A region around the nucleus of an atom where electrons are likely to be found​

Answers

Answer 1

Answer:

The region where an electron is most likely to be is called an orbital. Each orbital can have at most two electrons. Some orbitals, called S orbitals, are shaped like spheres, with the nucleus in the center.

Explanation:Hope this helps :)

Answer 2

By definition, a region around the nucleus of an atom where electrons are likely to be found​ is called an orbital.

First of all, an atom is the smallest constituent unit of ordinary matter that has the properties of a chemical element.

All atoms are made up of subatomic particles: protons and neutrons, which are part of their nucleus, and electrons, which revolve around them. Protons are positively charged, neutrons are neutrally charged, and electrons are negatively charged.

In other words, every atom consists of a nucleus in which neutrons and protons meet and energy levels where electrons are located.

This is, the atomic nucleus is the central part of the atom that is made up of protons and neutrons, while the orbitals or peripheral region is an area where electrons are found.

In summary, a region around the nucleus of an atom where electrons are likely to be found​ is called an orbital.

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Related Questions

What determines the path that an object in projectile motion follows? (Ignore air resistance)

gravity only
inertia only
gravity and inertia
neither gravity or inertia

Answers

Answer:

C

gravity and inertia

Explanation:

Answer:

c :)

Explanation:

What is the net work, in joules, required to stop a crate of mass 64.5 kg that is moving at a speed of 1.26 m/s

Answers

Answer:

51.2Joules

Explanation:

Work done = Force × distance

Force = mg = 64.5×9.81

Force = 632.745N

Next is to get the distance using the equation of motion

v² = u²+2gS

1.26² = 0+2(9.81)S

1.5876 = 19.62S

S = 1.5876/19.62

S = 0.0809m

Get the work done:

Work done = F×S

Work done = 632.745×0.0809

Work done = 51.2Joules

Hence the net work done in Joules is 51.2Joules

The net work done required to stop a crate will be "51.2 Joules".

Force and Mass

According to the question,

Mass, m = 64.5 kg

Speed, v = 1.26 m/s

Acceleration due to gravity, g = 9.8

We know,

The force, F = mg

By substituting the values,

                    = 64.5 × 9.8

                    = 632.745 N

By using Equation of motion,

→       v² = u² + 2gS

 (1.26)² = 0 + 2(9.81) S

1.5876 = 19.62 S

         S = [tex]\frac{1.5876}{19.62}[/tex]

            = 0.0809 m  

hence,

The work done (W) will be:

= F × S

= 632.745 × 0.0809

= 51.2 Joules

Thus the above response above is correct.

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The public is not yet able to purchase cars powered by hydrogen fuel cells because engineers have to determin

how the cars perform based on which scenario?

on racetracks

Answers

Answer:

The options are

A.on racetracks

B.in real-world conditions

C.in flooded environments

D.on closed courses

The answer is B. In real world conditions

The public is not yet able to purchase cars powered by hydrogen fuel cells because engineers have to determin

how the cars perform based on real world conditions.

This will ensure they encounter the real and first hand experiences about the challenges and also the advantages associated with using this type of fuel.

A squirrel drops an acorn from a tree. Starting from rest, it reaches the ground 22.0 meters
below. What is the acorn's velocity as it hits the ground?

Answers

Does it not tell you how long it took it to reach the ground? Constant Velocity should be distance over time

for an emitted wavelength of 500 nanometers and a redshift of 0.4 what will be the observed wavelength g

Answers

Answer:

The observed wavelength is  [tex] \lambda = 700nm[/tex] (color -  Red)

Explanation:

From the question we are told that

   The wavelength of the emitter is  [tex]\lambda_ e  = 500 nm  =  500 *10^{-9} \  m[/tex]

  The redshift is  R  =  0.4  

     Generally red shift is mathematically represented as

    [tex]R =  \frac{ \lambda -  \lambda_e }{\lambda_e}[/tex]

=>  [tex]0.4  =  \frac{ \lambda -   500 *10^{-9} }{500 *10^{-9} }[/tex]

