A vessel is filled with a gas at a temperature 30c and a pressure of 760mmhg calculate the final pressure if the volume of the gas is double while it's heated at 80c

The observed reduction in the volume of the salt solution after shaking suggests that the added water was able to dissolve the salt, resulting in a more compact solution.

A solution is a homogeneous mixture made up of two or more substances that are evenly distributed at a molecular or ionic level. The substance that is present in the largest amount is called the solvent, and the substances that are dissolved in it are called solutes. The solutes can be gases, liquids, or solids.

The process of forming a solution involves the solute particles being surrounded by the solvent particles, which causes the solute particles to become evenly distributed throughout the solvent. The attractive forces between the solvent and solute molecules or ions play a crucial role in determining the concentration of the solution.

Solutions can have a wide range of properties, such as color, density, boiling and melting points, and electrical conductivity, which depend on the identity of the solutes and the solvent. Solutions are an essential part of many chemical, biological, and industrial processes, and understanding their properties and behavior is crucial in many fields of science and technology.

Here in this Question, When salt is added to water, it dissolves to form a saltwater solution. However, the addition of more water than the solubility of salt causes some of the salt to remain undissolved at the bottom of the flask. When the flask is shaken, the salt particles that were initially undissolved become suspended in the solution due to the agitation, thereby reducing the volume of the solution. This is because the suspended particles take up space in the solution, which was initially occupied by the water molecules.

Therefore, The observed decrease in salt solution volume after shaking indicates that the salt was able to dissolve in the additional water, resulting in a more compact solution.

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The electromagnet becomes weaker when the number of coils around the nail is decreased. The correct answer is "It becomes weaker."

An electromagnet is created by coiling a wire around a magnetic core, such as a nail, and running an electric current through the wire. This creates a magnetic field around the wire, which magnetizes the core.

The strength of the magnetic field and thus the strength of the electromagnet is directly proportional to the number of coils around the magnetic core.

This is because each coil adds to the magnetic field, and the more coils there are, the stronger the magnetic field becomes.

When some coils are removed, there are fewer coils contributing to the magnetic field. As a result, the strength of the magnetic field and thus the strength of the electromagnet decreases.

Therefore, the correct option is " it becomes weaker" when the number of coils around the nail is decreased.

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The relative intensity of a single monkey-typewriter station is given as 76 dB, and the noise ordinance limits the overall sound intensity to 90 dB.

The sound intensity is proportional to the number of stations, so we can use a logarithmic equation to determine the maximum number of stations:

[tex]I1/I2 = (d1/d2)^2[/tex]

where I1 is the desired overall sound intensity (90 dB), I2 is the intensity of a single station (unknown), d1 is the maximum distance from the installation at which the sound level must be below the limit (let's say 10 meters), and d2 is the distance from the installation to a single station (also unknown).

Solving for I2, we get:

[tex]I2 = I1 \times (d2/d1)^2 = 76 dB \times (10 m / d2)^2[/tex]

To determine the maximum number of stations, we can set I2 to the maximum allowable intensity (90 dB) and solve for d2:

[tex]90 dB = 76 dB \times (10 m / d2)^2[/tex]

[tex]d2 = \sqrt{[(76\; dB \times 10 m^2) / 90\; dB]} = 3.27 meters[/tex]

Therefore, each station must be at least 3.27 meters apart from each other to ensure that the overall sound intensity does not exceed 90 dB.

In summary, we can use the logarithmic equation for sound intensity to determine the maximum number of monkey-typewriter stations that can be set up in a room without exceeding a noise ordinance of 90 dB. We found that each station must be at least 3.27 meters apart from each other to ensure compliance.

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The maximum current across the resistor is 0.01 amps.

The capacitor can hold a maximum charge of 1500 C.

