Answer:
The tension in the rope if it is parallel to the slope is 24.31 N.
Explanation:
Given;
mass of the sled, m = 9 kg
angle of inclination of the slope, θ = 16⁰
The tension in the rope if it is parallel to the slope is calculated from the parallel component of the tension;
[tex]T_|_| = mgSin \theta\\\\T_|_| = 9 \times 9.8 \times sin(16^0)\\\\T_|_| = 24.31 \ N[/tex]
Therefore, the tension in the rope if it is parallel to the slope is 24.31 N.
An equipotential surface that surrounds a point charge q has a potential of 536 V and an area of 1.20 m2. Determine q.
Answer:
q = 1.84×10^-8coulombs
Explanation:
Surface area = 4πr²
r is the distance
1.2 = 4(3.14)r²
1.2 = 12.56r²
r² = 1.2/12.56
r² = 0.0956
r = √0.0956
r = 0.309m
Get the charge C
V = kq/r
536 = 9.0×10^9q/0.309
536×0.309 = 9×10^9q
165.73 = 9×10^9q.
q = 165.73/9×10^9
q = 1.84×10^-8coulombs
Jail
1. What is the momentum of a 4 kg bowling ball moving with a speed of 4 m/s?
a. 16 kg•m/s
b. 8 kg•m/s
c. O kg•m/s
d. 1 kg•m/s
Answer:
c.o Kg • ms 08
Explanation:
put all together
The answer is option c) 0 kg m/s
What is momentum ?It is a property of moving body by virtue of its mass and motion and that is equal to the product of the body's mass and velocity
momentum = mass * velocity
since , momentum is a vector quantity
in order to calculate momentum we need one of the quantity to be vector since , mass can never be vector as it is a scaler quantity we need to use velocity ( vector quantity ) not speed ( scaler quantity ) as multiplication of two scalers can never give rise to a vector quantity
so, the answer is option c) 0 kg m/s
Learn more about momentum
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A man walks 40 m North, then 70 m East and then 40
m south. What is his displacement
from the starting point?
Answer:
Displacement = 70 m towards east
Explanation:
Displacement is the shortest distance between the two points.
Let us say that he starts at the point O and travels in a path ABC.
If we join the initial and final point of the path travelled by him, it will give the displacement of the man.
Distance from O to A = 40 m
Distance from A to B = 70 m
Distance from B to C = 40 m
Distance from O to A = Distance from B to C
We want the displacement which is distance between the points O and C
In rectangle opposite sides are equal. Hence Distance from O to C = Distance from A to B
Displacement = Distance from A to B
Hope it helps,
Please mark me as the brainliest.
Thank you
Answer:
Displacement = 70 m towards east
Explanation:
2. Write an expression for the work
done when a force is acting on
an object in the direction of its
displacement
Answer:
work done=Fs
Explanation:
F : force
s : displacement
by definition
Messages from the Perseverance Rover on Mars reach Earth in 11 min. The speed of light is 3.00 x 108 m/s. Using this information, how far is Mars from Earth?
Answer:
[tex]d=1.98\times 10^{11}\ m[/tex]
Explanation:
Messages from the Perseverance Rover on Mars reach Earth in 11 min i.e. time is 660 s
The speed of light is [tex]3\times 10^8\ m/s[/tex]
We need to find the distance between Mars and Earth. Let the distance be d.
We know that,
Distance = speed × time
So,
[tex]d=660\times 3\times 10^8\\\\d=1.98\times 10^{11}\ m[/tex]
So, Mars is [tex]1.98\times 10^{11}\ m[/tex] from the Earth.
Pls help me I’m failing
Answer:
A is the answer okkkkkkkkkkkkkkkk
If you were to stand in the exact center of a rotating disc, you would only have what kind of
speed?
Tangential speed
Increasing speed
Linear speed
Rotational speed
Answer:
Tangential speed or Rotational speed
How are decompression and how gasses dissolve in liquids related? Explain in your own words.
