A new car sells for 25000 the value of the car decreases by 15% each year what is the approximate value of the car 5 years

The type of transformation modeled in the graph is Reflection across y-axis.

The three different kinds of coordinate transformation are listed below. The motor's three-phase current and voltage are transformed by the Clark transformation from their original natural coordinates to two-phase static coordinates determined with reference to the stator.

Because the domain or range values of the function f(x) have changed, rules of transformations assist in changing f(x) to a new function f'(x). With the use of these transformational rules, the function can be stretched or compressed as well as transformed vertically or horizontally.

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Answer:

The appropriate test statistic for testing the null hypothesis that the slope of the population regression line equals 0 is the t-statistic.

The t-statistic for testing the slope coefficient is calculated as follows:

t = (b1 - 0) / SE(b1)

where b1 is the estimated slope coefficient, and SE(b1) is the standard error of the estimated slope coefficient.

From the computer output, we see that the estimated slope coefficient for exercise time is -2.20, and the standard error of the estimated slope coefficient is 0.07.

Therefore, the t-statistic is:

t = (-2.20 - 0) / 0.07 = -31.43

This t-statistic follows a t-distribution with n-2 degrees of freedom, where n is the sample size. The sample size is not given in the output, so we cannot determine the exact degrees of freedom.

The integral of  [tex]\int\limits^e_1 {x^{1/2}lnx } \, dx[/tex]  is (2/3)[tex]e^{3/2}[/tex] - (4/9).

To find the integral of   [tex]\int\limits^e_1 {x^{1/2}lnx } \, dx[/tex]  , we can use integration by parts. Let u = ln x and dv = [tex]x^{1/2}[/tex] dx. Then du/dx = 1/x and v = (2/3) [tex]x^{3/2}[/tex] .

Using the formula for integration by parts, we have:

∫[tex]x^{1/2}[/tex]lnx dx = uv - ∫v du/dx dx

= ln x * (2/3) [tex]x^{3/2}[/tex]  - ∫(2/3) [tex]x^{3/2}[/tex]  * (1/x) dx

= ln x * (2/3) [tex]x^{3/2}[/tex]  - (2/3) ∫ [tex]x^{1/2}[/tex]  dx

= ln x * (2/3) [tex]x^{3/2}[/tex]  - (4/9) [tex]x^{3/2}[/tex]  + C

where C is the constant of integration.

To evaluate the definite integral from 1 to e, we substitute e for x in the expression above and subtract the result when x = 1:

 [tex]\int\limits^e_1 {x^{1/2}lnx } \, dx[/tex]   = [(2/3) [tex]e^{3/2}[/tex] ln e - (4/9) [tex]e^{3/2}[/tex] ] - [(2/3)[tex]1^{3/2}[/tex]ln 1 - (4/9)[tex]1^{3/2}[/tex]]

= (2/3) [tex]e^{3/2}[/tex] - (4/9)

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Step-by-step explanation:

The constant of proportionality is just the slope of the line

using 0,0   and  3,2   points

slope = (y1-y2 ) / ( x1-x2) = (0-3) / ( 0-2) = 3/2 = constant of proportionality

Answer:

a) y = 5.2727x + 32.5276

b) y = 5.2727(6) + 32.5276

= 64.1638 inches

c) y = 5.2727(7.153) + 32.5276

= 70.2432 inches

The piecewise function is

f(x) = { x -3 , x≤3

             8, -3 < x ≤ 5

           x+10, x>6

For values less than or equal to -3, we have a line with a positive slope. We have two lines, y = x - 2, and y = x - 3.

1. For y = x - 2

-5 = -3 - 2= -5

2. For y = x - 3

-5 = -3-3 = -6

The fact that the domain is specified for x less than -3  further demonstrates that the first choice is not an option.

Additionally, we know that the function's value is equal to 8 for the range from x greater than -3 to less than or equal to 5.

Additionally, the equation is given as y = -x + 10 and the line has a negative slope for values greater than 6.

