A small sphere of mass 10 kg
is released from rest at a height of
15.0 m above the ground level.
The sphere experiences a constant
resistive force (due to air
resistance) of magnitude R = 10.0
N.
a) Calculate the speed of the
sphere after it has fallen
through a distance of 5.00 m

bCalculate the speed of the ball just before a it hits the gound.

Answer:

45° to min.

1° ----> 60 min

45° ----> ?.

45 * 60

2700 min

The net force on q2 will be 1.35 N

A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.

Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.

We have to find the net force on q2

At first we will find Force due to q1

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²

F = 450 × 10⁻³

F₁ = 0.45 N (+)

Now we will find Force due to q2

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²

F = 1800 × 10⁻³

F₂ = 1.8 N (-)

So net force (F) will be

F = F₂ - F₁

F = 1.8 - 0.45

F = 1.35 N

Hence the net force on q2 will be 1.35 N

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Answer:

C probably

Explanation:

think c because when you first start the car the first thing you hear electrical sound.

Plugging in a lamp is not an example of Static electricity. Thus, the correct option is C.

Static electricity may be defined as the consequence of an imbalance between negative and positive charges in an object. It does not involve the direct flow of electrons throughout a wire.

Clothes sticking together in the dryer and getting shocked when you touch a doorknob are examples of static electricity while plugging in a lamp is an example of mobile electricity that mediates the direct flow of electrons to generate an electric current and as a result, the lamp glows.

Therefore, the correct option for this question is C.

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Answer:

D

Explanation:

F = G m1 m2 / r^2       now double  r

 F =  G m1m1/ (2r)^2

    F =  1/4  G m1m2/r^2     <===== this is 1/4 of the original

Answer:

50km/h

Explanation:

average = (a + b) / 2

average = (60 + 40) / 2

average = 50

Answer:

4.2 A

Explanation:

V=IR

V= voltage

I= Current

R= resistance

so you will find the resistance in the circuit so

R= V/I

R=2V/0.70A

R=2.857 ohms ( TO THE NEAREST THOUSANDTH)

then you will find the current of the 12V battery using the resistance in the circuit

I=V/R

I=12/2.857

I=4.2A (TO THE NEAREST TENTH)

The estimated density of the golf ball is  170  kg/m³

What is density?

Density is the ratio as Mass per unit Volume.

In displacement method,  

First , we measuring the volume of water displaced by an object which tell us the volume of the object then we will use the physical balance to determine its mass.

Then calculate the density by dividing the mass by the volume.

Here,  D = m/V

By displacement method , the estimated volume of golf ball is 100 cm³  and estimated mass is 600 g

Then ,

Density =  100 cm³ / 600 g = 0. 17 g/ cm³ = 170  kg/m³

So the estimated density of golf ball is  170  kg/m³

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a. The spring is compressed  by  0.174 m.

b.  The vertical distance the dart travels from its position when the spring is compressed to its highest position is 9.6 m.

c. The horizontal velocity of the dart at that time is  13.74 m/s.

d. The horizontal distance from the equilibrium position at which the dart hits the ground is 19.236 m.

The energy by virtue of its position is called the potential energy.

a. Given is the potential energy stored in the compressed spring of a dart gun, with a spring constant of 62.00 N/m, is 0.940 J.

PE  of spring = 1/2 kx²

Put the values, we get

P.E = 0.940 = 1/2 x 62 x²

x = 0.174 m

Thus, the spring is compressed by 0.174 m.

b. Given is a 0.010 kg dart is fired straight up.

The vertical height is find out by

0.940 J = (0.010 kg) (9.8 m/s²) h

h = 9.6 m

Thus, the vertical distance the dart travels from its position is 9.6 m

c. From the conservation of energy principle, total mechanical energy is conserved.

1/2 mv² =mgh

v = √2gh

Plug the values, we get

v = √2 x 9.8x 9.6

v = 13.74 m/s

Thus, the horizontal velocity is  13.74 m/s.

d.  Time that dart spends in air, t = √2h/g

t = √(2x9.6)/9.81

t = 1.4 s

The horizontal distance from the equilibrium position at which the dart hits the ground.