It takes 0.15 seconds for the capacitor to reach.

a) The maximum current that flows through the resistor during charging can be calculated using the formula I = V/R, where V is the voltage of the battery and R is the resistance of the circuit. Therefore, I = 1.5V / 150Ω = 0.01 A.

b) The maximum charge on the capacitor can be calculated using the formula Q = CV, where C is the capacitance of the capacitor and V is the maximum voltage across the capacitor during charging. Therefore, Q = (1000 μF) * (1.5V) = 1500 μC.

c) The time it takes for the capacitor to reach a potential of 1.0V can be calculated using the formula t = RC, where R is the resistance of the circuit and C is the capacitance of the capacitor. Therefore, t = (150Ω) * (1000 μF) = 0.15 s.

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Because the gasoline expands more quickly than the steel can,4.44 L is the amount that will overflow

Define  thermal expansion.

The propensity of matter to vary in volume in response to temperature changes is known as thermal expansion. A substance's particles move more when it is heated, maintaining a greater average separation. Thermosets experience linear thermal expansion since they are employed in solid form.

The phenomena known as thermal expansion can be seen in solids, liquids, and gases. An object or body expands during this process when heat (temperature) is applied. The term "thermal expansion" refers to an object's propensity to change its dimensions as a result of heat, including length, density, area, and volume.

volume 216 L

Temperature  T1 is 13. 5°C, T2 is 36. 0°C

T will be 22.5 K

Amount of gasoline that overflows:

9.14 x 10(-6)/K *V*T^2

9.14 x 10(-6)/K x 216 L x 22.5 K x 22.5 K = 4.44 L

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(a) Using a_rad = [tex]\omega^{2r[/tex]: Approximately 100.53 m/s²

(b) Using a_rad = [tex]v^{2/r[/tex]: Approximately 31.42 m/s²

To solve the problem, let's first convert the angular acceleration from revolutions per minute (rpm) to radians per second squared (rad/s²):

Given:

Diameter of the wheel (D) = 40.0 cm

Radius of the wheel (r) = D/2 = 20.0 cm = 0.20 m

Angular acceleration (α) = 4 rpm

(a) Using the relationship a_rad = [tex]\omega^{2r[/tex]:

The angular acceleration (α) can be converted to angular velocity (ω) using the formula:

ω = αt, where t is the time taken to complete two revolutions.

Since the wheel starts from rest, the time taken to complete two revolutions is given by:

t = (2 rev) / (4 rpm) = 0.5 min = 30 s

Now we can calculate the angular velocity (ω):

ω = αt = (4 rpm) × (2π rad/1 min) × (1 min/60 s) × (30 s) = 4π rad/s

Using the relationship a_rad = [tex]\omega^{2r[/tex], we can calculate the radial acceleration:

a_rad = [tex]\omega^{2r[/tex] = (4π rad/s)² × 0.20 m

a_rad = 16π² × 0.20 m ≈ 100.53 m/s²

Therefore, the radial acceleration of a point on the rim, calculated using a_rad = [tex]\omega^{2r[/tex], is approximately 100.53 m/s².

(b) Using the relationship a_rad = [tex]v^{2/r[/tex]:

The wheel starts from rest, so its initial linear velocity (v) is zero.

The final linear velocity (v) can be calculated using the formula:

v = ωr

The time taken to complete two revolutions is already calculated as 30 seconds, so we can find the final angular velocity (ω) as follows:

ω = αt = 4π rad/s (same as before)

Now we can calculate the final linear velocity (v):

v = ωr = (4π rad/s) × 0.20 m ≈ 2.513 m/s

Using the relationship a_rad = [tex]v^{2/r[/tex], we can calculate the radial acceleration:

a_rad = [tex]v^{2/r[/tex] = (2.513 m/s)² / 0.20 m

a_rad ≈ 31.42 m/s²

Therefore, the radial acceleration of a point on the rim, calculated using a_rad = [tex]v^{2/r[/tex], is approximately 31.42 m/s².