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The expression that Sally can use to determine how many dominoes can fit in the tin based on the number of dominoes in each row stacked is (Number of rows stacked ÷ 0.75) x (9 x 4)

Sally can use the fact that she can fit 3 dominoes stacked on top of each other, 9 dominoes side-by-side, and 4 dominoes end-to-end in the tin to figure out how many dominoes can fit in the tin. Since she knows that 27 dominoes fit in one row stacked, she can use addition to determine the total number of dominoes that can fit in the tin.

First, she can find the number of dominoes that can fit in one layer of the tin by multiplying the number of dominoes that fit side-by-side and the number that fit end-to-end: 9 x 4 = 36.

Then, she can divide the total number of dominoes that fit in one row (27) by the number of dominoes that can fit in one layer (36): 27 ÷ 36 = 0.75.

This means that each layer of the tin can hold 0.75 rows of dominoes.

To find the total number of dominoes that can fit in the tin, Sally can multiply the number of layers by the number of dominoes in each layer: Number of layers x Number of dominoes in each layer = Total number of dominoes that can fit in the tin.

Therefore, the expression that Sally can use to determine how many dominoes can fit in the tin based on the number of dominoes in each row stacked is:

Total number of dominoes = Number of layers x Number of dominoes in each layer

Total number of dominoes = (Number of rows stacked ÷ 0.75) x (9 x 4)

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Answer:

  (3, 9) and (3, -7)

Step-by-step explanation:

You want the end points of the latus rectum for the parabola defined by ...

 (y -1)² = 16(x +1)

Compare the given equation to the form ...

  (y -k)² = 4p(x -h)

we see that (h, k) = (-1, 1) and p = 16/4 = 4. The ordered pair (h, k) is the vertex of the parabola. The scale factor 'p' gives the distance from the vertex to the focus (and from the directrix to the focus). Larger 'p' values result in a "flatter" parabola.

Since the squared term is a y-term, and the value of 'p' is positive, we know the parabola opens to the right. The end points of the latus rectum are ...

  (h+p, k±2p) = (-1+4, 1±2·4) = (3, 9) and (3, -7)

__

Additional comment

If the roles of x and y are interchanged (the parabola opens up or down), then the end points of the latus rectum are (h±2p, k+p).

On a graph of the parabola, the end points of the latus rectum lie on lines through the vertex with slope ±2 (parabola opens in x-direction), or with slope ±1/2 (parabola opens in y-direction).

Answer:

3 x 195 = 585 minutes

Step-by-step explanation:

In one week, Alejandro attends a 45-minute lesson and practices for (6 x 25) = 150 minutes (assuming a 7-day week). So, the total number of minutes that Alejandro spends on his guitar in one week is:

45 + 150 = 195 minutes

In 3 weeks, the total number of minutes that Alejandro spends on his guitar is:

3 x 195 = 585 minutes

Therefore, Alejandro spends 585 minutes on his guitar in 3 weeks, including attending a 45-minute lesson once a week and practicing for 25 minutes on the remaining days of the week.

Answer: The mean absolute deviation is approximately is 11.43.

A. The 51st note on a piano keyboard corresponds to a pitch of 440 cycles per second.

B. The pitch that is 73 notes higher on the keyboard has a frequency of about 1760 cycles per second.

A. Use the formula to find how many notes up the piano keyboard the pitch of 440 cycles per second corresponds to:

440 = 27.5 × 2⁽ⁿ⁻¹⁾/12

Dividing both sides by 27.5 and taking the logarithm with base 2 gives:

log₂(440/27.5) = (n-1)/12

n-1 = 12 × log₂(440/27.5)

n-1 = 12 × 4.1702 ≈ 50.042

n ≈ 51.042

Therefore, the pitch of 440 cycles per second is the 51st note up the piano keyboard.

B. Use the same formula to find the frequency of the pitch that is 73 notes up the keyboard:

73 = 1 + 12 log₂(f/27.5)

72 = 12 log₂(f/27.5)

6 = log₂(f/27.5)

f/27.5 = 2⁶

f = 27.5 × 2⁶

f ≈ 1760

Therefore, the frequency of the pitch that is 73 notes up the keyboard is approximately 1760 cycles per second.