Horizontal distance = (Velocity on x direction) x time

Horizontal distance = 13.74 m/s x 1.4s

Horizontal distance = 19.236 m

Thus, the horizontal distance is 19.236 m.

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The acceleration will be constantly equal to 1 m/s².Option c is correct.

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Given data;

Force,F = 350 N

Friction force,f=350 N

F=f

Because the frictional and applied forces on the two boxes are of equal strength, both move at the same pace. As a result, the acceleration will be constantly equal to 1 m/s².

Hence option c is correct.

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The magnitude and direction of the resultant velocity of the car will be 169.70 km/h and 45°.

The quantity which has magnitude, direction and follows the law of vector addition is called a vector.

A car traveling at 120 km/h towards west makes a right turn and travel north without changing its speed.

Then the magnitude (R) will be

R² = 120² + 120²

R² = 28800

R = 169.70 km / h

Then the direction of the resultant velocity will be

tan θ = 120 / 120

tan θ = 1

tan θ = tan 45°

     θ = 45°

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A tennis ball is hit by a large force so that it goes up into the air and then it comes back straight down because of gravity.

We know that objects move upward due to application of force on it while on the other hand, object comes to the ground because of the attraction of earth which we called gravity.

So we can conclude that a tennis ball is hit by a large force so that it goes up into the air and then it comes back straight down because of gravity.

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The work done by the force to stretch the spring is determined as 12.5 J.

The work done by the force to stretch the spring is calculated as follows;

W = ¹/₂Fx

F = kx

W = ¹/₂F(F/k)

W = ¹/₂F²/k

W = ¹/₂ x (50²)/100

W = 12.5 J

Thus, the work done by the force to stretch the spring is determined as 12.5 J.

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The work done by the electric field on the proton when it reaches the positive plate willl be 9.1 ×10⁻¹⁵ J.

A physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field, either attracting or repelling them, is referred to as an electric field,

The electric field formula is as follows:

E = F /Q

Where,

The electric field is denoted by the letter E.

F is a powerful letter.

The charge is Q.

The potential difference between the plate;

[tex]\rm V = E d \\\\ V = 3.40 \times 10^6 \times 0.13 \ m \\\\ V= 442000 \\\\ V = 4.42 \times 10^5 \ v[/tex]

Force on the charged particle ;

[tex]\rm F = qV \\\\ F= 1.6 \times 10^{-19} \times 4.42 \times 10^ 5 \\\\\ F = 7.0 \times 10^{-14} \ N[/tex]

Work done in  order to move the charge;

[tex]\rm W = F \times d \\\\ W= 7.0 \times 10^{-14} \ N \times 0.13 m \\\\ W=9.1 \times 10^{-15} \ J[/tex]

Hence, the work done by the electric field on the proton when it reaches the positive plate willl be 9.1 ×10⁻¹⁵ J.

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They use less wire, A

Explanation:

it is almost zero .this is because the distance and the electrostatic force are inversely proportional

Answer

688.32m and 277.44m

Explanation :

⠀

[tex] \large{\maltese{\textsf{\underline{To find :-}}}} [/tex]

The X and Y coordinates of the rocket relative of firing

⠀

⠀

[tex] \large{\maltese{\textsf{\underline{Given :-}}}} \\ \\ \sf velocity (v_i) = 100m{s}^{-1} \\ \sf angle ({\theta}_{1}) = 55.0{\degree} \\ \sf time (t) = 12s [/tex]

⠀

⠀

[tex] \Large{\maltese{\textsf{\underline{\underline{Step by Step Solution:-}}}}} [/tex]

⠀

⠀

The horizontal range of projectile at x.