The resolution of a telescope is ultimately limited by the diameter of its objective lens or mirror. A typical amateur astronomer's telescope may have a 6.09 in diameter mirror. What is the minimum angular separation (in arc seconds) of two stars that can be resolved with a 6.09 in scope
Answer:
θ = 3.19 arc second
Explanation:
The resolution of a telescope is given by the rayleigh criterion, which establishes that two objects are separated if the principal maximum of diffraction of one of them coincides with the first minimum of diffraction of the second object, based on this the solution is given by the first diffraction minimum, the a slit is
a sin θ = m λ
with m = 1
in the case of circular apertures the equation must be found in polar coordinates, therefore a numerical constant is introduced
a sin θ = 1.22 λ
Angles are measured in radians and in these experiments they are small
sin θ = θ
θ= 1.22 λ / a
in this case a = 6.09 in, the wavelength is wrong = 550 10⁻⁹ m which is the maximum resolution of the human eye
l
et's reduce the magnitudes to the SI system
d = 6.09‘ 2.54 10⁻-2 m / 1 inch = 15.4686 10-2 m
let's calculate
θ = 1.22 550 10-9 / 15.468 10-2
θ = 15.5 10⁻⁶ rad
rad = 2.06 105 s
θ = 15.5 10⁻⁶ rad 2.06 105s/ 1 rad
θ = 3.19 s
Albert's laboratory is filled with a constant uniform magnetic field pointing up everywhere. Into this magnetic field albert throws some charges. He throws the charges in different directions, and observes the resulting magnetic forces on them. Given the sign of each charge and the direction of its velocity, determine the direction of the magnetic force (if any) acting on the charge.
Resulting magnetic force:
Positive charge moving south:
Negative charge moving west:
Negative charge not moving at all:
Positive charge moving up:
Positive charge moving east:
Negatve charge moving down:
Negative charge moving north:
Positive charge not moving at all:
Positive charge moving west:
Negative charge moving south:
Negative charge moving east:
Positive charge moving north:
options: up, down, no force, north, south, east, west
Answer:
Follows are the solution to this question:
Explanation:
The magnetic force is parallel to a [tex]\bar{V} \times \bar{B}[/tex] axis, through right law. The direction would be in a reverse way for a positive particle. The gravitational flux is upward.
1) Its magnet strength will be directed westward.
2) The [tex]\bar{V} \times \bar{B}[/tex] path is parallel to the east. The permanent magnet is oriented against the south so because the object is considered impolite.
3) Its gravitational field of the velocity v of the object is zero. Thus no force was its solution.
4) The magnetic field and velocity are all on the same track. The magnetic strength is also zero. Consequently, the answer is no power.
5) Its gravitational field is to the south.
6) Its magnetic field, as well as the speed, are different. Which magnet strength is also zero. Consequently, no power is the answer.
7) Accessible in French only. The [tex]\bar{V} \times \bar{B}[/tex] direction parallel to the east. Its magnetic energy is guided west because the particle is charged negatively.
8) Unless the particle velocity is 0, the magnetic strength is 0. Consequentl, no power is the response.
9) Its magnet power is from the north.
10) Another one of these: The [tex]\bar{V} \times \bar{B}[/tex] is parallel to the west. Its gravitational field is oriented to the east as the object is negatively charged.
11) The Pope said the following: The [tex]\bar{V} \times \bar{B}[/tex] direction is parallel to the south. The gravitational fluid is transmitted towards the North because a particle is considered impolite.
12) The gravitational field is from the east.
what's the dimension symbol for amount of substance
Answer:
The mole (symbol: mol) is the unit of measurement for amount of substance in the International System of Units (SI). It is defined as exactly 6.022 140 76 × 1023 particles, which may be atoms, molecules, ions, or electrons.
Explanation:
what is the average speed of a bird that flies 1 km in 5 hours?
Answer:
0.25 or 1/4
Explanation:
................