=>  [tex] \lambda - 500*10^{-9} = 200*10^{-9}  [/tex]

=>   [tex] \lambda = 700 *10^{-9}[/tex]

=>   [tex] \lambda = 700nm[/tex]

Vertical acceleration of the stone thrown upwards at the top of the trajectory (where its velocity vanishes) is equal to

A. g
B. g/2
C. 0
D. nine of the above

Answers

I think it’s b but not 100%

Answer:

A. g

Explanation:

Find the distance along an arc on the surface of the earth that subtends a central angle of 1 minutes (1 minute = 1/60 degree). The radius of the earth is 3960 miles. Round to the thousandths. (3 decimal places)

Answers

Answer:

1.152 miles

Explanation:

Given: central angle = 1 minute = [tex](\frac{1}{60}) ^{o}[/tex]

           radius of the earth = 3960 miles

The length of an arc = [tex]\frac{\alpha }{360^{o} }[/tex] 2[tex]\pi[/tex]r

where: [tex]\alpha[/tex] is the central angle, and r is the radius.

Thus,

Distance along the arc = [tex]\frac{\alpha }{360^{o} }[/tex] 2[tex]\pi[/tex]r

Distance along the arc = [tex]\frac{(\frac{1}{60}) ^{o} }{360^{o} }[/tex] x 2 x [tex]\frac{22}{7}[/tex] x 3960

                                      = [tex]\frac{(\frac{1}{60}) ^{o} }{360^{o} }[/tex] x 24891.4286

                                      = 1.1524

The required distance along an arc is 1.152 miles.

Please help which one is correct

Answers

Answer:

option (i) is correct

Explanation:

as there is no air resistance, no force is acting on the object horizontally, but gravitational acceleration will obviously act, regardless of the air resistance... option (i) is correct

The latent heat of fusion of mercury is 11.8 J/g. The amount of energy, rounded to the nearest tenth, needed to change 8.00 grams of mercury to a liquid is

Answers

Answer:

94.4

Explanation:

it is

Answer:

94.4 i took the test and got it right :)

hope that helps

If you borrow your mom's car to drive 128 m to the store, but you go cruising
instead and drive a total distance of 1256 m in 3600s. What was your speed during the
trip? Round answer to 2 significant figures.

Answers

Answer:

v = 0.349 m/s

Explanation:

If you borrow your mom's car to drive 128 m to the store, but you go cruising  instead and drive a total distance of 1256 m in 3600s.

We need to find your speed during the  trip. It is equal to the total distance divided by time taken.

He has done cruising  instead and drive a total distance of 1256 m.

So,

[tex]v=\dfrac{d}{t}\\\\v=\dfrac{1256\ m}{3600\ s}\\\\v=0.349\ m/s[/tex]

So, the speed of the person during the trip is 0.349 m/s.

A 1000-turn solenoid is 50 cm long and has a radius of 2.0 cm. It carries a current of 18.0 A. What is the magnetic field inside the solenoid near its center

Answers

Answer:

The value  is  [tex]B =  0.0452 \  T [/tex]

Explanation:

From the question we are told that

   The number of turns is  N  =  1000

    The length is  L =  50 cm =  0.50 m  

    The radius is  r =  2.0 cm  =  0.02 m

     The current is I  =  18.0 A

   

Generally the magnetic field is mathematically represented as

         [tex]B = \mu_o  * \frac{N }{L}  *  I[/tex]

Here [tex]\mu_o[/tex] is the permeability of free space with value  

     [tex]\mu_o  =  4\pi * 10^{-7} N/A^2[/tex]

So

     [tex]B =  4\pi * 10^{-7}  *   \frac{1000}{0.50} *  18.0[/tex]

=>   [tex]B =  0.0452 \  T [/tex]

The earth has a mass of, MEarth=6.4 X 1024 kg and a radius of REarth= 6.0 X 106meter and it has acceleration due to gravity, gE = 9.8 . One of Jupiter’s moon also has MJmoon = ½ * MEarth =3.2 x 1024 kg with a radius of, RJmoon = ½ * REarth =3.0 x 106 m and gJmoon value unknown. From the information, what is acceleration due to gravity of Jupiter’s moon, gjmoon, comparing to the earth’s acceleration due to gravity, gEarth?