⠀

[tex] \sf \large{x = v_{xi}} \times t \\ \\ \sf \large{x = v_i \times \cos {\theta}_{i} \times t} [/tex]

⠀

⠀

[tex] \large\textsf{\underline{Now substituting the required values}} [/tex]

⠀

⠀

[tex] \sf x = 300 \times \cos 55{\degree} \times 12 \\ \\ \sf x = 100 \times 0.5756 \times 12 \\ \\ {\underline{\boxed{\bold{ x = 688.32m}}}} [/tex]

⠀

⠀

The vertical position of projectile at y.

⠀

⠀

[tex]\sf \large y = v_{yi} \times t - (\frac{1}{2} \times g \times {t}^{2}) \\ \\ \sf \large y = v_i \times \cos \theta \times t - \frac{1}{2} g {t}^{2} [/tex]

⠀

⠀

[tex]\textsf{ \large {\underline{Now substituting the required values}} } [/tex]

⠀

⠀

[tex] \sf y = 100 \times \cos55{ \degree} \times 12 - \frac{1}{2} \times 9.80 \times {12}^{2} \\ \\ \sf y = 100 \times 0.8192 \times 12 - 0.5 \times 9.8 \times 144 \\ \\ \sf y = 983.04 - 705.6 \\ \\ \underline{ \boxed{ \bold{y = 277.44m}}} [/tex]

⠀

⠀

⠀

Answer:

Explanation:

Force:

⇒ Mass × Acceleration

Work Done:

⇒ Force × Distance

Calculations:

⇒ Force = 0.0083 × 7000 N

⇒ Work done = 0.0083 × 7000 × 5.8 × 10^4 Joules

The allowable ampacity of a No. 12 copper wire with type THHN insulation installed in a raceway with 35 wires is approximately 12 amperes. This is best represented by option D.

According to the National Electrical Code Table (NEC), a derating factor must be applied for any raceway with more than three current-carrying conductors (in our case, copper wires). In a raceway with 31-40 current-carrying conductors, the derating factor is 50%. Because the ampacity of a No. 12 copper wire usually is 25 amperes (A), we can multiply this by our derating factor to find that:

25 • 0.50 = 12.5

The exact allowable ampacity of this copper wire is 12.5 amperes; however, we can round down to find that the closest answer is 12 A.

Hence, option D represents the best answer.

Answer:

  D)  12 A

Explanation:

You want to know the allowable ampacity of AWG 12 type THHN copper wire in a raceway with 35 wires.

Table 310.15(B)(16) of the 2017 National Electrical Code gives the nominal rating of AWG 12 type THHN copper wire as 30 A when installed in an environment with a temperature of 30 °C or less.

Table 310.15(B)(3)(a) gives the adjustment factor when there are more than three conductors in a raceway or cable. For 31–40 conductors, the ampacity must be derated to 40% of its nominal value.

In a raceway with 35 wires, the allowable ampacity of THHN AWG 12 wire is ...

  (30 A)(0.40) = 12 A

__

Additional comment

For environmental temperatures above 30 °C, Table 310.15(B)(2)(a) gives additional derating factors. The adjustment factor for temperatures up to 50 °C (122 °F) is 0.82, which would bring the allowable ampacity down to about 9.8 A.

(a) The equilibrant C for force of vector A and B is 3.43 N.

(b) The equilibrant C for fx of vector A and B is 2.1 N.

(c) The equilibrant  C, for fy of vector A and B is 2.12 N.

An equilibrant force is a single force that will bring other bodies into equilibrium.

Vector A: mass = 0.2 kg, θ = 20⁰

Vector B: mass = 0.15 kg, θ = 80⁰

Fx = mg cosθ

Fy = mg sinθ

where;

Force of A due to its weight

F(A) = mg

F(A) = 0.2 x 9.8 = 1.96 N

Fx = (0.2 x 9.8) cos(20) = 1.84 N

Fy = (0.2 x 9.8) sin(20) = 0.67 N

R = √(0.67² + 1.84²)