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Answer:

10) 73

11) 107

12) 107

13) x = 23

14) 135

15) 45

16) 123, 28 29

17) 180 - 72 - 28 = 80

Angle K is 80

Step-by-step explanation:

10:

Vertical angels are congruent.  The same measurement.

11:

Supplements angles add to 180

180 - 73 = 107

12:

Same as 11

13:

135

Vertical angles are congruent

5x + 20 = 3x + 66  Subtract 3x from both sides

2x + 20 = 66 Subtract 20 from both sides

2x = 46  Divide both sides by 2

x = 23

14:

5x + 20  Substitute 23 for x

5(23) + 20

115 + 20

135

15:

This angle is supplemental to ABC

180 - 135 = 45

16:

The sum of the interior angles of a triangle is 180

123 + x-2 + x -3 = 180 Combine like terms

118 +2x = 180  Subtract 118 from both sides

2x = 62  Divide both sides by 2

x = 31

x- 2

31 - 2 = 29

x - 3

31 - 3 = 28

Three angles 123, 29, 28

17:

The sum of the interior angles is 180

180 - 72 - 28 = 80

Helping in the name of Jesus.

The amount of the final payment is $1,004.99.

To solve the given problem, we will use the concept of present value. We need to find the present value of the two payments due in the past, and then find the future value of the remaining payments due in the future.

Let's first find the present value of the two past payments:

PV1 = $1010 / (1 + 0.0775/12)⁵ = $868.15

PV2 = $1280 / (1 + 0.0775/12)⁰ = $1280

Next, we can find the future value of the remaining payments due in the future

FV1 = $615 x (1 + 0.0775/12)⁴ = $664.69

FV2 = X

Now we can set up an equation to solve for X, the final payment:

PV1 + PV2 = FV1 + FV2 / (1 + 0.0775/12)⁷

Substituting the values we have calculated:

$868.15 + $1280 = $664.69 + X / (1 + 0.0775/12)⁷

Simplifying and solving for X

X = ($868.15 + $1280 - $664.69) x (1 + 0.0775/12)⁷ = $1,004.99

Therefore, the amount of the final payment is $1,004.99.

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to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below.

[tex](\stackrel{x_1}{-4}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-1}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-1}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-4)}}} \implies \cfrac{-5}{0 +4} \implies \cfrac{ -5 }{ 4 } \implies - \cfrac{ 5 }{ 4 }[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{- \cfrac{ 5 }{ 4 }}(x-\stackrel{x_1}{(-4)}) \implies y -4 = - \cfrac{ 5 }{ 4 } ( x +4) \\\\\\ y-4=- \cfrac{ 5 }{ 4 }x-5\implies {\Large \begin{array}{llll} y=- \cfrac{ 5 }{ 4 }x-1 \end{array}}[/tex]

first off, let's find out how much he's making on the 2nd year, so since he's getting slashed by 20%, that means his new commission is 100% - 20% = 80%, so 80% of 60000, how much is that?

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{80\% of 60000}}{\left( \cfrac{80}{100} \right)60000}\implies 48000[/tex]

now, if we want to go up to 57600, that means we need to increase his commission by 57600 - 48000 = 9600.

So, if we take 48000(origin amount) to be the 100%, what's 9600 off of it in percentage?

[tex]\begin{array}{ccll} Amount&\%\\ \cline{1-2} 48000 & 100\\ 9600& x \end{array} \implies \cfrac{48000}{9600}~~=~~\cfrac{100}{x} \\\\\\ 5 ~~=~~ \cfrac{ 100 }{ x }\implies 5x=100\implies x=\cfrac{100}{5}\implies \boxed{x=20}[/tex]

$3988.71 should be invested by them to be able to contribute $9000 to his education.

We can use the continuous compound interest formula:

[tex]A = Pe^{(rt)[/tex]

where A is the future value, P is the present value, r is the interest rate, and t is the time in years.

We know that A = $9000, r = 0.085 (8.5% expressed as a decimal), and t = 12.

Solving for P, we get:

[tex]P = A / e^{(rt)}\\\\P = 9000 / e^{(0.085*12)}\\\\P = \$ \ 3988.71[/tex]

Therefore, Mr. and Mrs. Tran should invest approximately $3988.71 now in order to have $9000 in twelve years, assuming continuous compound interest at a rate of 8.5% per year.