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The index of refraction of this medium is 1.36. The index of refraction (n) of a medium is the ratio of the speed of light in vacuum (c) to the speed of light in the medium (v): n = c/v

Given the speed of light in the medium as 2.2 × 10^8 m/s, we can calculate the index of refraction as: n = c/v = (3.0 × 10^8 m/s) / (2.2 × 10^8 m/s) = 1.36

Therefore, the index of refraction of this medium is 1.36. This indicates that light travels slower in this medium compared to a vacuum and is bent when it enters the medium at an angle, a phenomenon called refraction.

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Hormones send signal → Egg released from ovary → Egg travels to fallopian tube.

Hormones send signal: The process of ovulation is triggered by hormonal signals. In the female reproductive system, the pituitary gland releases follicle-stimulating hormone (FSH) and luteinizing hormone (LH) in response to the signals from the hypothalamus. These hormones play a crucial role in the maturation of ovarian follicles and the release of an egg from the ovary.

Egg is released from the ovary: Once the hormonal signals are received, the dominant ovarian follicle (containing a developing egg) reaches maturity.

The surge in luteinizing hormone (LH) triggers the release of the egg from the ovary. This is known as ovulation. The released egg is then available for potential fertilization.

Egg travels to the fallopian tube: After ovulation, the released egg, also known as the ovum or oocyte, travels through the fallopian tube. The fallopian tubes, also called uterine tubes, are structures that connect the ovaries to the uterus.

The fallopian tubes have finger-like projections called fimbriae that help capture the released egg and guide it into the tube.

In summary, the correct order of processes before and during ovulation is as follows:

Hormones send signal

Egg is released from the ovary

Egg travels to the fallopian tube

These processes are essential for successful reproduction in females and are part of the menstrual cycle.

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Answer:

d

Explanation:

edge

The correct answer is D. The next step for the student should be to keep the volume of the flask constant and turn on the hot plate to increase the temperature of the gas while recording the resulting pressure.

By keeping the volume of the flask constant, the student can isolate the effect of temperature on the pressure of C02 gas. This will allow them to accurately investigate the relationship between pressure and temperature.

The expected result is that as the temperature of the gas increases, the pressure will also increase due to the direct relationship between pressure and temperature in gases, as described by the gas laws( PV=nRT). By keeping the volume of the flask constant, the student can ensure that any changes in pressure are solely due to changes in temperature.

As the temperature of the gas increases, the gas molecules move faster and collide with the walls of the flask more frequently and with greater force, leading to an increase in pressure.

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The right side of the heart is the circuit that pumps oxygen-poor blood to the lungs.

Here are some points to explain this further:

- The heart is a muscular organ located in the chest that pumps blood throughout the body.

- The heart has four chambers, two on the right side and two on the left side.

- The right side of the heart is responsible for pumping blood to the lungs, where it can receive oxygen.

- When oxygen-poor blood from the body enters the right atrium of the heart, it is pumped into the right ventricle.

- The right ventricle then pumps the oxygen-poor blood through the pulmonary artery to the lungs, where it can be oxygenated.

- After the blood is oxygenated in the lungs, it returns to the left side of the heart via the pulmonary veins.

- The left side of the heart then pumps the oxygen-rich blood out to the rest of the body through the aorta.

- This process is known as the pulmonary circulation, and it is responsible for delivering oxygen to the body's tissues and organs.

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The distance between two consecutive staples in the finished part is approximately 0.28 meters or 28.46 centimeters.

Consider the relative velocity between the staple gun and the parts to be stapled.

The staple gun is rolling to the left at 1.5 m/s, while the parts are rolling to the right at 2.2 m/s. Therefore, the relative velocity between the staple gun and the parts is:

v_rel = v_parts - v_staple_gun = 2.2 m/s - (-1.5 m/s) = 3.7 m/s

The staple gun fires 13 staples per second, so the time between two consecutive staples is:

t = 1/13 s

During this time, the relative velocity between the staple gun and the parts causes the distance between the two consecutive staples in the finished part. Let's call this distance "d".

d = v_rel * t = 3.7 m/s * (1/13 s) = 0.2846 m

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Vdst and Vdsq are different measurements of the voltage drop across the drain-source terminals of a MOSFET transistor, and to find Vdsq from Vdst, we need to measure Vdst and use a formula that takes into account Vgs and Vth.