R = 1.96 N

Force of B due to its weight

F(B) = mg

F(B) = 0.15 x 9.8

F(B) = 1.47 N

Fx = (0.15 x 9.8) cos(80) = 0.26 N

Fy = (0.15 x 9.8) sin(80) = 1.45 N

R = √(0.26² + 1.45²)

R= 1.47 N

Equilibrant force:

Force, C = 1.96 N + 1.47 N

Force, C = 3.43 N

Equilibrant FX:

Fx, C = Fx(A) + Fx(B)

Fx, C = 1.84 N + 0.26 N = 2.1 N

Equilibrant FY:

Fy, C = Fy(A) + Fy(B)

Fy, C =0.67 N + 1.45 N = 2.12 N

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A valve placed is before the rotameter to regulate the flow of liquid entering the extraction bed. The correct option is c.

Control valves are generally used to maintain a flow as close as possible to the desired value.

Valves positioned before the rotameter for throttling purposes. A control valve will regulates the rate of fluid flow. Control valves control typically flow rate, pressure, and temperature.

Thus, the correct option is c.

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Answer:

it will float

Explanation:

according to Archimedes' principle, if the buoyant force is equal to the weight of the mass of the object, the object will float

Bianca is helping the theatre director at her school with lighting, sound, and set design for a school play. She will be choosing the materials that will be used on stage and on the walls of the theatre the materilas neee to be changes is The only lights available are white, purple, and yellow.

A proper echo is a single mirrored image of the sound source. The phrase echo derives from the Greek ἠχώ (ēchō), itself from ἦχος (ēchos), "sound". Echo withinside the Greek peoples tale is a mountain nymph whose cappotential to talk changed into cursed, leaving her capin a position handiest to copy the ultimate phrases spoken to her.

Bianca draws a detailed illustration of her plan to show the theatre director. She labels it with the materials she plans to use the  only lights available are white, purple, and yellow should be removed as to avoid the light refraction.

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Answer:

ways can carry either __machanical___ or electromagnetic energy

The final common speed of the two carts will be 69.3 m/sec.The momentum conservation principle is applied.

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

Unit conversion:

1 metric tons = 1000 kg

Given data;

m₁= 11.6 metric ton =11600 kg

m₂ = 23.2 metric ton =  23200 kg

Let v represent the combined velocity of the two carts once they are connected, and let u represent the starting velocity of cart 1 when it reaches the bottom.

Considering energy conservation;

[tex]\rm m_1 g h = \frac{1}{2} m_1 \times u^2 \\\\ u^2 = 2gh\\\\ u^2 = 2 \times 9.8 \times 10.6 \\\\ u = 207.972 \ m/s[/tex]

From the conservation of momentum principle;

[tex]\rm m_1 \times u = (m_1 + m_2) v\\\\ 11600 \times 207.972 = (11600 + 23200) \times v \\\\ v = 69.3 \ m/s[/tex]

Hence, the final common speed of the two carts will be 69.3 m/sec.

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The statement best describes how upwelling occurs is Upwelling causes nutrients, minerals, and tiny organisms to rise. The correct option is C.

Upwelling occurs when winds push surface water away from the shore and deeper water rises to fill the gap.

The upwelling is a cycle that shows up in the water bodies all over the planet. This cycle is basically addressing the ascending of the virus waters towards the surface where there's hotter environment, subsequently hotter water also.

With the ascent of the virus waters towards the surface, everything with it ascend also. The virus waters are plentiful in supplements and minerals, as well as minuscule creatures, like the Phyto-microscopic fishes.

This is a cycle that is vital for the presence of the environments in the bigger water bodies.

Thus, the correct option is C.

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Some words that have changed meaning due to technological advances are dial, type, tweet, drone, and spam.

Answer:

Magnification= -image distance/object distance

.253=image distance/33.5

image distance= 8.48 cm

[tex] \color{skyblue}{ \underline{ \frak { \: option \: ( \: c \: ) = 2 \: hertz ✓}}}[/tex]

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Given :

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[tex] \: \: [/tex]

We, have to find frequency :

[tex] \: [/tex]

[tex] \: \: [/tex]

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