. A single strand of wire of adjustable length is wound around the circumference of a round balloon that has a diameter of 21.0 cm. A uniform magnetic field with a magnitude of 1.40 T is perpendicular to the plane of the loop. If the balloon is blown up such that its diameter and the diameter of the wire loop increase to 31.0 cm in 0.048s, what is the magnitude of the average value of the emf induced in the loop
Answer:
EMF = 1.1929 V
Explanation:
In this case we need to use the following expression:
EMF = B *ΔA / t (1)
Where:
B: Magnetic field
ΔA: Difference of area of the balloon
t: time
To get the area, we have the innitial diameter of the balloon, and the expanded diameter when the balloon is blown up, so, assuming the circunference of the balloon, the area can be determined with:
A = π r² (2)
So, let's calculate the Area of the balloon before and after the blown. Remember to use the units in meter (I just divided the diameter by 2 to get the ratio, and then divide by 100 to convert the units of cm to m)
A₁ = π * (0.105)² = 0.0346 m²
A₂ = π * (0.155)² = 0.0755 m²
Now that we have both areas, let's calculate ΔA:
ΔA = A₂ - A₁
ΔA = 0.0755 - 0.0346 = 0.0409 m²
Finally, we can determine the value of the EMF, using (1):
EMF = 1.4 * 0.0409 / 0.048
EMF = 1.1929 VHope this helps
Will mark BRAINLYEST
Answer:
A dribble ends when the player touches the ball with both hands simultaneously or permits the ball to come to rest in one or both hands. The ball being touched with both hands simultaneously (dribble with both hands) is a double dribble
Nothing in the rulebook that says a player cannot start a dribble with two hands. A dribble can end when touching both hands simultaneously, but a single dribble is OK as long as you catch the ball
Explanation:
Answer:
No, so it's false you're correct.
Hope this helped
A dry cell is used in a flashlight to convert to light.
a. electrical energy
b. static electricity
Answer:
Electrical energy this is because when the flashlight us turned on the chemical energy stored in the battery is converted to electrical energy that flows through the wire of the flashlight
The torque required to turn the crank on an ice cream maker is 4.50 Nm. How much work does it take to turn the crank through 300 full turns?
A) 4240 J
B) 8480 J
C) 2120 J
D) 1350 J
E) 2700 J
Answer:
B) 8480 J
Explanation:
From the question,
The work required to turn the Crank in on turn is
W = 2πT................ Equation 1
Where W = work, T = torque.
Given: T = 4.50 Nm, π = 3.14
Substitute into equation 1
W = 4.5(2)(3.14)
W = 28.26 J per turn.
For 300 full tern,
W = 28.26×300
W = 8476 J
Hence,
W≈ 8480 J.
The right answer is B) 8480 J
In SI units, what is the magnitude the net force acting on a 1,152 kg car that accelerates uniformly along a straight line from a speed of 3 m/s to a speed of 17 m/s in 5s?
Answer:
Fnet = 14515.2 Newton
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
[tex] Fnet = Fapp + Fg[/tex]
Where;
Fnet is the net force. Fapp is the applied force. Fg is the force due to gravitation.Given the following data;
Mass = 1,152 kg
Initial velocity, u = 3m/s
Final velocity, v = 17m/s
Time, t = 5 seconds
To find the magnitude of the net force;
First of all, we would determine the acceleration of the car.
Acceleration = (v-u)/t
Acceleration = (17 - 3)/5
Acceleration = 14/5
Acceleration = 2.8m/s
To find the applied force;
Fapp = mass * acceleration
Fapp = 1,152 * 2.8
Fapp = 3225.6 N
Next, we would find the force exerted on the car due to gravity.
Fg = mass * acceleration due to gravity
We know that acceleration due to gravity is equal to 9.8m/s²
Fg = 1152 * 9.8
Fg = 11289.6N
Substituting the values into the equation, we have;
Fnet = 3225.6 + 11289.6
Fnet = 14515.2 Newton
An object is dropped from a bridge. A second object is thrown downwards 1.0 s later. They both reach the water 20 m below at the same instant. What was the initial speed of the second object? Neglect air resistance.
Answer:
15m/s
Explanation:
[tex]20m = \frac{1}{2} g {t}^{2} \\ t = 2s \\ t0 = 2s - 1s = 1s \\ vt + \frac{1}{2} g {t}^{2} = 20m \\ v \times 1s + \frac{1}{2} \times 10 \times 1 = 20 \\ v = 15[/tex]
How does Physics help you as a student?