To understand how to find Vdsq from Vdst, we need to first understand what these terms represent.

Vdst is the voltage drop across the drain-source terminals of a MOSFET transistor when it is in its ON state. This voltage drop is caused by the current flowing through the transistor, and it is a dynamic value that changes as the current changes.

Vdsq, on the other hand, is the voltage drop across the drain-source terminals of a MOSFET transistor when it is in its steady-state or quiescent state. This voltage drop is caused by the biasing of the transistor and is a static value that remains constant as long as the biasing conditions remain the same.

To find Vdsq from Vdst, we need to first measure the value of Vdst while the transistor is in its ON state. This can be done using a multimeter or an oscilloscope. Once we have the value of Vdst, we can then calculate Vdsq using the following formula:

Vdsq = Vdst + Vgs - Vth

where Vgs is the voltage applied to the gate of the transistor and Vth is the threshold voltage of the transistor.

As for how the value of 7 for Vdsq was found, it is impossible to say without more context. It could have been calculated using the formula above, or it could have been measured using experimental methods.

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Protostars are difficult to observe because : they are heavily obscured by dust and gas, making them hard to detect in visible light and other forms of electromagnetic radiation.

Electromagnetic (EM) radiation is a form of energy that is produced by the movement of electrically charged particles. It is a type of energy that can travel through space at the speed of light, and is made up of both electric and magnetic fields. EM radiation is created by the acceleration of charged particles, such as electrons, protons, and ions. EM radiation is found in a broad spectrum of wavelengths, which includes everything from radio waves to gamma rays. EM radiation has many practical uses, such as in television, radio, and mobile phones. It is also used in medical treatments such as radiation therapy and X-ray imaging. EM radiation is also used in communication between spacecraft and the Earth.

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Sydney McLaughlin's average speed during the 400-meter hurdles race was 7.77 m/s.

The average speed of Sydney McLaughlin during the 400-meter hurdles race is calculated as follows;

Average speed = distance / time

The distance is 400 meters, and the time is 51.46 seconds.

The average speed of Sydney McLaughlin during the 400-meter hurdles race is calculated as;

Average speed = 400 / 51.46

Average speed = 7.77 m/s

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Answer: new moon

Explanation:

The molar specific heat of a diatomic gas measured at constant volume and found to be 29.1 J/mol·K indicates that the types of energy contributing to the molar specific heat are: (b) translation and rotation only.

This is because diatomic molecules have 5 degrees of freedom: 3 translational and 2 rotational. The molar specific heat at constant volume (Cv) can be calculated using the formula Cv = (f/2)R, where f is the degrees of freedom and R is the gas constant (8.314 J/mol·K).

For diatomic molecules with 5 degrees of freedom, Cv = (5/2)R = 20.785 J/mol·K. However, given the value of 29.1 J/mol·K, it is close to the expected value of (7/2)R = 29.09 J/mol·K, which represents the 3 translational and 2 rotational degrees of freedom without including vibrational energy.

Thus, only translation and rotation are contributing to the molar specific heat in this case.

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When a single neutron hits a Uranium-235 atom, a chain reaction can occur, releasing a huge amount of energy, this process, known as nuclear fission, occurs when the Uranium-235 atom absorbs the neutron and becomes unstable.

As a result, the unstable Uranium-235 atom decays into smaller elements, specifically Barium-141 and Krypton-92. In addition to these two elements, a certain number of neutrons are also released during the decay process.

These newly released neutrons can go on to collide with other Uranium-235 atoms, perpetuating the chain reaction and leading to the release of a massive amount of energy. This phenomenon is the basis for nuclear power generation and atomic weapons.