Answers

Answer:

gjmoon = 19.6 m/s2

Explanation:

Applying the Universal Law of Gravitation, the force exerted by the Earth on a mass m, can be written as follows:

       [tex]F_{gE} = m* \frac{G*M_{E} }{R_{E} ^{2} } = m*g_{E}[/tex]

In the same way, the force due to gravity of Jupiter's moon, can be written as follows:

      [tex]F_{gjmoon} = m* \frac{G*M_{Jmoon} }{R_{Jmoon} ^{2} } = m*g_{jmoon} (1)[/tex]

Now, we know the following:

       [tex]M_{Jmoon} = \frac{M_{E} }{2} (2)[/tex]  

      [tex]R_{Jmoon} = \frac{R_{E} }{2} (3)[/tex]

Replacing (2) and (3) in (1), we get:

       [tex]F_{gjmoon} = m* \frac{G*M_{E} }{2*\frac{R_{E} ^{2}}{4} } = m*g_{jmoon} (1) = m* 2* \frac{G*M_{E} }{R_{E} ^{2}} = 2* m*g_{E}[/tex]

      ⇒  [tex]g_{jmoon} = 2* g_{E}[/tex]

       gjmoon = 19.6 m/s2 (in magnitude).

my mom is dum and anoying asl, what should i do?

Answers

Answer:

stop being an annoying child and appreciate everything your mother does for you because she cares for you

Explanation:

its the right thing to do

Be thankful for everything your mom does bc one day she wont be here any more! Love her while you can

Forces are expressed in ________. (newtons or mass)

Answers

Newtons

Mass isn’t even a unit of measurement

Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 9.0 kg gibbon has an arm length (hand to shoulder) of 0.60 m. We can model its motion as that of a point mass swinging at the end of a 0.60-m-long, massless rod. At the lowest point of its swing, the gibbon is moving at 3.5 m/s. What upward force must a branch provide to support the swinging gibbon

Answers

Answer:

The correct solution will be "271.95 N".

Explanation:

The given values are:

velocity  

v = 3.5 m/s

mass

m = 9.0 kg

r = 0.6 m

According to the question:

⇒ [tex]F_{branch}=F_{gravity}+F_{centrifugal}[/tex]

⇒             [tex]=mg+\frac{mv^2}{r}[/tex]

On substituting the values, we get

⇒             [tex]=9\times 9.8+\frac{9\times (3.5)^2}{0.6}[/tex]

⇒             [tex]=88.2+\frac{110.35}{0.6}[/tex]

⇒             [tex]=271.95 \ N[/tex]

You and some friends visit the Florida State Fair and decide to play a game. To play the game you must slide a metal hockey-type puck up a wooden ramp so that it drops through a hole at the top of the ramp. Your prize, if you win, is a large, stuffed gorilla. You realize the secret to winning is giving the puck just enough velocity at the bottom of the ramp to make it to the hole. You estimate the distance from the bottom of the ramp to the hole at about 3 m, and the ramp appears to be inclined with an angle of 10o from the horizontal. You just got out of physics class and recall the coefficient of static friction between steel and wood is 0.1 and the coefficient of kinetic friction between steel and wood is 0.08. The mass of the puck is about 1 kg. You decide to impress your friends by sliding the puck at the precise speed on the first try so as to land it in the hole. You slide the puck at 2.0 m/sec. Do you win the stuffed poodle? Let g = 10 m/s2. Note: A slightly too hard throw will win since your aim is so good the puck would drop in the hole.

