t.

[tex]\text{t}=3.534797566\ \text{seconds}[/tex]  

Remember that this is only half of the time that the object spends in the air. However, this is the time that it takes for the object to reach its maximum height, which we will use later. For now, let's say that the time of the object is 2t.

[tex]\text{2t = 7.069595132 seconds}[/tex] Maximum Height of the Object:

In order to find the maximum height of the object, let's use another kinematic equation for constant acceleration:

[tex]$x_f=x_i+v_it+\frac{1}{2} at^2[/tex]

Since we are still dealing with the y-direction, we can change this equation to be in terms of y.

[tex]$(x_f)_y = (x_i)_y + (v_i)_yt + \frac{1}{2} a_yt^2[/tex]

The displacement in the y-direction, or the vertical displacement, can be modeled by subtracting [tex](x_i)_y[/tex] from both sides of the equation.

[tex]$\triangle x_y = (v_i)_yt + \frac{1}{2} a_yt^2[/tex]

In order to solve for the maximum height of the object, we want to use the time t that it takes for the object to reach its highest point, which we found was ~3.53 seconds. This is true because the object essentially follows the movement of a parabola.

We know the vertical component [tex](v_i)_y[/tex] , and we know the acceleration in the y-direction is -g, so let's substitute these values into the formula for vertical displacement and solve for [tex]\triangle x_y[/tex].

[tex]$\triangle x_y = (40 \times \text{sin}(60))(3.534797566) + \frac{1}{2} (-9.8)(3.534797566)^2[/tex] [tex]$\triangle x_y = (122.4489796) + \frac{1}{2} (-9.8)(3.534797566)^2[/tex] [tex]$\triangle x _y = (122.4489796) -(4.9 \times 3.534797566^2)[/tex] [tex]$\triangle x_y = (122.4489796) - (61.22448978)[/tex] [tex]$\triangle x_y = 61.2244898[/tex]

The maximum height of this object in projectile motion is 61.224 m.

(This answer exceeded the character limit if I included the "Helpful Shortcuts" section, so I included it as an attachment in case you're interested.)

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