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To determine the heat capacity of the calorimeter, we can use the principle of heat transfer and the equation:

q = m * c * ΔT,

where:

q is the heat transferred,

m is the mass of the water,

c is the specific heat capacity of water, and

ΔT is the change in temperature.

In this case, we have two portions of water with masses of 60 g each, mixed together, and the resulting temperature is 45°C.

Let's calculate the heat transferred for each portion of water:

q1 = m1 * c * ΔT1,

q2 = m2 * c * ΔT2,

where:

m1 = 60 g (mass of water at 20°C),

m2 = 60 g (mass of water at 80°C),

c = specific heat capacity of water (approximately 4.18 J/g°C), and

ΔT1 = 45°C - 20°C,

ΔT2 = 45°C - 80°C.

Now, let's calculate the heat transferred for each portion of water:

q1 = 60 g * 4.18 J/g°C * (45°C - 20°C),

q2 = 60 g * 4.18 J/g°C * (45°C - 80°C).

The total heat transferred in the calorimeter setup is the sum of the heat transferred for each portion of water:

q_total = q1 + q2.

Since the heat transferred in the calorimeter is equal to the negative of the heat transferred by the water (q_total = -q_calorimeter), we can write:

-q_calorimeter = q_total.

Therefore, the heat capacity of the calorimeter (C_calorimeter) can be calculated as:

C_calorimeter = -q_calorimeter / ΔT_total,

where ΔT_total is the change in temperature of the combined water portions.

Substituting the calculated values into the equation will give you the heat capacity of the calorimeter.

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The net force acting on the airplane is the centripetal force required to keep the airplane moving in a circular path. The angular acceleration of the airplane is 12.25 [tex]rad/s^2.[/tex]

The centripetal force is given by:

[tex]F = m * a_c[/tex]

where

F is the net force,

m is the mass of the airplane, and

[tex]a_c[/tex] is the centripetal acceleration.

The centripetal acceleration is given by:

[tex]a_c = v^2 / r[/tex]

where

v is the speed of the airplane and

r is the radius of the circle.

Since the airplane is in level flight, the net thrust of the engine is perpendicular to the tethering wire.

Therefore, it does not contribute to the centripetal force. The centripetal force is provided by the tension in the wire.

The tension in the wire is given by:

[tex]T = F_c = m * a_c[/tex]

where [tex]F_c[/tex] is the centripetal force.

The angular acceleration of the airplane is given by:

[tex]\alpha = a_c / r[/tex]

Substituting the values given:

[tex]F_c = m * a_c[/tex]

    = T = 0.6 N

[tex]a_c = v^2 / r[/tex]

[tex]0.6 N = m * v^2 / r[/tex]

[tex]v^2 = F_c * r / m[/tex]

[tex]v = \sqrt{ (F_c * r / m)[/tex]

  [tex]=\sqrt{(0.6 N * 0.2 m / 0.5 kg)[/tex]

 = 0.49 m/s

  [tex]a_c = v^2 / r[/tex]

      = 0.49 m/s / 0.2 m

      = 2.45 [tex]m/s^2[/tex]

      [tex]\alpha = a_c / r[/tex]

          [tex]= 2.45 m/s^2 / 0.2 m[/tex]

          = 12.25 [tex]rad/s^2[/tex]

Therefore, the angular acceleration of the airplane is 12.25 [tex]rad/s^2.[/tex]

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If Dylan were to triple his distance from the center of the Earth by flying in a spacecraft, his weight on the surface of the Earth would decrease to one-ninth of his original weight, which is approximately 69 N.

According to the law of universal gravitation, the weight of an object is directly proportional to the mass of the planet and inversely proportional to the square of the distance from the center of the planet.

Therefore, if Dylan triples his distance from the center of the Earth by flying in a spacecraft, his weight on the surface of the Earth would be one-ninth of his original weight. This is because the distance has been tripled, and the inverse square of three is nine.