Answers

Answer:

No you didn't win the stuffed poodle

Explanation:

From the question we are told that

    The distance of the ramp to the hole is  d =  3 m \

     The angle of inclination is  [tex]\theta  =  10^o[/tex]

       The coefficient of static friction is [tex]\mu_s = 0.1[/tex]

     The coefficient of kinetic  friction is [tex]\mu_k = 0.08[/tex]

      The mass of the puck is  m  =  1 kg

     The velocity of the first slide  is  [tex]v_1  =  2.0 m/s[/tex]

       

Generally the kinetic energy at the bottom of the ramp  is equal the energy loss due to friction and this can be mathematically represented as

    [tex]\frac{1}{2} m *  v^  2 =  \mu_k * [m *  g] *  cos (theta )  *  d[/tex]

=>     [tex]\frac{1}{2}  *  v^  2 = 0.08 * 9.8 *  cos (10 )  *  3[/tex]

=>     [tex] v=  2.17 \  m/s [/tex]

Comparing the relative velocity obtained and the velocity of your first throw we can see that you didn't win the stuffed animal  

An airline employee tosses two suitcases in rapid succession with a horizontal velocity of 7.2 ft/s onto a 50-lb baggage carrier which is initially at rest. Problem 14.003.a Conservation of momentum: two colliding suitcases Knowing that the final velocity of the baggage carrier is 4.8 ft/s and that the first suitcase the employee tosses onto the carrier has a weight of 30 lb, determine the weight of the other suitcase. (You must provide an answer before moving on to the next part.) The weight of the other suitcase is lb.

Answers

Answer:

m₁ = 70 lb

Explanation:

Here we will use the law of conservation of momentum:

m₁u₁ + m₂u₂ + m₃u₃ = m₁v₁ + m₂v₂ + m₃v₃

where,

m₁ = mass of first suitcase = ?

m₂ = mass of second suitcase = 30 lb

m₃ = mass of baggage carrier = 50 lb

u₁ = initial speed of first suitcase = 7.2 ft/s

u₂ = initial speed of second suitcase = 7.2 ft/s

u₃ = initial speed of baggage carrier = 0 ft/s

v₁ = Final speed of first suitcase = 4.8 ft/s

v₂ = Final speed of second suitcase = 4.8 ft/s

v₃ = Final speed of baggage carrier = 4.8 ft/s

because after collision all three will have same speed

Therefore,

(m₁)(7.2 ft/s) + (30 lb)(7.2 ft/s) + (50 lb)(0 ft/s) = (m₁)(4.8 ft/s) + (30 lb)(4.8 ft/s) + (50 lb)(4.8 ft/s)

(m₁)(7.2 ft/s) + (216 lb ft/s) + (0 lb ft/s) = (m₁)(4.8 ft/s) + (144 lb ft/s) + (240 lb ft/s)

(m₁)(7.2 ft/s) - (m₁)(4.8 ft/s) = 168 lb ft/s

m₁ = (168 lb ft/s)/(2.4 ft/s)

m₁ = 70 lb

An ion has unequal numbers of which two particles?

Answers

protons and electrons

Which property of a substance can be determined using a pH indicator.​

Answers

Answer:

Acidity

Explanation:

A pH indicator measures how acidic or basic a substance is.

Hope this helped :)

A small box with mass 0.600 kg is placed against a compressed spring at the bottom of an incline that slopes upward at 37.0∘ above the horizontal. The other end of the spring is attached to a wall. The coefficient of kinetic friction between the box and the surface of the incline is μk=0.400. The spring is released and the box travels up the incline, leaving the spring behind.

What minimum elastic potential energy must be stored initially in the spring if the box is to travel 2.00 m from its initial position to the top of the incline?

Answers

Answer:

[tex]10.845\ \text{J}[/tex]

Explanation:

m = Mass of box = 0.6 kg

[tex]\theta[/tex] = Angle of incline = [tex]37^{\circ}[/tex]

[tex]\mu_k[/tex] = Coefficient of kinetic friction = 0.4

l = Distance the box travels = 2 m

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

The potential energy in the spring is given by

[tex]U=mgl\sin\theta+mg\mu_k\cos\theta l\\\Rightarrow U=mgl(\sin\theta+\mu_k\cos\theta)\\\Rightarrow U=0.6\times 9.81\times 2\times(\sin37^{\circ}+0.4\times\cos37^{\circ})\\\Rightarrow U=10.845\ \text{J}[/tex]

The minimum elastic potential energy required is [tex]10.845\ \text{J}[/tex].