Answer:
The goal of physics is to understand how things work from first principles. ... Courses in physics reveal the mathematical beauty of the universe at scales ranging from subatomic to cosmological. Studying physics strengthens quantitative reasoning and problem solving skills that are valuable in areas beyond physics
Answer:
you get to understand why things happen this way
Explanation:
for example, are you not curious about why when standing in the bus and when the bus stops, you will might feel like you are going to fall ,
why does this happen because....
newton's laws explains it,
inertia causes you to be reluctant to change your initial state of motion due to your mass so you fall because you are still moving at the 'speed of the bus ' , something in like that
hope this helps,
please mark also
.You have always been impressed by the speed of the elevators in your apartment building. You wonder about the maximum acceleration for these elevators during normal operation, so you decide to measure it by using your bathroom scale. While the elevator is at rest on the ground floor,you get in, put down your scale, and stand on it. The scale reads 50 kg. You continue standing on the scale when the elevator goes up, carefully watching the reading. During the trip to the 10th floor, the greatest scale reading was
Answer:
5.51 m/s^2
Explanation:
Initial scale reading = 50 kg
assume the greatest scale reading = 78.09 kg
Determine the maximum acceleration for these elevators
At rest the weight is = 50 kg
Weight ( F ) = mg = 50 * 9.81 = 490.5 N
At the 10th floor weight = 78.09 kg
Weight at 10th floor ( F ) = 78.09 * 9.81 = 766.11 N
F = change in weight
Change in weight( F ) = ma = 766.11 - 490.5 (we will take the mass as the starting mass as that mass is calculated when the body is at rest)
50 * a = 275.61
Hence the maximum acceleration ( a ) = 275.61 / 50 = 5.51 m/s^2
pdf
Due date: February 22, 2021
10:00 AM EST
5: Holt SF 05Rev 43 - 10.0 pts possible
A 0.290 kg block on a vertical spring with a
spring constant of 4.65 x 103 N/m is pushed
downward, compressing the spring 0.0500 m.
When released, the block leaves the spring
and travels upward vertically.
The acceleration of gravity is 9.81 m/s.
How high does it rise above the point of
release?
Answer in units of m.
x x
True or False 1-10
1. When air temperature falls, the air can hold more water vapor.
2. Cloudy days tend to have a greater range of temperatures than clear days.
3. Water vapor condenses when air temperature reaches the dew point.
4. A cloud consists of billions of individual water droplets.
5. Dust or other particles are needed for clouds to form.
6. Only high clouds consist of ice crystals.
7. Stratocumulus clouds rarely bring precipitation.
8. Advection fog forms when warm humid air travels up a hillside and cools.
9. All precipitation falls from clouds.
10. Hail forms in cumulonimbus clouds with strong updrafts.
Answer:
in order of questions asked:
f
t
t
t
t
t
f
t
f
t
When air temperature falls, the air can hold more water vapor, this statement if false because air doesn't hold more water in this case.
Cloudy days tend to have a greater range of temperatures than clear days. This assertion is true.
Water vapor condenses when air temperature reaches the dew point. This assertion is true.
A cloud consists of billions of individual water droplets. This assertion is true
Dust or other particles are needed for clouds to form. This assertion is true.
Only high clouds consist of ice crystals. This assertion is true.
Stratocumulus clouds rarely bring precipitation. This assertion is false.
Advection fog forms when warm humid air travels up a hillside and cools. True.
All precipitation falls from clouds. False.
Hail forms in cumulonimbus clouds with strong updrafts. True.
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what is the effect of divorce on females?
Answer:
Numerous studies have shown that the economic costs of divorce fall more heavily on women. After separation, women experience a sharper decline in household income and a greater poverty risk (Smock 1994; Smock and Manning
Answer:
sadness and stress...................
A piece of glass with index of refraction 1.50 is coated with a coating of thickness 138 nm and index of refraction 1.22. Light traveling perpendicular to the surface of the glass reflects at the interface between air and the coating, and at the interface between the coating and the glass. What is the largest vacuum wavelength for which the interference between the two reflected rays is completely destructive
Answer:
Explanation:
At both interface light is travelling from a medium of lower refractive index to medium of higher refractive index. So the phase difference of 180⁰ occurring at both interface will cancel out .