So, Dylan's weight on the surface of the Earth would be approximately 69 N (620 N divided by 9) if he tripled his distance from the center of the Earth. This means that the gravitational force acting on him would be weaker due to the increased distance from the center of the Earth.

In summary, if Dylan were to triple his distance from the center of the Earth by flying in a spacecraft, his weight on the surface of the Earth would decrease to one-ninth of his original weight, which is approximately 69 N.

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The reading addresses how some people use "uncertainty" as a way to undermine science: by pointing out that these individuals often exploit the inherent limitations and ambiguities present in scientific research.

They tend to focus on the fact that scientific findings are often provisional, and conclusions can change with the introduction of new evidence or advancements in methodologies. By emphasizing the uncertainty aspect, they attempt to discredit or cast doubt on the overall credibility of scientific results.

Furthermore, these individuals may cherry-pick data or studies that support their preconceived beliefs, while ignoring the broader consensus within the scientific community. This selective presentation of evidence contributes to misinformation and public confusion about scientific issues, such as climate change or vaccinations.

In some cases, those who use uncertainty to undermine science may have ulterior motives, such as protecting vested interests or promoting a specific political or ideological agenda. By sowing doubt and mistrust in scientific findings, they can manipulate public opinion and obstruct the development or implementation of evidence-based policies.

To counteract these attempts to undermine science, it is essential for the scientific community and the public to recognize and appreciate the inherent uncertainties within the scientific process.

By fostering critical thinking, encouraging open and transparent communication, and supporting continued research and education, we can help build resilience against misinformation and promote a better understanding of the role of uncertainty in scientific progress.

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Answer:

The gravitational force between two objects of mass 25 kg and 20 kg separated by a distance of 5 m is [tex]1.334 * 10^-9[/tex]

Explanation:

Given

Mass of the body (MA)= 25kg

Mass of the other body (MB)= 20kg

Distance of separation between them (R)= 5m

We know that

The gravitational force between two masses

[tex]F= (G*MA*MB)/R^2[/tex]  N

where

[tex]G=6.67 * 10^-11 m^3 kg^-1 s^-2[/tex]

Putting all the values in the above formula,

[tex]F=(6.67*10^-11 *25*20)/5*5[/tex] N

[tex]F=1.33*10^-9 N[/tex]

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Answer:

Thermal Energy

Explanation:

The magnitude of the electrostatic force between the two charged particles is 2.59 * 10^4 N.

To calculate the magnitude of the electrostatic force between the two charged particles, we can use Coulomb's law which states that the magnitude of the electrostatic force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

So, the formula to calculate the electrostatic force between two charged particles is:

F = (k * q1 * q2) / r^2

where F is the electrostatic force, k is Coulomb's constant (9 * 10^9 N*m^2/C^2), q1 and q2 are the charges of the two particles and r is the distance between them.

In this case, q1 = +8.0 μC = +8.0 * 10^-6 C, q2 = +9.0 μC = +9.0 * 10^-6 C, and r = 0.5 cm = 0.5 * 10^-2 m.

Substituting these values into the formula, we get:

F = (9 * 10^9 * 8.0 * 10^-6 * 9.0 * 10^-6) / (0.5 * 10^-2)^2
F = 2.59 * 10^4 N

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The electric power of the lamp is 240 watts.

The electric power of a lamp can be calculated using the formula:

Power = Current x Voltage

In this case, the current is 2 A and the voltage is 120 V.

Power = 2 A x 120 V = 240 watts (W)

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To calculate the amount of work done, we need to know the force exerted by the person and the distance the car was moved. Work is calculated using the formula: Work = Force × Distance. Without the information about the force exerted and the distance the car was moved, it is not possible to determine the exact amount of work done by the person over the 4 hours spent pushing the 800 kg car.

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Satellite mass is 1.69 x 10²² kg; Distance to Corus is 6,760 km; Gravitational acceleration is 3.77 m/s²; Gravitational force is 1.26 x 10¹⁰ N; Minimum orbit speed is 3.25 km/s.