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Answer: I believe it would be 2/5.

Step-by-step explanation:

Reduction means the fraction is reduced to it's simplest form.

7/7=1

2/5=2/5

15/13=1 2/13

See as the '2/5' does not change in reduction.

So, '2/5' would be your answer.

Hope this helps! :)

Answer:

option c) x=-6

Step-by-step explanation:

-15x = 90

= x = 90/-15

= x = (-6)

A word problem that matches the inequality -2.75 > x is:

John has a balance of $25 in his bank account and wants to withdraw some money and he needs to withdraw at least x dollars, but not more than $2.75.

A word problem that matches the inequality -2.75 > x is:

John has a balance of $25 in his bank account and wants to withdraw some money. He needs to withdraw at least x dollars, but not more than $2.75.

What is the largest possible value of x that John can withdraw and still have a positive balance in his account?

In this scenario, the variable x represents the amount that John can withdraw from his account, and the inequality -2.75 > x means that x must be less than -2.75 (i.e., negative and greater in magnitude than 2.75)

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The length of unknown side is,

⇒ 4.92

We have to given that;

A triangle is shown in image.

Let the length of unknown side = x

Now, From trigonometry formula we get;

⇒ tan 51° = x / 4

⇒ 1.23 = x / 4

⇒ x = 1.23 × 4

⇒ x = 4.92

Thus, the length of unknown side is,

⇒ x = 4.92

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Answer:-₍1,3₎

Step-by-step explanation:

To solve this system of equations, we can use the method of elimination to eliminate one of the variables. We can multiply the first equation by 5 and the second equation by -3, then add the two equations to eliminate $y$:

$(5)(2x + 3y = 4) \Rightarrow 10x + 15y = 20$

$(-3)(3x + 5y = 7) \Rightarrow -9x - 15y = -21$

Adding the equations, we get:

$10x + 15y - 9x - 15y = 20 - 21$

Simplifying, we get:

$x = -1$

Now we can substitute $x=-1$ into one of the original equations to solve for $y$. Using the first equation, we have:

$2(-1) + 3y = 4$

Solving for $y$, we get:

$y = 2$

Therefore, the solution to the system of equations is $x=-1$ and $y=2$. We can check this solution by substituting $x=-1$ and $y=2$ into the other two equations:

$3(-1) + 5(2) = 7$

$10(-1) + 15(2) = 20$

Both equations are true, so our solution is correct.

b. The range is 32 - 16 = 16. and IQR  4

c. 32

a. Here is a box and whisker plot to represent the given data:

The horizontal axis shows the range of the data, and the vertical axis represents the frequency. The box represents the middle 50% of the data, with the bottom of the box being the 25th percentile and the top of the box being the 75th percentile. The whiskers represent the lowest and highest values within 1.5 times the interquartile range (IQR) of the box, and any points outside the whiskers are considered outliers.

b. The range is the difference between the highest and lowest values in the data set. In this case, the range is 32 - 16 = 16.

c. There is one outlier in the data set, which is the value of 32. It is outside the whiskers of the box and is considered to be an outlier.

The interquartile range (IQR) is the difference between the 75th and 25th percentiles of the data set. In this case, the IQR is:

IQR = Q3 - Q1

   = 22 - 18

   = 4

where Q1 is the first quartile (the value below which 25% of the data falls), and Q3 is the third quartile (the value below which 75% of the data falls).

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Answer:

b

4 x 3.2 = 12.8

17.8 - 5 =12.8

so,

4 x 3.2 = 17.8-5

12.8=12.8

Answer:

15 19/20

Step-by-step explanation:

95 cents means 95/100 then reduce that and you get 19/20 and then on the end you still have the $15

Step-by-step explanation:

step A is incorrect.

-40/5 does not equal to -40/-5.

-40/-5 is equal to 40/5 as we can simplify the negative 1 out.