Net path difference = 2 μ t where μ is refractive index of thin layer and t is its thickness
For destructive interference
2 μ t = (2n + 1 )λ / 2 where λ is wavelength of light , n is any number
λ = 4 μ t / ( 2 n + 1 )
For largest wavelength , n = 0
λ = 4 μ t
= 4 x 1.22 x 138 nm
= 673.44 nm .
An object is dropped from a bridge. A second object is thrown downwards 1.0 s later. They both reach the water 20 m below at the same instant. What was the initial speed of the second object? Neglect air resistance.
In this unit, you learned about Athenian democracy and government in ancient Greece. What were some of the main characteristics of Athenian democracy? How is Athenian democracy similar to modern democracy? How is it different? Do you think Athenian democracy would be possible in the United States today? Why or why not?
(PLEASE HELP, WORTH 70 POINTS)
under this system all male citizens had equal political rights freedom of speech and the opportunity to participate directly in the political Arena
Answer:
Today, government in the United States is most similar to the Roman Republic because it is a representative democracy.
Although Athens is known as the world's first democracy, system that exist in United States today is most similar to Roman system.
Namely, Roman Republic was choosing its officials to represent them in the bodies such as Senate, which is also the case today with United States.
Explanation:
what causes most thing to expand on heating and contracts on cooling draw a diagram to support the answer
Answer:
air and oxygen makes in bigger
Explanation:
Which of the following is a disadvantage of using solar energy
Please provide options.
Answer:
It requires a high initial investment
Explanation:
please help! help! help!.. Two metal spheres of the material and of equal radius R are touching each other .show the force of attraction between them is proportional to
[tex]r {4}[/tex]
Answer:
F ∞ r^4
Explanation:
I can't really write the equation here because its complex
Hope this helps:)
An automobile tire is filled to a gauge pressure of 200 kPa when its temperature is (Gauge pressure is the difference between the actual pressure and atmospheric pressure.) After the car has been driven at high speeds, the tire temperature increases to (a) Assuming that the volume of the tire does not change and that air behaves as an ideal gas, find the gauge pressure of the air in the tire. (b) Calculate the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent.
This question is incomplete, the complete question is;
An automobile tire is filled to a gauge pressure of 200 kPa when its temperature is 20°C (Gauge pressure is the difference between the actual pressure and atmospheric pressure.)
After the car has been driven at high speeds, the tire temperature increases to 55°C
(a) Assuming that the volume of the tire does not change and that air behaves as an ideal gas, find the gauge pressure of the air in the tire. (kPa)
(b) Calculate the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent. (kPa)
Answer:
a) the gauge pressure of the air in the tire is 236 kPa
b) the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent is 205.33 kPa
Explanation:
Given the data in the question;
Gauge pressure at 20°C = 200 kPa
Absolute pressure at 20°C is; p = 200 + 101.3 = 301.3 kPa
Initial temperature T = 20°C = 20 + 273 = 293 k
Final temperature T" = 55°C = 55 + 273 = 328 K
Now, at constant volume, P"/P = T"/T
P"T = PT"
P" = PT" / T
P" = PT" / T
we substitute
P" = ( 301.3 × 328 ) / 293
P" = 98826.4 / 293
P" = 337.29
so Gauge pressure at 55°C is;
⇒ P" - 101.3
⇒ 337.29 - 101.3 = 235.99 ≈ 236 kPa
Therefore, the gauge pressure of the air in the tire is 236 kPa
b)
Final Volume V'' = V + 10% of V
V" = V + 0.1V
V" = 1.1V
we know that;
P"V"/T" = PV/T
P" = P (T"/T)(V/V")
we substitute
P" = 301.3 (328 /293 )(V/1.1×V)
P" = × 1/1.1 × V/V
P" = 337.29 × 1/1.1
P" = 306.628 kPa
so, absolute pressure at 55°C = 306.628 - 101.3 = 205.33 kPa
Therefore, the gauge pressure if the tire expands so the volume of the enclosed air increases by 10 percent is 205.33 kPa