PLEASE HELP WILL MARK BRAINLIEST

Answers

Answer:

also choose D and E i belive those are also correct

D. and E are correct. i hope you get a good score happy halloween

Lab report on motion 6th grade

Answers

Answer:

I'm in 10th grade

Explanation:

Question #4
4. Anthony walks to the pizza place for lunch. He walk 4 km
east, he realized he passed it and then walked 1 km west.
What distance did he cover? What was his displacement?

Answers

Answer:

Distance 5 km, Displacement 3 km east

Explanation:

The distance covered by Anthony is 5 km, while his displacement is 3 km.

Distance and displacement:

The distance is defined as the total length of space covered during motion between the starting point and end point, not necessarily a straight line. Whereas displacement is defined as the minimum distance between two points in space, that is a straight line.

Suppose, if you start from one point and walk for 100 meters then come back at the same point that you started your walk, you would have traveled 2 times 100 meters that is 200 meters. But your displacement will be zero because your starting point and the end point are the same.

The given question clarifies the difference between distance and displacement:

Since Anthony walks 4 km east and then walks 1 km west, the distance covered by him is:

distance = 4 + 1 = 5 km

but as he walks west, he comes closer to the starting point, and his displacement is the distance between the starting point and the end point.

displacement = 4 - 1 = 3 km

Referto the figure below for more information.

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If the experimenter knows who is in the experimental and control groups and treats them accordingly, she runs the risk of ________.

Answers

She runs the risk of experimenter bias

Answer:

Experimenter bias

Explanation:

If the experimenter knows who is in the experimental and control groups and treats them accordingly, she runs the risk of Experimenter bias.

Definitions of Experimenter bias

1) Research bias, also called experimenter bias, is a process where the scientists performing the research influence the results, in order to portray a certain outcome.

2) Observer bias (also called experimenter bias or research bias) is the tendency to see what we expect to see, or what we want to see. When a researcher studies a certain group, they usually come to an experiment with prior knowledge and subjective feelings about the group being studied.

Briefly explain why arterial injuries are more dangerous than damage to veins
or capillaries. Explanation should address structure and function of the
blood vessels.

IF YOU SEE THIS PLZ ANSWER RN

Answers

Answer:

Injury to a vein increases the risk of forming a blood clot.

Explanation:

hoped this helped


Which part of the brain plays a vital role in sensory information processing?


Occipital Lobe
Cerebral Cortex
Pons
Parietal Lobe

Answers

Answer:

Parietal Lobe

Explanation:

Streams compensate for changes in their systems by adjusting other factors in order to return to _______

Answers

Answer:

Equilibrium.

Explanation:

Streams compensate for changes in their systems by adjusting other factors in order to return to equilibrium because so as to maintain their watershed. When the surface runoff move downslope, it also cause a concentration in small areas and create small channels of streams. These channels normally allow the flow of water during rainfall.

What happens to the energy in a closed system?

Answers

Answer:

can exchange energy with its surroundings through heat and work transfer. In other words, work and heat are the forms that energy can be transferred across the system boundary.

The law of conservation of energy is an important law of physics. Basically, it says that while energy can turn from one kind into another, the total amount of energy doesn't change. This law applies only to closed systems, meaning systems that can't exchange energy with their environment

Shoot the cannon velocity of 25 m/s and observe the velocity vector on the simulator and make a statement about your observation . In other words what is happening to the projectile as it travel its parabolic trajectory ?​

Answers

Answer:

Its speed remains the same but its velocity keeps chaging (in direction)

Explanation:

HELP URGENTTTTTTTTTTTTT

Answers

Answer:

Gravitational Potential Energy

B Gravitational potential energy

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