Answer:

The correct answer is step A

Answer:

i dont know if this helps, im not sure if you are telling me to do all of these things or B, c, d are answer

Step-by-step explanation:

To find the total amount of money that the photography club will raise to meet their goal, we can multiply the average amount of money each member must raise by the number of members in the club:

Average amount of money each member must raise = m

Number of members in the club = 20

Total amount of money to be raised = Average amount of money each member must raise x Number of members in the club

Total amount of money to be raised = m x 20

We know that the club is trying to raise at least $1,400, and they have already raised $540. Therefore, the amount of money they still need to raise is:

Amount of money still needed to reach goal = $1,400 - $540

Amount of money still needed to reach goal = $860

We can set up an equation to represent the total amount of money the club will raise to meet their goal:

Total amount of money to be raised = Amount of money still needed to reach goal

m x 20 = $860

We can solve for "m" by dividing both sides of the equation by 20:

m = $860 / 20

m = $43

Therefore, the total amount of money the club will raise to meet their goal is:

Total amount of money to be raised = Average amount of money each member must raise x Number of members in the club

Total amount of money to be raised = $43 x 20

Total amount of money to be raised = $860

B))) We can set up an equation to represent the total amount of money the club will raise to meet their goal:

Total amount of money to be raised = Amount of money already raised + Amount of money still needed to reach goal

We know that the club has already raised $540 and they need to raise $860 more to reach their goal of $1,400. Therefore, we can substitute these values in the equation:

Total amount of money to be raised = $540 + $860

Total amount of money to be raised = $1,400

So the equation that represents the club raising all the money is:

$1,400 = $540 + $860

C)))) To solve the equation:

$1,400 = $540 + $860

We can simplify the right-hand side of the equation by adding $540 and $860:

$1,400 = $1,400

This equation is true, which means that it is a consistent equation. The solution to this equation is that the club will be able to raise all the money they need to buy the new photography equipment.

In the context of the scenario, the solution means that the club will be able to meet their goal of raising at least $1,400 for new photography equipment. They have already raised $540, and they need to raise $860 more to reach their goal. The equation shows that the total amount of money they will raise is exactly $1,400, which is the amount they need to meet their goal.

D))))) To represent the amount of money each member must raise, on average, to meet or exceed their goal, we can use the following inequality:

Average amount of money each member must raise ≥ Total amount of money still needed to reach goal / Number of members in the club

We know that the total amount of money still needed to reach the goal is $860, and there are 20 members in the club. Therefore, we can substitute these values in the inequality:

Average amount of money each member must raise ≥ $860 / 20

To simplify the right-hand side of the inequality, we can divide $860 by 20:

Average amount of money each member must raise ≥ $43

This inequality shows that each member must raise at least $43, on average, to meet or exceed their goal of raising $1,400.

To show the possible average amount of money each club member needs to raise, we can use the following inequality:

0 < Average amount of money each member must raise ≤ Total amount of money still needed to reach goal / Number of members in the club

This inequality shows that the average amount of money each member must raise is greater than 0 (since each member must contribute something), but it is less than or equal to $43 (which is the minimum amount each member must raise to meet or exceed their goal).

The first equation of this system is y = 2x + 3, the second equation is y = 3x - 1, and the solution of the system is (4, 11).

a) The first equation of this system can be found by using the points given in the first table. We can use the two points (-1, 1) and (0, 3) to find the equation of the line passing through them using the slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.

The slope of the line passing through (-1, 1) and (0, 3) is (3-1)/(0-(-1)) = 2/1 = 2.

Substituting one of the points in the slope-intercept form, we get 1 = 2(-1) + b, which gives us b = 3. Therefore, the equation of the line is y = 2x + 3.

b) Similarly, we can use the points given in the second table to find the equation of the second line. Using the points (0, -1) and (2, 5), we get the slope as

(5-(-1))/(2-0)

= 6/2

= 3.

Substituting one of the points in the slope-intercept form, we get

-1 = 3(0) + b, which gives us b = -1.

Therefore, the equation of the second line is y = 3x - 1.

c) To find the solution of the system, we need to find the point of intersection of the two lines. We can do this by solving the two equations simultaneously.

Substituting the second equation in the first, we get:

2x + 3 = 3x - 1

Simplifying, we get x = 4.

Substituting x = 4 in either of the equations, we get y = 11. Therefore, the solution of the system is (4, 11).

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