To estimate the mass of the satellite, we can use the formula for the period of a satellite's orbit, which is given by [tex]T=2\pi \sqrt(r^{3} /GM)[/tex], where T is the period, r is the distance between the satellite and the center of Corus, G is the gravitational constant, and M is the mass of Corus.

We know that the period of the satellite is 15 Earth days, which is approximately 1.296 x 106 seconds. We also know that the distance between Corus and the satellite is the sum of the radius of Corus and the altitude of the satellite.

Assuming the altitude of the satellite is 500 km, which is similar to the altitude of the International Space Station, we can estimate the distance to be 6,760 km.

To calculate the satellite's mass, we can rearrange the formula to solve for M, which gives [tex]M=(4\pi ^{2} r^{3} )/(GT^{2} )[/tex]. Substituting the known values, we get M = 1.69 x 1022 kg.

Using the formula for gravitational acceleration,[tex]g = G (M/r^{2} )[/tex], we can calculate the gravitational acceleration towards the core of Corus. Substituting the known values, we get g=3.77 m/s².

To calculate the gravitational force between the satellite and Corus, we can use the formula for gravitational force, [tex]F=G(Mm/r^{2} )[/tex] , where m is the mass of the satellite. Substituting the known values, we get F = 1.26 x 1010 N.

Finally, to calculate the minimum speed of the satellite to orbit Corus, we can use the formula for circular velocity, [tex]v=\sqrt(GM/r)[/tex]. Substituting the known values, we get v = 3.25 km/s.

In summary, a suitable mass for the satellite is approximately 1.69 x 1022 kg, the distance between the satellite and Corus's surface is approximately 6,760 km, the gravitational acceleration towards the core of Corus is approximately 3.77 m/s².

The gravitational force between the satellite and Corus is approximately 1.26 x 1010 N, and the minimum speed of the satellite to orbit Corus is approximately 3.25 km/s.

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Complete Question:

A new planet called "Corus" was discovered by a team of astronomers that is 60 x 106 km away from Earth: A satellite was launched by a rocket from Earth to reach Corus. At a specific distance from Corus, the rocket releases the satellite to the orbit of the planet The satellite makes one complete revolution around Corus in 15 Earth days. If Corus has a similar mass to Mars, propose a suitable mass of the satellite and estimate:

i. Distance between the satellite and the Corus's surface

ii. Satellite's gravitational acceleration towards the core of Corus

iii. Gravitational force between the satellite and the Corus

iv. Minimum speed of the satellite to orbit Corus

The new volume of the gas when the temperature is raised to 29°C and the pressure is not changed is approximately :4.73 L. The correct option is A.

To determine the new volume of a gas when its temperature is changed, we can use Charles' Law. Charles' Law states that the volume of a gas is directly proportional to its temperature, provided that the pressure remains constant. Your initial temperature (T1) is 14°C, and the initial volume (V1) is 4.5 L.

The final temperature (T2) is 29°C, and we need to find the new volume (V2). Remember to convert the temperatures from Celsius to Kelvin by adding 273.15 to each value (T1 = 287.15 K, T2 = 302.15 K).

Using Charles' Law, we have:

V1/T1 = V2/T2

Now, we can plug in the values:

(4.5 L)/(287.15 K) = V2/(302.15 K)

To find V2, multiply both sides by 302.15 K:

V2 = (4.5 L x 302.15 K) / 287.15 K

V2 ≈ 4.73 L

The new volume of the gas when the temperature is raised to 29°C and the pressure is not changed is approximately 4.73 L. The correct option is A.

To know more about temperature, refer here:

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Complete  question:

A gas has a temperature of 14 °C, and a volume of 4. 5 L. If the temperature is raised to 29 °C and the pressure is not changed, what is the new volume of the gas?

A. 4. 7 L

B. 4. 9 L

C. 5. 3 L

D. 5. 5 L